PHP - Php Update Query Changed All Rows. Please Help

Hello all,   Based on the suggestion of you wonderful folks here, I went away for a few days (to learn about PDO and Prepared Statements) in order to replace the MySQLi commands in my code. That's gone pretty well thus far...with me having learnt and successfully replaced most of my "bad" code with elegant, SQL-Injection-proof code (or so I hope).   The one-and-only problem I'm having (for now at least) is that I'm having trouble understanding how to execute an UPDATE query within the resultset of a SELECT query (using PDO and prepared statements, of course).   Let me explain (my scenario), and since a picture speaks a thousand words I've also inlcuded a screenshot to show you guys my setup:   In my table I have two columns (which are essentially flags i.e. Y/N), one for "items alreay purchased" and the other for "items to be purchased later". The first flag, if/when set ON (Y) will highlight row(s) in red...and the second flag will highlight row(s) in blue (when set ON).   I initially had four buttons, two each for setting the flags/columns to "Y", and another two to reverse the columns/flags to "N". That was when I had my delete functionality as a separate operation on a separate tab/list item, and that was fine.   Now that I've realized I can include both operations (update and delete) on just the one tab, I've also figured it would be better to pare down those four buttons (into just two), and set them up as a toggle feature i.e. if the value is currently "Y" then the button will set it to "N", and vice versa.   So, looking at my attached picture, if a person selects (using the checkboxes) the first four rows and clicks the first button (labeled "Toggle selected items as Purchased/Not Purchased") then the following must happen:   1. The purchased_flag for rows # 2 and 4 must be switched OFF (set to N)...so they will no longer be highlighted in red. 2. The purchased_flag for row # 3 must be switched ON (set to Y)...so that row will now be highlighted in red. 3. Nothing must be done to rows # 1 and 5 since: a) row 5 was not selected/checked to begin with, and b) row # 1 has its purchase_later_flag set ON (to Y), so it must be skipped over.   Looking at my code below, I'm guessing (and here's where I need the help) that there's something wrong in the code within the section that says "/*** loop through the results/collection of checked items ***/". I've probably made it more complex than it should be, and that's due to the fact that I have no idea what I'm doing (or rather, how I should be doing it), and this has driven me insane for the last 2 days...which prompted me to "throw in the towel" and seek the help of you very helpful and intellegent folks. BTW, I am a newbie at this, so if I could be provided the exact code, that would be most wonderful, and much highly appreciated.   Thanks to you folks, I'm feeling real good (with a great sense of achievement) after having come here and got the great advice to learn PDO and prepared statements.   Just this one nasty little hurdle is stopping me from getting to "end-of-job" on my very first WebApp. BTW, sorry about the long post...this is the best/only way I could clearly explaing my situation.   Cheers guys!

case "update-delete":
	if(isset($_POST['highlight-purchased'])) 
		{
			// ****** Setup customized query to obtain only items that are checked ******
			$sql = "SELECT * FROM shoplist WHERE";
					for($i=0; $i < count($_POST['checkboxes']); $i++)
						{
							$sql=$sql . " idnumber=" . $_POST['checkboxes'][$i] . " or";
						}
					$sql= rtrim($sql, "or");
											
			$statement = $conn->prepare($sql);
			$statement->execute();
																						
			// *** fetch results for all checked items (1st query) *** //
			$result = $statement->fetchAll();

			$statement->closeCursor();
											
			// Setup query that will change the purchased flag to "N", if it's currently set to "Y"
			$sqlSetToN = "UPDATE shoplist SET purchased = 'N' WHERE purchased = 'Y'";
											
			// Setup query that will change the purchased flag to "Y", if it's currently set to "N", "", or NULL
			$sqlSetToY = "UPDATE shoplist SET purchased = 'Y' WHERE purchased = 'N' OR purchased = '' OR purchased IS NULL";

			$statementSetToN = $conn->prepare($sqlSetToN);
			$statementSetToY = $conn->prepare($sqlSetToY);
											
			/*** loop through the results/collection of checked items ***/
			foreach($result as $row)
				{
					if ($row["purchased"] != "Y")
						{
							// *** fetch one row at a time pertaining to the 2nd query *** //
							$resultSetToY = $statementSetToY->fetch();
															
							foreach($resultSetToY as $row)
								{															
									$statementSetToY->execute();																
								}
						}
					else
						{
							// *** fetch one row at a time pertaining to the 2nd query *** //
							$resultSetToN = $statementSetToN->fetch();
															
							foreach($resultSetToN as $row)
								{															
									$statementSetToN->execute();																
								}
						}
				}
				break;
		}

 CRUD Queston.png   20.68KB   0 downloads    

Hi,

Ok, so I'm making a registration form system, where I can create new registration forms for the users to pick a date etc.

