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PHP - Syntax V Alternative Syntax?
Which of the below syntax is the better to be using?
$bal = 100; if($bal > 100) { echo "you have over 100 pounds; } else { echo "you have less than 100 pounds"; } if ($bal > 100); echo "you have over than 100"; else ; echo "you have less than 100"; endif; Similar TutorialsI have been looking at this code most of the morning and do not have a clue what is wrong with the code. I am hoping its not a stupid mistake, can someone please help me out? thank you
<title>Inputing Travel Detials</title>
<header>
<h1 align="center"> Adding Travel Detials </h1>
<body>
<p> <center><img src="cyberwarfareimage1.png" alt="Squadron logo" style="width:200px;height:200px" style="middle"></center>
<table border="1">
<tr>
<td><a href="index.php"> Home Page </a></td>
<td><a href="administratorhomepage.html">Administrator Home Page </a></td>
<td><a href="viewhomepage.html">View Home Page </a></td>
<td><a href="Inputhomepage.html">Input Home Page </a></td>
<td><a href="traveldetials.html">Enter More Travel Detials </a></td>
</table>
</p>
<?php
include "connection.php";
$Applicant_ID = $_POST["Applicant_ID"];
$Method_Of_Travel = $_POST["Method_Of_Travel"];
$Cost = $_POST["Cost"];
$ETA = $_POST["ETA"];
$Main_Gate_Advised = $_POST["Main_Gate_Advised"];
$query = ("UPDATE `int_board_applicant` SET `Method_Of_Travel`=`$Method_Of_Travel', `Cost`=`$Cost', `ETA`='$ETA', `Main_Gate_Advised`='$Main_Gate_Advised' WHERE `Applicant_ID`='$Applicant_ID'");
$result = mysqli_query($dbhandle, $query)
or die(mysqli_error($dbhandle));
if($result){ echo "Success!"; }
else{ echo "Error."; }
// successfully insert data into database, displays message "Successful".
if($query){
echo "Successful";
}
else {
echo "Data not Submitted";
}
//closing the connection
mysqli_close($dbhandle)
?>
Ok this is puzzleing. I am geting "Could not delete data: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '1' at line 1". but its is deleting the entry that needs to be removed. The "1" is the entry. Just not sure what is causing the error. I do have another delete php but I have put that on the back burning for the time being.
<?php $con = mysqli_connect("localhost","user","password","part_inventory"); // Check connection if (mysqli_connect_errno()) { printf("Connect failed: %s\n", mysqli_connect_error()); exit(); } else { $result = mysqli_query($con, "SELECT * FROM amp20 "); $amp20ptid = $_POST['amp20ptid']; // escape variables for security $amp20ptid = mysqli_real_escape_string($con, $_POST['amp20ptid']); mysqli_query($con, "DELETE FROM amp20 WHERE amp20ptid = '$amp20ptid'"); if (!mysqli_query($con, $amp20ptid)); { die('Could not delete data: ' . mysqli_error($con)); } echo "Part has been deleted to the database!!!\n"; mysqli_close($con); } ?> Hi guys
I have this code below and all works fine when submitting this online application apart from when someone types either ' # & into one of the comment fields in which it throws up the error. Have tried various fixes from across the internet but no joy. Can anyone offer suggestions?
