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PHP - Migrated From Mysql 4 To 5 (now Session Access Doesn't Work)
I have a site with a members area that uses sessions. I migrated my DB from MySQL 4 to 5. Now my login page does not work. Please help.
Member Login Page: Code: [Select] <?php session_name ('name'); ini_set ('session.use_cookies', 0); session_start(); ?><!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title></title> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <link href="css/style.css" rel="stylesheet" type="text/css" /> <script type="text/javascript" src="js/swfobject/swfobject.js"></script> <script type="text/javascript"> var flashvars = {}; flashvars.xml = "config.xml"; flashvars.font = "font.swf"; var attributes = {}; attributes.wmode = "transparent"; attributes.id = "slider"; swfobject.embedSWF("cu3er.swf", "cu3er-container", "960", "400", "9", "expressInstall.swf", flashvars, attributes); </script> <link href="css/menu.css" rel="stylesheet" type="text/css" /> <style type="text/css"> #apDiv1 { position:absolute; left:592px; top:75px; width:552px; height:53px; z-index:1; } a:visited { color: #5D4580; } a:hover { color: #FFF; } a:active { color: #5D4580; } </style> </head> <body> <div class="main"> <div class="blok_header"> <div class="header"> <div class="rss"><strong>P</strong></div> <div class="clr"></div> <div class="logo"><a href="index.html"><img src="images/logo.jpg" width="211" height="88" border="0" alt="" class="one" /></a></div> <div class="menu"> <ul id="css3menu"> <li class="topfirst"><a href="index.html" title="Home">Home</a></li> <li><a href="#" title=""><span>Omega Psi Phi</span></a> <ul> <li><a href="founders.html" title="Fraternity Founders">Fraternity Founders</a></li> <li><a href="omegahistory.html" title="Fraternity History">Fraternity History</a></li> <li><a href="programs.html" title="Mandated Programs">Mandated Programs</a></li> <li><a href="links.html" title="Links">Links</a></li> </ul> </li> <li><a href="#" title="Phi Gamma Chapter"><span>Phi Gamma Chapter</span></a> <ul> <li><a href="history.html" title="Phi Gamma History">Phi Gamma History</a></li> <li><a href="lineage.html" title="Phi Gamma Lineage">Phi Gamma Lineage</a></li> <li><a href="dedication.html" title="Dedication">Dedication</a></li> <li><a href="calendar.html" title="Calendar">Calendar</a></li> <li><a href="photogallery.html" title="Photo Gallery">Photo Gallery</a></li> <li><a href="members/login.php" title="Member Login">Member Login</a></li> <li><a href="roster.html" title="Chapter Roster">Chapter Roster</a></li> </ul> </li> <li><a href="members/login.php" title="Member Login">Member Login</a></li> <li class="toplast"><a href="contact.html" title="Contact Info.">Contact Info.</a></li> </ul> </div> </div> <div class="clr"></div> <div class="body"> <div class="body_bg"> <h2>Member's Only </h2> <?php if ($_SESSION['membername'] != null) { // print "<META HTTP-EQUIV='Refresh' content='0;URL=updatemember.php'>"; echo "You are already logged in. Please wait to be redirected to the members page, or <a href=\"members.php\">click here</a> if you are not automatically redirected. User name for the session is ".$_SESSION['username'].", the member name is ".$_SESSION['membername']; print "<META HTTP-EQUIV='Refresh' content='5;URL=members.php'>"; //header("Location: members.php"); //exit; } else { ?> <form name="admin" method="post" action="userlogon.php"> <table width="891" border="0" cellspacing="5" cellpadding="5"> <tr> <td height="80" colspan="2" align="left"><p>Please enter you username and password. Don't remember your password, <u><strong><a href="password.php">click here</a></strong></u><strong><a href="password.php"></a></strong>.