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PHP - Notice: Undefined Offset: 1 Line 58 - Error Produced By Array Key Empty.
I'm trying to develop a Joomla plugin for 1.6/1.7 and from what I've read, future versions are supposed to be php E~STRICT compliant. I know that doesn't mean I have to fix this since it is just a notice, but I am curious how one would hide the error.
Code: [Select] $task_array = explode('.', JRequest::getVar('task')); # Splits article.save $task = $task_array[1]; #This is line 58 I know it happens because $task_array is empty, but how can i wrap that in something to stop this Notice error? I've tried !empty() but that doesn't work. Similar Tutorialsi get the error for this code: <?php $news = fopen("test.txt", "rb"); while (!feof($news) ) { $line = fgets($news); $parts = explode('=', $line); print $parts[0] . $parts[1]. "<BR>";//line 60!!! } fclose($news); ?> i know that this means that the array gets one argument instead of two but i do'nt know how to solve it... this code works fine in my localhost but not on the server Im having this error and have the not even the slightest clue on how to solve it... Code: [Select] Notice: Undefined offset: 2 in C:\wamp\www\updat5.php on line 146 <?php $picture = array(); while($row = mysql_fetch_assoc($result)) { $id = $row['id']; $picture = array(); switch ($row['icon']) { case 1: $picture[$id] = '<img src="img/apple.gif" title="apple" alt="apple" />'; echo $picture[$id]; break; case 2: $picture[$id] = '<img src="img/banana.gif" title="banana" alt="banana" />'; echo $picture[$id]; break; case 3: $picture[$id] = '<img src="img/orange.gif" title="orange" alt="orange" />'; echo $picture[$id]; break; default: $picture[$id] = ''; echo $row['icon'] . " is something other than 1 2 or 3"; break; } } ?> <hr> <?php echo $picture[2]; ?> And line 146 is: echo $picture[2]; My next post will be the full code if needed incase the error I have currently cant be fixed with the current snippet/block i posted. I'm getting an error: Undefined offset: 1 in… I'm trying to display a 2D array after filling it. It displays fine if I echo it while it's being made, but after it is not working.
I'm making a pyramid solitaire game and am trying to set up the pyramid of cards. There are 7 arrays, each with a set amount of cards in them. The first array only gets one cards while the last array gets seven. This makes it like a pyramid. All the indexes that don't get a card are set to 0. So it looks like this where the 1's are cards:
1 0 0 0 0 0 0 0
1 1 0 0 0 0 0 0
1 1 1 0 0 0 0 0
1 1 1 1 0 0 0 0
1 1 1 1 1 0 0 0
1 1 1 1 1 1 0 0
1 1 1 1 1 1 1 0
1 1 1 1 1 1 1 1
The display2Darray function is what is causing the error. Specifically this line:
if($array[$i][$j] == 0)Heres my main code:
<?php
include_once "pyramidCard.php";
include_once "pyramidDeck.php";
$theDeck = new Deck();
$pyramid = array(array(), array(), array(), array(), array(), array(), array());
$size = 7;
$theDeck->shuffleCards();
makePyramid($pyramid, $size, $theDeck);
display2Darray($pyramid, $size);
//************************
// FRUNCTIONS *
//************************
function makePyramid($array, $size, $deck)
{
$row = 0;
for($i = 0; $i < $size; $i++)
{
for($j = 0; $j < $size; $j++)
{
if($j > $row)
{
$array[$i][$j] = 0;
//echo ". <br>";
}
else
{
$array[$i][$j] = $deck->dealCards();
//echo "this card is ".$array[$i][$j]->getFace()." of ".$array[$i][$j]->getSuit()."<br>";
}
}
$row++;
}
}
function display2Darray($array, $size)
{
for($i = 0; $i < $size; $i++)
{
for($j = 0; $j < $size; $j++)
{
if($array[$i][$j] == 0)
echo " ";
else
echo $array[$i][$j]->getFace()." of ".$array[$i][$j]->getSuit();
