PHP - Fopen Multiple Files, Then Select One
Hi I want to read multiple .txt files and then if an action requires select one.
Quote <? // /home/person-mike.txt // /home/person-sarah.txt // /home/person-paul.txt while ($row = sqlite_fetch_array($result)) { $name = $row['name']; $filename = "/home/person-$name.txt"; $handle = fopen($filename, "r"); $sendrequest = fread($handle, filesize($filename)); fclose($handle); } ?> <? if ( $client == "sarah" ) { echo "$sendrequest[sarah]"; ?> How do I do the last bit to have a variable like $sendrequest[sarah] Similar TutorialsHello, I'm working on a script which should read lines from a file keyword.txt create a new file with that variable name, insert the content close and loop through all the lines in the keyword file. The loop itself works but now that i'm adding the fopen fwrite and fclose i'm running into trouble. I'm not that great a coder and have pieced this together so far. I'd appreciate any suggestions on how to fix the fopen and other file functions to create unique files using the keywords from the file Thanks in advance <?php $read_file = file('keywords.txt'); foreach($read_file as $var) { $file = fopen($var, "x"); $content = "<!DOCTYPE html PUBLIC \"-//W3C//DTD XHTML 1.0 Transitional//EN\" \"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd\"> <html xmlns=\"http://www.w3.org/1999/xhtml\"> <head> <meta http-equiv=\"Content-Type\" content=\"text/html; charset=utf-8\" /> <title>This is the title</title> </head> <body> <h2>The keyword is $var</h2> <p><p> </body> </html>"; fwrite($file, $content); fclose($file); } ?> hi, I want to write pdf file but it is getting garbage value i check following url http://bugs.php.net/bug.php?id=21904&edit=1 Code: [Select] $fp = fopen($fdirandname,'wb'); fwrite($fp,$pdfcode); fclose($fp); hirealimo.com.au/code1.php this works as i want it: Quote SELECT * FROM price INNER JOIN vehicle USING (vehicleID) WHERE vehicle.passengers >= 1 AND price.townID = 1 AND price.eventID = 1 but apparelty selecting * is not a good thing???? but if I do this: Quote SELECT priceID, price FROM price INNER JOIN vehicle....etc it works but i lose the info from the vehicle table. but how do i make this work: Quote SELECT priceID, price, type, description, passengers FROM price INNER JOIN vehicle....etc so that i am specifiying which colums from which tables to query?? thanks This seems to be a bit of a challenge but I am creating a multiple page form and on one of the pages I have a select field. I would like the user to have the ability to select multiple options but I am using some functions to move the data in hidden fields from page to page. I don't think my functions are jiving with my my foreach loop cause I keep getting an invalid argument error. Thanks in advance for any help. Here is my function: function setSelected($fieldName, $fieldValue) { if(isset($_POST[$fieldName]) && $_POST[$fieldName] == $fieldValue) { echo 'selected="selected"'; } } And here is my loop: $selections = ""; if(isset($_POST["selections"])) { foreach ($_POST["selections"] as $selection) { $selections .= $selection . ", "; } } Hi guys, I have a feeling the answer to this will be something incredibly simple I will be amazed I have failed to overlook but lets see. I have a database currently storing images as BLOB, it appears to be holding them fine, my upload page works fine to put images there etc The issue is coming when trying to display the images on an alternate page. I am using the code below, and it seems to recognize the field, however it is not displaying an image, it is displaying code. I have a feeling I need to add something to my headers to allow the page to show the images, but am not 100% sure. If someone could let me know what I am missing it would be great. Thanks in advance. Code: [Select] <? include "config.php"; $query = mysql_query("Select * FROM app_images WHERE image_month='test' ") or die(mysql_error()); while ($row = mysql_fetch_array($query)) { echo " " .$row['image']. " <br /><br />";} ?