PHP - Looping Help
I am pulling data from an sql data base. I want it to displayed (Item # | Error button | Link) however as its looping with a while on the database info I cant seem to get it to loop on the item number so it shows 1, 2, 3,.... on each row.
Current coding is: while ($info = mysql_fetch_array($data)){ Print '<tr>'; Print"<td style='width: 15px;' class='cat-list'>$D</td>"; if ($info['id']==""){ Print"<td class='cat-list'> </td>"; }else{ Print"<td class='cat-list' style='width: 20px;'><img border='0' src='images/error.png' width='16' height='16'></td>"; } if ($info['link']==""){ Print"<td class='cat-list'> </td>"; }else{ Print"<td class='cat-list'><a target='_blank' href='".html_entity_decode(stripslashes($info[link]))."'>".substr(html_entity_decode(stripslashes($info[link])), 0, 85)."</a></td>"; } } How would I get the $D item to show 1 2 3... ect? Thanks, Jim Similar TutorialsHow come this doesn't loop? Everything is in the while loop.
My database connection is in the included file you see to begin the code which is what db_conx refers to just to be clear. Database connection is not an issue nor is getting values. I just get the first one and nothing more. No looping taking place here.
What I miss?
require('includes/db_connect.php'); $query = "SELECT * FROM events ORDER BY displayorder ASC"; $result = mysqli_query($db_conx, $query); while ($row = mysqli_fetch_array($result, MYSQLI_ASSOC)) { $pid = $row["id"]; $title = $row["title"]; $date = $row["date"]; $info = $row["info"]; $linkTxt = $row["linkTxt"]; $link = $row["link"]; $message = "<div id='events_holder'><table width='500' border='0' cellspacing='0' cellpadding='10'> <form action='edit_event_parse.php' method='post'> <tr> <td class='prayer_title'>Title:</td> <td><input type='text' name='title' class='admin_input' value='" .$title."' /></td> </tr> <tr> <td class='prayer_title'>Date:</td> <td><input type='text' name='date' class='admin_input' value='".$date."' /></td> </tr> <tr> <td class='prayer_title'>Link Text:</td> <td><input type='text' name='linkTxt' class='admin_input' value='".$linkTxt."' /></td> </tr> <tr> <td class='prayer_title'>Link URL:</td> <td><input type='text' name='link' class='admin_input' value='".$link."' /></td> </tr> <tr> <td class='prayer_title'>Event Details:</td> <td><textarea name='info' cols='20' rows='10' class='admin_area'>".$info."</textarea></td> </tr> <tr> <td><input type='hidden' name='pid' value='".$pid."' /></td> <td><input name='submit' type='submit' value='Edit Event' class='admin_submit'/></td> </tr> </form> </table> <p> </p> <hr /> <p> </p> </div>"; }Thanks! ANYONE WHO CAN HELP ME WITH MY LOOP? THIS IS THE CODE THANKS IN ADVANCE.
