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PHP - Question Regarding Checkboxes And Mysql
Hey everyone. [=
I don't have much time to read through all of the forums, because I'm on a time crunch and I'll be putting this certain project behind a couple others while I wait for some answers. This project is confusing me a bit, because I haven't worked much with arrays and the good ol' checkbox, so I need some help getting this to work. This project requires me to set-up a checkbox next to each order that was pulled off a database. You are allowed to select as many checkboxes as you'd like, and then click on the "process receipts" for all of the orders that were selected. I need to be able to have the form send me straight to a new page that pulls a loop of receipts one after another. I have the receipts built, and I can access a receipt one at a time based off the ID of a certain order, and I can easily build a loop that presents the receipts. I'm just having a problem pulling the information off the database based from the checkbox array. If you can give me some ideas on where to start with this, I'd greatly appreciate it. Note: Example is inside a hidden administrative page. Can't really give you something to play with, sorry! QQ Thanks! Alex D.A. Designing Similar Tutorialshaving a small issue setting up a search, trying to use check boxes, here is my form code <form action="workorder_index.php" method="POST"> <input type="checkbox" name="wos_0" <? if($wos_0 != NULL) { echo "checked"; }?>>0 - Active <input type="checkbox" name="wos_1" <? if($wos_1 != NULL) { echo "checked"; }?>>1 - Completed awaiting pickup <input type="checkbox" name="wos_2" <? if($wos_2 != NULL) { echo "checked"; }?>>2 - Completed and out the door <input type="checkbox" name="wos_3" <? if($wos_3 != NULL) { echo "checked"; }?>>3 - Waiting call back <input type="checkbox" name="wos_4" <? if($wos_4 != NULL) { echo "checked"; }?>>4 - Waiting for parts<br> <input type="checkbox" name="wos_5" <? if($wos_5 != NULL) { echo "checked"; }?>>5 - Parts in waiting for completion <input type="checkbox" name="wos_6" <? if($wos_6 != NULL) { echo "checked"; }?>>6 - not used <input type="checkbox" name="wos_7" <? if($wos_7 != NULL) { echo "checked"; }?>>7 - Overdue for pickup <input type="checkbox" name="wos_8" <? if($wos_8 != NULL) { echo "checked"; }?>>8 - Scrapped per customer <input type="checkbox" name="wos_9" <? if($wos_9 != NULL) { echo "checked"; }?>>9 - Scrapped by overdue<br><br> <input type="hidden" value="1" name="customsearch"> <input type="Submit" value="Update"> </form> here is my handling code $wos_0=$_POST[wos_0]; $wos_1=$_POST[wos_1]; $wos_2=$_POST[wos_2]; $wos_3=$_POST[wos_3]; $wos_4=$_POST[wos_4]; $wos_5=$_POST[wos_5]; $wos_6=$_POST[wos_6]; $wos_7=$_POST[wos_7]; $wos_8=$_POST[wos_8]; $wos_9=$_POST[wos_9]; if(isset($_POST['customsearch'])) { $str=''; if($wos_0 != NULL) { $str.= "'0'"; } if($wos_1 != NULL) { $str.= ",'1'"; } if($wos_2 != NULL) { $str.= ",'2'"; } if($wos_3 != NULL) { $str.= ",'3'"; } if($wos_4 != NULL) { $str.= ",'4'"; } if($wos_5 != NULL) { $str.= ",'5'"; } if($wos_6 != NULL) { $str.= ",'6'"; } if($wos_7 != NULL) { $str.= ",'7'"; } if($wos_8 != NULL) { $str.= ",'8'"; } if($wos_9 != NULL) { $str.= ",'9'"; } $query="SELECT * FROM workorders a INNER JOIN customers b ON a.customer_id = b.customer_id WHERE a.workorder_status IN (".$str.") ORDER BY a.workorder_id"; } everything works as intended as long as the first check box remains checked, the others can be checked or not, if the first box gets unchecked I get this error Quote SELECT * FROM workorders a INNER JOIN customers b ON a.customer_id = b.customer_id WHERE a.workorder_status IN (,'1','2','3','4','5','6','7','8','9') ORDER BY a.workorder_id Warning: mysql_numrows() expects parameter 1 to be resource, boolean given in workorder_index.php on line 84 basically I can't get the commas right, ...? any help is much appreciated I was fiddling around with php and concerning data in a mysql database. All I was wanting to understand was being able to remove values with cheking multiple items