PHP - Select Same Field From Multiple Tables
I want to select the user from super_administrators, administrators, teachers and students, and give the user permission based from what table he "came". But is giving the "Query failed" error...
Code: [Select] <?php //Start session session_start(); //Include database connection details require_once('../config/config.php'); //Array to store validation errors $errmsg_arr = array(); //Validation error flag $errflag = false; //Connect to mysql server $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD); if(!$link) { die('Failed to connect to server: ' . mysql_error()); } //Select database $db = mysql_select_db(DB_DATABASE); if(!$db) { die("Unable to select database"); } //Function to sanitize values received from the form. Prevents SQL injection function clean($str) { $str = @trim($str); if(get_magic_quotes_gpc()) { $str = stripslashes($str); } return mysql_real_escape_string($str); } //Sanitize the POST values $email = clean($_POST['email']); $password = clean($_POST['password']); //Input Validations if($email == '') { $errmsg_arr[] = 'O campo Email nao foi preenchido.'; $errflag = true; } if($password == '') { $errmsg_arr[] = 'O campo Senha nao foi preenchido.'; $errflag = true; } //If there are input validations, redirect back to the login form if($errflag) { $_SESSION['ERRMSG_ARR'] = $errmsg_arr; session_write_close(); header("location: ../index.php"); exit(); } //Create query $qry = "SELECT * FROM super_administrators,administrators,teachers,students WHERE email = '$email' AND passwd = '".md5($_POST['password'])."'"; $result = mysql_query($qry); $member = mysql_fetch_assoc($result); $table = mysql_field_table('$result', '0'); //Check whether the query was successful or not if($result) { if(mysql_num_rows($result) == 1) { if($table == 'super_administrators') { session_regenerate_id(); $_SESSION['SESS_ID'] = $member['id']; $_SESSION['SESS_NAME'] = $member['name']; $_SESSION['SESS_EMAIL'] = $member['email']; session_write_close(); header("location: ../users/sadmin/index.php"); exit(); } if($table == 'administrators') { session_regenerate_id(); $_SESSION['SESS_ID'] = $member['id']; $_SESSION['SESS_SCHOOL_ID'] = $member['school_id']; $_SESSION['SESS_NAME'] = $member['name']; $_SESSION['SESS_EMAIL'] = $member['email']; session_write_close(); header("location: ../users/admin/index.php"); exit(); } if($table == 'teachers') { session_regenerate_id(); $_SESSION['SESS_ID'] = $member['id']; $_SESSION['SESS_SCHOOL_ID'] = $member['school_id']; $_SESSION['SESS_NAME'] = $member['name']; $_SESSION['SESS_EMAIL'] = $member['email']; session_write_close(); header("location: ../users/prof/index.php"); exit(); } if($table == 'students') { session_regenerate_id(); $_SESSION['SESS_ID'] = $member['id']; $_SESSION['SESS_SCHOOL_ID'] = $member['school_id']; $_SESSION['SESS_CLASS_ID'] = $member['class_id']; $_SESSION['SESS_NAME'] = $member['name']; $_SESSION['SESS_REGISTRATION'] = $member['registration']; $_SESSION['SESS_EMAIL'] = $member['email']; session_write_close(); header("location: ../users/aluno/index.php"); exit(); } } else { $errmsg_arr[] = 'Suas informacoes de login estao incorreta. Por favor, tente novamente.'; $errflag = true; $_SESSION['ERRMSG_ARR'] = $errmsg_arr; session_write_close(); header("location: ../index.php"); exit(); } } else { die("Query failed"); } ?> Similar Tutorialshirealimo.com.au/code1.php this works as i want it: Quote SELECT * FROM price INNER JOIN vehicle USING (vehicleID) WHERE vehicle.passengers >= 1 AND price.townID = 1 AND price.eventID = 1 but apparelty selecting * is not a good thing???? but if I do this: Quote SELECT priceID, price FROM price INNER JOIN vehicle....etc it works but i lose the info from the vehicle table. but how do i make this work: Quote SELECT priceID, price, type, description, passengers FROM price INNER JOIN vehicle....etc so that i am specifiying which colums from which tables to query?? thanks I'm having a hard time grasping how to select data from several tables. Here's the code Code: [Select] <?php require_once "config.php"; $gamedate = $_SESSION['date']; echo "These umpires are