> Hi all, I was wondering if it was possible and not too messy to have a single form page (html) and have it post to 2 or more PHP files? Surely this is something that is desirable and accomplished at some point, right? Thanks. Richard Hi Guys, I have a HTML form which posts to a PHP mail script page. This data then emails to the company email address. I have two file attachments on my form: CV and Photo ID How do I integrate my php mail script to upload and then email these TWO files as TWO attachements on the email? $fileatt_cv $fileatt_id I have tried a few methods that I found on Google but they dont work Code: [Select] <?php // Grab Data from Form if(isset($_POST['submit'])) { // Personal Information $surname = mysql_real_escape_string($_POST['surname']); $firstname = mysql_real_escape_string($_POST['firstname']); $telephone = mysql_real_escape_string($_POST['telephone']); $mobile = mysql_real_escape_string($_POST['mobile']); $email = mysql_real_escape_string($_POST['email']); $address = mysql_real_escape_string($_POST['address']); $postcodep1 = mysql_real_escape_string($_POST['postcodep1']); $postcodep2 = mysql_real_escape_string($_POST['postcodep2']); $dob_dd = mysql_real_escape_string($_POST['dob_dd']); $dob_mm = mysql_real_escape_string($_POST['dob_mm']); $dob_yyyy = mysql_real_escape_string($_POST['dob_yyyy']); // Next of Kin $nextkinname = mysql_real_escape_string($_POST['nextkinname']); $nextkintel = mysql_real_escape_string($_POST['nextkintel']); // Availability $days_mon = mysql_real_escape_string($_POST['days_mon']); $days_tue = mysql_real_escape_string($_POST['days_tue']); $days_wed = mysql_real_escape_string($_POST['days_wed']); $days_thu = mysql_real_escape_string($_POST['days_thu']); $days_fri = mysql_real_escape_string($_POST['days_fri']); $days_sat = mysql_real_escape_string($_POST['days_sat']); $days_sun = mysql_real_escape_string($_POST['days_sun']); $availability_am = mysql_real_escape_string($_POST['availability_am']); $availability_pm = mysql_real_escape_string($_POST['availability_pm']); $availability_allday = mysql_real_escape_string($_POST['availability_allday']); $availability_requirements = mysql_real_escape_string($_POST['availability_requirements']); // Experience $experience = mysql_real_escape_string($_POST['experience']); // File Attachments $fileatt_cv = mysql_real_escape_string($_POST['fileatt_cv']); $fileatt_id = mysql_real_escape_string($_POST['fileatt_id']); // Rates $rate = mysql_real_escape_string($_POST['rate']); $rate_specific = mysql_real_escape_string($_POST['rate_specific']); // Employer Ref $employrefname = mysql_real_escape_string($_POST['employrefname']); $employrefcomp = mysql_real_escape_string($_POST['employrefcomp']); $employreftel = mysql_real_escape_string($_POST['employreftel']); $employrefadd = mysql_real_escape_string($_POST['employrefadd']); // Personal Ref $persrefname = mysql_real_escape_string($_POST['persrefname']); $persreftel = mysql_real_escape_string($_POST['persreftel']); $persrefadd = mysql_real_escape_string($_POST['persrefadd']); // Extra Information $allergy = mysql_real_escape_string($_POST['allergy']); $allergy_details = mysql_real_escape_string($_POST['allergy_details']); $drive = mysql_real_escape_string($_POST['drive']); $car = mysql_real_escape_string($_POST['car']); $criminal = mysql_real_escape_string($_POST['criminal']); $criminal_details = mysql_real_escape_string($_POST['criminal_details']); $howlongworkuk = mysql_real_escape_string($_POST['howlongworkuk']); $police_check = mysql_real_escape_string($_POST['police_check']); $right2work = mysql_real_escape_string($_POST['right2work']); $right2workna = mysql_real_escape_string($_POST['right2workna']); // Email Options $subject = "Test Company - Job Application"; $to = "test@test.com"; $mailheader = "From: $email" . "\r\n"; $mailheader .= 'MIME-Version: 1.0' . "\r\n"; $mailheader .= 'Content-type: text/html; charset=iso-8859-1' . "\r\n"; // Applicants copy $mailheader .= "BCc: $email" . "\r\n"; // Message Content $body .= 'Message'; // End of Email Content > Display Message echo "Thank you. Your application was submitted to us successly. We review all applications carefully and we may contact you shortly."; // Attempt to Send Email mail($to, $subject, $body, $mailheader); } else { echo "Application Failed. Unfortunatley, there was a problem with your application and it was not submitted. Please try again later or alternativley please contact us."; } ?