PHP - Strange Isset($_get Problem
I am trying to do isset($_GET but I have a bizarre problem come up. I am using "id" as one of my fields but when I try to use it in the code it says it is not recognised. However I use this field quite widely.
The code its coming up with is "Undefined variable: id" but I cant see why it has a problem with id. My code is: <?php if(isset($_GET['id'])){ $sql = mysql_query("SELECT * FROM productfeed WHERE id='$id' LIMIT 1"); } { while($row = mysql_fetch_array($sql)) $id = $row['id']; $image = $row['awImage']; $link = $row['link']; $description = $row['description']; $fulldescription = $row['fulldescription']; $price = $row['price']; echo "<div class=\"productdisplayshell\"> <div class=\"productdisplayoutline\"> <div class=\"productborder\"><center> <a href=\"$link\" target=\"_blank\" ><img src=\"$image\" /></a> </center> </div></div> <div class=\"productdescriptionoutline\"><div class=\"productdescriptionbox\"> <a href=\"$link\" target=\"_blank\" >$description</a> </div><div class=\"productfulldescriptionbox\"> $fulldescription </div></div> <div class=\"productpriceoutline\"> <div class=\"productpricebox\"><center>&#163; $price</center></div> <div class=\"productbuybutton\"><center><a href=\"$link\" target=\"_blank\" ><img src=/images/buybutton.png /></a></center></div></div></div>"; } ?> Similar TutorialsI am having problems with my $_GET. When a user chooses an Article from "article_index.php", they click on a hyperlink, e.g. Code: [Select] <a href="<?php echo BASE_URL; ?>articles/postage-meters-can-save-you-money"> This triggers my Mod_Rewrite... Code: [Select] RewriteEngine on #PRETTY: articles/postage-meters-can-save-you-money #UGLY: article.php?slug=postage-meters-can-save-you-money RewriteRule articles/([a-zA-Z0-9_-]+)$ article.php?slug=$1 Which should take them to "article.php?slug=postage-meters-can-save-you-money" and then this code is supposed to grab the "slug" and retrieve the Article... Code: [Select] // Attempt to Retrieve Article. if (isset($_GET['slug'])){ // Slug found in URL. // Set Slug. $slug = $_GET['slug']; That part is working fine, however, if I go into the Address Bar and delete out the slug, so my URL looks like this... Code: [Select] www.MySite.com/articles/"> I would expect the ELSE part of the above code to kick in... Code: [Select] }else{ // Slug not found in URL. header("Location: " . BASE_URL . "index.php"); }//End of ATTEMPT TO RETRIEVE ARTICLE Unfortunately I am just getting this error... Quote Not Found The requested URL /articles/ was not found on this server. Apache/2.0.59 (Unix) PHP/5.2.6 DAV/2 Server at local.debbie Port 80 Why is my ELSE not detecting that there is no slug?? Debbie A few months ago, and a good amount of time before that, I had people telling me to use isset() instead of performing to see if the variable is empty, such as: !$_GET[''] I know the differences in the function and what they do, but when could isset() be used in a situation where it's better/more efficient then: !$_GET[''] I do use isset(), though. Hi, I'm new to php and am attempting to build a site where the navigation and content is built with query functions. My current tables in my database are Categories, Products, and Variation. So a person chooses a category -> then a product -> then a product page shows variations for that product. The problem I am currently having is after when a person selects a section the previous section selected is reset. So lets a person selects a category the product list is shown, but when a person selects a product, the category is no longer selected in the navigation. Or if someone selects product and sees all the variations, if he selects a variation the product ID is reset. I've tried to comb through the internet for some type of solution. I came across concatenating