in outputted html list. One that reads a set of values from a database, then displays a check box allowing the user to delete such values, that's it basically, here is my script I used to do it: Code: [Select] <?php function deleteRow($value) { $sql = "DELETE FROM checkbox WHERE value LIKE '$value'"; $result = mysql_query($sql); } if(array_key_exists('delete', $_POST)){ if(isset($_POST['value'])) { $count = count($_POST['value']); $connect = mysql_connect('localhost', 'jeremy', 's56pj989'); if($connect) { $select_db = mysql_select_db('test'); if($select_db) { for($i=0; $i<$count; $i++){ // print 'This is item = '.$_POST['value'][$i]; // outputs fine if(strlen($_POST['value'][$i]) > 0) { deleteRow($_POST['value'][$i]); } } } } } } ?> <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html lang="en"> <head> <title></title> </head> <body> <form id="myform" name="myform" action="<?=$_SERVER['PHP_SELF']; ?>" method="post"> <?php if($_SERVER['REMOTE_ADDR'] == '192.168.0.2') { // printf("<p>Yes you have connected to this script successfully!</p>"); $connect = mysql_connect('localhost', 'mydbuser', 'mydatabasepassword'); if($connect) { // printf("<p>You have now connected to the database, well done!</p>"); $select_db = mysql_select_db('test'); if($select_db) { // printf("<p>Selected database now</p>"); $sql = 'SELECT * FROM checkbox'; $result = mysql_query($sql); if($result) { if(mysql_num_rows($result)>0){ while($row = mysql_fetch_assoc($result)) { printf("%s <input type=\"checkbox\" name=\"value[]\" value=\"%s\">\n<br />\n", $row['value'], $row['value']); } } else { printf("<p>No rows in system!</p>"); } } } } } ?> <input type="submit" id="delete" name="delete" value="Delete" /> </form> </body> </html> There must be a better way shouldn't there? I am not too concerned with error checking, ie if result of removing the values doesnt work, since I will just use this as an example of how to do this. Going on from that, how would I allow it to update a set of say changed values, just purely out of interest, pretty happy since it works though this script. But I was also wondering if there's some easy way of updating a set of values perhaps? Hmm good though and I look forward to any replies, Jeremy. I cant seem to grasp how to accomplish this... I have 10 check boxes in a form on submit I need to be able to see which boxes where checked and depending on which ones were checked display a static link for each. so if i select boxes 1, 5, 8 i will get back www.link.com/1.php www.link.com/5.php www.link.com/8.php thanks Hey everyone, I am trying to set up a thing where i will have a list of states in a drop down list. After a state is select i would like a section of check boxes to appear with cities that a person can choose from. Can anyone help me out with this i have looked on the internet and been trying to code this my self but with progress. I can work with php or java script all i need is some help on getting started and maybe an example. Thanks E Hey all... I'm running into a problem here. If you take a look at the code for this, you'll see it's to enter "horses" into a "class." It's all fine and dandy except I'm trying to get the way the horses are selected to have a different option. Right now they exist as a drop down/select option where you have to choose one at a time and enter submit. My goal is to have checkboxes that users can toggle and submit them all at once (with the rest of the eligibility checks etc still applicable). I've looked it up and the problem is, each user has a different amount of horses, so I can't account for all of them manually. Could someone help me out? On DaniWeb a user was trying to help me with an implode option, but I have zero idea how to work with that. I will literally need my hand to be held through this one. Thank you in advance - I have been trying to do this myself for a good chunk of the day, but my PHP skills are quite limited. Code: [Select] <?php session_start(); // Maintain session state header("Cache-control: private"); // Fixes IE6's back button problem. $page_title = "Class