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PHP - Mysql Populating Table With Million Entries
Dear All,
I have attached here with a schema, of MySql DB format i am refering to for the topic i need help on. I want to know what is the best way to achieve this problem / task. I have a profile table, and a category table, and a table to map profiles to category. Which allows me to define/add into the category_profile_mapping table, profile ids against a category id. Each category can have anywhere between 2 to 1,00,000 profiles mapped to it. I have another table called sms_out. hence on the site, when i select a category and submit the form value with message, i want to know what is the best way to populate sms_out with MSISDN from the table "Profile" and the message from the form. The list of MSISDN will be based on the category id selected, hence the profile id's will be available in the category_profile_mapping table. I am bad at explaining the problem, however incase you folks need more info do let me know. i shall be glad to provide the same to .. all of you guys who are willing to help me PS: I am asking this question, cuz i want to knw the best solution to achieve this, when there is entries in millions to be done at one form submit. [attachment deleted by admin] Similar Tutorialshello. i have an issue where the data stored with an image is not saving to a mysql table. the image data is ok, just not the selections from the dropdown lists. here is the code <?php include ('connect.php'); // Insert any new image into database if(isset($_POST['xsubmit']) && $_FILES['imagefile']['name'] != "") { $fileName = $_FILES['imagefile']['name']; $fileSize = $_FILES['imagefile']['size']; $fileType = $_FILES['imagefile']['type']; $content = addslashes (file_get_contents($_FILES['imagefile']['tmp_name'])); $jeweltype = $_POST['jeweltype']; $jewelsize = $_POST['jewelsize_in']; $jewelcolour = $_POST['jewelcolour_in']; $jewelmaterial = $_POST['jewelmaterial_in']; $jewelgender = $_POST['jewelgender_in']; if(!get_magic_quotes_gpc()) { $fileName = addslashes($fileName); } // Checking file size if ($fileSize < 150000) { mysql_query ("INSERT into jewel_images (name,size,type,content,jeweltype,jewelsize,jewelcolour,jewelmaterial,jewelgender) " . "values ('$fileName','$fileSize','$fileType','$content','$jeweltype','$jewelsize','$jewelcolour','$jewelmaterial','$jewelgender')"); } else { $err = "The Image file to too large!"; } } // Find out about latest image $gotten = mysql_query("select * from jewel_images order by row_id desc"); $row = mysql_fetch_assoc($gotten); $bytes = $row['content']; // If this is the image request, send out the image if ($_REQUEST['pic'] == 1) { header("Content-type: $row[type];"); print $bytes; } ?> <html> <head> <title>Upload an image to a database</title> </head> <body> <font color="#FF3333"><?php echo $err ?></font> <table> <form name="Upload" enctype="multipart/form-data" method="post"> <tr> <td>Upload <input type="file" name="imagefile"><br /> Jewelery Type: <select> <?php $sql="SELECT jeweltype FROM jeweltypes"; $result =mysql_query($sql); while ($data=mysql_fetch_assoc($result)){ ?> <option value ="jeweltype" ><?php echo $data['jeweltype'] ?></option> <?php } ?> </select> <br /> Jewelery Size: <select> <?php $sql="SELECT jewelsize FROM jewelsizes"; $result =mysql_query($sql); while ($data=mysql_fetch_assoc($result)){ ?> <option value ="jewelsize" ><?php echo $data['jewelsize'] ?></option> <?php } ?> </select> <br /> Jewelery Colour: <select> <?php $sql="SELECT jewelcolour FROM jewelcolours"; $result =mysql_query($sql); while ($data=mysql_fetch_assoc($result)){ ?> <option value ="jewelcolour_in" ><?php echo $data['jewelcolour'] ?></option> <?php } ?> </select> <br /> Jewelery Material: <select> <?php $sql="SELECT jewelmaterial FROM jewelmaterials"; $result =mysql_query($sql); while ($data=mysql_fetch_assoc($result)){ ?