PHP - Is_file File_exists Filesize Problems On Cifs Mount
From my old gentoo server I run the following code with success. "/mnt/images" is a cifs mount!
Code: [Select] <?php $source = '/mnt/images/1001.jpg'; $target = '/tmp/1001.jpg'; if ( file_exists($source) ) echo "file_exists: TRUE<br/>"; else echo "file_exists: FALSE<br/>"; if ( is_file($source) ) echo "is_file: TRUE<br/>"; else echo "is_file: FALSE<br/>"; if ( copy($source, $target) ) echo "copy: TRUE<br/>"; else echo "copy: FALSE<br/>"; echo "filesize source: ".filesize($source)."<br/>"; echo "filesize target: ".filesize($target)."<br/>"; ?>The output is Quote file_exists: TRUE is_file: TRUE copy: TRUE filesize source: 4715 filesize target: 4715 When I try this on my newly installed CentOS machine I get Quote file_exists: FALSE is_file: FALSE Warning: copy(/mnt/images/1001.jpg) [function.copy]: failed to open stream: Permission denied in /var/www/html/filetest.php on line 16 copy: FALSE Warning: filesize() [function.filesize]: stat failed for /mnt/images/1001.jpg in /var/www/html/filetest.php on line 21 filesize source: Warning: filesize() [function.filesize]: stat failed for /tmp/1001.jpg in /var/www/html/filetest.php on line 22 filesize target: Every function fails. Then I found that when I disable SELinux with "echo 0 > /selinux/enforce" file_exists() and copy() works. Quote file_exists: TRUE is_file: FALSE copy: TRUE Warning: filesize() [function.filesize]: stat failed for /mnt/images/1001.jpg in /var/www/html/filetest.php on line 21 filesize source: filesize target: 4715 But is_file() and filesize() still doesn't work. They all work when I run them on local files so it is somewhat related to the cifs mount. What could be the problem here? Similar TutorialsI have an avatar upload script. The uploading and moving of the image file to the correct directory works fine, but the displaying of the image causes problems. This is the code that is supposed to display the avatar. // _DISPLAY_ avatar - START $query2 = "SELECT * FROM user WHERE user_id = '$dbuser_id'"; $row2 = mysqli_query ($dbc, $query2) or die (mysqli_error($dbc)); $assoc2 = mysqli_fetch_assoc ($row2); $target = AVATAR_UPLOADPATH; $avatar_name = $target . $assoc2['avatar']; if (is_file($assoc2['avatar'])) { echo "<img src='$avatar_name' alt='Avatar' /><br /><br />"; } else { echo "is not a regular file"; } // END The avatar column in the MySQL database says: image.jpg So there's a regular file. What I want to accomplish: I want the script to check if there's an avatar in the database, if NOT, then it should say: "no avatar uploaded yet." But as it is now it's telling me that there's no regular file even if there is, as I said the avatar column has an entry saying: image.jpg. Should I use if !empty instead? The strange thing is it used to work, now for some reason it suddenly doesn't. EDIT: With !empty it works, am I using the is_file function incorrectly? I'm reading data from a database and writing it to an XML file. I then read the content of that file and parse the XML data. It is a little cache script so it only writes data every 180 seconds, whenever it writes data the filesize that is retrieved is still the old file size before the new data was written. This leads to an XML error... The XML error I get: XML error: no element found at line 39 $fp = fopen($file,"r") while (($data = fread($fp, filesize($file)))) { xml_parse($xml_parser, $data, feof($fp)); } fclose($fp); Having an issue where a peice of code is just being ignored. <?php if($_POST){ $image =$_FILES["image"]["name"]; $img = $_FILES['image']['tmp_name']; $size= filesize($_FILES["image"]["name"]); $maxsize= 400; if ($size > $maxsize*1024){ echo "File too big"; exit(); } else { That is the first bit of code in the page, if i upload a image within the size allowance everything is ok, but if i try one which is a lot bigger, it ignore the if $size > statement and just continues on and throws a bunch of errors. Any ideas? I'm trying to get the filesize() of a file based on a retrieval of filename from the database. The file is located in the download directory and the code calling the function is in the root of the website. Here's the code I've tried: $test = $pdo->query("SELECT filename FROM files WHERE id =1"); $isoname = $test->fetchColumn(); $test = "download/".$isoname; $isosize = filesize($test)/1000000; It always returns zero although is returns the correct filename.
