PHP - Insert Dynamic Number Of Checked Box Values To Database
What I have so far is a page that produces a list of usernames with checkboxes next to them. From the usernames that I check, I want to update a field for each of those users. My problem is that the number of checkboxes I check is not going to be static so I am pretty sure I have to run a loop based on the number of checked checkboxes ("People chosen"). Here is what I have so far:
Code: [Select] <?php if (isset($_POST['submit1'])) { $pick = $_POST["pick"]; $how_many = count($pick); echo 'People chosen: '.$how_many.'<br><br>'; echo "<br><br>"; $count = 0; while ($count < $how_many) { //mysql code probably should go here but I am stuck $count++; } } else { $gender = mysql_real_escape_string($_POST['Gender']); $limit = mysql_real_escape_string($_POST['limit']); echo $gender; echo "<br />"; $count = 0; if ($gender == 'Male') { $result = mysql_query("SELECT * FROM users WHERE gender =\"1\" LIMIT 0, $limit", $connection); if (!$result) { die("Database query failed: " . mysql_error()); } ?> <form method="post"> <?php while ($row = mysql_fetch_array($result)) { ?> <input name="pick[]" type="checkbox" value="<?php echo $row['username'] ?>"><?php echo $row['username'];?> <br /> <?php } ?> <input type="submit" name="submit1" value="Make Offer" /> </form> <?php } ?> I hope this makes sense. Any help would be greatly appreciated. Similar TutorialsI use the following code to generate a scrollable checkbox list of options: Code: [Select] <html> <form action="SCRIPT.php"> <?php $expList = array('Engineering ','Science', 'Art', 'IT', 'Electronics', 'Communications'); sort($expList); $tmp = array(); $i = 1; $tmp[] = '<ul style="height: 95px; overflow: auto; width: 200px; border: 1px solid #480091; list-style-type: none; margin: 0; padding: 0;">'; foreach ($expList as $option) { $tmp[] = '<li id="li' . $i . 'b"><label for="chk' . $i . 'b"><input name="chk' . $i . 'b" id="chk' . $i . 'b" type="checkbox" onchange="Enable(\'chk' . $i . 'b\',\'li' . $i . 'b\')">' . $option . '</label></li>'; $i++; } $tmp[] = '</ul>'; echo implode("\n",$tmp) . "\n"; ?> <input type="submit"> </form> </html> But there are in fact over 50 options (not just 6) and they are in fact stored in an array $expList in an external php file called LISTS.php. As you can see, the checkbox list consists of checkboxes chk1b, chk2b, chk3b, etc. with associated labels (Art, Communications, Electronics, etc.). What I need in SCIPT.php is code that will insert each of the labels where the associated checkbox has been checked in my MySQL database. E.g. in this particular case: if chk1b & chk3b have been checked, 'Art' & 'Electronics' will be inserted. Also, I want the label of the first checked checkbox to be inserted in the (database) table column 'Exp1', the 2nd one in 'Exp2'.........25th one in 'Exp25' (I already have a script that allows a maximum of 25 checkboxes to be checked). I'm guessing some sort of 'foreach' loop is required, but I can't quite work it out. Pls help! Many thanks! I have a table made up of time slots, when the user clicks maybe one or two and presses submit, i would like the date selected and the time slots chosen to be saved in to my sql.