In my form I can add and remove text fields via Javascript - to add additional dates etc. so I don't know if I'll be submitting 3 fields or 15.

The could look like this:
<input type="hidden" name="session_id[]" value="<?php echo $session_id; ?>">
<input type="text" name="picked_date[]">
<input type="text" name="picked_room[]">

They are put in a big array:
De bliver smidt i et stort array:
$n=0;
    foreach ($session_id as $_session_id) {
        $bigar[$n][1] = $_session_id;
        $n++;
        }
        $n=0;
    foreach ($picked_date as $_picked_date) {
        $bigar[$n][2] = $_picked_date;
        $n++;
        }
        $n=0;
    foreach ($picked_room as $_picked_room) {
        $bigar[$n][3] = $_picked_room;
        $n++;
        }
        $n=0;

which is then updated in the database using:
foreach ($bigar as $part)
{
mysql_query("UPDATE...
}

Right - so far so good. The updating works fine with existing fields, but if I remove some of the fields (via JS) it obviously only updates the remaining in the array. The left out will be ignored. On the same note I would like to add fields as well, so - the bottom line - I want to:

- UPDATE rows, where the ID is in the array
- DELETE existing rows, WHERE the ID is NOT in the array
- CREATE new rows for the new fields in the array (not having an ID)

How can this be achieved? Hope someone can help...

hey can someone advice me on how to make my update script update multiple rows.

here's what i've got so far:
update.php

<?php
require('connect.php');

$update = mysql_query("SELECT DISTINCT rideName FROM ride ORDER BY rideName DESC" );
$numrows = mysql_num_rows($update);

echo "<form action='mysql_update.php' method='POST'>
<select name='updateRide' >";


while ($row=mysql_fetch_assoc($update))
{
                        #$rideID = $row ['rideID'];
                        $rideName = $row ['rideName'];
                        #$seatNumber = $row ['seatNumber'];
                        #$time = $row ['time'];
                        #$price = $row ['price'];


echo "<option value='$id'> $rideName </option>";



}
echo "</select>
<input type='text' name='tochange'> 
<input type='submit' name='submit' value='change'>      
</form>";
?>


and now the handler script: mysql_update.php

<?php
require ('connect.php');

$updateRide=$_POST['updateRide'];
$tochange=$_POST['tochange'];

if ($updateRide&&$tochange)
{
$change = mysql_query("UPDATE ride SET rideName='$tochange'
WHERE $id='updateRide'");

}

?>
 




When I try this I get nothing, no changes. In the table there is 3 distinct rideNames each have more than 20 rows. Is there a way using the drop down box and ext field like i Have to update all of the distinct rideNames in the table?

Thanks.

I have ran this code before and it worked but not it won't update.  Can anyone see what I am doing wrong?



Code: [Select]
<?
if(isset($_POST[sort_invest]))   {   // if form was submitted
 
$id = $_POST['sel_record'];
$sort = $_POST['sort'];

for($i=0;$i<$count;$i++){

$sql = "UPDATE invest SET id='$id[$i]', sort='$sort[$i]' WHERE id='$id[$i]'";

$sql_result = mysql_query($sql,$con)
or die (mysql_error());
}
  }

// if form was submitted or if it came from another page
if (isset($_POST['order_invest']) || isset($_POST['sort_invest'])) {