</td> <td width="360" rowspan="5" align="center" valign="middle"><img src="images/login_image.jpg" width="239" height="314" /></td> </tr> <tr> <td width="257" height="38" align="right"><p><strong>Username:</strong></td> <td width="224" align="left"><input type="text" name="username"></td> </tr> <tr> <td height="38" align="right"><p><strong>Password:</strong></td> <td align="left"><input type="password" name="password"></td> </tr> <tr> <td height="34"> </td> <td align="left"><input type="submit" class="yellowbutton" name="submit" value="Sign In"></td> </tr> <tr> <td colspan="2"><p>To register for a username and password with Phi Gamma, please <u><strong><a href="register.php">click here</a></strong></u><strong><a href="password.php"></a></strong>.</td> </tr> </table> </form> <?php } ?> <p> </p> <div class="clr"></div> </div> <div class="clr"></div> </div> </div> <div class="footer"> <div class="footer_resize"> <p class="center"> <a href="index.html">Home</a> | <a href="contact.html">Contact</a> </p> <div class="clr"></div> </div> <div class="clr"></div> </div> </body> </html> After the credentials are entered the user is returned back to the login page and NOT the member's page. This is the userlogon.php page: Code: [Select] <?php $link = mysql_connect('localhost:/tmp/mysql5.sock', 'dbuser', 'dbpw'); if (!$link) { die('Could not connect: ' . mysql_error()); } //mysql_close($link); if (!mysql_select_db('db_name', $link)) { echo 'Could not select database'; exit; } $username = $HTTP_POST_VARS["username"]; $password = $HTTP_POST_VARS["password"]; $member_id = ''; $role = ''; $firstname = ''; // Formulate Query // This is the best way to perform a SQL query // For more examples, see mysql_real_escape_string() $query = sprintf("SELECT users.member_id, users.username, users.password, users.role, FROM users join members on users.member_id = members.member_id WHERE users.username ='%s' AND users.password='%s'", mysql_real_escape_string($username), mysql_real_escape_string($password)); // Perform Query $result = mysql_query($query); // Check result // This shows the actual query sent to MySQL, and the error. Useful for debugging. if (!$result) { $message = 'Invalid query: ' . mysql_error() . "\n"; $message .= 'Whole query: ' . $query; die($message); } // Use result // Attempting to print $result won't allow access to information in the resource // One of the mysql result functions must be used // See also mysql_result(), mysql_fetch_array(), mysql_fetch_row(), etc. while ($row = mysql_fetch_assoc($result)) { $member_id = $row['member_id']; $username = $row['username']; $role = $row['role']; } if ($member_id != ''){ session_start(); $_SESSION['membername'] = $username; $_SESSION['username'] = $username; $_SESSION['memberid'] = $member_id; $_SESSION['role'] = $role; print "<META HTTP-EQUIV='Refresh' content='0;URL=members.php'>"; } else { print "<META HTTP-EQUIV='Refresh' content='0;URL=memberlogin.php'>"; } // Free the resources associated with the result set // This is done automatically at the end of the script mysql_free_result($result); ?> It worked fine before the migration??? Anyone know where the problem is? Similar TutorialsI am using this PHP code with a MySQL query. PHP parses the PHP fine, but the MySQL query is not having any effect on the database. Can anyone see an error in my code? I can't. $query = "UPDATE `products` set `id` = '".$_POST['id']."' where `id` = '".$_POST['id']."'"; MOD EDIT: Changed PHP manual link tags to [php] . . . [/php] tags.