}
echo "<br>";
}
}
?>
Google has failed me once again . I'm getting this error, which I can't find out how to fix: Here's the code: $Database_Factions = "factions"; $Database_Factions_1 = "Name"; $Database_FName_Num = 1; $searchmemberdata = mysql_query("SELECT " . $Database_Factions_1 . " FROM " . $Database_Factions . " WHERE " . $Database_Factions_1 . " LIKE '" . mysql_real_escape_string($_GET['name']) . "%' LIMIT 1"); $searchdata = mysql_fetch_row($searchmemberdata); echo($searchdata[$Database_FName_Num]); echo("<meta http-equiv='refresh' content='55;url=member.php?action=ViewFaction&name=" . $searchdata[$Database_FName_Num] . "' />"); I know my code is not optimized, I'm fixing it after i'm done with what i'm doing. Everytime $searchdata[$Database_FName_Num] is called, the error: Notice: Undefined offset: 1 comes out. Any help? this is my code im getting an error message Notice: Undefined offset: 20 in C:\wamp\www\examples\ideas\new2.php on line 33 Code: [Select] <?php echo "<table>\n"; //Move through a CSV file, and output an associative array for each line ini_set("auto_detect_line_endings", 1); $current_row = 1; $d=0; $handle = fopen("widget.csv", "r"); while ( ($data = fgetcsv($handle, 10000, ",") ) !== FALSE ) { $number_of_fields = count($data); echo "<thead>\n<tr>"; if ($current_row == 1) { //Header line /* for ($c=0; $c < $number_of_fields; $c++) */ { $header_array[$d] = $data[$d]; echo "<th>" . $data[$d] . "</th>"; } echo "</tr>\n</thead>\n\n<tbody>"; } else { //Data line for ($c=1; $c < $number_of_fields; $c++) echo "<tr>"; { $data_array[$c] = $data[$c]; /* echo "<td>" . $data[$c] . "</td>"; */ } echo "</tr>\n"; } $current_row++; } fclose($handle); echo "</tbody>\n</table>"; echo $number_of_fields; echo "<br />"; echo $current_row; ?> this is my csv file Quote A,Airlie Beach,Andergrove,Alexandra,Armstrong Beach,Alligator Creek,,,,,,,,,,,,,, B,Bucasia,Blacks Beach,Beaconsfield,Bakers Creek,Balberra,Bloomsbury,Breadalbane,Ball Bay,Belmunda,,,,,,,,,, C,Cannonvale,Calen,Crystal Brook,Cremorne,Chelona,Campwin Beach,Cape Hillsborough,Conway,,,,,,,,,,, D,Dows Creek,Dumbleton,Dolphin Heads,,,,,,,,,,,,,,,, E,Eimeo,Eton,Erakala,,,,,,,,,,,,,,,, F,Foulden,Foxdale,Flametree,Farleigh,Freshwater Point,,,,,,,,,,,,,, G,Glen Isla,Glenella,,,,,,,,,,,,,,, ,, H,Homebush,Hampden,,,,,,,,,,,,, ,,,, I,,,,,,,,,,,,,,, ,,,, J,Jubilee Pocket,,,,,,,,,,,,,, ,,,, K,Kinchant Dam,Kolijo,Koumala,Kuttabul,,,,,,,,,,, ,,,, L,Laguna Quays,,,,,,,,,,,,,, ,,,, M,McEwens Beach,Mackay,Mackay Harbour,Mandalay,Marian,Mia Mia,Middlemount,Midge Point,Mirani,Moranbah,Mount Charlton,Mount Jukes,Mount Julian,Mount Marlow,Mount Martin,Mount Ossa,Mount Pelion,Mount Pleasant,Mount Rooper N,Narpi,Nebo,Nindaroo,North Eton,,,,,,,,,,,,,,, O,Oakenden,Ooralea,,,,,,,,,,,,,,,,, P,Palmyra,Paget,Pindi Pindi,Pinevale,Pioneer Valley,Pleystowe,Preston,Proserpine,,,,,,,,,,, Q,,,,,,,,,,,,,,,,,,, R,Racecourse,Richmond,Riordanvale,Rosella,Rural View,,,,,,,,,,,,,, S,St Helens Beach,Sandiford,Sarina,Seaforth,Slade Point,Shoal Point,Shute Harbour,Shutehaven,Strathdickie,Sugarloaf,Sunnyside,,,,,,,, T,Te Kowai,The Leap,,,,,,,,,,,,,,,,, U,,,,,,,,,,,,,,,,,,, V,Victoria Plains,,,,,,,,,,,,,,,,,, W,Wagoora,Walkerston,Woodwark,,,,,,,,,,,,,,,, X,,,,,,,,,,,,,,,,,,, Y,Yalboroo,,,,,,,,,,,,,,,,,, Z,,,,,,,,,,,,,,,,,,, Could anyone please help little stuck on why its causing this error. Hi, I'm testing my PHP in the console and was wondering what this means? PHP Notice: Undefined offset: 1 Is it a warning or an error? My code... Code: [Select] $form_submission = "brother"; $lines = file('eo_dic.txt'); if ($form_submission == null){ // Sanitization. echo 