URL encode, but am not sure if this is the correct solution. I tried concatenating one of my urls with Code: [Select] "<a href=\"product_detail.php?cat=" . urlencode($sel_cat["id"]) . '&' . "product=" . urlencode($sel_product['id']) . '&' . "var=" . urlencode($var["id"]) . "\" its a bit of a stab in the dark. My $_GET function is Code: [Select] function find_selected_product() { global $sel_cat; global $sel_product; global $sel_var; if (isset($_GET['cat'])) { $sel_cat = get_cat_by_id($_GET['cat']); } elseif (isset($_GET['product'])) { $sel_cat = NULL; $sel_product = get_product_by_id($_GET['product']); } elseif (isset($_GET['product'])) { $sel_product = get_product_by_id($_GET['product']); $sel_var = get_default_var($sel_product['id']); } elseif (isset($_GET['var'])) { $sel_product = NULL; //test $sel_var = get_variation_by_id($_GET['var']); } else { $sel_cat = NULL; $sel_product = NULL; $sel_var = NULL; } } My navigation code is Code: [Select] function public_navigation($sel_cat, $public = true) { $output = "<td class=\"c1\"><div class=\"sidenav\"><ul>"; $cat_set = get_all_cats($public); while ($cat = mysql_fetch_array($cat_set)) { $output .= "<li>"; if ($cat["id"] == $sel_cat['id']) { $output .= "<a class=\"current\""; } $output .= "<a href=\"index.php?cat=" . urlencode($cat["id"]) . "\">{$cat["cat_name"]}</a></li>"; } $output .= "</ul>"; return $output; } My product is divided into gender and is written like Code: [Select] function cat_content_ladies($sel_cat, $sel_product, $female = true) { $output = "<ul class=\"regions\">"; $cat_set = get_all_cats($female); while ($cat = mysql_fetch_array($cat_set)) { if ($cat["id"] == $sel_cat['id']) { $product_set = get_products_for_female($cat["id"], $female); $output .= "<tr>"; while ($product = mysql_fetch_array($product_set)) { if ($cat["id"] == $sel_cat['id']) { $output .= "<tr>"; $output .= "<div class=\"pre\"><a href=\"product_detail.php?product=" . urlencode($product["id"]) . "\"></li>"; $output .= "<img src=\"{$product["img_src"]}\" height=\"121\" width=\"121\">"; $output .= "<div>{$product["prod_name"]}</a></div>"; } } $output .= "</tr>"; } } return $output; } My variation table is set up in thumb nails and is written in this function Code: [Select] function show_thumb($sel_product, $sel_var, $public = true) { $output = "<ul class=\"subjects\">"; $product_set = get_all_products($public); while ($product = mysql_fetch_array($product_set)) { $output .= "<li"; if ($product["id"] == $sel_product['id']) { $output .= " class=\"selected\""; } //$output .= "><a href=\"product_detail.php?product=" . urlencode($product["id"]) . //"\">{$product["id"]}</a></li>"; if ($product["id"] == $sel_product['id']) { $var_set = get_variations_for_product($product["id"], $public); $output .= "<ul class=\"pages\">"; while ($var = mysql_fetch_array($var_set)) { $output .= "<li"; if ($var["id"] == $sel_var['id']) { $output .= " class=\"selected\""; } $output .= "><a href=\"product_detail.php?var=" . urlencode($var["id"]) . "\">{$var["id"]}</a></li>"; } $output .= "</ul>"; } } $output .= "</ul>"; return $output; } any light on this subject would be greatly appreciated. Hi I have written a simple bit of code, i used to code php a little and have just decided to start coding php again but for the life of me can't work out why this isn't working, so if someone could help this would be great. address www.mysite.co.uk/index.php?vid=video2 <php if (isset($_GET['vid'])){ $video=$_GET['vid']; }else{ $video="video1"; } when i echo $video i only get video=1 soory guys .. actually i am trying to add pagination in script.. but its not pagging.
but when i tried without isset($_get the code worked fine and then i tried to doing with isset($_get for a perticular cat
but its not working. can someone see my code and tell me whats worng i have done.