I am working on the query but a little stuck in regards to the query, i have done the following:
<?php $username = "root"; $password = ""; $hostname = "localhost"; $dbhandle = mysql_connect($hostname, $username, $password) or die ("no connection to database"); if(isset($_POST['Submit'])){ $start = mysql_real_escape_string($_POST['start']); $end = mysql_real_escape_string($_POST['end']); $booked = mysql_real_escape_string($_POST['booked']); $selected = mysql_select_db("booking", $dbhandle); ?>i have set the table as follows <input data-val='08:30 - 08:45' class='fields' type='checkbox' name="booked[]" /> Hi everyone. I have a registration form on my website that returns errors if the form isnt filled out correctly. An example of the code that returns the errors is: // if first name is blank return error if (!$first_name) { echo "Please enter your first name!<br />"; } // if first name contains invalid charcters return error if (preg_match('/[^a-zA-Z\s]/', $first_name)) { echo "Your first name contains invalid charcters!<br />"; } // set first name maximum length if ($first_name && !preg_match('/[^a-zA-Z0-9\s]/', $first_name)) { if (strlen($first_name) >25) { echo "The maximum length for first name is 25 characters!<br />"; } } Iv wrote it like this so that i can get multiple error messages appearing at the same time. When it comes to writing the form data to the database im using the following: if ($first_name && !preg_match('/[^a-zA-Z\s]/', $first_name) && strlen($first_name) <26 && $last_name && !preg_match('/[^a-zA-Z\s]/', $last_name) && strlen($last_name) <26 && $dob_day != "Day" && $dob_month != "Month" && $dob_year != "Year" && $gender != "Select" && $email && filter_var($email, FILTER_VALIDATE_EMAIL) && $confirm_email && $email == $confirm_email && $email_count == 0 && $town && !preg_match('/[^a-zA-Z0-9\s]/', $town) && strlen($town) < 26 && $location != "Select" && $postcode && !preg_match('/[^a-zA-Z0-9\s]/', $postcode) && $username && !preg_match('/[^a-zA-Z\s]/', $username) && strlen($username) >2 && strlen($username) <25 && $username_count == 0 && $password && strlen($password) >5 && strlen($password) <26 && $confirm_password && $password == $confirm_password) { // code to write to database here } I was wondering if there was a better way to confirm that all the form data is ok, and if so write the data to the database? Im new to php and would love to learn a way to make this easier instead of typing out loads of lines of code. Thanks to anyone that can help me. Hi all, I've made a page the variables are being recieved and echo'd ok, however they are not being inserted into the database. below is the file with the insert statement. any help really appreciated. MsKazza Code: [Select] <?php // Database connect $con = mysql_connect("mysql1.myhost.ie","admin_book","root123"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("book_test", $con); $orderid=$_GET['orderid']; //Parse Values from Coupon.php Form $orderid = mysql_real_escape_string(trim($_POST['orderid'])); $design = mysql_real_escape_string(trim($_POST['design'])); $childname = mysql_real_escape_string(trim($_POST['childname'])); $address = mysql_real_escape_string(trim($_POST['address'])); echo $orderid; echo $design; echo $childname; echo $address; $sql="INSERT INTO details (orderid, design, childname, address) VALUES ('$orderid','$design','$childname','$address')"; ?> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /> <title>Digital Scribe Books</title> <link href="style.css" rel="stylesheet" type="text/css" /> <script type="text/javascript"> function MM_preloadImages() { //v3.0 var d=document; if(d.images){ if(!d.MM_p) d.MM_p=new Array(); var i,j=d.MM_p.length,a=MM_preloadImages.arguments; for(i=0; i<a.length; i++) if (a[i].indexOf("#")!=0){ d.MM_p[j]=new Image; d.MM_p[j++].src=a[i];}} } function MM_swapImgRestore() { //v3.0 var i,x,a=document.MM_sr; for(i=0;a&&i<a.length&&(x=a[i])&&x.oSrc;i++) x.src=x.oSrc; } function MM_findObj(n, d) { //v4.01 var p,i,x; if(!d) d=document; if((p=n.indexOf("?"))>0&&parent.frames.length) { d=parent.frames[n.substring(p+1)].document; n=n.substring(0,p);} if(!