'Text field is empty!'; exit; } foreach ($lines as $line) { list($field1, $field2) = preg_split('/=/', $line); // back slash might not be needed if (stristr($field1, $form_submission) || stristr($field2, $form_submission)){ echo $field1 . ' = ' . $field2; } } The results and error... Code: [Select] Brother = frato Brotherhood = frateco Brotherly = frata PHP Notice: Undefined offset: 1 in /home/asdf/Dev/Projects/eo_translate/script_part2.php on line 50 PHP Notice: Undefined offset: 1 in /home/asdf/Dev/Projects/eo_translate/script_part2.php on line 50 PHP Notice: Undefined offset: 1 in /home/asdf/Dev/Projects/eo_translate/script_part2.php on line 50 PHP Notice: Undefined offset: 1 in /home/asdf/Dev/Projects/eo_translate/script_part2.php on line 50 Line 50 = list($field1, $field2) = preg_split('/=/', $line); while i am coding to find text between some html tags ,, am getting an error... Notice: Undefined offset: 1 in D:\xamp\xampp\htdocs\file\dash.php on line 48 my code is at line 47 and 48 is Code: [Select] preg_match('/<td class="trow1" rowspan="3" valign="top">(.*)<\/td> /',$dat,$regs); echo $etc=$regs[1]; i am thinking copy data from Code: [Select] </td> <td class="trow1" rowspan="3" valign="top"> Posts per day: <strong>6.03</strong><br /> Threads per day: <strong>3.78</strong><br /> Members per day: <strong>4.76</strong><br /> Posts per member: <strong>1.27</strong><br /> Replies per thread: <strong>0.6</strong> </td> </tr> this much Code: [Select] Posts per day: <strong>6.03</strong><br /> Threads per day: <strong>3.78</strong><br /> Members per day: <strong>4.76</strong><br /> Posts per member: <strong>1.27</strong><br /> Replies per thread: <strong>0.6</strong> Here is an example of the beginning of a rating system script: Code: [Select] // RATING SYSTEM - START if ((isset($array[0]) || isset($array[1])) && isset($_SESSION['user_id'])) { // check to see if user has already voted on given contribution $query = "SELECT * FROM votes WHERE con_id = '$array[2]' AND user_id = '$array[3]'"; $query_run = mysqli_query ($dbc, $query) or die (mysqli_error($dbc)); $num_rows = mysqli_num_rows ($query_run); $assoc = mysqli_fetch_assoc ($query_run); $rating = $assoc['rating']; // check to see if it's user's own contribution $query = "SELECT * FROM con WHERE con_id = '$array[2]'"; $query_run = mysqli_query ($dbc, $query) or die (mysqli_error ($dbc)); $assoc = mysqli_fetch_assoc ($query_run); $con_user_id = $assoc['user_id']; For every array variable I am getting the error message "Undefined Offset". Any ideas how to solve this one, I do not fully know yet what is common practice in these cases. The warnings also do not always happen, they usually happen, they happen in a specific moment when I use a drop down menu, to show table content. hello all, i am stuck with a problem and hoping someone can help me. i have got the following code to sort of work. the problem i am having is when i put e.g. index.php?page=test and there is no information with test under page in the sqlite db i get this message, Notice: Undefined offset: 0 in C:\xampp\htdocs\test\Frontend\left.php on line 8. as soon as i type index.php?page=test2 and i have test2 in the database the error is gone and shows the content heres the code Code: [Select] if (isset($_GET['page'])) { $page = $_GET['page']; // Display Page. $query = "SELECT body FROM content WHERE page = '$page' AND location = 'left' AND disabled = 'no' ORDER BY id"; $results = $base->arrayQuery($query, SQLITE_ASSOC); $arr = $results[0]; echo '<div id="left">'; echo '<p>' . $arr['body'] . '</p>'; echo '</div>'; } else { //Show Home Page $query = "SELECT