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PHP - Variable Holding Php Code....
Hey guys im making a PHP page using PHP
So i have this ##################################################### # Make the PHP page # ##################################################### $PHPCode = " <?php //Title of page used to select the correct record from the database $Title = '".$Name."'; //Use the database information stored in this file include ($_SERVER['DOCUMENT_ROOT'].'/MySQL/Lighthouses-Database-Connection-Information.php'); //Take the information from the database using the method in this file include ($_SERVER['DOCUMENT_ROOT'].'/MySQL/Retrieve-Information.php'); //Process the information using the methods in this file include ($_SERVER['DOCUMENT_ROOT'].'/MySQL/Processing.php'); //Use the layout HTML held in this file include ($_SERVER['DOCUMENT_ROOT'].'/MySQL/PageCode-Lighthouse-Information-Page.php'); //Display the page code made. Resulting in the page displayed. echo $pagecode; ?> "; However, i keep getting syntax errors, possibly due to the fullstops. How shall i get round this?! Danny Similar TutorialsI have inherited some php code, but I am not a real php programmer.
I have just chased down a bug, and I'd like some advice on it.
The code is full of snippets like:
$paramNum = ControlCent :getElementIds(ControlCent :PARAMETER, $bdb, 1, $filterType, $filterId); I have an include file that is included in every page of my website. I'm using sessions and trying to streamline code. The very first line of any page is my include file, and the very first thing in that file is: Code: [Select] <?php session_start(); ?> The page doesn't register that a session was started. Do I have to have session_start() on every single page? Or is there a way to have it in my include file so it is automatically on every page for me? Thank you! I have a option in my profile settings for users to beable to "hide" there friends list this si my code to show there friends on there profile Code: [Select] $this->to_print .= <<< LOL <fieldset><legend>$Friends</legend> <div class="padding4"> $Friends2 LOL; while( $r = $DB->fetch_row() ){ if ( $r['last_activity'] > (time() - 900) ) $r['status'] = "<span style=float:right;><span class=desc4><b>Online</b></span></span>"; else $r['status'] = "<span style=float:right;><span class=desc4>Offline</span></span>"; $column++; if ($ibforums->member['settings']['2'] or (!$ibforums->member['id'])){ $color = "{$r['color']}"; $colors = explode(",", $color); if ( strpos($_SERVER['HTTP_USER_AGENT'], 'MSIE') ){ { $r['color'] = ($r['color']) ? "style=\"padding:1px 1px 1px 2px;color:#{$colors[0]};filter:Glow(color=#{$colors[1]},strength=3)\"":""; } }else{ $r['color'] = ($r['color']) ? "style=\"color:#{$colors[0]};text-shadow:#{$colors[1]} 2px 1px 1px\"":""; } } $test = explode(";", $info['pdata']); $r['avatar'] = ($r['avatar']) ? "<img src={$r['avatar']} width=64 height=64>" : ""; $r['star'] = ($r['star']) ? "<img class=top3 src=style_images/1/icons/{$r['star']}.png>":""; $r['name'] = "<a href=?i={$r['friendid']}>{$r['name']}{$r['star']}</a>"; $this->to_print .= <<< LOL <dl class="LOL LEFT flm" style="margin-right:5px"><dt2>{$r['name']}</dt2><dd class=padding4>{$r['avatar']}<div class="RIGHT">{$r['status']}</div></dd></dl> LOL; } $this->to_print .= <<< LOL </div> </fieldset> now I will be using this code to make it hidden based on a variable (they set in there settings) Code: [Select] //Hide Friends if ($display[0] == "1"){ $friend = ""; }else{ $friend = 'show that function here above code'; } how can I pull all that info into my $friend variable to make it easy? See then I could just echo out $friend and it will show that code above, or not (if they hidden it in settings)? Help ty Hey Everyone, I writing on here because I am taking a course on PHP and learning it by using the textbook PHP 6 Fast & Easy Web Development by Julie Meloni and came across a problem on an assignment that I dont know how to fix. Any who, in the assignment I was working on I wrote a script that shows data I have in a table in my