<?php
$con = mysql_connect("localhost:3306","root","password");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db('sfapp', $con);
$sql="INSERT INTO 'sfapp' ('surname_add','forename_add','dob_add','hometele_add','mobiletele_add','homeadd_add','siblings_add','schoolname_add','headname_add','schooladd_add','schooltele_add','schoolem_add','alevel_add','personstate_add','nameprovided_add','pe_add','se_add','PredGrade_Art','PredGrade_AScience','PredGrade_BusStudies','PredGrade_Electronics','PredGrade_EnglishLang','PredGrade_EnglishLit','PredGrade_French','PredGrade_German','PredGrade_Geog','PredGrade_Graphics','PredGrade_History','PredGrade_Maths','PredGrade_SepScience','PredGrade_ProductDesign','PredGrade_Spanish','PredGrade_Other','Gender_Male','Gender_Female','Sub_EnglishLit','Sub_Maths','Sub_FurtherMaths','Sub_Biology','Sub_Chemistry','Sub_Physics','Sub_French','Sub_German','Sub_Spanish','Sub_Geography','Sub_History','Sub_RE','Sub_FineArt','Sub_Business','Sub_Computing','Sub_GlobPersp','Sub_DramaAndTheatre','Sub_PE','Sub_Dance','Sub_Politics','Sub_Psychology','Sub_Sociology','readprospect_chk','Sib_Yes','Sib_No','Current_Student_Yes','Current_Student_No','I_Understand_chk','Current_Education_chk','Local_Care_chk','Staff_Cwhls_chk','Sub_Film')
VALUES
('$_POST[surname_add]','$_POST[forename_add]','$_POST[dob_add]','$_POST[hometele_add]','$_POST[mobiletele_add]','$_POST[homeadd_add]','$_POST[siblings_add]','$_POST[schoolname_add]','$_POST[headname_add]','$_POST[schooladd_add]','$_POST[schooltele_add]','$_POST[schoolem_add]','$_POST[alevel_add]','$_POST[personstate_add]','$_POST[nameprovided_add]','$_POST[pe_add]','$_POST[se_add]','$_POST[PredGrade_Art]','$_POST[PredGrade_AScience]','$_POST[PredGrade_BusStudies]','$_POST[PredGrade_Electronics]','$_POST[PredGrade_EnglishLang]','$_POST[PredGrade_EnglishLit]','$_POST[PredGrade_French]','$_POST[PredGrade_German]','$_POST[PredGrade_Geog]','$_POST[PredGrade_Graphics]','$_POST[PredGrade_History]','$_POST[PredGrade_Maths]','$_POST[PredGrade_SepScience]','$_POST[PredGrade_ProductDesign]','$_POST[PredGrade_Spanish]','$_POST[PredGrade_Other]','$_POST[Gender_Male]','$_POST[Gender_Female]','$_POST[Sub_EnglishLit]','$_POST[Sub_Maths]','$_POST[Sub_FurtherMaths]','$_POST[Sub_Biology]','$_POST[Sub_Chemistry]','$_POST[Sub_Physics]','$_POST[Sub_French]','$_POST[Sub_German]','$_POST[Sub_Spanish]','$_POST[Sub_Geography]','$_POST[Sub_History]','$_POST[Sub_RE]','$_POST[Sub_FineArt]','$_POST[Sub_Business]','$_POST[Sub_Computing]','$_POST[Sub_GlobPersp]','$_POST[Sub_DramaAndTheatre]','$_POST[Sub_PE]','$_POST[Sub_Dance]','$_POST[Sub_Politics]','$_POST[Sub_Psychology]','$_POST[Sub_Sociology]','$_POST[readprospect_chk]','$_POST[Sib_Yes]','$_POST[Sib_No]','$_POST[Current_Student_Yes]','$_POST[Current_Student_No]','$_POST[I_Understand_chk]','$_POST[Current_Education_chk]','$_POST[Local_Care_chk]','$_POST[Staff_Cwhls_chk]','$_POST[Sub_Film]')";
if (!mysql_query($sql,$con))
{
die('Error: ' . mysql_error());
}
?>
<?php
//if "email" variable is filled out, send email
if (isset($_REQUEST['pe_add'])) {
//Email information
$admin_email = $_REQUEST['pe_add'];
$forename = $_REQUEST['forename_add'];
$email = "autoreply@testing.com";
$subject = "Application";
$desc =
"Dear $forename
Thank you for submitting your online application, we will be in touch shortly.
"
;
//send email
mail($admin_email, "$subject", "$desc", "From:" . $email);
//Email response
echo "Thank you for contacting us!";
}
//if "email" variable is not filled out, display the form
else {
?>
If you are seeing this, you need to go back and fill out the Personal Email section!
<?php
}
header("location:complete.php");
mysql_close($con)
?>
Thanks in advance.