not currently scheduled on this date, and have not asked for the day off:<br />"; $umpirelist = Array('umpire 1 name', 'umpire 2 name', 'umpire 3 name'); $dbc = mysql_pconnect($host, $username, $password); mysql_select_db($db,$dbc); foreach($umpirelist as $data) { //now get stuff from a table $sql = "SELECT calendar.date, calendar.ump1, calendar.ump2, calendar.ump3, calendar.ump4, calendar.ump5, vacation.date, vacation.umpire FROM umps, calendar, vacation WHERE umps.full_name = $data AND $gamedate = `calendar.date` AND $gamedate = `vacation.date` AND $data NOT IN ('calendar.ump1', 'calendar.ump2', 'calendar.ump3', 'calendar.ump4', 'calendar.ump5') AND $data NOT IN ('vacation.umpire') order by umps.full_name asc"; $rs = mysql_query($sql,$dbc); $matches = 0; while ($row = mysql_fetch_assoc($rs)) { $matches++; echo "$row[$data]<br />"; } } ?> The table CALENDAR holds the date of the game, who is playing, and what umpires are schedule for that game. it does have a unique "row_number" column as well, but didn't think I'd need it in this select. The table VACATION has the date, and umpire's name that is on vacation. The table UMPS contains the umpires name (same names as the array in the code) and email addresses and login info. I'm getting this error: Quote Warning: mysql_fetch_assoc(): supplied argument is not a valid MySQL result resource on line 152 This is line 152 Quote while ($row = mysql_fetch_assoc($rs)) { Can someone please point me in the right direction as to where I'm going wrong? Thanks! hi im trying to echo out all the possibilities from one column in 2 different tables, both with the same structure. if that makes sense this is what i have $query = mysql_query("SELECT * FROM stanjamesprem,centrebetprem GROUP BY eventname ORDER BY eventtime "); while($row = mysql_fetch_assoc($query)) { echo $row[eventname]; } if i take one of the tables out it works fine but if i have 2 table names it doenst work please help me cheers matt any questions please ask away This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=348013.0 Hi,
How can I select multiple columns from two tables and run a search through multiple fields?
My tables a
t_persons (holds information about persons)
t_incidents (holds foreign keys from other tables including t_persons table)
What I want is to pull some columns from the two tables above and run a search with a LIKE criteria, something like below. The code originally worked well with only one table, but for two tables it generate errors:
$query = "SELECT p.PersonID ,p.ImagePath ,p.FamilyName ,p.FirstName ,p.OtherNames ,p.Gender ,p.CountryID ,i.IncidentDate ,i.KeywordID ,i.IncidentCountryID ,i.StatusID FROM t_incidents AS i LEFT JOIN t_persons AS p ON i.PersonID = p.PersonID WHERE FamilyName LIKE '%" . $likes . "%' AND FirstName LIKE '%" . $likes . "%' AND OtherNames LIKE '%" . $likes . "%' AND Gender LIKE '%" . $likes . "%' AND IncidentDate LIKE '%" . $likes . "%' AND KeywordID LIKE '%" . $likes . "%' AND IncidentCountryID LIKE '%" . $likes . "%' AND StatusID LIKE '%" . $likes . "%' ORDER BY PersonID DESC $pages->limit";Errors a Column 'IncidentDate' in where clause is ambiguous Column 'KeywordID' in where clause is ambiguous Column 'IncidentCountryID' in where clause is ambiguous Column 'StatusID' in where clause is ambiguousThese columns are foreign keys on t_incidents table. I have also attached the table relationship diagram if it helps. I will appreciate any better way to do this. Thanx. Joseph Attached Files Model - 3.png 76.6KB 0 downloads Below is a page which is supposed to output the name, blog contribution and picture of contributing members of a website. <div id="blog_content" class="" style="height:90%; width:97%; border:5px solid #c0c0c0; background-color: #FFFFFF;"> <!--opens blog content--> <?php //address error handling ini_set ('display_errors', 1); error_reporting (E_ALL & ~E_NOTICE); //include the config file require_once("config.php"); //Define the query. Select all rows from firstname column in members table, title column in blogs table,and entry column in blogs table, sorting in ascneding order by the title entry, knowing that the id column in mebers table is the same as the id column in blogs table. $sql = "SELECT blogs.title,blogs.entry,members.firstname,images.image FROM blogs LEFT JOIN members ON blogs.member_id = members.member_id LEFT JOIN images ON blogs.member_id = images.member_id ORDER BY blogs.title ASC "; $query = mysql_query($sql); if($query !