?>       
      <p><strong>Order Invest</strong></p>
     
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post">     
<?   
$sql = "SELECT id, sort, title FROM invest ORDER BY sort ASC";
$sql_result = mysql_query($sql,$con) or die(mysql_error());

     while ($row = mysql_fetch_array($sql_result)) {   
            $id = $row["id"];     
            $title = $row["title"];
            $sort = $row["sort"];
?>
          <input type="hidden" name="sel_record[]" value="<? echo "$row[id]"; ?>">

<table width="545" border="0" cellspacing="0" cellpadding="0">
  <tr>
    <td width="69"><input type="text" name="sort[]" value="<? echo "$row[sort]"; ?>" size="3"></td>
    <td width="476"><? echo "$row[title]"; ?></td>
  </tr>
</table>
 
<br>
<?
}
  }
?>

            <input name="sort_invest" type="submit" value="Sort">
      </form>

I created this code to upload a member's main picture on his member page on website.  I'll only include the query part of the code since that's what is relevant to my problem.  The idea is basically to upload a new picture onto the database if no picture already exists for that member and display the picture on the page.  If a picture already exists, then the script replaces the old picture with the new one upon upload.    But for whatever reason
I don't understand,  when I try to replace the old pic, it gets inserted in a new row on the database instead of replacing the old row, and the new pic gets displayed on the web page alongside the old. Code: [Select]
$query = "SELECT username FROM images WHERE member_id = '".$_SESSION['id']."' AND image_cartegory = 'main'";
        $result = @mysql_query($query);
        $num = @mysql_num_rows($result);
       
        if ($num> 0)   {

    //Update the image

    $update = mysql_query("UPDATE images SET image = '" . $image['name'] . "' WHERE member_id = '".$_SESSION['id']."' AND image_cartegory = 'main'"); 

   
          $_SESSION['error'] = "File updated successfully.";  //really should be session success message.

                    header("Location: member.php");


    exit;
}

else

{
// NOTE: This is where a lot of people make mistakes.
// We are *not* putting the image into the database; we are putting a reference to the file's location on the server

    $sql = "insert into images (member_id, image_cartegory, image_date, image) values ('{$_SESSION['id']}', 'main', NOW(), '" . $image['name'] . "')";

    $result = mysql_query($sql) or die ("Could not insert data into DB: " . mysql_error());

    $_SESSION['error'] = "File uploaded succussfully.";  //really should be session success message.

                    header("Location: member.php");
                                }


So can anyone tell me what the problem is?  Could the fact that my insert script actually uploads the image onto a folder on my server and only stores the path name in the database have anything to contribute to the mixup?  Appreciate your responses in advance.

Only the last row will update when I submit.

I have this form (and one nerve left):


<form action="" method="post" >

echo"
<input style=\"text-align:center\" type=\"text\" name=\"linkorder\" value=\"".$row['order']."\" />
<input type=\"hidden\" name=\"id\" value=\"".$row['id']."\"/>
";
<input type="submit" name="updateorder" value="Save Order" />
</form>


On Submit:


if (isset($_POST['updateorder'])){

connect();
$changeorder = mysql_unbuffered_query("update links set `order` = '".$_POST['linkorder']."' where id = '".$_POST['id']."'") or die(mysql_error());

}



I was going put my fist through the monitor but then I remembered I could get help here.

Thank you!

Hey. Third question today. Very stuck on this one. I am displaying a ton of while loops to display a bunch of data from two different tables. there is NO possible way i can combine the two tables. I mean, I can, but I'm not going to because they are two totally different thins. Anyway. Here is what I'm trying to do:
Lets say I have 3 items, a grape, an orange and an apple.
- 3 apples
- 2 oranges
- 1 grape

I'm displaying an update price box for each different fruit. (so 3 different boxes), and one submit button.