body FROM content WHERE page = 'home' AND location = 'left' AND disabled = 'no' ORDER BY id"; $results = $base->arrayQuery($query, SQLITE_ASSOC); $arr = $results[0]; echo '<div id="left">'; echo '<p>' . $arr['body'] . '</p>'; echo '</div>'; } hope you understand what i am trying to say, thanks very much all. the array is getting the values as he should get and from there i send them to $temp (string),but when i'm trying to print them i can't. the array and the string at the end of code saved the values that the code gave them,but i can print the values one by one, but i need the values in string and the array at the end and print $temp(string) in a row without white space. print_r is working but she's not build to this job can someone look at the code and the result of the code and tell me what seem to be the problem and how to fix that? the problem start with $txt when the array is getting the values. the output of this code:http://pastebin.com/0QkzjviW the code page is attach to this message as php file. I am new to php and html, I am trying to make a search function where you can search by a persons firstname or lastname but I am getting an error. the error is Notice: Undefined variable: searchq in C:\wamp\www\search2.php on line 17. Can anyone help me please hi, I need help really badly for my PHP-Postcard Script. Basically it sends the card out but the URL does not work, I get the following error message: The URL is not valid and cannot be loaded It also states that Notice: Undefined index: www.voluntary.awardspace.co.uk in /home/www/voluntary.awardspace.co.uk/Postcard.php on line 25 Notice: Undefined index: Postcard.php in /home/www/voluntary.awardspace.co.uk/Postcard.php on line 25 See Code below: <?php session_start(); //check error log ini_set('display_errors', 1); ini_set('log_errors', 1); ini_set('error_log', dirname(__FILE__) . '/error_log.txt'); error_reporting(E_ALL); // CHANGE PARAMETERS HERE BEGIN $senderName = " Holidays From Home "; // Eg.: John's Postcards $senderEmail = "chris01@voluntary.awardspace.co.uk"; // Eg.: john@postcard.com // Change only if you have problems with urls $postcardURL = "http://".$_SERVER["www.voluntary.awardspace.co.uk"].$_SERVER["Postcard.php"]; // CHANGE PARAMETERS HERE END $result = 0; $msg = ""; $msg1 = ""; $pic = ""; function displayPhotos() { global $pic; $columns = 5; $act = 0; $act1 = 0; // Open the actual directory if($handle = opendir("thumbs")) { // Read all file from the actual directory while($file = readdir($handle)) { if(!is_dir($file)) { if(isset($pic[1])) { if($pic[1] == $act1){$sel = "checked";} else{$sel = "unchecked";} } if($act == 0){echo "<tr>";} echo "<td align='center'><img src='thumbs/$file' alt='postcard'/><br/><input type='radio' name='selimg' value='$file,$act1' $sel/></td>"; $act++; $act1++; if($act == $columns){$act = 0;echo "</tr>";} } } echo "</tr>"; } } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "DTD/xhtml1-transitional.dtd"> <html> <head> <title>Micro Postcard</title> <link href= "style/style.css" rel="stylesheet" type="text/css" /> </head> <body> <div id="main"> <div class="style1" id="caption"> <div align="left" class="style1"></div> </div> <?php //makes sure form is correctly filled in if(!empty($_POST["submit"])) { if(empty($_POST["selimg"])){$msg = "Please select an image from above!";$result = 3;} else{$pic = explode(",",$_POST["selimg"]);} if(empty($_POST["email"]) && empty($result)){$msg1 = "You must enter an email address!";$result = 3;} $secCode = empty($_POST["secCode"]) ? "" : strtolower($_POST["secCode"]); if($secCode == $_SESSION["securityCode"] && $result != 3) { $filename = date("YmdGis"); $f = fopen("messages/".