PHP - Drop Down List Display Help

I have a drop down list that contains expiration dates in the format 01/12 and if the user selected a certain drop down list I would like that same date selected. Does anyone know the code to do this?

Thanks.

Hello all,   I am new in php and would like to help me in in code.   I would like to implement a html form that will upload to my linux server some files, some info as well and will run a bash command.   To be more clear, users will: Send to the linux server two files (I have done it). Select from a drop down list a specific directory, and once this specific directory has been selected to activate one other drop down menu with its childs. Send all those info to a bash script. For case b, assume that we have the following structure my_dir/cars/brand1 my_dir/cars/brand2 my_dir/cars/brand3 my_dir/motors/brand5 my_dir/motors/brand6   the first drop down list should list only cars and motors while the second only brand1, brand2, and brand3 if cars is selected or brand5 and brand6 if motors is selected.   For case c, once the form is submitted, I would like the command: ./script.sh –a uploadedfile1 –b uploadedfile2 –c dropdown1 –d dropdpwn2   Any help is appreciated.   Best,

Hey guys,

I made in php an sql droplist. But I need some help. I want it to work like this.
When I select something from the list and click Add To Cart, that also the product gets send to the cart and not only the quantity.

you can check it out here : http://fhcs.be/cart-demo2/index.php

I also added my index.php as an attachment


Greets

hi,

I'm sruggling to get a drop down list to post the chosen value from an sql database..

could someone please point me in the right direction

many thanks!

I have two basic dropdown lists in a form, my question is this:

After selecting an item from the 1st dropdown list, the second dropdown list should automatically load only fields that are connected with the first selected item. (ex Site1 has Tank01 and Tank06, but Site2 has Tank03, Tank04 and also a Tank06).

What is the script needed / or how do I change my script to accommodate this?

Here is the basic script I use for the second dropdown list:

<?php
   include("../xxx.php");
   $cxn = mysqli_connect($host,$user,$password,$dbname);
   $query = "SELECT DISTINCT `diesel_tank_id` FROM `diesel_tank`
            ORDER BY `diesel_tank_id`";
   $result = mysqli_query($cxn,$query);
      while($row = mysqli_fetch_assoc($result))
      {
      extract($row);
      echo "<option value='$diesel_tank_id'>$diesel_tank_id</option>\n";
      }
?>

Hi,

I am trying to create a drop down list in php and I want the data to come from a table that I have created in phpmyadmin. The code that I have created allows me to select values from the drop down list and insert the rest of the data. However when I check the the table the SID and Cid are set to 0 and the grade field is empty and the comments field contains the grade. The SID and Cid are both composite keys.


<?php
        $sql = "SELECT Cid FROM course";
        $db1 = new DBStudent_Course();
        $db1->openDB();
        $result = $db1->getResult($sql);

        echo"<select name = Cid>";
        while ($row = mysql_fetch_object($result)) {
            echo "<option value = '" . $row->Cid . "'>$row->Cid</option>";
        }

        echo"</select>";
        echo "</p>";
        ?>

        <?php
        $sql = "SELECT SID FROM student";
        $db1 = new DBStudent_Course();
        $db1->openDB();
        $result = $db1->getResult($sql);

        echo"<select name = SID>";
        while ($row = mysql_fetch_object($result)) {
            echo "<option value = '" . $row->SID . "'>$row->SID</option>";
        }

        echo"</select>";
        echo "</p>";
        ?>
        <?php
        if (!$_POST) { //page loads for the first time
        ?>
            <form action="<?php echo $_SERVER['PHP_SELF'] ?>" method="post">
                grade:<input type="text" name="grade"/><br/>
                comments:<input type="text" name="comments" /><br />
                <input type="submit" value="Save" />
            </form>
<?php
        } else {
            $Cid = $_POST["Cid"];
            $SID = $_POST["SID"];
            $grade = $_POST["grade"];
            $comments = $_POST["comments"];
            $db1 = new DBStudent_Course();
            $db1->openDB();
            $numofrows = $db1->insert_student_course("", $SID, $Cid, $grade, $comments);
            echo "Success. Number of rows affected:
<strong>{$numofrows}<strong>";
            $db1->closeDB();
        }
?>


 

Hello,
I'm trying to get a drop down list (ordinary html function, select option ...) but I want it to start from an image. When you click the image I want the   drop down list to appear. Hove can I do this?

