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PHP - Echoing A Checkbox With Js In It
I am having issue creating a checkbox that uses a onClick() js method. I believe this might be due to the fact that I am echoing the html but if any one could help id appreciate it.
echo "<tr><td>WrkComp</td><td><input type='checkbox'" ?> <script>onClick="show()" </script> <? "name='WrkComp[]' value='DEP' '.$checked.' '.$Disabled.'/></td>"; Similar TutorialsI am simply trying to keep a check box checked once selected. What I have works, but not correctly. Because I am calling each array element in my checkbox like name="checkbox[]" And I am using this as the input return the check: <input type="checkbox" name="checkbox[]" value="checkOneValue" <?php if(isset($_POST['checkbox'])) echo "checked"; ?> /> I have 5 checkboxes that use the same code! And as I said it works, but returns ALL checkboxes as selected when submitted. I only want the actual selected boxes to remained checked. Any insight on a work around? The problem is I cannot solve how to identify unique array values as they are all named the same... Maybe I am not thinking right on all of this. Here is my full source code: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Checkbox Echoing Test</title> </head> <body> <form name="" action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post"> One <input type="checkbox" name="checkbox[]" value="checkOneValue" <?php if(isset($_POST['checkbox'])) echo "checked"; ?> /> <br /> Two <input type="checkbox" name="checkbox[]" value="checkTwoValue" <?php if(isset($_POST['checkbox'])) echo "checked"; ?> /> <br /> Three <input type="checkbox" name="checkbox[]" value="checkThreeValue" <?php if(isset($_POST['checkbox'])) echo "checked"; ?> /> <br /> Four <input type="checkbox" name="checkbox[]" value="checkFourValue" <?php if(isset($_POST['checkbox'])) echo "checked"; ?> /> <br /> Five <input type="checkbox" name="checkbox[]" value="checkFiveValue" <?php if(isset($_POST['checkbox'])) echo "checked"; ?> /> <br /> <input type="submit" name="submit" value="Echo Checkbox Data!" /> </form> <?php if (isset($_POST['checkbox']) && (isset($_POST['submit']))) { $checkbox = $_POST['checkbox']; foreach ($checkbox as $checkboxValue) { var_dump($checkboxValue); if (!empty($checkboxValue)) { echo "<br />$checkboxValue is checked"; } } }; // End of foreach loop if (!isset($_POST['checkbox']) && (isset($_POST['submit']))) { echo "<br />No checkboxes were selected!"; }; ?> </body> </html> Hello, I have a PHP page (below) that is suppose to update a field in my database. For some reason it does not update. I am trying to echo that sql with this script. Any help would be greatly appreciated. Thanks JR Code: [Select] $p = (100-$_POST[$c])/100; $sql = "delete from products_groups where customers_group_id = ".$sppc['customers_group_id']; echo $sql; tep_db_query($sql); $sql = "insert into products_groups select '". $sppc['customers_group_id'] ."' as customers_group_id, ( " . $p . " * p.products_price) as customers_group_price, p.products_id from products p"; echo $sql; tep_db_query($sql); Below is the complete code, Code: [Select] <?php require('includes/application_top.php'); ?> <!DOCTYPE html public "-//W3C//DTD HTML 4.01 Transitional//EN"> <html <?php echo HTML_PARAMS; ?>> <head> <meta http-equiv="Content-Type" content="text/html; charset=<?php echo CHARSET; ?>"> <title><?php echo TITLE; ?></title> <link rel="stylesheet" type="text/css" href="includes/stylesheet.css"> <script language="javascript" src="includes/general.js"></script> </head> <body marginwidth="0" marginheight="0" topmargin="0" bottommargin="0" leftmargin="0" rightmargin="0" bgcolor="#FFFFFF" onload="SetFocus();"> <div id="popupcalendar" class="text"></div> <!-- header //--> <?php require(DIR_WS_INCLUDES . 'template_top.php'); ?> <!