PHP - How To Link A Stylesheet With Php
Hi, I wanted to know how to link a stylesheet using php specifically for the purpose of loading a different stylesheet when the home page displays. I heard of echoing out the stylesheet but I do not know how. Any help would be appreciated.
Similar TutorialsHello: I am trying to make a StyleSheet updateable from my admin panel, but I'm not sure if what I want to do is possible. So ... I have a TEXTAREA in my admin panel that writes to the DB just fine. it has styles like: Code: [Select] body { margin: 5px 0; padding: 0; background-color: #ebe9e6; background-image: url('../images/Site-BG2.jpg'); background-position: center bottom; background-repeat: no-repeat; background-attachment: scroll; font-family: arial, sans-serif; font-size: 100%; line-height: 1.4em; } ... Etc... On the frontend, it writes into the StyleSheet just fine like: Code: [Select] <?php include('myConn.php'); //contains your mysql connection and table selection $query=mysql_query("SELECT * FROM myStyleSheet") or die("Could not get data from db: ".mysql_error()); while($result=mysql_fetch_array($query)) { $myPageData=$result['myPageData']; } ?> <?php echo $myPageData; ?> So, what I want to see is if I can somehow pull the styles onto the page like: Code: [Select] <link rel="stylesheet" type="text/css" href="include/StyleSheet.css" /> Now, if I do it as listed above it and look at the code it displays the Code: [Select] <?php include('myConn.php'); //contains your mysql connection and table selection Etc... If I do it like Code: [Select] <link rel="stylesheet" type="text/css" href="include/StyleSheet.php" /> It displays the styles fine, but the browser doesn't read it as a StyleSheet and therefore the page doesn't get formatted. So, is there any way to make this work? Anyone have any ideas about this? The idea is so I can manage the Styles via an admin panel remotely without having to login with web editing software. Thanks. Hi, Can someone why my stylesheet is not working? Code: [Select] <?php header('Content-type: text/html; charset=utf-8'); include 'config.php'; include 'lib.php'; $db = dbConnect(); if (isset($_GET['ip'])) { $ip = $_GET['ip']; $longitude = $_GET['long']; $latitude = $_GET['lat']; $searches = getSearchesByIP($ip); $watchUser = true; } else { $searches = getSearches(); $watchUser = false; } dbClose($db); ?> <html> <head> <title>cms</title> <meta http-equiv="content-type" content="text/html; charset=utf-8" /> <link rel="stylesheet" type="text/css" href="inc/css/style.css" /> </head> <body> <h1>WTF</h1> <div id="container"> <? if ($watchUser == true) {?> <a href=searches.php> See all</a> <br/> <table> <tr> <th>ip</th> <td><?=$ip;?></td> </tr> <tr> <th>longitude</th> <td><?=$longitude;?></td> </tr> <tr> <th>latitude</th> <td><?=$latitude;?></td> </tr> </table> <? } ?> <br/> <table> <tr> <th>id</th> <? if ($watchUser == false) echo "<th>ip</th>"; ?> <th>question</th> <? if ($watchUser == false) echo "<th>longitude</th>"; ?> <? if ($watchUser == false) echo "<th>latitude</th>"; ?> </tr> <? foreach($searches as $search) { ?> <tr> <td><?=$search['id'];?></td> <? if ($watchUser == false) { echo "<td> <a href='searches.php?ip=" . $search['userIP'] . "&long=" . $search['longitude'] . "&lat=" . $search['latitude'] . "'>" . $search['userIP'] . "</ a> </td>"; } ?> <td><?=$search['question'];?></td> <? if ($watchUser == false) echo "<td>" . $search['longitude'] . "</td>"; ?> <? if ($watchUser == false) echo "<td>" . $search['latitude'] . "</td>"; ?> <td><a href="answers.php?id=<?=$search['id'];?>">see answers</a></td> <td><a href="inc/php/utils/search-delete.php?id=<?=$search['id'];?>">delete</a></td> </tr> <? } ?