I update it, and it does update the price but it only updates the very first row. I want to be able to update every row I types the price in for. Here is my code: (it is quite long):
Code: [Select]
<?php
session_start();
include("config536.php");
?>
<html>
<head>
<link rel="stylesheet" type="text/css" href="style.css" />
</head>

<?php
if(!isset($_SESSION['username'])) {
echo "<banner></banner><nav>$shownavbar</nav><ubar><a href=login.php>Login</a> or <a href=register.php>Register</a></ubar><content><center><font size=6>Error!</font><br><br>You are not Logged In! Please <a href=login.php>Login</a> or <a href=register.php>Register</a> to Continue!</center></content>";
}

if(isset($_SESSION['username'])) {
echo "<nav>$shownavbar</nav><ubar>$ubear</ubar><content><center><font size=6>User Shops</font><br><br>";

$action = $_GET['action'];

if(!isset($action)) {
echo "<a href=?action=edit>Edit Shop</a> | <a href=?action=view&user=$showusername>View Shop</a> | <a href=?action=stock>View Stock</a> | <a href=?action=quick>Quick Stock</a><br><br>";
}
if(isset($action)) {
$getshopq = "SELECT * FROM usershops WHERE owner='$showusername'";
$getshop = mysql_query($getshopq);
while($tri = mysql_fetch_array($getshop)) {
$theid = $tri['ushopid'];
$owner = $tri ['owner'];
$desc = $tri['description'];
$image = $tri['image'];
$name = $tri['name'];
$status = $tri['status'];
$discount = $tri['discount'];
}

$countq = "SELECT * FROM usershops WHERE owner='$showusername'";
$countit = mysql_query($countq);


 if($action == "edit") {
echo "<a href=?action=edit>Edit Shop</a> | <a href=?action=view&user=$showusername>View Shop</a> | <a href=?action=stock>View Stock</a> | <a href=?action=quick>Quick Stock</a><br><br><font size=5>Edit Shop</font><br><br>";
if(mysql_num_rows($countit)) {
?>
<form action="<?php echo "$PHP_SELF"; ?>" method="POST">
<?php
}
if(!mysql_num_rows($countit)) {
$create = $_POST['create'];
$thename = $_POST['thename'];
$thedesc = $_POST['thedesc'];
$thestatus = $_POST['thestatus'];
$theimage = $_POST['theimage'];
if(!isset($create)) {
?>
<form action="<?php echo "$PHP_SELF"; ?>" method="POST">
Shop Name: <input type="text" name="thename"><br>Description<br><textarea name="thedesc" rows="5" cols="25"></textarea><br>
Status: <select name="thestatus">
<option>Open</option>
<option>Closed</option>
<option>Gallery</option>
</select><br><br>
<input type="submit" name="create" value="Create Shop"></form>
<?php
}
if(isset($create)) {
 if($thename == "" || $thedesc == "") {
echo "<font color=red>Error! Please fill out the entire form!</font><br><br>";
?>
<form action="<?php echo "$PHP_SELF"; ?>" method="POST">
Shop Name: <input type="text" name="thename"><br>Description<br><textarea name="thedesc" rows="5" cols="25"></textarea><br>
Status: <select name="thestatus">
<option>Open</option>
<option>Closed</option>
<option>Gallery</option>
</select><br><br>
<input type="submit" name="create" value="Create Shop"></form>
<?php
}
if($thename != "" && $thedesc != "") {
mysql_query("INSERT INTO usershops (owner, name, description, image, status, discount) VALUES ('$showusername', '$thename', '$thedesc', 'image.gif', '$thestatus', 'None')");
echo "<font color=green>Success! You have created your shop! Click <a href=?action=view>here</a> to view it.</font><br><br>";
}
}
}

}

 if($action == "view") {
echo "<a href=?action=edit>Edit Shop</a> | <a href=?action=view&user=$showusername>View Shop</a> | <a href=?action=stock>View Stock</a> | <a href=?action=quick>Quick Stock</a><br><br><font size=5>Shop Name Here</font><br><br>";

$wowq = "SELECT * FROM uitems WHERE username='$showusername' AND location='2'";
$wow = mysql_query($wowq);
while($wrow = mysql_fetch_array($wow)) {
$umid = $wrow['uitemid'];
$umiid = $wrow['theitemid'];
$umloc = $wrow['location'];
$umprice = $wrow['price'];