> <option value ="jewelmaterial_in" ><?php echo $data['jewelmaterial'] ?></option> <?php } ?> </select> <br /> Jewelery Gender: <select> <?php $sql="SELECT jewelgender FROM jewelgenders"; $result =mysql_query($sql); while ($data=mysql_fetch_assoc($result)){ ?> <option value ="jewelgender_in" ><?php echo $data['jewelgender'] ?></option> <?php } ?> </select> <br /> <input type="submit" name="xsubmit" value="Upload"> </td> </tr> <tr> <td>Latest Image</td> </tr> <tr> <td><img src="?pic=1"></td> </tr> </form> </table> </body> </html> ============================================== here is the query =============================================== <html> <head><title>Your Page Title</title></head> <body> <?php $database="josh_jewel"; mysql_connect ("localhost", "xxxxxxxxx", "yyyyyyyyyyyy"); @mysql_select_db($database) or die( "Unable to select database"); $result = mysql_query( "SELECT jewelcolour FROM jewel_images" ) or die("SELECT Error: ".mysql_error()); $num_rows = mysql_num_rows($result); print "There are $num_rows records.<P>"; print "<table width=400 border=1>\n"; while ($get_info = mysql_fetch_row($result)){ print "<tr>\n"; foreach ($get_info as $field) print "\t<td><font face=arial size=1/>$field</font></td>\n"; print "</tr>\n"; } print "</table>\n"; ?> </body> </html> Here is one of those purely conceptual questions, which involves no code. I'm trying to create a select query which among other things, allows a user of a website to search other members who fall within a particular age range. I have a column in the table where the members' information are stored which records their ages. Which brings us to the problem. On any given day, a member's age may increase by one year compared to what it was the previous day, hence the need to update this column periodically. I can't think of any way to automatically update this column on a daily basis. So my solution is to run an initial update query every time a member tries to search other members based on age, which updates the age column for all other members, before running the select query which eventually retrieves the desired age range. This leads to the second problem. Imagine there are thousands of users using the website. At any given instance, there could be hundreds of members, trying to search others based on age. This means hundreds of users will be updating a single column (the age column) in one table at the same time. Is this feasible? Can it cause the server to crash? Or is there really a more reasonable way to do all of this? Thank you all for taking your time to read this. Appreciate any responses. <?php $con=mysql_connect("localhost","root",""); if(!$con) { die('could not connect' .mysql_error()); } mysql_select_db("hrc_fault",$con); $query = "SELECT * " . "FROM fault_book"; $result = mysql_query($query, $con) or die(mysql_error()); $num_movies = mysql_num_rows($result); $registered_comp=<<<EOD <h2><center>Registered Fault HRC</center></h2> <table width="70%" border="1" cellpadding="2" cellspacing="2" align="center"> <tr> <th>Job Cd No</th> <th>Date</th> <th>Section</th> <th>Item Description</th> <th>Item Sl.No</th> <th>Fault</th> </tr> EOD; $fault_details = ''; while ($row = mysql_fetch_array($result)) { $jc_no = $row['jc_no']; $date = $row['date']; $section = $row['section']; $itm_des = $row['itm_des']; $itm_slno = $row['itm_slno']; $fault_brf = $row['fault_brf']; $fault_details .=<<<RAM <tr> <td>$jc_no</td> <td>$date</td> <td>$section</td> <td>$itm_des</td> <td>$itm_slno</td> <td>$fault_brf</td> </tr> RAM; } $movie_footer ="</table>"; $movie =<<<MOVIE $jc_no $date $section $itm_des $itm_slno $fault_brf MOVIE; echo "There are $num_movies complains in our database"; echo $movie; ?