PHP - Can I Put My Code Into A Single Global In Oop ???

I use $db object to handle database function like $db->get_row for example. Is there any way that I don't need to put into every function global $db or do I actually need to repeat in every function global $db?

Code: [Select]
function example(){
   global $db //Do I need to repeat this in each function?
}

It's a function=>

Code: [Select]
function _wp_call_all_hook($args) {
global $wp_filter;
//var_dump($wp_filter);
//exit();

reset( $wp_filter['all'] );
do {
foreach( (array) current($wp_filter['all']) as $the_ )
if ( !is_null($the_['function']) )
call_user_func_array($the_['function'], $args);

} while ( next($wp_filter['all']) !== false );
}

Why is $wp_filter variable declared as global ? Was $wp_filter assigned before ?

Just wanted to know if $_Session was a global thing or does php require cookies setup?   I assumed that I could do something like this:

PAGE: A.php
session_start();
$_Session['Cat'] = 'Meow';

// -----------------------

PAGE: B.php
if (isset($_Session['Cat']) && !empty($_Session['Cat'])){
echo $_Session['Cat'];
}
OUTPUT: Meow

// -----------------------
PAGE: C.php
if (isset($_Session['Cat']) && !empty($_Session['Cat'])){
echo $_Session['Cat'];
}

OUTPUT: Meow

I can't seem to get this to work.   Page: Handler.inc

	// ========================================================= Session Log in / out
	public function logon($username, $password){
		if ($username == "admin" && $password == "coffee"){
			
				session_start();
				$_SESSION['USER_STATUS'] = '1';
				
				echo 'IN SESSION LOGIN HANDLER';
				echo $_SESSION['UserLogged'];
			}
		}
		
	public function logout(){
				$_SESSION['USER_STATUS'] = '0';
				
				echo 'IN SESSION LOGOUT HANDLER';
				
				session_destroy();
				//session_unset();
		}

Page: index.php

if (!isset($_SESSION['USER_STATUS']) && empty($_SESSION['USER_STATUS']) || $_SESSION['USER_STATUS'] == 0){
		if (isset($_POST['username']) && !empty($_POST['username']) && isset($_POST['password']) && !empty($_POST['password'])){
			
			$username = $_POST['username'];
			$password = $_POST['password'];
			
			echo $handler->logon($username, $password); 
		
			}

<LOGIN FORM CODE>

}else{

		if (isset($_SESSION['USER_STATUS']) && !empty($_SESSION['USER_STATUS']) || $_SESSION['USER_STATUS'] == 1){
			echo 'Session name: '. $_SESSION['USER_STATUS'];
		}

	if (isset($_POST['btn_logout']) && !empty($_POST['btn_logout'])){

		$handler->logout();
		echo '<br />Logged out<br />';
		
		}

<LOGOUT FORM BUTTON CODE>

}

Could someone point me in the right direction please. It does not seem to hold its session.        

i have two classes and I am trying to call one class in through another here is my code but my welcome is not showing at all ever when i change the var's to 1
Code: [Select]
class site {
     function DisplayContent ($page) {
        global $Users;
        echo '<div align="center">
                <div id="Header">
                <div id="NavBar">';
                if ($Users->logged == 1) {
                    echo 'Welcome '. $Users->user .' - <a href="?page=viewreminders">View Reminders</a> - <a href="?page=addreminder">Add Reminder</a> - <a href="logout.php" id="Logout">Logout</a>';
                } else {
                    echo '<a href="?page=login">Login</a> - <a href="?page=register">Register</a> - <a href="?page=forgotpassword">Forgot Password?</a>';
                }
        echo '</div>
            </div>
            <div id="Content">';
            $this->ShowPage($page);
            echo '</div>
            <div id="Footer">Copyright &copy; '.date('Y').'<br />
            Coded and Designed by Chris Cloyd</div>
        </div>';
     }
}

class users {
   
    var $logged;
    var $user;
    var $email;
    var $level;
   
    function LogIn ($name,$email,$level) {
        $this->logged =  1;
        $this->user = $name;
        $this->email = $email;
        $this->level = $level;
    }
   
    function LogOut () {
        $this->logged =  "0";
        $this->user = "";
        $this->email = "";
        $this->level = "";
    }
   
}

hello,

ok if i set a Global on index.php  (wwwroot/admin/index.php) it works

Code: [Select]
$page1='hello from page1 on index';
global $page1;
echo $page1;

i can echo $page1 on other pages like (wwwroot/admin/pages/home.php) and it will echo out "hello from page1 on index".

