PHP - How Would I Make An Iframe Type Of Link
Hi People.
I am doing quite well with my www.airfieldcards.com website which is information for pilots in the UK and ireland should they wish to visit another airfield. It is in the form of a flight guide for free. Each card is held in a database and the cards are shown on the site by loading the following script /php/results.php?id=132 In the above example the card for c-moor in Ireland would be loaded. I want to be able to add a link within the cards that will give the user "the code" to enter that card within their own website. Sort of a "click here to get the code to add to your website" Then opening a separate box in a new window that had something like this in it. Copy and Paste the following code into your website Code: [Select] <iframe width="720" height="1500" frameborder="0" scrolling="no" marginheight="0" marginwidth="0" src="http://airfieldcards.com/php/results.php[b][i]"what goes here?"[/i][/b] What would I put into the bit "what goes here?" to dynamically load that specific card? and give the user the correct code to add into their own site? Thanks in advance, you guys on here have always been brilliant. Similar TutorialsSo I'm trying to make an online quiz where the user can 'take the quiz' or go to 'module' where the user can edit the quiz. I've tried for days to search through the net for this particular one but I can't find any solutions. For the quiz I made a comma delimited text file and tried to use that file to make a multidimensional array. So far I only have the following: <h2>ONLINE QUIZ</h2> <ul> <li><a href='question.php'>Take quiz</a></li> <li><a href='module.php'>Admin Module</a></li> </ul> <?php $file = fopen ("data.txt","r"); $i=0; while (feof($file)==false) { $line = fgets($file); $array[$i]=$line; $i=$i + 1; } fclose($file); session_start(); $_SESSION["questions_array"]=$array; ?> My question is, how do I turn the text file from something that looks like this: HTML is...,Main markup language for web pages,Cross-site Security,Cleverly Structured Scripting,eXtremely Safe and Secure, PHP...,General-purpose server-side scripting language,Cross-site Security,Processing Hypertext Products,Process HTML Prettily To output something like this: Question #1 HTML is... [radio button] a.) Main markup language for web pages [radio button] b.) Cross-site Security etc, etc ll----I will type out the exact plan for this quiz----ll Main page: module and quiz link. For the quiz Question page: Questions only show up one by one. ex.) What is a dog? a.) a human b.) a pet c.) a job d.) a car (Submit button) Answer page: Once submit is hit, the page goes here, where the user can see whether they answered right or wrong. ex.) INCORRECT Your answer: a.) a human Correct answer: b.) a pet (continue link) Note that when 'continue' is hit, the page redirects back to the 'question page' but this time outputs the next question. When no more questions are available, the page automatically redirects to the 'results page'. Results page: Table of results For the module Main: A table of the available questions plus their choice answers ex.) Question l choice a l choice b l [] What? cat toy [] How? rat pop etc. Each row can be selected through a radio button. (so we know which question to edit) Select option: Drop down list whether to 'add', 'edit' or 'delete' a question. Each choice directs to a different page where you can perform the action. Also, if 'delete' is chosen, a confirmation page should show up. (i.e are you sure you want to delete this file?) I think that's detailed enough, I'm so sorry for the trouble;; but please if you don't have the time to help me throughout the whole thing, please help me figure out how to use the text file as a multi-dim array (aka the first thing I asked). I've been dying to know how to do it but I just can't get it to work so I'd really appreciate that! Thank you! Hey, What i want is that if a username inserts some text into a field like "Hey @martin how are ya" ? then it will display @martin as a link that takes you to site.com/martin, i searched php.net from preg_replace and str_replace...unfortunately for me things got so complicated that i don't even want to talk about it. Anyone who can do it will be my saviour! This topic has been moved to HTML Help. http://www.phpfreaks.com/forums/index.php?topic=307669.0 ok, how do I make this button go to the specific link that is set with it.......it goes to page without eventid=eventid: Code: [Select] <form action= \"editevent.php?eventid=".$row['eventid']."