$filename.".txt","w+"); fwrite($f,$pic[0]."\n"); fwrite($f,$_POST['email']."\n"); fwrite($f,stripslashes($_POST["message"])."\n"); fclose($f); // Compose the mail $from = "From: $senderName <$senderEmail>\r\n"; $replay = "Reply-To: $senderEmail\r\n"; $params = "MIME-Version: 1.0\r\n"; $params .= "Content-type: text/plain; charset=iso-8859-1\r\n"; $mailtext = "You have just received a Virtual Postcard!\r\n\r\n You can pick up your postcard at the following web address:\r\n $postcardURL?show=$filename\r\n\r\n We hope you enjoy your postcard, and if you do, please take a moment to send a few yourself!\r\n\r\n Regards,\r\n Holidays From Home\r\n $postcardURL"; // Send email @mail($_POST["email"],"You've received a postcard",$mailtext,$from.$replay.$params); echo "<center> Your postcard was sent successfully!<br /><br /> <img src='images/$pic[0]' alt='postcard' /><br /><br /><br />".stripslashes($_POST["message"]). "</center>"; $result = 1; } else{if($result != 3){$result = 2;}} } if(!empty($_GET["show"])) { $file = $_GET["show"]; $content = file("messages/$file.txt"); $pic = $content[0]; unset($content[0]); unset($content[1]); foreach($content as $value){$main .= $value;} echo "<center> Your postcard!<br /><br /> <img src='images/$pic' alt='postcard' /><br /><br /><br />$main </center>"; } if((empty($result) || $result == 2 || $result == 3) && empty($_GET["show"])) { echo "<form action='#' method='post'> <table align='center'>"; displayPhotos(); echo "</table> <div style='color:#f00;font-size:16px;'>$msg</div> <h2>Fill in the Form and then click on Send Card!!</h2> <table width='100%'> <tr><td>Send to (email address):</td><td><div style='color:#f00;font-size:16px;'>$msg1</div><input type='text' name='email' size='30' value='".$_POST["email"]."' /></td></tr> <tr><td>Message:</td><td><textarea name='message' rows='10' cols='40'>".stripslashes($_POST["message"])."</textarea></td></tr> <tr><td colspan='2'>".($result == 2 ? "<p style='color:#f00;font-size:16px;'>Sorry the security code is invalid! Please try it again!</span></p>" : " ")."</tr> <tr> <td>Security code: <input class='text' name='secCode' type='text' size='10' /> </td><td><img src='securityCode.php' alt='security code' border='1' /></td> </tr> <tr><td colspan='2'> </tr> <tr><td colspan='2' align='left'><input type='submit' value='Send card!' name='submit'/></td></tr> </table> </form>"; } ?> Absolutely any help would be much appreciated. I want ot know is there a way round this problem? Here is the http://voluntary.awardspace.co.uk/Postcard.php I am absolutely desperate to solve this burning issue I have 2 issues happening, first one I need to get resolved is, line 60 is giving me a 'Notice: Undefined variable: delete'. This codes had multi issues but was able to resolve all but this one and my table not filling in with the data from my database. If you need any other info please let me know, Again I am new at this.
<tr> <td colspan="5" align="center" bgcolor="#FFFFFF"><input name="delete" type="submit" id="delete value="delete"></td> </tr> <?php // Check if delete button active, start this *line 60* -----> if ($delete){ for($i=0;$i<$count;$i++){ $del_id = $checkbox[$i]; $sql = "DELETE FROM $tbl_name WHERE id='$del_id'"; $result = mysqli_query($sql); } // if successful redirect to delete_multiple.php if($result){ echo "<meta http-equiv=\"refresh\" content=\"0;URL=delete_multiple.php\">"; } } mysqli_close($con); ?> Hell Every one , there is some problem in this code one line 54,117,129 and 133
please help me
l attached
registration.php 5.72KB
1 downloads file .please download the attached file.