> </table> </div> <a href="search.php">Add new</a> </body> </html> my css file: a:link {color:#FF0000;} /* unvisited link */ a:visited {color:#00FF00;} /* visited link */ a:hover {color:#FF00FF;} /* mouse over link */ a:active {color:#0000FF;} /* selected link */ /* table { font-family: "Arial"; font-size: 10px; color:red; } */ table, th, td { border:1px solid black; } h1 {color:#00ff00;} Okay the reason I'm doing it this way is because I work locally and then transfer them to the production site. For some reason, this isn't working even though when I view the page source, it has the right URL, but when it's clicked it goes to a blank page, but when I copy and paste, it goes to the right page. Anywho, this is what I'm trying: Code: [Select] <?php $homeURL = 'localhost:90/Elvonica'; ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>Elvonica</title> <meta http-equiv="content-type" content="text/html;charset=utf-8" /> <link rel="stylesheet" type="text/css" href="<?php echo $homeURL; ?>/template/css/skySpirit.css" /> I didn't plug in the rest to ignore it since it's not part of the problem. It's printing: localhost:90/Elvonica/template/css/skySpirit.css, but when it's clicked, goes to blank page. When it is copied and pasted, it goes to the right page. I have a feeling you can't include PHP inside a link rel or any sort of that header information. If anyone could please help me how to do this, I would appreciate it. FYI: I did have just template/css/skySpirit.css and it worked until I go into a another directory like forums/index.php. Then it tries to go localhost:90/Elvonica/forums/template/css/skySpirit.css and it's not in there obviously. Thank you for anything that you can offer! I know how to do the includes with the dirname(__FILE__). ...in a different folder? For instance, I have a stylesheet in my C:\xampp\htdocs\rcm folder, and I want to link it to files in the C:\xampp\htdocs\ folder. Is there a way of doing this? Thanks in advance due to mod_rewrite flaws, i have to give everything an absolute path. somehow though, the stylesheet's absolute path wont work. heres the code: <link href="C:/xampp/htdocs/lso/style.css" rel="stylesheet" type="text/css" /> the stylesheet is in the lso folder, yet somehow this wont work and no styles are loaded! Hello.
I have a bit of a problem. When I fetch the link field from the database.i don't see an actual link on the page.
One more thing, what type of field should I use to store the link in the database? Probably there is where I went wrong.
All help is
Hi I've got this database I created with fields ProductId ProductName Image I've managed to get it to list the ID,productname, and Image urls in a list. My next step is to have the image field actually display an image and make it clickable: heres what I've done so far: Code: [Select] <?php $con = mysql_connect("localhost","root",""); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("productfeed", $con); $result = mysql_query("SELECT * FROM productfeeds"); echo "<table border='0'> <tr> <th>Firstname</th> <th>Lastname</th> <th>Image</th> </tr>"; while($row = mysql_fetch_array($result)) { echo "<tr>"; echo "<td>" . $row['ProductID'] . "</td>"; echo "<td>" . $row['ProductName'] . "</td>"; echo "<td>" . $row['ImageURL'] . "</td>"; echo "</tr>"; } echo "</table>"; mysql_close($con); ?> Heres what I want to do: Code: [Select] while($row = mysql_fetch_array($result)) { echo "<tr>"; echo "<td>" . $row['ProductID'] . "</td>"; echo "<td>" . $row['ProductName'] . "</td>"; // my changes beneath echo "<td>" . <a href="<?php echo $row['ImageURL'];?>"> <img src="<?php echo $row['LinkURL']; ?>"> </a>. "</td>"; echo "</tr>"; } echo "</table>"; mysql_close($con); ?> Can you guys point me in the right direction? Many thanks Hi Support, I have a form, where it collects user description input. I can collect the inputs and store it with newline. The issue is - how to collect the http link to actual hyperlink ref during display. The following is my code: <textarea name="description" cols="50" rows="10" id="description"><?php echo str_replace("<br>", "\n", $description);?