Thanks for any guidance in advance. Good morning Experts! My code creates a PNG file output 505 x 600 pixels, 24bit, 96dpi. The average file size is 130kb. No mystery there. Here is the mystery: when I open the file using ACDSee (v10) and then "save as" (even with the same filename), the file size SHRINKS to about 80kb. All the specs remain the same and I can see no difference in the image! How in the world... What could an ACDSee file-save-as be doing and how do I do it in PHP? Doing a file-save-as in Windows Paint has the same result! So I have tried to reduce the filesize in the code using compression and filters: from imagepng($Image, $ImageName) to imagepng($Image, $ImageName, 9, PNG_ALL_FILTERS). No difference. I tried running through PNGCRUSH, file size only goes to 112kb. The mystery is driving me crazy. Any ideas of what to check in my code or image? Any ideas of tricks to try in the code? A 30% filesize reduction is too great to ignore. I've attached a not-yet-shrunk file for your entertainment (It appears that the upload program wont allow my original as it is 120kb) Thank you in advance for all your ideas! I am trying to do a loop which uses file_exists to check if an image exists and if so display it using the following code: <?php $i = 1; while ($i <= 8) { $filename = $img_loc . "/hovers-800px/" . $image . "-" . $i . ".jpg"; if (file_exists($filename)) { ?> <a class="fuglybox" rel="gxr" href="<?php echo $filename; ?>"> <!--Main thumbnail image--> <img src="<?php echo $img_loc; ?>/product-detail-90px/<?php $image . "-" . $i . ".jpg"; ?>" alt="" width="90" height="90" /></a> <?php } $i++; } ?> I have echoed out $filename to check my directory structure and filename is fine and copied the echoed directory out. The structure is however http://Http://www.xxxxxx.com/img/filename.jpg. Could this be whats causing the problem? I've read as many previous posts as I can find and tried all the suggested solutions but the following simple test code will not work for me (the session variable has been echoed and is correct). Instead of echoing the correct answer, the if(file_exists($target_file)) skips the true result and always displays the false one. I've tested it with files that do and don't exist of course. Here is the code :- $filename = $_SESSION["filename"]; $target_file = $_SERVER['CONTEXT_DOCUMENT_ROOT'] . '/folder/' . $_SESSION["filename"]; if (file_exists($target_file)) { echo 'Selected file is ' . $filename . ' and will be written.'; } else { echo "Selected file " . $filename . " doesn't exist."; } I'd really appreciate any help on this please. Edited July 11, 2020 by oldcelt<code> $jpg_path = '../../../users/user_avatars/' . $_SESSION['the_user'] . '.jpg'; $jpeg_path = '../../../users/user_avatars/' . $_SESSION['the_user'] . '.jpeg'; $gif_path = '../../../users/user_avatars/' . $_SESSION['the_user'] . '.gif'; $png_path = '../../../users/user_avatars/' . $_SESSION['the_user'] . '.png'; $jpg_test = file_exists($jpg_path); $jpeg_test = file_exists($jpeg_path); $gif_test = file_exists($gif_path); $png_test = file_exists($png_path); </code> the path is EXACTLY correct I've checked and rechecked and everything. echoed the path and everything else that is relevant. but later when I call if ($png_test == '1') { blah blah blah } it won't return 1. even though I KNOW that the picture is there and it is at that path. if i echo the path in a src for an image it appears. hmm? Hello all, I am a real newby to this but need some help with a file_exists / while loop issue i have. I am trying to show a table of pictures (with their own ID's) but also if someone hasn't uploaded a picture to the server a default picture will be shown instead. I get the error: Parse error: syntax error, unexpected T_VARIABLE, expecting ',' or ';' in /home/thefrien/public_html/members1.php on line 103 Here is my code: $i = 1; echo "<table border='1' align='center'><tr>"; $result = mysql_query( "SELECT * FROM membership order by L_ID asc" ); while ( $row = mysql_fetch_assoc( $result ) ) { echo "<td align='center' bgcolor='#DDDEFF'><a href='profile_view.php?L_ID=".$row["L_ID"] ."'>" $pic = 'images/avatar/'. $row["L_ID"] .'s.jpg'; if (file_exists($pic)) { echo '<img src=http://www.thefriendzconnection.co.uk/images/avatar/'.$row["L_ID"] ."s.jpg>"; } else { echo '<img src=http://www.thefriendzconnection.co.uk/images/0s.jpg border='0'>'; } "</a> <br><font size='1' face='Arial, Helvetica, sans-serif'>".