<?php $testTwo = 'bakit ayaw po gumana paulit ulit bakit'; $testOne = 'bakit paulit ulit bakit ulit'; $tTwo = explode(' ', $testTwo); $tOne = explode(' ', $testOne); echo"SIMILARITIES:</br>"; foreach($tOne as $first) { foreach($tTwo as $second) { if($second == $first) { echo $second.' '; } } echo"</br>"; } ?> THIS IS THE OUTPUT SIMILARITIES: bakit bakit paulit ulit bakit bakit ulit THIS IS MY EXPECTING OUTPUT. bakit paulit ulit bakit ulit lang i have this bit of code which is supposed to do a while loop of rows from a database then inside that does a while loop of columns, so its basically creating a html table of dynamic data from mysql. the column loop works fine, but the row one isnt, it only goes through and echos out the first row then stops. ive spent hours now trying to see why and i cant see it hence my call for help. $totalrows = 4; $columns = 5; $columncount = 1; $rowcount = 1; echo "<table>"; while ($rowcount <= $totalrows) { echo "<tr>"; $sql = "SELECT * FROM ville_map WHERE id = '$rowcount'"; $sql_result = mysql_query($sql, $connection); while ($row = mysql_fetch_array($sql_result)) { $c1 = explode(',', $row["c1"]); $c2 = explode(',', $row["c2"]); $c3 = explode(',', $row["c3"]); $c4 = explode(',', $row["c4"]); $c5 = explode(',', $row["c5"]); while ($columncount <= $columns) { $arraynum = ${'c'.$columncount}; if ($arraynum[2] > 0) { $playerimage = '<img src="images/player' .$arraynum[2]. '.png"'; } else { $playerimage = ""; } echo '<td background="images/' .$arraynum[0]. '.jpg" width="50" height="50">' .$playerimage. '</td>' ; $columncount++; } } echo "</tr>"; $rowcount++; } ?> </table> any help would be much appreciated. Hey, I have the following code that gets the name of the course from the XML. XML Snippet Code: [Select] <?xml version="1.0"?> <courses> <course> <id>70</id> <name>Marketing and Social Media</name> <dates> <date> <instance_id>6747</instance_id> <location /> <course_type>Day</course_type> <date_available>2011/07/13</date_available> <time_start>9:30</time_start> <time_end>17:00</time_end> <availibility>7</availibility> <running_dates> <running_date>2011/07/13</running_date> <running_date>2011/07/14</running_date> </running_dates> </date> </dates> </course> <course> </courses> PHP Code: [Select] $dom = new DomDocument(); $dom->load("courses.xml"); $xp = new domxpath($dom); $titles = $xp->query("/courses/course/name"); foreach ($titles as $node) { print $node->textContent . " "; } This prints out the course name fine. My question is how Can i get the rest of the data from the same query. For example why cant I do something like.. Code: [Select] ... foreach ($titles as $node) { print $node->name. " "; print $node->time_start. " "; print $node->course_type. " "; etc.. } So I want to loop through get the name and assign the rest of the nodes in there to variables or something. Take a look he http://answers.yahooapis.com/AnswersService/V1/questionSearch?appid=YahooDemo&query=test That is a generated XML file from Yahoo's API. If you take a look, it has a node titled "Question". With PHP, how can I loop through each "Question" node and grab all of it's children as well? I tried this code, but apparently it did not work: $req = "http://answers.yahooapis.com/AnswersService/V1/questionSearch?appid=YahooDemo&query=php"; $res = file_get_contents($req); $xml = simplexml_load_string($res); foreach ($xml->xpath('//Question') as $question) { // "//question" means for each question node echo((string)$question['Subject']." - ".(string)$question['Content']); // you get all the child nodes in $question } ok, here is some code: Code: [Select] <?php // Query member data from the database and ready it for display $sql = mysql_query("SELECT * FROM products"); while($row = mysql_fetch_array($sql)){ $product = $row["product"]; ?