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PHP - Help With A Admin Panle
So i got my login down and the cookies, kinda set up
my problem is how do i make the admin panle save the true/false in the string in settings.php id like do do it with a drop down menu to enable/disable it. any help? Code download Similar Tutorialshello. I need your help please. I'm building logistics website with user panel and admin panel. I've done all login and register forms. now I want to : admin can add package with: tracking number , weight , cost , and declaration form. user can fill declaration form after admin add package to user panel. then admin can see the declared form. is it possible in php? thank you in advance Hi, I am new here 🙂 I have been learning PHP and am currently working on my own OOP MVC CMS. I am up to the stage where I would like to start working on the admin area, but I am not sure how best to organise things. Should I create admin specific Controllers and Models? In Views, should I create a sub directory Admin, and place all admin view templates within it? Are there any good books on OOP/MVC you would recommend?
Hello I am trying to add an IF statement to my login script so that if the username entered is 'admin' it directs to 'adminpage.php Here is my script: <?php include ("connection.php"); session_start(); // Collect data from form and save in variables //See if any info was submitted $Username = $_GET['Username']; //Clean data - trim space $Username = trim ( $Username); //Check its ok - if not then add an error message to the error string if (empty($Username)) $errorString = $errorString."<br>Please supply Username."; //See if any info was submitted $Password = $_GET['Password']; //Clean data - trim space $Password = trim ( $Password); //Check its ok - if not then add an error message to the error string if (empty($Password)) $errorString = $errorString."<br>Please supply Password."; // Query to search the user table $query= "SELECT * FROM Users WHERE Username='$Username' AND Password='$Password'"; // Run query through connection $result = mysql_query ($query); $row = mysql_fetch_assoc($result); // if rows found set authenticated user to the user name entered if (mysql_num_rows($result) > 0) { $_SESSION["authenticatedUser"] = $Username; $_SESSION['UserID'] = $row['UserID']; // Relocate to the logged-in page header("Location: loggedon.php"); } else // login failed redirect back to login page with error message { $_SESSION["message"] = "Could not connect as $Username " ; header("Location: login.php"); } ?> Thank you Hey guys, I've set up a database with a login and logout script for my site.. There is a TINYINT value called admin and it either equals 1 or 0 depending on whether the user is an admin or not.. The registration script works perfectly to create the table value and the login script works fine for the site.. The question I had was if I wanted to add a link to the bottom of every page that said: Go to Administration Panel and make it only viewable by ADMINS I figured this little script would work.. Here would be the end of the page: Code: [Select] <br /> <center>Copyright © 2010 <a href="http://www.website.com">www.WEBSITE.com</a></center> <?php include('includes/start_admincheck.php'); ?> <center><a href="<?php echo $homedir .'admin.php'; ?>">Go to Administration Panel</a></center> <?php include('includes/end_admincheck.php'); ?> </body> </html> Inside start_admincheck.php I have: (NOTE: $cUsername refers to a setcookie and $cAdmin does as well.. They are defined on my Variable page included at the top.) Code: [Select] <?php include('variables/variables.php'); ?> <?php mysql_connect("$mysql_hostname", "$mysql_username", "$mysql_password") or die(mysql_error()); mysql_select_db("$mysql_database") or die(mysql_error()); if(isset($cUsername)) { $check = mysql_query("SELECT * FROM users WHERE username = '$cUsername'")or die(mysql_error()); while($info = mysql_fetch_array( $check )) { if (($cAdmin == 1) && ($info['admin'] == 1)) { ?> And this is the end_admincheck.php Code: [Select] <?php include('variables/variables.php'); ?> <?php } else die(); } } else die(); ?> ?> I get this Parse error thrown at the bottom of the page: Code: [Select] Parse error: syntax error, unexpected $end in /*******/includes/start_admincheck.php on line 15 Naturally I would checkout line 15 in start_admincheck.php, but normally when I get an $end error it is the last line of the code and leaves me lost.. Something I'm missing guys? As always, thanks in advance Any help would be greatly appreciated! <?php $host="localhost"; // Host name $username="user"; // Mysql username $password=""; // Mysql password $db_name=""; // Database name $tbl_name=""; // Table name mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); $barcodeID=$_POST['barcode']; echo $barcodeID; $barcodeID = stripslashes($barcodeID); $barcodeID = mysql_real_escape_string($barcodeID); $sql="SELECT * FROM $tbl_name WHERE BarcodeID='$barcodeID'"; $result=mysql_query($sql); // Mysql_num_row is counting table row $count=mysql_num_rows($result); $count=mysql_num_rows($result); if($count==1){ $_SESSION['barcode'] = $barcodeSession; $_SESSION['userlevel'] = $row['Priority']; if($row['userlevel'] == "Admin") { header("location:AdminSection.php"); }else{ header("location:index.php"); } header("location:LoggedIn.php"); } else { header("location:index.php"); } ?