-- header_eof //--> <?php if (isset($_POST['Update'])) { $sppc_query_raw = "select * from " . TABLE_CUSTOMERS_GROUPS . " order by customers_group_id"; $sppc_query = tep_db_query($sppc_query_raw); while( $sppc = tep_db_fetch_array( $sppc_query ) ) { if ($sppc["customers_group_name"] != "Retail"){ //$sppc['customers_group_id'] $c = "CG_".$sppc['customers_group_id']; $tmp = $_POST[$c]; if ($tmp != 0) { $p = (100-$_POST[$c])/100; tep_db_query("delete from products_groups where customers_group_id = ".$sppc['customers_group_id']); tep_db_query ("insert into products_groups select '". $sppc['customers_group_id'] ."' as customers_group_id, ( " . $p . " * p.products_price) as customers_group_price, p.products_id from products p"); } //if not 0 } //if not Retail } } ?> <!-- body //--> <table border="0" width="100%" cellspacing="2" cellpadding="2"> <tr> <td width="<?php echo BOX_WIDTH; ?>" valign="top"><table border="0" width="<?php echo BOX_WIDTH; ?>" cellspacing="1" cellpadding="1" class="columnLeft"> </table></td> <!-- body_text //--> <td width="100%" valign="top"><table border="0" width="100%" cellspacing="0" cellpadding="2"> <tr> <td width="100%"><table border="0" width="100%" cellspacing="0" cellpadding="0"> <tr> <td class="pageHeading"><?php echo "Special Pricing Discount Setup"; ?></td> <td class="specialPrice" align="right"> </td> </tr> </table></td> </tr> <tr> <td><table border="0" width="100%" cellspacing="0" cellpadding="0"> <tr> <td valign="top"><table border="0" width="100%" cellspacing="2" cellpadding="2"> <tr class="dataTableHeadingRow"> <td class="dataTableHeadingContent" align="left"> <?php if (isset($_POST['Update'])) { echo "<center>Updated!</center>"; } ?> </td> </tr> <?php $sppc_query_raw = "select * from " . TABLE_CUSTOMERS_GROUPS . " order by customers_group_id"; $sppc_query = tep_db_query($sppc_query_raw); while( $sppc = tep_db_fetch_array( $sppc_query ) ) { ?> <tr class="dataTableRow" onmouseover="rowOverEffect(this)" onmouseout="rowOutEffect(this)"> <td class="dataTableContent" align="left"> <?php if ($sppc["customers_group_name"] != "Retail"){ echo $sppc["customers_group_name"]; } if (isset($_POST['Update'])) { if ($sppc["customers_group_name"] != "Retail"){ $c = "CG_".$sppc['customers_group_id']; $tmp = $_POST[$c]; echo " Current Discount is $tmp%" ; } } ?> </td> </tr> <?php } ?> </table></td> </tr> <tr> <td valign="top"> <form action="" method="post"> <table border="0" width="40%" cellspacing="0" cellpadding="2"> <tr> <td class="smallText" align="left"> </td> <td> </td> </tr> <?php $sppc_query_raw = "select * from " . TABLE_CUSTOMERS_GROUPS . " order by customers_group_id"; $sppc_query = tep_db_query($sppc_query_raw); while( $sppc = tep_db_fetch_array( $sppc_query ) ) { if ($sppc["customers_group_name"] != "Retail"){ ?> <tr> <td class="smallText" align="left">Set New Percentage (%) Discount for <?=$sppc["customers_group_name"]?> :</td> <td><input name="CG_<?=$sppc['customers_group_id']?>" type="text" size="5" value="0"></td> </tr> <?php } } ?> <tr> <td colspan="2" align="center"><input type="submit" name="Update" value="Update"></td> </tr> </table> </form> </td> </tr> </table></td> <!-- body_text_eof //--> </tr> </table> <!-- body_eof //--> <!-- footer //--> <?php require(DIR_WS_INCLUDES . 'footer.php'); ?> <!-- footer_eof //--> </body> </html> <?php require(DIR_WS_INCLUDES . 'application_bottom.php'); ?> Hello guys, I want to get the values of 3rd level of my referral but it did not echo any value but if i put the ref id directly on the code, it will echo the values. why is it so? or am i doing it the wrong way? in my database i have a table test_referral id acct_name ref_id refer_id 1 john J1234 0 2 bull B3456 J1234 3 doe D5567 J1234 4 frank F7788 J1234 5 jimmy J9990 J1234 6 tommy T6784 F7788 7 tom T9988 F7788 8 girly G8866 D5567 9 fred F0099 J9990 10 ronaldo R7722 B3456 thanks
$stmt= $pdo->query("SELECT * FROM test_referral WHERE acct_name='Chidi Okafor'");
$parent = $stmt->fetch(PDO::FETCH_LAZY);
echo "<ul><li>";