> <script type="text/javascript" src="http://code.jquery.com/jquery-1.4.2.min.js"></script> <script type="text/javascript" src="http://ajax.microsoft.com/ajax/jquery.validate/1.7/jquery.validate.min.js"></script> <script type="text/javascript"> $(document).ready(function(){ $("#myform").validate({ debug: false, submitHandler: function(form) { // do other stuff for a valid form $.post('process.php', $("#myform").serialize(), function(data) { $("#price").load("index.php #price"); $('#results').html(data); }); } }); }); </script> <form name="myform" id="myform" method="POST" action=""> <input type="hidden" name="hiddenField" id="hiddenField" value="<?php echo $product; ?>" /> <input type="submit" name="submit" value="Submit" style="background-color:lightgreen; height:50px; width:100px;"> </form> <?php } ?>and here is process.php Code: [Select] <?php include_once("/connect.php"); ?> <?php $price=$_POST['hiddenField']; $sql = "INSERT INTO cart (price) VALUES('$price')"; $rs = mysql_query($sql) or die ("Problem with the query: $sql<br>" . mysql_error()); echo mysql_error(); ?>. what is happening is it is supposed to be submitting form without page reload.......but only the first one in the loop does it. I want all of them to do it. can anyone help me do this properly. ok I'm a bit stuck here were I would think something would work easily im getting an error. What I am trying to loop is.. $data="UPDATE ts12 SET djid='$_POST[TS0]' WHERE id=1"; $data="UPDATE ts12 SET djid='$_POST[TS1]' WHERE id=2"; This would go on for 84 id's. So I figured I could just loop this line so I only have to type it once. Right now I have it set up for just testing 7 ids and I have this code.... if ($edit == yes) { for ($i=0; $i < 7; $i++){ $n=($i+1); $data.="UPDATE ts12 SET djid='$_POST[TS$i]' WHERE id=$n"; } if (!mysql_query($data,$con)) die('Error: ' . mysql_error()); }else{} The error I am getting is... PHP Parse error: syntax error, unexpected T_VARIABLE, expecting ']' in dir/page on line 6 What am I doing wrong here? I've made a loop here.. Code: [Select] <form name="formdeliver" method="post" action="addOrder.php" onSubmit="return confirm('Are you Sure the data inputed are correct? Click Ok to continue.')"> <div id="apDiv2" style="overflow:auto "> <?php $host="localhost"; $username="root"; $password=""; $db_name="SEdatabase"; $tbl_name="bottlenumbers"; mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); $sql="SELECT * FROM $tbl_name"; $result=mysql_query($sql); $name = $_SESSION['customername']; $q = $_SESSION['quantity']; echo "<table border='1'> <tr> <td><font size = '2'>Customer Name : $name </font></td></tr><tr> <td><font size = '2'>Quantity : $q </font></td> </tr> </table><br>"; for($i = 0; $i < $q; $i++){ echo "Bottle Number :"; echo "<select name=\"bottlenum[]\" onChange=\"this.name\"> <option>Select</option>"; if(mysql_num_rows($result)) { while($row = mysql_fetch_assoc($result)) { echo "<option>" .$row['BottleNumber']. "</option>"; } echo "</select>"; } else { echo "<option>No Customer Encoded</option></select>"; } echo "<font size = 2 >Type :</font> <select name=\"bottletype[]\" onChange=\"this.name\"'>'; <option selected>Select .. </option> <option> Slim </option> <option> Round </option> </select><br>"; } ?> <br> <input type="image" src="continue.png" width="100" height="25" name="login" border="0" /> </div> </form> So what it basically do is.. User will input some data w/c i included as $_POST['customername'] and $_POST['quantity'] So when the user will input 5 quantity.. i want my loop to have 5 pairs of 2 drop down list.. well i suceeded there. but, my problem is the 1st pair will output the .$row['BottleNumber']. w/c i included at the loop, and then the rest will have no output.. when i clicked them the dropdown list will only show the Select one. but for the 1st pair its working fine. Sorry for the bad english.. someone help me pls Ok I have this form with 6 fields that the user enters a geocaching code. In the database I have a table called cacheinfo. There are 6 enteries in the database in this table. Now Im trying to confirm that each field entered matches the right geo code. I have it working but I feel that its a very bad way of doing it my way. can someone please show me a better way as I have other situations I do something simliar and its just getting silly. Here is the code; if(isset($_POST['nextbtn'])){ $cache1 = trim($_POST['cache1']); $cache2 = trim($_POST['cache2']); $cache3 = trim($_POST['cache3']); $cache4 = trim($_POST['cache4']); $cache5 = trim($_POST['cache5']); $cache6 = trim($_POST['cache6']); $cache1 = mysql_real_escape_string($cache1); $cache2 = mysql_real_escape_string($cache2); $cache3 = mysql_real_escape_string($cache3); $cache4 = mysql_real_escape_string($cache4); $cache5 = mysql_real_escape_string($cache5); $cache6 = mysql_real_escape_string($cache6); $FetchCache = mysql_query("SELECT * FROM cacheInfo WHERE cacheInfoID='1'") or die('can not find cache information'); $cache1 = mysql_fetch_array($FetchCache); if($cache1 !==$cache1['cacheCode']){ $url = "/register-cache.php?error=true"; header("Location: $url"); } $FetchCache = mysql_query("SELECT * FROM cacheInfo WHERE cacheInfoID='2'") or die('can not find cache information'); $cache2 = mysql_fetch_array($FetchCache); if($cache2 !==$cache2['cacheCode']){ $url = "/register-cache.php?error=true"; header("Location: $url"); } $FetchCache = mysql_query("SELECT * FROM cacheInfo WHERE cacheInfoID='3'") or die('can not find cache information'); $cache3 = mysql_fetch_array($FetchCache); if($cache3 !==$cache3['cacheCode']){ $url = "/register-cache.php?error=true"; header("Location: $url"); } $FetchCache = mysql_query("SELECT * FROM cacheInfo WHERE cacheInfoID='4'") or die('can not find cache information'); $cache4 = mysql_fetch_array($FetchCache); if($cache4 !==$cache4['cacheCode']){ $url = "/register-cache.php?error=true"; header("Location: $url"); } $FetchCache = mysql_query("SELECT * FROM cacheInfo WHERE cacheInfoID='5'") or die('can not find cache information'); $cache5 = mysql_fetch_array($FetchCache); if($cache5 !==$cache5['cacheCode']){ $url = "/register-cache.php?error=true"; header("Location: $url"); } $FetchCache = mysql_query("SELECT * FROM cacheInfo WHERE cacheInfoID='6'") or die('can not find cache information'); $cache6 = mysql_fetch_array($FetchCache); if($cache6 !==$cache6['cacheCode']){ $url = "/register-cache.php?error=true"; header("Location: $url"); } // If all match now run the rest of my code...... } Hi, I was wondering why this won't work, i am INSERTING an array of authors like so in a table, see insertAuthor() method below: <?php class People { public function insertAuthor(){ $authArray = array(); array_push($authArray, mysql_real_escape_string($_POST['author'])); //Check if Pname exists foreach($authArray as $author): $query = "SELECT * FROM People WHERE Pname = '".$author."'"; $result = mysql_query($query); if(mysql_num_rows($result) > 0): $row = mysql_fetch_array($result); $Pid = $row['Pid']; //If exists Get their Pid and insert into PeopleCon $sql = "INSERT INTO PeopleCon(Pid, PCorder, PCdateadded, PCdeleted) VALUES (".$Pid.", (select MAX(PCorder) + 1), now(), 0)"; $result = mysql_query($sql); else: //Else Get MAX Pid $query = "SELECT MAX(Pid) as max FROM People"; $result = mysql_query($query); $max = mysql_fetch_array($result); $Pid = $max['max']; //Insert into People $sql = "INSERT INTO People (Pname, Pdateadded, Pdeleted) VALUES ('".$author."', now(), 0)"; $result = mysql_query($sql); //Insert into PeopleCon $sql = "INSERT INTO PeopleCon(Pid, PCorder, PCdateadded, PCdeleted) VALUES (".$Pid.", (select MAX(PCorder) + 1), now(),0)"; $result = mysql_query($sql); endif; endforeach; } } ?> However what i need to do is, check to see if an Author exists, if so INSERT into a table called PeopleCon, if the Author does NOT exist i need to INSERT into 2 different tables, People and PeopleCon... The reason i have the 2 tables is because People simply holds the persons personal details, but PeopleCon holds details linking to different tables. But this query does not work, i know there are better methods of getting this to work.. I do this in the front end: if(isset($_POST['add_author'])): People::insertAuthor(); endif; Is this possible? I would appreciate any help. Just want to get this working Thanks Kind regards Billy I want to display 50 results, theirfore I'm using a while loop to do so, the issue is, if $row consists of results lower then 50 (it will display them) and not display 50..so I'm trying to figure out a way so even if $row doesn't cosist of 50 i'll display what it has aswell as continue the $i (and for the rest display NO CONTENT). I've come up with the following on the spot (not sure if it even would work) - but was wanting a better solution. $i = 0; $results = mysql_num_rows($result); while ($row = mysql_fetch_assoc($result)) { $i++; echo $i .' CONTENT '.