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PHP - Check If Firstname And Lastname Exist Before Inserting Records
I have a customer registration form up and running, the form allows customers to complete the forms and the data is then inserted into mysql db table via php form. I want to prevent duplicates records from already existing customers from creating a new records instead I want the customers to update their existing records in the backend. That is allow them to complete the form as normal, once they hit the submit button, the code should check if the customer first name and last name is already in the database if yes then it should update their records and if not it should insert new record to the table.
I do not want to alert the customer that their records already exist. I do not know where to start. Please help Thank you so much in advance for your help. Similar TutorialsHi, This is a part of a script that suggests firstname+lastname when a user tries to search. What I'm trying to do is that the suggestions become links to the users profile, but then I have to get the username from the same row as each of the names it suggests. Here's my code so far: $GetNames = "SELECT firstname, lastname, username FROM users"; $GetNamesConnect = $database->query($GetNames); While($row = mysql_fetch_array($GetNamesConnect)) { $a[] = $row['firstname'] . " " . $row['lastname']; } //get the q parameter from URL $q=$_GET["q"]; //lookup all hints from array if length of q>0 if (strlen($q) > 0) { $hint=""; for($i=0; $i<count($a); $i++) { if (strtolower($q)==strtolower(substr($a[$i],0,strlen($q)))) { if ($hint=="") { $hint=$a[$i]; } else { $hint=$hint.", ".$a[$i]; } } } } // Set output to "no suggestion" if no hint were found // or to the correct values if ($hint == "") { $response="no suggestion"; } else { $response= "<a href=\"profile.php?user=(THIS IS WHERE I NEED THE USERNAME)\">$hint</a>"; } //output the response echo $response; ?> Gud pm!! So i made this script to check if a username and password exist but it kinda fails me. It gives me a database connection error from my confirm_query() which means it returned false? so here's my code: Code: [Select] function check_if_exist($username, $password) { global $connection; $query = "SELECT username, hashed_password"; $query .= "FROM users "; $query .= "WHERE username = '$username' "; $query .= "AND hashed_password = '$password' "; $query .= " LIMIT 1"; $result_set = mysql_query($query, $connection); confirm_query($result_set); if(mysql_num_rows($result_set) == 1) { return true; } else { return false; } } my confirm_query(): Code: [Select] function confirm_query($result) { if(!$result) { die("Database connection failure ". mysql_error()); } } I have a another script to check if the email exist and it works perfectly, i dunno why this won't work properly.. maybe another simple mistake.. Any ideas or Violent reaction? Thanks! Hi.. So what i want to do is basicly to check if id XX exist in my database. How can this be done? Im thinking of something like: if(xx exist){do this} else{do this} Iv'e tried google etc before i posted here, but couldent really find anything where i found a soutable answer.. Hope someone can help! (: Is it possible to check if multiple rows exist at the same time. For example, if a row with the id "1" and another row with id "2" exists, and return something like true then false if only the first exists?
I have a file that provides tens of thousands to check and it takes forever. I know this sounds bad off the start, but it's not something that is run normally. Only to update my database with new additions.
Is there any good way to check a lot at once? I know you can insert many at a time and save a lot of time.