$row["name"] ."</font> <br><font size='1' face='Arial, Helvetica, sans-serif'>ID: ".$row["L_ID"] ."</font> <br> </td>"; if ( $i % 6 == 0 ) { echo "</tr><tr>"; } $i++; } mysql_free_result( $result ); echo "</tr></table>"; The line I am having issues with seems to be: $pic = 'images/avatar/'. $row["L_ID"] .'s.jpg'; Any suggestions would be greatfully received Thanks. Hi, I am trying to verify if the given url exists or not, by using file_exists() function. It always returns 'FALSE' , according to my understanding it happening because the file to be checked on the given url is located in safe mode. Could anyone please suggest as to how this could be overcome, by similar function or by using alternative method. Regards Abhishek Madhani I'm just trying to find out if php has the ability to check if any file exists, with only part of the filename given.. I have this path: if (file_exists($dir.'/'.$c_file.'/templ_*')) { I added a little star.. That star represents whatever the rest of that file is named for this example.. It could be anything.. So can php match any files that start with "templ_", and say that it does or does not exist?? Thanks I want to get suggested keywords from yahoo api service. When xml file is empty (no keyword), it gives error. To resolve this problem I used this code: if (file_exists('http://search.yahooapis.com/WebSearchService/V1/relatedSuggestion?appid=YahooDemo&query=Madonna&results=2')) { $xmlmetades = simplexml_load_file('http://search.yahooapis.com/WebSearchService/V1/relatedSuggestion?appid=YahooDemo&query=Madonna&results=2'); } Since it is not a normal .xml file, it is always considered no file, and return nothing. I'm working on a WordPress theme and I'm trying to build in a simple if statement which will check if the user has add his own logo into the images folder if he doesn't then the name of the blog will appear as normal text in place of the graphic logo. This is how it looks like: <?php $logo_dir = get_template_directory_uri() . "/images/logo.png"; if (file_exists($logo_dir)) { ?> <li><img src="<?php bloginfo ('template_directory'); ?>/images/logo.png" alt="<?php bloginfo('description'); ?>" /></li> <?php } else { ?> <li id='blog_name'><a href="<?php bloginfo('url'); ?>"><?php bloginfo('name'); ?><font>*</font></a></li> <?php } ?> I've echo'd out $logo_dir, the URL is correct, but still for some reason it's seeing it as if there would no file exist. If I turn it around into !file_exists then the graphic logo WILL show up. So it's always seeing it as non-existent. Any ideas why this could be or am I using this function in a wrong fashion? As far as I've understood the PHP manual, this is the correct way of using it. My setup: (everything on a local network) Web server: Ubuntu Server 8.10 -- Workgroup File server: Windows Server 2008 x64 -- domain Test server: Win 2000 running WAMP -- domain I'm trying to run the code snippet below. $file is a file on the File server above. It definitely exists. Running the code below on the Test server works perfectly. But the file cannot be found when running from the Web server. $file = '//server/share/file.txt'; if (file_exists($file)) echo 'yay!'; else echo 'error'; What with the safe mode considerations, I've also tried to add: ini_set('safe_mode', 'Off'); to no effect. And since file, and fopen similarly not work, I'm pretty sure it's not that either. The File & Test servers are on the same Windows domain, but that's definitely not the reason. I tried the code on a file on a Linux computer in the Workgroup (where the Web server is) with the same results: Test server works, Web server does not. Please advise; I'm really lost. PHP Warning: file_exists() expects parameter 1 to be string, array given in /home/mysite/public_html/display.mysite.com/wp-content/themes/mytheme/form.php on line 9 PHP Warning: file_exists() expects parameter 1 to be string, array given in /home/mysite/public_html/display.mysite.com/wp-content/themes/mytheme/form.php on line 13I have a form that is having some issues and in the error log I see a bunch of these warnings. What is wrong with this?? I numbered the offending lines below (lines 9 & 13) Thanks for any help on this. function CheckExistance($VUrl) { /*9*/ if ( file_exists($VUrl) ) echo $VUrl; /*13*/ elseif ( file_exists(str_replace('www.display.mysite.com','www.display.com', $VUrl)) ) echo str_replace('www.display.mysite.com','www.mysite.com', $VUrl); else echo str_replace('www.mysite.com','www.display.mysite.com', $VUrl); } Edited by damion, 02 July 2014 - 06:01 PM. Hi ppl got code problem cant get it show users avatar & blank avatar at same time not that good at php ppl. avatar box page Code: [Select] <style type="text/css"> #name_area{height:20px; padding:3px;}; </style> <script language="javascript"> <!