(x=d[n])&&d.all) x=d.all[n]; for (i=0;!x&&i<d.forms.length;i++) x=d.forms[i][n]; for(i=0;!x&&d.layers&&i<d.layers.length;i++) x=MM_findObj(n,d.layers[i].document); if(!x && d.getElementById) x=d.getElementById(n); return x; } function MM_swapImage() { //v3.0 var i,j=0,x,a=MM_swapImage.arguments; document.MM_sr=new Array; for(i=0;i<(a.length-2);i+=3) if ((x=MM_findObj(a[i]))!=null){document.MM_sr[j++]=x; if(!x.oSrc) x.oSrc=x.src; x.src=a[i+2];} } </script> </head> <body onload="MM_preloadImages('images/buttons/home_over.png','images/buttons/books_over.png','images/buttons/cards_over.png','images/buttons/letters_over.png')"> <div id="snow"> <div id="wrapper"> <div id="header"> <div id="logo"><img src="images/digital_scripe.png" width="218" height="91" /></div> <div id="menu"><a href="index.php" onmouseout="MM_swapImgRestore()" onmouseover="MM_swapImage('Home','','images/buttons/home_over.png',1)"><img src="images/buttons/home_act.png" name="Home" width="131" height="132" border="0" id="Home" /></a><a href="books.php" onmouseout="MM_swapImgRestore()" onmouseover="MM_swapImage('Books','','images/buttons/books_over.png',1)"><img src="images/buttons/books_act.png" name="Books" width="131" height="132" border="0" id="Books" /></a><a href="cards.php" onmouseout="MM_swapImgRestore()" onmouseover="MM_swapImage('Cards','','images/buttons/cards_over.png',1)"><img src="images/buttons/cards_act.png" name="Cards" width="131" height="132" border="0" id="Cards" /></a><a href="letters.php" onmouseout="MM_swapImgRestore()" onmouseover="MM_swapImage('Letters','','images/buttons/letters_over.png',1)"><img src="images/buttons/letters_act.png" name="Letters" width="131" height="132" border="0" id="Letters" /></a></div> </div> <div id="content"> <div id="info_bar"><br /><br /><br /> <p>Your personal order number is:</p><br /> <br /> <p>Please fill out the details of where you would like your order to be shipped to.</p> </div> <form action="card_paynow.php" method="POST" name="custdetails" id="custdetails"> <table width="60%" border="0" cellspacing="0" cellpadding="0"> <tr> <td width="19%">orderid</td> <td width="81%"><input name="orderid" type="hidden" value="<? echo $orderid; ?>"></td> </tr> <tr> <td>name</td> <td><input name="name" type="text" id="name"></td> </tr> <tr> <td>surname</td> <td><input name="surname" type="text" id="surname"></td> </tr> <tr> <td>address 1 </td> <td><input name="add1" type="text" id="add1"></td> </tr> <tr> <td>address 2 </td> <td><input name="add2" type="text" id="add2"></td> </tr> <tr> <td>town</td> <td><input name="town" type="text" id="town"></td> </tr> <tr> <td>county</td> <td><input name="county" type="text" id="county"></td> </tr> <tr> <td>postcode</td> <td><input name="postcode" type="text" id="postcode"></td> </tr> <tr> <td>number</td> <td><input name="phone" type="text" id="phone"></td> </tr> <tr> <td>email</td> <td><input name="email" type="text" id="email"></td> </tr> <tr> <td> </td> <td> </td> </tr> <tr> <td> </td> <td><input type="submit" name="Submit" value="Continue..."></td> </tr> <tr> <td> </td> <td> </td> </tr> </table> </form> </div> <div id="footer" class="clear"><div id="sign"><div id="sign_text">Personalised<br /> Books</div> </div></div> </div></div> </body> </html> I know it's maybe EASY but how can I insert datas into database from multi-select html form? Here is the code: Code: [Select] <body><form action="<?=$_SERVER['PHP_SELF']?>" method="post"> <select name="test[]" multiple="multiple"> <option value="one">one</option> <option value="two">two</option> <option value="three">three</option> <option value="four">four</option> <option value="five">five</option> </select> <input type="submit" value="Send" /> </form> <?php $test=$_POST['test']; if ($test){ foreach ($test as $t){echo 'You selected ',$t,'<br />';} } ?></body>Any ideas how to modify the above code so I can INSERT INTO values from multi-select box? Hi,
I'm trying to insert calculate values to DB.this is my code
