PHP - I'm Getting An "invalid Argument" Error For My While Loop....
I'm getting an invalid argument error for my While loop. I can't figure out why.
Code: [Select] $sql="SELECT * FROM schools ORDER BY class DESC,sectional ASC,team ASC"; $results = mysql_query($sql); while ($team = mysql_fetch_assoc($results)) { echo $team['school'] . '<br>'; } Here is the error: Quote Warning: mysql_fetch_assoc(): supplied argument is not a valid MySQL result resource in /home/******/public_html/hoosierhoopsmagazine.com/resources/sectional_assignments.php on line 7 Similar TutorialsI have a table with a list of users and an edit button and delete button. When the edit button is pressed on a site it passes the user_id as p_id to the page that catches it and displays the data. The problem is when I click on the "update user" button, I get the following error:
Warning: Undefined variable $the_user_id in C:\xampp\htdocs\3-19-21(2) - SafetySite\admin\edit_user.php on line 10 The weird thing is I had another update user page with a table I created that ran the query to update the table in the database just fine. But as I created it, it didn't look all that great so I recreated the page and used a bootstrap table because of the much cleaner look. Both pages have the exact same PHP code, the only difference is the bootstrap table I added in. So I'm really at a loss with this. Other than the table and PHP code, there is a script at the bottom of the page for the table itself to allow for searching within the table, i'll include that as well. The PHP code is as follows:
<?php //THE "p_id" IS BROUGHT OVER FROM THE EDIT BUTTON ON VIEW_ALL_USERS if (isset($_GET['p_id'])) { $the_user_id = $_GET['p_id']; } // QUERY TO PULL THE SITE INFORMATION FROM THE p_id THAT WAS PULLED OVER $query = "SELECT * FROM users WHERE user_id = $the_user_id "; $select_user = mysqli_query($connection,$query); //SET VALUES FROM ARRAY TO VARIABLES while($row = mysqli_fetch_assoc($select_user)) { $user_id = $row['user_id']; $user_firstname = $row['user_firstname']; $user_lastname = $row['user_lastname']; $username = $row['username']; $user_email = $row['user_email']; $user_phone = $row['user_phone']; //$user_image = $row['user_image']; $user_title_id = $row['user_title_id']; $user_role_id = $row['user_role_id']; } THE UPDATE QUERY CODE....................................................................................................................
<?php if(isset($_POST['update_user'])) { $user_id = $_POST['user_id']; $user_firstname = $_POST['user_firstname']; $user_lastname = $_POST['user_lastname']; $username = $_POST['username']; $user_email = $_POST['user_email']; $user_phone = $_POST['user_phone']; //$user_image = $_POST['user_image']; $user_title_id = $_POST['user_title_id']; $user_role_id = $_POST['user_role_id'];
$query = "UPDATE users SET "; $query .= "user_id = '{$user_id}', "; $query .= "user_firstname = '{$user_firstname}', "; $query .= "user_lastname = '{$user_lastname}', "; $query .= "username = '{$username}', "; $query .= "user_email = '{$user_email}', "; $query .= "user_phone = '{$user_phone}', "; //$query .= "user_image = '{$user_image}', "; $query .= "user_title_id = '{$user_title_id}', "; $query .= "user_role_id = '{$user_role_id}' "; $query .= "WHERE user_id = '{$the_user_id}' "; $update_user = mysqli_query($connection,$query); if(! $update_user) { die("QUERY FAILED" . mysqli_error($connection)); } } ?> THE "UPDATE USER" BUTTON THE USER CLICKS ON TO UPDATE....................................................................................................................