> I m using above code but it only display the last record please debug the code Alright so I created a MySQL database that has 5 tables each named a brand of a dirt bike. In each table their are 2 fields, one INDEX_ID and MODELS. Under that for rows I have every model bike named. A quick question before I get onto what I want to do: Can data be added underneath the rows? For example, users will be able to submit information about each bike model. If each bike model is a row, can there be a category past that row or do I need to make each field a model name and just have a ton of fields and have the rows be the information users submit. To make it easier to understand I'll post the SQL code for the brand Honda: CREATE TABLE `Honda` ( `INDEX_ID` int(3) NOT NULL auto_increment, `MODELS` varchar(20) collate latin1_general_ci NOT NULL, PRIMARY KEY (`INDEX_ID`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 COLLATE=latin1_general_ci AUTO_INCREMENT=23 ; -- -- Dumping data for table `Honda` -- INSERT INTO `Honda` VALUES(1, 'CR85'); INSERT INTO `Honda` VALUES(2, 'CR125'); INSERT INTO `Honda` VALUES(3, 'CR250'); INSERT INTO `Honda` VALUES(4, 'CRF100'); INSERT INTO `Honda` VALUES(5, 'CRF150'); INSERT INTO `Honda` VALUES(6, 'CRF230'); INSERT INTO `Honda` VALUES(7, 'CRF250X'); INSERT INTO `Honda` VALUES(8, 'CRF250R'); INSERT INTO `Honda` VALUES(9, 'CRF450X'); INSERT INTO `Honda` VALUES(10, 'CRF450R'); INSERT INTO `Honda` VALUES(11, 'CRF50'); INSERT INTO `Honda` VALUES(12, 'CRF70'); INSERT INTO `Honda` VALUES(13, 'CRF80'); INSERT INTO `Honda` VALUES(14, 'XR650'); INSERT INTO `Honda` VALUES(15, 'CR500'); INSERT INTO `Honda` VALUES(16, 'XR100'); INSERT INTO `Honda` VALUES(17, 'XR200'); INSERT INTO `Honda` VALUES(18, 'XR250'); INSERT INTO `Honda` VALUES(19, 'XR400'); INSERT INTO `Honda` VALUES(20, 'XR50'); INSERT INTO `Honda` VALUES(21, 'XR70'); INSERT INTO `Honda` VALUES(22, 'XR80'); Anyway I still need to figure out how to have this under a form that a user can use to select the bike they want to submit information about. A code like this perhaps?: <? $connection = mysql_connect("localhost","user","pass"); $fields = mysql_list_fields("dbname", "table", $connection); $columns = mysql_num_fields($fields); echo "<form action=page_to_post_to.php method=POST><select name=Field>"; for ($i = 0; $i < $columns; $i++) { echo "<option value=$i>"; echo mysql_field_name($fields, $i); } echo "</select></form>"; ?> Thanks. How would I force a certain table format and then populate it with the SQL results in their respective columns and rows? i.e. Code: [Select] +------------------+----------+----------+----------+ | | Col 1 | Col 2 | Col 3 | +-------------------+----------+----------+----------+ | row 1 lab data | 16777216 | | 573 | +-------------------+----------+----------+----------+ | row 2 lab data | 23454235 | 87247247 | 65743 | +-------------------+----------+----------+----------+ | row 3 lab data | 16777216 | 47832364 | | +-------------------+----------+----------+----------+ Currently I'm just using a while loop to populate it horizontally, but that doesn't work for row 1. Code: [Select] <?PHP while($row = mysql_fetch_array($result) { ?> blah blah blah html here <?PHP echo $row[0]; ?> more html <?PHP echo $row[1]; ?> and so forth <?PHP } ?> It ends up producing this: Code: [Select] +------------------+----------+----------+----------+ | | Col 1 | Col 2 | Col 3 | +-------------------+----------+----------+----------+ | row 1 lab data | 16777216 | 573 | | +-------------------+----------+----------+----------+ | row 2 lab data | 23454235 | 87247247 | 65743 | +-------------------+----------+----------+----------+ | row 3 lab data | 16777216 | 47832364 | | +-------------------+----------+----------+----------+ Hi, Can someone help me with the following problem... I am populating a html table with results from a mysql query. These results populate the 1st of four columns. The second column is a "RAG STATUS" dropdown menu - so GREEN/AMBER/RED. When this is selected I want it to change the colour of the corresponding row it is on. I have had a play around but can only get it to change the colour of the first row, no matter which dropdown menu I change. Code is below. If anything is not clear please let me know. Any help appreciated Code: [Select] <?php include ("commonTop.php"); include("dbvariables.php"); include("functions.php"); ?