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PHP - I Have Entered Two Values But Only One Is Being Added To The Mysql
Hey guy
<?php $con = mysql_connect("localhost","root",""); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("Examination", $con); $sql="INSERT INTO Test (Tes_Name, Tes_Description) VALUES ('$_POST[Tes_Name]','$_POST[Tes_Description]')"; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } echo "1 record added"; mysql_close($con) ?> This is my code and I can enter Tes_Name on to mysql but nothing is shown for Tes_Description. The form is Code: [Select] <html> <body> <h3>Test</h3> <table border="0"> <form method="POST" action="try2.php"> <tr><td>Tes_Name</td><td>:</td><td><input type="text" name="Tes_Name" size="20"></td></tr> <tr><td>Tes_Description</td><td>:</td><td><input type="Tes_Description" name="password" size="20"></td></tr> <tr><td> </td><td> </td><td><input type="submit" value="Submit"></td></tr> </form> </table> </body> </html> Similar TutorialsThis topic has been moved to HTML Help. http://www.phpfreaks.com/forums/index.php?topic=316203.0 Code what i made so far.
$inputText = 'This is testing http://www.youtube.com';
$allowedDomains = 'www.google.com
youtube.com/
http://www.test.org';
$array = preg_split('/[\s]+/', $allowedDomains);
$regex = '';//Need this line
if(preg_match($regex, $inputText)){
print 'Domain match!';
}else{
print 'Domain not match!';
}
Edited by jacob21, 16 October 2014 - 08:31 AM. hello, i'm actually doing a javascript here to create dynamic textboxes when a button is clicked. now my problem is, how to get all the values from these textboxes and save these values altogether in a column on the table.. i know few php coding methods like $_POST in handling values from txtboxes and saving it to database but it doesn't include working with javascript and dynamic textboxes.. and i'm actually doubtful if this is possible..so any help from you guys i would deeply appreciate. heres my code: Code: [Select] <html> <head> <script type="text/JavaScript"> function AddTextBox() { document.getElementById('container').innerHTML+='<input type="text" name="block"><br>'; } </script> </head> <body> <input type="text" name="block"> <div id="container"></div> <br> <button onclick="AddTextBox();">Add another textbox</button> </body> </html> I have deleted mysql info for safety reasons. Here are the two webpage's codes i'm using right now menu.php <? session_start(); if(!session_is_registered(myusername)){ header("location:login.php"); } ?> <html><title>ChronoServe - Saving Time</title> <link href="style.css" rel="stylesheet" type="text/css"> <body> <table width="100%" border="0" cellpadding="0" cellspacing="0" class="container"> <tr> <td> <table width="335px" height="50%" border="1" align="center" cellpadding="0" cellspacing="0" class="centered"> <tr> <td> <form method="post" action="insertvalues.php"> <table width="100%" border="0" align="center" cellpadding="3" cellspacing="10"> <tr> <td colspan="2"><div align="center" class="font2">Activation Information</div></td> </tr> <tr> <td colspan="2"></td> </tr> <tr> <td width="40%" class="font3">First Name :</td> <td width="60%"> <div align="center"> <input name="firstname" type="text" class="font3" id="firstname" maxlength="25" /> </div></td> </tr> <tr> <td class="font3">Last Name :</td> <td> <div align="center"> <input name="lastname" type="text" class="font3" id="lastname" maxlength="25" /> </div></td> </tr> <tr> <td height="28" class="font3">Phone Number :</td> <td> <div align="center"> <input name="pnumber" type="text" class="font3" id="pnumber" maxlength="10" /> </div></td> </tr> <tr> <td class="font3">Personnel Activated :</td> <td> <div align="center"> <input name="numberactivated" type="text" class="font3" id="numberactivated" maxlength="3" /> </div></td> </tr> <tr> <td height="37" colspan="2"></td> </tr> <tr> <td colspan="2"><div align="center"> <input name="submit" type="Submit" class="font3" value="Submit" /> </div> </td> </tr> </table> </form></td> </tr> </table> </td> </tr> </table> </body> </html> insertvalues.php <?php if(isset($_POST['Submit'])) { $firstname = $_POST['firstname']; $lastname = $_POST['lastname']; $pnumber = $_POST['pnumber']; $numberactivated = $_POST['numberactivated']; mysql_connect ("deleted", "deleted", "deleted") or die ('Error: ' . mysql_error()); mysql_select_db ("deleted"); $query = "INSERT INTO disney_database (id, firstname, lastname, pnumber, numberactivated, date) VALUES ('NULL', '".