== false && mysql_num_rows($query) > 0) { while(($row = mysql_fetch_assoc($query)) !== false) { echo '<div id="blog_content1" style="float:left; position:relative;bottom:18px;left:13px; background-color: #FFFFFF; height:16.7%; width:100%; border:0px none none;" <!--opens blog_content1 same as main center top 1 and 2 from index page everything scaled down by a factor of 3, heightwise--> <div class="red_bar" style="height:3%; width:100%; border:1px solid #959595;"> <!--a--> <div class="shade1" style="height:5px; width:100%; border:0px none none;"> </div> <div class="shade2" style="height:5px; width:100%; border:0px none none"> </div> <div class="shade3" style="height:5px%; width:100%; border:0px none none"> </div> </div> <!-- closes red bar--> <div class="content" style="height:28.3%; width:100%; border:0px none none;"> <!----> <div class="slideshow" id="keylin" style="float:left; width:20%; border:0px none none;"> <!--a--> <div><img header("Content-type: image/jpeg"); name="" alt="" id="" height="105" width="105" src="$row[image]" /></div> </div> <!-- closes pic--> <div class="content_text" style="float:right; position:relative;top:7px;left:0px; max-height:150px; width:78.5%; border-width:4.5px; border-bottom-style:solid; border-right-style:solid; border-color:#c0c0c0; "> <!--a-->'; echo "<h3>".$row['title']."</h3>"; echo "<p>" .$row['entry']."<br />".$row['firstname']."</p>"; echo '</div> <!-- closes content text--> </div> <!-- closes content--> </div> <!-- closes blog_content1-->'; } } else if($query == false) { echo "<p>Query was not successful because:<strong>".mysql_error()."</strong></p>"; echo "<p>The query being run was \"".$sql."\"</p>"; } else if($query !== false && mysql_num_rows($query) == 0) { echo "<p>The query returned 0 results.</p>"; } mysql_close(); //Close the database connection. ?> </div> <!-- closes blog content--> The select query is designed to retrieve all the blog contributions(represented by the fields blogs.title and blogs.entry) from the database, alongside the contributing member (member.firstname) and the member's picture(images.image), using the member_id column to join the 3 tables involved, and outputs them on the webpage. The title, entry and firstname values are successfully displayed on the resulting page. However, I can't seem to figure out how to get the picture to be displayed. Note that the picture was successfully stored in the database and I was able to view it on a separate page using a simple select query. It is now just a question of how to get it to display on this particularly crowded page. Anyone knows how I can output the picture in the img tag? I tried placing the header("Content-type: image/jpeg"); statement at the top of the php segment, then just right below the select query and finally just right above the img tag, but in every case, I just got a big white blank page starring at me. How and where should I place the header statement? And what else am I to do to get this picture displayed? Any help is appreciated. Im doing a search system and Im having some problems.
I need to search in two tables (news and pages), I already had sucess doing my search system for just one table, but for two tables its not easy to do.
I already use a select statment with two tables using UNION because I want to show number of search results, that is number of returned rows of my first sql statment.
But now I need to do a select statment that allows me to acess all fields of my news table and all fields of my pages table.
I need to acess in my news table this fields: id, title, content, link, date, nViews
I need to acess in my pages table this fields: id, title, content, link
Im trying to do this also with UNION, but in this case Im not having any row returning.
Do you see what I have wrong in my code?