Hello, i want to check whether image exist or not, but i can't get any data about it. I have tried everything: getimagesize, file_exist, filesize, etc. <? $info = @getimagesize('http://jargames.eu/ic.php?lf=files/All phone/240x320/007-quantum_of_solace_240x320.jar'); if(isset($info['mime'])){echo 'Image exist';} else{echo 'Image doesnt exist';} ?> Ty, for your help. Hi. When a record is added its done via a form and processed via inserts.php. I need to use the same form but to recall the data (by id) so it can be editted. Cant work it out though. Help would be well appreciated! edit.php: <CENTER><B>Update a Vehicle</B></CENTER> <BR> <?php $query="SELECT * FROM cars"; $result=mysql_query($query); $i=0; while ($i < $num) { $carname=mysql_result($result,$i,"CarName"); $cartitle=mysql_result($result,$i,"CarTitle"); $carprice=mysql_result($result,$i,"CarPrice"); $carmiles=mysql_result($result,$i,"CarMiles"); $cardesc=mysql_result($result,$i,"CarDescription"); ?> <form action="showroomedit.php" method="post"> <CENTER>Vehicle Name:</CENTER> <CENTER><input type="text" name="CarName" value="<?php echo $carname; ?>"></CENTER> <br> <CENTER>Vehicle Type:</CENTER> <CENTER><input type="text" name="CarTitle" value="<?php echo $cartitle; ?>"></CENTER> <br> <CENTER>Vehicle Price:</CENTER> <CENTER><input type="text" name="CarPrice" value="<?php echo $carprice; ?>"></CENTER> <br> <CENTER>Vehicle Mileage:</CENTER> <CENTER><input type="text" name="CarMiles" value="<?php echo $carmiles; ?>"></CENTER> <br> <CENTER>Vehicle Description:</CENTER> <CENTER><textarea name="CarDescription" rows="10" cols="30" value="<?php echo $cardesc; ?>"></textarea></CENTER> <br> <CENTER><input type="Submit"></CENTER> </form> </TD> cant work out why it isnt working... I'm sorry to be back so soon, but I'm up against another mystery. I'm using the code below to enter a bunch of css data from a spreadsheet into a mysql table. I think the data file is OK. The array created by the script checks out with print_r. (There are many more records than shown. I truncated it to save space.) The problem is that I get this error regarding my sql statement, not the data or anything else: Fatal error: Uncaught PDOException: SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'check, name, phone, email, entry_fee, print_fee, image_name, description, med...' at line 1 in /Users/studio/Sites/BannerProject/b-as/_test_site/csv_to_array.php:242 Stack trace: #0 /Users/studio/Sites/BannerProject/b-as/_test_site/csv_to_array.php(242): PDO->prepare('INSERT INTO tbl...') #1 {main} thrown in /Users/studio/Sites/BannerProject/b-as/_test_site/csv_to_array.php on line 242 I've typed it in a dozen times to make sure there are no errors and keep getting the same error. I tried running a test file and gradually increasing the number of placeholders and at some point I always end up getting the same error, I can delete the most recent addition and it works again. Then I can add another placeholder exactly as before and it works the second time. It feels like a ghost in the machine. Any idea what I am doing wrong? An I typing something I don't see?
<?php
require '__classes/Db.php';
$csvData = '1,FALSE,Carol Lettko,,,TRUE,FALSE,Carol_Lettko-DSC_3022.jpg,Baby Herons/Brickyard,photo,,,
,,,925-285-0320,cjl164@aol.com,,,Carol_Lettko-DSC_0164.JPG,Heron/Brickyard,photo,,,
,,,,,,,Carol_Lettko-IMG_5723.jpg,Kayaker/Brickyard,photo,,,
,,,,,,,,,,,,
2,FALSE,Louise Williams,,,TRUE,FALSE,Louise_Williams-BirdsOfAFeatherAOPR.jpg,Alligator with Words,Book Excerpt,,,
,,,510-232-9547,lkw@louisekwilliams.com,,,Louise_Williams-Hope-TheFairyChickenAOPR.jpg,Hope The Fairy Chicken,,,,
,,,The d exatrfrfvct/.*tygrvurr,,,,,,,,,
,,,,,,,,,,,,
3,TRUE,Dorothy Leeland,,lelanddorothy@gmail.com,TRUE,FALSE,DJ_Lee-bridge at dusk 700px width.jpg,Bridge,photo,,,
,,,,,,,DJ_Lee-friends 700px width.jpg,Friends,photo,,,
,,,,,,,DJ_Lee-hybiscus 700 px wide.jpg,Hibiscus,photo,,,
,,,,,,,,,,,,
4,FALSE,Rita Gardner,,,TRUE,FALSE,Rita_Gardner-Explosion - Gardner photo.JPG,Explosion,photo,,,
,,,,tropicrita@msn.com,,,Rita_Gardner-Ferry Point tables and chair - Gardner.JPG,Ferry Point Tables,photo,, ,
,,,,,,,Rita_Gardner-Forks - Gardner photo.JPG,Forks,photo,,,
,,,,,,,,,,,,
';
$lines = explode(PHP_EOL, $csvData);
$array1 = array();
foreach ($lines as $line) {
$array1[] = str_getcsv($line);
}
$stmt = $pdo->prepare("INSERT INTO tbl_person_data (number, check, name, phone, email, entry_fee, print_fee, image_name, description, medium, select, orient, site) VALUES (?,?,?,?,?,?,?,?,?,?,?,?,?)");
foreach ($array1 as $row)
{
$stmt->execute('$row');
}
echo '<pre>';
print_r($array1);
echo '</pre>';
?>
Hi I'm using this code to insert multiple records. The code executes but nothing is entered into my database. This usually happens when there's a mismatch in data types.