> <script type="text/javascript"> function changeBGCol(status) { document.getElementById("colour").bgColor=status; } </script> <?php $Checkout_ID = 2; $result = mysql_query( "SELECT Task FROM Task T, Checkout C Where T.Checkout_ID = C.Checkout_ID and C.Checkout_ID= $Checkout_ID" ) or die("SELECT Error: ".mysql_error()); $num_rows = mysql_num_rows($result); echo "This will be sent to the following recepients $num_rows records.<P>"; echo "<table width=70% border=3>\n"; echo "<tr><th>Check</th><th>STATUS</th><th>JIRA</th><th>Comments</th></tr>"; while ($get_info = mysql_fetch_row($result)){ echo "<tr id=colour>\n"; foreach ($get_info as $field) echo "\t<td><font face=arial size=1/>$field</font></td>\n"; echo "\t<td><select name='Status'> <option value='None'>-- Choose --</option> <option onclick='changeBGCol(this.value)' value='green' >GREEN</option> <option onclick='changeBGCol(this.value)' value='orange'>AMBER</option> <option onclick='changeBGCol(this.value)' value='red'> RED</option> </select></td>"; echo "\t<td><input type='text' name='JIRA'></td>"; echo "\t<td><input type='text' name='Comments'></td>"; echo "</tr>\n"; } print "</table>\n"; ?> [code] </code> The only 2 tables relevant to what I want to do are "User" and "Scores." Basically this database holds high scores for a project I've been working on. I only want to display 10 scores, all from different users. No 2 or more scores from the same user. This is my db structure within phpmyadmin: Quote database -> table -> X / User / Score / X / X / X / X / X / X / X / X If possible I'd like to run a query where it checks for duplicate entries by the same user and only show the highest score. The current query I'm running is below: $result = mysql_query("SELECT * FROM table ORDER BY Score DESC LIMIT 0, 10"); Is this possible? I can only seem to find information regarding the INSERT IGNORE clause and that obviously won't help me as the users and scores are already in the database. Thanks. Hello. Many thanks for your help. I am writing a PHP/MySQL dating-site and have hit a programming impass. I have a database full of members and a search form consisting of checkboxes. So to search, a member ticks say...gender: female; age: 21,22,23,24,25,26; height: 5'4",5'5",5'6",5'7"; county: cornwall,devon,somerset How can a run a check on the database selecting all entries that fall into the selected criteria. For example a 23 year old female of 5'5" living in Cornwall and a 26 year old female of 5'4" living in Somerset? The key index of my database is 'id' and the fields a age,height,county The names of the form checkboxes a Gender: male, female; Age: 21,22,23,24 etc; Height: 5_4,5_5,5_6 etc; county: cornwall,devon etc Hello, i am inserting some form data into my mysql db, i happen to get some duplicates so i want to check first if the entry exists already before i insert. my current code: Code: [Select] <?php if(isset($_POST['submit'])) { ?> <?php if (strlen($_POST['code']) == 19 && substr($_POST['code'],0,7) == '5541258') { mysql_query("INSERT INTO table(code,secret,ip,date) VALUES('$_POST[code]','$_POST[secret]','$_SERVER[REMOTE_ADDR]',CURDATE())"); Print "<font color='green'>The code will be checked now</font>"; } else { Print "<font color='red'>The code is invalid</font>"; } ?><?php } ?