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PHP - Simple Explode And Echo Not Working.. .php File
Hi,
Im trying to pull an email from an url, and then echo the email as value into a email form-- under the "from" heading. The echo is not working i get blanks. here is the code: <?php $thisurl='$_SERVER['REQUEST_URI']'; $thepart = explode('/', $thisurl); $themail='$thepart[2]'; ?> <form method="post" action="sendit.php"> To: <br><input type="text" name="to" size="44" value="<?php for($i=1; $i<=$lines; $i=$i+1) { $names[$i] = str_replace("<br>", "", $names[$i]); $names[$i] = str_replace("\n", "", $names[$i]); echo $names[$i].';'; } ?>"><br> From: <br><input type="text" name="email" size="44" value="<?php echo '$themail'; ?>" readonly><br> Subject: <br><input type="text" name="subject" size="44" /><br><br> Similar TutorialsOK, have no idea what's going on... I've done this a million times... why wont this output!?? I must have a major brain meltdown and dont know it yet!!! Code: [Select] <?php // this echoes just fine: echo $_POST['testfield']; // but this wont echo: echo if (isset($_POST['testfield'])) { $_POST['testfield'] = $test; } echo $test; /// or even this DOESNT echo either!: $_POST['testfield'] = $test; echo $test; ?> Hi
I try to echo out random lines of a html file and want after submit password to whole content of the same html file. I have two Problems.
1st Problem When I echo out the random lines of the html file I don't get just the text but the code of the html file as well. I don't want that. I just want the text. How to do that?
for($x = 1;$x<=40;$x++) {
$lines = file("$filename.html");
echo $lines[rand(0, count($lines)-1)]."<br>";
}
I tried instead of "file("$filename.html");" "readfile("$filename.html");" But then I get the random lines plus the whole content. Is there anything else I can use instead of file so that I get the random lines of text without the html code?P.S file_get_contents doesn't work either have tried that one.
2nd Problem:
As you could see in my first problem I have a file called $filename.html. After I submit the value of a password I want the whole content. But it is like the program did forget what $filename.html is. How can I make the program remember what $filename.html is? Or with other words how to get the whole content of the html file?
My code:
if($_POST['submitPasswordIT']){
if ($_POST['passIT']== $password ){
$my_file = file_get_contents("$filename.html");
echo $my_file;
}
else{
echo "You entered wrong password";
}
}
If the password isn't correct I get: You entered wrong password. If the password is correct I get nothing. I probably need to create a path to the file "$filename.html", but I don't know exactly how to do that.
If I explode a string well using a substring when I implode that substring is now missing. for example. Code: [Select] $exploded = explode("[MAC]",$data); $data = implode($exploded); Now [MAC] would be missing in the $data string. any way to get around this? <td><label for='images'> <b>File to upload:</b> </label></td> <td><input type='file' name = 'drama_image' '<?php echo $row['drama_image']; ?>'/></ </tr> <?php $target_path = "images/"; $target_path = $target_path . basename( $_FILES['images']['name']); if(move_uploaded_file($_FILES['images']['tmp_name'], $target_path)) { echo "The file ". basename( $_FILES['images']['name']). " has been uploaded"; } else{ echo $row['drama_image']; } ?> ['drama_image'] is the name of the file I wanna echo it out in the box of file upload so when I save , the default picture will still be there instead of being overwritten as the box does not have any value in it. I set up a form that you can type html code into. When you click submit it sends the form data to a php script that receives the data and then prints it. Basically im trying to accomplish something similar to this http://www.w3schools.com/html/tryit.asp?filename=tryhtml_intro. I have tried to print the html code using echo and print_r. The problem is that it is not displaying correctly. For instance if i were to type in Code: [Select] <body bgcolor="FFCC00"> Nothing would happen. Most of the html displays correctly. What is the reason behind this? Do i need to use a different command to print the form variable? Or do i need to save it as an html document then display it? hi there all. hope i can get your help. i am creating a php page that talks to mysql tabes. i want to print query into my html page inside html tags. the first echo in my code works but the one embedded inside the html code prints nothing to the page. look at my code if it helps: <html><body> <?php mysql_connect("localhost", "root", "123456") or die("Connection Failed"); mysql_select_db("man_utd")or die("Connection Failed"); $name = $_POST['members']; $query = "select * from members where username = 'burns'"; $result = mysql_query($query); while ($line = mysql_fetch_array($result, MYSQL_ASSOC)) { echo $line['pass']; } ?> <table border="0" cellspacing="2" cellpadding="2"> <tr> <th><font face="Arial, Helvetica, sans-serif"><?php echo $line['pass']; ?></font></th> <th><font face="Arial, Helvetica, sans-serif">Value2</font></th> <th><font face="Arial, Helvetica, sans-serif">Value3</font></th> <th><font face="Arial, Helvetica, sans-serif">Value4</font></th> <th><font face="Arial, Helvetica, sans-serif">Value5</font></th> </tr> </body> </html> thanks all for any help echo will not print out a value. I do the simple string " " and it doesn't even do that. It's just blank in my browser. I use netbeans and firefox and chrome. Any idea as to what I'm doing wrong? Simple code snippet: <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"/> <title>PHP Testing</title> </head> <body> <?php echo "print me"; ?> </body> </html> Thanks for any future help. Hello all, I'm passing variables through a URL. This will work: echo $v4; But neither of these will: echo "<a href='test.php?v4=$v4'>Places</a>"; echo "<a href='test.php?v4=".$v4."> Places</a>"; It WILL work if I hardcode v4, like so: echo "<a href='test.php?v4=Utah'>Places</a>"; But that's useless to me, as I don't want to have to write 50 If statements for every database entry. Does anyone know how to fix this? Thanks! Please help, when I run this search and enter something in the search thats not in the database, it doesnt reply with "Your query returned 0 results" as it should. I tjust stays blank Here's the section of code in question... if ($search) // perform search only if a string was entered. { mysql_connect($host, $user, $pass) or die ("Problem connecting to Database"); $srch="%".$search."%"; $query = "select * from tvads WHERE advert LIKE '$srch' ORDER BY advert, year DESC, details ASC LIMIT 0,30"; $result = mysql_db_query("cookuk_pn", $query); if ($result) { $count = 1; print "<table border=\"0\" cellpadding=\"0\" cellspacing=\"0\" bordercolor=\"#0000FF\" width=\"900\">"; print "<tr><td width=\"200\" height=\"30\" align=\"left\"><u><b><font face=\"arial\" size=\"2\" color=\"#800080\">Advert / Description</font></b></u></td>"; print "<td width=\"80\" align=\"left\"><u><b><font face=\"arial\" size=\"2\" color=\"#800080\">Year</font></b></u></td>"; print "<td width=\"200\" align=\"left\"><u><b><font face=\"arial\" size=\"2\" color=\"#800080\">Artist</font></b></u></td>"; print "<td width=\"200\" align=\"left\"><u><b><font face=\"arial\" size=\"2\" color=\"#800080\">Track</font></b></u></td>"; print "<td width=\"80\" align=\"left\"><u><b><font face=\"arial\" size=\"2\" color=\"#800080\">Buy Album</font></b></u></td>"; print "<td width=\"100\" align=\"left\"><u><b><font face=\"arial\" size=\"2\" color=\"#800080\">Download MP3</font></b></u></td></tr>"; while ($row = mysql_fetch_array($result)) { // Begin while $data .= "<td width=\"200\" height=\"30\" align=\"left\"><font face=\"arial\" size=\"1\">" .$row['advert']. "</font><br>"; $data .= "<font face=\"arial\" size=\"1\" color=\"#000080\"><i>" .$row['details']. "</i></font></td>"; $data .= "<td width=\"80\" height=\"30\" align=\"left\"><font face=\"arial\" size=\"1\">" .$row['year']. "</font></td>"; $data .= "<td width=\"200\" height=\"30\" align=\"left\"><font face=\"arial\" size=\"1\">" .