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PHP - Getimagesize() "no Such File Or Directory" - But The Image Is There!
Hi all,
I'm iterating 4 images out in a loop. All 4 images exist (definitely), and using an earlier script, have been resized to a width of 200px, so they are not large. I'm finding that if I use the following code: Code: [Select] $image_info = getimagesize($filename); $type = $image_info['mime']; echo $type; .. some of the images come up with no mime type. Is this normal? As a (possible) result of / link to having no mime type assigned to it, I'm getting: [function.getimagesize]: failed to open stream: No such file or directory .. but I am positive the image exists. Viewing the image info in a browser gives "image/jpeg", so I'm a bit weirded out as to how the script queries the image for a mime type, and it returns nothing. Has anybody else seen this, can anyone help? All the best, WoolyG Similar TutorialsMy images generator comprises
an array of image names extracted form an images table from a database using a select statement
a random number generator,
and a string that builds the correct pathname for the selected file.
To select one of the images for display, i generate a random number between 1 and the length of the array.
Though the generator is working, I noticed one of the random numbers is throwing up this error:
Warning: getimagesize(images/): failed to open stream: No such file or directory in
An inspection of the array reveals 2 array elements (representing my number of images) but one array element is NULL ( the first entry in the banner table
image_generator.php
require_once('connection.inc.php');
$sql = 'SELECT `filename` FROM banner';
$result = $mysqli->query($sql, MYSQLI_STORE_RESULT) or die(mysqli_error());
$row = $result->fetch_array(MYSQLI_ASSOC);//an array of image names
$count = $result->num_rows;
for ($i = 1; $i <= $count; ++$i)
{
$row[$i] = $result->fetch_array(MYSQLI_ASSOC);
}
$i = rand(1, $count); //a random number generator,
//The random number is used in the final line to build the correct pathname for the selected file.
$selectedImage = "images/{$row[$i]['filename']}";
if (file_exists($selectedImage) && is_readable($selectedImage))
{
$imageSize = getimagesize($selectedImage);
}
var_dump($row)
array (size=1)
'filename' => string 'ginsomin2.jpg' (length=13)
null
RANDON IMAGE DISPLAY
require_once 'image_generator.php';
<div id="banner" class="wrapper clearfix">
<img src="<?php echo $selectedImage; ?>" alt="banner">
</div>
Kindly advice how i may proceed from here?
Thanks.
Can someone please help me with an array problem i can not figure out. I need the array to be numbered from 1 to how ever many fields that are needed in the form and have a mysql field name and the title of the field also in the array. 1, "mysql_field_name", "Title of form field" 2, "", "" and so on then the form will be shown based on the array. I have the following draft code which I am working with. any suggestions on how i may do this array ? Code: [Select] <?php $options = array( '1'=> array('fieldtext'=>'option1', 'mysqlfield'=>'option1'), '2'=> array('fieldtext'=>'option2', 'mysqlfield'=>'option2'), '3'=> array('fieldtext'=>'option3', 'mysqlfield'=>'option3'), '4'=> array('fieldtext'=>'option4', 'mysqlfield'=>'option4'), ); // $options = array(1 => "option1", "option2", "option3", "option4"); // the line above works but i want to include the name of the mysql field as well. $userid = 1; ?> <div style="align: center; margin: 12px; font-family:Tahoma;"> <br><br><?php if ($_POST['Update'] != "Update") { // check if form submitted yet, if not get data from mysql. $res = db_query("SELECT * FROM `users` WHERE `userid` = '" . $userid . "'"); foreach($options as $key => $value) { $_POST[$key] = mysql_result($res, 0, $value); } $ok_to_update = "no"; } elseif ($_POST['Update'] == "Update") { // check if form submitted yet, if so get POST data. // error checking // foreach($options as $key => $value) { // $_POST[$i] = ""; // } $ok_to_update = "yes"; } if ($_POST['Update'] == "Update" && $ok_to_update == "yes") { // $res = db_query("INSERT INTO `users` () VALUES ()"); // add user details to database. ?><p><br><br><br>Thank you for updating</p><?php } else { ?><form name="form1" method="post" action=""> <?php foreach($options as $key => $value) { ?><p><?php echo($value); ?>: <input type="text" name="<?php echo($key); ?>" value="<?php echo($_POST[$key]);?