> when the script has been run, I want it to redirect to either the user page or admin page depending on their priority level. if Priority field == "Admin" then go to admin page. Can you see anything missing? Thank You I get this error: Code: [Select] Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in C:\xampp\htdocs\user\user.php on line 5 code: user.php: Code: [Select] <?php $get = (isset($_GET['id'])); //this means that user.php?id=1 would mean $get = 1. Note: This is not SQL Inject protected. $users = mysql_query("SELECT * FROM users WHERE id='".$get."'"); while ($row = mysql_fetch_array($users)) { echo ' Id = '.$row['id'].' Name = '.$row['name'].' Username = '.$row['username'].' Password = '.$row['password'].' Reg. on = '.$row['date'].' '; } ?> <html> <body> <form action='user.php' method='GET'> Username: <input type='text' value=''> <input type='submit' value='submit'> </form> <?php //what goes here? ?> </body> </html> Hey, So i have an admin.php page that lists all of the users in the database and im wondering how i can add functions so the administrator can delete / ban the user from the webpage i'm not sure on how you would select the user?
Hello, Do you know where I can download a nice looking PHP admin dashboard for free? Thanks in advance for the help Hallo I have a problem.
This is my code:
<?php include 'connect.php';
?>
<html>
<head>
<title>Admin Insert page!</title>
</head>
<body>
<?php
error_reporting(-1);ini_set('display_errors',1);
if (isset($_POST['submit'])){
$name = $_POST['name'];
$password = $_POST['password'];
$result = mysql_query("SELECT * FROM users WHERE user='$name' AND password='$password'");
$num = mysql_num_rows($result);
if($num == 0){
echo "Bad login, go <a href='login.php'>back</a>";
}else{
session_start();
$_SESSION['name'] = $name;
header("Location: admin.php");
}
}else{
?>
<form action='login.php' methody='post'>
Username: <input type='text' name='name'/><br />
Password: <input type='password' name='password'/><br />
<input type='submit' name='submit' value='Login' />
</body>
</html>
I try to use console to find the problem but I didn't....
I know that there is some problem with $num
Can somebody help me?
Thank you.
Edited by Artur, 19 October 2014 - 12:11 PM. Hey, in a nutshell the only thing in admin.php is the ability to moderate unapproved images, however, once approved, the "Approve Delete" links are still on screen. How it works is a user uploads an image, the filename is added to mysql and the image is added to uploads/ once I Approve an image, the image is then moved to img/ to display on the index.php (to prevent porn and anything that doesn't belong to the general public). I know what's happening, because I've got while loops to display the image while looping through the mysql database, so once the image is moved, the links are still on screen, displaying an "Approve Delete" for every image in the database. Also another thing that happens is the images on index.php are blank until approved. How can I work around this? Here is the index.php when an image hasn't been approved: http://www.xodiac.net/1.png And here is the admin.php displaying Approve and Delete once an image has been approved: http://www.xodiac.net/2.png i want that when someone post some comment on post that don't insert in table directly before inserting i can check and after approving then insert in table for which what i doo ?any IDea about this Hello guys. By the end of the day, my client wants the daily report sent to his email account in .xls format. how can i attain this? I know the php mail() function but i dont know how will php create an excel file and email it to my client automatically. Where should i start? Thanks guys! Hey all, I'm using cakephp and it asks me a question and I'm not sure what to put in, because I don't necessarily know the consequences of what I put in: Code: [Select] Would you like to create the methods for admin routing? (y/n) [y] > y You need to enable Configu :write('Routing.admin','admin') in /app/config/core.php to use admin routing. What would you like the admin route to be? Example: www.example.com/admin/controller What would you like the admin route to be? [admin] > Thanks for response Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in C:\xampp\htdocs\sas\shoppingcart\adminlogin.php on line 16 Warning: Cannot modify header information - headers already sent by (output started at C:\xampp\htdocs\sas\shoppingcart\adminlogin.php:16) in C:\xampp\htdocs\sas\shoppingcart\adminlogin.php on line 33 Hi all, I've tried to access the admin.php of the xcart installation he http://www.cleaningshopuk.com