broswer (which btw works) BUT it always gives me the following message: Notice: Undefined variable: display_block in 127.0.0.1\sel_byid.php on line 29. I have checked my code over and and am sure I copied it right but still get the notice. Here's the code: Code: [Select] <?php $db_name = "testDB"; $table_name = "my_music"; $connection = @mysql_connect("localhost", "brenda", "mouse") or die(mysql_error()); $db = @mysql_select_db($db_name, $connection) or die(mysql_error()); $sql = "SELECT * FROM $table_name ORDER BY title"; $result = @mysql_query($sql, $connection) or die(mysql_error()); while($row = mysql_fetch_array($result)) { $id = $row['id']; $format = $row['format']; $title = stripslashes($row['title']); $artist_fn = stripslashes($row['artist_fn']); $artist_ln = stripslashes($row['artist_ln']); $rec_label = stripslashes($row['rec_label']); $my_notes = stripslashes($row['my_notes']); $date_acq = $row['date_acq']; if($artist_fn != "") { $artist_fullname = trim("$artist_fn $artist_ln"); }else{ $artist_fullname = trim("$artist_ln"); } if($date_acq == "0000-00-00") { $date_acq = "[unknown]"; } $display_block .= "<P><strong>$id. $title</strong>on $rec_label, by $artist_fullname<br>$my_notes<em>(acquired: $date_acq, format: $format)</em></P>"; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>My Music (Ordered by Title)</title> </head> <body> <H1>My Music: Ordered by Title</H1> <?php echo "$display_block"; ?> <P><a href="my_menu.html">Return to Menu</a></P> </body> </html> I've been trying to fix it for like a week now and the only thing I understand from the notice is that this line: Code: [Select] $display_block .= "<P><strong>$id. $title</strong>on $rec_label, by $artist_fullname<br>$my_notes<em>(acquired: $date_acq, format: $format)</em></P>"; is trying to concatentate to a variable which does not exist ($display_block) and I dont know how to fix it... Can anyone help me? Hi a get a server error with this code, this worked for awhile, now it doesn't work. I use the first part to extract the user name from the url. then parse it to the IF cookie function as a variable for the cookie name. The cookie is placed on another html page and i placed it like this: <script language="javascript"> document.cookie = "{PROFILE_USERNAME}= 1"; </script> // this code works perfectly i used php to parser the variable to the javascript function, when i check the browser for cookies, it is placed correctly. this code i use to check the cookie's name to see if it exists. the variable below is taken from the url, and matches the username above, but when i execute the code i get this error: Illegal variable _files or _env or _get or _post or _cookie or _server or _session or globals passed to script. can anyone see the problem? <?php $url = $_SERVER['SCRIPT_FILENAME']; $newurl = explode("/", $url); $profmanager=$newurl[6]; $cook= $profmanager; if(!isset($_COOKIE['$cook'])) { $url2 = $_SERVER['HTTP_HOST']; $myurls = 'http://'.$url2.'/'; echo "<META HTTP-EQUIV=Refresh CONTENT=\"0;URL=$myurls\">"; } else { my page code here }?> // to note when i echo the $newurl[6] it does equal the username. the first code in on a html page/the javascript above, // the second code piece is AT THE TOP of a php page. // if there is a better way, liike matching values instead of the cookie name, i would be keen to see it in action. <?php $pageTitle='Edit Profile'; require_once ("header.php"); ?> How can I pass a variable like that through header.php? I know it doesn't work the way I have it. Hi All, I'm having a major mind blank, and can't find anything in the previous posts resolving what I'm after. I'm setting $searchtext = $_POST['searchtext']; I want to check $seachtext is not null. I've seen isset($searchtext) but it doesn't solve my problem. Basiclaly; I want an if statement to say if(isset($searchtext)) {......