<?php //first I get my $search keyword $search = $url[1]; $pdo = connecting(); //then I want to show number of returned rows for keyword searched $readALL = $pdo->prepare("SELECT title,content FROM news WHERE title LIKE ? OR content LIKE ? UNION SELECT title,content FROM pages WHERE title LIKE ? OR content like ?"); $readALL->bindValue(1,"%$search%", PDO::PARAM_STR); $readALL->bindValue(2,"%$search%", PDO::PARAM_STR); $readALL->bindValue(3,"%$search%", PDO::PARAM_STR); $readALL->bindValue(4,"%$search%", PDO::PARAM_STR); $readALL->execute(); //I show number of returned rows echo '<p>Your search keyword returned <strong>'.$readALL->rowCount().'</strong> results!</p>'; //If dont return any rows I show a error message if($readALL->rowCount() <=0){ echo 'Sorry but we didnt found any result for your keyword search.'; } else{ //If return rows I want to show, if it is a page result I want to show title and link that I have in my page table //if it is a news result I want to show title and link that I have in my news table and also date of news echo '<ul class="searchlist">'; $readALL2 = $pdo->prepare("SELECT * FROM news WHERE status = ? AND title LIKE ? OR content LIKE ? LIMIT 0,4 UNION SELECT * FROM pages where title LIKE ? OR content LIKE ? LIMIT 0,4"); $readALL2->bindValue(1, '1'); $readALL2->bindValue(2, "%$search%", PDO::PARAM_STR); $readALL2->bindValue(3, "%$search%", PDO::PARAM_STR); $readALL2->bindValue(4, "%$search%", PDO::PARAM_STR); $readALL2->execute(); while ($result = $readALL2->fetch(PDO::FETCH_ASSOC)){ echo '<li>'; echo '<img src="'.BASE.'/uploads/news/'.$result['thumb'].'"/>'; echo '<a href="'.BASE.'/news/'.$result['id_news'].'">'.$result['title'].'</a>'; //if it is a news result I also want to show date on my list //echo '<span id="date">'.$result['date'].'</span>'; echo '</li>'; } echo ' </ul>'; //but how can I do my select statement to have access to my news table fields and my page table fields?? } ?> Hi, I'm developing an app using flash AS2 as the front end via PHP and a mySQL database at the backend on my server. what i'm looking to do is update/insert into a table called 'cards' and at the same time update/insert into another table called 'jingle'. There is a field called 'cardID' in jingle that should be the same as the ID number created in 'cards' thus creating a link between entries in the different tables that can be called up as i choose. hope i've been clear i just wouldn't know where to start any help would be appreciated. MySQL client version: 5.0.91 PHPmyAdmin Version information: 3.2.4 thanks in advance This seems to be a bit of a challenge but I am creating a multiple page form and on one of the pages I have a select field. I would like the user to have the ability to select multiple options but I am using some functions to move the data in hidden fields from page to page. I don't think my functions are jiving with my my foreach loop cause I keep getting an invalid argument error. Thanks in advance for any help. Here is my function: function setSelected($fieldName, $fieldValue) { if(isset($_POST[$fieldName]) && $_POST[$fieldName] == $fieldValue) { echo 'selected="selected"'; } } And here is my loop: $selections = ""; if(isset($_POST["selections"])) { foreach ($_POST["selections"] as $selection) { $selections .= $selection . ", "; } } I have 2 queries that I want to join together to make one row
I have a form where a user can duplicate part of a form like below: I've named the fields with the HTML arrays (ie. "fieldName[]") and came up with this: //--> CONTROLLERS $system_controllers_qty = $_POST['system_controllers_qty']; $system_controllers_make = $_POST['system_controllers_make']; $system_controllers_model = $_POST['system_controllers_model']; $system_controllers_serial_no = $_POST['system_controllers_serial_no']; for ($i = 0; $i < count($system_controllers_qty); $i++) { echo "qty " . clean($system_controllers_qty[$i]) . "<br/>"; echo "make " . clean($system_controllers_make[$i]) . "<br/>"; echo "model " . clean($system_controllers_model[$i]) . "<br/>"; echo "serial_no " . clean($system_controllers_serial_no[$i]) . "<br/>"; } //--> CPUS $system_cpus_qty = $_POST['system_cpus_qty']; $system_cpus_model = $_POST['system_cpus_model']; $system_cpus_serial_no = $_POST['system_cpus_serial_no']; $system_cpus_speed = $_POST['system_cpus_speed']; for ($i = 0; $i < count($system_cpus_qty); $i++) { echo "qty " . clean($system_cpus_qty[$i]) . "<br/>"; echo "model " . clean($system_cpus_model[$i]) . "<br/>"; echo "serial_no " . clean($system_cpus_serial_no[$i]) . "<br/>"; echo "speed " . clean($system_cpus_speed[$i]) . "<br/>"; } //--> DISKS $system_disks_qty = $_POST['system_disks_qty']; $system_disks_make = $_POST['system_disks_make']; $system_disks_model_no = $_POST['system_disks_model_no']; $system_disks_size = $_POST['system_disks_size']; $system_disks_serial_no = $_POST['system_disks_serial_no']; for ($i = 0; $i < count($system_disks_qty); $i++) { echo "qty " . clean($system_disks_qty[$i]) . "<br/>"; echo "make " . clean($system_disks_make[$i]) . "<br/>"; echo "model_no " . clean($system_disks_model_no[$i]) . "<br/>"; echo "size " . clean($system_disks_size[$i]) . "<br/>"; echo "serial_no " . clean($system_disks_serial_no[$i]) . "<br/>"; } //--> MEMORY $system_memory_qty = $_POST['system_memory_qty']; $system_memory_serial_no = $_POST['system_memory_serial_no']; $system_memory_manf = $_POST['system_memory_manf']; $system_memory_part_no = $_POST['system_memory_part_no']; $system_memory_size = $_POST['system_memory_size']; for ($i = 0; $i < count($system_memory_qty); $i++) { echo "qty " . clean($system_memory_qty[$i]) . "<br/>"; echo "serial " . clean($system_memory_serial_no[$i]) . "<br/>"; echo "manf " . clean($system_memory_manf[$i]) . "<br/>"; echo "part_no " . clean($system_memory_part_no[$i]) . "<br/>"; echo "size " . clean($system_memory_size[$i]) . "<br/>"; } This just outputs all the fields I post at the moment. Say I have 3 different disk types, it's going to loop 3 times. Is it possible to make this all into 1 giant query or am I better off doing each query separately? Each section is a different table. I have a search where I want to be able to search a string of words. The search is going to be looking in 2 different table joined by a left outer join. The tables are "quotes" and "categories". $sql="SELECT q.id, q.username, q.quote, q.by, q.voteup, q.votedown, q.servtime, c.quote_id, c.label FROM quotes q LEFT OUTER JOIN categories c ON q.id = c.quote_id WHERE ( q.username LIKE '$srch' OR q.quote LIKE '$srch' OR q.`by` LIKE '$srch' OR c.label LIKE '$srch')"; The above mysql statement works and returns values..BUT if say, I search "john" and "funny", and a quote is posted by the user "john", but has a category of "funny" it will output the same quote twice. I was wondering if there was a way to see if a quote has either 1 term or both terms, if so display that quote but only display it once. Below is what the query is outputting. [100] => Array ( [id] => 100 [username] => John [quote] => new test quote blah blah [by] => John [voteup] => 0 [votedown] => 0 [servtime] => 2010-12-02 @ 16:27:03 [label] => Array ( [0] => Historic [1] => Serious [2] => Funny ) ) Here is the code in full. //// $sword = explode(" ",$search); foreach($sword as $sterm){ $srch="%".$sterm."%"; echo"$srch<br />"; $sql="SELECT q.id, q.username, q.quote, q.by, q.voteup, q.votedown, q.servtime, c.quote_id, c.label FROM quotes q LEFT OUTER JOIN categories c ON q.id = c.quote_id WHERE ( q.username LIKE '$srch' OR q.quote LIKE '$srch' OR q.`by` LIKE '$srch' OR c.label LIKE '$srch')"; $result=mysql_query($sql); while($row=mysql_fetch_object($result)){ $quote[$row->id]['id'] = $row->id; $quote[$row->id]['username'] = $row->username; $quote[$row->id]['quote'] = $row->quote; $quote[$row->id]['by'] = $row->by; $quote[$row->id]['voteup'] = $row->voteup; $quote[$row->id]['votedown'] = $row->votedown; $quote[$row->id]['servtime'] = $row->servtime; $quote[$row->id]['label'][] = $row->label; } echo"<pre>"; print_r($quote); echo"</pre>"; I don't think this is the fastest way of doing this, as it loops for each item in the db, per each keyword that is search. Any help would be great!! -BaSk I am trying to export multiple csv files to download from 2 separate tables in my database. Some background: I have a web app that links to a phpmyadmin database. There are 2 tables in the database (entering and exiting). These tables hold the phone inventory information of employees currently entering or exiting the organization. The fields in my tables a location, firstname, lastname, username, extension, mac, type What I am trying to do is export the data in these 2 tables to CSV (which I have working now) but I need to have multiple CSVs for each. For example, for my exiting table, I need to have one CSV export all the fields in the