> I would like to use the value 'code' to check if the entry exists, that one is unique for each entry. How would i do that ? Thanks ! Ok, so I've spent quite a bit of time piecing together this solution from a variety of sources. As such, I may have something in my code below that doesn't make sense or isn't neccessary. Please let me know if that is the case. I'm creating an administrative form that users will you to add/remove items from a MySQL table that lists open positions for a facility. The foreach loop generates all of the possible job specialties from a table called 'specialty_list'. This table is joined to a second table ('open_positions') that lists any positions that have been selected previously. Where I'm stuck is getting the checkbox to be checked if the facility_ID from the open_positions table matches the $id passed in the URL via ?facility_id=''. Here's where I am so far: $query = "SELECT specialty_list.specialty_displayname , specialty_shortname , open_positions.position , facility_ID FROM specialty_list LEFT OUTER JOIN open_positions ON open_positions.position = specialty_list.specialty_shortname ORDER BY specialty_list.specialty_shortname"; $results = mysql_query($query) or die(mysql_error()); while($row = mysql_fetch_assoc($results)) { $positions[$row['specialty_shortname']] = $row['specialty_displayname']; } echo "<form method='POST' action='checkbox.php'>"; foreach($positions as $specialty_shortname => $specialty_displayname) { $facility_ID = $row['facility_ID']; $checked = $facility_ID == $row['facility_ID'] ? ' checked' : ''; echo "<input type='checkbox' name='position[]' value=\"{$specialty_shortname}\"{$checked}> {$specialty_displayname}</input><br/>"; } echo "<input type='hidden' name='facility_ID' value='$id'>"; echo "<input type='submit' value='Submit Checkboxes!'>"; echo "</form>"; Any ideas how to get this working? I feel like I'm very close, but I just can't get it. I also tried starting from scratch with a WHILE statement instead of a FOREACH, but haven't tweaked it enough to prevent duplicate checkboxes. With that in mind, here it is, just in case that's a better direction: $query = "SELECT specialty_list.specialty_displayname , specialty_shortname , open_positions.position , facility_ID FROM specialty_list LEFT OUTER JOIN open_positions ON open_positions.position = specialty_list.specialty_shortname ORDER BY specialty_list.specialty_shortname"; $results = mysql_query($query) or die(mysql_error()); echo "<form method='POST' action='checkbox.php'>"; while($row=mysql_fetch_assoc($results)) { $facility_ID = $row['facility_ID']; $specialty_shortname = $row['specialty_shortname']; $specialty_displayname = $row['specialty_displayname']; if ($facililty_ID==$id) { $checked=' checked'; } echo "<input type='checkbox' name='position[]' value=\"$specialty_shortname\"$checked> $specialty_displayname</input><br/>"; } echo "<input type='hidden' name='facility_ID' value='$id'>"; echo "<input type='submit' value='Submit Checkboxes!'>"; echo "</form>"; Hi Everyone, I was looking for some direction on how to go about this. A client has asked to set up a small league table with 12 teams where simply they can add fixtures and the result of that fixture. So pending on what the result is if they win they get 2 points and if they loose they get nothing and this will determine what position they are in the league table. Any help on this matter would be greatly appreciated even a small step in the right direction Thanks Barry How would I compare 2 random numbers to rows in a table. The table has 4 rows and 2 colums. My table is setup like this: ID hp mp then has just randomly placed numbers from 0 to 5. So far my script looks like this: I have $new_hp=rand(0,5); $new_mp=rand(0,5). Then i query the db by $myquery=doquery("select hp,mp from users"; $myrow=mysql_fetch_array($myquery); once this is done would a while statement like while ($myrow = mysql_fetch_array($myquery) to what each line in the table has? I would then need to compare the random numbers to those entries in the database. Something like if($myrow[hp] == $new_hp && $myrow[mp] == $new_mp) { ? But if the if statement isnt true it needs go back choose another random number and run same again and again until the statement is true and that is where im stuck at so any help would be greatly appreciated Hi, this