How do I ensure that description goes in as text which in sql is wrapped in single quotes, but also make sure the other variables go in as numeric.
// an array items to insert
$array = array( 'theid' => $theid,
'descr' => $descr,
'costperunit' => $costperunit,
'quantity' => $quantity,
'costperlot' => $costperlot
);
// begin the sql statement
$sql1 = "INSERT INTO descriptions (jobid, description, costperunit, quantity, costperlot) VALUES ";
$it = new ArrayIterator( $array );
// a new caching iterator gives us access to hasNext()
$cit = new CachingIterator( $it );
// loop over the array
foreach ( $cit as $value )
{
// add to query
$sql1 .= "('".$cit->key()."','" .$cit->current()."')";
if( $cit->hasNext() )
{
$sql1 .= ",";
}
}
Hi everyone, I'm still learning, but getting intermediate in PHP now, but it is still challenge to learn. I'm trying to have php check to see if one file inside folder in server, seem I could not get it right, but I tested it on other site, it works, but not this script, I don't understand why it won't work...maybe logical is wrong? here my code:
if ($_POST['video']) {
$path1 = "UPLOADS/Home/";
$path2 = "UPLOADS/Breakfast/";
$path3 = "UPLOADS/Spider/";
$scan1 = scandir($path1);
$scan2 = scandir($path2);
$scan3 = scandir($path3);
$count1 = count($scan1) - 3;
$count2 = count($scan2) - 3;
$count3 = count($scan3) - 3;
if($count1 > 0) {
header('location:exist.html');
}elseif ($count2 > 0) {
header('location:exist.html');
}elseif ($count3 > 0) {
header('location:exist.html');
}
But other site, it works:
$scan = scandir($path);
$count = count($scan) - 3;
echo $count;
if($count > 1){
echo "Hello yourself!<br />";
}
Anyone will help will be appreciate! Thank you! Gary Edited April 3, 2019 by sigmahokiesHi! I wrote a small function that check if person_id already exist in the table called persons_web_tbl. If the person_id exist I get a message otherwise I add twitter/facebook profile of that person. I'm just trying to prevent duplicated entries this way. I will get person_id from table person_tbl, where are all people saved. The function actually works, I'm just curious if I'm on the right path. Thanks!
$person_id = 11;
class test extends dbh{
public function personExist($person_id) {
$sql = "SELECT person_id FROM persons_web_tbl WHERE person_id = ?";
$stmt = $this->conn->prepare($sql);
$stmt->execute([$person_id]);
$row = $stmt->fetchColumn();
if ($row > 0){
echo "found";
}else {
$person_web_twitter = "add something";
$sql = "INSERT INTO persons_web_tbl (person_web_twitter, person_id) VALUES (?, ?)";
$stmt = $this->conn->prepare($sql);
$stmt->execute([$person_web_twitter, $person_id]);
}
}
}
$person = new test ();
$person = $person->personExist($person_id);
Edited February 15, 2020 by mactron
//database
create table mydata (
id int(11) NOT NULL PRIMARY KEY AUTO_INCREMENT,
fname varchar(20),
phoneno int(12) NOT NULL
/*......*/
);
//class my data php
<?php
include('connect.php');
class InsertMydata {
public function insertnow($fname, $phoneno) {
$connect = new Connect;
$insrt = $db -> prepare('INSERT INTO mydata (fname, phoneno) VALUES (?,?)');
$insrt -> execute(array($fname, $phoneno));
}
}
?>
//insernow validate form
<?php
include('../classs/mydata.php');
//Declare data and error arrays
$errors = [];
$mydara = [];
if(!preg_match('/^[a-zA-Z]{4,15}$/', $_POST['fname'])) {
$errors['fname'] = 'Enter full name!';
}
//this block not working even the phone exist
$connect = new Connect;
$phoneno = $_POST['phoneno'];
$checkiexist = $connect -> prepare('SELECT * FROM mydata WHERE phoneno = ?');
$checkiexist -> execute([$phoneno]);
if($checkiexist->rowCount() > 0) {
$errors['phonenoexist'] = 'Try another phone number!';
}
if(!empty($errors)){
$data['success'] = false;
$data['errors'] = $errors;
}else{
$data['success'] = true;
$data['message'] = 'success message!';
$mydata = new InsertMydata;
$mydata -> insertnow($fname, $phoneno);
}
echo json_encode($data);
?>
//my ajax
$("#insertbtn").click( function(e) {
var fname = $('#fname').val(),
phoneno = $('#phoneno').val(),
$.ajax({
url: 'insertnow.php',
type: 'POST',
data: {fname:fname, phoneno:phoneno},
dataType: "JSON",
encode: true,
}).done( function (data) {
if (data.success == false) {
if (data.errors.fname) {
$('#fname').append('<p class="text-danger">' + data.errors.fname + '</p>');
}
if (data.errors.phonenoexist) {
$('.card-header').append('<div class="alert alert-info alert-dismissible" role="alert">
<button type="button" class="close" data-dismiss="alert" aria-label="Close"><span aria-hidden="true">×</span></button>'+data.errors.phonenoexist+'</div>');
}
} else {
$('.card-header').append('<div class="alert alert-success alert-dismissible" role="alert"><button type="button" class="close" data-dismiss="alert" aria-label="Close"><span aria-hidden="true">×</span></button>'+data.message+'</div>');
}
});
e.preventDefault();
});
//the problem is, the code insert data even if the phone exist why?