<?php require('dbconnection.php'); $a=$_POST['a']; $b=$_POST['b']; class cal{ public function insert($a,$b){ if((($a)&&($b))!="") { $c=$a*$b; $sql = "INSERT INTO cropplant (sbetweenQ ,sbetweenC ,sbetweenTC ) VALUES ('$a', '$b', '$c')"; $query = mysql_query($sql); if(!$query) { echo '<script type="text/javascript">alert("DB Update error ! please Re-enter your details.");</script>'; }else { echo '<script type="text/javascript">alert("New Cropplant Added Successfuly.");</script>'; } }else{ echo"please enter all"; } } } ?>what is the error in this code.please help Hi everyone, I'm new to this group and new to php. I have created a multi-part form that allows the user the option to add multiple input fields to a form to upload images. Here is the form structu Code: [Select] <form action="Scripts/processreports2.php" method="post" enctype="multipart/form-data" name="report_form" target="uploader" class="reportfrm"> <fieldset> <legend>Upload your images</legend> <ol id="add_images"> <li> <input type="file" class="input" name="files[]" /> </li> <li> <input type="file" class="input" name="files[]" /> </li> <li> <input type="file" class="input" name="files[]" /> </li> </ol> <input type="button" name="addFile" id="addFile" value="Add Another Image" onclick="window.addFile(this);"/> </fieldset> <p>* indicates a required field.</p> <input name="submit" type="submit" id="submit" value="Send Info!" /> </form> Through php a maximum of three input fields are fed into an array that checks to make sure that the uploaded files are images and not some other type of file. The uploading porition of this script works. Now I am trying to get the values of the input fields as a string and insert them into the database as one record. Let's say the user has three files they want to upload. I have managed to get the files as a string ie; file1.jpg, file2.jpg, file3.jpg but what is happening is that I am getting three separate records with file1.jpg, file2.jpg, file3.jpg in them. If the user has only two files to upload then I get two separate records with file1.jpg and file2.jpg in them. (Hope that makes sense). I want one record. I have been struggling with this since Monnday and while every day I get closer, this is as close as I can get. Below is the php code. #connect to the database mysql_connect("localhost", "root", ""); mysql_select_db("masscic"); //Upload Handler to check image types function is_image($file) { $file_types = array('jpeg', 'gif', 'bmp'); //acceptable file types if ($img = getimagesize($file)){ //echo '<pre>'; //print_r($_FILES); used for testing //print_r($img); used for testing if(in_array(str_replace('image/', '', $img['mime']), $file_types)) return $img; } return false; } //form submission handling if(isset($_POST['submit'])) { //file variables $fname = $_FILES['files']['name']; $ftype = $_FILES['files']['type']; $fsize = $_FILES['files']['size']; $tname = $_FILES['files']['tmp_name']; $ferror = $_FILES['files']['error']; $newDir = '../uploads/'; //relative to where this script file resides for($i = 0; $i < count($fname); $i++) { //echo 'File name ' . $fname[$i] . ' has size ' . $fsize[$i]; used for testing if ($ferror[$i] =='UPLOAD ERR OK' || $ferror[$i] ==0) { if(is_image($tname[$i])) { //append the tmp_name($tname) to the file name ($fname) and upload to the server move_uploaded_file($tname[$i], ($newDir.time().$fname[$i])); echo '<li><span class="success">'.$fname[$i].' -- image has been accepted<br></span></li>'; }else echo '<li><span class="error">'.$fname[$i].' -- is not an accepted file type<br></span></li>'; } if (is_array($fname)) $files = implode(', ',$fname); //else $files = $fname; $sqlInsert = mysql_query("INSERT INTO files (file_names) VALUES('$files')") or die (mysql_error()); } } Hello everyone I need code for this question
would you help me please..?
Please guys, I need your help on this one. How can call the data from mysql and make the values checked on the checkboxes Have got three tables. I am retrieving data and updating two tables at once... Dear All Members here is my table data.. (4 Columns/1row in mysql table)
id order_no order_date miles How to split(miles) single column into (state, miles) two columns and output like following 5 columns /4rows in mysql using php code.