> Thanks in advanced. Hi, I'm having a bit of a problem sharing some variables I have across a few files. My first file (index.php) calls an ajax request for (display.php) and sends a few variables to it. All fine so far. display.php then does its thing and displays the content on index.php as it should. Now in display.php I need a variable to be passed back to index.php for use in a menu. I've tried setting a session variable in display.php but unfortunately this doesn't seem to work. I also can't use get or post as I don't want to refresh the page. Really scratching my head over this one! Edd I need to be able to upload multiple files with the use of one form. Right now I have support for one file and it works great. I am stuck on what route I should take for times sake and reliability and functionality. Can I run each file on its own through the PHP script to upload the file; I would have to create a loop to run through the script as many times as there are files. OR Do I create new functionality and add the files through the use of an array? This is where I am getting the ARRAY idea: http://www.phpeasystep.com/phptu/2.html This is the PHP code that is submitting the image and uploading to file system. This is what I would use to loop through multiple files if I take the loop method. <? header("location: /classifieds/index.php"); echo '<html><center>'; //first lets upload any files that were selected// $date = date("m/d/y",time()); //check that we have a file if((!empty($_FILES["uploaded_file"])) && ($_FILES['uploaded_file']['error'] == 0)) { //Check if the file is JPEG image and it's size is less than 350Kb $filename = basename($_FILES['uploaded_file']['name']); $ext = substr($filename, strrpos($filename, '.') + 1); if (($ext == "jpg") && ($_FILES["uploaded_file"]["type"] == "image/jpeg") && ($_FILES["uploaded_file"]["size"] < 2500000)) { //Determine the path to which we want to save this file $newname = dirname(__FILE__).'/uploads/'.$filename; //Check if the file with the same name is already exists on the server if (!file_exists($newname)) { //Attempt to move the uploaded file to it's new place if ((move_uploaded_file($_FILES['uploaded_file']['tmp_name'],$newname))) { //strip off file path for $newname variable so path is not accessible via html// $tempnewname = explode('/', $newname); echo $tempnewname; $newname=$tempnewname[9].'/'.$tempnewname[10]; echo "It's done! The file has been saved as: ".$filename; } else { echo "Error: A problem occurred during file upload!"; } } else { //echo "Error: File ".$_FILES["uploaded_file"]["name"]." already exists";// $timestampname = str_replace('.jpg', date('j-n-Y_g:i:s').'.jpg', (basename($_FILES['uploaded_file']['name']))); $path = dirname(__FILE__).'/uploads/'; $fullname = $path.$timestampname; //strip off file path for $newname variable so path is not accessible via html// $tempnewname = explode('/', $fullname); $newname=$tempnewname[7].'/'.$tempnewname[8]; $picname=$tempnewname[8]; ((move_uploaded_file($_FILES['uploaded_file']['tmp_name'],$newname))); } } else { echo "Error: Only .jpg images under 2.5MB are accepted for upload"; } } else { echo "Error: No file uploaded"; } ?> Thanks for hte help -Beemer Good day all. I am looking for guidence. I am using phpexcell to format an excell file. all working 100% What should i be looking to do when i want to edit and format multiple files in a directory. about 200 excell documents all the same and with same formatting? Found this code for reading, but lets say row c3:i3 i want bold and size 14 in all the excell files . . . $path = "..."; ///the folder path $theFilePath = ""; $theFileName = glob ($path . "*.xls"); //Read more than one file here for($j = 0; $j< count($theFileName); $j++) { $theFilePath = $theFileName[$j]; $excel = new Spreadsheet_Excel_Reader(); $excel->setOutputEncoding('CP1251'); $excel->setUTFEncoder('mb_convert_encoding'); error_reporting(E_ALL ^ E_NOTICE); //echo $theFileName[$j];; echo "<br />"; echo $theFilePath; echo "<br />"; $excel->read($theFilePath); . . .// Do what u want display here }
So I am tryting to create a script to upload a CSV file into a MySql DB. It has like 10K records into SQL
My Code is copy below ...
I get the following errors.