Information"; include('header.php'); $class_id = $_GET['id']; $enter = $_POST['enter_horse']; $enter_check = $_POST['check']; $horse_id = $_POST['horse_id']; //general show information $result = @mysql_query("SELECT s.show_id, s.player_id, s.type, s.name, DATEDIFF(s.run_date, NOW()) AS datedif, c.class_id, s.entry_fee FROM classes c, shows s WHERE c.class_id='$class_id' AND c.show_id=s.show_id LIMIT 1")or die("Cannot find class! " . mysql_error()); $row = @mysql_fetch_array($result); $show_id = $row['show_id']; $show_name = $row['name']; $runs_in = $row['datedif']; $species = $row['species']; $type = $row['type']; $owner_id = $row['player_id']; if(!$row['class_id']){myError("Invalid class!");include('footer.php');} $entry_fee = $row['entry_fee']; $num_entries = @mysql_num_rows(@mysql_query("SELECT horse_id FROM horses_entered WHERE class_id='$class_id'")); $runs_in = "$runs_in day[s]"; if($enter){ //ensure horse is eligible to enter $good = @mysql_num_rows(@mysql_query("SELECT horse_id FROM horses WHERE horse_id='$horse_id' AND player_id='$player_id' AND age>=2 AND age<=20")); $exists = @mysql_num_rows(@mysql_query("SELECT horse_id FROM horses_entered WHERE horse_id='$horse_id' AND class_id='$class_id' LIMIT 1")); if($my_money < $entry_fee){myError("You cannot afford the entry fee.", 1);} if(!$good){myError("Are you sure you own the horse and it is between 3 and 20 years of age?"); }elseif($exists){myError("That horse is already entered in this class!"); }else{ @mysql_query("INSERT INTO horses_entered(horse_id, class_id) VALUES('$horse_id', '$class_id')")or die("Cannot create entry!"); if($type == 1 AND $entry_fee){@mysql_query("UPDATE players SET money=money+'$entry_fee' WHERE player_id='$owner_id' LIMIT 1")or die("Cannot update player money!"); $points=1; }elseif($type == 2 AND $entry_fee){@mysql_query("UPDATE clubs SET money=money+'$entry_fee' WHERE president='$owner_id' LIMIT 1")or die("Cannot update player money2!"); $points=2;} @mysql_query("UPDATE players SET money=money-'$entry_fee', points=points+'$points' WHERE player_id='$player_id' LIMIT 1")or die("Cannot update player money3! " . @mysql_error()); @mysql_query("UPDATE horses SET points=points+'$points' WHERE horse_id='$horse_id' LIMIT 1")or die("Cannot update horse points!"); myError("Class entered!"); } } //display the show information echo "<table> <tr><td><b>Class:</td><td>#$class_id</td></tr> <tr><td><b>Show:</td><td><a href='shows.php?id=$show_id'>$show_name (#$show_id)</a></td></tr> <tr><td><b>Runs:</td><td>$runs_in</td></tr> <tr><td><b>Entry Fee:</td><td>$$entry_fee</td></tr> <tr><td><b>Total Entrants:</td><td>$num_entries</td></tr> <tr><td valign=top><b>Your Horses:</td><td> <form action='classes.php?id=$class_id' method=POST> <select name='horse_id'> "; $result = @mysql_query("SELECT horse_name, breed, horse_id FROM horses WHERE player_id='$player_id' AND age>2 AND age<=20 ORDER BY horse_name ASC")or die("Cannot find horses! " . mysql_error()); while($row = @mysql_fetch_array($result)): $horse_id = $row['horse_id']; $horse_name = stripslashes($row['horse_name']); $breed = $row['breed']; echo "<option value='$horse_id'>$horse_name (#$horse_id), $breed</option>\n"; $prev_species = $species; endwhile; if(!$horse_id){echo "<option value=0>No eligible horses!";} echo " </select> <input type=submit name='enter_horse' value='Enter Horse!'></td></tr></form> <tr><td valign=top><b>Entrants:</td><td> "; $query = "SELECT h.horse_name, h.horse_id, h.breed FROM horses_entered he LEFT JOIN horses h ON he.horse_id=h.horse_id WHERE he.class_id='$class_id' ORDER BY h.horse_name ASC"; $result = @mysql_query($query)or die(mysql_error()); while($row = @mysql_fetch_array($result)): $name = $row['horse_name']; $aid = $row['horse_id']; $breed = $row['breed']; $page = "horses.php"; echo "<a href='$page?id=$aid'>$name (#$aid)</a>, $breed<br>\n"; endwhile; if(!$aid){echo "<i>No entrants.";} echo "</td></tr> </table>"; include('footer.php'); ?