GREAT

but if i write a Global on (wwwroot/admin/pages/home.php) it does not work. i also can not echo it out on any other page

Code: [Select]
$page2='hello from page2 on home';
global $page2;
echo $page2;



why is this ???

I have some variables that I have set with the global command but they don't seem to be working correctly. It's probably my order of operation but not sure. Here's the stripped down version of whats going on:



locator()

//functions
function geoip()
global $zip, $city, $areacode, $metrocode, $state, $country, $latitude, $longitude;

function locator()
geoip()
use globals from geoip pass to-
ad_display()

function ad_display()
does some work
stat_tracking()

function stat_tracking()
access global $zip, $city, $areacode, $metrocode, $state, $country, $latitude, $longitude;


The problem is once I call stat_tracking() and try to access the global variables, they are all empty. Just to clarify the chain of events is: page loads, calls locator(), locator() calls function geoip() fine then passes work to ad_display(), ad_display() calls stat_tracking(), stat_tracking() now tries to access the globals I made but all variables are blank if I echo them.

Any ideas?

<?php


function getglobal() {

global $my_global;

echo "The value of \$foobar is '$foobar' <br />";


}

$my_global = 20;

getglobal();

?>

It's supposed to give the result,

Quote

'The value of $my_global is '20';



But instead when I try it, its giving me

Quote

Notice: Undefined variable: foobar in C:\wamper\www\php\index.php on line 17
The value of $foobar is ''



So I don't really understand what's happening and why it's not working.

Through out my program I have used
global $mysqli;
as a connection to my database - this has worked fine so far.

Now I have called
$sql_statement = "SELECT * FROM items WHERE name='$itemName'";
$itemStats = mysqli_fetch_array(mysqli_query($mysqli, $sql_statement), MYSQLI_ASSOC);
via a function and I get the following warnings -
Quote

Warning: mysqli_query() expects parameter 1 to be mysqli, null given in /functions/getdata.php on line 27
Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, null given in /functions/getdata.php on line 27

it still works though and returns the correct information.

If I take the code out of the function and use it normally then I get no Warnings - but this defeats the whole purpose of having functions!

How do I get rid of the warnings? (and no, I don't mean turn the warnings off  )

I need the following three variables to be available globally, that is to every page.
(An common header.html uses them at every page).
Please teach me how to initialize them.
(inside the header.html maybe?)

          
'U_M_CODE'   => append_sid("{$phpbb_root_path}faq.$phpEx", 'mode=bbcode'),
'U_M_TERMS'  => append_sid("{$phpbb_root_path}ucp.$phpEx", 'mode=terms'),
'U_M_PRV'    => append_sid("{$phpbb_root_path}ucp.$phpEx", 'mode=privacy'),        


Thank you.
   

Sorry, this will be a simple question.  Say you define two global variables in your functions.php file as:
GLOBAL  $salesTax = .07;
GLOBAL $shipping = 5.00;

Those variables would be accessiible in the checkout.php page, right? 

If I want to load some user information from the database into an object/array and share it throughout my application, what's the best approach for this? Here is what I thought of doing:

- I can call a function (e.g user_info() ) that will return the user information whenever I need it , but It'll have to run a DB query each time I call it.

- Load user information once from the DB, assign it into a global array/object, then call that object whenever I need it.

A lot of people recommended against using global variables, but I think performance wise it's better than running a query each time.