\" method=\"link\"><INPUT TYPE=\"submit\" VALUE=\"Edit\"></form>"; I have created a database that echos out the result on a webpage, what i want to do is create one of the echo results into a link - the code is as follows: "Web Address: $web_address <br>" . Is there an easy way to make the result a link as the input will always be a web address? Thanks in advance! I basically have a PHP Search Form, and when a user fills in a form it outputs the results. Each result displays a image of a property, how could i make them images have their own unique link which will take them directly to the page of the property being shown? Im using PHP and mySQL tables Any help is appreciated, Thank You. Heres the PHP that outputs the results: Code: [Select] <?php require_once 'mstr_ref.php'; function san($input){ if(get_magic_quotes_gpc()){ $input=stripcslashes($input); } $output = mysql_real_escape_string($input); return $output; } if(isset($_POST['submit'])){ $pVars = array('area'=>$_POST['areas'], 'propType'=>$_POST['prop_type'], 'saleType'=>$_POST['ptype'], 'minB'=>$_POST['min_bedrooms'], 'maxB'=>$_POST['max_bedrooms'], 'minP'=>$_POST['min_price'], 'maxP'=>$_POST['max_price']); foreach ($pVars as $k=>$v){ $v = san($v); } $sql = new makeQuery(); $sql->manAdd('location_id', $pVars['area']); if($pVars['propType'] != 'Any'){ $sql->manAdd('catagory_id', $pVars['propType']); } if ($pVars['maxB'] > 0){ $sql->manAdd('bedrooms', $pVars['maxB'], '<='); } if($pVars['minB'] > 0){ $sql->manAdd('bedrooms',$pVars['minB'],'>='); } if($pVars['saleType'] != 'Any'){ if($pVars['saleType'] == "forsale"){ $sql->manAdd('market_type', 'sale'); if($pVars['minP'] != 0){ $pVars['minP'] = $pVars['minP'] * 1000; } if($pVars['maxP'] != 0){ $pVars['maxP'] = $pVars['maxP'] * 1000; } } if($pVars['saleType'] == 'forrent'){ $sql->manAdd('market_type', 'rent'); } } $qry = $sql->sqlStart.$sql->stmt.'Group By property.id'; $results = mysql_query($qry) or die (mysql_error()."<br />|-|-|-|-|-|-|-|-|-|-|-|-<br />$qry"); if(mysql_num_rows($results) < 1){ die ("Sorry, No Results Match Your Search."); } while($row = mysql_fetch_assoc($results)){ echo '<div class="container" style="float:left;">'; echo '<div class="imageholder" style="float:left;">'; echo "<img class='image1' src='{$row['image_path']}' alt='{$row['summary']}'> <br />"; echo '</div>'; echo '<div class="textholder" style="font-family:helvetica; font-size:14px; float:left; padding-top:10px;">'; echo "{$row['summary']}"; echo "<span style=\"color:#63be21;\"><br><br><b>{$row['bedrooms']} bedroom(s) {$row['bathrooms']} bathroom(s) {$row['receptions']} reception room(s)</b></span>"; if($row['parking'] != null){ echo "<span style=\"color:#63be21;\"><b> {$row['parking']} parking space(s)</b></span>"; } echo '</div>'; echo '<div style="clear:both"></div>'; } } else{ echo "There was a problem, please click<a href='index.php'> Here </a>to return to the main page and try again"; } ?> I have a site, and there is an image with a link to another page, how can I make it so this is the only way to get to that page is by clicking on that image, and not by typing www.mywebsite.com/page.php into the address bar in a browser? I have a table where it displays some data. How do I make this Code: [Select] echo "<td>" . $row['title'] . "</td>"; into a link? Seems to be a basic question, but I couldn't find an answer nor figure it out on my own. Basically I have a script that takes out specific data out of the database, the script works on its own, now I just need a way to make the user execute it with a link or a button. Example: Category: [Smileys] - [Category2] - [Category3] - etc. As soon as the user clicks on [Smileys] all data in the database which contains the word smileys in the category field gets selected and outputted as a list. Again the script works, I just need to be able to execute it with a button. If I understood it correctly I have to run the script by adding a if (isset($_POST['Smileys'])) { in front of the script. But how do I build the connection with the text link? Lets say that I want to make a certain word (or words) on a page a link. How would I make it a link without having to code in a link. Some site have adds on certain words; one day and not the next day. I am looking for similar feature, but less intrusive. No pop-up, just a link. Hi I would like to know how to make a link select certain stuff from the database. For example the link called cape town with the id 11 is selected then the link must search through the events table for the city_id 11 and take that information and display it in another page. I would like to know how to do that or can you let me know of place that I can look. I have tried google but I don't know how to put what I'm looking for in words I would like to know how to make my links show that it's active. For example if I click on a link that says overview then that link has to be highlighted. This is the code that I have: Code: [Select] <?php if (isset($this->_params['submenus']) && is_array($this->_params['submenus'])){ foreach ($this->_params['submenus'] as $submenu){ ?