$row['name'].'<br />'; } if ($result < 50) { for($i <= 50 - $result; $i++) { echo $i .' NO CONTENT<br />'; } } i have some code which loops through a table, and displays the results. i have then added extra code so that it loops through another table, and prints out the reults, that are related to the first loop. so the page should look like menu submenu 1 submenu 2 submenu 3 menu 2 submenu 4 etc The problem is that the code only prints out the first row from the first loop and nothing else. <?php $list = "SELECT * FROM section_main"; $result = mysql_query($list) or die ("Query failed"); $numofrows = mysql_num_rows($result); echo "<table border='1' id='section_list'>"; echo "<tr><th>section_id</th><th>section_title</th></tr>"; for($j = 1; $j < $numofrows; $j++) { echo '<tr>'; $row = mysql_fetch_array($result); echo "<td>". $row['section_id'] . "</td><td>". $row['section_title'] . "</td>"; $query = "SELECT section_sub.section_sub_title, section_sub.section_title WHERE section_sub.section_title = " .$row['section_title']."ORDER BY section_sub_title"; $result2 = mysql_query($query) or die ("query failed2");//This part does not work $numofrows2 = mysql_num_rows($result2); for($i = 0; $i<$numofrows2; $i++){ $row2 = mysql_fetch_array($result2); echo '<tr>'.$row2['section_sub_title'].''; } } echo "</tr>"; echo '</table>'; ?> Any help on whats wrong would be great Hello All, I have two arrays. One called $number_array and one called $title_array. $number_array = (1,2,3,4); $title_array = ("Title One", "Title Two", "Title Three", "Title Four"); Now what I want to do is run through each of the arrays one by one each time I query my database, so for example the first time it would output the query and title as: Code: [Select] //First time SELECT * FROM tbl WHERE something = 1 <optgroup label="Title One"> //Second time SELECT * FROM tbl WHERE something = 2 <optgroup label="Title Two"> //etc.. so here's my code: <? echo '<select id="class" class="selectbox" name="class">'; $number_array = (1,2,3,4); $title_array = ("Title One", "Title Two", "Title Three", "Title Four"); $result = mysql_query ('SELECT * FROM tbl WHERE something = ".$number_array."') or die ('Error: '.mysql_error ()); echo '<optgroup label="".$title_array."">'; while ($row = mysql_fetch_array($result)) { echo '<option value="'.$row['id'].'" class="'.$row['name'].'">'.strtoupper($row['name']).'</option>'; } echo '</optgroup>'; echo ' </select>'; ?> Anyone please help? I am trying to get it to display the table where only some rows will be shown. It works on picking up each indivual value from the othere page but when it comes to displaying the table it only pics up the first value and only displays that. Here is my code bellow Code: [Select] <? session_start(); if ($_SESSION['userName']) {} else { header('location:../index.php'); } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Deliver-Pizza Order</title> <link href="css/order.css" rel="stylesheet" type="text/css" /> </head> <body> <div id="container"> <div id="header"> <img src="images/logo.jpg" alt="logo" /> <a href="log-off.php" id="logg-off" >log off</a> <ul id="nav"> <li><a href="home.php" target="_self">Home</a></li> <span> | </span> <li><a href="Pizza-Topping.php" target="_self">Pizza Topping</a></li> <span> | </span> <li><a href="order.php" target="_self">Order</a></li> <span> | </span> <li><a href="Account.php" target="_self">Account Details</a></li> <span> | </span> </ul> </div> <div id="Featured"> <img src="images/banner1.jpg" alt="banner" name="banner"" ID="banner"></div><!