></textarea></td> For example, User input: Hi, Check it out - http://www.google.com/ I would like to display google link as href so that Viewers can click the link and go to the page. Right now, it is not href and user need to copy the link to new tabs or pages and then it can come. Thanks for your help. Regards, Ahsan hi hope you all are fine. i have been working on a Email Form (like user fills up the form which send the information to our email) but i was having problem with (URL field i created) link of form is (http://services.shadowaura.com/allquotations/static.php) field which is not working is "Inspirational Website:" when i submit the form it says (Forbidden You don't have permission to access /allquotations/staticworking.php on this server. Additionally, a 404 Not Found error was encountered while trying to use an ErrorDocument to handle the request.) Can some one help me out ????????????? code behind this form is: Code: [Select] <?php /* Email Variables */ $emailSubject = 'Shadow Aura Contact Info!'; $webMaster = '*****@shadowaura.com'; /* Data Variables */ $Name = $_POST['Name']; $email = $_POST['email']; $Cell = $_POST['Cell']; $Phone = $_POST['Phone']; $CompanyName = $_POST['CompanyName']; $TypeOfBusiness = $_POST['TypeOfBusiness']; $Address = $_POST['Address']; $YourBudget = $_POST['YourBudget']; $HaveDomain = $_POST['HaveDomain']; $RunningWeb = $_POST['RunningWeb']; $WebLink = $_POST['WebLink']; $Inspiration1 = $_POST['Inspiration1']; $Inspiration2 = $_POST['Inspiration2']; $NumberPages = $_POST['NumberPages']; $UseFlash = $_POST['UseFlash']; $TimeFrame = $_POST['TimeFrame']; $Provided = $_POST['Provided']; $Comments = $_POST['Comments']; $body = <<<EOD <h1> Static Website Quotation </h1> <br> <b>Name of Client:</b>$Name<br> <b>Your Email:</b>$email<br> <b>Cell Number:</b>$Cell<br> <b>Line Phone Number:</b>$Phone<br> <b>Company Name:</b>$CompanyName<br> <b>Type of Business:</b>$TypeOfBusiness<br> <b>Address:</b>$Address<br> <b>Your Budget:</b>$YourBudget <br> <b>Do you have Domain:</b>$HaveDomain<br> <b>Your Site is Running:</b>$RunningWeb <br> <b>Website Link:</b><a href="$WebLink">$WebLink</a><br> <b>Inspiration:</b>$Inspiration1<br> <b>2nd Inspiration:</b>$Inspiration2<br> <b>Number of Pages:</b>$NumberPages<br> <b>Use Flash:</b>$UseFlash <br> <b>Time Frame:</b>$TimeFrame<br> <b>You will provide:</b>$Provided<br> <b>Comments:</b>$Comments<br> EOD; $headers = "From: $email\r\n"; $headers .= "Content-type: text/html\r\n"; $success = mail($webMaster, $emailSubject, $body, $headers); /* Results rendered as HTML */ $theResults = <<<EOD <html> <head> <title>sent message</title> <meta http-equiv="refresh" content="3;URL=http://services.shadowaura.com/"> <style type="text/css"> <!-- body { background-color: #8CC640; font-family: Verdana, Arial, Helvetica, sans-serif; font-size: 20px; font-style: normal; line-height: normal; font-weight: normal; color: #fec001; text-decoration: none; padding-top: 200px; margin-left: 150px; width: 800px; } --> </style> </head> <div align="center">Your email will be answered soon as possible! You will return to <b>Shadow Aura Services</b> in a few seconds !</div> </div> </body> </html> EOD; echo "$theResults"; ?> here's my code that i've used to send an email. Code: [Select] $link = "<a href=\"http://www.example.com/" . $num . "\">" . $num . "</a>"; $query = "SELECT content FROM emails"; $result = mysql_query($query) or die(); $email_content = mysql_result($result, 0); $email = sprintf($email_content, $first, $name, $from, $link, $record, $rec, $inc, $max); $email_body = stripslashes(htmlentities($email, ENT_QUOTES, 'UTF-8')); // this is sent to another php script via post.... $subject = $_POST['subject']; $message = nl2br(html_entity_decode($_POST['email_body'])); $to = "me@whatever.com"; $charset='UTF-8'; $encoded_subject="=?$charset?B?" . base64_encode($subject) . "?