/Pelle

how do i loop this so that the option in the drop down list loop.

i tried this but get an error
Code: [Select]
<select name="age"><?php 

for ($i=10; $i<71; $i++;) {

echo "<option value='$i'>$i</option>"; 

}

?></select>

Basically I have a form and What I want it to do is when a user selects the 'For Sale' radio button the minimum and maximum prices will be displayed in the drop down list as "70,000"+ but when the user selects the 'To Rent' radial button then the minimum and maximum drop down list prices will change to e.g. "200"+. How would I do this?

Heres my Code for the form:
Code: [Select]

<div id="ptype">

<input type="radio" class="styled" name="ptype" value="forsale"/> For Sale

<p class="increase">
<input type="radio" class="styled" name="ptype" value="forrent"/> To Rent
</p>
<p class="increase">
<input type="radio" class="styled" name="ptype" value="any"/> Any
</p>

</div>
</td>
</tr>

</table>

<div id="table2">
<table id="NBtable">
<tr>
<td><p class="NBS">Number of bedrooms:</p></td>
<td><div id="NB">

<select name="min bedrooms">
<?php
$roomLimit = 5;
for($minRooms = 0; $minRooms <= $roomLimit; $minRooms++){
  if ($minRooms == 0){
    echo"<option value=\"0\" selected=\"selected\">No Min</option>";
  }
  else{
    echo "<option value=\"$minRooms\">$minRooms</option>";
  }
}
?>
</select> to

<select name="max bedrooms">
<?php
$roomLimit = 5;
for($maxRooms = 0; $maxRooms <= $roomLimit; $maxRooms++){
  if ($maxRooms == 0){
    echo"<option value=\"0\" selected=\"selected\">No Max</option>";
  }
  else{
    echo "<option value=\"$maxRooms\">$maxRooms</option>";
  }
}
?>
</select>
</div>
</td>

<td><p class="PR">Price range:</p></td>
<td><div id="PR">

<select name="min price" style='width:80px;'>
<?php
$priceLimit = 350;
for($minPrice = 40; $minPrice <= $priceLimit; $minPrice =( $minPrice+ 10)){
  if ($minPrice == 40){
    echo"<option value=\"0\" selected=\"selected\">No Min</option>";
  }
  else{
    echo "<option value=\"$minPrice000\">&pound;$minPrice,000</option>";
  }
}
?> </select> to

<select name="max price" style='width:80px;'>
<?php
$priceLimit = 350;
for($maxPrice = 40; $maxPrice <= $priceLimit; $maxPrice =( $maxPrice+ 10)){
  if ($maxPrice == 40){
    echo"<option value=\"0\" selected=\"selected\">No Max</option>";
  }
  else{
    echo "<option value=\"$maxPrice000\">&pound;$maxPrice,000</option>";
  }
}
?>
</select>
Thanks in advance.

Hey--I'm new to the forum, to php, and to web development in general.  I am using php to populate a drop-down list from a MySQL database, and then echo the text in a field associated with the selected value below.  I'm having no trouble creating the drop-down list, but I can't figure out how to echo the associated field below, or the ?Abbreviation=value that I expected in the url.

