PHP - Php Mailer - I Can Not Give Values To Properites Of The Class Object

Folks,

I need to Extract the Content of "[content] => " Class from the output of the below Script:

<?php


$keywords = file_get_contents('http://ajax.googleapis.com/ajax/services/search/web?rsz=large&v=1.0&q="paintball"');
$keywords = json_decode($keywords);
print_r($keywords);



?>


Output is like:
Quote


stdClass Object ( [responseData] => stdClass Object ( [results] => Array ( => stdClass Object ( [GsearchResultClass] => GwebSearch [unescapedUrl] => http://www.paintball.com/ [url] => http://www.paintball.com/ [visibleUrl] => www.paintball.com [cacheUrl] => http://www.google.com/search?q=cache:Zcnr-K8jU4YJ:www.paintball.com [title] => PaintBall.com [titleNoFormatting] => PaintBall.com [content] => Information and meeting place for new and experienced players. Features industry news, equipment reviews, information for new players, links to online ... ) [1] => stdClass Object ( [GsearchResultClass] => GwebSearch [unescapedUrl] => http://www.zephyrpaintball.com/ [url] => http://www.zephyrpaintball.com/ [visibleUrl] => www.zephyrpaintball.com [cacheUrl] => http://www.google.com/search?q=cache:EkBfV3VsT9UJ:www.zephyrpaintball.com [title] => Cheap Paintball Guns - Cheap Paintball Gear - Cheap Paintball Supplies [titleNoFormatting] => Cheap Paintball Guns - Cheap Paintball Gear - Cheap Paintball Supplies [content] => Cheap Paintball Gear - Zephyr Paintball offers a wide variety of cheap paintball guns as well as cheap paintball supplies that can get you into the painball ... ) [2] => stdClass Object ( [GsearchResultClass] => GwebSearch [unescapedUrl] => http://www.addictinggames.com/paintballthegame.html [url] => http://www.addictinggames.com/paintballthegame.html [visibleUrl] => www.addictinggames.com [cacheUrl] => http://www.google.com/search?q=cache:TM1GFy3lDIQJ:www.addictinggames.com [title] => Paintball - The Game - Free Puzzle and Board Game from AddictingGames! [titleNoFormatting] => Paintball - The Game - Free Puzzle and Board Game from AddictingGames! [content] => Paintball - The Game, a Free Puzzle and Board Game from AddictingGames: Use your skills to paint a path for the ball to get to the magical square. ) [3] => stdClass Object ( [GsearchResultClass] => GwebSearch [unescapedUrl] => http://www.paintball-online.com/ [url] => http://www.paintball-online.com/ [visibleUrl] => www.paintball-online.com [cacheUrl] => http://www.google.com/search?q=cache:rm9AvRxLLX4J:www.paintball-online.com [title] => Paintball Guns & Markers at Paintball-Online.com [titleNoFormatting] => Paintball Guns & Markers at Paintball-Online.com [content] => The Internet's largest paintball store featuring over 4000 paintball guns, markers and other gear. Free shipping and 10% off for all VIP members. ) [4] => stdClass Object ( [GsearchResultClass] => GwebSearch [unescapedUrl] => http://en.wikipedia.org/wiki/Paintball [url] => http://en.wikipedia.org/wiki/Paintball [visibleUrl] => en.wikipedia.org [cacheUrl] => http://www.google.com/search?q=cache:h3rpb57aWfcJ:en.wikipedia.org [title] => Paintball - Wikipedia, the free encyclopedia [titleNoFormatting] => Paintball - Wikipedia, the free encyclopedia [content] => Paintball is a sport in which players compete, in teams or individually, to eliminate opponents by hitting them with capsules containing food coloring and ... ) [5] => stdClass Object ( [GsearchResultClass] => GwebSearch [unescapedUrl] => http://www.ansgear.com/ [url] => http://www.ansgear.com/ [visibleUrl] => www.ansgear.com [cacheUrl] => http://www.google.com/search?q=cache:uiYno-g6MOkJ:www.ansgear.com [title] => Paintball - Cheap Paintball Guns, Gear and Paintball Equipment [titleNoFormatting] => Paintball - Cheap Paintball Guns, Gear and Paintball Equipment [content] => Ansgear has Paintball guns and Paintball equipment for everyone. Get your Paintball equipment for cheap. All Paintball gear on sale! ) [6] => stdClass Object ( [GsearchResultClass] => GwebSearch [unescapedUrl] => http://www.pbreview.com/ [url] => http://www.pbreview.com/ [visibleUrl] => www.pbreview.com [cacheUrl] => http://www.google.com/search?q=cache:OzXP0G1QzFMJ:www.pbreview.com [title] => Paintball Reviews of Guns, Equipment, Games & More | pbreview.com [titleNoFormatting] => Paintball Reviews of Guns, Equipment, Games & More | pbreview.com [content] => All things paintball on pbreview.com. Paintball gun & equipment reviews, paintball videos, a paintball field locator for paintball games & tournaments. ) [7] => stdClass Object ( [GsearchResultClass] => GwebSearch [unescapedUrl] =>