>"></p> <?php } ?> <input name="Update" type="submit" value="Update"> </form> <?php } ?> </div> Hi, bit stuck on how to find and replace "<" and ">" with "<" and ">". I basically have a database record that outputs to screen and I need the code in the <code> tags to be rendered to the screen. I therefore need it to go through the whole array variable from the db and change the symbols just inside the code tags. Please be aware that the code tags might happen more than once here's an example below Code: [Select] <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1> </code> <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1> </code> the desired output would be: <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1 </code> <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1 </code> help on this would be great Cheers Rob Do I need to check both the "Image Size" AND "Image Dimensions" for files that Users upload to my website? Currently I have... // ******************** // Check File-Size. * // ******************** if (empty($errors)){ // Check File-Size in Bytes. if (filesize($tempFile)<4000){ // File too small. $errors['upload'] = 'File-size must be greater than 4 Kilobytes.'; }elseif (filesize($tempFile)>100000){ // File too big. $errors['upload'] = 'File-size must be less than 100 Kilobytes.'; }else{ // File-Size Okay. // Continue Processing Upload... } }//End of CHECK FILE-SIZE I guess I haven't been worrying about "File Dimensions" because I resize everything here... // ********************** // Set New Dimensions. * // ********************** // Capture Dimensions on Original Image. $origWidth = imageSX($origImage); $origHeight = imageSY($origImage); if ($origWidth > $origHeight){ $newWidth = 100; $multiplier = $newWidth/$origWidth; $newHeight = $origHeight * $multiplier; } if ($origWidth < $origHeight){ $newHeight = 100; $multiplier = $newHeight/$origHeight; $newWidth = $origWidth * $multiplier; } if ($origWidth == $origHeight){ $newWidth = 100; $newHeight = 100; } Thanks, Debbie Hi, I want to separate out the file name from an image url. Not sure the best way to do it? I want to basically select all text after the last / slash. eg - image.jpg would be the result from http://www.google.com/images/image.jpg What's the best way to do it? Cheers Rob Hey, friends. I have some trouble on the server front. My sites have been hacked, and I need to make sure I've eradicated every trace of this exploit. I'm looking for a way to search for any and all php files contained in multiple directories with specific names. For instance, I have found a commonality in relation to where these malicious files are placed, such as: Code: [Select] /some/dir/img/somename.phpor: Code: [Select] /some/dir/js/somename.php Is there a way I can easily (e.g. using ssh and the "find" command) locate all files ending in php but only found in directories named "img"? I can't seem to find anything that would allow me to do this with find, or with a combination of find and grep. I can't go directory by directory, as some of these img directories are created many levels deep, some even in .svn directories. Any and all help is appreciated. Hackers suck. Hey guys, I have a folder which has images. In this folder there are images that start with "refl_". I want to make sure those are not displayed. This is what I tried and it does not work. I want to show all images that don't start with "refl_". I am new to this as I am sure some can see. Thanks for the help if possible! <?php $dir = opendir("img/portfolio/"); while (false !== ($file = readdir($dir))) { $pos = strpos($file, "refl_"); if ($pos == false) { echo '<img src="img/portfolio/' . $file . '" longdesc="img/portfolio/' . $file . '" /></a>'; } } ?> Hi guys I am a newbie with PHP and I have been trying to solve this problem for 3 days.. Ive set up a booking form on my website to be sent directly to my email once the client clicked on the send button.. The problem I am having while checking these pages on wamp is that the booking form is ok but when I click on the send button the following message error appears "Warning: mail() [function.mail]: Failed to connect to mailserver at "localhost" port 25, verify your "SMTP" and "smtp_port" setting in php.ini or use ini_set() in C:\wamp\www\fluffy_paws\booking_form2.php on line 27" When I check online I have this message "500 - Internal server error. There is a problem with