(5 Columns in mysql table) id order_no order_date state miles 310 001 02-15-2020 MI 108.53 310 001 02-15-2020 Oh 194.57 310 001 02-15-2020 PA 182.22
310 001 02-15-2020 WA 238.57 ------------------my php code -----------
<?php
if(isset($_POST["add"]))
$miles = explode("\r\n", $_POST["miles"]);
$query = $dbh->prepare($sql);
$lastInsertId = $dbh->lastInsertId(); if($query->execute()) {
$sql = "update tis_invoice set flag='1' where order_no=:order_no"; $query->execute();
} ----------------- my form code ------------------
<?php -- Can any one help how to correct my code..present nothing inserted on table
Thank You Edited February 8, 2020 by karthicbabuhi all I have 3 checkboxes whose values are getting stored in the database with a comma separator. Code: [Select] <input name="color[]" type="checkbox" value="red" id="red" />red <input name="color[]" type="checkbox" value="blue" id="blue" />blue <input name="color[]" type="checkbox" value="green" id="green" />green values getting stored with comma separator Code: [Select] red, blue, green now i want to show the checkboxes as "checked" to show the customer as which colors they chose lasttime when they submitted the form. How can i make it possible ? If it is possible without the comma separator then i can remove the comma. vineet Hello,
I want to show checkbox is checked when there is entry of that id in a table in my database.
I have 2 tables page and access_level. I am getting data from page table and displays it in <ul><li> tag with checkbox to select all or only few. After selecting the checkbox, i will store only selected checkbox value in access_level table along with table id. Page link and page name details will be stored in page table.
Now if i want to edit , i should display all the pages which is there in page table and i should also mark checked to those which are already stored in access_level table.
I am using LEFT OUT JOIN, It displays all the pages. But it is not displaying the check mark to those which are already selected.
Here is my code
<?php $s1 = mysql_query("SELECT pages.page_id, pages.code, pages.page, pages.href, access_level.aid, access_level.page_id as pgid, access_level.department, access_level.position, access_level.active FROM pages LEFT OUTER JOIN access_level ON pages.page_id=access_level.page_id WHERE access_level.department=".$department." AND access_level.position=".$position." AND pages.code='sn'") or die(mysql_error()); while($s2 = mysql_fetch_array($s1)) { ?> <tr><td><li><?php echo $s2['page']; ?> </td><td><input type="checkbox" name="sn[]" value="<?php echo $s2['page_id']; ?>" <?php if($row['pgid'] === $s2['page_id']) echo 'checked="checked"';?> />here is my pages table pages.JPG 26.55KB 0 downloads access_level access_level.JPG 19.09KB 0 downloads In access_level table i do not have page ids 8 and 9. But i want to display that also from pages table and for 1 to 7 and 10 i should display check mark. How i can achieve this? Please Help I need to create a custom PK similar to 000111-GH. whe 0001 is the counter 11 is the year GH i need randomly generated with either numbers/letters once 2012 occurs, i need the counter to be reset to 000112-DF How would i increment 0001 until 2012, then reset the first few digits back to 0001? similarly, i will have a linked table but will have a different autonumber format for client 1 the linked data would look look like this 000111-GH-001 for record 1 000111-GH-002 for record 2 but then for client 2 000211-DS-001 00211-DS-002 Can anyone provide any assistance on how to accomplish this? thank you. Hi, I'm quite new to OOP PHP and i'm trying to make a dynamic insert function , i've followed an example on Stackoverflow to do so since its my first try at making something dynamic.http://stackoverflow...3333344/3559635 It works but im still quite confused about the two foreach loops , and if possible could someone explain that part to me please and or is there an easier more clean way to do this for a new guy like me? Im sending my POST values from the index.php <?php include("Database.php"); $db = new Database(); var_dump($db); $table = "users"; $whitelist = array('username', 'password'); $data = array_intersect_key($_POST, array_flip($whitelist)); if(isset($_POST['username']) AND ($_POST['password'])) { $db->postTesting($data, $table); } else { echo "Please fill in everything!"; }Database.php <?php class Database { private $connection; private $typedb = "mysql"; private $host = "127.0.0.1"; private $dbname = "oopphp"; private $username = "root"; private $password = ""; public function __construct() { try{ $this->connection = new PDO($this->typedb. ":host=".