Hi, this query runs fine when I run it from PHPMyAdmin: UPDATE `tran_term_taxonomy` SET `description` = (SELECT keyword from `good_keywords` ORDER BY RAND() LIMIT 1,1) WHERE `tran_term_taxonomy`.`taxonomy` = 'post_tag' AND `tran_term_taxonomy`.`description` = "" LIMIT 1 However, when I run the same query in a PHP file on my server, the page doesn't load at all. The message I get is: www.somesite.com is currently unable to handle this request. HTTP ERROR 500. This is my PHP code:
<?php
include("/database/connection/path/db_connect.php");
$result4 = mysqli_query($GLOBALS["___mysqli_ston"], "UPDATE `tran_term_taxonomy` SET `description` = (SELECT keyword from `good_keywords` ORDER BY RAND() LIMIT 1,1) WHERE `tran_term_taxonomy`.`taxonomy` = 'post_tag' AND `tran_term_taxonomy`.`description` = "" LIMIT 1");
echo $result4;
?>
So how do I make this query work please? Thanks for your guidance. I have created a registration page to access my website. After the user registrate himself should appear an alert saying that the registration was OK and a redirect to main.php page... however for some reason if I create an insert statement the alert and the redirect don't appear... If I remove the insert the alert and the redirect works... why? This is part of the code of my 3 files: registration.php (ajax call) $('#submit').click(function() {var username2 = $('#uname2').val(); var password2 = $('#psw2').val(); $.ajax({ url: 'ajax/response.php', type: 'GET', data: {username2 : username2, password2: password2}, success: function(data) { if(data === 'correct') { alert("Username and Password have been created!"); //don' work with the insert location.replace("main.php"); //don' work with the insert } else { alert("Username or password are not correct... please register yourself!"); } } }); }); response.php (answer to ajax call) if(isset($_GET['username2']) && isset($_GET['password2'])) {$username2 = $_GET['username2']; $password2 = $_GET['password2']; if (checkUser($pdo, $username2) === true) { echo 'duplicate'; } else { insertUserPwd($pdo, $username2, $password2); //including this line the redirect and the alert doesn't work... the insert is OK echo 'correct'; } } data_access.php (the function works but doesn't permit alert and redirect to appear) function insertUserPwd(PDO $pdo, $usr, $pwd){ $data = [ 'id' => '', 'user' => $usr, 'password' => $pwd ]; $sql = "INSERT INTO users (id, user, password) VALUES (:id, :user, :password)"; $stmt= $pdo->prepare($sql); $stmt->execute($data); } Can someone help me to fix the code? If you also have any feedback on my code, please do tell me. I wish to improve my coding base. Basically when you fill out the register form, it will check for data, then execute the insert query. But for some reason, the query will NOT insert into the database. In the following code below, I left out the field ID. Doesn't work with it anyways, and I'm not sure it makes a difference. Code: Code: [Select] mysql_query("INSERT INTO servers (username, password, name, type, description, ip, votes, beta) VALUES ($username, $password, $name, $server_type, $description, $ip, 0, 1)"); Full code: Code: [Select] <?php include_once("includes/config.php"); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title><? $title; ?></title> <meta http-equiv="Content-Language" content="English" /> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /> <link rel="stylesheet" type="text/css" href="style.css" media="screen" /> </head> <body> <div id="wrap"> <div id="header"> <h1><? $title; ?></h1> <h2><? $description; ?></h2> </div> <? include_once("includes/navigation.php"); ?> <div id="content"> <div id="right"> <h2>Create</h2> <div id="artlicles"> <?php if(!$_SESSION['user']) { $username = mysql_real_escape_string($_POST['username']); $password = mysql_real_escape_string($_POST['password']); $name = mysql_real_escape_string($_POST['name']); $server_type = mysql_real_escape_string($_POST['type']); $description = mysql_real_escape_string($_POST['description']); if(!$username || !$password || !$server_type || !$description || !$name) { echo "Note: Descriptions allow HTML. Any abuse of this will result in an IP and account ban. No warnings!<br/>All forms are required to be filled out.