<div class="col-1"> <button class="btn btn-primary" type="submit" name="update_user">Update User</button> </div>
Any Help is Greatly Appreciated! Edited March 23 by Zserenecant work out this mysql syntax error "operation":"medupdate","medid":"","name":"ibo","medyear":"5","medmonth":"21","medday":"1","recuser":1,"SuccFail":"fail","SuccFailMessage":"error occured You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '''WHERE med_id=' at line 2","ResultData":""} Code: [Select] $sql="update metodology set med_description='".$req['name']."', med_year='".$req['medyear']."', med_month='".$req['medmonth']."', med_day='".$req['medday']."', med_recorddate= now(), med_recorduserid= 1'"; $sql.= " WHERE med_id=".$req['medid']; Can someone please help me with an array problem i can not figure out. I need the array to be numbered from 1 to how ever many fields that are needed in the form and have a mysql field name and the title of the field also in the array. 1, "mysql_field_name", "Title of form field" 2, "", "" and so on then the form will be shown based on the array. I have the following draft code which I am working with. any suggestions on how i may do this array ? Code: [Select] <?php $options = array( '1'=> array('fieldtext'=>'option1', 'mysqlfield'=>'option1'), '2'=> array('fieldtext'=>'option2', 'mysqlfield'=>'option2'), '3'=> array('fieldtext'=>'option3', 'mysqlfield'=>'option3'), '4'=> array('fieldtext'=>'option4', 'mysqlfield'=>'option4'), ); // $options = array(1 => "option1", "option2", "option3", "option4"); // the line above works but i want to include the name of the mysql field as well. $userid = 1; ?> <div style="align: center; margin: 12px; font-family:Tahoma;"> <br><br><?php if ($_POST['Update'] != "Update") { // check if form submitted yet, if not get data from mysql. $res = db_query("SELECT * FROM `users` WHERE `userid` = '" . $userid . "'"); foreach($options as $key => $value) { $_POST[$key] = mysql_result($res, 0, $value); } $ok_to_update = "no"; } elseif ($_POST['Update'] == "Update") { // check if form submitted yet, if so get POST data. // error checking // foreach($options as $key => $value) { // $_POST[$i] = ""; // } $ok_to_update = "yes"; } if ($_POST['Update'] == "Update" && $ok_to_update == "yes") { // $res = db_query("INSERT INTO `users` () VALUES ()"); // add user details to database. ?><p><br><br><br>Thank you for updating</p><?php } else { ?><form name="form1" method="post" action=""> <?php foreach($options as $key => $value) { ?><p><?php echo($value); ?>: <input type="text" name="<?php echo($key); ?>" value="<?php echo($_POST[$key]);?>"></p> <?php } ?> <input name="Update" type="submit" value="Update"> </form> <?php } ?> </div> I am getting the following error when using composer: "continue" targeting switch is equivalent to "break". Did you mean to use "continue 2"? Just started. I am pretty sure composer.json wasn't changed. journalctl doesn't show anything. Maybe Doctrine related, however, nothing seems to help.
Any ideas? [michael@devserver www]$ php -v PHP 7.3.4 (cli) (built: Apr 2 2019 13:48:50) ( NTS ) Copyright (c) 1997-2018 The PHP Group Zend Engine v3.3.4, Copyright (c) 1998-2018 Zend Technologies with DBG v9.1.9, (C) 2000,2018, by Dmitri Dmitrienko [michael@devserver www]$ composer -V Composer version 1.4.2 2017-05-17 08:17:52 [michael@devserver www]$ yum info composer Loaded plugins: fastestmirror Loading mirror speeds from cached hostfile * base: mirror.us.oneandone.net * epel: mirror.rnet.missouri.edu * extras: mirror.us.oneandone.net * remi-php73: mirror.bebout.net * remi-safe: mirror.bebout.net * updates: mirror.us.oneandone.net Installed Packages Name : composer Arch : noarch Version : 1.8.4 Release : 1.el7 Size : 1.8 M Repo : installed From repo : epel Summary : Dependency Manager for PHP URL : https://getcomposer.org/ License : MIT Description : Composer helps you declare, manage and install dependencies of PHP projects, : ensuring you have the right stack everywhere. : : Documentation: https://getcomposer.org/doc/ [michael@devserver www]$ composer update Loading composer repositories with package information Updating dependencies (including require-dev) [ErrorException] "continue" targeting switch is equivalent to "break". Did you mean to use "continue 2"? update [--prefer-source] [--prefer-dist] [--dry-run] [--dev] [--no-dev] [--lock] [--no-custom-installers] [--no-autoloader] [--no-scripts] [--no-progress] [--no-suggest] [--with-dependencies] [-v|vv|vvv|--verbose] [-o|--optimize-autoloader] [-a|--classmap-authoritative] [--apcu-autoloader] [--ignore-platform-reqs] [--prefer-stable] [--prefer-lowest] [-i|--interactive] [--root-reqs] [--] [<packages>]... [michael@devserver www]$