=\n"; $headers="From: " . $userEmail . "\n" . "Content-Type: text/html; charset=$charset; format=flowed\n" . "MIME-Version: 1.0\n" . "Content-Transfer-Encoding: 8bit\n" . "X-Mailer: PHP\n"; mail($to,$encoded_subject,$message,$headers); in the db, emails.content is of the text type and contains several lines of text with %4$s which inserts the value of $link into the body. when the email arrives, there is a link and it appears fine, with the value of $num hyperlinked. however when you click on it it doesn't go anywhere. when copying the link location from the email it gives me x-msg://87/%22http://www.example.com/16 what is x-msg? how can i get this to work properly? Hi guys, I'm using a twitter script that grabs the title and publishings it like so: "Title - Read More at..." I was wondering how i would be able to post the direct link into twitter.. like news.php?id=1 for example. Code: [Select] $tweet->post('statuses/update', array('status' => ''.$_POST[title].' - more at MY URL')); This part is in the script to publish automatically when the users adds to the news database. How am i able to get the ID just after the posting of the news? Thanks! I have a line like this it prints text link but I prefer image link how should i edit it I would appreciate some feedback Code: [Select] $templates['etiket'] = array('name' => t('ETİKET'), 'module' => 'uc_invoice_pdf', 'path' => $templates_uc_invoice_pdf_path, 'pdf_settings' => $pdf_settings); Hi Everyone, So I am building a page that list records from a table, in this case customers, and I want to the printed last name (lname) of the record to be the link to the a detail php page that displays the detailed record. Any suggestions on how to do that? Here is what I'm using now. I don't like the button look, that's why i'm trying to make a link. Any Suggestions? Thanks <? session_start(); include 'menu.php'; include ("include/connect.php"); // how many rows to show per page $rowsPerPage = 10; // by default we show first page $pageNum = 1; // if $_GET['page'] defined, use it as page number if(isset($_GET['page'])) { $pageNum = $_GET['page']; } // counting the offset $offset = ($pageNum - 1) * $rowsPerPage; $sql = @mysql_query("SELECT * FROM customer ORDER BY id LIMIT $offset, $rowsPerPage"); $id = ''; echo "<table border='0' align='center'><tr><td align='left' colspan='2'>Last Name</td><td align='center'>Location</td><td align='right'>Date Posted</td></tr>"; while ($row = mysql_fetch_array($sql)) { if ($id != $row['id']) { echo "<tr><td><form action='customerdetail.php' method='post'><input type='hidden' name='locationp' value='{$row['location']}' /><input type='hidden' name='titlep' value='{$row['title']}' /><input type='hidden' name='idp' value='{$row['id']}' /><b><font size='4'><input type='submit' value='{$row['lname']}'></font></b></form></td><td> </td><td align='center'><b><font size='4'>{$row['location']}</font></b></td><td align='right'><b><font size='4'> {$row['datep']}</font></b> </td></tr><tr><td colspan='4'> </td></tr>"; $id = $row['id']; } } echo "</table>"; // how many rows we have in database $query = "SELECT COUNT(id) AS numrows FROM customer"; $result = mysql_query($query) or die('Error, query failed'); $row = mysql_fetch_array($result, MYSQL_ASSOC); $numrows = $row['numrows']; // how many pages we have when using paging? $maxPage = ceil($numrows/$rowsPerPage); // print the link to access each page $self = $_SERVER['PHP_SELF']; // creating previous and next link // plus the link to go straight to // the first and last page if ($pageNum > 1) { $page = $pageNum - 1; $prev = " <a href=\"$self?page=$page\">[Prev]</a> "; $first = "<br><center> <a href=\"$self?page=1\">[First Page]</a> "; } else { $prev = ' '; // we're on page one, don't print previous link $first = '<br><center> '; // nor the first page link } if ($pageNum < $maxPage) { $page = $pageNum + 1; $next = " <a href=\"$self?page=$page\">[Next]</a> "; $last = "<a href=\"$self?page=$maxPage\">[Last Page]</a></center> "; } else { $next = ' '; // we're on the last page, don't print next link $last = ' </center>'; // nor the last page link } // print the navigation link echo $first . $prev . " Showing page $pageNum of $maxPage pages " . $next . $last; // and close the database connection mysql_close($con) // ... and we're done! ?