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PHP - How Do I Query Multiple Tables For A Single Instance Of A Foreign Key?
I have a table that contains the schools in my system:
schools id name location ... Then, I have three tables that use the id of this table: schoolAdmins schoolID schoolContests schoolID students schoolID When I go to delete a school from my system, I want to check to see if that school is connected to any of these three other tables first. This is what I tried (but obviously failed because I'm here) where I'm passing the query the $studentID in question: SELECT * FROM schoolAdmins, schoolContests, students WHERE (schoolAdmins.schoolID = $schoolID) OR (schoolContests.schoolID = $schoolID) OR (students.schoolID = $schoolID) I'm really new to the concept of querying multiple tables in a single statement, so I'm just kind of guessing at this point. Thanks in advance. Similar TutorialsHi All
I have not really played around with PHP in ages so I am having a hard time trying to figure out the best way to proceed. Anyhow... what I need to get done is to take a singleton pattern core database class that has a extended driver based class (ie; the type of database server the connection is connecting to), and build a new class that dynamically handles as many driver based connections that are called using a single instance. As a side note, I tried PDO but it only supports a single driver per class instance, and then each of those connections cannot not have their on set of properties that relate to each connection. Anyway, I was thinking that the best way to handle all the driver specific connections, is to hand out a 'unique hash reference' that points to an array of connection objects and the object properties. then when the client runs any sql function they pass the 'unique hash reference' which the class then returns the object and it properties that will be used by the class to call up the driver specific sql function that was requested by the client. So what do you all thing about that....
TIA stephanieT
PS...
I reason i need this is because I need to update up 25 different databases based on data stored on all the databases and not all of the database servers are of the same type, (ie; MSSQL, Oracle, MySQL, MariaDB, berkeley DB, postgres, sqlite2,3, etc, etc)! Edited January 16, 2019 by StephanieTI can use the first while loop, but there is no data in the second while loop. Is there a better way as I have never done this before... Code: [Select] <?php $featured_results = mysql_query("SELECT * FROM products LEFT JOIN product_images ON products.product_id=product_images.product_id WHERE products.product_featured='1' AND products.product_active='1' AND thumb='1'"); $fa=0; while($featured_row = mysql_fetch_assoc($featured_results)) { $fthumb_result = mysql_query("SELECT image_name FROM product_images WHERE product_id='".$featured_row['product_id']."' AND thumb='1'"); $fthumb = mysql_fetch_row($fthumb_result); if ($fa==0) { echo "\n<img id=\"home-slider-photo-".$fa."\" class=\"home-slider-photo preload\" src=\"/includes/getimage.php?img=".$fthumb[0]."&w=370&h=370\" alt=\"\" />"; } else { echo "\n<img id=\"home-slider-photo-".$fa."\" class=\"home-slider-photo preload home-slider-photo-unsel\" src=\"/includes/getimage.php?img=".$fthumb[0]."&w=370&h=370\" alt=\"\" />"; } $fa++; } echo "<div id=\"home-slider-photo-price\">"; $fb=0; while($featured_row2 = mysql_fetch_assoc($featured_results)) { if ($fb==0) { echo "\n<div id=\"home-slider-photo-price-".$fb."\" class=\"home-slider-photo-price\">\n<span>only</span>$".$featured_row2['product_price']."\n</div>"; } else { echo "\n<div id=\"home-slider-photo-price-".$fb."\" class=\"home-slider-photo-price home-slider-photo-price-unsel\">\n<span>only</span>$".$featured_row2['product_price']."\n</div>"; } $fb++; } echo "</div>"; ?