PHP - Date Conversion Function

I'm getting this Time Zone error.
Perhaps it's a compatibility issue with PHP 5.3. Looked all over for an answer without finding one.
Here is the error message


Warning: date() [function.date]: It is not safe to rely on the system's timezone settings.
You are *required* to use the date.timezone setting or the date_default_timezone_set() function.
In case you used any of those methods and you are still getting this warning,
you most likely misspelled the timezone identifier. We selected 'America/New_York' for 'EST/-5.0/no DST'
instead in /blocked.php on line 41
12/02/12

Here is the code. Line 41 is near the bottom, the one with the d,m,y.  Perhaps the echo date (d/m/y") needs to be changed. Appreciate any help!

Code: [Select]
   <table border="3" width="16%" align="center" cellspacing="0" bgcolor="#FF6600" bordercolor="red" bordercolordark="red" bordercolorlight="red">
                            <tr>
                                    <td width="176">

                                            <p align="center"><?php // shows IP Number on Page
            echo $ip; ?> </p>

                                    </td>
                            </tr>
                    </table>
                    <p align="center"><?php // Show the user agent
        echo 'Your user agent is: <b>'.$_SERVER['HTTP_USER_AGENT'].'</b><br />';?></p>
                    [b]<h1 align="center"><?php echo date("d/m/y");?></h1>[/b]
            </td>
    </tr>
</table
[,code]

I am scraping Birthdays from a webpage that are in this format
September 15, 1987

$age = 15;
$page = source code of a html page;

so far i have made this function

How do i return the function as true if the date scaped makes the person over 15 and false if the person is younger?


function checkForAge($page,$age) {
  preg_match('|Born on ([a-zA-Z]*\s[0-9]*,\s[0-9]*)\\\u003c\\\/span>|', $page, $match);
    if($match && count($match)>0) {
        echo "Match Found";
$dateOfBirth = str_replace(",","",$match[1]);
// $dateOfBirth = date('d/m/Y', strtotime($dateOfBirth));
$dateOfBirth = strtotime($dateOfBirth);
/*

       if("date of birth makes person over $age)
         {
          return true;
         }
       else 
        {
         return false;
         }
*/

    }

i just want to display the values form database which i have saved before and just want to be displayed when specific time comes as i told above in e.g

if i have stored some thing like value let say ( 10,20,30,40 and so on ) in database
now i just want a php code to display it on site but on specific time only like this,

i time = 10:00am display value = 10
when time = 10:30am display value = 20
when time = 11:00am display value = 30

and so own simple.

Hello Again guys,

I have varous dates stored in a database , these dates can look like this
2010-08-06
07/08/2010
07-08-2010

The problem is I dont know what format they are stored in..
What I need is a function which takes in 1 date at a time and returns it in a format I need it to be..

the format I need is
07/08/2010

thank you again for all you help

I have been looking at thr date() but not been able to answer my qustion yet

Hi all,

I want to include the date and time in the web page to display when a user logged into the site.
I found a code.I want to know how it could modify with relevant to our local time?


<?php
$today = date("d M Y h:i A"); 
echo $today 
?>


Thanks,

$date=date("Y-m-d H:i:s");

This is returning me the GMT time instead of EST. I get 15:26:08 as the time instead of 10:26:08. How can I get around this?

I am doing somthing complicated with dates and I think I am making it harder than I should. I need to subtract "x" number of months from the current date, then create 2 dates in that month that represent the first day, and last day of the month. Then make it in a format that SQL can read to get the SUMS I need between those dates. My last 2 strtotimes are wrong and are giving me the 1969 dates.
Code: [Select]
function commiss($nummonth){
$repnum = $_SESSION['REPID'];
$date = date("Y-m-d", strtotime("-" . $nummonth . ""));
$time2 = " 00:00:01";
$time = " 23:59:59";
$date1 =date("Y-m-d", strtotime(date('m').'/01/'.date('Y')));
$date2 =date("Y-m-d", strtotime('-1 second',strtotime('+1 month',strtotime(date('m').'/01/'.date('Y')))));
$date1 = date("Y-m-d", strtotime("-" . $nummonth . "", $date1));
$date2 = date("Y-m-d", strtotime("-" . $nummonth . "", $date2));
$date1 = $date1 . $time2;
$date2 = $date2 . $time;
$string = "SELECT SUM(premium), SUM(repcom) FROM commission WHERE repnum = '$repnum' BETWEEN '$date1' AND '$date2'";
$sqltotal = mysql_query($string)or die (mysql_error());
$sqlprem = mysql_fetch_array('[SUM(premium)]');
$sqlcomm = mysql_fetch_array('[SUM(repcom)]');
echo "Premium: " . $sqlprem;
echo "\n Rep Commission: " . $sqlprem;
}

How would you use the date function to display a birthday with an user's input?   