<!DOCTYPE HTML> <html> <head> </head> <body> <?php // include database connection include 'libs/db_connect.php'; // page is the current page, if there's nothing set, default is page 1 $page = isset($_GET['page']) ? $_GET['page'] : 1; // set records or rows of data per page $recordsPerPage = 1; // calculate for the query LIMIT clause $fromRecordNum = ($recordsPerPage * $page) - $recordsPerPage; // select all data $query = "SELECT * FROM posts ORDER BY post_id desc LIMIT {$fromRecordNum}, {$recordsPerPage}"; /* page and its LIMIT clause looks like: 1 = 0, 5 2 = 5,10 3 = 10,15 4 = 15, 20 5 = 20, 25 */ $stmt = $con->prepare( $query ); $stmt->execute(); //this is how to get number of rows returned $num = $stmt->rowCount(); //check if more than 0 record found if($num>0){ $cat=1; if(isset($_GET['cat'])){ $cat_id = $_GET['cat']; $get_posts = "select * from posts where category_id = '$cat_id'"; $run_posts = mysql_query($get_posts); while($row_posts = mysql_fetch_array($run_posts)){ $post_id = $row_posts['post_id']; $post_title = $row_posts['post_title']; $post_date = $row_posts['post_date']; $post_author = $row_posts['post_author']; $post_image = $row_posts['image']; $post_content = substr($row_posts['post_content'],0,80); echo " <div class='post_area'> <h4> <a href = 'details.php?post=$post_id'>$post_title</a> </h4> <div class='date'><div id='com'> Date</div>$post_date</div><span style='font-size:12px'><i style='color:grey;font-size:10px'>Posted By</i> </b>$post_author</span> <content><img src = '123dondadatest/news_images/$post_image' width = '100' height='100'/> <div>$post_content <br/><a id='rmlink' href = 'details.php?post=$post_id'> Read More...</a></div><br /><br/><br/><br/> </div> "; } } // *************** <PAGING_SECTION> *************** echo "<div id='paging'>"; // ***** for 'first' and 'previous' pages if($page>1){ // ********** show the first page echo "<a href='" . $_SERVER['PHP_SELF'] . "' title='Go to the first page.' class='customBtn'>"; echo "<span style='margin:0 .5em;'> << </span>"; echo "</a>"; // ********** show the previous page $prev_page = $page - 1; echo "<a href='" . $_SERVER['PHP_SELF'] . "?page={$prev_page}' title='Previous page is {$prev_page}.' class='customBtn'>"; echo "<span style='margin:0 .5em;'> < </span>"; echo "</a>"; } // ********** show the number paging // find out total pages $query = "SELECT COUNT(*) as total_rows FROM posts"; $stmt = $con->prepare( $query ); $stmt->execute(); $row = $stmt->fetch(PDO::FETCH_ASSOC); $total_rows = $row['total_rows']; $total_pages = ceil($total_rows / $recordsPerPage); // range of num links to show $range = 2; // display links to 'range of pages' around 'current page' $initial_num = $page - $range; $condition_limit_num = ($page + $range) + 1; for ($x=$initial_num; $x<$condition_limit_num; $x++) { // be sure '$x is greater than 0' AND 'less than or equal to the $total_pages' if (($x > 0) && ($x <= $total_pages)) { // current page if ($x == $page) { echo "<span class='customBtn' style='background:red;'>$x</span>"; } // not current page else { echo " <a href='{$_SERVER['PHP_SELF']}?page=$x' class='customBtn'>$x</a> "; } } } // ***** for 'next' and 'last' pages if($page<$total_pages){ // ********** show the next page $next_page = $page + 1; echo "<a href='" . $_SERVER['PHP_SELF'] . "?page={$next_page}' title='Next page is {$next_page}.' class='customBtn'>"; echo "<span style='margin:0 .5em;'> > </span>"; echo "</a>"; // ********** show the last page echo "<a href='" . $_SERVER['PHP_SELF'] . "?page={$total_pages}' title='Last page is {$total_pages}.' class='customBtn'>"; echo "<span style='margin:0 .5em;'> >> </span>"; echo "</a>"; } echo "</div>"; // ***** allow user to enter page number echo "<form action='" . $_SERVER['PHP_SELF'] . "' method='GET'>"; echo "Go to page: "; echo "<input type='text' name='page' size='1' />"; echo "<input type='submit' value='Go' class='customBtn' />"; echo "</form>"; // *************** </PAGING_SECTION> *************** } // tell the user if no records were found else{ echo "<div class='noneFound'>No records found.</div>"; } ?> </body> </html> Hey, I've got a site and I need to query a database to check if there is a result. If there isnt then I need a default result... //Check the database and get a result $skinName = strtolower(get_post_meta($post_id, $key, $single)); if (isset($skinName)) { //If there is a result, then use it $skinName = strtolower(get_post_meta($post_id, $key, $single)); } else { //If NO result then use RED $skinName = 'red'; } //Build up the var to show REDsite $skinName = $skinName . 