> This link dnt seem to work. Can someone help? echo "<td><a href =" . $rows['url'] .">"</a>"</td>"; Thankz. Hello dear friends, Let say we have Code: [Select] $space ="hello world"; then remove spaces between the words by using Code: [Select] $title = str_replace(' ', '-', trim($space)); so it would be here as "hello-world" and let say we have stored title,article text...whever in an database table that call back all this using id then for an article with id=1 its link will be Code: [Select] site.com/index.php?id=1 it is clear that the Code: [Select] echo "$id"; //<--- 1 now some wordpress or/and blogs using rewrite .htaccess to make the link as Code: [Select] site.com/$title-$id (as our example site.com/hello-world-1) then how they know its $id = 1 to get any variables from database that needs the id i've tried but never works and only works if i made something like Code: [Select] site.com/$title_$id //<-- site.com/hello-word_1 cause it needs difference separate in order to understand the id so how to make it ? how to make it understand that the last separated is the id thanks Hello dear friends, Let say we have Code: [Select] $to = "gigi"; then we have link like this Code: [Select] mysite.com/$to_$id.html with indeed .htaccess code Code: [Select] RewriteRule -(.*)\.htm file.php?id=$1 it will works , Now what if i want to make the link like this Code: [Select] mysite.com/$id/$to.html what will be the .htaccess code in this way ??? I have a lovely RSS creation script which dynamically writes an RSS feed using the information from the database, which you can automatically update every time a blog entry (or anything else generated by a script) is added. The only issue with it, is that the Code: [Select] <strong> tags have had to be deleted using strip_tags() because the RSS doesn't like it. I want to keep the original formatting of the blog article but because I have to strip out the strong links, the hyperlinks are also removed. I don't know enough about RSS (IMHO) to work out how to put the links back in - do I need to format the STRONG tags differently, or do i need to change the PHP to str_replace() the strong tags with nothing? Here's some code that does work: Code: [Select] <item rdf:about="http://www.manteya.com/blog/Music-Improves-Productivity_24.html"> <title>Music Improves Productivity</title> <link>http://www.manteya.com/blog/Music-Improves-Productivity_24.html</link> <description>Research shows that music can improve speed of working within organisations. There is a double-edged sword to this article, however. Music with fast tempos can help the release of adrenalin and therefore increase the heart rate of the listener. Music producers here in the UK have taken advantage And here's some that doesn't: Code: [Select] <item rdf:about="http://www.manteya.com/blog/Music-Improves-Productivity_24.html"> <title>Music Improves Productivity</title> <link>http://www.manteya.com/blog/Music-Improves-Productivity_24.html</link> <description>Research shows that music can improve <strong>speed</strong> of working within organisations. There is a double-edged sword to this article, however. Music with fast tempos can help the release of adrenalin and therefore increase the heart rate of the listener. Music producers here in the UK have taken advantage I'm sure you geniuses (or geniei) can work it out, so any help would be very welcome indeed. Just need a correction on this please, there is a Parse error, think I got the quote marks wrong somewhere? echo "<li>" . <a href="/stock/$stock.htm"> .