<br><form action='create.php' method='POST'><table><tr><td>Username</td><td><input type='text' name='username'></td></tr><tr><td>Password</td><td><input type='password' name='password'></td></tr>"; echo "<tr><td>Sever Name</td><td><input type='text' name='name' maxlength='35'></td></tr><tr><td>Type of Server</td><td><select name='type'> <option value='Any'>Any</option> <option value='PvP'>PvP</option> <option value='Creative'>Creative</option> <option value='Survival'>Survival</option> <option value='Roleplay'>RolePlay</option> </select></td></tr> <tr><td>Description</td><td><textarea maxlength='1500' rows='18' cols='40' name='description'></textarea></td></tr>"; echo "<tr><td>Submit</td><td><input type='submit'></td></tr></table></form>"; } elseif(strlen($password) < 8) { echo "Password needs to be higher than 8 characters!"; } elseif(strlen($username) > 13) { echo "Username can't be greater than 13 characters!"; } else { $check1 = mysql_query("SELECT username,name FROM servers WHERE username = '$username' OR name = '$name' LIMIT 1"); if(mysql_num_rows($check1) < 0) { echo "Sorry, there is already an account with this username and/or server name!"; } else { $ip = $_SERVER['REMOTE_ADDR']; mysql_query("INSERT INTO servers (username, password, name, type, description, ip, votes, beta) VALUES ($username, $password, $name, $server_type, $description, $ip, 0, 1)"); echo "Server has been succesfully created!"; } } } else { echo "You are currently logged in!"; } ?> </div> </div> <div style="clear: both;"> </div> </div> <div id="footer"> <a href="http://www.templatesold.com/" target="_blank">Website Templates</a> by <a href="http://www.free-css-templates.com/" target="_blank">Free CSS Templates</a> - Site Copyright MCTop </div> </div> </body> </html>
if ($count==1){
header("Location:store.php");
}
very simple I have issolated it and it doesn't redirect maybe u can see where my mistake is
I was asked to make new thread for this, so how do I use a session or something to restrict access to a page.....like if accounttype=Admin, stay here, all others go away......do you need to see code, or can you just give me an example....... Hello I have included a simple login system into my website. When a user logs in, a session is started and he stays connected throughout the whole website until logging out again. The user logs in via his e-mailaddress and a password, which are stored in a mysql database. Now I want to add a page on which a user that is logged in, can see and edit his own information (password, cellphone number, e-mail, etc.). Or easier: instead of showing "Welcome!" showing "Welcome, John!". I thought about storing the e-mailaddress into the session, and then trying to access it to select the correct record (to edit afterwards). But so far, I haven't booked any success. I have to say that this is the first time I'm working with sessions as well, so this is very new to me. Thank you in advance for any help! Just curious how other people feel about this. I am working on an application where a lot of info is pulled from MySQL and needed on multiple pages.
Would it make more sense to...
1. Pull all data ONCE and store it in SESSION variables to use on other pages
2. Pull the data from the database on each new page that needs it
I assume the preferred method is #1, but maybe there is some downside to using SESSION variables "too much"?
Side question that's kind of related: As far as URLs, is it preferable to have data stored in them (i.e. domain.com/somepage.php?somedata=something&otherdata=thisdata) or use SESSION variables to store that data so the URLs can stay general/clean (i.e. domain.com/somepage.php)?
Both are probably loaded questions but any possible insight would be appreciated.
Thanks!
Greg
Edited by galvin, 04 November 2014 - 10:30 AM. Hi, I am struggling to find an answer here.. If for example my iframe source, file.php has a initcheck/direct access block, how can i still have access to it in an iframe? <center><iframe name="frame1" id="frame1" style="width: 100%; height: 120px; z-index: 0; " scrolling="0" src="file.php" frameborder="0"></iframe></center> //then the file.php has an initcheck and itself includes multiple other files so i cant remove the initcheck.. //header of file.php // ################################################################ defined( '_MYAPP_INITCHECK' ) or die( '' ); // ################################################################ I've joined querys because I'm making my own forums. However, when it gets to the echoin out part, it shows the category and only ONE of the sub categorys. Code: [Select] <div id="forumContainer"> <?php $lastboard = ''; $forumQ = mysql_query("SELECT f1.cat_name as catName, f1.cat_id as catID, f2.cat_id as subCatID, f2.sub_id as subID, f2.sub_name as subName, f2.sub_desc as subDesc FROM `forum_cats` as f1 LEFT JOIN `forum_sub` as f2 ON f1.cat_id = f2.cat_id GROUP BY f2.cat_id "); while($forumF = mysql_fetch_assoc($forumQ)) { if($forumF['catName'] != $lastboard) { echo '<div class="forumCat">'.$forumF['catName'].'</div>'; $lastboard = $forumF['catName']; } echo '<div class="forumSub">'.$forumF['subName'].'</div>'; } ?