PHP - Copy/move Files From Domain To Subdomain

hey, can some one provide a code to help me copy a folder called contents with files in it to another folder called items

cheers

How would I copy an array of selected files? I know how to list them using a 'for' loop, and how to separate them using a 'foreach' loop, but I am unable to get a checkbox array to copy to a destination folder. Help is appreciated.

I know this code works

INSERT INTO archive_table
SELECT * FROM original_table WHERE id = 1

But i want to also add the current date whenever i copy the data into a new table.     Thanks in advance    

hi all,

i have this music website and i have to upload every album under this folder "newsongs" ... in AlbumName folder i have normal quilty songs and HQ folder..under HQ folder i have High Quilty songs for each album.


i have this coding which moves Album folder  and normal quilty songs to other folder "songs" but i also want to move subfolder "HQ" and High Quilty songs with AlbumName  folder



for($i=0;$i<=$ct;$i++)
{
$alb=$alname[$i];
$cat=$catname[$i];
$albids=$albid[$i];
$fon=$folder_name[$i];

$tmp_name=$doc_root."newsongs/$fon";
$uploads_dir=$doc_root."songs/$cat/$fon";

if ($handle = opendir($tmp_name)) {
/* This is the correct way to loop over the directory. */ 
while (false !== ($file = readdir($handle))) {
//echo "$file\n <br>";
if($file !=='..' and $file !=='.')
{
$song_path="songs/$cat/$fon/$file";
if(!is_dir("$tmp_name/$file") and (!is_dir("$uploads_dir/$file")))
{
if(copy("$tmp_name/$file", "$uploads_dir/$file"))
{
$cp=1;
$ext=substr($file,-4);
if($ext=='.mp3')
$insqry=mysql_query(" insert into tbl_songs set song_name='$file', album_id='$albids', artist_id='$artid', song_path='$song_path' ");

unlink($tmp_name.'/'.$file);
}
else
{
echo "could not move songs ";
}
}
}
if($insqry)
  $msg="songs Added to the database";
else
$msg="songs Not Added to the database";
}
closedir($handle);


thnx in advnce

I need to copy php files from remote linux (apache) server to windows usb drive. I am using php windows but the files were created in php under linux.   Do I just download them or do I need to do something to make this work  

I am unsuccessfully able to do the following:   User creates an account   After login, checks server if user has their own folder created   If doesn't exist, create it   Copy files from source_code to this new folder   My code does create a folder, but no files appear inside it. Been trying to find an example with google search for the past 3 days with no luck.   I am running LAMP on Linux Mint OS to run my PHP webpages.   Can anyone tell me if issues with this section of coding?

<?php
 
function wait_time($seconds)

{

    $seconds = abs($seconds);

    if ($seconds < 1):

       usleep($seconds*1000000);

    else:

       sleep($seconds);

    endif;   

}
 
$file1 = "blank.html";

$file2 = "channel_video.php";

$file3 = "clear_playlist.php";

$file4 = "confirm.html";

$file5 = "index.html";
set_time_limit(0); //prevent script from timing out
 
$account = $_POST["account_name"];
$src = "source_code/";
$dst = $account."/";
 
echo 'Setting up your account page ->.';
mkdir($account, 0777, true); echo '.'; //create folder with full write permissions
wait_time(2000); //wait 2 seconds before copying files over
copy($src.$file1, $dst.$file1); echo '.';
wait_time(2000); //wait 2 seconds before copying files over
copy($src.$file2, $dst.$file2); echo '.';
wait_time(2000); //wait 2 seconds before copying files over
copy($src.$file3, $dst.$file3); echo '.';
wait_time(2000); //wait 2 seconds before copying files over
copy($src.$file4, $dst.$file4); echo '.';
wait_time(2000); //wait 2 seconds before copying files over
copy($src.$file5, $dst.$file5); echo '.<- setup finished<br>';
 
?>

Thanks for any input you can provide.

Hi,

I have a question.

Can I actually use windows hosting on .php files, or .php files are only suitable to linux domain?

Currently I am practicing some php files in the windows domain and I have received a message stated 'no database selected'. However I have definitely created the database, are there any other reasons which may cause this problem? Thanks

<?php
         echo '<select name="race" id="race">
         <option value="">--Please select one--</option>';
   
         $dbc = mysql_connect(111', '111', '111', '111')
         or die(mysql_error());
         $query = ("SELECT * FROM race ORDER BY race_id ASC");
         $sql = mysql_query($query, $dbc)
         or die(mysql_error());
      
            while($data = mysql_fetch_array($sql)) {
               echo'<option value="'.$data['race_id'].'">'.$data['race_name'].'</option>';
            }
         echo '</select><br/>';
   
         mysql_close($dbc);    ?>

After image is drop into container , I want to move copy of the original image to be move when original image dragend within container. I tried but it display copy image each time when original image dragend. can anyone help me?

 <!DOCTYPE html>
<html>
  <head>
    <meta charset="utf-8">
    <title>Prototype</title>
    <script type="text/javascript" src="http://code.jquery.com/jquery.min.js"></script>
    <script src="http://d3lp1msu2r81bx.cloudfront.net/kjs/js/lib/kinetic-v4.7.2.min.js"></script>
    <script src="http://code.jquery.com/ui/1.9.2/jquery-ui.min.js"></script>
<style>
    body{padding:20px;}
    #container{
      border:solid 1px #ccc;
      margin-top: 10px;
      width:350px;
      height:350px;
    }
    #toolbar{
      width:350px;
      height:35px;
      border:solid 1px blue;
    }
</style>        
<script>
$(function(){
 
    var $house=$("#house");
    $house.hide();
 
    var $stageContainer=$("#container");
    var stageOffset=$stageContainer.offset();
    var offsetX=stageOffset.left;
    var offsetY=stageOffset.top;
 
    var stage = new Kinetic.Stage({
        container: 'container',
        width: 350,
        height: 350
    });
    var layer = new Kinetic.Layer();
    stage.add(layer);
 
    var image1=new Image();
    image1.onload=function(){
        $house.show();
    }
    image1.src="http://vignette1.wikia.nocookie.net/angrybirds/images/b/b6/Small.png/revision/latest?cb=20120501022157";
 