Hi,

I have the following code which lists all the dates since October 5th 2007 until yesterday's date, and displays it as a link. This part works fine. What I want to do is omit the weekends, so the first few lines would read like so:

05/10/2007
08/10/2007
09/10/2007
10/10/2007
11/10/2007
12/10/2007
15/10/2007

Does anyone know how I can modify this code, or have any other methods of doing this? 

Code: [Select]
<?php function dates_between($start_date, $end_date = false) 
 { 
     if ( !$end_date ) 
     { 
         $end_date = date("Y-m-d"); 
     } 
      
     $start_date = is_int($start_date) ? $start_date : strtotime($start_date); 
     $end_date = is_int($end_date) ? $end_date : strtotime($end_date); 
      
     $end_date -= (60 * 60 * 24 + 1); 
      
     $test_date = $start_date; 
     $day_incrementer = 1; 
      
     do  
     { 
         $test_date = $start_date + ($day_incrementer * 60 * 60 * 24); 
         echo '<a href="http://markets.ft.com/RESEARCH/markets/DataArchiveFetchReport?Category=CU&amp;Type=WORL&amp;Date=' . date("m/d/Y", $test_date) . '">' . date("d/m/Y", $test_date) . "\n</a><br>"; 
     } while ( $test_date < $end_date && ++$day_incrementer ); 
 } 
  
 dates_between("2007-10-04"); 
 echo "\n\n"; ?>
Thanks,
Dave

Hi, I am using this function to output a list of dates for every friday over the next 12months. This is working fine.

Code: [Select]
[php]
//function
function nextWeeksDay($date_begin,$nbrweek)
{
$nextweek=array();
for($i = 1; $i <= $nbrweek; $i++)  { // 52 week in one year of course
$nextweek[$i]=date('Y-m-d', strtotime('+'.$i.' week',$date_begin));
}
return $nextweek;
}
/// end function
/// example of a select date
// var
$date_begin=strtotime('this Friday');
$nbrweek=52;
// call function
$result=nextWeeksDay($date_begin,$nbrweek);
// Insert
//$date1=date('Y-m-d', $date_begin);
for($i = 1; $i <= $nbrweek; $i++)  {
//$date=$result[$i];
echo $result[$i]."<br/>";
}

[/php]
My problem is that when I alter the code to try and get the date for every second Friday for the next year the script freezes.

Code: [Select]
[php]
//function
function nextWeeksDay($date_begin,$nbrweek)
{
$nextweek=array();
for($i = 2; $i <= $nbrweek; $i+2)  { // 52 week in one year of course
$nextweek[$i]=date('Y-m-d', strtotime('+'.$i.' week',$date_begin));
}
return $nextweek;
}
/// end function
/// example of a select date
// var
$date_begin=strtotime('this Friday');
$nbrweek=52;
// call function
$result=nextWeeksDay($date_begin,$nbrweek);
// Insert
//$date1=date('Y-m-d', $date_begin);
for($i = 2; $i <= $nbrweek; $i+2)  {
//$date=$result[$i];
echo $result[$i]."<br/>";
}

[/php]
I really don't understand why??  Does anyone know why?

Thanks

Hi, I'm making an RSS feed

http://dev.subverb.net/mixes_rss.php

and as you see the date('r', $row['date']) function is not converting it. I've echo'd $row['date'] into the description to show what format the date is in (just mysql datetime. Am I missing something?

Thanks

hello i got this small function i`m working on to get the date of a month something like get current date - 1 but not sure how to handle jan month can someone help me please ?



$month = date('m') - 1;
$date_startt = date('Y').'-'.$luna.'-01';
$timestamp_start = strtotime($data_start);

Hi there, what I have been trying to do is add some additional logic.. My problem is I want to stop displaying the month and day after the year 2000? I know I need to add an if and else statement but this is my first actual project and I am a little stuck.. here is the page, it's a plugin for a timeline http://www.llandover...oject-timeline/   And the file is attached below.. any help would be appreciated. The plugin code was too long to just post in here, didn't want to cause any slow loading issues for people on a slow connection.. Thanks and I appreciate any help.    Attached Files  annual_archive.php   18.15KB   5 downloads

want something like:
Code: [Select]
date('F j, Y, g:i a')
but in central timezone, how do I change the timezone to central?

I cant figure out how to add $recieved into this
needs to take place of time
hope someone knows how to do this
what im doing is adding in the UNIX time i want to offset


Code: [Select]
<?php $offset = date('m/d/Y/H:i:s', time()+$send1['time_offset']); ?>