$firstname."', '".$lastname."', '".$pnumber."', '".$numberactivated."', 'NULL')"; mysql_query($query) or die('Error updating database'); header("location:menu.php"); echo "Database Updated With: ".$firstname."" - "".$lastname."" - "".$pnumber."" - "".$numberactivated.""; } else { echo "Database Error" { ?> Here is my problem. I set a one <form> on every form field I have including the submit button. Now whenever I press the submit button it redirects to insertvalues.php which it should be doing. In insertvalues i told it to query the form data and post it into my database's table. Its not doing that and tells me that it has a database error which i set it to tell me if something goes wrong. Anyone can help me? BTW I can manually query in the information using sql with phpmyadmin. so can someone please review my code for me? thanks big help! You can see what is happening. Visit www.chronoserve.com The username and password are "admin" The script below used to work fine but the HTTP_REFERER was unreliable so i added a re-direct if the HTTP_REFERER was unavailable and now nothing is being added to the MySQL BD, the script runs ok ie it sends the user back to where they come from, any ideas what could be wrong? <?php require("../include/mysqldb.php"); $uinwish = $_GET['uinwish']; $wishrefer = $_SERVER['HTTP_REFERER']; $wishdate = mktime(0, 0, 0, date("m"), date("d")+3, date("Y")); $rand_wish_cookie = $_COOKIE["wishtracking"]; $con = mysql_connect("$dbhost","$dbuser","$dbpass"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("$dbame", $con); //DB Stuff start code below //check if the uin and cookie have already been stored together. $sql = "select * from Wish_list_guest where usercookie='$rand_wish_cookie' and uinwish='$uinwish'"; $result = mysql_query($sql); $row = mysql_fetch_row($result); if (mysql_num_rows($result)!= 1) { $issetvar = "1"; if (!isset ($wishrefer)){ $host = $_SERVER['HTTP_HOST']; $extra = 'profile.php?uin='; header("Location: http://$host/$extra$uinwish"); exit; } if (isset ($wishrefer)){ header("Location: $wishrefer"); exit; } } if ($issetvar = 1) { mysql_query("INSERT INTO Wish_list_guest (usercookie, date_delete, uinwish, referwish) VALUES ('$rand_wish_cookie', '$wishdate', '$uinwish', '$wishrefer')"); mysql_close($con); if (!isset ($wishrefer)){ $host = $_SERVER['HTTP_HOST']; $extra = 'profile.php?uin='; header("Location: http://$host/$extra$uinwish"); exit; } if (isset ($wishrefer)){ header("Location: $wishrefer"); exit; } } ?> Hi all, Just curious why this works: Code: [Select] while (($data = fgetcsv($handle, 1000, ",")) !== FALSE){ $import="INSERT into $prodtblname ($csvheaders1) values('$data[0]','$data[1]','$data[2]','$data[3]','$data[4]','$data[5]','$data[6]')"; } And this does not: $headdata_1 = "'$data[0]','$data[1]','$data[2]','$data[3]','$data[4]','$data[5]','$data[6]'"; while (($data = fgetcsv($handle, 1000, ",")) !== FALSE){ $import="INSERT into $prodtblname ($csvheaders1) values($headdata_1)"; }it puts $data[#'s] in the database fields instead of the actual data that '$data[0]','$data[1]'... relates to. I wrote a script to create the values in $headdata_1 based on the number of headers in $csvheaders1 but can't seem to get it working in the sql statement. Thanks Hi I have a XML file as follows: <?xml version="1.0"?