I get an undefined offset error when i try and call the array i made i know very little so I'm stuck and i don't know what to do Code: [Select] <?php $file = fopen("playerstats.csv","r"); $data = array(); while (($csv_line = fgetcsv($file, 0, ";")) !== FALSE) { echo $csv_line; $number = $csv_line[0]; $name = $csv_line[1]; $half = $csv_line[2]; $goals = $csv_line[3]; $assists = $csv_line[4]; $SOG = $csv_line[5]; $shots = $csv_line[6]; $fouls = $csv_line[7]; $yellow = $csv_line[8]; $yellowred = $csv_line[9]; $red = $csv_line[10]; $CK = $csv_line[11]; $saves = $csv_line[12]; $data[] = array( 'name' => $name, 'half' => $half, 'goals' => $goals, 'assists' => $assists, 'sog' => $SOG, 'shots' => $shots, 'fouls' => $fouls, 'yellow' => $yellow, 'yellowred' => $yellowred, 'red' => $red, 'ck' => $CK, 'saves' => $saves ); } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <table><tr><td>Number: </td><td><?php echo $data[0];?></td></tr></table> </body> </html> Hi everyone... please help me with this. I have a gallery that I am working on. Part of that are two files upload.php and preupload.php which upload pics. And it does its job successfully BUT it shows an error 'Notice: Undefined offset: 9 in C:\wamp\www\upload.php on line 34' My line 34 is Code: [Select] if($photos_uploaded['size'][$counter] > 0). My whole code for the upload.php is <?php include("config.inc.php"); // initialization $result_final = ""; $counter = 0; // List of our known photo types $known_photo_types = array( 'image/pjpeg' => 'jpg', 'image/jpeg' => 'jpg', 'image/gif' => 'gif', 'image/bmp' => 'bmp', 'image/x-png' => 'png' ); // GD Function List $gd_function_suffix = array( 'image/pjpeg' => 'JPEG', 'image/jpeg' => 'JPEG', 'image/gif' => 'GIF', 'image/bmp' => 'WBMP', 'image/x-png' => 'PNG' ); // Fetch the photo array sent by preupload.php $photos_uploaded = $_FILES['photo_filename']; // Fetch the photo caption array $photo_caption = $_POST['photo_caption']; while( $counter <= count($_FILES['photo_filename']['tmp_name']) ) { if($photos_uploaded['size'][$counter] > 0) { if(!array_key_exists($photos_uploaded['type'][$counter], $known_photo_types)) { $result_final .= "File ".($counter+1)." is not a photo<br />"; } else { mysql_query( "INSERT INTO gallery_photos( `photo_filename`, `photo_caption`, `photo_category` ) VALUES( '0', '".addslashes($photo_caption[$counter])."', '".addslashes($_POST['category'])."')" ) or die(mysql_error() . 'Photo not uploaded'); $new_id = mysql_insert_id(); $filetype = $photos_uploaded['type'][$counter]; $extention = $known_photo_types[$filetype]; $filename = $new_id.".".$extention; mysql_query( "UPDATE gallery_photos SET photo_filename='".addslashes($filename)."' WHERE photo_id='".addslashes($new_id)."'" ); // Store the orignal file copy($photos_uploaded['tmp_name'][$counter], $images_dir."/".$filename); // Let's get the Thumbnail size $size = GetImageSize( $images_dir."/".$filename ); if($size[0] > $size[1]) { $thumbnail_width = 200; $thumbnail_height = (int)(200 * $size[1] / $size[0]); } else { $thumbnail_width = (int)(200 * $size[0] / $size[1]); $thumbnail_height = 200; } // Build Thumbnail with GD 1.x.x, you can use the other described methods too $function_suffix = $gd_function_suffix[$filetype]; $function_to_read = "ImageCreateFrom".$function_suffix; $function_to_write = "Image".$function_suffix; // Read the source file $source_handle = $function_to_read ( $images_dir."/".$filename ); if($source_handle) { // Let's create an blank image for the thumbnail $destination_handle = ImageCreateTrueColor ( $thumbnail_width, $thumbnail_height ); // Now we resize it ImageCopyResized( $destination_handle, $source_handle, 0, 0, 0, 0, $thumbnail_width, $thumbnail_height, $size[0], $size[1] ); } // Let's save the thumbnail $function_to_write( $destination_handle, $images_dir."/tb_".$filename, 99 ); ImageDestroy($destination_handle ); // $result_final .= "<img src='".$images_dir. "/tb_".$filename."' /> File ".($counter+1)." Added<br />"; } } $counter++; } // Print Result echo <<<__HTML_END <html> <head> <title>Photos uploaded</title> </head> <body> $result_final </body> </html> __HTML_END; ?> I am getting these errors . This is my complete HTML page. Everything seems to work fine but when i retweet a message these error show up. Here is my tweet.php and the errors are at line 32 and 41. Previously there was an error at line 24: It was like this: '.((!empty($tweet->retweetMsg) && $tweet->tweetID === $retweet['tweetID'] or $tweet->retweetID > 0) ? ' I changed it to this and the error went away '.