is what I want to get working: each time I add an entry, it is displayed in a nice html table, and each entry listed in this html table has an UPDATE link that allows the user to update the Price and Description field of the corresponding table in my database. I have also included an upload element which whenever a user chooses an image, it will replace the default fileUploadIcon.jpg with this. Please see the index.php and bellUpdateForm.php below respectively Code: [Select] //index.php <table border="border"> <?php require 'bellConnect.inc.php'; $curImage; $imgIndx=-1;//iniitally $result=mysql_query("SELECT ID, Name, Manufacturer, Price, Description, SimSupport FROM bellProducts"); $indx=0;//***HOW DO I MAKE THIS SHARED SO THAT EACH ENTRY ADDED HAS AN INCREMENTED index appended to end of its name attribute //phpinfo(); //print "Val of \$counter so far: ".$counter; //NB: print table headings if(mysql_num_rows($result))//if there is at least one entry in bellProducts, make a table { //$counter+=1; print "<table border='border'>"; print "<tr> <th>ID</th> <th>Image</th> <th>Name</th> <th>Manufacturer</th> <th>Price</th> <th>Description</th> <th>SimSupport</th> <th colspan=2 align='center'>Modify</th> </tr>"; //NB: now output each row of records while($row=mysql_fetch_assoc($result)) { //extract($row); //if($indx<sizeof($bellProductsArray)) //{ "<tr align='center'> <td>$row[ID]</td> <td>"; if($_POST['upload']) print "<img src=".$_FILES['image']['name'].">"; else print "<img src='fileUploadIcon.jpg' name='image' /> </td> <td> $row[Name] </td> <td> $row[Manufacturer] </td> <td> $$row[Price]</td> <td align='left'>$row[Description]</td> <td>$row[SimSupport]</td> <td><a href='bellUpdateForm.php?ID=$row[ID]'>UPDATE</a></td> <td><a href='bellDeleteForm.php?ID=$row[ID]' name='delete'>DELETE</a></td> </tr>"; //}//END INNER IF $indx++; }//END WHILE }//END BIG IF ?> </table> </body> </html> Code: [Select] //bellUpdateForm.php <?php require 'bellConnect.inc.php'; if($_GET && !$_POST)//this is to make sure that the current entry is selected BUT the updated info NOT submitted yet { if(isset($_GET['ID'])) { $ID=$_GET['ID']; $result=mysql_query("SELECT * FROM bellProducts WHERE ID=$ID"); $row=mysql_fetch_assoc($result); //store the one entry that will be updated print "You are currently updating item: <strong>$row[Manufacturer] $row[Name] </strong> <br /><br />"; "<form action='bellUpdate.php' method='post'> <label> Price:<input type='text' value='$row[Price]' name='price' id='price'></input> </label> <label> Description: <textarea cols='60' rows='3' name='description' id='description'> $row[Description] </textarea> </label> <div> <input type='submit' value='Update entry' name='update' id='update' /> <input type='hidden' value=$row[ID] name='id' /> </div> <input type='reset' value='Reset entry' />"; print "</form>"; }//END INNER IF }//END BIG IF ?> <form method='post' action='index.php' enctype='multipart/form-data' name='uploadImage' id='uploadImage'> <p> <label>Upload image</label> <input type='file' name='image' id='image' /> </p> <p> <input type='submit' value='Upload this' name='upload' id='upload' /> </p> </form> <?php if(array_key_exists('upload', $_POST)) { // define constant for upload folder define('UPLOAD_DIR', 'C:\wamp\www'); // move the file to the upload folder and rename it move_uploaded_file($_FILES['image']['tmp_name'], ! UPLOAD_DIR.$_FILES['image']['name']); } ?