table and I also need another CSV to export just the location and username field. I have a simple html form with a submit button which is currently working now: <form action="exportexiting.php" method="POST" style="width: 456px; height: 157px"> <div> <fieldset> <legend style="width: 102px; height: 25px"><strong>Entering CSV:</strong></legend> <input name="Export" type="submit" id="Export" value="Export"> </fieldset><br/> </div> </form> This links to my exportexiting.php file: <?php $host = 'localhost'; $user = 'root'; $pass = 'xxxx'; $db = 'PhoneInventory'; $table = 'exiting'; // Connect to the database $link = mysql_connect($host, $user, $pass); mysql_select_db($db); require 'exportcsv.inc.php'; exportMysqlToCsv($table); ?> Then to exportcsv.inc.php: <?php function exportMysqlToCsv($table,$filename = 'export.csv') { $csv_terminated = "\n"; $csv_separator = ","; $csv_enclosed = ''; $csv_escaped = "\\"; $sql_query = "select * from $table"; // Gets the data from the database $result = mysql_query($sql_query); $fields_cnt = mysql_num_fields($result); $schema_insert = ''; for ($i = 0; $i < $fields_cnt; $i++) { $l = $csv_enclosed . str_replace($csv_enclosed, $csv_escaped . $csv_enclosed, stripslashes(mysql_field_name($result, $i))) . $csv_enclosed; $schema_insert .= $l; $schema_insert .= $csv_separator; } // end for $out = trim(substr($schema_insert, 0, -1)); $out .= $csv_terminated; // Format the data while ($row = mysql_fetch_array($result)) { $schema_insert = ''; for ($j = 0; $j < $fields_cnt; $j++) { if ($row[$j] == '0' || $row[$j] != '') { if ($csv_enclosed == '') { $schema_insert .= $row[$j]; } else { $schema_insert .= $csv_enclosed . str_replace($csv_enclosed, $csv_escaped . $csv_enclosed, $row[$j]) . $csv_enclosed; } } else { $schema_insert .= ''; } if ($j < $fields_cnt - 1) { $schema_insert .= $csv_separator; } } // end for $out .= $schema_insert; $out .= $csv_terminated; } // end while header("Cache-Control: must-revalidate, post-check=0, pre-check=0"); header("Content-Length: " . strlen($out)); // Output to browser with appropriate mime type, you choose header("Content-type: text/x-csv"); //header("Content-type: text/csv"); //header("Content-type: application/csv"); header("Content-Disposition: attachment; filename=$filename"); echo $out; exit; } ?> Again, this is working perfectly for only exporting all the data from the exiting table into one CSV file. My question is, how can I make my one submit button export the 2 CSV files that I need? Thanks for the help... Hi. I have two select fields one called category and the other sub category. Both are in the format. <select name="category" value=" <?php $qGetCat = "SELECT * FROM club_category" ; $rGetCat = mysql_query($qGetCat); while ($Cat = mysql_fetch_assoc($rGetCat)) { ?>" /> <option value="<?php echo $Cat['categorys'];?>"><?php echo $Cat['categorys']; ?></option> <?php } ?> </select> <select name="sub_category" value=" <?php $qGetSubCat = "SELECT * FROM sub_categorys" ; $rGetSubCat = mysql_query($qGetSubCat); while ($SubCat = mysql_fetch_assoc($rGetSubCat)) { ?>" /> <option value="<?php echo $SubCat['sub_categorys'];?>"><?php echo $SubCat['sub_categorys']; ?></option> <?php } ?> </select> Now I want to make it so that when a particular category is chosen for example self defence. The sub category when clicked shows all the self defence stuff. If watersports was chosen sub category would show things like swimming. What do I need to look up to do this? At the minute there is no link the way I have coded these to fields. In the database its self there is a; category table with categoryID and category_name sub category table with sub_cat_name and categoryID I think this will work but I have never done this so its making my head hurt just thinking about it. Does anyone have any advice, tuts or scripts to do this? Thank you Hello. I am trying to display only one instance of records that have the same memberid in my db. I am using the following statement but it continues to show all of the records that have the same memberid. Any ideas what I may be doing wrong? Code: [Select] $sql = "select DISTINCT memberid, event, category, date, enddate, locality, location, address, city, state, zip, contact, phone, notes, doc1, doc2, doc3, doc4, doc5 from event where date >= '$datenow' ORDER by date ASC"; Thanks for any help! hey, i'm trying to select information from 2 tables in one query... so i have 2 tables... members - (holds the members information) looks like this: Code: [Select] +---+--------+------------+------------+ | id | name | email | password | +---+--------+------------+------------+ | 1 | user1 | 1@g.com | **** | | 2 | user2 | 2@g.com | **** | | 3 | user3 | 3@g.com | **** | | 4 | user4 | 4@g.com | **** | | 5 | user5 | 5@g.com | **** | | 6 | user6 | 6@g.com | **** | +---+--------+------------+------------+ the second table is profile_views which stores the profile views... Code: [Select] +---+--------+-----------+---------------+ | id | userid | viewerid | time | +---+--------+-----------+---------------+ | 1 | 4 | 1 | 1287949172 | | 2 | 6 | 2 | 1287949172 | | 3 | 2 | 4 | 1287949172 | | 4 | 4 | 5 | 1287949172 | | 5 | 3 | 2 | 1287949172 | +---+--------+-----------+---------------+ userid - the profile (member) id that been watched viewerid - the id of the member who watched time - the time this happened im trying to select from profile_views the viewers ids' and select the info from the members according to the viewerid, but also i want to select the time from the profile_views, so it's should look like this: Code: [Select] +---+--------+------------+----------+------------+ | id | name | email | password | time +---+--------+------------+----------+------------+ | 1 | user1 | 1@g.com | **** | 1287949172 | 2 | user2 | 2@g.com | **** | 1287949172 | 3 | user3 | 3@g.com | **** | 1287949172 | 4 | user4 | 4@g.com | **** | 1287949172 | 5 | user5 | 5@g.com | **** | 1287949172 | 6 | user6 | 6@g.com | **** | 1287949172 +---+--------+------------+----------+------------+ this is my code: Code: [Select] $DB->query("SELECT viewerid FROM profile_views WHERE userid={$core->input['showuser']} ORDER BY time DESC LIMIT 5"); if ( $DB->get_num_rows() > 0 ) { while ( $all_viewers = $DB->fetch_row() ) { $viewers_ids[] = $all_viewers['viewerid']; } $viewers_ids = implode(",", $viewers_ids); $DB->query("SELECT m.*, v.* FROM members m LEFT JOIN profile_views v ON (v.userid=m.id) WHERE m.id IN ({$viewers_ids})"); while ( $viewers = $DB->fetch_row() ) { } } but it's just dont work! any ideas? Thanks in advance! hey, i trying to select * colums form one table and 1 colum from another table... this is my code: Code: [Select] $DB->query("SELECT m.*, v.time, v.viewerid FROM members m LEFT JOIN profile_views v ON (m.id=v.userid) WHERE m.id IN ({$viewers_ids})"); but sometimes this query return multiply rows... any ideas? Thanks! Hi there I have 2 tables: Fleet FleetName PlanetName Status Planet PlanetName PlayerName Im trying to write a select query that will search through the fleet table and display Fleet table details Where the PlanetName from the fleet table is = to the PlanetName of the Planet table. Ive tried joining the tables but i dont think the logic quite works.. Code: [Select] mysql_select_db($database_swb, $swb); $query_Fleet = sprintf("SELECT fleet.FleetName, planet.PlanetName FROM fleet, planet WHERE fleet.PlanetName = planet.PlanetName"); $Fleet = mysql_query($query_Fleet, $swb) or die(mysql_error()); $row_Fleet = mysql_fetch_assoc($Fleet); $totalRows_Fleet = mysql_num_rows($Fleet); I want ONLY the Fleets from the planet i am looking at to be displayed not all of them. I have created another query that displays the planet name of the particular one I am looking at as it is parsed from a hyperlink on a previous page. So is there some way i can use both queries together? "SELECT FROM fleet, WHERE $fleet.PlanetName = $planet.PlanetName" Im a little bit confussed, please help Hello, i am trying to get my form to list usernames ascending as an option, but the select field just returns blank. Here is my code: Code: [Select] /** * editUserForm - Displays the users database table in * a nicely formatted field table. */ function editUserForm(){ $q = "SELECT * " ."FROM ".TBL_USERS." ORDER BY username ASC"; $result = $database->query($q); while ($row = mysql_fetch_assoc($result)) { echo '<option value="'.$row["username"].'">'.$row["username"].'</option>'; } } Code: [Select] <form action="/" method="post"> <div class="column"> <p> <select name="user" id="user" placeholder="Select A User To Edit" class="{validate:{required:true}}"> <option>Select A User To Edit</option> <? editUserForm(); ?> </select> </p> <div class="action_bar"> <input type="submit" class="button blue" value="Submit Post" /> <a href="#modal" class="modal button">Cancel</a> </div> </form> All help is appreciated |