echo $parent['acct_name'];
$ref_id = $parent['ref_id'];
echo "</li><ul>";
$stmt= $pdo->query("SELECT * FROM test_referral WHERE refer_id='$ref_id'");
$child_count = $stmt->rowCount();
while($child = $stmt->fetch(PDO::FETCH_LAZY)){
echo "<li>";
echo $child['acct_name'];
$ref_ids = $child['ref_id'];
echo "</li>";
}
//$reff = "F7788";
//$stmt= $pdo->query("SELECT * FROM test_referral WHERE refer_id='$F7788'");
$stmt= $pdo->query("SELECT * FROM test_referral WHERE refer_id='$ref_ids'");
$child_count2 = $stmt->rowCount();
while($children = $stmt->fetch(PDO::FETCH_LAZY)){
echo "<ul><li>";
echo $children['acct_name'];
echo "</li></ul>";
}
Edited by Mr-Chidi, 25 December 2014 - 05:34 AM. This problem is existing on a few pages so I'll be in the clear if I can figure out to solve it on one page. Problem is on form submission its still echoing back that sortorder variable which makes it hard for it to compare on the success function to display the right message because the message should be good, bad1, bad2, ... . So is there anyway around that or do I need to do something on the client side of the form page. <?php // Include the database page require ('../inc/dbconfig.php'); if ( isset( $_POST['menuid'] ) ) { $menuid = (int)$_POST['menuid']; $query = "SELECT COUNT(sortorder) AS numOrder FROM `menuitems` WHERE `menu_id` = '".$menuid."'"; $result = mysqli_query ($dbc, $query); $row = mysqli_fetch_array( $result, MYSQL_ASSOC ); $sortorder = $row[ 'numOrder' ] + 1; echo $sortorder; } if (isset($_POST['submitmenuitem'])) { $menuid = mysqli_real_escape_string($dbc, $_POST['menuid']); $itemname = mysqli_real_escape_string($dbc, $_POST['itemname']); $itemurl = mysqli_real_escape_string($dbc, $_POST['itemurl']); $sortorder = mysqli_real_escape_string($dbc, $_POST['sortorder']); $contentpage = mysqli_real_escape_string($dbc, $_POST['contentpage']); $newscategory = mysqli_real_escape_string($dbc, $_POST['newscategory']); $application = mysqli_real_escape_string($dbc, $_POST['application']); $query = "SELECT * FROM `menuitems` WHERE (`itemname` = '".$itemname."') OR (`itemurl` = '".$itemurl."') OR (`contentpage_id` = '".$contentpage."') OR (`application_id` = '".$application."') OR (`newscategory_id` = '".$newscategory."') AND `menu_id` = '".$menuid."'"; $result = mysqli_query ( $dbc, $query ); // Run The Query $rows = mysqli_num_rows($result); if ($rows == 0) { $query = "INSERT INTO `menuitems` (menu_id, itemname, itemurl, sortorder, contentpage_id, newscategory_id, application_id, creator_id, datecreated, enabled) VALUES ('".$menuid."','".$itemname."','".$itemurl."','".$sortorder."','".$contentpage."', '".$newscategory."', '".$application."', 1, NOW(), 0)"; mysqli_query($dbc, $query); echo "good"; } else { $row = mysqli_fetch_array($result); if (($row['itemname'] == $itemname) && ($row['newscategory_id'] == $newscategory)) echo 'bad9'; elseif (($row['itemname'] == $itemname) && ($row['application_id'] == $application)) echo 'bad8'; elseif (($row['itemname'] == $itemname) && ($row['contentpage_id'] == $contentpage)) echo 'bad7'; elseif (($row['itemname'] == $itemname) && ($row['itemurl'] == $itemurl)) echo 'bad6'; elseif ($row['newscategory_id'] == $newscategory) echo 'bad5'; elseif ($row['application_id'] == $application) echo 'bad4'; elseif ($row['contentpage_id'] == $contentpage) echo 'bad3'; elseif ($row['itemurl'] == $itemurl) echo 'bad2'; elseif ($row['itemname'] == $itemname) echo 'bad1'; } } if (isset($_POST['deletemenuitem'])){ $menuitemID = (int)$_POST['menuitemID']; $query = "UPDATE `menuitems` SET `enabled` = '1' WHERE `id` = '".$menuitemID."' LIMIT 1"; mysqli_query($dbc,$query); } ?