> <inspection_form> <inspection_type> <inspection_area_tlb>yard_and_lot</inspection_area_tlb> <inspection_area>Yard and Lot</inspection_area> <items> <item> <item_name>PID Signage/unauthorized sign on pole</item_name> <item_value>0</item_value> </item> <item> <item_name>Landscape well maintained</item_name> <item_value>0</item_value> </item> </items> </inspection_type> <inspection_type> <inspection_area_tlb>pump_island</inspection_area_tlb> <inspection_area>Pump Island and Canopies</inspection_area> <items> <item> <item_name>pumps clean and free of dirt</item_name> <item_value>0</item_value> </item> <item> <item_name>Approved trash cans/clean</item_name> <item_value>0</item_value> </item> </items> </inspection_type> </inspection_form> I want to insert into DB as follows: inspection_area_tlb inspection_area item_name item_value yard_and_lot yard and Lot PID Signage/unauthorized sign on pole 0 yard_and_lot yard and Lot Landscape well maintained 0 pump_island Pump Island and Canopies pumps clean and free of dirt 0 pump_island Pump Island and Canopies Approved trash cans/clean 0 I have written some php code. But every item node as insert for every 'inspection_type'. This is my code $filename="sample.xml"; if(filesize($filename)>0) { $oDOM = new DOMDocument(); $oDOM->loadXML(file_get_contents($filename)); foreach ($oDOM->getElementsByTagName('inspection_type') as $oBookNode) { foreach ($oDOM->getElementsByTagName('item') as $itmNode) { $sSQL = sprintf( "INSERT INTO inspections_master_tablename_import (INSPECTION_TYPE_DB_C_NAME, INSPECTION_TYPE_C_NAME, INSPECTION_TYPE_ITEM_C_NAME,INSPECTION_TYPE_ITEM_VALUE_C_NAME) VALUES ('%s', '%s', '%s', '%s')", mysql_real_escape_string($oBookNode->getElementsByTagName('inspection_area_tlb')->item(0)->nodeValue), mysql_real_escape_string($oBookNode->getElementsByTagName('inspection_area')->item(0)->nodeValue), mysql_real_escape_string($itmNode->getElementsByTagName('item_name')->item(0)->nodeValue), mysql_real_escape_string($itmNode->getElementsByTagName('item_value')->item(0)->nodeValue) ); $rResult = mysql_query($sSQL); if(mysql_errno() > 0) { printf( '<h4 style="color: red;">Query Error:</h4> <p>(%s) - %s</p> <p>Query: %s</p> <hr />', mysql_errno(), mysql_error(), $sSQL ); } } } } Can anyone help me pls. Hi Folks, I'm thinking this is simple, but just can't seem to figure it out. I use similar code for different tables that works fine, but for this table, it doesn't work so I'm thinking this is a MySQL issue. Here's the code: Code: [Select] $sqlmeds = mysql_query("SELECT ALL value FROM test WHERE type like 'media:'"); $meds = mysql_fetch_array($sqlmeds); foreach ($meds as $med){ echo "$med"; } and here is the relevant area of the table with row names "type" and "value" type value . . . media: painting media: works on paper media: collage/assemblage . . . When I run the query to find all 3 values from within phpMyAdmin, no problem, all three are returned, but when I run the exact same query from php, I only get "painting" returned, and oddly, I get an array with two values in it, both of which are "painting". Any ideas??? Thanks!! p.s. I also tried this just in case instead of the foreach, but same result: Code: [Select] for ($i=0; isset($meds[$i]); ++$i) { echo "$meds[$i]"; } I am trying to display a single value on my page and i cant seem to display it for the life of me. can someone tell me if im doing something wrong? this is what i have so far: <?php require_once('inc/common.inc.php'); // Connect to the database db_connect(); // Check and update the authentication. check_auth(); db("select * from ${db_name}_users where login_id = '$login_id'"); echo "$login_id"; ?> obviously there is a field in the database that corresponds to turns and it is int(4), ..... Now, i am able to display $login_id, but when i try to display another field, named turns, it just displays a blank page. Any pointers would be appreciated thank you. I have the following code. Basically I'm trying to count the amount of colours returned in the $colour variable. What I have is always returning 1, any ideas why? Code: [Select] $colour = $db->query("SELECT * FROM colours WHERE prod_id = ".