Desired Output:

Quote

[content] => Cheap Paintball Gear - Zephyr Paintball offers a wide variety of cheap paintball guns as well as cheap paintball supplies that can get you into the painball ...
[content] => Paintball - The Game, a Free Puzzle and Board Game from AddictingGames: Use your skills to paint a path for the ball to get to the magical square. )

..........................
Till the End of the Page...





How can it be achieved?

Cheers
Natasha T

Hi guys,

I have below values in array
Code: [Select]
stdClass Object ( [Category] => stdClass Object ( [ChildCategoryDescription] => 50s / 60s ERA [ChildCategoryID] => 87 [GrandchildCategoryDescription] => - [GrandchildCategoryID] => 25 [ParentCategoryDescription] => CONCERTS [ParentCategoryID] => 2 ) [Description] => Tony Bennett [ID] => 1073 [HomeVenueID] => 0 )
When am calling Desciption object by $resultsObj->Description then i got the result " Tony Bennett" but i do not know to get the value GrandchildCategoryID . Just i tried this
Code: [Select]
echo $resultsObj->$resultsObj->ParentCategoryID and i got below error.
Catchable fatal error: Object of class stdClass could not be converted to string in D:\Program Files\xampp\htdocs\t1\genericLib.php on line 255.

How i can get this value...

Long story short, I have a class that does some data verification and session management.  In order to do some of this verification, it needs a database connection.  I am using the MDB2 class;

here is a sample of the constructor's code:


this is a snippet of code from My Class.




// FUNCTIONS
function __construct() {

/*

other code here 

*/
// set up our datbase connection
global $dsn; // must use global as to include the one *from* the settings.php include

$mdb2 =& MDB2::singleton($dsn);

if (PEAR::isError($mdb2)) {
die("<H1> THERE WAS AN ERROR </H1>" . $mdb2->getMessage());
}

echo("SESSION CLASS: if you see this, then we're goood!");     // some very crude debugging, please ignore this!
}




Now, i have another function within this same class:


public static function data_validateUserName($safeUserName){



// build the query
$q = "SELECT uName FROM Users WHERE username = '$safeUserName'";

$result = $this->$mdb2->query($q);

if($result->numRows() >= 1){

// there is 1 or more hits for a username, it is not available!
return false;

} else if ($result->numRows() < 1){

// there is less than 1 row with that username, we're golden!
return ture;

}

}



Inside the constructor, i have correctly set up a MDB2 object.  I was able to run some queries and other things on it *inside* the constructor.  Because of this, i know that it's settings are correct and it is fully working.

However, when i try to use that $mdb2 object inside this other method, i get all sorts of errors about that being a bad reference to an object that essentially does not exist.

Now, i tried searching here, and didn't get much help, so apologies.  If you've got a link to a similar question, then please post that with a brief explanation of what you searched for to get it...


Also, the php.net manual is not very helpful about the scope of objects in this particular setup... so please know that i did pour over that before posting here.

Thanks for your time, all.