} Thoughts? So what i mean is if i set a variable to "[" ($some_variable = "[") the rest of my code is now going to go CRAZY because there is an open [. Is there a way I can just make everything inside the first set of "" not relevant to the code? thanks! Dear Friends I want to execute a php code when my session has been destroy or demoinshed, I need a help regarding this kindly help me. Best Regards Habib User clicks on a url, ie: example.com/AEQ438J When I perform this in the code below: Code: [Select] $referrer = $_GET['_url']; // echo $referrer displays the referrer ID contents correctly as "AEQ438J" if ( ! empty($referrer)) { $mysqli->query("UPDATE coming_soon_emails SET clicks = clicks + 1 WHERE code='" . $referrer ."'"); } // this also updates the database correctly as it should if (!empty($_POST['email'])){ // echo $referrer displays the referrer ID contents as BLANK. It should display "AEQ438J"! ..... $referrer displays correctly BEFORE if($_POST['form']), however during the if($_POST['form']) $referrer is empty. How can I fix my code so that $referrer is not empty during the time the user posts their email address in the form? Thank you! Complete PHP and HTML Code: [Select] <?php require "includes/connect.php"; //var_dump($_GET);die; function gen_code($codeLen = 7) { $code = ''; for ($i=0; $i<$codeLen; $i++) { $d=rand(1,30)%2; $code .= $d ? chr(rand(65,90)) : chr(rand(48,57)); } return $code; } function add_code($email_id) { global $mysqli; $code = gen_code(7); $mysqli->query("UPDATE coming_soon_emails SET code='" . $code ."' WHERE email_id='" . $email_id . "'"); if($mysqli->affected_rows != 1) { add_code($email_id); } else return $code; } $msg = ''; $referrer = $_GET['_url']; // echo $referrer displays the referrer ID contents correctly if ( ! empty($referrer)) { $mysqli->query("UPDATE coming_soon_emails SET clicks = clicks + 1 WHERE code='" . $referrer ."'"); } if (!empty($_POST['email'])){ // echo $referrer displays the referrer ID contents as BLANK // Requested with AJAX: $ajax = ($_SERVER['HTTP_X_REQUESTED_WITH'] == 'XMLHttpRequest'); try{ if(!filter_input(INPUT_POST,'email',FILTER_VALIDATE_EMAIL)){ throw new Exception('Invalid Email!'); } $mysqli->query("INSERT INTO coming_soon_emails SET email='".$mysqli->real_escape_string($_POST['email'])."'"); if($mysqli->affected_rows != 1){ throw new Exception('This email already exists in the database.'); } else { $email_code = add_code($mysqli->insert_id); } $msg = "http://www.example.com/" . $email_code; //the following doesn't work as referrer is now empty :( if ( ! empty($referrer)) { $mysqli->query("UPDATE coming_soon_emails SET signup = signup + 1 WHERE code='" . $referrer ."'"); } if($ajax){ die(json_encode(array('msg' => $msg))); } } catch (Exception $e){ if($ajax){ die(json_encode(array('error'=>$e->getMessage()))); } $msg = $e->getMessage(); } } ?> <!DOCTYPE html> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title></title> <link rel="stylesheet" type="text/css" href="css/styles.css" /> </head> <body> <div id="launch"> <form id="form" method="post" action=""> <input type="text" id="email" name="email" value="<?php echo $msg;?>" /> <input type="submit" value="Submit" id="submitButton" /> </form> <div id="invite"> <p style="margin-top:20px;">The ID of who referred you: <?php echo $referrer; //this displays correctly?>)</p> <p style="margin-top:20px;"><span id="code" style="font-weight:bold;"> </span></p> </div> </div> <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.3/jquery.min.js"></script> <script src="js/script.js"></script> </body> </html> script.js Code: [Select] $(document).ready(function(){ // Binding event listeners for the form on document ready $('#email').defaultText('Your Email Address'); // 'working' prevents multiple submissions var working = false; $('#form').submit(function(){ if(working){ return false; } working = true; $.post("./index.php",{email:$('#email').val()},function(r){ if(r.error){ $('#email').val(r.error); } else { $('#email').val(r.msg); // not needed but gets hidden anyways... $('#launch form').hide(); $("#code").html(r.msg); $("#invite").fadeIn('slow'); } working = false; },'json'); return false; }); }); // A custom jQuery method for placeholder text: $.fn.defaultText = function(value){ var element = this.eq(0); element.data('defaultText',value); element.focus(function(){ if(element.val() == value){ element.val('').removeClass('defaultText'); } }).blur(function(){ if(element.val() == '' || element.val() == value){ element.addClass('defaultText').val(value); } }); return element.blur(); } htaccess Code: [Select] RewriteEngine on RewriteCond %{HTTP_HOST} ^my-url.com RewriteRule (.