> I currently have a page where I have each row in my table listed using: Code: [Select] $getinfo="SELECT * FROM tablename WHERE Closed='n'"; $result=mysql_query($getinfo); while ($row=mysql_fetch_array($result)){ ... // list of user information } That successfully displays my content. What I am trying to do is have a checkbox next to each user (row) that when I check them and hit submit at the bottom, it will change the value of each row on the 'Closed' column to 'y' so it will not be displayed when the page is refreshed. I want to be able to select multiple items to "close". And I would like it to come back to this page. I think I can use this page as the form action and have the code above my while loop to change the Closed column so it then would not be displayed when the while loop is called... is that right? How do I set this up? Not sure where to start the form tag and where to end it, and not sure how to...well...do any of it. I built a series of insertion forms to put entries into a mysql database. Everything is working fine, except that I just now realized my checkboxes don't put any entry in. It's just leaving it's respective smallint field as a default "0". Being new, I've must've overlooked how to handle these. The form's checkboxes have a bit of code in the value that remembers what users chose in case they have to backtrack and redo their form. How would I solve the problem and keep this code? Here's what all the checkboxes are written like: Code: [Select] <input type="checkbox" name="green_leaf" value="<?php if(isset($_POST['1'])) echo $_POST['1']; ?>" > green I have figured out far enough to loop through my table and return a list of check boxes that will be matched to a product. My issue now, is i cannot figure out the proper way to loop through them after they are selected and return them as checked/unchecked for the given product. Thought there is some MySQL involved, that part isn't the problem, I know how to insert into a database or update...when the product is selected from a drop down, I need to be able to populate the checkboxes. Here is the code i am using to initially display all of the categories to choose from... <ul class="categories"> <?php $query = "SELECT * FROM products"; $result = mysql_query($query) or die(mysql_error()); while ($row = mysql_fetch_assoc($result)) { $category = $row['category']; $catId = $row['id']; echo "<li><input class='catCheck' type='checkbox' name='p_cat[]' value='$catId' /> $category</li>"; } ?> </ul> Thanks guys.... Hi people. I have a form which inputs into a database. Here is the code that inserts a yes no option... Code: [Select] <select name = "consent"> <option value = "Yes" <?php if ($_POST['consent'] == 'Yes') { echo 'selected="selected"'; } ?>>Yes</option> <option value = "No" <?php if ($_POST['consent'] == 'No') { echo 'selected="selected"'; } ?>>No</option> </select> However, I have been asked if I can make it a yes or no checkbox instead. Please can you tell me how I need to code it so that the "yes" or "no" is recorded in the DB. At the moment I just have this Code: [Select] <input name="consent" type="checkbox" value="Yes" />Yes<br /> <input name="consent" type="checkbox" value="No" />No<br /> Thanks in advance VinceG I have a table in a mysql database with 5 columns, id, Name, Wifi, Bluetooth, GPS, with rows that are for example 1, Galaxy S2, yes, yes, yes. So basically i want to build a form that has check boxes (3 checkboxes for wifi bluetooth and GPS respectively) that once selected will query the database depending on which check boxes are selected. I have made the form but need to know what to put in the filter.php to make the results be displayed accordingly. Ideally if anyone knows how i would want it so the results were shown on the same page which i believe u need to use ajax to happen but any help on how to show the results will be greatful. the code for the form i have made is as follows: Code: [Select] <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> <title>test</title> </head> <body> <form action="filter.php" method="post"> <INPUT TYPE=CHECKBOX NAME="option[]" VALUE="Wifi" id="r1">Wifi <INPUT TYPE=CHECKBOX NAME="option[]" VALUE="Bluetooth" id="b1">Bluetooth <INPUT TYPE=CHECKBOX