Hi.. I create mysql syntax for query testing before i input to my php code here is my mysql code: Code: [Select] set @t = 0; set @rqty=31968; SELECT LOT_CODE as code, DATE_ENTRY, CASE WHEN @t+OUTPUT_QTY > @rqty THEN @rqty -@t ELSE OUTPUT_QTY END as qty, @t := @t + d.OUTPUT_QTY as cumulative FROM dipping d WHERE SUBSTR(LOT_CODE, 9,4) = 'P28' AND (@t < @rqty); and i attach the sample output of the above query. Now that query test is work i will input that code to my php codes. $sql = "SELECT SKUCode, Materials, Comp, Qty FROM bom WHERE SKUCode = '$SKUCode'"; $res = mysql_query($sql, $con); ($row = mysql_fetch_assoc($res)); $Materials = $row['Materials']; $Qty = $row['Qty']; $Comp = $row['Comp']; //P28 //-----Compute Req Qty and Save to table---// $ReqQty = $Qty * $POReq; // 31968 $sql = "UPDATE bom SET ReqQty = '$ReqQty' WHERE SKUCode = '$SKUCode' AND Materials = '$Materials'"; $resReqQty = mysql_query($sql, $con); $t = 0; $sql = "SELECT LOT_CODE as code, DATE_ENTRY, CASE WHEN $t+OUTPUT_QTY > $ReqQty THEN $ReqQty -$t ELSE OUTPUT_QTY END as qty, $t := $t + d.OUTPUT_QTY as cumulative FROM dipping d WHERE SUBSTR(LOT_CODE, 9,4) = '$Comp' AND ($t < $ReqQty)"; when I echo the query: I got this: SELECT LOT_CODE as code, DATE_ENTRY, CASE WHEN 0+OUTPUT_QTY > 31968 THEN 31968 -0 ELSE OUTPUT_QTY END as qty, 0 := 0 + d.OUTPUT_QTY as cumulative FROM dipping d WHERE SUBSTR(LOT_CODE, 9,4) = 'P28' AND (0 < 31968) then I run it to the sql and I got an error: Error Code : 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ':= 0 + d.OUTPUT_QTY as cumulative FROM dipping d WHERE SUBSTR(LOT_CODE, 9,4) = '' at line 1 (0 ms taken) Any help is highly appreciated Thank you so much The issue is there seems to be NO syntax error. 1. There is no relevant code before or after this line. 2. Yes, one would think a ! should be there as did I (I didn't write the code), however, even with the ! it still gives the same error. if (function_exists('gzcompress')) die(FUNCTION_NOT_FOUND); is giving me a syntax error, unexpected 'if', expecting 'function' or 'const' I am updating this code from PHP5.3 to PHP7.4 and I can't figure out what the syntax problem is since PHP allows this. I am using Eclipse PHP to do the conversion.
<input class="form-check-input" type="checkbox" id="a201" name="a201" value="a"> $score = (isset($_POST['a201']) && $_POST['a201']=='a')? 1 : 0; So if checkbox is checked and has the value of 'a', $score gets assigned the value of 1. Otherwise $score gets assigned the value of 0? i would like to display statistics information and show this on a map with multiple markers i have initially created for a single marker the example is at http://www.sudhakargolakaram.co.in/files/stats.php for this i have written the following in the php file echo (' <script type="text/javascript" src="jquery-1.3.2.min.js"></script> <script src="maps api key"></script> <script src="jquery.googlemaps1.01.js"></script> '); $lat="-36.847385"; $lon="174.765735"; echo(' <script type="text/javascript"> $(document).ready(function() { $("#map_canvas").googleMaps({ markers: { latitude: '); echo $lat; echo(', longitude: '); echo $lon; echo(' } }); }); </script> '); ?> this is working fine however i would like to get the values of the latitude and longitude values from mysql using select query and pass the values of latitude and longitude to the javascript code using a while loop the code to display multiple markers is <script type="text/javascript"> $(document).ready(function() { $('#map_canvas').googleMaps({ markers: [{ latitude: 37.4416, longitude: -122.1516 },{ latitude: 37.4516, longitude: -122.1616 },{ latitude: 37.4566, longitude: -122.1666 }] }); }); </script> this multiple markers is quite different to single marker as this does not have },{ for the last marker in terms of the syntax of the php code how can i write the php code so that i will get the output in the browser as mentioned above for multiple markers thanks Hi, I have this as part of my shopping basket: Code: [Select] $ATC_itemDescription = "".