$infoq = "SELECT * FROM items WHERE itemid='$umiid'";
$info = mysql_query($infoq);
while($row = mysql_fetch_array($info)) {
$myname = $row['name'];
$myid = $row['itemid'];
$myimage = $row['image'];
$mydesc = $ow['description'];
$myrarity = $row['rarity'];

echo "$myname";
}
}
}
 if($action == "stock") {
$setprice = $_POST['price'];
$updateprice = $_POST['updateprice'];

echo "<a href=?action=edit>Edit Shop</a> | <a href=?action=view&user=$showusername>View Shop</a> | <a href=?action=stock>View Stock</a> | <a href=?action=quick>Quick Stock</a><br><br><font size=5>Stock Shop</font><br><br>";
$eq = "SELECT * FROM uitems WHERE username='$showusername' AND location='2' GROUP BY theitemid";
$ee = mysql_query($eq);
while($erow = mysql_fetch_array($ee)) {

$eeloc = $erow['location'];
$eeid = $erow['theitemid'];
$eenowid = $erow['uitemid'];
$eeprice = $erow['price'];

$wq = "SELECT * FROM items WHERE itemid='$eeid'";
$ww = mysql_query($wq);
while($wrow = mysql_fetch_array($ww)) {

$cq = mysql_query("SELECT * FROM uitems WHERE username='$showusername' AND location='2' AND theitemid='$eeid'");
$lcq = mysql_num_rows($cq);
$fid = $wrow['itemid'];
$fname = $wrow['name'];
$fimage = $wrow['image'];
$frarity = $wrow['rarity'];
$fdesc = $wrow['description'];

echo "$fname<br><img src=/images/items/$fimage>";
?>
<form action="<?php echo "$PHP_SELF"; ?>" method="POST">
<input type="text" name="price" maxlength="5"><br><br>
<?php
}
}
if(isset($updateprice)) {
mysql_query("UPDATE uitems SET price='$setprice' WHERE username='$showusername' AND theitemid='$fid'");
echo "<font color=green>Success! Your prices have been set and updated!</font>";
}
?>
<input type="submit" name="updateprice" value="Update Prices">
<br>
<?php

}

 if($action == "quick") {
echo "<a href=?action=edit>Edit Shop</a> | <a href=?action=view&user=$showusername>View Shop</a> | <a href=?action=stock>View Stock</a> | <a href=?action=quick>Quick Stock</a><br><br><font size=5>Quick Stock</font><br><br>";
}
}

}
?>

</html>
To help you find it, I'm asking about the "stock" $_GET part, about three quarters down. Thanks in advance for anybody who can help me, I've been stuck on this script all day! Thanks again!

Hi,
 
I want to update a txt files 10. row with a form but I could not it how can I do it?

Hey Guys. I have tried looking this up on Google but the only answers I am finding is using there where clause. I wanted to know if I can update or delete a range of rows like from id 100-200. Is there a way to do that? Thanks!

Hi all,
I have a data base with the following table:

---member_data---
id ^ mid ^fieldname^ fieldvalue
1 - 2 - applicant - Seth Smith
2 - 4 - firstname - Chris
3 - 4 - lastname - Cooper
4 - 7 - full_name - Joey Jones
5 - 7 - occupation - Programmer
6 - 7 - phone - 800-555-1212


And below is a snippet that I use to display the selected members data for editing

-------------------------------
<table>
<tr>
<td>Name:</td>
<td>Value:</td>
</tr>
<?php

$query = "SELECT * FROM member_data WHERE mid='$mid'";
$result= mysql_query($query);
  while($row = mysql_fetch_array($result)) {

      $fieldname = $row["fieldname"];
      $fieldvalue = $row["fieldvalue"];

?>
<tr>
<td><input type="text" name="<?php echo $fieldname;?>" value="<?php echo $fieldname;?>"></td>
<td><input type="text" name="<?php echo $fieldvalue;?>" value="<?php echo $fieldvalue;?>"></td>
<?php } ?>
</tr>
</table>
-------------------------------

My question is:

- using the Db example above:
- lets say Ive selected mid#7 (member id 7) to edit which is displayed using the snippet code from above.
- once displayed how do I edit  mid#7  given the fact that  mid#7  is located on 3 seperate rows from the same table?