Are there any better alternatives than the above approaches?

This topic has been moved to CSS Help.

http://www.phpfreaks.com/forums/index.php?topic=356577.0

        $errors=0;

         //NEW USER NAME HAS BEEN SUBMITTED, CHECK IT OUT AND THEN ADD IF OKAY
$newuser=$_REQUEST['newuser'];

function TryAgain(){
global $errors;
$errors++;
echo '<br/><br/>Please try again <a href="index.php?locate=admin&sub=add_admin">here</a>';
echo "<br/>errors=[$errors]";
}



echo "<br/>Trying to add user: $newuser<br/><br/>";
if ($newuser){
}else{
// field was left blank, report this to user and give them option to try again
echo '<br/>Field was left empty, you must pick a username.';TryAgain();
}

if (strlen($newuser)<5){echo 'Username should be at least 5 characters.';TryAgain();}

if (!$errors){echo "continue to SQL [errors=$errors]";}



what is wrong with this code?
For some reason if I increment $errors with $errors++   within the function it doesn't increment outside the function's scope. even though I declare it as a global at the start of the function. I know I'm doing something stupid here but can somebody please tell me what it is?

Thanks

Hey,

I've been developing a browsergame. In this you are able to produce something ("weed"). Now I've got some kind of trouble with the function that is responsible for updating the "weed" on the user accounts.

Im going to explain, how my script is working

First step:

Loading the datas from "worlds". In this case id, weed_factor, weed_basis. What this is required for you will see in the next steps 


<?php

include 'includes/settings/mysql.php';
mysql_connect($dbhost, $dbuser, $dbpass);
mysql_select_db($dbbase);

$time = time();

$update_weed_world_data_sql = "SELECT id, weed_factor, weed_basis FROM worlds";
$update_weed_world_data_res = mysql_query($update_weed_world_data_sql) OR DIE (mysql_error());
while($update_weed_world_data_while = mysql_fetch_assoc($update_weed_world_data_res)){
$update_weed_world_id = $update_weed_world_data_while['id'];
$update_weed_world_basis[$update_weed_world_id] = $update_weed_world_data_while['weed_basis'];
$update_weed_world_factor[$update_weed_world_id] = $update_weed_world_data_while['weed_factor'];
global $update_weed_world_basis;
}


Second step:

This is the function which is editing each account by the data given as parameters.


function do_update_weed($profile_id,$world,$update,$level,$time){
$update_weed_period = $time - $update;
$update_weed_add = ($update_weed_period / 3600 * $update_weed_world_basis[$world] * pow($update_weed_world_factor[$world],$level)) +1;
echo $update_weed_world_basis[$world];
echo "<br>";
mysql_query("UPDATE profiles SET weed = weed +$update_weed_add, weed_update = $time WHERE id = $profile_id LIMIT 1");
}


Note:


echo $update_weed_world_basis[$world];


doesnt result an output.

In step three, the accounts are loaded:


function todo_update_weed($time){
$todo_update_weed_sql = "SELECT * FROM profiles WHERE weed_update < $time";
$todo_update_weed_res = mysql_query($todo_update_weed_sql) or die (mysql_error());
while($todo_update_weed_while = mysql_fetch_assoc($todo_update_weed_res)){
do_update_weed( $todo_update_weed_while['id'],
$todo_update_weed_while['world_id'],
$todo_update_weed_while['weed_update'],
$todo_update_weed_while['level_farm'],
$time
);
}
}


And the last step is calling function "todo_update_weed" with the time.


todo_update_weed($time);


I script calculate the time between the last update and the current time. This make a difference in time. With this value I calculate something else. And then the update time has to be saved.

The script has just working fine, when I set the variable "$update_weed_add" with a fix value. But by now the script doesn't work, because I don't know how to make the array available inside functions.

I considered whether I put the database-function for the world_data inside the function that updates the profiles. But if I do this, the database will be called thousands of times...

Hope anybody has a nice idea to fix the problem