NAME="option[]" VALUE="GPS" id="g1">GPS <input type="submit" name="formSubmit" value="Submit" /> </form> </body> </html> im not sure on how to make the filter.php page but i do have this code for displaying the all the data but i want to kno how to make it only display the data from the choices on the checkboxes Code: [Select] <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> <title>pls work</title> </head> <body> <?php function h($s) { echo htmlspecialchars($s); } mysql_connect("localhost", "root", "") or die (mysql_error()); mysql_select_db("project") or die (mysql_error()); $result= mysql_query('SELECT * FROM test') or die('Error, query failed'); ?> <?php if (mysql_num_rows($result)==0) { ?> Database is empty <br/> <?php } else { ?> <table> <tr> <th></th> <th>Name</th> <th>Wifi</th> <th>Bluetooth</th> <th>GPS</th> </tr> <?php while ($row= mysql_fetch_assoc($result)) { ?> <tr> <td> <a href="uploaded-images/<?php h($row['Name']); ?>.jpg"> <img src="uploaded-images/<?php h($row['Name']); ?>.jpg" alt="test"/> </a> </td> <td><a href="textonly.html"><?php h($row['Name']); ?></a></td> <td><?php h($row['Wifi']); ?></td> <td><?php h($row['Bluetooth']); ?></td> <td><?php h($row['GPS']); ?></td> </tr> <?php } ?> </table> <?php } ?> </body> </html> Hi, I am having difficulty deleting rows in my table using check boxes. I have all the check boxes displaying for each row and a delete button below the table. However when i click on the delete button it isnt deleting the checked rows, i have displayed the code below that i am using; Code: [Select] <?php $result = mysql_query("SELECT * FROM contact ORDER BY msg_id ASC"); echo "<table border='1'> <tr> <th>Delete</th> <th>Message ID</th> <th>Name</th> <th>Email</th> <th>Message</th> </tr>"; while($row = mysql_fetch_array($result)) { ?> <td align="center" bgcolor="#FFFFFF"><input name="checkbox[]" type="checkbox" id="checkbox[]" value="<?php echo $row['del_id']; ?>"></td> <?php echo "<td>" . $row['msg_id'] . "</td>"; echo "<td>" . $row['name'] . "</td>"; echo "<td>" . $row['email'] . "</td>"; echo "<td>" . $row['msg'] . "</td>"; echo "</tr>"; } echo "</table>"; ?> <td colspan="5" align="center" bgcolor="#FFFFFF"><input name="delete" type="submit" id="delete" value="Delete"></td> </tr> <?php // Check if delete button active, start this if(isset($_GET['delete'])) { for($i=0;$i<$count;$i++){ $del_id = $checkbox[$i]; $sql = "DELETE FROM contact WHERE id=".$_GET['del_id']; $result = mysql_query($sql); } // if successful redirect to delete_multiple.php if($result){ } } mysql_close(); ?> Please help Thank you how to cross reference $_POST array 'checkboxes[]' with mysql field I have a form that is submitted so the user can select which results to print. but I am having problems getting the results to show correctly. how do I correctly cross reference the form data with the mysql Code: [Select] $getRequests = mysql_query("SELECT * FROM requests WHERE `customer_email`='{$_SESSION['FM_user']}'"); while($request = mysql_fetch_assoc($getRequests)) { if (!in_array($request['request_id'],array($_POST[request]))) { echo '<li style="font-size:10px; border-bottom: 0.1em solid #D0D0D0"> <div class="leftfloat"> <input type="checkbox" name="request[]" value="',$request['request_id'],'"> </div> <div class="leftfloat"> <em>',$request['request_id'],'</em> </div><div class="leftfloat"> | </div> <div class="leftfloat"> <em>',$request['customer_name'],'</em> </div><div class="leftfloat"> | </div> <br style="clear:both"> </li>'; } } Hi, my PHP code currently outputs the results from a users search by querying a backend postgresql database. As result/row is retuned to the user i would like to be able to detect whether or not they have checked a checkbox at the end of each rown in which case multiple rows can then be deleted from the database upon the user clicking a 'delete multiple records' button. I have no problem in being able to display the checkboxes on the webpage but i am a little unsure as to how to refernce them and detect which ones the user has checked. Given my database stores hostnames/IP addresses would it be