> Hey, I was wondering if there is a way to pull multiple rows at once using a list of unique identifiers. For example, I want to pull the rows with the IDs of 4,13,91 and 252 I know the WHERE part of this query is incorrect, but I'm putting it to hopefully help you guys understand what I'm looking for. $result = mysql_query("SELECT * FROM $table WHERE id='4' OR '13' OR '91' OR '252'"); while($row = mysql_fetch_array($result)) { echo($row['name']); } Or is the best way simply to do it one query at a time without a while statement? There could be as many as a few dozen records being pulled per page. Hey, I have a query running inner joins... which currently works, but I need some more information pulled from other tables... Code: [Select] define('WPSC_TABLE_PRODUCT_LIST', "{$wp_table_prefix}wpsc_product_list"); define('WPSC_TABLE_PRODUCTMETA', "{$wp_table_prefix}wpsc_productmeta"); define('WPSC_TABLE_CATREF', "{$wp_table_prefix}wpsc_item_category_assoc"); define('WPSC_TABLE_CATNAME', "{$wp_table_prefix}wpsc_product_categories"); $cf="Linked Products"; $sku = get_post_meta($post->ID, $cf, true); $array = explode(",",$sku); $products = array_count_values($array); foreach($products as $key => $value) { $product = $wpdb->get_row("SELECT meta.product_id AS pid, list.name AS name, list.price AS price, retailer.category_id AS catid FROM ".WPSC_TABLE_PRODUCTMETA." AS meta INNER JOIN ".WPSC_TABLE_PRODUCT_LIST." AS list ON ( list.id = meta.product_id ) INNER JOIN ".WPSC_TABLE_SHOPNAME." AS retailer ON ( retailer.product_id = meta.product_id ) WHERE `meta_key` IN ( 'sku' ) AND `meta_value` IN ( '{$key}' ) ORDER BY list.id DESC"); ?> But I also need the category name - So I have to cross reference the following... wordpdem_wpsc_product_list id name 433 itemone 432 itemtwo 431 itemthree wordpdem_wpsc_item_category_assoc id product_id category_id 1 433 1 2 432 2 3 410 3 wordpdem_wpsc_product_categories id name 1 Bread 2 Fish 3 Snacks I've now written: Code: [Select] SELECT meta.product_id AS pid, list.name AS name, list.price AS price, retailer.category_id AS catid, category.name AS catname FROM wordpdem_wpsc_productmeta AS meta INNER JOIN wordpdem_wpsc_product_list AS list ON ( list.id = meta.product_id ) INNER JOIN wordpdem_wpsc_item_category_assoc AS retailer ON ( retailer.product_id = meta.product_id ) INNER JOIN `wordpdem_wpsc_product_categories``wordpdem_wpsc_product_list` AS category ON ( retailer.category_id = category.id ) WHERE `meta_key` IN ( 'sku' ) AND `meta_value` IN ( '{$key}' ) ORDER BY list.id DESC However it fails on line 12 (the Where statement...) Any ideas what I've done wrong? $query = mysql_query("SELECT COUNT(tickets.id),tickets.id,tickets.status,tickets.date,tickets.question,tickets.title,users.position FROM tickets,users WHERE tickets.id='$existing' users.username='$username'"); How do I get it so it selects data from the table tickets where id='$existing', but I also want to get a user's (who is viewing the ID) position (rank). $username is a session. So, any thoughts on how I would do so? My updated code: <?php session_start(); include("../includes/mysql.php"); include("../includes/config.php"); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <link href="../style.css" rel="stylesheet" type="text/css" /> <title><?php echo $title; ?></title> </head> <body> <div id="container"> <div id="content"> <div id="left"> <div class="menu"> <?php include("../includes/navigation.php"); ?> <div class="menufooter"></div> </div> <?php include("../includes/menu.php"); ?> </div> <div id="middle"> <?php $existing = $_POST['existing']; $ip = $_SERVER['REMOTE_ADDR']; $username = $_SESSION['user']; $query = mysql_query("SELECT COUNT(tickets.id),tickets.id,tickets.status,tickets.date,tickets.question,tickets.title,users.position FROM tickets,users WHERE tickets.id='$existing' OR users.username='$username'"); $get = mysql_fetch_assoc($query); if(!$existing) { echo ' <div class="post"> <div class="postheader"><h1>Error</h1></div> <div class="postcontent"> <p>You have not enetered in a ticket ID. Please go back and do so.</p> </div> <div class="postfooter"></div> </div> '; } elseif($get['COUNT(id)'] < 1) { echo ' <div class="post"> <div class="postheader"><h1>Error</h1></div> <div class="postcontent"> <p>The ticket ID you are trying to use doesnt exist. Please go back or submit another ticket.</p> </div> <div class="postfooter"></div> </div> '; } elseif($get['tickets.ip']==$ip || $get['user.position'] >= 1) { $status["tickets.status"]["0"] = "Waiting for support..."; $status["tickets.status"]["1"] = "Waiting for user..."; $status["tickets.status"]["2"] = "Ticket Closed..."; $status["tickets.status"]["3"] = "Ticket Opened..."; echo ' <div class="post"> <div class="postheader"><h1>View Ticket Status - ID '. $get["id"] .'