$row['prod_id']." AND LENGTH(col_image_1) > 0 ORDER BY col_rank ASC LIMIT 1"); $colourcount = mysql_num_rows($colour); if($db->numrows($colour)) { $colour = $db->fetchrow($colour); } else { unset($colour); } Code: [Select] echo $colourcount; This: Code: [Select] echo "<pre>"; print_r($torrent->content()); echo "</pre>"; Returns: Code: [Select] Array ( [Eureka.S05E01.HDTV.XviD-ASAP\Eureka.S05E01.HDTV.XviD-ASAP.avi] => 367011826 [Eureka.S05E01.HDTV.XviD-ASAP\eureka.s05e01.hdtv.xvid-asap.nfo] => 4798 [Eureka.S05E01.HDTV.XviD-ASAP\Sample\eureka.s05e01.hdtv.xvid-asap.sample.avi] => 7883092 ) Needs to be inserted to MySQL like: In other words, the array $torrent->content() needs to be inserted to MySQL as new lines at columns "filename" and "size". Please help me.. What gets put in for the values is my problem. I have tried every way I can think of but I get errors in the code or I don't get the row inserted. Can anyone give me a code sample using $ variables, preferably a multi-line list? I would have to fix up my code to show you what I am trying as it is in between tries now. I have to be doing something wrong and may have to put together a simple test script but a working example would be better. Everything I look at on the web shows "xxxxx xxxx" examples not $variables. Thanks in advance. I have managed to create an update script that allows a user to submit changes to their details but I need help to finish of the code. I'm using sessions to login in members, here is my update.php code. After while($member = mysql_fetch_array($result)) { I would like to retrieve the new values entered by them to be displayed back to the previous form which uses $_SESSION to hold their information when they previously login. Any suggestions or ideas, as I think it's to do with clearing the session but unfamiliar on how to proceed. <?php include("config.php"); mysql_connect("$dbhost","$dbuser","$dbpass") or die(mysql_error()); mysql_select_db("$dbname") or die(mysql_error()); $id= mysql_real_escape_string($_POST['member_id']); $fname= mysql_real_escape_string($_POST['firstname']); $lname= mysql_real_escape_string($_POST['lastname']); $address= mysql_real_escape_string($_POST['address']); $town= mysql_real_escape_string($_POST['address2']); $county= mysql_real_escape_string($_POST['county']); $postcode= mysql_real_escape_string($_POST['postcode']); $telephone= mysql_real_escape_string($_POST['telephone']); $mobile= mysql_real_escape_string($_POST['mobile']); $username= mysql_real_escape_string($_POST['login']); $email=mysql_real_escape_string($_POST['email']); $id= $_POST['member_id']; $sql="UPDATE members SET firstname='$fname', lastname='$lname', address='$address', address2='$town', county='$county', postcode='$postcode', telephone='$telephone', mobile='$mobile', login='$username', email='$email' WHERE member_id='$id' LIMIT 1"; $result=mysql_query($sql) or die ("Error: ". mysql_error(). " with query ". $sql); $query = "SELECT * FROM members WHERE member_id = '$id'"; $result = mysql_query($query) or die(mysql_error()); while($member = mysql_fetch_array($result)) { } ?> Hello Guys, I am trying to insert a value in my table like this image.jpg,image2.jpg,image3.jpg Currently it just runs the image names together Here is my code.. I tried to use explode, but it just adds the word "array" in the table. Please advise $filename2 = $phstring; } $csv = $filename2; $fphoto = explode(',', $csv); // Insert ad details into mysql $query = "INSERT INTO ads (ad_type,ad_title,ad_body,ad_category,ad_photo,ad_member,ad_status,ad_city,ad_state,ad_zip)VALUES('".$ad_type."','".$ad_title."','".$ad_body."','".$catid."','".$fphoto."','".$vname."','".$ad_status."','".$city."','".$state."','".$zip."')"; Hello Guys, I have a question I have the following query $result3 = mysql_query("SELECT * FROM table1 WHERE ad_id='$id2'") or die(mysql_error()); $row3 = mysql_fetch_array( $result3 ); // Grab all the var $features = $row3['features']; I am turning it into an array (comma separated) $feature2 = explode(",", $features); print_r($feature2); ) The result is like so Array ( [0] => 5 [1] => 9 [2] => 13 I want to query the features for just the ids (F_name) are for the features . This query will show all.. I would like to just display the f_name values from the array query. // build and execute the query $sql = "SELECT * FROM features"; $result = mysql_query($sql); // iterate through the results while ($row = mysql_fetch_array($result)) { echo $row['f_name']; echo "<br />"; } Please Advise.. Thanks, Dan Hi People i'm a newb at this so bare with me but i currently have a php file called Newkpi.php which has a select statement in. this selects data from a table called "StaffList". this then populates the page with a html table with 14 records (this will increase/decrease