PHP - Opendir Function And Website...

I'm writing a PHP script to pull information from another website which I don't own. That website uses javascript for pagination, splitting data across 3 pages. They also have a function to list all their data on one page but it requires clicking the link on the page which runs a javascript AJAX call. I want to pull all that data with PHP but how do I emulate the Javascript AJAX call in my code so I can get all that data instead of just the first page? Even if I could just call that function and then parse the information it returns to me. Thanks.

I get this error on my homepage  :
Warning: implode() [function.implode]: Invalid arguments passed in /home/shqip1/peqini.com/wp-content/themes/sportpress/functions/wpzoom-widgets.php on line 1469

This is the code to modify

http://pastebin.com/RiBsyG3c



Thanks

I'm trying to make a League of Legends (a video game) community website, both as a personal project and for practice.
Now the game has a lot of champions, each of whom have 5 unique abilities. Now, I thought about manually inputting all the details about each champion into a MySQL database, but that would long and tedious, and I don't really have the time for it now. Also, the game patches very oftern (like, once every 2 weeks) which changes many of the stats, etc. of the champion, and it is not possible for me to keep manually updating these every time there is a patch.

Fortunately, there is a League of Legends Wiki which has all the data I need in their specific champion pages, which they keep updated per patch. So I was wondering if there was any way to get the data from the divs in the wiki, and have it display on my site. What I want to do in my website is that whenever someone types a champion's name (in a post or whatever), I want it to display a hover-over dialog with some of the champions details. And a lot of other features such as that.

In plain English I need a way to :
> Tell PHP to go to the wiki's source code on a specific page
> Find a specific div container
> Get X data from there
> Pass X data into a function to display the hover-over

I think this way, I would not have to maintain a database as I can leech off the wiki's data.
I have not coded anything like this before, so I would like a few pointers as to how to achieve this. Any help will be appreciated!

I tried searching on google but couldn't find any relevant information, please redirect me to relevant source or help me with the code.

I want to pass a domain name in text field which will be scanned and then the script will display entire site map.

Not external links or links on a page. Sorry it is not easy for me to explain.

Eg. if i pass abc.com

Script will display

abc.com/12/adn.php
abc.com/asd/asd/
etc

Whatever their url format is.

All the links on that domain.

hello
My database is in a same server with seperate domain name , then I want to insert from website1 mysql data on website2 mysql data.
can anyone help me?

Is it possible to download files from a website to my online websites root directory? reason I'm asking is because I have been downloading large video files to my computer which take about 20 minutes!! Then I use FTP to upload them to my site but it takes about 2-3 hours per video!! I was looking for a faster way! All help would be great!

Hello all, I have some piece of code that is nested like this


$variable = 'This is a global argument';
function parentFunction($variable) {
function childFunction() {
echo 'Argument of the parent function is '.$GLOBALS['variable'];
}
childFunction();
}
parentFunction(5);


What I want to know is - Is there a way to access a variable from the parent function without passing arguments to the child function? (Something like how classes have parent::?). I don't want to use $GLOBALS because it might cause some variable collision, and I didn't want to pass arguments because incase I decide to change the arguments in the parent function I'd have to do it in the child function aswell. From my searching around in the Internet it seems like this is not possible, but if theres a slight chance that there might be something out there, i'm willing to give it a shot .

Thanks in advance

I have this function completely written in my class file that I am working on.  The point to this function is to be able to check the login of a user or administrator for either of the control panels associated with my site.

It will check the session intime as well as the page / module referenced.  Once it passes all those checks, it will check and ensure the emailaddress/password stored in the current session still holds true and the account is still active...  if the account is still active it will update the lastActivity as well as update all of the session variables with what is currently in the database.

What I am looking for is basically a look at the function, see if it looks good..  If there is any part to it that could create security holes for the site just off the login function itself...

Usage: $q->validUser($_SESSION['user'], $_mod);

<?php
 function validUser($sess, $p) {

if ($sess['inTime'] == '' && $p != 'login' && $p != 'logout') {
session_destroy();
$login = '0';
$_int = '';
return $login;
} else if ($sess['inTime'] < time()-3600 && $p != 'login') {
$sess['inTime'] = '';
session_destroy();
$this->check_login($sess, $p);
} else {
$this->user = $sess['emailAddress'];
$this->pass = $sess['password'];

$login = $this->sql_query("SELECT * FROM users WHERE emailAddress = '".$this->user."' AND password = '".$this->pass."' 
   AND status = '1' LIMIT '1'");
if ($login = $this->sql_numrows($login) < 1) {
$sess['inTime'] == '';
session_destroy();
$login = '0';
} else {
// logged in, lets update the database for last_activity AND the session.

$this->sql_query("UDATE users SET lastActivity = '".now()."' WHERE
  emailAddress = '".$this->user."'");
$login = $this->sql_query("SELECT * FROM users WHERE emailAddress = '".$this->user."' AND password = '".$this->pass."' 
       AND status = '1' LIMIT '1'");
$login = mysql_fetch_assoc($login);
foreach ($login as $key => $value)
{ 
$sess[$key] = $value;
}
$sess['inTime'] = time();
$login = '1';
}
return $login;
}
}

?>

That is the main function, sql_query and sql_numrows is:

<?php
function sql_query($query = "", $transaction = FALSE) {
unset($this->query_result);

if ($query != "") {
$this->num_queries++;
if ($transation == BEGIN_TRANSACTION && !$this->in_transation) {
$result = mysql_query("BEGIN", $this->db_connect_id);
if (!$result) {
return false;
}
$this->in_transaction = TRUE;
}