Hi, I want something this to be done. When a user tries to logged into the site by entering wrong password, the error message like " Invalid username or password" should be displayed in the same page. I tried following coding. But it shows the error message in a different page. $connect=mysql_connect('localhost','root',''); mysql_select_db('bank',$connect); $username= $_POST['username']; $password= $_POST['password']; $result = mysql_query ('select * from users where username = "' . $_POST['username'] . '" and password = "' . $_POST['password'] . '"'); while($row=mysql_fetch_row($result)){ $user_type=$row[4]; } session_start(); session_register("user_type"); $_SESSION["user_type"]=$user_type; if($user_type=='T'){ header('Location:teller_page.php'); }else if($user_type=='AO'){ header('Location:accofficer_page.php'); }else if($user_type=='AS'){ header('Location:accsup_page.php'); }else if($user_type=='LS'){ header('Location:loansup_page.php'); }else if($user_type=='CS'){ header('Location:cashsup_page.php'); }else{ header('Location:try_again.php'); } Hi everyone, I have some code which has been successfully zipping up the contents of a folder full of images. However, whilst playing around with some other things on the site, I seem to have broken it! The error message I get is... Code: [Select] <b>Warning</b>: ZipArchive::addFile() [<a href='ziparchive.addfile'>ziparchive.addfile</a>]: Invalid or unitialized Zip object in <b><server path to my file>/gallery/includes/classes/hwGallery.php</b> on line <b>195</b><br /> Could anyone please explain what might be causing this? I'm sure the object is being initialised OK, as it's exactly the same code as previously, which worked in the past, although now even that seems to have broken (i.e. uploading an old version of the code, which used to work, also now fails). Could this be a file permissions error? I'm not entirely sure where PHP would be writing the file (does it even do that, or is it all carried out in memory?). Any pointers or helpers would be gratefully received - Google and the search feature on this site haven't turned up anything so far. Thanks, Haydn Code: The code to get the zip file is part of the 'hwGallery' class... Code: [Select] /* * Create a ZIP file containing all the images in the gallery * */ public function getZipFile() { // Partially taken from http://ubuntuforums.org/showthread.php?t=859477 // Zip file header header("Content-Type: application/zip"); header('Content-Disposition: attachment; filename="gallery.zip"'); // Create actual Zip file $zipFile = new ZipArchive(); $zipFile->open("download.zip", ZipArchive::OVERWRITE); foreach ($this->imagePaths as $imageFile) { if (strpos($imageFile,"index") == false) { $zipFile->addFile($imageFile); } } $zipFile->close(); // Return the ZIP file, then delete it echo file_get_contents("download.zip"); unlink("download.zip"); } which is called in the following manner: Code: [Select] $gallery = new hwGallery($id); $gallery->getZipFile(); Hi, bit stuck on how to find and replace "<" and ">" with "<" and ">". I basically have a database record that outputs to screen and I need the code in the <code> tags to be rendered to the screen. I therefore need it to go through the whole array variable from the db and change the symbols just inside the code tags. Please be aware that the code tags might happen more than once here's an example below Code: [Select] <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1> </code> <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1> </code> the desired output would be: <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1 </code> <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1 </code> help on this would be great Cheers Rob Hi guys I am a newbie with PHP and I have been trying to solve this problem for 3 days.. Ive set up a booking form on my website to be sent directly to my email once the client clicked on the send button.. The problem I am having while checking these pages on wamp is that the booking form is ok but when I click on the send button the following message error appears "Warning: mail() [function.mail]: Failed to connect to mailserver at "localhost" port 25, verify your "SMTP" and "smtp_port" setting in php.ini or use ini_set() in C:\wamp\www\fluffy_paws\booking_form2.php on line 27" When I check online I have this message "500 - Internal server error. There is a problem with the resource you are looking for, and it cannot be displayed." Are my codes wrong??? My webhosting is Blacknight.com , Im on Windows Vista, my internet is a dongle with O2 ireland Thanks for your help! Hi guys I'm struggling a bit, I need to replace a word that occurs multiple times in text with an array("up","down","forward","backwards") of words. $find = "left"; $replace = array("up","down","forward","backwards"); $text = "left left left left"; echo str_replace($find,$replace,$text); The Output is: array array array array Did try this with a foreach statement as well, but no luck. Is there a better way of doing this? Thanks
Hello, i got a problem with my codes, it says Parse error: syntax error, unexpected token "endwhile" . Please help me, Here's my code:
<?php
while($rows=mysqli_fetch_array($result)); I've searched but can't seem to find anything I can apply to this situation. Most of the resources are dedicated to dropdown menu's from the same table. I have two tables 'regions' and 'cities' and I am looking to create a menu that lists all the cities within a region then moves on to do the same for the rest of the regions in that state: State1 Region1 City1 City2 City3 Region2 City1 City2 City3 Region3 Etc My tables: States table: stateID, state Regions table: regionID, region, stateID Cities table: cityID, city, regionID I currently have two pages- select region, then select city... I'd like to consolidate to one step after choosing a state. I know I need a nested loop, (while?), and to count the results somehow to retrigger loop; also not sure how to handle two mySQL