the resource you are looking for, and it cannot be displayed." Are my codes wrong??? My webhosting is Blacknight.com , Im on Windows Vista, my internet is a dongle with O2 ireland Thanks for your help! Hi guys I'm struggling a bit, I need to replace a word that occurs multiple times in text with an array("up","down","forward","backwards") of words. $find = "left"; $replace = array("up","down","forward","backwards"); $text = "left left left left"; echo str_replace($find,$replace,$text); The Output is: array array array array Did try this with a foreach statement as well, but no luck. Is there a better way of doing this? Thanks cant work out this mysql syntax error "operation":"medupdate","medid":"","name":"ibo","medyear":"5","medmonth":"21","medday":"1","recuser":1,"SuccFail":"fail","SuccFailMessage":"error occured You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '''WHERE med_id=' at line 2","ResultData":""} Code: [Select] $sql="update metodology set med_description='".$req['name']."', med_year='".$req['medyear']."', med_month='".$req['medmonth']."', med_day='".$req['medday']."', med_recorddate= now(), med_recorduserid= 1'"; $sql.= " WHERE med_id=".$req['medid']; I am getting the following error when using composer: "continue" targeting switch is equivalent to "break". Did you mean to use "continue 2"? Just started. I am pretty sure composer.json wasn't changed. journalctl doesn't show anything. Maybe Doctrine related, however, nothing seems to help.
Any ideas? [michael@devserver www]$ php -v PHP 7.3.4 (cli) (built: Apr 2 2019 13:48:50) ( NTS ) Copyright (c) 1997-2018 The PHP Group Zend Engine v3.3.4, Copyright (c) 1998-2018 Zend Technologies with DBG v9.1.9, (C) 2000,2018, by Dmitri Dmitrienko [michael@devserver www]$ composer -V Composer version 1.4.2 2017-05-17 08:17:52 [michael@devserver www]$ yum info composer Loaded plugins: fastestmirror Loading mirror speeds from cached hostfile * base: mirror.us.oneandone.net * epel: mirror.rnet.missouri.edu * extras: mirror.us.oneandone.net * remi-php73: mirror.bebout.net * remi-safe: mirror.bebout.net * updates: mirror.us.oneandone.net Installed Packages Name : composer Arch : noarch Version : 1.8.4 Release : 1.el7 Size : 1.8 M Repo : installed From repo : epel Summary : Dependency Manager for PHP URL : https://getcomposer.org/ License : MIT Description : Composer helps you declare, manage and install dependencies of PHP projects, : ensuring you have the right stack everywhere. : : Documentation: https://getcomposer.org/doc/ [michael@devserver www]$ composer update Loading composer repositories with package information Updating dependencies (including require-dev) [ErrorException] "continue" targeting switch is equivalent to "break". Did you mean to use "continue 2"? update [--prefer-source] [--prefer-dist] [--dry-run] [--dev] [--no-dev] [--lock] [--no-custom-installers] [--no-autoloader] [--no-scripts] [--no-progress] [--no-suggest] [--with-dependencies] [-v|vv|vvv|--verbose] [-o|--optimize-autoloader] [-a|--classmap-authoritative] [--apcu-autoloader] [--ignore-platform-reqs] [--prefer-stable] [--prefer-lowest] [-i|--interactive] [--root-reqs] [--] [<packages>]... [michael@devserver www]$
Hi, It's been a while since I've been on here... I've got a script that takes an image url and resizes it, then outputs it to the screen (using image headers etc). I've then got a htaccess file that changes my nice url, such as: 'images/thumb/50-70/logo.jpg' to: 'incudes/resize.php?width=50&height=70&img=logo.jpg' Which is the resize script, so I can use a nice url in img tags. The width and height are just the maximum allowed, so sometime the image will be smaller. Now, this all works correctly, but I am now trying to find out the width and height of the thumbnailed image, from outside of the resize.php script. I thought that I could use getimagesize, but this doesn't seem to work... I first tried it using the 'nice' url: '/images/thumb/50-70/logo.jpg' Thinking that .htaccess would re-direct, but no. I then tried a direct link to the resize file: '/incudes/resize.php?width=50&height=70&img=logo.jpg' But that returns a file not found error... Although I can access the file directly. Trying the direct url without the get variables, however, successfully finds the file, but it doesn't seem to be able to detect the image dimensions. I just get a blank result.. Is PHP able to recognise htaccess re-directs? Is PHP able to parse