$this->host. ";dbname=".$this->dbname, $this->username, $this->password); $this->connection->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); return $this->connection; } catch(PDOException $e) { throw new Exception("Connection failed: ".$e->getMessage()); } } public function postTesting($data, $table) { try{ //var_dump($table, $data); $columns = ""; $holders = ""; foreach ($data as $column => $value) { //var_dump($column); //var_dump($value); $columns .= ($columns == "") ? "" : ", "; $columns .= $column; $holders .= ($holders == "") ? "" : ", "; $holders .= ":$column"; //var_dump($columns); //var_dump($holders); } $sql = "INSERT INTO $table ($columns) VALUES ($holders)"; //return $sql; $stmt = $this->connection->prepare($sql); //var_dump($stmt); foreach ($data as $placeholder => $value) { $stmt->bindValue(":$placeholder", $value); //var_dump($stmt); //var_dump($placeholder); //var_dump($value); } //var_dump($sql); //var_dump($stmt); $stmt->execute(); } catch(PDOException $rError) { throw new Exception("Registering Failed: ".$rError->getMessage()); } } }Im seriously confused about this part. foreach ($data as $column => $value) { //var_dump($column); //var_dump($value); $columns .= ($columns == "") ? "" : ", "; $columns .= $column; $holders .= ($holders == "") ? "" : ", "; $holders .= ":$column"; //var_dump($columns); //var_dump($holders); }Thanks in advance for the help Edited by iPwNix, 17 January 2015 - 09:44 AM. after cloasing connection of database i still got the values form database. Code: [Select] <?php session_start(); /* * To change this template, choose Tools | Templates * and open the template in the editor. */ require_once '../database/db_connecting.php'; $dbname="sahansevena";//set database name $con= setConnections();//make connections use implemented methode in db_connectiong.php mysql_select_db($dbname, $con); //update the time and date of the admin table $update_time="update admin set last_logged_date =CURDATE(), last_log_time=CURTIME() where username='$uname'limit 3,4"; //my admin table contain 5 colums they are id, username,password, last_logged_date, last_log_time $link= mysql_query($update_time); // mysql_select_db($dbname, $link); //$con=mysql_connect('localhost', 'root','ijts'); $result="select * from admin where username='a'"; $result=mysql_query($result); mysql_close($con); //here i just check after closing data baseconnection whether i do get reselts but i do, why? echo "after the cnnection was closed"; if(!$result){ echo "cont fetch data"; }else{ $row= mysql_fetch_array($result); echo "id".$row[0]."usrname".$row[1]."passwped".$row[2]."date".$row[3]."time".$row[4]; } // echo "<html>"; //echo "<table border='1' cellspacing='1' cellpadding='2' align='center'>"; // echo "<thead>"; // echo"<tr>"; // echo "<th>"; // echo ID; // echo"</th>"; // echo" <th>";echo Username; echo"</th>"; // echo"<th>";echo Password; echo"</th>"; // echo"<th>";echo Last_logged_date; echo "</th>"; // echo "<th>";echo Last_logged_time; echo "</th>"; // echo" </tr>"; // echo" </thead>"; // echo" <tbody>"; //while($row= mysql_fetch_array($result,MYSQL_BOTH)){ // echo "<tr>"; // echo "<td>"; // echo $row[0]; // echo "</td>"; // echo "<td>"; // echo $row[1]; // echo "</td>"; // echo "<td>"; // echo $row[2]; // echo "</td>"; // echo "<td>"; // echo $row[3]; // echo "</td>"; // echo "<td>"; // echo $row[4]; // echo "</td>"; // echo "</tr>"; // } // echo" </tbody>"; // echo "</table>"; // echo "</html>"; session_destroy(); session_commit(); echo "session and database are closed but i still get values from doatabase session is destroyed".$_SESSION['admin']; ?> session is destroyed but database connection is not closed. thanks Hello:
How could I use php to automatically insert the correct 3 letter month abbreviations and four digit year in the following pdf filenames on the first of each month?
(For example "...Feb2015.pdf" then "...Mar2015.pdf" and so on....