querries in the nested loop. I'm having trouble wrapping my mind around it. Thank you. hello how do i pass a foreach loop through "Passing by Reference" say i have a foreach loop in a function like this: Code: [Select] function findText(&$output){ $word = Text::find_all(); foreach ($word as $words){ $output = $words->text; } } then one the page i put Code: [Select] findText($output); echo $output; that will just give me the last word in the database. so how do i get it to echo out the array on the page ? thanks I am trying to make a loop simply write "static" code...if that is the correct explanation.... But it seems PHP wants to "process" such things as 'IF' and other Conditions which is defeating the purpose. The problem specifically is that I NEED for a dynamic write to happen based on a variable that will put the following lines that start with IF (! isset // Make sure the checkbox arrays exist if (! isset($_POST['cp_checkbox_one'])) $_POST['cp_checkbox_one'] = array(); if (! isset($_POST['cp_checkbox_two'])) $_POST['cp_checkbox_two'] = array(); if (! isset($_POST['cp_checkbox_three'])) $_POST['cp_checkbox_three'] = array(); // here in the lines below is one way I have tried to make the the LINES ABOVE get written Dynamically // THIS PART returns the values I need, the checkbox names ---- // // foreach($_POST as $meta_key => $meta_value) { // if(cp_str_starts_with($meta_key, 'cp_checkbox')) { echo $meta_key; } // } // So that code WILL RETURN THE VALUES I NEED : // cp_checkbox_one, cp_checkbox_two, cp_checkbox_three // BASED ON THIS I WROTE THE FOLLOWING CODE-- BUT IT DOES NOT WORK AS A REPLACEMENT FOR A LINE // SUCH AS--- if (! isset($_POST['cp_checkbox_one'])) $_POST['cp_checkbox_one'] = array(); // function checkboxloop() { foreach($_POST as $meta_key => $meta_value) { if(cp_str_starts_with($meta_key, 'cp_checkbox')) { if (! isset($_POST[$meta_key])) $_POST[$meta_key] = array(); } } } // HERE I ASK FOR THE FUNCTION BUT WHILE I GET NO ERRORS I GET NO RESULTS // WHICH IS A PROPER SAVE OF UNCHECKED CHECKBOXES ON SUBMIT checkboxloop; I would very much appreciate knowing how to make the code keep looping whatever $meta_key names turn up on this page and then use those names to write the complete lines as STATIC PHP so that the IF conditions don't get "processed" while this function is called. In effect, I want to duplicate the effect of having the code lines WRITTEN, so that they perform exactly as if I had written them as PHP hard-code, as many lines as there will be $meta_keys, but not SEE the code--- just have it valid PHP. This function does NOT make the same thing happen internally. As soon as I replace the function with the HARD CODE PHP then it works...but, I have reached the stage where these lines of code have to happen dynamically. I am baffled how to get this to happen! If I use Echo then I get errors about the "IF". Thank you very much for your help! Hey guys, Got another question im hoping someone can help me with. I have a foreach loop (for use in a mysql query): foreach ($interests as $interest) { $query .= "($id, $interest), "; } problem is i do not want the comma(,) in the last loop. Is there some kinda of function i can use so it does not insert it on last loop? Or should i just use a for loop with a nested if loop? something like ; for($i=0; $i < count($interests); $i++){ $query .= "($id, '$interests[$i]')"; if($i + 1 < count($interests)) { $query .= ", "; } } Cheers guys This topic has been moved to Linux. http://www.phpfreaks.com/forums/index.php?topic=318175.0 question of perfomance .. Code: [Select] //take the names from table1 apply($sql1); foreach($names as $name){ //grab other info about the current user from table2 apply($sql2); } is this fine ? Hi Guys Ever had the feeling your being a spoon and can't see the wood for the trees? Well, that's how I feel today. All I am trying to to is implement a variable in a "foreach" loop that increments by one through each iteration of the loop. I know how to do it in a "for" loop but can't for the life of me get it to work here. Here is the code: foreach ($cart as $prodcode => $qty) { $item = get_product_details($prodcode); echo '<input type="hidden" name="item_name_'.[b]$needavariablehere[/b].'" value="'.$item['description'].$_SESSION['finish'][$prodcode].$_SESSION['handles'][$prodcode].'" />' . "\n"; } Where I have highlighted $needavariablehere is where I want a number to appear i.e. if there is one item available and the foreach loop iterates once I want the number 1 here. If there are two items and the foreach loop iterates twice I want the output to have number 1 in the first line and number 2 the second time around and so on. How many times the foreach loop iterates is based on the $cart array which contains items in a shopping cart. Thanks for any help you can give guys. This topic has been moved to PHP Installation & Configuration. http://www.phpfreaks.com/forums/index.php?topic=347922.0 Hi, I currently have an if, elseif, else program that starts off with Code: [Select] if( $v_name == "" || $v_msg == "" ) echo "something" how do I turn this into a switch? but the very next elseif I have Code: [Select] elseif( strcspn( $_REQUEST['msg'], '0123456789' ) == strlen( $_REQUEST['msg'] ) ) echo "something" is it possible to turn this into a switch with 2 different strings like that to evaluate? |