> </div> $Row[2] doesn't work but if I use $Row["linkcat"] than it works fine. Is there somewhere to activate in the php.ini file ? Code: [Select] // I got 9 fields to in the table tbl_link ! $Row[2] should give me a number. $Verbinding = mysql_connect($db_host, $db_user, $db_passw); mysql_select_db($db_name); $sql = "Select * from tbl_link where userid=1"; $ResultShow = mysql_query($sql); while ($Row = mysql_fetch_assoc($ResultShow)){ echo $Row[2]; } I'm trying to implement an email activation method for my registration script. For that I need the last inserted id straight off the query. This is how the part of my script looks like: // write into database $query = sprintf("INSERT INTO user (user_id, firstname, lastname, nickname, password, email, dob, doj, random, activated) VALUES (' ', '%s', '%s', '%s', '%s', '%s', '%s', now(), '$random', '0')", mysqli_real_escape_string($dbc, $firstname), mysqli_real_escape_string($dbc, $lastname), mysqli_real_escape_string($dbc, $nickname), mysqli_real_escape_string($dbc, $password), mysqli_real_escape_string($dbc, $user_email), $dob); echo $lastid = mysqli_insert_id($dbc) or die (mysqli_error($dbc)); The query itself WORKS, the data gets inserted correctly, the scripts dies right at the die of mysqli_insert_id. When I take away the "or die", then I always get printed out a 0 when trying to register, THOUGH the data entered into the registration page gets inserted correctly into the database as said. I've read on w3schools.com, that the connection ($dbc) is OPTIONAL in mysqli_insert_id($dbc), because it automatically takes the last active connection, but when I leave it empty I get an error saying that it needs at least one parameter. I must be doing something wrong, if you need more of the script let me know. Since the scripts dies at the die, I didn't post anything below, and everything above is just if statements to check the entered data. All the tables are correct and it's making the connect to the database fine it's just not working, did I write it wrong? Code: [Select] function newPm($to, $from, $title, $text){ $q = $db->query("SELECT * FROM ibf_message_topics ORDER BY mt_id DESC"); $lastMsg = $db->fetch_assoc($q); $mid = $lastMsg['mt_id'] + 1; $msgId = $lastMsg['mt_msg_id'] + 1; $db->query("INSERT INTO ibf_message_topics SET mt_id=$mid, mt_msg_id=$msgId, mt_date=". time(). ", mt_title='$title', mt_from_id=$from, mt_to_id=". $to. ", mt_vid_folder='in', mt_read=0, mt_owner_id=$to, mt_user_read=0") or die(mysql_error()); $db->query("INSERT INTO ibf_message_text SET msg_id=$msgId, msg_date=". time() .", msg_post='$text', msg_sent_to_count=1, msg_author_id=$from") or die(mysql_error()); $userq = $db->query("SELECT new_msg FROM ibf_members WHERE id = $to"); $userData = $db->fetch_assoc($userq); $msgCount = $userData['new_msg'] + 1; $db->query("UPDATE ibf_members SET new_msg=$msgCount, show_popup=1 WHERE id = $to") or die(mysql_error()); } Here's how that function is being called in the beginning of the page: Code: [Select] if($action =="banUser"){ $expire = time() + (3600000 * 24 * $_GET['duration']); $q = $db->query("SELECT * FROM ibf_message_topics ORDER BY mt_id DESC"); $lastMsg = $db->fetch_assoc($q); $mid = $lastMsg['mt_id'] + 1; $msgId = $lastMsg['mt_msg_id'] + 1; $title = "Notification"; $duration = $_GET['duration'] ." days"; if($_GET['duration'] == "1"){ $duration = "1 day"; } if($_GET['duration'] == "Forever"){ $duration = "forever"; } $temp = 0; if($expire > time()){ $temp = 1; } $body = "This automated message has been sent to notify you that your account has been banned $duration. To appeal this ban, click on Irc from the menu on the homepage and ask to speak to a moderator. If this ban is temporary, your account will be reinstated automatically at the appropriate time"; newPm($id, 3017, $title, $body); $msgCount = $_GET['msg'] + 1; $db->query("UPDATE ibf_members SET ban_level = $level, tempbanned = $temp, banned = 1, ban_expire='$expire', ban_reason='". $_GET['reason']."', ban_by='". $name."' WHERE id=$id") or die(mysql_error()); ?> <center><b>User banned!