> </body> </html> So when I execute this it'll go for about 130k rows then give a 500 error. Any ideas how to avoid this and get it to complete? Code: [Select] $i=10000000; while($i<=99999999) { $public = $i; $value = rand(10000000, 99999999); mysql_query("INSERT INTO yummy_table (public, value) VALUES('$public', '$value' ) ") or die(mysql_error()); $i++; } echo "done"; I would appreciate your assistance, there are tons of login scripts and they work just fine. However I need my operators to login and then list their activities for the other operators who are logged in to see and if desired send their clients on the desired activity. I have the login working like a charm and the activities are listed just beautifully. How do I combine the two tables in the MySQL with PHP so the operator Logged in can only make changes to his listing but see the others. FIRST THE ONE script the member logges in here to the one table in MSQL: <?php session_start(); require_once('config.php'); $errmsg_arr = array(); $errflag = false; $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD); if(!$link) { die('Failed to connect to server: ' . mysql_error()); } $db = mysql_select_db(DB_DATABASE); if(!$db) { die("Unable to select database"); } function clean($str) { $str = @trim($str); if(get_magic_quotes_gpc()) { $str = stripslashes($str); } return mysql_real_escape_string($str); } $login = clean($_POST['login']); $password = clean($_POST['password']); if($login == '') { $errmsg_arr[] = 'Login ID missing'; $errflag = true; } if($password == '') { $errmsg_arr[] = 'Password missing'; $errflag = true; } if($errflag) { $_SESSION['ERRMSG_ARR'] = $errmsg_arr; session_write_close(); header("location: login-form.php"); exit(); } $qry="SELECT * FROM members WHERE login='$login' AND passwd='".md5($_POST['password'])."'"; $result=mysql_query($qry); if($result) { if(mysql_num_rows($result) == 1) { session_regenerate_id(); $member = mysql_fetch_assoc($result); $_SESSION['SESS_MEMBER_ID'] = $member['member_id']; $_SESSION['SESS_FIRST_NAME'] = $member['firstname']; $_SESSION['SESS_LAST_NAME'] = $member['lastname']; session_write_close(); header("location: member-index.php"); exit(); }else { header("location: login-failed.php"); exit(); } }else { die("Query failed"); } ?> ................................................. ................................ Now I need the person who logged in to the table above to be able to make multiple entries to the table below <? $ID=$_POST['ID']; $title=$_POST['title']; $cost=$_POST['cost']; $activity=$_POST['activity']; $ayear=$_POST['aday']; $aday=$_POST['ayear']; $seats=$_POST['special']; $special=$_POST['seats']; mysql_connect("xxxxxx", "xxx350234427", "========") or die(mysql_error()); mysql_select_db("xxxx") or die(mysql_error()); mysql_query("INSERT INTO `activity` VALUES ('ID','$title', '$cost','$activity', '$aday', '$ayear', '$special', '$seats')"); Print "Your information has been successfully added to the database!" ?> Click <a href="member-profile.php">HERE</a> to return to the main menu <?php ?> I have a bad way with words, so if the title doesnt make much sense nor my post, I apolagize! But I am using a while loop and mysql_fetch_array to echo all information in a table in mysql. With each entry, I have included a button that executes a delete query for that entry. Code: [Select] $delquery="DELETE FROM requests WHERE user = '".$row['user']."'"; mysql_query($delquery,$link2); echo "<font size='19px' color='#009933'>User deleted from request database.When I click the button, the message is echod in every entry listed on the page, and nothing happens. I figured Id use delete from the username, so that way mysql will know which one to delete... but Idk when I think about it thats dumb and makes no sense. Im stuck. This side of the application im trying to make is the admin side where I can process requests. After I process the request I delete it from the database so I know I processed it. I have no idea what query to use for this. Anybody know how I could do this? Thanks
create table mimi (mimiId int(11) not null, mimiBody varchar(255) );
<?php
//connecting to database
include_once ('conn.php');
$sql ="SELECT mimiId, mimiBody FROM mimi";
$result = mysqli_query($conn, $sql );
$mimi = mysqli_fetch_assoc($result);
$mimiId ='<span>No: '.$mimi['mimiId'].'</span>';
$mimiBody ='<p class="leading text-justify">'.$mimi['mimiBody'].'</p>';
?>
//what is next?