</h1></div> <div class="postcontent"> <p>Title: '. $get["tickets.title"] .' - Posted on: '. $get["tickets.date"] .'</p> <p>Ticket Status: '. $status[$get["tickets.status"]] .'</p> <p>Question: '. nl2br($get["tickets.question"]) .'</p> </div> <div class="postfooter"></div> </div> '; } else { echo ' <div class="post"> <div class="postheader"><h1>Error</h1></div> <div class="postcontent"> <p>This is not your ticket. You only have permission to view your tickets. Please go back.</p> </div> <div class="postfooter"></div> </div> '; } ?> </div> </div> </div> </body> </html> Hi guys, I'm trying to query two tables for different data and echo the results that match both tables. Here are the tables I have and the query I'm trying to run. (Table) qc_reports (Fields) id report_date report_lot_number report_po report_supplier report_buyer report_inspectedby report_pulptemprange report_carrierconditions report_supplierclaim report_carrierclaim report_temprecorder report_temprange_N report_temprange_M report_temprange_B report_suppliercontact report_contactedby report_time report_comments (Table) qc_lots (Fields) id report_id lot_temprange lot_commodity lot_rpcs lot_brand lot_terms lot_cases lot_orgn lot_estnum lot_avgnum This is the query that I'm trying to do. Code: [Select] <?php $sql = "SELECT * FROM qc_reports, qc_lots WHERE "; if (!empty($start_date) and !empty($end_date)) $sql .= " qc_reports.report_date BETWEEN '$start_date' and '$end_date' AND "; if (!empty($search_fronteralot)) $sql .= " qc_reports.report_lot_number = '$search_fronteralot' AND "; if (!empty($search_buyer)) $sql .= " qc_reports.report_buyer = '$search_buyer' AND "; if (!empty($search_supplier)) $sql .= " qc_reports.report_supplier = '$search_supplier' AND "; if (!empty($search_po)) $sql .= " qc_reports.report_po = '$search_po' AND "; if (!empty($search_carrierconditions) and $search_carrierconditions != 'all') $sql .= " qc_reports.report_carrierconditions = '$search_carrierconditions' AND "; if (!empty($search_commodity) and $search_commodity != 'all') $sql .= " qc_lots.lot_commodity = '$search_commodity' AND "; if (!empty($search_inspectedby)) $sql .= " qc_reports.report_inspectedby = '$search_inspectedby' AND "; $sql = substr($sql, 0, -4); $query = mysql_query($sql); $numrows = mysql_num_rows($query); ?> RESULTS - <?php echo $numrows; ?> <hr> <table width='500'><tr><td><b>Date</b></td><td><b>Lot Number</b></td><td><b>PO</b></td><td> </td></tr> <tr> <td> </td> </tr> <?php while ($row = mysql_fetch_assoc($query)) { $id = stripslashes($row['id']); $report_lot_number = stripslashes($row['report_lot_number']); $report_po = stripslashes($row['report_po']); $report_date = stripslashes($row['report_date']); echo "<tr> <td>" . $report_date . "</td></td><td>" . $report_lot_number . "</td><td>" . $report_po . "</td><td><a href='view_report.php?id=" . $id . "'>View</a></td> </tr>"; } echo '</table><br><br><br><hr><br><br>'; } ?> All the variables are passed from a HTML form with $_POST. I need the search to work like this: If there is a value in a form field then the query gets appended with that value but when it gets to the $search_commodity it needs to search the second table (qc_lots) and check for the results. Any results that match have to be matched to the results from the first table (qc_reports) and display (echo) only qc_reports that match to both tables. The only common field is the report_id on the qc_lots table and the id on the qc_reports table. I'm stuck and need some guidance. Can someone help please? Hi, i have a database with multiple records. One of those values is an image. When i query the database and i want only the images as a result it gives the result in a field. It then fills up the field horizontal and when there is no more field left it starts a new row. That is what i want. But now i want some extra info next to the picture so i put that in a table with two colums like this: echo '<table border="1" width="400"><td><a href="'.$row['website'].'"> <img src="'.$row['prod_img'].'"> '.$row['prod_name'].' <a href="'.$row['website'].'">'.$row['website'].'</td></table> ';}} But i still want the result to fill up the field and when the field is full i want the next results on a row below this.... Anyone? Below is a page which is supposed to output the name, blog contribution and picture of contributing members of a website. <div id="blog_content" class="" style="height:90%; width:97%; border:5px solid #c0c0c0; background-color: #FFFFFF;"> <!