***** EDIT ******

I've thought about doing it another way:

Each function is passed in a reference to the MDB2 object as an argument instead of relying on the one that is *suposed to be* built in to the actual class it's self.  Would this be better / more secure / more efficient?!

The following is an extract of PHP code I have interacting with a MySQL database and I keep getting the "object of class mysqli_result could not be converted to string" error on the line of code inside my loop. This is my code.

 

#This is just storing a single integer, a moduleID

$sqlmodID = mysqli_query($con,"select moduleID from module_details WHERE moduleName = '$moduleName' AND lecturerID = '$lecturerID'");
            

#This is a query to get relevant idNumbers            

$sqlstudent = "select idNum from user_info WHERE courseCode = '$courseCode'";

 

#Running the previous statement

$result = mysqli_query($con, $sqlstudent);

 

#Storing the statements results in an array 

$row = mysqli_fetch_array($result);

 

#I'm not sure if this line is necessary but it converts the array values into a string (I'm storing the ID's as strings as they contain numbers and letters)

$studentArray = array_map('strval', $row);

 

#The error flashes on my condition of this loop. I'm trying to take each element of my array, and enter it to my table, assigning each variable the same ModuleID.

for($i=0; $i < count($studentArray); $i++){
                mysqli_query($con,"insert into student_classlist VALUES ('$sqlmodID', '$studentArray')");
 }

 

Any help would be much appreciated. I hope I've explained my code sufficiently.

Hey, I'm trying to create an object oriented webpage, with just some basic features, like creating a user, logging in, admin restricted pages.
However I'm stuck at this point.
This is my code:
class_user.php
Code: [Select]
<?php
include_once $_SERVER['DOCUMENT_ROOT'] . "/includes/class_database.php";
?>



<?php

class User {

    private $database;
    
    public    function __construct(MySqlDatabase $database) { //Type Hinting
    $this->database = $database;
    }
    
    public function find_all() {
    $result = $this->database->db_query("SELECT * FROM users");
    return $result;    
    }
    
    public function find_by_id($id=1) {
    $result = $this->database->db_query("SELECT * FROM users WHERE id={$id}");
    $final = mysqli_fetch_array($result);
    return $final;    
    }
}
?>class_database.php
Code: [Select]
<?php
include_once $_SERVER['DOCUMENT_ROOT'] . "/includes/values.php";
include_once $_SERVER['DOCUMENT_ROOT'] . "/includes/class_user.php";
?>

<?php

class MySqlDatabase extends MySQLi {
    
    function __construct() {
        //Check if constants are missing
        if (defined(!DB_USERNAME) || defined(!DB_SERVER) || 
            defined(!DB_PASSWORD) || defined(!DB_NAME)) {
            die("One or more of the database constants are missing: " . mysqli_errno);
            }
            
        //Establish connection if constants are present using the parent class
        parent::__construct(DB_SERVER, DB_USERNAME, DB_PASSWORD, DB_NAME);
        
        //Echo error message if connection has failed
        if ($this->connect_errno) {
            die("Database connection has failed: " . $this->connect_errno);
            }
    
    
    }

    public function db_query($sql) {
    $result = mysqli_query($this->connection, $sql);
        if (!$result) {
            die("Database query failed: " . $this->errno);
        }
    return $result;
    
}

    public function query_prep($value) {
    $result = mysqli_real_escape_string($this->connection, $value);
        if (!$result) {
            die("Preparing query failed: " . $this->errno);
        }
    return $result;
}  
}
?>Calling externally:
Code: [Select]
<?php
$database = new MySqlDatabase();
$user = new User($database);
$found = $user->find_all();
?>This is the error I'm getting:
Quote

Warning: mysqli_query() expects parameter 1 to be mysqli, null given in C:\xampp\htdocs\includes\class_database.php on line 28
Database query failed: 0


I've tried everything I can come up with, but still I'm stuck at this error.