-- function member_change(id){ <?php $allgames = mysql_query("SELECT * FROM games") or die (mysql_error()); $allgames_total = @mysql_num_rows($allgames); if($allgames_total!=0) { $i=0; while($i<$allgames_total) { ?> document.getElementById('<?php echo mysql_result($allgames, $i, 'game_id'); ?>').style.display = "none"; <?php $i++; } } ?> document.getElementById(id).style.display = "block"; } function show_name(name){ document.getElementById('name_area').innerHTML = name; } function hide_name(){ document.getElementById('name_area').innerHTML = ''; } //--> </script> <div style="text-align:left;"> Choose Squad: <select name="D1" onchange="member_change(this.options[this.selectedIndex].value)" class="standardforms"> <?php $allgames = mysql_query("SELECT * FROM games") or die (mysql_error()); $allgames_total = @mysql_num_rows($allgames); if($allgames_total!=0) { $i=0; while($i<$allgames_total) { $game = mysql_result($allgames, $i, 'game_title'); $members_total2 = mysql_num_rows(mysql_query("SELECT * FROM members WHERE game = '$game'")); if($members_total2!=0) { ?> <option value="<?php echo mysql_result($allgames, $i, 'game_id'); ?>"><?php echo mysql_result($allgames, $i, 'game_title'); ?></option> <?php } $i++; } } ?> </select><br /><br /> </div> <?php $allgames = mysql_query("SELECT * FROM games") or die (mysql_error()); $allgames_total = @mysql_num_rows($allgames); if($allgames_total!=0) { $i=0; while($i<$allgames_total) { $game = mysql_result($allgames, $i, 'game_title'); $members = mysql_query("SELECT * FROM members WHERE game = '$game'"); $members_total = @mysql_num_rows($members); if($allgames_total!=0) { ?> <div id="<?php echo mysql_result($allgames, $i, 'game_id'); ?>" style="display: block; text-align:left;"> <?php if($members_total!=0) { $d=0; while($d<$members_total) { ?> <a href="index.php?page=members&id=<?php echo mysql_result($members, $d, 'id'); ?>"><img onmouseover="show_name('<?php echo mysql_result($members, $d, 'username'); ?>')" onmouseout="hide_name()" src="user/<?php echo mysql_result($members, $d, 'avatar_link'); $filename = 'avatar_link'; if (file_exists($filename)) { echo "avatar_link"; } else { echo "avatars/blank.jpg"; } ?>" width="50" height="50" alt="<?php echo mysql_result($members, $d, 'username'); ?>" title="<?php echo mysql_result($members, $d, 'username'); ?>"/></a> <?php $d++; } } } echo "</div>"; $i++; } } ?> <div id="name_area"></div> *delurk! It had to happen sooner or later!* OK, I am totally and utterly stumped. I have this script: $this->clear_cache ($this->cache_dir, $this->cache_time); if ($this->cache_time > 0) { $current_page = $_SERVER ['REQUEST_URI']; $current_page_encoded = base64_encode($current_page); $current_page_path = $this->cache_dir . $current_page_encoded; if (file_exists($current_page_path)) { // see if there is still a file with the name of the current request URI after cache cleared $content = file_get_contents ($current_page_path); return $content; } } Basically, it is for checking if there is a cached version of the page before running the rest of the script, using the REQUEST_URI as the identifier. So it calls a function to clear the cache, which works fine (and I've tried just deleting the cache files manually anyway). Then it checks if we are even caching, i.e. if cache time is greater than 0. Then it uses the BASE64-encoded REQUEST_URI (under which name the file would have been cached previously) to check if a file with that name still exists in the cache dir, and if so loads it. Now, this works perfectly with a url like: mysite/myscript/mysubpage But when the page has parameters, like: mysite/myscript/mysubpage?search=widgets the file_exists function returns TRUE, even though the directory is empty. I did do a clearstatcache(); but it made no difference and anyway, it wouldn't explain why the URI with query string would fail