best to name each checkbox to reflect the hostname or name the value it returns when checked to reflect the hostname. Given the above and that I also store the results of a users search in a $_SESSION['hosts'][][] array how can I then tie the two together? Thanks for reading. How can i do the sum of two numbers inside of a mysql quory, or if this is possible? Code: [Select] while($rand = mysql_fetch_array($cerereSQL)) { $pctsteaua = $rand['puncte']; echo "<pre>"; print_r ($rand); echo "</pre>"; } First i have this variable $pctsteaua who will return me a number. This number i need to use it here. Code: [Select] mysql_query ("UPDATE liga1 SET puncte='$pctsteua + 3', m='1', v='1' WHERE echipa='Steaua' "); The problem is, how i do the math inside this myslq quory to work properly and update my database not with a submited number, but with the sum between the $pctsteaua variable + 3. Hi, wye does $link return a empty row in mysql? Code: [Select] $link = $m[1]; $ssql = "INSERT INTO site (id, link) VALUES ('', '$link');"; mysql_query($ssql); thanks, What will make the database take longer to load and pull data from it A database with lots of tables or a database with very few tables but a shit load of data in each table? Thanks for your reply Hi, I have an array that I've set up as a JSON feed API. The array pulls data from a MySQL query, one of the fields in the query ('description') contains text with escape characters. I'm just wondering how I change either the query to remove the escape characters (ie can you strip escape chars in MYSQL?) - or change the array to strip the escape chars?? Code: [Select] //Run query $result = mysql_query(' SELECT DATE_FORMAT(gl_date,"%d-%m-%Y")as "date", gl_venue as "venue", gl_city as "city", gl_postcode as "postcode", gl_text as "description", concat(DAYOFMONTH(gl_date), MONTHNAME(gl_date),".png") AS "imageName" FROM tg_gig_list where gl_date >= curdate() and gl_publish = 1 order by gl_date '); $array = array(); $array['gigs'] = array(); while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) { $array['gigs'][] = $row; } $output = json_encode($array); } Well, basically I am making my log in script. This is my first website with php and MySQL... actually, its my first website I have done that isn't for a school project. Anywho, the problem I am having is I can't seem to verify the password of the account I am trying to log into. Here is the code snippet I am having trouble with: $usr = $_REQUEST['Username']; $pass = $_REQUEST['Password']; $pass = md5($pass); if(mysql_query('SELECT Password FROM Accounts WHERE Username = "' .$usr . '"') == $pass) { session_start(); $_SESSION['loggedin'] = yes; $_SESSION['User'] = $usr; $_POST['info'] = ("You have successfully logged in " . $usr . "."); } else { $_POST['info'] = "Username and password do not match.";} The problem is that it doesn't seem to matter if the username and password are correct, it always prints "Username and password do not match.". So, here is the table layout of 'Accounts': Did I type the mysql query wrong? This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=354997.0 Hey all. mysql_real_escape_string() seems to be working fine for me, but I'm wondering why the entries in the database don't reflect my SQL query. For example, here is the string php is sending to MYSQL: Code: [Select] insert into bands (bandname, hometown, website, creation, bio, addedon) values ('band', '\'gaewg\"f gswogsw<?php OR \'\'=\' rswaiohgri ', '', '1992', '\' OR \'\'=\'', '10182010') This has already been run through mysql_real_escape_string(), but when I go to phpmyadmin here is what I see: Code: [Select] `bands` (`id`, `bandname`, `creation`, `photo`, `bio`, `hometown`, `website`, `addedon`) VALUES (34, 'band', '1992', '', ''' OR ''''=''', '''gaewg"f gswogsw<?php OR ''''='' rswaiohgri ', '', '10182010'); My question is does it matter if it's not slashed in the database? Might be just a newbie here but isn't that how injection works? Anyhow, just let me know wise phpfreaks users. Thanks in advance. |
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