I can not understand why this isn't working, basically it works in one place but not  the other

I have this in my main class:

class phpLive{

public function loadCore(){

foreach(glob($this->location."/core/*/*.core.php") as $coreFile){

$info = (object)pathinfo($coreFile);

require_once $coreFile;

$pos = strrpos($info->dirname, "/");

$coreMedia = substr($info->dirname, $pos + 1);

$className = str_replace(".core", "", $info->filename);

$instance = strtolower($className);

$this->$coreMedia->$instance = new $className();

}

}
}

On the page that I run (index.php), I use this:

$_live->example->loadurl();

which is in a class that looks like this:
<?php
class ExampleClass extends phpLive{
    public function __construct(){

$this->loadCore();

}

public function loadurl(){

$this->net->http->getHttp('http://google.com');

}
}
?>

and I get the following error:
Quote

Notice: Undefined property: ExampleClass::$net in C:\wamp\www\phpLive\phpLive\plugins\Example\ExampleClass.inc.php on line 7

Notice: Trying to get property of non-object in C:\wamp\www\phpLive\phpLive\plugins\Example\ExampleClass.inc.php on line 7

Fatal error: Call to a member function getHttp() on a non-object in C:\wamp\www\phpLive\phpLive\plugins\Example\ExampleClass.inc.php on line 7


but, when I run this on the main page:
$_live->net->http->getHttp("http://google.com");

The code works just fine.

Why doesn't the first one work (the above is the actual code, copy and pasted from my editor)?

I don't know why it won't work.. as the topic titles says that I am trying to pass a mysqli object to a property in another class  but it keeps me getting an error. here's the code for the mysqli object that i want to pass to another class

class ConnectMe2Db
{
	public $dbname  = 'somedatabase';
	public $dbuname = 'root';
	public $dbpass  = '';
	public $dbhost  = 'localhost';
	
	function __construct()
	{
		$mysqli = new mysqli($this->dbhost,$this->dbuname,$this->dbpass,$this->dbname)
			or die ('ERROR: '.$mysqli->connect_errno);
		return $mysqli;
	}
       # OTHER CODES...
}

and here is the class that i want the Mysqli object to pass to:

class DatabaseUsers
{
	private $dbconnection;
	
        function __construct()
	{
		$this->dbconnection = new ConnectMe2Db();#mysqli object will be passed to this attribute '$dbconnection'
	}
	
	public function session($username, $password)
	{
		$UserName = mysqli_real_escape_string($this->dbconnection,$username);
		$Password = mysqli_real_escape_string($this->dbconnection,md5($password));
		$querry = "SELECT * FROM trakingsystem.login WHERE username='$username' and password='$password'";
		$result = mysqli_query($this->dbconnection,$querry) or die (mysqli_error($this->dbconnection));
		$count = mysqli_num_rows($result);
		$row = mysqli_fetch_array($result);
		if ($count > 0)
			{
                              #some code here
			}
	}
#some other code here
}

and this outputs 4  errors:

#outputs 2 of these:

Warning: mysqli_real_escape_string() expects parameter 1 to be mysqli

and some

mysqli_query() expects parameter 1 to be mysqli

mysqli_error() expects parameter 1 to be mysqli

is there something wrong with the logic that I've made? please help thanks

why do i keep getting this error from line 7?

Object of class stdClass could not be converted to string
Code: [Select]
<?php
include_once"../includes/db_connect.php";
$item_number="2";
$custom="54298";
$query=mysql_query("SELECT `prodID`, `quanity` FROM `cart` WHERE `sessID`='$custom'") or mysql_error();
while($cart=mysql_fetch_object($query)){
mysql_query("INSERT INTO  `orderItems` (  `id` ,  `orderInfoID` ,  `productID` ,  `quanity` ) VALUES ('',  '$item_number',  '$cart-> prodID',  '$cart->quanity');");
}
mysql_query("UPDATE `cart` SET `show`='1' WHERE `sessID`='$custom'");

?>

I'm receiving the error "Object of class player could not be converted to string" yet I cannot find why what I'm inputting is an object and not a string. As far as I can see it is a string and this error shouldn't be happening, yet it is...