while the regular one would not. And even if something is wrong with my code elsewhere, the fact is it is returning TRUE for a non-existent file. Can someone prevent my slide into insanity?! I'm getting back into web coding after 5 years and am re-learning PHP & Mysql. I am using a book of tutorials and am having a problem with this section of code. The problem is that the "is_file" test always fails. If I remove the test then the image files (whose name we're pulling from the database) display as intended. The constant "GW_UPLOADPATH" is correct as it correctly displays the default image when the "is_file" test fails. I'm sure it's something simple I'm just overlooking. Thanks for the help Code: [Select] <?php //Define the upload path and maximum file size constants define('GW_UPLOADPATH', 'images/'); // Connect to the database $dbc = mysqli_connect('localhost', 'testing', '12345', 'guitarwars'); // Retrieve the score data from MySQL $query = "SELECT * FROM guitarwars"; $data = mysqli_query($dbc, $query); // Loop through the array of score data, formatting it as HTML echo '<table>'; while ($row = mysqli_fetch_array($data)) { // Display the score data echo '<tr><td class="scoreinfo">'; echo '<span class="score">' . $row['score'] . '</span><br />'; echo '<strong>Name:</strong> ' . $row['name'] . '<br />'; echo '<strong>Date:</strong> ' . $row['date'] . '</td>'; if (is_file($row['screenshot']) && filesize($row['screenshot']) > 0) { echo '<td><img src="' . GW_UPLOADPATH . $row['screenshot'] . '" alt="Score Image" /></td></tr>'; } else { echo '<td><img src="' . GW_UPLOADPATH . 'unverified.gif" alt="Unverified Score" /></td></tr>'; } } echo '</table>'; mysqli_close($dbc); ?> MOD EDIT: [code] . . . [/code] BBCode tags added. Hi all My code give this: <b>Warning</b>: file_exists(): open_basedir restriction in effect. File(/tmp) is not within the allowed path(s): (/home/clients/........ I get the tmp folder and check for its existanse and whether it is writeable
$t=sys_get_temp_dir(); Both gives no which is fine, I can process that. I do it to avoid the output above, but I still get that. How should I check for allowed paths? This runs on several systems where I cannot access php.ini or other system stuff.
class curl2{ private $curl_init; private $CURLOPT_URL; public function connect(){ $this->curl_init = curl_init(); } public function debug(){ curl_setopt($this->curl_init, CURLOPT_VERBOSE, TRUE); $fp = fopen("curl2.txt", "w"); curl_setopt($this->curl_init, CURLOPT_STDERR, $fp); curl_setopt($this->curl_init, CURLOPT_RETURNTRANSFER, TRUE); } public function setUrl($url = null){ $this->CURLOPT_URL = $url; curl_setopt($this->curl_init, CURLOPT_URL, $this->CURLOPT_URL); } public function execute(){ $out = curl_exec($this->curl_init); curl_close($this->curl_init); return $out; } } $curl2 = new curl2; $curl2->connect(); $curl2->setUrl("http://www.linuxformat.co.uk"); $curl2->debug(); echo $curl2->execute(); It display a blank page like attachment result1.jpg, but if I move the $fp = fopen("curl2.txt", "w"); curl_setopt($this->curl_init, CURLOPT_STDERR, $fp); curl_setopt($this->curl_init, CURLOPT_RETURNTRANSFER, TRUE); from function debug() and join it with function execute() like this: public function execute(){ $fp = fopen("curl2.txt", "w"); curl_setopt($this->curl_init, CURLOPT_STDERR, $fp); curl_setopt($this->curl_init, CURLOPT_RETURNTRANSFER, TRUE); $out = curl_exec($this->curl_init); curl_close($this->curl_init); return $out; } it return me Linuxformat content ( expected result ) like result2.jpg below is the working code : class curl2{ private $curl_init; private $CURLOPT_URL; public function connect(){ $this->curl_init = curl_init(); } public function debug(){ curl_setopt($this->curl_init, CURLOPT_VERBOSE, TRUE); } public function setUrl($url = null){ $this->CURLOPT_URL = $url; curl_setopt($this->curl_init, CURLOPT_URL, $this->CURLOPT_URL); } public function execute(){ $fp = fopen("curl2.txt", "w"); curl_setopt($this->curl_init, CURLOPT_STDERR, $fp); curl_setopt($this->curl_init, CURLOPT_RETURNTRANSFER, TRUE); $out = curl_exec($this->curl_init); curl_close($this->curl_init); return $out; } } $curl2 = new curl2; $curl2->connect(); $curl2->setUrl("http://www.linuxformat.co.uk"); $curl2->debug(); echo $curl2->execute(); Why I couldn't split "CURLOPT_STDERR, CURLOPT_RETURNTRANSFER" with "curl_exec" |