$this->query_result = mysql_query($query, $this->db_connect_id);
} else {
if ($transaction == END_TRANSACTION && $this->in_transaction ) {
$result = mysql_query("COMMIT", $this->db_connect_id);
}
}
if ($this->query_result) {
unset($this->row[$this->query_result]);
unset($this->rowset[$this->query_result]);

if ($transaction == END_TRANSACTION && $this->in_transaction ) {
$this->in_transaction = FALSE;
if (!mysql_query("COMMIT", $this->db_connect_id)) {
mysql_query("ROLLBACK", $this->db_connect_id);
return false;
}
}
return $this->query_result;
} else {
if ($this->in_transaction ) {
mysql_query("ROLLBACK", $this->db_connect_id);
$this->in_transaction = FALSE;
}
return false;
}
}

function sql_numrows($query_id = 0) {
if(!$query_id) {
$query_id = $this->query_result;
}
return ($query_id) ? mysql_num_rows($query_id) : false;
} ?>

Any insight that can help to benefit these functions would be appreciated.

Question 1) Is the only and proper way to call a parent function "parent::function()"?  Are there other/better ways from within a child function?

Question 2) What are the deciding factors for when to make a function or attribute static?  How do you make that decision?  Assuming 5.3...

Thanks.

I need to call usort from a class function, and I'm puzzled about how to define the comparison function.

I've tried to define the comparison function in the same class, but I can't get usort to call it. I found one hint that it will work if I make the comparison function static, but I tried that, and it didn't work for me.

If I define the comparison function outside the class, it won't have access to object properties that it needs to operate.

The only solution I can think of is to define the comparison function outside the class and put the object properties it needs in globals. Is there a cleaner way to do this?

When I put this chunk of code into it's own function:


function fetch_all ($dbc, $query) {

include ('knuffix_list_func.php');

pagination_start ($dbc, $query);

$offset = $pag_array[0];

$rows_per_page = $pag_array[1];

$query = $query . " LIMIT $offset, $rows_per_page";

echo "test query: " . $query;

knuffix_list ($query, $dbc);

pagination_end ($pag_array);
}


And when I echo out the query as you can see in the example, then I notice that the variables $offset and $rows_per_page never get appended.
I set the variable $pag_array to a global inside the function pagination_start(). It usually works when I DON'T wrap a function around this chunk of code, but if I do wrap a function around everything then the global suddenly won't work anymore.

Btw, this also won't work if I wrap a function around the function DECLARATIONS.

Any ideas, how I could make it work?

I want to define a function instead of repeating query in all my php pages. I call a function by passing an $id value and from that function i have to get all the info related to that id, like name, description and uom.    I am trying to do this, but i dont know how to get these values seperately.   here is my function  

function items($item_id)
{
$details = array(); 
$result = mysql_query("select item_id, name, uom, description from items where item_id=".$item_id."") or die (mysql_error());
while($row = mysql_fetch_array($result))
{
$details[] = array((stripslashes($row['name'])), (stripslashes($row['uom'])), (stripslashes($row['description'])));
}
return $details;
}

and i call my function like this

$info = items($id);

Can somebody guide me in this    

im using a function which connects to a db called 'comments' and then inside that function i again called another function that will connect to the db 'main' to get avatars.... but as i put Code: [Select]
mysql_select_db("main") or die(mysql_error()); on the new function, the original function stops to fetch rows.

i tried to remove "mysql_select_db("main") or die(mysql_error());" and used the new function to return some text only and it worked, so i guess the connection to the db was the problem... i tried doing Code: [Select]
mysql_query("SELECT * FROM  main.avatar
INNER JOIN main.list ON main.avatar.title=main.list.id
WHERE main.avatar.page_id='$id'"); but it also didnt work

Hi all, I want to call a javascript function from a php function like this:

        public function Buscar()
        {
            $HoraInicio = $_POST['edtHoraInicio'];
            $HoraFin = $_POST['edtHoraFin'];
            $FechaInicio = $_POST['edtFec1'];
            $FechaFin = $_POST['edtFec2'];

            $FechaMax = $FechaFin." ".$HoraFin.":00";
            $FechaMin = $FechaInicio." ".$HoraInicio.":00";

            $_GET["FechaMax"] = $FechaMax;
            $_GET["FechaMin"] = $FechaMin;

            echo $FechaMin;

            echo "<script language=javascript>alert('Hi.')</script>";
           
        }

but the function Buscar never show the alert but shows the $FechaMin

I hopu u guys can help me out with this probem

Thanks,

Siddhartha

Hi I have a table class and functions I want to call in another function but can't get it working. Some help will be very welcome.

It seesm that the new table class is not working in this function if I pass the values to it, I have tested the class, it does get the post values I post to it so $_POST['id'] are being received as well as all the other $_POST's but the table class and find function is not working, it works fine if I don't put it in a function..

function edit() {
   
   if (isset($error)){ $error.="Please fix the error(s) above";}
   else {

      if ($_POST['id'] <> "") { 
                   
         $update =& new table($db, 'publisher');

         $update->find($_POST['id']);
         $update->name       = $_POST['name'];
         $update->url        = $_POST['url'];
         $update->contact    = $_POST['contact'];
         $update->address    = $_POST['address'];
         $update->phone        = $_POST['phone'];
         $update->email        = $_POST['email'];
         $update->save();

         $error = "The Publisher has been edited";   
                }
   }
  }