$row['artist']. "</font></td>"; $data .= "<td width=\"200\" height=\"30\" align=\"left\"><font face=\"arial\" size=\"1\">" .$row['track']. "</font></td>"; $data .= "<td width=\"80\" height=\"30\" align=\"left\"><font face=\"arial\" size=\"1\">" .$row['asin_ref']. "</font></td>"; $data .= "<td width=\"100\" height=\"30\" align=\"left\"><font face=\"arial\" size=\"1\">" .$row['mp3_ref']. "</font></td></tr>"; $count++; } // end while $data .="</table>"; echo $data; } else { echo "problems...."; } } else { echo "Your query returned 0 Results"; } ?> This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=320829.0 My variable which should be storing XML data and echos it to the screen is echoing the data as a string without the XML structure Below is my code but it is still not working: Code: [Select] $view = $_GET['view']; $xml_data = "http://www.website.com/STRATA/" . $view .".xml"; $handle = fopen($xml_data, 'r'); $Data = fread($handle, 10000); fclose($handle); echo $Data; How would I open a text file from another server and echo it. http://mysite.com/news/feed.txt for($i=0; $i!=count($account_data); $i++){ echo "\n::: ".strtoupper($account_data[$i][0])." :::\n"; if($account_data[$i][1] != "" && stristr($account_data[$i][0], "@") && stristr($account_data[$i][0], ".")){ list($place[0],$place[1],$place[2],$place[3]) = authorize($account_data[$i], $game_link); if($place[2] > 1 && strlen($place[3]) == 40){ $filename = 'auth-keys.txt'; $fp = file($filename,'a+'); $data = $place[2]." ".$place[3]."\r\n"; file_put_contents($filename, $data, FILE_APPEND); echo $data; } else echo "Account Skipped: wrong password/email combo, or a login error...\n"; $echo = file_put_contents($filename, FILE_APPEND); } else echo "Account Skipped: invalid email or blank password...\n"; } echo "\n::: PROGRAM FINISHED, YOU CAN CLOSE THIS AT ANY TIME :::"; sleep(10000); You see where I tried to put $echo file_put_contents etc... On success the acct writes a security id and a security auth key to a file, ever acct puts the tokens on a new line every acct... now when an acct echos account skipped, how can I make it print the echo on the file new line instead of nothing being writen and it just skipping the account I have an edit page but whenever I click edit the pathname of the original file is not in the file box so everytime I hit the save button , it will be considered as no file so my previous image or file will be overwritten by "nothing". I have a .txt file containing hundreds of lines of Names (e.g. Brad, Jennifer, etc.) What coding can I use to only echo the first 20? Ok, here's my code: How do i make it so that it outputs a maximum of only 5 results from the query where the img file exists. When I add LIMIT to the sql query it doesnt work so I guess its something else, but I have no clue. Can anyone help? $query = mysql_query("SELECT * FROM table WHERE date >= '$now' ORDER BY max(date) desc"); while ($row = mysql_fetch_assoc($query)) { $cid = $row['cat_id']; $title = $row['name']; $seoname = $row['seourl']; $img = 'images/'.$seoname.'.jpg'; if (!file_exists($img)) { $img = ''; } else { $img = 'images/'.$seoname.'.jpg'; } if (!empty($img)) { echo '<a href="images/'.$seoname.'/"><img src="'.$img .'" style="width:528px;" alt="" /></a>' . "\n"; } } Thanks. Hi, This is my first post in this forum and am a PHP beginner. I have written a script in php and need to use echo to see the values of variables etc. However I dont get the output on the screen while using echo . I am using Xampp server with Apache. The startup.html file code is
<!DOCTYPE HTML>
</head>
and the test.php code is <?php
$lat = $_REQUEST['latitude'];
echo 'latitude- '.$lat . ', longitude- ' . $lon; Please help regards
Sanjish Hi, Have a text file that is being read. I want to print the contents however I want each line of the text file to appear on a new line in the browser. So far $str = file_get_contents('records.txt'); $lines = explode("\n", $str); echo $lines[0]; Help appreciated |
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