Thank you,
Dave


*ALSO - I tried the snippet below which did Not work.

foreach($_POST as $key => $val) {
$sql = "UPDATE member_data SET fieldname='$key', fieldvalue='$val' WHERE mid='$mid'";
$result = mysql_query($sql);
}

My site seems to be going well, but on the back end, the users database is going crazy with duplicate entrys. but its not doing it from an INSERT. it seems to be doing it with this code:
Code: [Select]
               $bitquery = $bitcoin->move("bittleship$username", "bittleships", $cost, $minconfirmations);
               if ($bitquery == true){
               $query = mysql_query("INSERT INTO `transactions` ( `id` , `username` , `type` , `amount`, `address`) VALUES ('', '$username', 'buyclicks', '$cost', '')")  or die(mysql_error());
               $query = mysql_query("UPDATE users SET `clicks` = `clicks`+$quantity, `balance`=`balance`-$cost WHERE `username` = '$username' ") or die(mysql_error());
               include('update.php');

can anyone see anything wrong here?? it wont update the Ships table..

i should of gone bed hours ago but its bugging me:

<?php
$sql="SELECT * FROM ships ORDER BY auction='Yes' DESC";
$result=mysql_query($sql);

// Count table rows
$count=mysql_num_rows($result);
?>
<table width="100%" border="0" cellspacing="1" cellpadding="0">
<form name="form1" method="post" action="">
<tr>
<td>
<table width="100%" border="0" cellspacing="1" cellpadding="0">


<tr>
<td align="center"><strong>Active?</strong></td>
<td align="left"><strong>typeID</strong></td>
<td align="left"><strong>Item Name</strong></td>
<td align="left"><strong>Base Price</strong></td>
<td align="left"><strong>Market Price</strong></td>
<td align="center"><strong>Auction</strong></td>
</tr>
<?php
while($rows=mysql_fetch_array($result)){
?>
<tr>
<?php
if ($rows['auction'] != "Yes")  { ?>
<td align="center"><img src="../images/site/delete.png" /></td>
<?php }
else { ?>
<td align="center"><img src="../images/site/accept.png" /></td>
<? } ?>
<td align="left"><span class="isk">
<? $typeID[]=$rows[typeID]; ?>
<? echo $rows['typeID']; ?></span></td>
<td align="left"><span class="eveyellow"><? echo $rows['typeName']; ?></span></td>
<td align="left"><span class="normal"><?php echo number_format($rows['basePrice'])?> isk</span></td>
<td align="left"><input name="marketPrice[]" type="text" size="10" id="marketPrice" value="<? echo $rows['marketPrice']; ?>"> <span class="credits">(<?php echo number_format($rows['marketPrice']/1000000, 2)?> m)</span></td>
<td align="center"><input name="auction[]" type="text" size="6" id="auction" value="<? echo $rows['auction']; ?>"></td>
</tr>
<?php
}
?>
<tr>
<td colspan="4" align="center"><input type="submit" name="Submit" value="Submit"></td>
</tr>
</table>
</td>
</tr>
</form>
</table>
<?php
// Check if button name "Submit" is active, do this
if($Submit){
for($i=0;$i<$count;$i++){
$sql1="UPDATE ships SET marketPrice='$marketPrice[$i]', auction='$auction[$i]' WHERE typeID='$typeID[$i]'";
$result1=mysql_query($sql1);
}
}

if($result1){
header("location:ship.php");
}
mysql_close();
?>    

typeID is my primary key in the table and i only want to update "marketPrice" and "auction" upon submit. its a update multiple rows form by the way.

thank you so much for helping me... again.. would be lost without phpfreaks.

Hi there. I have a page that lists the records of a table. On this page I want to be able to edit/update two attributes of these records by a checkbox - e.g., being able to update multiple records at once. I thought the smartest way to achieve this would be by using arrays. I've implemented one checkbox array and have two fields. Currently when I change both fields and hit submit, the height value changes and the name value is changed to the last record displayed in the table.

E.g.