<div>Book One: <a href="http://monthlybookfi...One_Jan2015.pdf">Download Here</a></div> <div>Book Two: <a href="http://monthlybookfi...Two_Jan2015.pdf">Download Here</a></div> <div>Book Three: <a href="http://monthlybookfi...ree_Jan2015.pdf">Download Here</a> </div> <div>Book Four: <a href="http://monthlybookfi...our_Jan2015.pdf">Download Here</a> </div> Please advise, Eggie Hello everyone, I'm trying to code a section of the site which is like an advertising website (i.e, gumtree) where people can post an Ad on the site and have any responses sent to them via email. The thing is that I have a form where they can enter their details and need to POST the information to the following page which is a preview page of their Ad. I have the form action returning to the same page for validation but I need the $_POST vaules to populate the following page without sending information to the database (in an effort to keep the database clean should they decide not to publish their Ad. There are 3 pages in total CREATE AD > PREVIEW AD (where they can go back and edit if they need to) > Publish AD (where they confirm terms and send to database). I do have session variables already set after login in and a seperate table to hold the details after they have confirmed the Ad & terms. Any ideas would be greatly appreciated. Thanks, L-plate hello I want query from one table and insert in another table on another domain . each database on one domain name. for example http://www.site.com $con1 and http://www.site1.com $con. can anyone help me? my code is : <?php $dbuser1 = "insert in this database"; $dbpass1 = "insert in this database"; $dbhost1 = "localhost"; $dbname1 = "insert in this database"; // Connecting, selecting database $con1 = mysql_connect($dbhost1, $dbuser1, $dbpass1) or die('Could not connect: ' . mysql_error()); mysql_select_db($dbname1) or die('Could not select database'); $dbuser = "query from this database"; $dbpass = "query from this database"; $dbhost = "localhost"; $dbname = "query from this database"; // Connecting, selecting database $con = mysql_connect($dbhost, $dbuser, $dbpass) or die('Could not connect: ' . mysql_error()); mysql_select_db($dbname) or die('Could not select database'); //query from database $query = mysql_query("SELECT * FROM `second_content` WHERE CHANGED =0 limit 0,1"); while($row=mysql_fetch_array($query)){ $result=$row[0]; $text=$row[1]."</br>Size:(".$row[4].")"; $alias=$row[2]; $link = '<a target="_blank" href='.$row[3].'>Download</a>'; echo $result; } //insert into database mysql_query("SET NAMES 'utf8'", $con1); $query3= " INSERT INTO `jos_content` (`id`, `title`, `alias`, `) VALUES (NULL, '".$result."', '".$alias."', '')"; if (!mysql_query($query3,$con1)) { die('Error: text add' . mysql_error()); } mysql_close($con); mysql_close($con1); ?> Hi again , I am stuck with simplest problem of array .. i searched all forums and couldn't find similar problem.. Iam collecting array post data "data m_name[][email]" from a form, but I don't know how to get 2 array variables at the same time, here's what I tried : <form action="" method="post" name="myForm"> <div> <input type="text" name="m_name[]" /> <input type="text" name="m_name[][email]" /> </div> <div> <input type="text" name="m_name[]" /> <input type="text" name="m_name[][email]" /> </div> <div> <input type="text" name="m_name[]" /> <input type="text" name="m_name[][email]" /> </div> <input type="submit" name="button" id="button" value="Submit" /> </form> other page where I want to receive above array <?php if($_POST) { print_r($_POST['m_name']); // Output is : Array ( [0] => someone [1] => Array ( [email] => 3 ) [2] => someone two [3] => Array ( [email] => 4 ) [4] => someone three [5] => Array ( [email] => 5 ) ) while (list ($key,$val) = @each ( $_POST['m_name'])) { echo $val.val2 ???"<br/>"; // here I want to get both value $_POST['m_name'] and $_POST['m_name'] ['email'] since I am putting them in db << } } ?> I want to get both values of $_POST['m_name'], I don't know how to do it or is there another way to do it? thankx in advance!! phpfreaks have been very helpful .. |