the problem is, the code insert data even if the phone exist why? Edited April 8 by mahendaCode: [Select] $arr = array('../', 'j/', 'AcidBB/', 'fileBOMB/', 'OurHome', 'up'); foreach ($arr as $value) { // echo "Value: $value<br /><br />"; if (is_dir($value)) { echo "<tr> <td>{$value}</td> <td><font color='#66FF33'>Exists</font></td></tr><br />"; } else { echo "<tr> <td>{$value}</td> <td><font color='#FF0000'>Does Not Exist</font></td></tr><br />"; } } ~~~ Solved after posting. Sorry. ~~~ Ok i have an Array of directories i need to check before the script installs itself, I know how to check for directories but i dont know how to scan each array in the list without calling each one seperately in Code: [Select] If() { } Else If { } Else If { } And so on and so on... My Question is, If a For Statement is neaded, How would i go about checking each string in the Array List? I want to pull some records plus unique key from one mysql table and then use them as questions in a form/questionnaire. The post form will have six radio buttons to the right of the fields pulled with the key posted but hidden and will wirte to another table. I guess this is a templating question- as I've successfully retrieved the table 1 records via a query - I just can't seem to use them in the form. Below is the code I'm using to view table "PCM1" <?php // query.php require_once 'login.php'; $db_server = mysql_connect($db_hostname, $db_username, $db_password); if (!$db_server) die("Unable to connect to MySQL: " . mysql_error()); mysql_select_db($db_database) or die("Unable to select database: " . mysql_error()); $query = "SELECT * FROM pcm1"; $result = mysql_query($query); if (!$result) die ("Database access failed: " . mysql_error()); $rows = mysql_num_rows($result); for ($j = 0 ; $j < $rows ; ++$j) { echo 'RID: ' . mysql_result($result,$j,'mcde') ; echo 'Statement: ' . mysql_result($result,$j,'oppclub') . '<br />'; ; } As the title says, how can i check if multiple arrays exist inside an array or not? Any help is greatly appreciated!
Hi guys, I need your help. I am checking on a database as I want to see if the records have been updated or not. Code: [Select] <?php session_start(); define('DB_HOST', 'localhost'); define('DB_USER', 'mydbuser'); define('DB_PASSWORD', 'mydbpass'); define('DB_DATABASE', 'mydbtable'); $errmsg_arr = array(); $errflag = false; $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD); if(!$link) { die('Failed to connect to server: ' . mysql_error()); } $db = mysql_select_db(DB_DATABASE); if(!$db) { die("Unable to select database"); } function clean($var){ return mysql_real_escape_string(strip_tags($var)); } $username = clean($_GET['user']); $password = clean($_GET['pass']); $test = clean($_GET['test']); $public = clean($_GET['public']); if (isset($_GET['user']) && (isset($_GET['pass']))) { if($username == '' || $password == '') { $errmsg_arr[] = 'username or password are missing'; $errflag = true; } } elseif (isset($_GET['user']) || (isset($_GET['test'])) || (isset($_GET['public']))) { if($username == '' || $test == '' || $public == '') { $errmsg_arr[] = 'user or others are missing'; $errflag = true; } } if($errflag) { $_SESSION['ERRMSG_ARR'] = $errmsg_arr; echo implode('<br />',$errmsg_arr); } else { $qry="SELECT * FROM members WHERE username='$username' AND passwd='$password'"; $result=mysql_query($qry) or die('Error:<br />' . $qry . '<br />' . mysql_error()); if ($username && $password) { if(mysql_num_rows($result) > 0) { $qrytable1="SELECT images, id, test, links, Public FROM user_channel_list WHERE username='$username'"; $result1=mysql_query($qrytable1) or die('Error:<br />' . $qry . '<br />' . mysql_error()); while ($row = mysql_fetch_array($result1)) { echo "<p id='test'>"; echo $row['test'] . "</p>"; echo '<p id="images"> <a href="images.php?test=test&id='.$row['id'].'">Images</a></td> | <a href="http://' . $row["links"] . '">Link</a> </td> | <a href="delete.php?test=test&id='.$row['id'].'">Delete</a> </td> | <span id="test">'.$row['Public'].'