--end Featured--> <div class="featuredimage" id="main"> <div id="content" class="tiles"> <h1>Order</h1><hr /> <div id ='staff'><div style="width:920px; height:autopx; overflow:auto; heightmax:300px"> <table> <tr> <th>pizza number</th> <th>Type</th> <th>Size</th> <th>Topping</th> <th>Cost</th> <th>Information</th> </tr> <?php mysql_connect("localhost", "root", "")or die("cannot connect"); mysql_select_db("deliverpizza")or die("cannot select DB"); $sql="SELECT * FROM `pizzatopping` "; $result= mysql_query($sql); while($row = mysql_fetch_assoc($result)) { $pizza = $row['id']; if(isset($_POST["pizza$pizza"])) { if ($_POST["pizza$pizza"] == $row['id']){ $id = $row['id']; $dis="SELECT * FROM `pizzatopping` where id='$id'"; $result= mysql_query($dis); while($row =mysql_fetch_assoc($result)){ ?> <tr> <td><?php echo $row['id'] ?></td> <td><?php echo $row['type'] ?></td> <td><?php echo $row['size'] ?></td> <td><?php echo $row['topping'] ?></td> <td><?php echo $row['cost'] ?></td> <td><?php echo $row['info'] ?></td> </tr> <?php } } } } ?> </table> </div> </div> </div> </div> <!--end content--> <div id="footer"><span><p>Created By Ryan Williams</p></span></div><!--end footer--> </div><!--end container--> </body> </html> Hi all, I am trying to show information on a page if a value collected from a $_GET value is the same as a value in a Mysql database provided that the users email address links the email address next to the value in the mysql database. I have created the script however as there are more than one $row['value'] I can not get a foreach loop to work to scroll through all the $row['value'] values until it finds a matching one. Hope you can see from the code what I am talking about. The code I have is below: <?php $email = $_SESSION['logname']; $sql = "SELECT reg FROM sales WHERE email='$email'"; $result = mysqli_query($cxn,$sql) or die ("Couldn't execute query"); while($row = mysqli_fetch_assoc($result)) // NEED HELP INSERTING A FOREACH $ROW['REG'] SEE IF IT MATCHES $_GET['REG'] TYPE OF SCRIPT// { if ($row['reg'] == $_GET['reg'] ) { echo $row['reg'] . " is registered by you!"; } elseif ($row['reg'] != $_GET['reg'] ) { echo $_GET['reg'] . "<br>"; echo $row['reg']; echo $email . "<br>"; echo "I am sorry but the $_GET[reg] does not seem to be registered by you!"; exit(); } } ?> I'm trying to figure out what I'm doing wrong. For each recipient it runs each value which is an integer through the getUserByUserID function to verify that no values inside of the array are non users. But here's the part I'm not sure of and that's the if $recipient or $sender == FALSE. If ANY of the values are found to be non values then I want that if statement to activate. Code: [Select] foreach ($this->input->post('recipient[]') AS $recipient) { $this->users->getUserByUserID($recipient); } $sender = $this->users->getUserByUserID($this->input->post('sender')); // Verifies users were returned from database if (($recipient == FALSE) || ($sender == FALSE)) { // Users was not found in the database $outputArray['message'] = 'Either the recipient or yourself could not be found in the database!'; } Hi, I am having a problem, which if I don't get some help, promises to melt my brain. It may have a simple solution, but I cannot conjure it with my limited, and relatively new coding skills. I need to grab everything from a table, group them up by a tag and then, in their tag groups, print them out into div boxes. details below. Code: [Select] <?php // grab everything from the database and group by tag, sort by adddate $query = " select * from portfolio group by tag sort by adddate "; $result = mysql_query ($query); $row = mysql_fetch_array($result); /* I now need to loop through the array putting each tag group into separate div boxes.. HOW?? at the momenet I am using a while loop, but I think I should be using a for loop with foreach as well? */ // below is my current loop, which just takes each entry and sticks them all into seperate div boxes. which is crap. while ($row) { echo "<div class='boxgrid'><a href=".$row['fullPath']." rel='prettyPhoto[".$row['tag']."]'><img src=".$row['thumbPath']." title=".$row['desc']."