> <li class="active"><a href="<?php echo $this->get_uri("/{$submenu['controller']}/{$submenu['action']}") ?>" onclick="javascript:return setSubMenu(<?php echo $submenu['id'] ?>);"><?php echo strtoupper($submenu['name'])?></a></li> <?php } } ?> Unfortunately with this code all the links are selected as active. hi there, i am fairly new to OOPs in php, i get an error when i declare the argument type (as object) in a function and pass the same type (object). class eBlast { public static function getEmail(object $result) { return $result->email; } } $r = mysql_fetch_object($query); eBlast::getEmail($r); echo gettype($r); // outputs: object error is : Code: [Select] Catchable fatal error: Argument 1 passed to eBlast::getEmail() must be an instance of object, instance of stdClass given, called in C:\wamp\www\integra\client\pl_eblast\admin\send_emails.php on line 145 and defined in C:\wamp\www\integra\client\pl_eblast\app\app.eBlast.php on line 8 if i remove the type declaration in the function it works, but just would like to know why it shows error when pass the same type, also isnt mysql_fetch_object is the instance of stdclass? thanks in advance! This is the code I have now however when you click next to view more results it says please enter a search..., (there is more code above this however I thought that the problem would be within the code provided.) $currPage = (($s/$limit) + 1); //break before paging echo "<br />"; // next we need to do the links to other results if ($s>=1) { // bypass PREV link if s is 0 $prevs=($s-$limit); print " <a href=\"$PHP_SELF?s=$prevs&q=$var\"><< Prev 10</a>  "; } // calculate number of pages needing links $pages=intval($numrows/$limit); // $pages now contains int of pages needed unless there is a remainder from division if ($numrows%$limit) { // has remainder so add one page $pages++; } // check to see if last page if (!((($s+$limit)/$limit)==$pages) && $pages!=1) { // not last page so give NEXT link $news=$s+$limit; echo " <a href=\"$PHP_SELF?s=$news&q=$var\">Next 10 >></a>"; } $a = $s + ($limit) ; if ($a > $numrows) { $a = $numrows ; } $b = $s + 1 ; echo "<p>Showing results $b to $a of $numrows</p>"; ?> Probably a stupid question . . .
The MIME type in my php.ini file is set to text/html:
default_mimetype = "text/html"But, because I use XHTML 1.0 Strict, the MIME type of my web pages is set to text/xml: <meta http-equiv="content-type" content="text/xml; charset=utf-8" />I should therefore change the php.ini MIME type to text/xml, right? Okay so my news script is set to view only 10 pieces of news. But I want it so that it starts a new page once I have more than 10 pieces of news. Code: [Select] <?php require("functions.php"); include("dbconnect.php"); session_start(); head1(); body1(); new_temp(); sotw(); navbar(); $start = 0; $display = 10; $query = "SELECT * FROM news ORDER BY id DESC LIMIT $start, $display"; $result = mysql_query( $query ); if ($result) { while( $row = @mysql_fetch_array( $result, MYSQL_ASSOC ) ) { news_box( $row['news'], $row['title'], $row['user'], $row['date'], $row['id'] ); } mysql_free_result($result); } else { news_box( 'Could not retrieve news entries!', 'Error', 'Error', 'Error'); } footer(); mysql_close($link); ?> I tried a few things but they failed....miserably. Hello.
I have a bit of a problem. When I fetch the link field from the database.i don't see an actual link on the page.
One more thing, what type of field should I use to store the link in the database? Probably there is where I went wrong.
All help is
Hi I've got this database I created with fields ProductId ProductName Image I've managed to get it to list the ID,productname, and Image urls in a list. My next step is to have the image field actually display an image and make it clickable: heres what I've done so far: Code: [Select] <?php $con = mysql_connect("localhost","root",""); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("productfeed", $con); $result = mysql_query("SELECT * FROM productfeeds"); echo "<table border='0'> <tr> <th>Firstname</th> <th>Lastname</th> <th>Image</th> </tr>"; while($row = mysql_fetch_array($result)) { echo "<tr>"; echo "<td>" . $row['ProductID'] . "</td>"; echo "<td>" . $row['ProductName'] . "</td>"; echo "<td>" . $row['ImageURL'] . "</td>"; echo "</tr>"; } echo "</table>"; mysql_close($con); ?> Heres what I want to do: Code: [Select] while($row = mysql_fetch_array($result)) { echo "<tr>"; echo "<td>" . $row['ProductID'] . "</td>"; echo "<td>" . $row['ProductName'] . "</td>"; // my changes beneath echo "<td>" . <a href="<?php echo $row['ImageURL'];?>"> <img src="<?php echo $row['LinkURL']; ?>"> </a>. "</td>"; echo "</tr>"; } echo "</table>"; mysql_close($con); ?> Can you guys point me in the right direction? Many thanks |