((isset($retweet['retweetID']) ? $retweet['retweetID'] === $tweet->retweetID OR $tweet->retweetID > 0 : '') ? ' Maybe this could help! I will really appreciate any suggestion coming my way! im getting Undefined offset: 0 in many line what can be the issue? Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /><!-- <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> --> <title>Untitled Document</title> </head> <body> <?php if(isset($_POST['submit'])) { $userquery = $_POST['userquery']; $xml = simplexml_load_file("http://www.google.com/ig/api?weather='".$userquery."'"); $information = $xml->xpath("/xml_api_reply/weather/forecast_information"); $current = $xml->xpath("/xml_api_reply/weather/current_conditions"); $forecast_list = $xml->xpath("/xml_api_reply/weather/forecast_conditions"); echo "<h1>".$information[0]->city['data'].", ".$information[0]->forecast_date['data']."</h1>"; echo "<h2>Current Contition</h2>"; echo "<div class=\"weather\">"; echo "<table width='250' border='1'>"; echo "<tr>"; echo "<td><img src='http://www.google.com".$current[0]->icon['data']."' width='70' height='70' alt='weather'></td>"; echo "<td>"; echo $current[0]->condition['data']; echo "<br/>Min "; echo $current[0]->temp_c['data']."° C, <br/>"; echo $current[0]->temp_f['data']."° F, <br/>"; echo $current[0]->humidity['data'].", <br/>"; echo $current[0]->wind_condition['data']."."; echo "</td>"; echo "</tr>"; echo "</table>"; echo "</span>"; echo "</div>"; echo "<h2>Forecast</h2>"; foreach ($forecast_list as $forecast) : echo "<div class=\"weather\">"; echo "<table width='250' border='1'>"; echo "<tr>"; echo "<td>"; echo "<img src='http://www.google.com".$forecast->icon['data']."' width='50' height='50'alt='weather'>"; echo "</td>"; echo "<td>"; echo "<div>".$forecast->day_of_week['data']."</div>"; echo "<span class=\"condition\">"; echo $forecast->low['data']."° F - ".$forecast->high['data']."° F,<br/>"; echo $forecast->condition['data']."."; echo "</td>"; echo "</tr>"; echo "</table>"; echo "</span>"; echo "</div>"; endforeach; } ?> <form action="test.php" method="post"> <input name="userquery" type="text" value=""/> <input type="submit" name='submit' value="get"/> </form> </body> </html> here all errors and there are few more Notice: Undefined offset: 0 in C:\wamp\www\fiunc\test.php on line 16 Notice: Trying to get property of non-object in C:\wamp\www\fiunc\test.php on line 16 Notice: Undefined offset: 0 in C:\wamp\www\fiunc\test.php on line 16 Notice: Trying to get property of non-object in C:\wamp\www\fiunc\test.php on line 16 , it happens when i add if(isset($_POST['submit'])) { $userquery = $_POST['userquery']; and this in '".$userquery."' $xml = simplexml_load_file("http://www.google.com/ig/api?weather='".$userquery."'"); What I am trying to do is to associate a user (id) to a page they create, so if joe blogs is user 4, then the data base will show the page details, and add the id (from a user page). However, when I try the code to save data I get the following error messages:
Notice: Undefined offset: 4 in C:\xampp\htdocs\MyCMS\admin\index.php on line 98 I include the code to insert the page:
<!-- Insert Page -->
<?php
if(isset($_POST['submitted']) == 1) {
$header = stripslashes($_REQUEST['header']);
$header = mysqli_real_escape_string($dbc, $header);
$title = stripslashes($_REQUEST['title']);
$title = mysqli_real_escape_string($dbc, $title);
$body = stripslashes($_REQUEST['body']);
$body = mysqli_real_escape_string($dbc, $body);
$userid = stripslashes($_REQUEST['userid']);
$userid = mysqli_real_escape_string($dbc, $userid);
$q = "INSERT INTO `pages` (`userid`, `header`, `title`, `body`) VALUES ($_POST[$userid], '$header', '$title', '$body')";
$r = mysqli_query($dbc, $q) or die(mysqli_error($dbc));
if($r) {
$message = '<p>Page was added.</p>';
} else {
$message = '<p>Page could not be added due to: </p>'.mysqli_error($dbc);
$message .= '<p>'.$q.'</p>';
} // end if inner
} // end if outer
?>
The form has - Page Header, Page Title, User, and boys. There is a working list of current users. It is these users (and new users) that I want to add to a 'Pages' database, which has the following fields: id, userid, header, title, body; and a 'User' database with the following fields: id, firstname, lastname, username, password, status. Any help to solve the issues will be appreciated. Thanks.
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