i want to download pdf or text document after clicking button or link how to do that Hello, I need some help. Say that I have a list in my MySQL database that contains elements "A", "S", "C", "D" etc... Now, I want to generate an html table where these elements should be distributed in a random and unique way while leaving some entries of the table empty, see the picture below. But, I have no clue how to do this... Any hints? Thanks in advance, Vero Hello everyone, Sorry if this has been answered but if it has I can't find it anywhere. So, from the begining then. Lets say I had a member table and in it I wanted to store what their top 3 interests are. Their$ row has all the usual things to identify them userID and password etc.. and I had a further 3 columns which were labled top3_1 top3_2 & top3_3 to put each of their interests in from a post form. If instead I wanted to store this data as a PHP Array instead (using 1 column instead of 3) is there a way to store it as readable data when you open the PHPmyadmin? At the moment all it says is array and when I call it back to the browser (say on a page where they could review and update their interests) it displays 'a' as top3_01 'r' as top3_02 and 'r' as top3_03 (in each putting what would be 'array' as it appears in the table if there were 5 results. Does anyone know what I mean? For example - If we had a form which collected the top 3 interests to put in a table called users, Code: [Select] <form action="back_to_same_page_for_processing.php" method="post" enctype="multipart/form-data"> <input name="top3_01" type="text" value="enter interest number 1 here" /> <input name="top3_02" type="text" value="enter interest number 2 here" /> <input name="top3_03" type="text" value="enter interest number 3 here" /> <input type="submit" name="update_button" value=" Save and Update! " /> </form> // If my quick code example for this form is not correct dont worry its not the point im getting at :) And they put 'bowling' in top3_01, 'running' in top3_02 and 'diving' in top3_03 and we catch that on the same page with some PHP at the top --> Code: [Select] if (isset($_POST)['update_button']) { $top3_01 = $_POST['top3_01']; // i.e, 'bowling' changing POST vars to local vars $top3_02 = $_POST['top3_02']; // i.e, 'running' $top3_03 = $_POST['top3_03']; // i.e, 'diving' With me so far? If I had a table which had 3 columns (1 for each interest) I could put something like - Code: [Select] include('connect_msql.php'); mysql_query("Select * FROM users WHERE id='$id' AND blah blah blah"); mysql_query("UPDATE users SET top3_01='$top3_01', top3_02='$top3_02', top3_03='$top3_03' WHERE id='$id'"); And hopefully if ive got it right, it will put them each in their own little column. Easy enough huh? But heres the thing, I want to put all these into an array to be stored in the 1 column (say called 'top3') and whats more have them clearly readable in PHPmyadmin and editable from there yet still be able to be called back an rendered on page when requested. Continuing the example then, assuming ive changed the table for the 'top3' column instead of individual colums, I could put something like this - Code: [Select] if (isset($_POST)['update_button']) { $top3_01 = $_POST['top3_01']; // i.e, 'bowling' changing POST vars to local vars $top3_02 = $_POST['top3_02']; // i.e, 'running' $top3_03 = $_POST['top3_03']; // i.e, 'diving' $top3_array = array($top3_01,$top3_02,$top3_03); include('connect_msql.php'); mysql_query("UPDATE members SET top3='$top3_array' WHERE id='$id' AND blah blah blah"); But it will appear in the column as 'Array' and when its called for using a query it will render the literal string. a r r in each field instead. Now I know you can use the 'serialize()' & 'unserialize()' funtcions but it makes the entry in the database practically unreadable. Is there a way to make it readable and editable without having to create a content management system? If so please let me know and I'll be your friend forever, lol, ok maybe not but I'd really appreciate the help anyways. The other thing is, If you can do this or something like it, how am I to add entries to that array to go back into the data base? I hope ive explained myself enough here, but if not say so and I'll have another go. Thanks very much people, L-PLate (P.s if I sort this out on my own ill post it all here) I know I'm doing it something right, but can someone tell me why only one table is showing up? Can you help me fix the issue? Heres my code: function showcoords() { echo"J3st3r's CoordVision"; $result=dbquery("SELECT alliance, region, coordx, coordy FROM ".DB_COORDFUSION.""); dbarray($result); $fields_num = mysql_num_fields($result); echo "<table border='1'>"; // printing table headers echo "<td>Alliance</td>"; echo "<td>Region</td>"; echo "<td>Coord</td>"; // printing table rows while($row = mysql_fetch_array($result)) { // $row is array... foreach( .. ) puts every element // of $row to $cell variable foreach($row AS $Cell) echo "<tr>"; echo "<td>".$row['alliance']."</td>\n"; echo "<td>".$row['region']."</td>\n"; echo "<td>".$row['coordx'].",".$row['coordy']."</td>\n"; echo "</tr>\n"; } echo "</table>"; mysql_free_result($result); } I have 2 rows inserted into my coords table. Just frustrated and ignorant to php. |
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