'site'; For some reason the above doesnt work. If there is a result then it uses it, however if there is no result then it simply shows "site" - not "redsite" like it should do. Any ideas what I missed? I'm having a problem where when I click the "use" link it only displays my check message which is "Hey", but for some reason I have to click it again for my queries to work. Here's a pick: . Here's the code: Code: [Select] <?php if(isset($_SESSION['user'])){ include_once('connect.php'); $session = $_SESSION['user']; echo " <br/> <div class='profile-general-stats'> <table> <th>Item Name</th><th>Description</th><th>Use/Sell</th> "; $yo = "SELECT * FROM player_items WHERE Username = '$session' ORDER BY id ASC"; $check = mysql_query($yo) or die (mysql_error()); $num_of = mysql_num_rows($check); if($num_of > 0){ while ($is = mysql_fetch_array($check)){ $item_id = $is['id']; $item_name = $is['Name']; $item_type = $is['Type']; $item_value = $is['Value']; $item_description = $is['Description']; $item_sell_value = $is['Sell_Price']; echo " <tr> <td align='left' style='padding: 5px; padding-left: 25px;'><strong>$item_name</strong></td> <td align='left' style='padding: 5px;'>$item_description</td> <td align='middle' style='padding: 5px;'><a href='?use&id=$item_id&name=$item_name&type=$item_type&value=$item_value'>Use</a> | <a href='#sell_$item_name' id='$item_id'>Sell</a></td> </tr> "; } }else{ echo " <tr> <td align='left' style='padding: 5px; padding-left: 25px;'>No Items</td> <td align='left' style='padding: 5px;'>No Items</td> <td align='middle' style='padding: 5px;'>No Items</td> </tr> "; } echo " </table> </div> "; if(isset($_GET['use'])){ echo "Hey"; $use_id = $_GET['id']; $use_name = $_GET['name']; $use_type = $_GET['type']; $use_value = $_GET['value']; if($use_type == "Credits"){ $use_type = "Current_Credits"; } $check_item = "SELECT id FROM player_items WHERE id = '".mysql_real_escape_string($use_id)."' AND Username = '".$_SESSION['user']."'"; $run_check = mysql_query($check_item) or die(mysql_error()); $num_check = mysql_num_rows($run_check); $e = mysql_fetch_array($run_check); $item_stat = "SELECT `".$use_type."` FROM stats WHERE Username = '".$_SESSION['user']."'"; $run_stat = mysql_fetch_array(mysql_query($item_stat)) or die (mysql_error()); $new_stat = $run_stat[''.$use_type.'']; if($num_check == 1){ $new_stat = $new_stat + $use_value; mysql_query("UPDATE stats SET `".$use_type."` = '".mysql_real_escape_string($new_stat)."' WHERE Username = '".mysql_real_escape_string($_SESSION['user'])."'") or die(mysql_error()); mysql_query("DELETE FROM player_items WHERE id = '$use_id'") or die(mysql_error()); }else{ } }else{ } }else{ header("Location: index.php"); } ?> Hi guys I am trying to create a page where if a selection has not been made then a jump menu is displayed listing all of the fixtures for a season, if a selection has been made then at present I want it to show Enter match info, however when a match is selectd it goes to a yahoo search page, as if the page cannot be found, the code I have used is below, any ideas what I have done wrong? The page can be seen at www.yardleyheroes.co.uk/admin/edit_result.php Code: [Select] <h1>Submit Results</h1> <?php if (isset ($_GET['match_id'])) { echo('Enter match info'); } else { $con = mysql_connect('localhost', 'user', 'password', true); if(!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db('dbname', $con); echo('<form name="form" id="form">'); echo('<select name="jumpMenu" id="jumpMenu" onChange="MM_jumpMenu(\'parent\',this,0)">'); $fixtures=mysql_query('SELECT * FROM `fixtures` where current=1 ORDER BY `match_date`'); if(mysql_num_rows($fixtures)==0) echo('<option>there is no data in table..</option>'); else echo('<option selected="selected">Please select the match</option>'); { while($matchrow=mysql_fetch_assoc($fixtures)) { echo ('<option value="edit.php?match_id='.$matchrow['match_id'].'">'.date("d-M-Y", strtotime($matchrow['match_date'])).'|'.$matchrow['Opposition']."</option>"); } } echo('</select>'); echo('</form>'); } ?> [/cod] Hi guys, first time posting here. Anyway, heres my problem. I have this section of code at the beggining of my page: Code: [Select] if (isset($_POST['userChoice'])) { $try = check_word($_POST['userChoice']); echo ("We are into the loop"); } else { echo ("<br/>about to call change word"); changeword(); echo ("<br/> we called the changeword"); } And here is my form: Code: [Select] <html> <head> </head> <body> <form name="wordguess" action="Index.php" method="POST"> <table> <tbody> <tr> Try to guess what the following word is: <?