a php file that outputs as an image? (I have all the correct headers etc set!) Thanks This topic has been moved to Linux. http://www.phpfreaks.com/forums/index.php?topic=318175.0 This topic has been moved to PHP Installation & Configuration. http://www.phpfreaks.com/forums/index.php?topic=347922.0 I have a registration form on my website and after Registration I want the user to activate first his account. I don't have problem on sending this email to the user. What I want to appear is like this.. GoodDay "username", Blah Blah! how can you actually do that? I know that you can do that through session variables but the thing is email's can't accept scripts on sending emails. how can I get the value from a session variable for example and convert it to plain html text so that i can OUTPUT it to the email.. HELP PLEASE! Hi, I currently have an if, elseif, else program that starts off with Code: [Select] if( $v_name == "" || $v_msg == "" ) echo "something" how do I turn this into a switch? but the very next elseif I have Code: [Select] elseif( strcspn( $_REQUEST['msg'], '0123456789' ) == strlen( $_REQUEST['msg'] ) ) echo "something" is it possible to turn this into a switch with 2 different strings like that to evaluate? When I Google the above string I find a lot of advice about using SFTP, turning on blocking, upgrading libraries and such, however, the code that does this seems to work during some operations and not work during others, so I don't think it's a matter of a buggy library. If I could find out why it cannot create the remote file, that might do a world of good. But I've been through all of /var/log and some log messages acknowledge the ssh session, but don't give any clues as to what goes wrong. I've looked at the user, password, host name and port name in and around the ssh2_connect() call. They are all good. I've also checked the permissions and ownership on the destination directory. They aren't the problem either. I've also tried duplicating the call w/a command-line scp call, and that test passes also. So now find myself staring at this "failure creating remote file" message, wondering what the failure is, and I'm running out of ideas. I'm running RHEL AS release 4. I have a text file that contain something like this : question.txt ------------------------ 12/10/2010 Quest : Was a web designer really care about your web security other than thinking so hard to design your web just based on how the web will looks like?. >>from:sombody@somwhere.com,opinion=not at all,comment:your site are cool 11/10/2010 Quest : Was a web designer really love his girl friend in other side they r almost got no time dating with her? >>from:sombody@somwhere.net,opinion=he loves computer,comment:your site are waste. ------------------------- All i need to do is, grabing all informations after the char ">>" and write it to another text file name "output.txt" that will contain : output.txt --------------------- from:sombody@somwhere.com,opinion=not at all,comment:your site are cool from:sombody@somwhere.net,opinion=he loves computer,comment:your site are waste. --------------------- can some one show me the way? thanks. I run a dev site locally on Windows and the real site on a hosting provider on LINUX. PHP5, XAMP, etc. Locally my fopen works. On the web server it throws an error: "Warning: fopen() [function.fopen]: Unable to access" filepath/name The file exists on both servers; upper/lower case is correct; so are access rights. I noticed the error only today; this was working for the last 7 months; the function serves a range of content-types; just tested XLS and it works. Now I am stuck This line throws the error: $handle = fopen($strPathFileName, 'rb'); $strPathFileName uses / only Any pointers appreciated... thanks. Hi. I have a page that allows users to upload some files, using <input type="file">... What I would like is to be able to upload the file "onchange" of this input field using ajax so that (1) users can upload their second file while their first one is uploading, and (2) so that they can see their file on the page as soon as it's done uploading. But I can't seem to find a way to populate the $_FIlLES array without actually submitting the form. I've seen some stuff online where people use iframes to do this kind of thing, but I was hoping there was another way to do it. Any help would be great. |
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