but it doesn't allow me to access it, saying that it's a 404 page not found error. That page does in fact exist, but I think the issue might be something to do with a redirection. The site owner apparently clicked on something in the admin section (possibly https or something similar) but what can I do to avoid this issue without having to re install everything? Thanks, Neil hello, I have created a website which has to incorporate administration features. I hjave been trying to do this for a couple of days and any help will be much appreciated. I have a login screen (form) when the user enters their username and password they are brought to the homepage.php. Is there anyway to redirect the administrator (username=admin) to a different page from all ordinary members? e.g. deletemember.php Thanks This topic has been moved to HTML Help. http://www.phpfreaks.com/forums/index.php?topic=356360.0 I am trying to check for an admin user to access the admin panel. I have been playing around try different things and this what I have ended up with in my database table I have a column called usergroup and i do the follow to check for admin user. Code: [Select] $checkAdmin = mysql_query("SELECT * FROM `users` WHERE email='$email' , usergroup = 'admin'"); $adminUser = mysql_num_rows($checkAdmin); if ($adminUser == 0) { echo count($adminUser); die ('You do not have permissions to access this area'); } I do the select statement through phpmyadmin and it comes back with one row. which is basically hat i want to check for. I do have a variable called $email which is getting a value from the email cookie. currently $adminUser Return a value of 10. All of the count() functions is for testing purposes only. Ok.. I have made an admin section for a couple of sites, and it works fine, alough i'm almost certain that the way i have done it is not the "proper way". What I have done is had a form with a password field that sends the password via POST to another script that checks the password is correct via variable, something like this: Code: [Select] <?php $pass = $_POST["pass"]; $correct = "imapassword"; if($pass == $correct){ //display contents of page else{ //return user to login screen } ?> And then it saves the password into a cookie, that dies either over time or when the browser closes. And then on each page it tests wether that cookie is still there and is correct. When the user wants to log out it just destroys the cookie. This seems like a really hashed up way of doing it, could anybody let me know the bare essentials for making a similar system, but the "right way". Thankyou in advance Hello, I have a problem with my website, Admin login page (http://www.tranceprofile.com/storeadmin/admin_login.php I can not login to my Admin controle panel. Login information: Username: Mitch Password: schuur111 Username: Admin Password: poopoo Can someone help me ? Here is my admin_login.php source code. If you need some other source code in my /storeadmin folder please tell Code: [Select] <?php session_start(); if (isset($_SESSION["manager"])) { header("location: index.php"); exit(); } ?> <?php // Parse the log in form if the user has filled it out and pressed "Log In" if (isset($_POST["username"]) && isset($_POST["password"])) { $manager = preg_replace('#[^A-Za-z0-9]#i', '', $_POST["username"]); // filter everything but numbers and letters $password = preg_replace('#[^A-Za-z0-9]#i', '', $_POST["password"]); // filter everything but numbers and letters // Connect to the MySQL database include "../storescripts/connect_to_mysql.php"; $sql = mysql_query("SELECT id FROM admin WHERE username='$manager' AND password='$password' LIMIT 1"); // query the person // ------- MAKE SURE PERSON EXISTS IN DATABASE --------- $existCount = mysql_num_rows($sql); // count the row nums if ($existCount == 1) { // evaluate the count while($row = mysql_fetch_array($sql)){ $id = $row["id"]; } $_SESSION["id"] = $id; $_SESSION["manager"] = $manager; $_SESSION["password"] = $password; header("location: index.php"); exit(); } else { echo 'That information is incorrect, try again <a href="index.php">Click Here</a>'; exit(); } } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Admin Log In </title> <link rel="stylesheet" href="../style/style.css" type="text/css" media="screen" /> </head> <body> <div align="center" id="mainWrapper"> <?php include_once("../template_header.php");?> <div id="pageContent"><br /> <div align="left" style="margin-left:24px;"> <h2>Please Log In To Manage the Store</h2> <form id="form1" name="form1" method="post" action="admin_login.php"> User Name:<br /> <input name="username" type="text" id="username" size="40" /> <br /><br /> Password:<br /> <input name="password" type="password" id="password" size="40" /> <br /> <br /> <br /> <input type="submit" name="button" id="button" value="Log In" /> </form> <p> </p> </div> <br /> <br /> <br /> </div> <?php include_once("../template_footer.php");?> </div> </body> </html> |
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