--opens blog content--> <?php //address error handling ini_set ('display_errors', 1); error_reporting (E_ALL & ~E_NOTICE); //include the config file require_once("config.php"); //Define the query. Select all rows from firstname column in members table, title column in blogs table,and entry column in blogs table, sorting in ascneding order by the title entry, knowing that the id column in mebers table is the same as the id column in blogs table. $sql = "SELECT blogs.title,blogs.entry,members.firstname,images.image FROM blogs LEFT JOIN members ON blogs.member_id = members.member_id LEFT JOIN images ON blogs.member_id = images.member_id ORDER BY blogs.title ASC "; $query = mysql_query($sql); if($query !== false && mysql_num_rows($query) > 0) { while(($row = mysql_fetch_assoc($query)) !== false) { echo '<div id="blog_content1" style="float:left; position:relative;bottom:18px;left:13px; background-color: #FFFFFF; height:16.7%; width:100%; border:0px none none;" <!--opens blog_content1 same as main center top 1 and 2 from index page everything scaled down by a factor of 3, heightwise--> <div class="red_bar" style="height:3%; width:100%; border:1px solid #959595;"> <!--a--> <div class="shade1" style="height:5px; width:100%; border:0px none none;"> </div> <div class="shade2" style="height:5px; width:100%; border:0px none none"> </div> <div class="shade3" style="height:5px%; width:100%; border:0px none none"> </div> </div> <!-- closes red bar--> <div class="content" style="height:28.3%; width:100%; border:0px none none;"> <!----> <div class="slideshow" id="keylin" style="float:left; width:20%; border:0px none none;"> <!--a--> <div><img header("Content-type: image/jpeg"); name="" alt="" id="" height="105" width="105" src="$row[image]" /></div> </div> <!-- closes pic--> <div class="content_text" style="float:right; position:relative;top:7px;left:0px; max-height:150px; width:78.5%; border-width:4.5px; border-bottom-style:solid; border-right-style:solid; border-color:#c0c0c0; "> <!--a-->'; echo "<h3>".$row['title']."</h3>"; echo "<p>" .$row['entry']."<br />".$row['firstname']."</p>"; echo '</div> <!-- closes content text--> </div> <!-- closes content--> </div> <!-- closes blog_content1-->'; } } else if($query == false) { echo "<p>Query was not successful because:<strong>".mysql_error()."</strong></p>"; echo "<p>The query being run was \"".$sql."\"</p>"; } else if($query !== false && mysql_num_rows($query) == 0) { echo "<p>The query returned 0 results.</p>"; } mysql_close(); //Close the database connection. ?> </div> <!-- closes blog content--> The select query is designed to retrieve all the blog contributions(represented by the fields blogs.title and blogs.entry) from the database, alongside the contributing member (member.firstname) and the member's picture(images.image), using the member_id column to join the 3 tables involved, and outputs them on the webpage. The title, entry and firstname values are successfully displayed on the resulting page. However, I can't seem to figure out how to get the picture to be displayed. Note that the picture was successfully stored in the database and I was able to view it on a separate page using a simple select query. It is now just a question of how to get it to display on this particularly crowded page. Anyone knows how I can output the picture in the img tag? I tried placing the header("Content-type: image/jpeg"); statement at the top of the php segment, then just right below the select query and finally just right above the img tag, but in every case, I just got a big white blank page starring at me. How and where should I place the header statement? And what else am I to do to get this picture displayed? Any help is appreciated. SET UP: Windows vista # XAMPP 1.7.3, # Apache 2.2.14 (IPv6 enabled) + OpenSSL 0.9.8l # MySQL 5.1.41 + PBXT engine # PHP 5.3.1 # phpMyAdmin Problem: The name_id column from the card_numbers table doesn't increment at all. Even if if I put in two rows of data I'm left with the name_id not increasing. Main Goal: I want that column to increment with the same values as the other tables. Code for Mysql database: <?php