</td>'; } } else { echo "user not found"; } } elseif($username && $test && $public) { $qry="SELECT * FROM members WHERE username='$username'"; $result1=mysql_query($qry) or die('Error:<br />' . $qry . '<br />' . mysql_error()); if(mysql_num_rows($result1) > 0) { $qrytable1="SELECT Public FROM user_channel_list WHERE username='$username' && test='$test'"; $result2=mysql_query($qrytable1) or die('Error:<br />' . $qry . '<br />' . mysql_error()); if(mysql_num_rows($result2) > 0) { $row = mysql_fetch_row($result2); mysql_query("UPDATE user_list SET Public=('$_GET[public]') WHERE username='$username' AND test='$test'"); echo "update!"; } else { echo "already updated!"; } } else { echo "user not found"; } } } ?> When I run debug the code on my php, if i input the data in a url bar while the records are the same as the data that I enter in the url, i should get the print out on my php "already updated", but I keep getting "update!". Do you know how i can check on mysql database to see if the records have been updated or not?? Hi everyone, I have the task of building a PHP page where users can enter or remove as many records as they like into different categories. This then makes the number of records entered unknown, and therefore it becomes more complicated. To make this clearer, I have attached an image of what I am trying to do. Two questions: - Before submitting the form, how can each record entry be matched with the correct category? (maybe hidden form fields somehow?) - What is the best way of inserting each record (and it's associated category) into a MySQL database table from a single form submit? I want to try and keep this as simple as possible as the data will later be updated, removed etc. I'm experiencing a brain fart and just cannot picture the best way of going about this Any help and advice is much appreciated! Thanks in advance. Code: [Select] Basic table schema example... CATEGORY TABLE ---------------------------- | catid | category | ---------------------------- | 1 | Category A | | 2 | Category B | etc. etc. ---------------------------- DATA ENTRY TABLE ---------------------------- dataid | catid | data | -------------------------------- | 1 | 2 | data xyz | | 2 | 1 | data zyx | etc. etc etc. -------------------------------- Hello all, I have another project I’m working on a php login and I am inserting a record in the db I’m checking the table to see if it exists or not so there can’t be 2 users with the same username but I am working with create the form submits but nothing is inserted. Also appreciate suggestions in code to make my php better.
<?php
//mySQL database config
require_once "config.php";
// Define all variables and initialize them as 'empty'
$name = $username = $password = $password2 = "";
$nameerror = $usernameerror = $passworderror = $password2error = "";
// Process data when the form is submitted.
if($_SERVER["REQUEST_METHOD"] == "POST") {
//Name check
if(empty(trim($_POST["name"]))) {
$nameerror = "Please enter a name.";
} else {
$name = trim($_POST["name"]);
}
// Validate 'Username'
if(empty(trim($_POST["username"]))) {
$usernameerror = "Please enter a Username.";
} else {
// Prepare a SELECT statement.
$sql = "SELECT userid FROM users WHERE username = :username";
if($stmt = $pdoConn->prepare($sql)) {
// Bind variables to prepared statement as parameters
$stmt->bindParam(":username", $param_username, PDO::PARAM_STR);
// Set parameters
$param_username = trim($_POST["username"]);
// Attempt to execute prepared statement
if($stmt->execute()) {
if($stmt->rowCount() == 1) {
$usernameerror = "Username is already taken.";
} else {
$username = trim($_POST["username"]);
}
} else {
echo "Something went wrong with SELECT, please try again later.";
}
}
// Close $stmt
unset($stmt);
}
// Validate Password
if(empty(trim($_POST["password"]))) {
$passworderror = "Please enter a password.";
} else if (strlen(trim($_POST["password"])) < 6) {
$passworderror = "Password must have at least 6 characters.";
} else {
$password = trim($_POST["password"]);
}
// Validate Confirm Password.
if(empty(trim($_POST["password2"]))) {
$password2error = "Please confirm your password";
} else {
$pass2 = trim($_POST["password2"]);
if(empty($password2error) && ($password != $pass2)) {
$password2error = "Passwords <b>DID NOT</b> match.";
}
}
//Check for inputs on form to continue.