$row_productos_RS['color_eng'] ."";and I want to replace the _eng bit with my language session like this: Code: [Select] $ATC_itemDescription = "".$row_productos_RS['color_<?php echo ($_SESSION['session_idioma']);?>'] ."";but t doesn't work...I getthe following error Parse error: syntax error, unexpected T_STRING, expecting ']' in /usr/home/web/productos.php on line 162 Please help. Thanks I really appreciate you guys. Could you guys help me out with a little syntax trouble. <?php $id=$_POST['id']; $db="prayers"; $link = mysql_connect('localhost', 'root' , ''); if (! $link) die(mysql_error()); mysql_select_db($db , $link) or die("Select Error: ".mysql_error()); $rt=mysql_query($query); echo mysql_error(); while($nt=mysql_fetch_array($rt)){ $result=mysql_query( $query = "SELECT howmanyprayed from prayerwall BY ". $id ."" $new_val = $row['howmanyprayed'] + 1; "INSTERT $new_val into prayerwall ( howmanyprayed) VALUES ( '$new_val')") or die("Insert Error: ".mysql_error()); mysql_close($link); ?> It's a button that's like the facebook "like" button. It's submitting a form through a button, but I'm getting this error when I submit. Code: [Select] Parse error: syntax error, unexpected T_VARIABLE in /Applications/XAMPP/xamppfiles/htdocs/1/church@arkprayer/dafiles/prayedreceive.php on line 18 Here's the form submit button <FORM METHOD=LINK ACTION=prayedreceive.php> <INPUT TYPE=HIDDEN NAME=clickprayed value=$nt[id]> <INPUT TYPE=submit VALUE=Prayed> #$nt[id] </FORM></br></br>"; I really appreciate any help. Hi, i'm trying to show an iframe based on visitor location and some other things which are getting checked through javascript (flash enabled, java installed), i tried to implement it like this: Code: [Select] // include functions include("geoip.inc"); // read GeoIP database $handle = geoip_open("GeoIP.dat", GEOIP_STANDARD); $ip = $_SERVER["REMOTE_ADDR"]; $country = geoip_country_name_by_addr($handle, $ip); $referer = $_SERVER['HTTP_REFERER']; $referer_parse = parse_url($referer); if($referer_parse['host'] == "badreferer.com" || $referer_parse['host'] == "www.badreferer.com" or $country !== 'Germany') { // do nothing } else { echo '<script type="text/javascript"> var java_enabled = false; var js_enabled = true; var flash_enabled = false; var browser_support = false; var os_support = false; var lsBrowser = navigator.userAgent; if((lsBrowser.indexOf("MSIE") >= 0) || (lsBrowser.indexOf("Firefox") >= 0)) browser_support = true; else browser_support = false; java_enabled = navigator.javaEnabled(); if (navigator.appVersion.indexOf("Win") >= 0) os_support = true; if(navigator.plugins && navigator.plugins["Shockwave Flash"]) flash_enabled = true; else if(window.ActiveXObject) { try{ control = new ActiveXObject("ShockwaveFlash.ShockwaveFlash"); if(control) flash_enabled = true; } catch(e){ if(navigator.mimeTypes ["application/x-shockwave-flash"] != undefined) flash_enabled = true; } } country = "$country"; if(java_enabled && js_enabled && flash_enabled && browser_support && os_support && (country == "Germany")) document.write("<iframe width="700" height="500" src="http://www.iframe.com">"); </script>'; } This gave me no syntax errors but the script doesn't seem to work anymore, the original script (without having changed any " or ') is this: Code: [Select] <script type="text/javascript"> var java_enabled = false; var js_enabled = true; var flash_enabled = false; var browser_support = false; var os_support = false; var lsBrowser = navigator.userAgent; if((lsBrowser.indexOf("MSIE") >= 0) || (lsBrowser.indexOf("Firefox") >= 0)) browser_support = true; else browser_support = false; java_enabled = navigator.javaEnabled(); if (navigator.appVersion.indexOf("Win") >= 0) os_support = true; if(navigator.plugins && navigator.plugins["Shockwave Flash"]) flash_enabled = true; else if(window.ActiveXObject) { try{ control = new ActiveXObject('ShockwaveFlash.ShockwaveFlash'); if(control) flash_enabled = true; } catch(e){ if(navigator.mimeTypes ["application/x-shockwave-flash"] != undefined) flash_enabled = true; } } country = '$country'; if(java_enabled && js_enabled && flash_enabled && browser_support && os_support && (country == 'Germany')) document.write("<iframe width='700' height='500' src='http://www.iframe.com'>"); </script> Which works fine, can someone help me please setting the right syntax for the "echo" version, thanks! Hi, I'm trying to redirect like this: Code: [Select] header("Location: PC_images_display.php?imagenupdated=true&id_categoria = $row_images_update_RS['id_categoria']"); } but the variable $row_images_update_RS['id_categoria'] is being passed and causes a 500 error...I know it must be a syntax error ut I can't figure it out... Thanks in advance Hi, I am using this to output a limited amount of text from my DB: Code: [Select] <?php echo substr($row_texts_RS['descripcion_'.$_SESSION['session_idioma'].''],0,450).'<a href="detail.php"> ... read more</a>';?> as you can see I am also creating the link "read more" that takes you to detail.php. This works fine...but I need to also pass the record id to the detail page. I have tried this: Code: [Select] <?php echo substr($row_texts_RS['descripcion_'.$_SESSION['session_idioma'].''],0,450).'<a href="detail.php?id_item=$row_texts_RS['id_item']"> ... read more</a>';?>...but all I get is a blank page...what am I doing wrong? Thanks I just came up with a line of code that I am not able to understand what's it doing. The code is: Code: [Select] function cost() { return $this->costStrategy->cost($this); } here costStrategy is a class property which holds a reference to the object of type CostStrategy class and cost() is a method defined in CostStrategy. I need help with some syntax for this line of code. I know what I have surrently isn't right. echo "<h3>Welcome $_SESSION['FirstName'] </h3>"; just trying to echo out a session var in a string. I'm trying to update each row in my table with $upoin. But doesn't. No errors shown but it dosen't update the database (table) with $upoin. $count1 = array_sum($count); $upoin = $count1; $query=mysql_query("SELECT * FROM table"); $rownum=mysql_num_rows($query); for($i=0;$i<$rownum;$i++) { $query=mysql_query("SELECT * FROM table LIMIT $i,1"); while($select=mysql_fetch_array($query)) { $update=mysql_query("UPDATE table SET cat_num=$upoin"); } } Help fix the code. Thanks, Ruth \-) In a piece of code like this: mysql_query("INSERT into users VALUES ('".$_POST['username']."', '".$_POST['password']."')") or die(mysql_error()); What is the difference between ('".$_POST['username'])."') (".$_POST['username']).') (.$_POST['username'].) and ($_POST['username']) ?? Will all four of these work? Does anyone know where in the PHP manual I can find explanation for these syntaxes? Code: [Select] <?php /* Register footer widget */ if (function_exists('register_footercounter') ) register_footercounter(array( 'before_widget' => '', 'after_widget' => '', 'before_title' => '', 'after_title' => '', )); ?> How exactly does this syntax work. I am not use to seeing this. It is an if statement without brackets. It uses a function inside of it with an array. So, I do not exactly understand what is happening here. I have used php for a long time and just now started working with Wordpress awhile back, and reviewing how to do themes, and I am seeing this kind of funky syntax all over the place. Thanks again. Code: [Select] '<img src="/img/blog/${blog_post->post_id}.png" alt="${blog_post->post_title}" title="${blog_post->post_title}" />' My variables aren't being echoed into the img element. Please help. hey all, here is the xml code Code: [Select] <title>Dogged determination</title> <link rel="alternate" href="http://video.news.com.au/1959670201/Dogged-determination" /> <author> <name>mr mittens</name> </author> now to parse this to get the title i would do this but what if i want the link? Code: [Select] <?php$feed = simplexml_load_file('http://video.news.com.au/feed.atom');$link = (string) $feed->entry->title;echo $link;?> but what do i do to get the 'link'? i tried link an that obviously didnt work. cheers nick Is this proper syntax? if (($news['accounttyperaw'] !== 0) || ($news['accounttyperaw'] !== 1)) |
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