Line 16 is the $handle
line 18 is the While Statement
Error:
Warning: fopen(): Filename cannot be empty in C:\local\htdocs\ADPStorage\DemandCSV.php on line 16 Warning: fopen()expects parameter 1 to be resource, boolean given in C:\local\htdocs\ADPStorage\DemandCSV.php on line 18 I use my script for another table and it worked like a charm. Less data and less colums do. Bad Code: (good Code sample below. this one) <?php $today = date("m.d.y.h.m.s"); echo $today; $BPTD_fy = '2014'; $BPTD_updatedate = $today; $conn = mysql_connect("Localhost","root","password") or die (mysql_error()); mysql_select_db("ds_storage",$conn); if(isset($_POST['submit'])) { $file = $_FILES['file']['tmp_name']; $handle = fopen($file, "r"); while(($fileop = fgetcsv($handle, 100000, ",")) !==FALSE) { $BPTD_fy = $fileop[0]; $BPTD_Status = $fileop[1]; $BPTD_Classification = $fileop[2]; $BPTD_ProcureCat = $fileop[3]; $BPTD_Product = $fileop[4]; $BPTD_Project = $fileop[5]; $BPTD_DSCategory = $fileop[6]; $BPTD_Calculated = $fileop[7]; $BPTD_CapacityType = $fileop[8]; $BPTD_Amount = $fileop[9]; $BPTD_Jul = $fileop[10]; $BPTD_Aug = $fileop[11]; $BPTD_Sep = $fileop[12]; $BPTD_Oct = $fileop[13]; $BPTD_Nov = $fileop[14]; $BPTD_Dec = $fileop[15]; $BPTD_Jan = $fileop[16]; $BPTD_Feb = $fileop[17]; $BPTD_Mar = $fileop[18]; $BPTD_Apr = $fileop[19]; $BPTD_May = $fileop[20]; $BPTD_Jun = $fileop[21]; $BPTD_Location = $fileop[22]; $BPTD_Env = $fileop[23]; $BPTD_Requester = $fileop[24]; $BPTD_ServiceArea = $fileop[25]; $BPTD_ServiceGroup = $fileop[26]; $BPTD_DepHead = $fileop[27]; $BPTD_Recgroup = $fileop[28]; $BPTD_RecOwner = $fileop[29]; $BPTD_Entrydate = $fileop[30]; $BPTD_updatedate = $fileop[31]; $sql = mysql_query("INSERT INTO inv_bpt_demand (Status, Classification, ProcureCat, Product, Project, DSCategory, Calculated, CapacityType, Amount, Jul, Aug, Sep, Oct, Nov, Dec, Jan, Feb, Mar, Apr, May, Jun, Location, Env, Requester, ServiceArea, ServiceGroup, DepHead, Recgroup, RecOwner, Entrydate, updatedate) VALUES ('$BPTD_Status', '$BPTD_Classification', '$BPTD_ProcureCat', '$BPTD_Product', '$BPTD_Project', '$BPTD_DSCategory', '$BPTD_Calculated', '$BPTD_CapacityType', '$BPTD_Amount', '$BPTD_Jul', '$BPTD_Aug', '$BPTD_Sep', '$BPTD_Oct', '$BPTD_Nov', '$BPTD_Dec', '$BPTD_Jan', '$BPTD_Feb', '$BPTD_Mar', '$BPTD_Apr','$BPTD_May', '$BPTD_Jun','$BPTD_Location', '$BPTD_Env','$BPTD_Requester', '$BPTD_ServiceArea', '$BPTD_ServiceGroup','$BPTD_DepHead', '$BPTD_Recgroup','$BPTD_RecOwner','$BPTD_Entrydate','$BPTD_updatedate')"); if($sql) { echo 'Data Uploaded Successfully'; } } } ?> <!DOCTYPE html> <html lang="en"> <head> <meta charset="utf-8"> <title>BPT Demand CSV</title> <link rel="stylesheet" type="text/css" href="file:///C|/local/htdocs/style/style.css" /> <script type="text/javascript" src="//ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js"></script> </head> <body> <div id="mainWrapper"> <form method="post" action="https://localhost/Storage/DemandCSV.php" enctype="multipart/form-data"> <input type="file" name="file" /> <br /> <input type="submit" name="submit" value="Submit" /> </form> </div><!--end mainWrapper--> </body> </html>Similar Working code (good) <?php $conn = mysql_connect("Localhost","root","password") or die (mysql_error()); mysql_select_db("ds_storage",$conn); if(isset($_POST['submit'])) { $file = $_FILES['file']['tmp_name']; $handle = fopen($file, "r"); while(($fileop = fgetcsv($handle,1000,",")) !==FALSE) { $PC_Num = $fileop[0]; $PC_Name = $fileop[1]; $PC_BPTNUM = $fileop[2]; $PC_busclass = $fileop[3]; $PC_Note = $fileop[4]; $PC_Acro = $fileop[5]; $PC_type = $fileop[6]; ///echo $fileop[1]; $sql = mysql_query("INSERT INTO inv_names (PC_Num, PC_Name, PC_BPTNUM, PC_busclass, PC_Note, PC_Acro, PC_type) VALUES ('$PC_Num', '$PC_Name', '$PC_BPTNUM', '$PC_busclass', '$PC_Note', '$PC_Acro', '$PC_type')"); if($sql) { echo 'Data Uploaded Successfully'; } } } ?