/></a></div>"; $row = mysql_fetch_array($result); } include('./scripts/footer.php'); mysql_close($con); // my actual desired output would be like shown below ?> <div class="boxgrid"> <a href="./images/imagename01.jpg" rel="prettyPhoto[TAG]"><img src="./images/thumbs/thumbname.jpg"/></a> <a href="./images/imagename02.jpg" rel="prettyPhoto[TAG]"><img src="./images/thumbs/thumbname.jpg"/></a> <a href="./images/imagename03.jpg" rel="prettyPhoto[TAG]"><img src="./images/thumbs/thumbname.jpg"/></a> <a href="./images/imagename04.jpg" rel="prettyPhoto[TAG]"><img src="./images/thumbs/thumbname.jpg"/></a> </div> <div class="boxgrid"> <a href="./images/imagename01.jpg" rel="prettyPhoto[TAG]"><img src="./images/thumbs/thumbname.jpg"/></a> <a href="./images/imagename02.jpg" rel="prettyPhoto[TAG]"><img src="./images/thumbs/thumbname.jpg"/></a> </div> <div class="boxgrid"> <a href="./images/imagename01.jpg" rel="prettyPhoto[TAG]"><img src="./images/thumbs/thumbname.jpg"/></a> </div> <div class="boxgrid"> <a href="./images/imagename01.jpg" rel="prettyPhoto[TAG]"><img src="./images/thumbs/thumbname.jpg"/></a> </div> <div class="boxgrid"> <a href="./images/imagename01.jpg" rel="prettyPhoto[TAG]"><img src="./images/thumbs/thumbname.jpg"/></a> </div> if anyone here can help, It is quite likely that I may cry. Ben. Hello all. How would I loop through this array and find each "DTM" value? I want to be able to loop thru this array so that I can determine when to add 123, 456, ... 789, 1012 ... 123, 456 to a database. Hope this makes some sense... Thanks for any help on this one. Code: [Select] <?php $aryValues = array('DTM', '123', '456', 'DTM', '789', '1012', 'DTM', '123', '456'); ?> Ok i have been after the solution for this for a while and I have finally got it in a state where it is producing results but....... they are wrong so I will start from the beginning with what I have and what I am trying to do. I have these tables Members Id Name Clubs ID Name Permission ID Name Link MemberID PermissionID ClubID When a member joins a club thier ID ant the ID of the club are entered into the link table along with their permission (as a number) so MemberID PermissionID ClubID 01 02 01 I have a loop which is going to echo the clubs a member is a part of. So for my querys function GetUser($user) { $qFindUser = "SELECT * FROM members WHERE email = '$user'"; $rFindUser = mysql_query($qFindUser); $UserInfo = mysql_fetch_array($rFindUser); return $UserInfo; } function GetLinkByMemberID($link) { $qLink = mysql_query("SELECT * FROM link WHERE memberID = '$link'"); $Link = mysql_fetch_array($qLink); return $Link; } function GetClub1($clubs) { $qFindClub = mysql_query("SELECT * FROM clubs WHERE clubID = '$clubs'"); return $qFindClub; } function GetPermission($per) { $qPermission = mysql_query("SELECT * FROM `permissions` WHERE permissionID = '$per'"); $permission = mysql_fetch_array($qPermission); return $permission; } $User = GetUser($_SESSION['Username']); // returns as array from the login details all member details $Link = GetLinkByMemberID($User['memberID']); // returns as a fetch array all clubs the member is a part of $Club = GetClub1($Link['clubID']); // returns as the query $permission = GetPermission($Link['permission']); //returns as array so I can echo the permission word not ID Now the loop is limited by 3 so <?php $Club = mysql_fetch_array($Club); $stack3 = ($Club+$Link); for($i = 0; ($CP = ($stack3)) && $i < 3; $i++ ){ ?> <tr> <th scope="col"><img name="" src="" width="32" height="32" alt="" /></th> <th scope="col"><?php echo $CP['name']; //from the club table ?><span class="ownertext"> <?php echo $CP['permission']; //from the link table ?> The problem I'm having the the loop is returning the first record its selects 3 times and not echoing each club once. I have worked on it for so long I can no longer make sense of it. Can anyone see my errors and point out just how to fix it? Im guessing it involves something to do with how Im finding my permission but I really dont know. As im sure you can see from the code Im a php beginner so Im struggling to make sense of this. |