// Error checks or input checks.
if(empty($name) && empty($username) && empty($password) && empty($password2)) {
// Prepare SELECT statement
$sql = "INSERT INTO users (name, username, password) " .
"VALUES (:name, :username, :password)";
if($stmt = $pdoConn->prepare($sql)) {
// Bind variables to prepared statement as parameters
$stmt->bindParam(":name", $param_name, PDO::PARAM_STR);
$stmt->bindParam(":username", $param_username, PDO::PARAM_STR);
$stmt->bindParam(":password", $param_pass, PDO::PARAM_STR);
// Set parameters
$para_name = $name;
$param_username = $username;
$param_pass = password_hash($password, PASSWORD_DEFAULT);
// attempt to execute the prepared Statement
if($stmt->execute()){
header("Location: ../index.php");
} else {
echo "Something went wrong with INSERT";
}
}
// Close Statement
unset($stmt);
}
// Close connection
unset($pdoConn);
}
?>
i have error where my code should update existing data where id exist, it get updated ..but the others data is disappeared .only the data updated is remained $sql1 ="select*from semakan_dokumen where email='$stdEmail'";
$sqlsearch1 = mysqli_query($dbconfig,$sql1);
$resultcount1 = mysqli_num_rows($sqlsearch1);
if($resultcount1 > 0){
$query1=("UPDATE semakan_dokumen set student_id='$noMatrik', email= '$stdEmail', surat_tawaran='$fileName', ic='$fileName1',sijil_lahir='$fileName2',sijil_spm= '$fileName3',sijil_sekolah= '$fileName4', sijil_dip= '$fileName5',sej_julai='$fileName6',bm_julai='$fileName7',muet='$fileName8', mid1='$fileName9',yuran= '$fileName10',umpa_bend1= '$fileName11',umpa_bend2='$fileName12',bpkp='$fileName13', penaja='$fileName14',kesihatan= '$fileName15', jhepa='$fileName16' where email= '$stdEmail' ");
}else{
//filezip
$query1 = "INSERT INTO semakan_dokumen (email,surat_tawaran,ic,sijil_lahir,sijil_spm,sijil_sekolah,sijil_dip,sej_julai,bm_julai,muet,mid1,yuran,umpa_bend1,umpa_bend2,bpkp,penaja,kesihatan,jhepa) VALUES ('$stdEmail','$fileName','$fileName1','$fileName2','$fileName3','$fileName4','$fileName5','$fileName6','$fileName7','$fileName8','$fileName9','$fileName10','$fileName11','$fileName12','$fileName13','$fileName14','$fileName15','$fileName16')";
}
i wanting users to be able to update there email address and check to see if the new email already exists. if the email is the same as current email ignore the check. i have no errors showing up but if I enter a email already in the db it still accepts the new email instead of bringing the back the error message. Code: [Select] // email enterd from form // $email=$_POST['email']; $queryuser=mysql_query("SELECT * FROM members WHERE inv='$ivn' ") or die (mysql_error()); while($info = mysql_fetch_array( $queryuser )) { $check=$info['email']; // gets current email // } if($check!=$email){ // if check not equal to $email check the new email address already exists// $queryuser=mysql_query("SELECT * FROM members WHERE email='$email' "); //$result=mysql_query($sql); $checkuser=mysql_num_rows($queryuser); if($checkuser != 0) { $error= "0"; header('LOCATION:../pages/myprofile.php?id='.$error.''); } } cheers it is displaying the lastnames in the order they are in the profile but do not know how to get it to sort by lastname - please help <?php $lines = file('database/profile.txt'); foreach($lines as $thisline){list($p_id,$p_status,$p_filestart,$p_filemodified,$p_first,$p_middle,$p_last,$p_nick) = explode('|',$thisline);{ $names []= $p_last.', '.$p_first.' '.$p_middle.'.'; foreach($names as $value); {echo ''.$value.'<br>';}}} ?> |
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