> <!DOCTYPE html> <html lang="en"> <head> <meta charset="utf-8"> <title>Upload CSV</title> <link rel="stylesheet" type="text/css" href="file:///C|/local/htdocs/style/style.css" /> <script type="text/javascript" src="//ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js"></script> </head> <body> <div id="mainWrapper"> <form method="post" action="https://localhost/Storage/Storage_CSV.php" enctype="multipart/form-data"> <input type="file" name="file" /> <br /> <input type="submit" name="submit" value="Submit" /> </form> </div><!--end mainWrapper--> </body> </html>Please help and thx in advance ~J I have this code and its downloading file nicely. But I want to show a progress bar while downloading file from external server. My existing code shows progress bar but its not effective (ex. if i try to download two media file, one video and another audio, and video size is larger than audio size the audio finishes first and the progress bar shows 100% also suddenly it drops to 50% as the video is still downloading ). I mean it actually shows two progress and I need one. If I could get average percentage value of two progress that would be better. Any suggestion regarding this will be greatly appreciated. <?php set_time_limit ( 0 ); function define_progress_callback($i) { global $conn; curl_setopt($conn[$i], CURLOPT_PROGRESSFUNCTION, function ($resource,$download_size, $downloaded, $upload_size, $uploaded) { if($download_size > 0) $progress = round($downloaded / $download_size * 100); echo '<script language="javascript">$(".loader").loader("setProgress", '.$progress.');</script>'; echo str_pad("",1024," "); flush(); usleep(20000); }); } $urls = array("http://example.com/file.mp3", "http:/example.com/file.mp4"); $save_to='./tmp/'; $conn = array(); $fp = array(); $mh = curl_multi_init(); foreach ($urls as $i => $url) { $g = $save_to . basename($url); $conn[$i]=curl_init($url); $fp[$i]=fopen ($g, "wb"); curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, FALSE); // No certificate curl_setopt($ch, CURLOPT_FOLLOWLOCATION, TRUE); curl_setopt ($conn[$i], CURLOPT_FILE, $fp[$i]); curl_setopt ($conn[$i], CURLOPT_HEADER ,0); curl_setopt($conn[$i],CURLOPT_CONNECTTIMEOUT,60); curl_setopt ($conn[$i], CURLOPT_MAXCONNECTS, 10); curl_setopt($conn[$i], CURLOPT_NOPROGRESS, false); define_progress_callback($i); curl_multi_add_handle ($mh,$conn[$i]); } do { $n=curl_multi_exec($mh,$active); } while ($active); foreach ($urls as $i => $url) { curl_multi_remove_handle($mh,$conn[$i]); curl_close($conn[$i]); fclose($fp[$i]); } curl_multi_close($mh); ?> Edited by requinix, 18 January 2015 - 08:16 AM. no code tags meant auto-embedding of mp3 hello! in my header.php file i have the following line of code: Code: [Select] <link rel="stylesheet" href="<?php echo $pageCSS; ?>"> in the document proper, i have the following at the top of the page: Code: [Select] <?php $pageCSS="_css/compare.css"; ?> this works as expected and it's clean and neat. what i want to know is how i can adapt this to pass MULTIPLE JavaScript files through it. would it be best to pass an array of files and then step through the array? would be nice to be able to pass a simple comma-delimited list. any help would be appreciated. WR! Good day.
I have just written my first php phpexcell file importing into mysql without errors. now my next step is to try and read multiple excell files in a directory " files are same format" and import into mysql.
Heres my code so far.