require 'db.inc.php'; $db = mysql_connect(MYSQL_HOST, MYSQL_USER, MYSQL_PASSWORD) or die ('Unable to connect. Check your connection parameters.'); mysql_select_db(MYSQL_DB, $db) or die(mysql_error($db)); $query = 'CREATE TABLE IF NOT EXISTS subscriptions ( name_id INTEGER UNSIGNED NOT NULL AUTO_INCREMENT, name VARCHAR(50) NOT NULL, email_address VARCHAR(50), membership_type VARCHAR(50), PRIMARY KEY (name_id) ) ENGINE=MyISAM'; mysql_query($query, $db) or die (mysql_error($db)); // create the user information table $query = 'CREATE TABLE IF NOT EXISTS site_user_info ( name_id INTEGER UNSIGNED NOT NULL, terms_and_conditions VARCHAR(50) NOT NULL, name_on_card VARCHAR(50), credit_card_number VARCHAR(50), FOREIGN KEY (name_id) REFERENCES subscriptions(name_id) ) ENGINE=MyISAM'; mysql_query($query, $db) or die (mysql_error($db)); $query = 'CREATE TABLE IF NOT EXISTS card_numbers ( name_id INTEGER UNSIGNED NOT NULL, credit_card_expiration_data VARCHAR(50), FOREIGN KEY (name_id) REFERENCES subscriptions(name_id) ) ENGINE=MyISAM'; mysql_query($query, $db) or die (mysql_error($db)); echo 'Success!'; ?> Code of the data being inserted into mysql from forms: <?php //let's start our session, so we have access to stored data session_start(); session_register('membership_type'); session_register('terms_and_conditions'); include 'db.inc.php'; $db = mysql_connect('localhost', 'root', '') or die ('Unable to connect. Check your connection parameters.'); mysql_select_db('ourgallery', $db) or die(mysql_error($db)); //let's create the query $query = sprintf("INSERT INTO subscriptions ( name_id, name, email_address, membership_type) VALUES ('%s','%s','%s','%s')", name_id, mysql_real_escape_string($_SESSION['name']), mysql_real_escape_string($_SESSION['email_address']), mysql_real_escape_string($_SESSION['membership_type'])); //let's run the query $result = mysql_query($query, $db) or die(mysql_error($db)); $name_id = mysql_insert_id(); $query = sprintf("INSERT INTO site_user_info ( name_id, terms_and_conditions, name_on_card, credit_card_number ) VALUES ('%s','%s','%s','%s')", mysql_insert_id(), mysql_real_escape_string($_SESSION['terms_and_conditions']), mysql_real_escape_string($_POST['name_on_card']), mysql_real_escape_string($_POST['credit_card_number'])); //let's run the query $result = mysql_query($query, $db) or die(mysql_error($db)); $name_id = mysql_insert_id(); $query = sprintf("INSERT INTO card_numbers ( name_id, credit_card_expiration_data) VALUES ('%s','%s')", mysql_insert_id(), mysql_real_escape_string($_POST['credit_card_expiration_data'])); $result = mysql_query($query, $db) or die(mysql_error($db)); echo '$result'; ?> Should I be JOINING these tables together? I don't want the IDs to get muddled up otherwise it will screw up my database. Hi,
I want each new incident created into the t_incidents table by the user to be associated with the AgencyID, a foreign key in the t_users table.
The problem is I do not know how this relationship will work and whether I will need a junction table.
The two tables a
t_Users +----------+----------+------------+ |UserID | AgencyID |User name | +----------+----------+------------+ |1 | 1 |john | +----------+----------+------------+ |2 | 1 |andrew | +----------+----------+------------+ t_Agencies +----------+------------+ |AgencyID |agency name | +----------+------------+ |1 |police | +----------+------------+ |2 |immigration | +----------+------------+I will appreciate your advice. Joseph Edited by josephbupe, 13 October 2014 - 03:04 AM. I have a scenario in PHP, i need a smart way: 1. I run one process on background forever, scheduler.php - done 2. User on the web submit their task in DB to be processed by the above process(scheduler.php) - done 3. scheduler.php read the db after every 1 sec, looking for user's task. Problem: Ideally, if it founds like 10 or more tasks it should process them concurently(in parallel)..i.e it should not wait one task to be fully executed so as to run the next one as one task might take a very long time to be fullu executed. I would do like exec("nohup php <path>/file_name.php >> /dev/null 2>&1 &"), but if i have alot of tasks this will create zombie processes. Any smart way to do this will be highly appreciated! I've been looking everywhere for a solution of this but I can't find one...