*) http://www.my-url.com/$1 [R=301,L] RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteRule ^([a-z0-9]+)$ /index.php?_url=$1 [NC,L,QSA] table.sql Code: [Select] CREATE TABLE IF NOT EXISTS `coming_soon_emails` ( `email_id` int(11) NOT NULL auto_increment, `email` varchar(64) collate utf8_unicode_ci NOT NULL, `code` char(7) collate utf8_unicode_ci DEFAULT NULL, `clicks` int(64) collate utf8_unicode_ci DEFAULT 0, `signup` int(64) collate utf8_unicode_ci DEFAULT 0, `ts` timestamp NOT NULL default CURRENT_TIMESTAMP, PRIMARY KEY (`email_id`), UNIQUE KEY `email` (`email`), UNIQUE KEY `code` (`code`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci; Dear Friends, I am alot before doing the mixed content of php and HTML in single variable in PHP.. I could not get the data even though there is not SYNTAX error.. please look my code and advise
$htmlcontent .="
<tr>
<td colspan=\"8\">".$details."></td>
</tr>";
for($k=0;$k<count($reg_years[$details]);$k++) {
$year = (int)($reg_years[$details][$k]);
$singlecount[$year] = array_filter($result[$details],function($details1) use ($year){
return ($details1['reg_year'] == $year && $details1['bench_type'] == 1);
});
$divisioncount[$year] = array_filter($result[$details],function($details2) use ($year){
return ($details2['reg_year'] == $year && $details2['bench_type'] == 2);
});
$fullcount[$year] = array_filter($result[$details],function($details3) use ($year){
return ($details3['reg_year'] == $year && $details3['bench_type'] >= 3);
});
$rpcount[$year] = array_filter($result[$details],function($rp) use ($year){
return ($rp['reg_year'] == $year && $rp['bench_type'] == 'RP');
});
$mjccount[$year] = array_filter($result[$details],function($mjc) use ($year){
return ($mjc['reg_year'] == $year && $mjc['bench_type'] == 'MJC');
});
$cocount[$year] = array_filter($result[$details],function($co) use ($year){
return ($co['reg_year'] == $year && $co['bench_type'] == 'X');
});
$total = 0;
$total = (int)(count($singlecount[$year])+count($divisioncount[$year])+count($fullcount[$year])+count($rpcount[$year])+count($mjccount[$year])+count($cocount[$year]));
$htmlcontent .="
<tr>
<td>".$year."</td>
<td align=\"center\">
if(count($singlecount[$year])>0) {
echo (count($singlecount[$year]));
}
else {
echo "-";
}
</td>
<td align=\"center\">
if(count($divisioncount[$year])>0) {
".count($divisioncount[$year])."
} else {
"-"
}
</td>
<td align=\"center\">
if (count($fullcount[$year]) > 0)
{
echo (count($fullcount[$year]));
}
else
{
echo "-";
} </td > < td align =\"center\">
if(count($rpcount[$year])>0) {
echo (count($rpcount[$year]));
} else { echo " - "; }
</td>
<td align=\"center\">
if(count($mjccount[$year])>0) {
echo (count($mjccount[$year]));
} else { echo " - "; }
</td>
<td align=\"center\">
if(count($cocount[$year])>0) {
echo (count($cocount[$year]));
} else { echo " - "; }
</td>
<td align=\"center\">
echo $total;
</td>
</tr>";
}
}
$htmlcontent .= "</tbody></table>";
$mpdf = new \Mpdf\Mpdf();
$mpdf->WriteHTML($htmlcontent);
$mpdf->Output();
Waiting for FAST reply
Thanks Anes I have a submit.php file that includes the following jQuery code:
<script> [...] request.done(function( json ) { jQuery('input[name=thumbnail-url]').val(json.thumbnail_url); jQuery('input[name=job_title]').val(json.title); jQuery('textarea[name=htmlcode]').val(json.html); [...] </script>
I need to remove
jQuery('textarea[name=htmlcode]').val(json.html);