<?php $db_host = "localhost";$db_user = "root";$db_pass = "";$db_name ="kk";$db_table = "test"; require '/Classes/PHPExcel.php'; require_once '/Classes/PHPExcel/IOFactory.php'; $objPHPExcel = PHPExcel_IOFactory::load('Amersfoort_WR.xlsx'); foreach ($objPHPExcel->getWorksheetIterator() as $worksheet) { $worksheetTitle = $worksheet->getTitle(); $highestRow = $worksheet->getHighestRow(); // e.g. 10 $highestColumn = $worksheet->getHighestColumn(); // e.g 'F' $highestColumnIndex = PHPExcel_Cell::columnIndexFromString($highestColumn); $nrColumns = ord($highestColumn) - 64; echo "File ".$worksheetTitle." has "; echo $nrColumns . ' columns'; echo ' y ' . $highestRow . ' rows.'; echo "$cellValue"; $link = mysql_connect($db_host,$db_user,$db_pass); if(!$link) die ('Could not connect to database: '.mysql_error()); mysql_select_db($db_name,$link); for ($row = 2; $row <= $highestRow; ++ $row) { $val=array(); for ($col = 0; $col < $highestColumnIndex; ++ $col) { $cell = $worksheet->getCellByColumnAndRow($col, $row); $val[] = $cell->getValue(); } $sql = "insert into test (F1, F2, F3, F4) values('".$val['0']."', '".$val['1']."', '".$val['2']."','".$val['3']."')"; mysql_query($sql); } } mysql_close($link); ?> I am trying to convert 6 files into a single 1 php file. I have attached the original files. I need help because I don't know where I am going wrong. this what I have done so far : <?php session_start(); if ($_SESSION['ON'] =="FALSE" || $_SESSION['ON']==null) { header( 'Location: index.php?error=invalid-login' ); session_unset(); session_destroy(); exit(); } ?> <html><head><meta http-equiv="content-type" content="text/html; charset=iso-8859-1"> <title>LOGIN WEB SESSION</title> <link rel="stylesheet" type="text/css" href="loginsession.css" /> </head> <body> <?php // If the step is one, show the correct form // if ($step == 0) { echo '<form action="index.php?step=2" method="post"> <table> <tr><td width="100">Username:</td><td width="200"><input type="text" name="username"></td></tr> <tr><td width="100">Password:</td><td width="200"><input type="password" name="password"></td></tr> <tr><td colspan="2" align="center"><input type="submit" value="Login"></td></tr> </table> </form>'; } else if ($step == 1) { // Create the step 2 section of the page // function clean($data) { $data = trim($data); $data = stripslashes($data); $data = htmlspecialchars($data); return $data; } $user = clean($_POST['username']); $pass = clean($_POST['password']); if ($user == "webdeveloper" && $pass == "master") { session_start(); $_SESSION['username'] = $user; $_SESSION['password'] = $pass; $_SESSION['ON']="TRUE"; $lifetime=600; setcookie(session_name(),session_id(),time()+$lifetime); header( 'Location: index.php?step=2' ) ; exit(); } else { header( 'Location: index.php' ); session_destroy(); exit(); } } else if ($step == 2) <div>LOGIN WELCOME</div> <div> HERE IS YOUR USER DATA:<br /> <label class="data">username:'; <?php echo $_SESSION['username'] ?> <br> password: <?php echo $_SESSION['password'] ?> <br></label> HERE IS YOUR SESSION DATA:<br /> <label class="data"> <?php echo (session_name().": ".session_id()) ?><br> <?php echo ("SESSION DATA: ".session_encode() )?> </label> </div>index.php?step=3">Logoff</a></div> } else if ($step == 3) { // Create the step 4 section of the page // header( 'Location: index.php' ); session_start(); session_unset(); session_destroy(); exit(); } ?> </body> </html> Hi guys i am kinda stuck at a part where i want a download button to prompt out two download windows in a click. Currently i am able to prompt out one download window only. I have tried putting another header line of Content Disposition but it doesn't work..i will appreciate if you guys can help me out, thanks! The desired scenario will be WinSCP.exe download prompt will appear first, follow by auditgroup.bat $file1 = "WinSCP.exe"; $file = "auditgroup.bat"; //Set headers header("Cache-Control: private"); header("Expires: 0"); header("Pragma: cache"); header("Content-Description: File Transfer"); header("Content-Disposition: attachment; filename=$file"); header("Content-Type: application/octet-stream"); header("Content-Transfer-Encoding: ASCII"); //Read the file from disk readfile($file); Hey I have this code which works fine, it echos the file names from a directory into a dropdown box how can I change it to include more then one directory <?php $dirname = "../images/staff"; $dir = opendir($dirname); echo '<select name="file2">'; echo '<option value="">none</option>'; while(false != ($file = readdir($dir))) { if(($file != ".") and ($file != "..")) { echo "<option value=".