Basically what I did was created a class named USER.
public class USER{
private static $USER = array();
public function __construct($U='')
{
// if $U is not entered (=='') then set $U to MY USER ID ($_COOKIE['user'])
// do a mysql query by the ID (ala $U) and store the results to self::$USER
}
public function ID()
{
return self::$USER['id'];
}
}
This is the code I am running...
I do a user profile page that shows different properties of the USER from the database: USERNAME(),ID(),PHONE(),EMAIL(), etc. etc.
// creates an instance of a different user (other than myself) $PROFILE = new USER($ID); // $ID: 26 will retrieve USERNAME: Test // create an instance of user class for myself using the cookie holding my id $ME = new USER($_COOKIE['user']) // $_COOKIE['user']: 01 will retrieve USERNAME: Monster echo($PROFILE->USERNAME()); // displays Monster echo($PROFILE->ID()); // displays 01Any idea what I am doing wrong? I would assume that $PROFILE->USERNAME() would display Test and $ME->USERNAME() would show monster. Greetings, I'm looking for a way to pass a query string (from page1) as part of a query string (to page2) as a single key=>value pair. The idea is the use the query string to return the user to the previous page after the action has been completed. query results[page1]->view record/action selection[page2]->back to results[page1] I'm sure someone has been down this path before. P.S. the script is all contained within one file, thus the filename.ext is already known. Thanks Hi everyone, I used to know the function, but it was a very long time ago, for when you need to just extract a single value from a query... instead of having to use mysql_fetch_assoc in a while loop to build an array... e.g. Code: [Select] $TheResultingFieldValue = mysql_fetch_SOMETHING(mysql_query("SELECT aField FROM aTable WHERE anotherField = 'aCondition'")); Let me preface this by saying that I've been using php for a while, but never got extremely advanced, so feel free to slap me about for something stupid... I'm working through a jQuery & PHP book, and I've noticed that he's wrapping all his column and table names in the apostrophe ` when making MySQL queries . In the past I've never done this. What does the ` do? I understand about single quotes and double quotes, but haven't come across the ` being used. What's the deal? Hi all, slightly confusing title! What I am trying to do is make a simple stores system whereby I can add and remove stores. It is purely php and no mySQL. My idea was to create a text file with the individual number and then include the file on the table on the page. I have worked out how to increment one value by one, but the others I am struggling with. Example I wish to have two links one which I click to increase and another to decrease the value by one. It's the multiple issue that is confusing me, I create a txt file and a php file using a variable from a submitted form (part number). The php file holds info and the text file holds the number which is default at '0' (Zero). My idea was to write some php to the file, perhaps when I click the plus it will open and write to the file + 1 .. Any guidance or points in the right direction would be greatly appreciated. Thanks. Shugs Hey guys, I'll be the first to say that I'm a real php n00b, and only understand the basics. I have a website already in place that someone else coded and I just need to add something to. There's a form that posts to another page and then back to a sql database. What I want to do is have the form also email me the contents of the form when it is submitted. Is there a way to have a form do multiple actions? I'm not sure the best way to go about this, so if someone has some pointers, I'd really appreciate it. Thanks! I have the form: Hi there im trying to set a single variable multiple rows of data that are echoed using a single variable. The trouble is i just cant seem to make it work by trying to add a while or do loop.. The variable is $alderaanfleetalt and consists of: Code: [Select] $fleetname = "FleetName"; $shipname = "Ship Name"; Which is just text stored in two other variables. The select query row of data is added the $alderaanfleetalt variable. Code: [Select] $alderaanfleetalt = $fleetname." ".$row_Alderaanfleet['FleetName']."</br>".$shipname." ".$row_Alderaanfleet['ShipName']; At the moment only a single row appears. ive tried to add a while/do loop so that multiple rows are outputted but its not working. Code: [Select] do{ $alderaanfleetalt = $fleetname." ".$row_Alderaanfleet['FleetName']."</br>".$shipname." ".$row_Alderaanfleet['ShipName']; } while ($row_Alderaanfleet = mysql_fetch_assoc($Alderaanfleet)); Im a bit lost here and not even sure it can be done this way... Any help would be ace. Thank you |
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