=$scrambled ?> <br/> </tr> <tr> Your Guess: <input type="text" id="userChoice" size="20" /> <br/> </tr> <tr> <td> <input type="submit" name="submit" id="submit" value="Submit"> </td> </tr> <tr> <?=$correct?> </tr> </tbody> </table> </form> </body> </html>' Now, how i assumed it worked was that the first time the page is loaded it would display the form and that's it. However, even when they hit the submit button on the form, its not really doing the POST, so when the page reloads, gives me the same stuff so it always goes on the else part of the if. Any help would be appreciated. Thanks, GoodVibe Hi, I'm very new to PHP so I hope this is not frustrating. I'm having trouble understanding how "isset" works. I'm trying to get it so that when I click a button, it returns two variables(in an array). This works, but I tried to use "Isset" to detect if a array was created, then alter the variable. It's not working... I'm not too sure where I'm going wrong, could anyone give me some advice? Thanks
<?php if(isset($_POST['name'])) { $userAnswer = $_POST['name']; if(isset($_SESSION['test'])){ $_SESSION['test'][$userAnswer]['var1']++; $test = $_SESSION['test'][$userAnswer]; foreach ($test as $key){ echo json_encode($key); }; } else { $test = $_SESSION['test'][$userAnswer]=array("var1" => 1, "var2" => 2); foreach ($test as $key){ echo json_encode($key); }; } } ?> $(document).ready(function(){ $("button").click(function(){ var test = "here"; $.ajax({ url: 'info.php', type: "POST", dataType:'json', data: ({name: test}), success: function(data){ $("#click").fadeOut(function() { $(this).append(data); }).fadeIn(); } }); }); }); I am an absolute beginner in php & am trying to validate a form using javascript. Problem is I am checking if the textbox is left empty before the user clicks on the submit button(using javascript). On the other hand i'm using isset function of php for the same submit button so that it does not run the code unless and until the button is clicked. Due to this, the default value of text box is being entered into database. How do i prevent this? Is there an alternate function to isset for such an event? Here is a sample code Code: [Select] <?php if(isset($_POST[sub])) $sql="insert into testing values('$_POST[txt1]')"; $exec = mysql_query($sql); ?> <script type="text/javascript"> function check() { var a = document.getElementById('add'); if (a.value = "") { return false; } } </script> <form action="add.php" method="post"> <input type="text" name="txt1" id="add"><br> <input type="submit" name="sub" value="Click to Add" onclick = "check();"> </form> I'm using ghost text technique on my page instead of labels so the text boxes have different values at different instances and hence I cant use !empty function either. How do i unset the submit button so that it does not run the script further? I have a form that is supposed to use PHP to display errors next to incomplete form fields when the form is submitted. But I am never getting into my PHP loop. I tried using the print_r(true) function to debug, but no luck. When I click submit I see this i the URL... http://localhost/00_MyWebSite/zzEmptyPHP.php?firstName=&lastName=&submit=Process+Order&submitted=true which is what I would expect on a blank form being submitted. Here is my code... Code: [Select] <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd"> <html> <head> <title></title> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> <link type="text/css" rel="stylesheet" href=".css"> <style type="text/css" > form{ width: 400px; margin: 0 auto; } </style> </head> <body> <?php // Initialize. $errors = array(); $errors['firstName'] = ''; $errors['lastName'] = ''; $firstName = $lastName = ''; echo "print_r = " . print_r(true); if (isset($_POST['submit'])){ // Handle Form. // Trim all incoming data. $trimmed = array_map('trim', $_POST); // Check First Name. if (preg_match('/^[A-Z\'.-]{2,20}$/i', $_POST['firstName'])){ $firstName = $_POST['firstNamae']; }else{ $errors['firstName'] = 'Please enter your First Name.'; } // Check Last Name. if (preg_match('/^[A-Z\'.-]{2,20}$/i', $_POST['lastName'])){ $lastName = $_POST['lastName']; }else{ $errors['lastName'] = 'Please enter your Last Name.'; } // if there are errors then go back to the form and display them }else{ } ?