and pass the "json.html" value into a PHP variable in another php file (functions.php). The code in the functions.php file is already there. The thing i need to do (and i am seriously struggling with it) is placing the value of json.html into a $phpvariable that i can then call from the function.php file. Do you need any more info for this issue? Thanks. I have a Google Adsense code that I am saving to the wp_options table. I can successfully save and retrieve the variable containing the google adsense code but it doesn't do anything except display it as plain text on screen. I have a form that users input user name, password, and email... all writes to csv fine. My problem is I need to concatenate a a string with a variable and some html code will preserving the html when written to the csv.. I need the csv to be this username,password,email,user,category,text with http://sub.domain..com/splash/,something,something here's what i have Code: [Select] <?php if($_POST['formSubmit'] == "Submit") $varUserName = $_POST['username']; $varPW = $_POST['PW']; $varEmail = $_POST['email']; { $fs = fopen("testcsv.csv","a"); fputcsv($fs, array($varUserName,$varPW,$varEmail,"user","title",",category","some text '<a href="http://$varUserName.url.com/splash/>site.com</a>',)); fclose($fs); exit; } ?> and of course I'm getting Parse error: syntax error, unexpected T_STRING, expecting ')' on line 9 I am trying to allow the user to update a variable he chooses by radio buttons, which they will then input text into a box, and submit, to change some attributes. I really need some help here. It works just fine until I add the second layer of variables on top of it, and I can't find the answer to this question anywhere. <?PHP require('connect.php'); ?> <form action ='' method='post'> <select name="id"> <?php $extract = mysql_query("SELECT * FROM cars"); while($row=mysql_fetch_assoc($extract)){ $id = $row['id']; $make= $row['make']; $model= $row['model']; $year= $row['year']; $color= $row['color']; echo "<option value=$id>$color $year $make $model</option> ";}?> </select> Which attribute would you like to change?<br /> <input type="radio" name="getchanged" value="make"/>Make<br /> <input type="radio" name="getchanged" value="model"/>Model<br /> <input type="radio" name="getchanged" value="year" />Year<br /> <input type="radio" name="getchanged" value="color" />Color<br /><br /> <br /><input type='text' value='' name='tochange'> <input type='submit' value='Change' name='submit'> </form> //This is where I need help... <?PHP if(isset($_POST['submit'])&&($_POST['tochange'])){ mysql_query(" UPDATE cars SET '$_POST[getchanged]'='$_POST[tochange]' where id = '$_POST[id]' ");}?> Hello all. I am very new to PHP, and I am not sure where to look or what I'm looking for in my current assignment. My task is to take in two numbers between 0-100. Once I take in that number, it should state beside it "The __ was accepted." The program should not accept any numbers greater than 100 or any characters. Once I do this, I must take a second number and do a similar thing. Finally, I must have a statement show up at the bottom stating which number is greater. Essentially, I need help in determining what I should use to place parameters, and how I can keep the program from echo ing any statement until input has been taken and tested for parameters. Any help you can provide will be greatly appreciated! My login script stores the user's login name as $_SESSION[ 'name'] on login. For some unapparent reason, i'm getting errors stating that $user and $priv are undefined variables, though I've attempted to define $user as being equal to $_SESSION['name'], using $user to look up the the user's privilege level (stored as the su column ) in the SQL table, and then where the result of the sql query is $priv which is then evaluated in an if statement. I can't seem to figure out why this might not be working. The code I'm using:
<?php
session_start();
function verify() {
//verify that the user is logged in via the login page. Session_start has already been called.
if (!isset($_SESSION['loggedin'])) {
header('Location: /index.html');
exit;
}
//if user is logged in, we then lookup necessary privleges. $_SESSION['name'] was written with the login name upon login. Privleges // are written in db as a single-digit integer of of 0 for users, 1 for administrators, and 2 for special users.