A form submits to a page which gets the data thus:
Code: [Select]
<?php
case "updplayer":
if(!isset($_GET['id']) || !isset($_POST['kit']) || !isset($_POST['level']) || !isset($_POST['group']) || !isset($_POST['state'])) {
header("location:admin.php?mode=settings&error=info&sid=$user->sid");
exit;
}
$var = "player" . $_GET['id'];
$$var->kit = mysql_real_escape_string($_POST['kit']);
$$var->level = mysql_real_escape_string($_POST['level']);
$$var->group = mysql_real_escape_string($_POST['group']);
$$var->state = mysql_real_escape_string($_POST['state']);
$$var->update();
header("location:admin.php?sid=$user->sid");
exit;
break;

The update function is:
Code: [Select]
<?php
function update() {
echo "Name: $this->name <br />
Kit: $this->kit <br />
Level: $this->level <br />
Group: $this->group <br />
State: $this->state <br />";
$sql = "UPDATE `players` SET `name` = '" . $this->name . "', `preferredKit` = '" . $this-kit . "', `gamingLevel` = '" . $this->level . "', `group` = '" . $this->group . "', `draftState` = " . $this->state;
if(!mysql_query($sql)) {
return mysql_error();
}
return TRUE;
}

I added the echo's in for error checking. They output exactly what was expected. What is wrong with this? Error occurs on the "$sql = " line.

Hi there,
I am just wondering which way is the correct one if you want to create object properties/attribute dynamically at run time

using magic method __set(), __get(), for example:

class Foo{
    
        public $data = array();
      
        public function __set($name,$value){
              $this->data[$name] = $value;
        }

        public function __get($name){
              if ( isset($this->data[$name]) ){
                    return $this->data[$name];
              }
        }
}


Or using the below way


class Foo{

          public function assign(array $data){
                     foreach($data as $key => $value){
                                $this->$key = $value;
                     }
          }

}


I just encountered the second way in many places and I am totally confused  . Is the __set() method called implicitly by the PHP engine in the second way or what? how come this is considered as a valid code  ?

your usual help is appreciated

I want to save class property values and want to write these in the database after being called from another function.
Code: [Select]
class model{
public $dbh;
public $user_arr=array('username','password','email','location','interest','homepage');
 public function insert_data()
 {
 
 $sql = "INSERT INTO account VALUES ('" .$user_info['username']."','".$user_info['password']
      ."','".$user_info['email']."', 'user','".$user_info['location']."','".$user_info['interests']
      ."','".$user_info['homepage']."')";
      //if(isset($data))
      echo $sql;   
 }
public function data_approoved($user){
 //$user_info = new array();
 $user_arr['username'] = $user['username'];
 $user_arr['password'] = $user['password'];
 $user_arr['email'] = $user['email'];
 $user_arr['location'] = $user['location'];
 $user_info['interests'] = $user['interests'];
 $user_info['homepage'] = $user['homepage'];
 Model::insert_data();
 }
}
}//class ended
The approoved_data function is supposed to set the values of $user_info array which should be later on stored in database.
Please somebody help me.

How does everyone take data input from an HTML Form and convert it into an Object in OOP?

I am thinking it would be better if user inputs resided in an object so that I could manipulate the data in OOP terms instead of referencing the Form procedurally.


TomTees

hi,
i have a class file that have all values from a database fields.
for example:


 class mospedidos extends mosDBTable {
id = null;
date =null;
}

 class mosunder extends mosDBTable {
id = null;
name =null;
}

each time i creat a new field in the database i need add the same field in the
class file, what i want is a way using  php to add that new field to the class file.
i just need a way to open the file and the class name that i give and add the value
and save the file.
how can i do this?
thanks for your help

I have the following script:
<?php

$tijd[] = '2012-05-23T02:00:00';

$date = new DateTime($tijd[0]);

echo $date;
?>


However it is not working and resulting in:
Quote

Catchable fatal error: Object of class DateTime could not be converted to string in time3.php on line 7


I think to solve this issue, I have to convert $tijd[0] into a string. Right? If this is correct, how do I do that?