> <form action=""> <fieldset> <legend>Billing Details</legend> <ol> <li> <label for="firstName">First Name:</label> <input id="firstName" name="firstName" class="text" type="text" /> <?php echo $errors['firstName']; ?> </li> <li> <label for="lastName">Last Name:</label> <input id="lastName" name="lastName" class="text" type="text" /> <?php echo $errors['lastName']; ?> </li> </ol> <input type="submit" name="submit" value="Process Order" /> <input type="hidden" name="submitted" value="true" /> </fieldset> </form> </body> </html> Any ideas what I am doing wrong? Thanks, Debbie When the form is summited it is supposed to check if the password field contained any text so that way it updates the password. so only if $password exists should it run that query. I tried all different ways of making that happen and it never works. I will summit the form without anything in the password field and it will still update the password to something encrypted in md5 anyways. Code: [Select] <?php include ('header.php'); if(isset($_GET['sa'])) { switch ( $_GET['sa']) { case 'edit': edit(); break; } }else{ echo "<div class='header'>Edit admins</div><div class='content'>"; $query = mysql_query("SELECT * FROM `admins`"); while($row = mysql_fetch_array($query)){ $username = clean_up($row['username']); $id = clean_up($row['id']); $email = clean_up($row['email']); $website = clean_up($row['website']); echo "$id $username $email $website | <a href='index.php?action=editadmins&sa=edit&id=$id'> Edit</a><br>"; } echo "</div>"; } function edit() { $id = clean_up($_GET['id']); if(isset($_POST['submit'])){ $username = clean_up($_POST['username']); $password = md5(clean_up($_POST['password'])); $email = clean_up($_POST['email']); $website = clean_up($_POST['website']); if(isset($username)){ if(isset($password)){ mysql_query("UPDATE `admins` SET `password`='$password' WHERE `id`='$id'"); } mysql_query("UPDATE `admins` SET `username`='$username', `email`='$email', `website`='$website' WHERE `id`='$id'"); echo "<b><font color=green>Information edited. Go <a href='index.php'>home</a>?</font></b><br>"; }else{ echo "please enter a username"; } }else{ $query = mysql_query("SELECT * FROM `admins` WHERE `id`='$id'"); while($row = mysql_fetch_array($query)){ $username = clean_up($row['username']); $email = clean_up($row['email']); $website = clean_up($row['website']); echo "<div class='header'>Edit $username</div><div class='content'><form action='index.php?action=editadmins&sa=edit&id=$id' method='post'> <b>Username:</b> <input type='text' name='username' id='username' value='$username'><br> <b>Password:</b>(leave blank to keep same) <input type='password' name='password' id='password' value=''><br> <b>Email:</b> <input type='text' name='email' id='email' value='$email'><br> <b>Website:</b> <input type='text' name='website' id='website' value='$website'><br> <input type='submit' name='submit' id=submit' value='Edit $username'></form></div>"; } } } include('footer.php'); ?> Hello again here is my code but its dont work correct Code: [Select] $super = $_GET['video_id']; $filmai = $TSUE['TSUE_Database']->query("SELECT rasta_cinema.video_id, rasta_cinema.name, rasta_cinema.description, rasta_cinema.video_name, rasta_cinema.thumb_image FROM rasta_cinema WHERE video_id = $super LIMIT 1"); error im get is Code: [Select] Database Error! Please try again later or contact an Administrator. (1064) You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'LIMIT 1' at line 1 SELECT rasta_cinema.video_id, rasta_cinema.name, rasta_cinema.description, rasta_cinema.video_name, rasta_cinema.thumb_image FROM rasta_cinema WHERE video_id = LIMIT 1 Thanks First of All hello to all I have done registration login script and when I starting to making the users profiles, I have problem in the $_GET function well this is the code <?php $getid = $_GET['id']; if (!$getid) $getid = "1"; require('scripts/connect.php'); $query = mysql_query("SELECT * FROM users WHERE id='$getid'"); mysql_real_escape_string; $numrows = mysql_num_rows($query); if ($numrows == 1){ $row = mysql_fetch_assoc($query); $id = $row['id']; $firstname = $row['first_name']; $lastname = $row['last_name']; $user = $row['username']; $avatar = $row['avatar']; $city = $row['city']; echo "<div id='profile'> <div id='leftside'> <a href='profile.php?