$user === $_SESSION['name'];
//Connect to Databse
$link = mysqli_connect("127.0.0.1", "database user", "password", "database");
if (!$link) {
echo "Error: Unable to connect to MySQL." . PHP_EOL;
echo "Debugging errno: " . mysqli_connect_errno() . PHP_EOL;
echo "Debugging error: " . mysqli_connect_error() . PHP_EOL;
exit;
}
//SQL Statement to lookup privlege information.
if ($result = mysqli_query($link, "SELECT su FROM accounts WHERE username = $user", MYSQLI_STORE_RESULT)) {
//LOOP TO CYCLE THROUGH SQL RESULTS AND STORE Privlege information as vairable $priv.
while ($row = $result->fetch_assoc()) {
$priv === $row["su"];
}
}
// close SQL connection.
mysqli_close($link);
// Verify privleges and take action. Only a privlege of "1" is allowed to view this page. A privlege of "2" indicates special
//accounts used in other scripts that have certain indermediate additional functions, but are not trusted administrators.
if ($priv !== 1) {
echo $_SESSION['name'];
echo "you have privlege level of $priv";
echo "<br>";
echo 'Your account does not have the privleges necessary to view this page';
exit;
}
}
verify();
?>
I have just re-installed Xampp and suddenly my sites are now displaying lots of: Notice: Use of undefined constant name - assumed 'name' in ... Notice: Use of undefined constant price - assumed 'price' in ... this is an example of the line its refering too: $defineProducts[1001] = array(name=>'This is a product', price=>123); Hello everyone, I can get Test 2 to successfully operate the if statement using a variable variable. But when I try the same method using a session variable (Test 1) the if statement is not executed. Please could you tell me why the if statement in Test 1 is not being executed? Code: [Select] <?php # TEST 1 $_SESSION[test_variable] = "abcd"; $session_variable_name = "_SESSION[test_variable]"; if ($$session_variable_name == "abcd") { echo "<br>line 373, abcd<br>"; } # TEST 2 $test_variable = "efgh"; $test_variable_name = "test_variable"; if ($$test_variable_name == "efgh") { echo "<br>line 379, efgh<br>"; } ?> Many thanks, Stu I have a script that adds points together based upon the placing. This is the actual script: Code: [Select] <? $points = 0; if($place === '1st') {$points = $points + 50;} elseif($place === '2nd') {$points = $points + 45;} elseif($place === '3rd') {$points = $points + 40;} elseif($place === '4th') {$points = $points + 35;} elseif($place === '5th') {$points = $points + 30;} elseif($place === '6th') {$points = $points + 25;} elseif($place === '7th') {$points = $points + 20;} elseif($place === '8th') {$points = $points + 10;} elseif($place === '9th') {$points = $points + 10;} elseif($place === '10th') {$points = $points + 10;} elseif($place === 'CH') {$points = $points + 50;} elseif($place === 'RCH') {$points = $points + 40;} elseif($place === 'TT') {$points = $points + 30;} elseif($place === 'T5') {$points = $points + 30;} elseif($place === 'Champion') {$points = $points + 50;} elseif($place === 'Reserve Champion') {$points = $points + 40;} echo "Total HF Points: $points"; ?>What it *should* do (my friend's script works the same way and it works) it starts at points = 0, than if there is a first place, it adds 50, and so forth until it reaches the end. It is included into a file, in this area: Code: [Select] <div class="tabbertab"> <h2>Records</h2> <? $query92 = "SELECT * FROM THISTABLE WHERE VARIABLE='$id' OR VARIABLE = '$name' ORDER BY ABS(VARIABLE), VARIABLE"; $result92 = mysql_query($query92) or die (mysql_error()); echo "<table class='record'> <tr><th>Show</th> <th>Class</th> <th>Place</th></tr> "; while($row92 = mysql_fetch_array($result92)) { $class = $row92['class']; $place = $row92['place']; $entries = $row92['entries']; $race = $row92['show']; $purse = number_format($row92['purse'],2); echo "<tr><td>$race</td> <td>$class</td> <td>$place</td></tr>"; } ?> <tr><td colspan='3'><div align='right'><? include('includes/points.php'); ?></div></td></tr> </table> </div> This is the code that is relevant. When ended here, it echoes the last place that appears in the results (such as a 5th place echoing 30 points). When I move it to be included in the while loop, it shows Total Points: 50 Total Points: 25 Total Points: 10 (depending on the results displayed on that page). What am I doing wrong? |
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