    $house.draggable({
        helper:'clone',
    });
 
    $house.data("url","house.png"); // key-value pair
    $house.data("width","32"); // key-value pair
    $house.data("height","33"); // key-value pair
    $house.data("image",image1); // key-value pair

    $stageContainer.droppable({
        drop:dragDrop,
    });
    function dragDrop(e,ui){
 
        var x=parseInt(ui.offset.left-offsetX);
        var y=parseInt(ui.offset.top-offsetY);
 
        var element=ui.draggable;
        var data=element.data("url");
        var theImage=element.data("image");
 
        var image = new Kinetic.Image({
            name:data,
            x:x,
            y:y,
            image:theImage,
            draggable: true,
        
        dragBoundFunc: function(pos) {
            return {
              x: pos.x,
              y: this.getAbsolutePosition().y
            }
        }        
        
	   });
			image.on("dragend", function(e) {
			   var points = image.getPosition();
			   var image1 = new Kinetic.Image({
					name: data,
					id: "imageantry",
					x: points.x+65,
					y: points.y,
					image: theImage,
					draggable: false
				});
					layer.add(image1);
					layer.draw();
			});
		image.on('dblclick', function() {
			image.remove();
			layer.draw();
		});
        layer.add(image);
        layer.draw();
    }
 
}); // end $(function(){});

</script>       
</head>
<body>
    <div id="toolbar">
        <img id="house" width=32 height=32 src="http://vignette1.wikia.nocookie.net/angrybirds/images/b/b6/Small.png/revision/latest?cb=20120501022157"><br>
    </div>
    <div id="container"></div>
</body>
</html>

Edited by Biruntha, 08 January 2015 - 10:14 AM.

Hello I have a problem.

I have been trying to copy my music folders structure but not copying the mp3s; instead using the file names as a file name for a .txt file and inserting the URL to the file in the .txt file.

Eg.

E:\My Music
       folder 1
           folder 1.1
               file.mp3
       folder 2
       folder 3

to

G:\My Music
       folder 1
           folder 1.1
               file.txt
       folder 2
       folder 3

and inside "file.txt" would be one line saying "http://www.xxx.com/my_music/file.mp3

Hello, I try to get website speed of some website, but i can read only ''domain.com'' i can't read website files like css , js ... why ? i use proxies for this job. here is the php code:

$options = array(
'useragent' => "Firefox (+http://www.firefox.org)", // who am i
'connecttimeout' => 120, // timeout on connect
'timeout' => 120, // timeout on response
'redirect' => 10, // stop after 10 redirects
'referer' => "http://www.google.com",
'proxyhost' =>'85.25.8.14:80'
);
$response = http_get("http://solve-ict.com/wp-content/themes/ict%20theme/js/jquery-1.7.1.min.js", $options , $info);

but it works fine with http://domain.com/ , but with files css or js it gives 404, using some free proxy servers available ? Thanks.

Ok I am designing a php upload that will take a image file from a form and change the name of the file to the productnumber also recieved from the form. I had it working the otherday now it says Warning: copy() [function.copy]: open_basedir restriction in effect File() is not within the allowed path(s): (/home:/tmp:/usr) addpro.php on line 51.

my files are attached.... note that $pnum is the product number gotten from my form and image is the image being uploaded gotten from the form also.  The thing is it worked the other day but now it don't is it a change to the server ( I dont run the server) or did I mess up my code since then?  I really need a code that will do this two time over once for a small image being put into a folder called small and once for a folder called large both images being uploaded and being changed to $pnum.ext so they will both be displayed when being called out by the product number. but I can work on that after I get this one working.


line 51 is $copied = copy($_FILES['image']['tmp_name'], $newname);

Hi guys,

I am wirting a script to upload an image file, but I get the error:

copy() [function.copy]: Filename cannot be empty in

Obviouly it has something to do with the copy() function - (copy($HTTP_POST_FILES['product_img']['tmp_name'], $path))

I think it is not copying from my temp folder or something.

Can anyone help me out?

Code is:

Code: [Select]
//IMAGE FILE
$file_name = $_FILES['product_img']['name'];

echo '<p>File Name:' . $file_name . '</p>';
//IMAGE UPLOAD
// random 4 digit to add to file name
$random_digit=rand(0000,9999);

//combine random digit to file name to create new file name
//use dot (.) to combile these two variables
$new_image_name = $random_digit.$file_name;

echo $new_image_name;


//SET DESINATION FOLDER
$path= "uploads/".$new_image_name;
echo '<p>Path:' . $path . '</p>';
if($product_img !=none)
{
if(copy($HTTP_POST_FILES['product_img']['tmp_name'], $path))
{
echo "Successful<BR/>";
echo "File Name :".$new_file_name."<BR/>";
echo "File Size :".$HTTP_POST_FILES['product_img']['size']."<BR/>";
echo "File Type :".$HTTP_POST_FILES['product_img']['type']."<BR/>";
}
else
{
echo "Image upload Error<BR/>";
}
}
Any help would be greatly appreciated!

Thanks

I came across the PHP clone method. Does this clone first level fields and methods or does it also do deep copying e.g. copying references to those fields. For example, a field may be an array. Does it make a copy of the actual array or does it refer to the same array position in memory, so if the original changes, then the copy's changes as well?