$file.">$file</option>"; } } echo '</select>'; ?> I tried this but it didnt work any help <?php $dirname = "../images/staff"; $dirname .= "../images/boarddirectors"; $dir = opendir($dirname); echo '<select name="file2">'; echo '<option value="">none</option>'; while(false != ($file = readdir($dir))) { if(($file != ".") and ($file != "..")) { echo "<option value=".$file.">$file</option>"; } } echo '</select>'; ?> Hi guys, i have an array of data, with customers and their pics. something like: Quote array (customerid=>customerpic,...........); something like Quote 123412=>'https://mylink.com/mypic343545.tiff' 433453=>'https://mylink.com/mypic3434345.tiff' my goal is to: 1. go through the array and download all the pics, with names like customerid.tiff 2. when done renaming, make a zip file ON-THE-FLY 3. download the zip file to my PC. i know i can use file_put_contents and things like that, but i am not able to really connect the dots, especially the zipping of them all on the fly.....anyone has an idea on this? This may sound like a very stupid question, but I can't find a clear answer anywhere. I'm making my first dive in OOP and all the tutorials only really show basic usage. They define a class, and show how to use it in a file. My question is how does it work to use an object throughout a program? Is it available everywhere or do I store things in sessions and start a new object on each page? For example: logging in a user. If I created an instance after confirming the credentials, would that same instance be available for use in say index.php, or would I just pass a session over and create a new instance on each page? Again, sorry if this seems dumb to some people. Hi there, I have a form submitting to a mysql database. It was requested that I put a multiple file upload option on it. So I added the fields to the form and the database and added the upload script to the form processing file (and of course created the folder on the server with proper permissions to upload to). It should upload the file(s) to the folder on the server and insert the filename into the database. I keep getting: HTTP Error 500 (Internal Server Error): An unexpected condition was encountered while the server was attempting to fulfill the request. This leads me to believe the upload script isn't working properly. If someone could take a look at it I would be a very happy guy. This is the upload script: (insert.php) Code: [Select] <?php $con = mysql_connect("server","user","pass"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("db", $con); $dateSubmitted = date("Y-m-d"); $target = "attachments/"; $target = $target . basename( $_FILES['doc1']['name']); $target = $target . basename( $_FILES['doc2']['name']); $target = $target . basename( $_FILES['doc3']['name']); $target = $target . basename( $_FILES['doc4']['name']); $target = $target . basename( $_FILES['doc5']['name']); $sql="INSERT INTO investments (active, project, inv_amount, account_type, prefix, first_name, last_name, address1, address2, city, province, postal_code, country, phone, email, referral_fee, ref_agent, ship_name, ship_address, ship_city, ship_province, ship_postal, ship_country, notes, dateSubmitted, doc1, doc2, doc3, doc4, doc5) VALUES ('$_POST[active]','$_POST[account_type]','$_POST[project]','$_POST[inv_amount]','$_POST[prefix]','$_POST[prefix]','$_POST[first_name]','$_POST[last_name]','$_POST[address1]', '$_POST[address2]','$_POST[city]','$_POST[province]','$_POST[postal_code]','$_POST[country]','$_POST[phone]','$_POST[email]','$_POST[referral_fee]','$_POST[ref_agent]','$_POST[ship_name]','$_POST[ship_address]','$_POST[ship_city]','$_POST[ship_province]','$_POST[ship_postal]','$_POST[ship_country]','$_POST[notes]','$_POST[dateSubmitted]',$_FILES['doc1']['name'],$_FILES['doc2']['name'],$_FILES['doc3']['name'],$_FILES['doc4']['name'],$_FILES['doc5']['name'])"; //Writes the photo to the server if(move_uploaded_file($_FILES['doc1']['tmp_name'], $target)) if(move_uploaded_file($_FILES['doc2']['tmp_name'], $target)) if(move_uploaded_file($_FILES['doc3']['tmp_name'], $target)) if(move_uploaded_file($_FILES['doc4']['tmp_name'], $target)) if(move_uploaded_file($_FILES['doc5']['tmp_name'], $target)) { //Tells you if its all ok echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded, and your information has been added to the directory"; } else { //Gives and error if its not echo "Sorry, there was a problem uploading your file."; } if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } //echo "1 record added"; header("Location: ../forms.php"); mysql_close($con) ?> Thanks in advance. JE |