over time) i then have some extra text boxes to enter more detail into like service amaount service date and so on. when i click the submit button i want it to cycle through each row and insert the data into a separate table called "Services". however i cannot for the life of me get this to work and need some help with it. people find attached the code for Newkpi and see if you can help me with this. in total i want it to take the names from stafflist and populate Services with the names and the extra detail which is entered on the page Much Thanx in advance SLOWIE while ( $categories = $category_result -> fetch_assoc() ) { $menu_sql = "select * from menu where category_id = {$categories['category_id']}"; $menu_result = $handle -> query( $menu_sql ); $category2 = strtoupper($categories['category']); echo '<h3 id="' . $category2 . '">' . $category2 . '</h3>'; while ($menu = $menu_result -> fetch_assoc()) { echo $menu['item_name'] . ' '; $size_sql = "select distinct size from size where category_id = {$categories['category_id']} order by size desc"; $size_result = $handle -> query( $size_sql ); while ($size = $size_result -> fetch_row()) { echo $size[0] . ' '; } //get base type from base_type table for the pizza category $type_sql = "select type from base_type where category_id = {$categories['category_id']}"; $type_result = $handle -> query( $type_sql ); while ($type = $type_result -> fetch_row()) { echo $type[0] . ' '; } //get price for each item from menu if it is not null $price_sql = "select price from menu where item_name = '{$menu['item_name']}'"; $price_result = $handle -> query( $price_sql ); while ($price = $price_result -> fetch_row()) { echo $price[0] . ' '; if( is_null( $price[0] ) ) { //get price from size table if price is null in menu table; //$categories = $category_result -> data_seek(0); $size = "double"; $category_id = $categories['category_id']; $item_id = $menu['item_id']; $type = 'deep'; echo $menu['item_id']; $price_size_sql = "select price from size where size = '$size' and category_id = $category_id and item_id = $item_id"; $price_size_result = $handle -> query( $price_size_sql ); while ($price_size = $price_size_result -> fetch_assoc()) { echo " {$price_size['price']} "; } } } echo '<br />'; } echo '<br />'; } I get duplicate vakues for $category_id = $categories['category_id']; $item_id = $menu['item_id']; dont know whats wrong it works for pizzas but not burgers, please help me. Hi all, I have a table... id | Name | Downloads | 01 | tom | 5 02 | thomas | 2 03 | tommy | 15 I need a button in my page whcih on submit would resent the 'downloads' column so all values are set to 0, Is this possible and how if it is? Thanks for any advice Say I have a table called artists with these fields (artistid, rank).
Then say I have an array called $rankadjustments with a value for each artist (like 1, 7, 3,-3, 5, 9, etc).
I am doing a MYSQL query that gets the info from artists table and sorts according to the rank field like this...
$sql = "SELECT * FROM artists ORDER BY rank";Easy enough. But what if I would like to bring that data back sorted by (rank + rankadjustment). For example, if the artist ranked 1st had a rank of "1" from mysql, but had a rankadjustment of "5" from the rankadjustment array, his "true" rank would be "6". Again, rankadjustment is NOT a field in my table, otherwise it would obviously be simple. It's calculated on the fly and stored in an array. FYI, the array has an index with their "artistid". For example, $rankadjustment[341][8] would be the artist with an artistid of "341" has a rank adjustment of 8. Is there a way to do this IN the query itself? It doesn't seem possible but wanted to find out for sure. If not, what is best way to do? I assume... Get the data sorted JUST by rank and put it all into an array, then create a new array that adds rank to rankadjustment and reorder by the "new" rank amount? I guess that wouldn't be too bad but again, wanted to make sure I'm not missing something that would allow me to do it all in the query (or just more efficiently). Thanks! Edited by galvin, 21 December 2014 - 09:13 PM. |
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