Here is the php file:

Code: [Select]
<!DOCTYPE HTML>
<html>
<head>
</head>
<body>

<form name="form" method="GET" action="<?php echo $_SERVER['PHP_SELF']; ?>">
<select>
<?php

$con = mysql_connect("localhost","root","root");

if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }

mysql_select_db("calculators", $con);

$result = mysql_query("SELECT * FROM calculator");

while($row = mysql_fetch_array($result))
  {
echo "<option type='text' name='Title' " . "value='" . $row['Title'] . "'>" . $row['Abbreviation'] . "</option>";
  }
mysql_close($con);
?>
</select>
<br>
<input type="submit" name="submit">
</form>
   
<?php echo $_GET['Title']; ?>

</body>
</html>

This is what the source code looks like in the browser:

Code: [Select]
<!DOCTYPE HTML>
<html>
<head>
</head>
<body>

<form name="form" method="GET" action="/calculators/index.php">
<select>
<option type='text' name='Title' value='Mean Arterial Pressure'>MAP</option><option type='text' name='Title' value='Body Mass Index'>BMI</option></select>
<br>
<input type="submit" name="submit">
</form>
   

</body>
</html>

And this is appearing in the url after I press submit:

Code: [Select]
?submit=Submit

I'm sorry if this is a silly question, or if I'm being long-winded in asking it.  I'm very new to web development, and I'm not sure exactly what information is necessary to solve the problem.  Also, though changes to the code are helpful, I may need an explanation to understand them...

Thanks,

Davis

This topic has been moved to Ajax Help.

http://www.phpfreaks.com/forums/index.php?topic=316053.0

Okay, so, here's my dilemma. I'm wanting to have it so someone can edit an item in the database, but it is a dropdown menu for the options to choose from.

How do I make it so that the option that the item currently is is what the default showing is?

For instance, if the item is for a "warrior", it will show warrior already in the dropdown menu. However, I could go to the dropdown menu and select a different option if I wanted. The {{class}} doesn't seem to give that default. Right now, it just defaults to "All" regardless of what the item truly goes to, such as "warrior".

Thanks in advance!!

Here's what I have for the coding:


<tr><td width="20%">Class:</td><td><select name="class" value="{{class}}">
<option value="1" {{class1select}}>All</option>
<option value="2" {{class2select}}>Alchemist</option>
<option value="3" {{class3select}}>Assassin</option> 
<option value="4" {{class4select}}>Dark Arts</option>
<option value="5" {{class5select}}>Dark Paladin</option>
<option value="6" {{class6select}}>Entertainer</option>
<option value="7" {{class7select}}>Hunter</option>
<option value="8" {{class8select}}>Mage</option>
<option value="9" {{class9select}}>Monk</option>
<option value="10" {{class10select}}>Paladin</option>
<option value="11" {{class11select}}>Pirate</option>
<option value="12" {{class12select}}>Priest</option>
<option value="13" {{class13select}}>Psion</option>
<option value="14" {{class14select}}>Scholar</option>
<option value="15" {{class15select}}>Thief</option>
<option value="16" {{class16select}}>Warlock</option>
<option value="17" {{class17select}}>Warrior</option>
</select></td></tr>

for some reason my code only posts the first word of the username even tho the last names are in the database.

www.checkmyweave.co.uk/new/dropdown.php

dropdown.php
Quote

<?php

mysql_connect("localhost","****","****");
mysql_select_db("checkmyw_database") or die("Unable to select database");

?>

<form action="/new/dropdown2.php" Method="POST">

User:<select name="username">
<?php
$result = mysql_query("SELECT * FROM members")
or die(mysql_error());
while($row = mysql_fetch_array( $result )) {
echo "<option value=".$row['username'].">";
echo $row['username']."</option>";
}
?>
</select>

<form action="/new/dropdown2.php" METHOD="POST">

<input type = "submit" value="New!">
</form>



dropdown2.php

Quote

<?php


$username=$_POST["username"];
echo $username ;
?>

So I was wondering if anyone could come up with a good way of having a drop down box list the dates of the previous week starting from Saturday.  The dates would need to go from Saturday to the coming/current friday.

Or would I just be better off having it list the days 'Saturday' to 'Friday'.

Any thoughts?