> $lastfm = file_get_contents('http://www.last.fm/group/Rishloo/members'); $users = explode('" id="r4_', $lastfm); $users = explode('">', $users[1]); var_dump($users[0]); that is only echoing one ID http://www.last.fm/group/Rishloo/members 1 id for each member it should be echoing.. any idea why it isnt? $lastfm = file_get_contents('http://www.last.fm/group/Rishloo/members'); $grab_id=explode('" id="r4_', $lastfm); for($b=1; $b<count($grab_id); $b++){ $getid=explode('">', $grab_id[$b]); echo count($getid[0]); } that echos all 1's.. any help is appreciated.. thanks thanks Hi, I have this variable that checks which page we're on: Code: [Select] <?php $checkit = $_SERVER['PHP_SELF']; ?> and I need to echo some text depending which page we're on. I am using this code to do so: Code: [Select] <?php if ($checkit=="index.php") { echo "this is the home page"; } if ($checkit=="index2.php") { echo "this is the other page"; }?>...but nothing is printed. what am i doing wrong? Thanks Hi, this is how I echo some results from my DB: Code: [Select] <?php if(mysql_num_rows($execute)>0){ do{ echo " " .$result['id_cliente']. " " .$result['company_name']. " " .$result['cliente_tel']. " " ; }while($result = mysql_fetch_assoc($execute)); }else{ echo " No customer found. " ; } ?> and this echoes the results in one paragraph. I need to print the results in rows...and I need help with that. :shy:Thanks Hi, I'm trying to echo some error message like this: Code: [Select] <?php echo (isset($_GET['failed']))?'.CNT_TXT_MYERRORMESSAGE.''; ?> i know it must be a syntax error....but I'm a newb.... Thanks I am probably making a dumb mistake...but heres the code... $gif = '.gif'; $jpg = '.jpg'; $jpeg = '.jpeg'; $png = '.png'; $jpeg1 = 'jpeg'; $gif1 = 'gif'; $jpg1 = 'jpg'; $png1 = 'png'; $max_file_size = '1048576'; $new_avatar = $_FILES['uploaded_avatar']['name']; $avatar_ext = end(explode('.', $new_avatar)); if (isset($_POST['change_submit1'])) { if ($_SESSION['logged_in'] != '1') { echo 'You need to be logged in!'; } elseif ($_POST['change_box1'] != 'CHANGE') { echo 'You must fill in the "CHANGE" box!'; } elseif (($uploaded_a_file == '1') && ($avatar_ext != $jpg1) && ($avatar_ext != $png1) && ($avatar_ext != $gif1) && ($avatar_ext != $jpeg1)) { echo 'File format not supported!'; } elseif ($uploaded_a_file != '1') { echo 'No file selected!'; } elseif ($_FILES["uploaded_avatar"]["size"] > $max_file_size) { echo 'File is too big!'; } } this is the code that should be echoing my avatar upload errors. Ive checked all the if statements ive changed the order around. still nothing. all of them work other than file format not supported. I can get this one to work...but at the cost of no file selected not working...help! i'm not sure whether this should be in this section or the ajax section. i'm trying to echo out an ajax script so that a page loads in a div tag after a link is clicked in the menu. Without the "echo", it works fine, but as soon as i include it within the "echo", it stops working. Any help would be great else echo" <div id='fcontrol'> <table border='1' class ='tstyle'> <tr height ='700'><td valign='top' class='ssbg' width='120'><div id='menu'> <a href='javascript:ajaxpage(''new_section.php'', ''contentarea'');'>Add new section</a><br/><br/> <a href='javascript:ajaxpage('new_sub_section.php', 'contentarea');'>Add new section to forum</a><br/><br/><a href='index.php'>Back to forum</a><br/><br/></div></td><td class='tcontrol' width='700' valign='top'> <center><div id='contentarea'>Control Panel</div></center></td></tr> </table></div> </div> "; ?> I want to echo the contents of column 4 for my username only, and it doesn't show anything. I can do if ($memberQuery->fetchColumn(4) < 2)() though. Code: [Select] $host = 'localhost'; $database = ''; $db_username = ''; $db_password = ''; if (($db = new PDO("mysql:host=$host;dbname=$database", $db_username, $db_password)) == NULL) { echo $db->getMessage(); } $memberQuery = $db->prepare("SELECT * FROM members WHERE username=:username"); $memberQuery->execute(array(':username' => $_SESSION['username'])); $result = $memberQuery->fetchColumn(4); echo "$result"; hi all, I have a piece of code which I coded where it