$user'><img src='avatars/$avatar' width='100px' height='100px' border='0'</a></img><br /><a href='profile.php?$user'>$firstname $lastname <br />($user)<br /></a>$city <br /></div>"; } else echo " You have to contact administrator"; ?> When I login as user id 1 then it display all right but when I go and login as another user it display the first users piture, name, surname & city can someone tell me what the problem is ? I know is this if (!$getid) $getid = "1"; but why is this happen If someone tell me or point to the right direction I would be thank full Ok, not sure what the problem is....hard to explain. I am trying to setup a login script but I get the normal: Warning: session_start() [function.session-start]: Cannot send session cache limiter error code. I have no white space above to cause problem. I have used this same code written by Jpmaster77 on a number of sites. What the strange thing is it also messed up a couple of my css text boxes. See the difference: http://www.monstersgonewild.ca/index.php - Problem http://www.monstersgonewild.ca/index1.php - Without session() I would post the code of the original page but it is 600+lines and growing. Anybody have any ideas? Im installing and testing a web application, and im having a strange bug that annoyes me because it dint have any sense and also it dont affects really to the web functionality: if($_POST["eliminar"]==""){ $consulta='SELECT * FROM impressora where Activa=0'; $result=mysql_query($consulta,$conexion); echo"<table align=CENTER class='sample'>"; echo"<p align=center>LLISTA D'IMPRESSORES INACTIVES.</p>"; printf("<th>MODEL</th><th>MARCA </th>"); while($fila=mysql_fetch_array($result,MYSQL_ASSOC)){ echo"<tr>"; echo "<td>" . $fila["Model"] . "</td>"; echo "<td>" . $fila["Marca"] . "</td>"; echo"</td>"; if($_SESSION["admin"]!=0){ ?> <form method= "post" ACTION="impressores_inactives.php?idr=<?php echo($fila["Id_impressora"])?>"> <td colspan="2"><INPUT TYPE ="SUBMIT" NAME="eliminar" VALUE="Eliminar"></td> </form></td> <?php } echo "</tr>"; } echo"</table>"; }else{ echo 'eliminado'; echo $_POST["eliminar"]; //BORRAMOS DE LA BBDD LA IMPRESSORA $consulta="delete from impressora where Id_impressora='".$_GET["idr"] ."'"; $result=mysql_query($consulta); echo "<meta http-equiv=Refresh content=\" ; url=../Impressores/impressores_inactives.php\">"; } The problem is that php say that eliminar is undefinded, and if i test $_POST it says its empty. See that eliminar is the name of the submit post and its checked for a function that deletes a item. The problem is that script is actually working. I can delete the printer but with that error... and if i test the value of eliminar is always empty. Ask for any other explanation without a problem , the code is in spanish. Hey guys, First of all thanks in advance for all the help you can give me. I'm using a php shopping script called plaincart to create a webstore. All is fine but the admin part is not working properly. When i go to http://localhost/admin it redirects to http://localhost/admin/admin/login.php The index.php is in the root of the server and the admin files are in a folder called admin... What is wrong? Please tell me if you need any code. Thank you Hi. I have to check if a session is started or not, and then, check for the rank of the user. For that i use two functions like is_administrator,etc. Well, but this isnt working. I cant get any clear way to know if a session have been already started or not. Code: [Select] function is_administrator() { session_start(); if (isset($_SESSION['usr']) and empty($_SESSION['usr'])) { $l = conect(); $user = $_SESSION['usr']; $cons = "SELECT * FROM `users` WHERE usr='" . $user . '\';'; $res = mysql_query ($cons,$l); $ob = mysql_fetch_array($res); if ($ob['tipo'] == 'A') { return true; } } return false; } What i want to do is to check if a sesion exist, if not, return false. If the sesion exist, check for the user rank and return true/false. Hi, I get this error when I load the page, but after hitting ctrl f5 to refresh.. the error goes away and the page works perfectly. I have edited out my details. Warning: mysql_connect() [function.mysql-connect]: Access denied for user 'user'@'localhost' (using password: YES) Access denied for user 'user'@'localhost' (using password: YES) I know everything is set right.. I just don't get it.. I am going crazy of this. Ive cleared my browser cache.. even tried it on my android phone and it does the same thing. Thanks, Deceevn |