Height - 170 -> 160 -> UPDATED TO 160
Name - Test1 -> Test2 -> UPDATED TO VICTORY (last record listed in table; displayed alphabetically)

My code is as follows:

<?php
include("connection.php");
$conn = oci_connect($UName,$PWord,$DB) or die("Database Error - Contact Admin - sjrei5@student.monash.edu");
if (empty($_POST["check"]))
{
    $query = "SELECT * FROM HORSE ORDER BY HORSE_NAME";
    $stmt = oci_parse($conn,$query);
    oci_execute($stmt);
$Horses = oci_fetch_array ($stmt);
?>
    <form method="post" action="horse_multi.php">
      <table border="1" id="customers">
      <tr>
        <th>ID</th>
        <th>EDIT</th>
        <th>NAME</th>
        <th>HEIGHT</th>
      </tr>
<?php
while ($Horses = oci_fetch_array ($stmt))
{
?>
        <tr>
          <td><?php echo $Horses["HORSE_ID"]; ?></td>
          <td align="center"><input type="checkbox" name="check[]" value="<?php echo $Horses["HORSE_ID"]; ?>"></td>
          <td align="center"><input type="text" size="5" name="<?php echo $Horses["HORSE_ID"]; ?>" value="<?php echo $Horses["HORSE_HEIGHT"]; ?>"></td>
          <td align="center"><input type="text" size="20" name="HORSE_NAME" value="<?php echo $Horses['HORSE_NAME']; ?>"></td>
        </tr>
<?php
}
?>
      </table><p />
        <h4><input type="submit" value="Update Selected Horses"></h4>
    </form>
<?php
oci_free_statement($stmt);
}
else
{

foreach($_POST["check"] as $horse_id)
{
$query = "UPDATE HORSE SET HORSE_NAME= '$_POST[HORSE_NAME]', HORSE_HEIGHT = ".$_POST[$horse_id]." WHERE HORSE_ID ='".$horse_id."'";
$stmt = oci_parse($conn,$query);
oci_execute($stmt);
}
}
?>
</body>
</html>


Any ideas? 

This topic has been moved to Third Party PHP Scripts.

http://www.phpfreaks.com/forums/index.php?topic=325508.0

Hello all, im new to this forum, im a noobie, just started coding about 3 weeks ago, don't be too hard on me.   My question is I wan't to check for challenges a user's team posted that have not been excepted after 1 day, then auto refund the user's team back there credits, and then also delete all the challenges. So far here is my code.

//Delete all matches not accepted after 1 day
$arrayin = array();
$autorefund = mysql_query("SELECT * FROM `challenges` WHERE `a` = " . $team['id'] . " "
. "AND `accepted` = 0 AND `completed` = 0 AND `chtype` = 1 AND (`expires` < " . ((int) time()) . ")");
if (mysql_num_rows($autorefund) > 0) {
while ($autorefund = mysql_fetch_assoc($autorefund)) {
$arrayin[] = $autorefund['id'];
mysql_query("UPDATE `teams` SET `balance` = `balance` + " . $autorefund['credits'] . " "
. "WHERE `id` IN (" . mysql_real_escape_string(implode(',', $arrayin)) . ")");
mysql_query("DELETE FROM `challenges` WHERE `a` IN "
. "(" . mysql_real_escape_string(implode(',', $arrayin)) . ") "
. "AND `accepted` = 0 AND `completed` = 0 AND `chtype` = 1 "
. "AND (`expires` < " . ((int) time()) . ")");
}
}

FYI here is the code i had, it works fine, however it will only delete 1 challenge per team, not all of there challenges. 

$autorefund   = mysql_query("SELECT * FROM `challenges` WHERE `a` = " . $team['id'] . " AND  `accepted` = 0 AND `completed` = 0 AND `chtype` = 1 AND (`expires` < ".((int)time()).")");
if (mysql_num_rows($autorefund) > 0) {
while ($autorefund  = mysql_fetch_assoc($autorefund)) {
if ($autorefund['accepted'] == 0 and $autorefund['expires'] < time()) {
mysql_query("UPDATE `teams` SET `balance` =  `balance` + " . $autorefund['credits'] . " WHERE `id` = " . $team['id'] . "");
mysql_query("DELETE FROM `challenges` WHERE `a` = " . $team['id'] . " AND  `accepted` = 0 AND `completed` = 0 AND `chtype` = 1 AND (`expires` < ".((int)time())."));
}
}
}

I inherited this script, its using deprecated statements, i know im not skilled to rewrite the entire site to use prepared statements.