selects all there cars out of the database and shows them, well it is meant to: $getall = mysql_query("SELECT car, id FROM garage WHERE owner='$username'"); $gotall = mysql_fetch_object($getall); echo "$gotall->car - $gotall->id<br />"; Its meant to echo out all the cars which the user own, but for some reason its only echoing one car. Can anyone see why its only showing one car with the id not all the cars they own? Thanks. I have a login form at http://cloydprojects.com you can login with username: test password test If you login the script works correctly, but if you type in the wrong info my session is not showing here is that I have. my login script Code: [Select] <?php session_start(); ?> <link href="signUp.css" rel="stylesheet" type="text/css" /> <?php include("db.php"); include("classes/class.account.php"); $Acc = new account; $u = $Acc->clean($_REQUEST['usernameLogin']); $password = $Acc->clean($_REQUEST['passwordLogin']); $p = md5($password); $get = mysql_query("SELECT * FROM users WHERE username = '".$u."' and password = '".$p."'"); $find = mysql_num_rows($get); if ($find == 1) { $info = mysql_fetch_assoc($get); $_SESSION['LoggedIn'] = $info['uID'].'.'.$info['username'].'.'.$info['email']; } else { $_SESSION['LoggedFailed'] = '<div id="ErrorBox">Incorrect username/password!</div>'; } //there is more just not showing it here is my index script where the error should be showing! Code: [Select] <div class="stylized"> <?php if(isset($_SESSION['LoggedIn'])) { echo '<h1> Welcome! </h1>'; echo '<a href="logout.php">logout!</a>'; } else { echo $_SESSION['LoggedFailed']; session_destroy(); ?> <form id="instantform" name="form" action="loginUser.php" method="post"> <h1>Login</h1> <label>Username <span class="small">The username you created!</span></label> <input type="text" name="usernameLogin" id="usernameLogin" /> <label>Password <span class="small">Case sensitive!</span></label> <input type="password" name="passwordLogin" id="passwordLogin" /> <button type="submit">Login</button></div> <div class="spacer"></div> </form> <?php } ?> </div> Hi all, On my website I have a Functions file which holds information about the user for the game, but earier on today I added ranks which are for the users money. So for the ammout of money they have gives them a different money rank. Heres what ive got: function wealthrank(){ if (($info->money >= "0") && ($info->money < "10000")){ $wealth = "Poor (£0 - £10,000)"; $done="1"; } elseif (($info->money >= "10000") && ($info->money < "500000")){ $wealth = "Won The Lottery (£10,000- £500,000)"; $done="1"; } elseif (($info->money >= "500000") && ($info->money < "5000000")){ $wealth = "Too Much (£500,000 - £5,000,000)"; $done="1"; } elseif (($info->money >= "5000000") && ($info->money < "20000000")){ $wealth = "Millionare (£5,000,000 - £20,000,000)"; $done="1"; } elseif (($info->money >= "20000000") && ($info->money < "75000000")){ $wealth = "Owns The Streets (£20,000,000 - £75,000,000)"; $done="1"; } elseif (($info->money >= "75000000") && ($info->money < "100000000")){ $wealth = "Won The Euro Millions (£75,000,000 - £100,000,000)"; $done="1"; } elseif (($info->money >= "100000000") && ($info->money < "300000000")){ $wealth = "Multi millionare (£100,000,000 - £300,000,000)"; $done="1"; } elseif (($info->money >= "300000000") && ($info->money < "700000000")){ $wealth = "Owns A Bank (£300,000,000 - £700,000,000)"; $done="1"; } elseif (($info->money >= "700000000") && ($info->money < "1500000000")){ $wealth = "Rather Rich (£700,000,000 - £1,500,000,000)"; $done="1"; } elseif (($info->money >= "1500000000") && ($info->money < "5000000000")){ $wealth = "Billionare (£1,500,000,000 - £5,000,000,000)"; $done="1"; } elseif (($info->money >= "5000000000") && ($info->money < "70000000000")){ $wealth = "Owner Of The Land (£5,000,000,000 +)"; $done="1"; } elseif ($info->money >= "100000000000"){ $wealth = "Nearly As Rich As NoName (Hidden!)"; $done="1"; } if (!