</b> (<a href="index.php?code=plyrmgmt">Back to Player Management</a>)</center> I've written a script where it counts the page impressions on my website. When a visitor lands on the page, it counts their impression and then sets a $_SESSION so that if they reload or return to the page it doesn't count it again. But the problem is it sometimes does. Does this mean that the $_SESSION isn't being set probably? That's what it seems to be. And if so, what would be the reason for that? Here's my basic code: Code: [Select] if(isset($_SESSION['userid'])){ $userid = $_SESSION['userid']; } else{ $userid = rand(1000, 10000000); $_SESSION['userid'] = $userid; } $date = date('Y-m-d'); $counters = mysql_query("SELECT * FROM counters WHERE userid='$userid' AND impressions='1' AND date='$date'") or die(mysql_error()); if(!mysql_num_rows($counters)){ mysql_query("INSERT INTO counters (userid, impressions, date) VALUES('$userid', '1', current_date)") or die(mysql_error()); } Hello, I've been working on some stuff, and get the information parsed like this: Code: [Select] Value1,Value2,Value3 0.68,4377.54,11069.02So I'm trying to explode it and insert the latest numbers into the database. I'm using: $value = explode(",", $variable); $secondsplit = explode(" ", $value[2]); mysql_query("INSERT INTO table(row) VALUES('".mysql_real_escape_string($secondsplit[1])."')"); The problem is that it has something like an enter in the database, or a space. But I can't figure out how to get rid of that problem. Does anyone know what's wrong? Regards, NLCJ Hey there, I am trying out some tag cloud code, but something is amiss, as am getting no tags displaying. Using PHP/MYSQL and JQuery. <?php //connection information $host = "localhost"; $user = "username"; $password = "pw"; $database = "DBName"; //make connection $server = mysql_connect($host, $user, $password); $connection = mysql_select_db($database, $server); //query the database $query = mysql_query("SELECT * FROM tags"); //start json object $json = "({ tags:["; //loop through and return results for ($x = 0; $x < mysql_num_rows($query); $x++) { $row = mysql_fetch_assoc($query); //continue json object $json .= "{tag:'" . $row["tag"] . "',freq:'" . $row["frequency"] . "'}"; //add comma if not last row, closing brackets if is if ($x < mysql_num_rows($query) -1) $json .= ","; else $json .= "]})"; } //return JSON with GET for JSONP callback $response = $_GET["callback"] . $json; echo $response; //close connection mysql_close($server); ?> and the JS Code: [Select] <script type="text/javascript"> $(function() { //get tag feed $.getJSON("/tagcloud.php?callback=?", function(data) { //create list for tag links $("<ul>").attr("id", "tagList").appendTo("#tagCloud"); //create tags $.each(data.tags, function(i, val) { //create item var li = $("<li>"); //create link $("<a>").text(val.tag).attr({title:"See all pages tagged with " + val.tag, href:"http://localhost/tags/" + val.tag + ".html"}).appendTo(li); //set tag size li.children().css("fontSize", (val.freq / 10 < 1) ? val.freq / 10 + 1 + "em": (val.freq / 10 > 2) ? "2em" : val.freq / 10 + "em"); //add to list li.appendTo("#tagList"); }); }); }); </script> when i turn on error reporting I get a lot of undefined index notices for tag and frequency so not sure if that is causing the problem or not. Hello all, I'm trying to clean up some user input for my database but the mysql_real_escape_string function doesn't seem to work, and neither does addslashes(). I've browsed the net and made sure I'm connected to the database before the function is called. I can't figure out what I'm doing wrong. Here's the relevant part of the code: Code: [Select] <?php mysql_connect("localhost","adminname","adminpassword") or die (mysql_error()); mysql_select_db("databasename") or die (mysql_error()); $comment=mysql_real_escape_string($_POST['commentbox']); ?> ...and then the result is put into the database along with some other data. The database entry is correct, except, when I check the database or echo the result I get the same thing that was entered into 'commentbox'. For instance, if I enter "I am very 'confused' by this" into the box, the same string will be found in the database table. No slashes, just quotes. Anyone have an idea what's wrong with this? Because it all seems simple and correct but doesn't work. Hey, $todo_upgrades_sql = "SELECT * FROM todo_upgrades WHERE time_completion >= $time"; $todo_upgrades_res = mysql_query($todo_upgrades_sql) or die (mysql_error()); results: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 1 I have something like below Code: [Select] $j = explode("-", $ROW['options']); if(array_search("src_str", $j) == false) echo '_no'; // This doesn't work Also i tried Code: [Select] $j = explode("-", $ROW['options']); if(!in_array("src_str", $j)) echo '_no'; // This also doesn't work Is this bug or am i doing something wrong? Hi, when I output this, it's same order, I want it to be: email/message/to/toLastName please see code: $testArray=array("toLastName","to","message","email"); $reversedTestArray=rsort($testArray);//rsort returns TRUE on success //$strTestArrayReversed=implode(",",$testArray); print_r($testArray); Any idea what I am doingwrong, it looks fairly straightforward. Any help much appreciated! |
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