$Stock . ": " . $Name . "</a></li>\n"; Thanks i have a form here that redirect to : "proc/edit.php?edit=<?php echo urlencode($function_name);?>" Code: [Select] <?php require_once("includes/functions.php");?> <?php session_start(); if (isset($_SESSION["user_name"])) { require_once("includes/connection.php"); if(isset($_GET['functions'])){ $function_name=$_GET['functions']; $function_type=$_GET['type']; $query = "SELECT * FROM functions WHERE function_name = '{$function_name}' "; $result = mysql_query($query,$connection); if($result){ $row = mysql_fetch_array($result, MYSQL_ASSOC); $function_description=$row['function_description']; ?> <html> <head> <title>Edit Your function</title> </head> <body> <form name="edit_function_n" action="proc/edit.php?edit=<?php echo urlencode($function_name);?>" method="get"> Edit Your function name : <input type="text" name="new_function_name"/><br/><br/> Edit Your description here :<br/><br/> <textarea name="new_function_description" rows="10" cols="30"></textarea><br/><br/> <input type="submit" value="Change" /><br/><br/> </form> </body> </html> <?php } elseif(!$result){ redirect("errors/error_db.html");} } } else { redirect("main.php?error=log"); } //close connection! mysql_close($connection); ?> AND i have a proc php file that UPDATE the database with the new form variables and then redirect to show.php Code: [Select] <?php require_once("../includes/functions.php");?> <?php session_start(); if (isset($_SESSION["user_name"])) { require_once("../includes/connection.php"); //ignore this , this is for deleting! if(isset($_GET['delete'])){ //warning : using urldecode here is wrong cuz $_GET[var]; is already decoded! $function_to_delete=$_GET['delete']; $function_type=$_GET['functions']; $query="DELETE FROM functions WHERE function_name='{$function_to_delete}' "; $result = mysql_query($query, $connection); if(!$result){redirect("../errors/error_db.html");} elseif($result){ redirect("../show.php?functions={$function_type}&delete=suc"); }} //the place for edit ! elseif(isset($_GET['edit'])){ $old_function_name=$_GET['edit']; $new_function_name=$_POST['new_function_name']; $new_function_description=$_POST['new_function_description']; $query="UPDATE functions SET function_name='{$new_function_name}', function_description='{$new_function_description}' WHERE function_name='{$old_function_name}' "; $result = mysql_query($query, $connection); if(!$result){redirect("../errors/error_db.html");} elseif($result){redirect("../show.php?functions='{$function_type}'&edit=suc");} } } else { redirect("../main.php?error=log"); } ?> <?php //close connection! mysql_close($connection); ?> The problem is i get redirect to a strange link that never existed and i never pointed to : /proc/edit.php?new_function_name=($new_function_name)&new_function_description=($new_function_description) with the variables replaces with their values and with no database update whatsoever! I tried a lot with it with no result could someone help me out here! Hi, DaniWeb I'm doing a website for a music school and i have a table with all the instruments: And i want to click in one image and it goes to other page where's the instrument program. I mean, each image has 1 page with its own program. I have this code: Code: [Select] <?php include "db_connect.php"; $sql_imagem = "SELECT cod_curso, imagem_curso, nome_curso FROM curso ORDER BY nome_curso ASC"; $i=0; echo "<table width = 90% height = 45% align = center>"; $executa=mysql_query($sql_imagem,$connect); while($dados=mysql_fetch_array($executa)) { $i+=1; if ($i == 1) { echo "<tr> <td align = center>"; } else { echo "<td align = center>"; } echo "<img src=\"".$dados['imagem_curso']."\"/></a> <br /> ".$dados['nome_curso']; if ($i == 4) { echo "</td> </tr>"; $i=0; } else { echo "</td>"; } } echo "</table>"; ?> And i was thinking about using Arrays, but i don't know how to work with it. Can someone help me, please? Thank you, PF2G |