$done){ $done="0"; } if ($done == "1"){ mysql_query("UPDATE users SET wealthrank='$wealth' WHERE username='$username'"); }} wealthrank(); For some reason its not echoing the correct wealth rank, even at that its only echoing the defult wealth rank. Here is what I done to test it. <?php session_start(); include ("includes/functions.php"); include ("includes/config.php"); logincheck(); $username = $_SESSION['username']; $get = mysql_query ("SELECT * FROM users WHERE username='$username'"); $fetch = mysql_fetch_object($get); ?> Testing something: <?php echo ($username); ?><br /> Wealth Rank: <?php echo ($fetch->wealthrank); ?><br /> Is there something wrong with the way im fetching it from the Database or something wrong with the code? Thanks for any help given. how do i echo "checked=checked" for a checkbox? here is what i have: Code: [Select] <input type='checkbox' name='ip_automatic_login' id='ip_automatic_login' value='1' if($IPCheck == true) {/"checked=checked/" } /> this code will be echoed! This code is suppose to echo out ALL the custom pages that are in the database, but it's only show ONE. Why is this? $query_get = mysql_query("SELECT COUNT(id),id,position,content,title FROM custom_pages ORDER BY id"); while($row = mysql_fetch_assoc($query_get)) { echo '<table border="0"> <tr><th><p>Title</p><td>'. $row['title'] .'</td></tr> <tr><th><p>Position</p><td>'. $row['position'] .'</td></tr> <tr><th><p>Action</p><td><a href="index.php?pages=1&delete='. $row['id'] .'">Delete</a> or <a href="index.php?pages=1&edit='. $row['id'] .'">Edit</a></td></tr> </table> '; } i am having issues checking which value is checked in a form. here is my code for it: Code: [Select] <input type="radio" name="accountActivation" id="no" value="no" checked=" <? if (isset($register_errors)) { if (($_POST['accountActivation']) == "no") { echo "checked"; } } ?> " /> when i first open the page, no is checked. why is this, when there should be no errors, and the radio should not even be checked in the first place? i have a form, and if the form has not been sent, it shows the form. here is my code for the beginning: Code: [Select] if($sent != true) { echo" ?> <div class='form'><form action='' method='post'> [b]!!![/b] <p class='form'>User ID: <br /><input name='memberID' type='hidden' value='<?php echo $row['id'] ?>' /> Your User ID will be logged for identity purposes. <br /><input type='checkbox' name='noIdentity' id='noIdentity' value='noIdentity' <?php if(isset($_POST['errors']) && isset($_POST[noIdentity])) { [b]!!![/b] echo ' checked='checked '"; } ?> /> and the end: Code: [Select] <?php "; } ?> it doesn't like what i have the exclamations next to. also, am i doing this right? I have stored some texts in the database associated with a variable name in my database ... I intend to use this in my site as global text using the variable name ... This is the code I've created in a php file, which I'm 'including' in my webpage .
<div style="display:none">
<?php
mysqli_select_db($xxx, $database_xxx);
$query_Recordset1 = "SELECT * FROM text_declares";
$Recordset1 = mysqli_query($xxx, $query_Recordset1) or die(mysqli_error());
$row_Recordset1 = mysqli_fetch_assoc($Recordset1);
$totalRows_Recordset1 = mysqli_num_rows($Recordset1);
?>
<?php do {
echo '$' . $row_Recordset1['bd_variable'] . ' = "' . $row_Recordset1['bd_desc'] . '"<br>';
} while ($row_Recordset1 = mysqli_fetch_assoc($Recordset1));
echo 'Company Name =' . $company_full_name ;
?>
</div>
When i execute the file, this is the ouput Quote
$company_full_name = "Some Company Pvt. Ltd." not able to figure out why the $company_full_name is not showing in the echo. Many Thanks for the support . Hey i'm just woundering how i would echo numbers from a database like 1000000 lets say 1 million how would i go about on echoing it like this 1,000,000 ZhsHero |
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