PHP - Please Help, 3 Hour Refresh Problem

Hi all,

Thanks for reading.

I'm running a script using jQuery that auto-refreshes a <div> on the index page from an external PHP script to get all the rows in a database and display them on the index page. The script works great - here it is as follows:

Code: [Select]
<script type="text/javascript">

$(document).ready(function() {

$("#responsecontainer").fadeOut("fast").load("getrows.php").fadeIn("slow");

var refreshId = setInterval(function() {
$("#responsecontainer").fadeOut("fast").load('getrows.php').fadeIn("slow");
}, 5000);

$.ajaxSetup({ cache: false });

});

</script>

The getrows.php script I'm working with looks like this:

Code: [Select]
<?php 

$rowsQuery = mysql_query("SELECT * FROM Happenings WHERE HappeningDate='$today'");

if (mysql_num_rows($rowsQuery) == 0) {
$happeningsToday = "There are no happenings today.";
} else {

$allHappeningsToday = 1;

while ($getHappeningsToday = mysql_fetch_array($rowsQuery)) {

$happeningName = stripslashes($getHappeningsToday['HappeningName']);
$happeningDate = $getHappeningsToday['HappeningDate'];
$happeningDescription = $getHappeningsToday['HappeningDescription'];

if ($allHappeningsToday == 1) {

$happeningsToday .= "
<div class=\"box\">
<p>".$happeningName." | ".$happeningDate." | ".$happeningDescription."
</div>";

$allHappeningsToday = 2; 

} else { 

$happeningsToday .= "
<div class=\"box\">
<p>".$happeningName." | ".$happeningDate." | ".$happeningDescription."
</div>";

$allHappeningsToday = 1; 

}

}

}

echo $happeningsToday;

?>

This script works great as well.

Currently, the auto-refresh jQuery script as you can see if getting and fading in/out all of the rows.

Off of the above getrows.php script, is there a way after I could get only the newly created rows since the last refresh and only fade those in and out while leaving the others already loaded by the auto-refresh script to not fade in/out?

Any ideas, thoughts or suggestions would be unbelievably helpful.

Thank you very much.

I am trying to display date and time
below code display date correctly but when it come to display time it display 3 hour behind.

eg. when it is 12:47 PM in my system it display 9:47 PM

Code: [Select]
<?php
$todaydate=date("j - F - Y g:i:s a");
echo $todaydate;
?>

Hi, i'm trying to create some detailed statistics about customer activity, i have entries in my mysql db when the customer has been active for the last time and want to create some statistics about that, basically a "online last 24 hours" but from specific countries.

Now i've tried this:

Code: [Select]

$time = date('Y-m-d H:i:s');
$time24 = date("Y-m-d H:i:s", time()-((60*60)*24));
$query = "SELECT COUNT(*) as Anzahl FROM customers WHERE country = 'de' AND time BETWEEN '$time' AND '$time24' ";

to get the current date and select all customers that have been available from the current date minus 24 hours, what's my mistake here, as this doesn't seem to work!

Thanks

$time="19:00:00";

how to do i output one hour later from the variable above?

Hi all,
I have a loop that is modifying a DateTime object. It goes through X number of times and adds 1 day to the date time object and stores the modified object in an array. I use ->add(new DateInterval('P1D')); For some reason it is losing an hour each time that I add a day. I start out at 19:00 and each iteration through the loop adds a day, but loses an hour.
2010-09-19 19:00:00
2010-09-20 18:00:00
2010-09-21 17:00:00

I can correct for this by doing ->add(new DateInterval('P1DT1H'));, but adding 25 hours instead of 24 hours doesn't make any sense to me. I am using PHP Version 5.3.1.

Any ideas?

Thanks,
W

So I am trying to check if the current time is one hour before a variable time:
Code: [Select]
$date_game=$dt->format('Y n j'.$pieces[2]);
echo $date_game;
echo date('Y n j H');

if (date('Y n j H') < $date_game)  {
echo "The time is before the stored time";
}

This displays
2012 1 21 17:30
2012 1 21 16
i.e $pieces[2] = 17:30. and $dt formatted Y n j = 2012 1 21.
The current Y n j H is 2012 1 21 16.
I want to know if it is more than one hour until the date/time stored in $date_game.

At the moment it just tells me that it is before that time.
Can I do something like
Code: [Select]
$data_game - 1->format('H');
or something?
Thanks guys

Hi,   I have a blog which records the amount of views on each article. I now want to be able to work out the average number of views per hour.   How can I work out the number of hours passed from a datetime format?   From there I can just do views divided by hours passed.   Thanks in advance!    

Hello,

I have a very simple table... DAY (Y-m-d) / TIME (00:00:00) / POWER (INT)

I am using a Jquery datepicker to select the date on the page, and that POST to the PHP file.

I am trying to select values from Mysql to make 3 HighCharts Graphs using the selected day of the datepicker. I have started with the DAY graph PHP to get the values for each hour of a 24 hour day. I need to get the values for each hour... 23,12,15,35 etc... , and then I need for the 31 days of a month for the month graph, and 12 months of the year for the month graph all in the same way so the HighCharts can use the values to make the chart (3 php files, one for each graph)

Here is the PHP I have for the 1 day that should get the 24 individual hour data, but it does not seem to work...

<?php
$choice = (isset($_POST['choice'])) ? date("Y-m-d",strtotime($_POST['choice'])) : date("Y-m-d"); 
$con = mysql_connect("localhost","root","mackie1604");  
if (!$con)  {  
die('Could not connect: ' . mysql_error());  
}  
mysql_select_db("inverters", $con);  
$sql = "SELECT HOUR(time), COUNT(power) FROM feed WHERE time = '".$choice."' GROUP BY HOUR(time) ORDER BY HOUR(time) "; 
$res = mysql_query($sql) or die('sql='.$sql."\n".mysql_error()); 
$row = mysql_fetch_assoc($res); 
echo $row['choice'].'<br />'; 
?>

What have a written wrong in the sql query ???

Alan

Hi guys,

I have a PHP Script were user would enter a username and password to get access, but the problem I keep having is every half n hour or so user have to sign in again cause the keeps logging them out for some reason.

Please I need your help and advice to make this stop.

Hi

I want to make something like this -

My Sites index.php will be avail avail to user after he has clicked in a link that will come after every 24 Hour in my site. Means when a user first enters the site it will come and clicking in there the site will be avail avail. again after 24 Hour it will come again.

But i am not getting how to do it.

So need help

SaKIB

This topic has been moved to PHP Freelancing.

http://www.phpfreaks.com/forums/index.php?topic=332844.0

Hi,

I am creating a date string using the following:

$curDate = date("Y-m-d H:i:s");

However, what I want to do is take one hour off this so that $curDate now becomes the current date and time minus one hour.

Thanks for your help.

I insert a time value using the following code     $ti= ( !empty($_POST['time']) ) ? "'{$_POST['time']}'" : 'NULL';    I want to insert a second time value into a differen column which would be the same time minus 1 hour   something along the lines of :   $ti2= ( !empty($_POST['time']) ) ? "'{$_POST['time'] -1 hour}'" : 'NULL';    What would be the correct way to do it

My site allows users to vote once per hour, and it checks the next time they vote if it's been 3600 seconds  (1 hour) since their last vote. But, it always returns the value 0.

$grab = mysql_fetch_assoc($has_voted);

$calc = strtotime($grab['date']) - strtotime(date("M-d-Y"));

if($calc > 3600)

{

mysql_query("DELETE FROM votes WHERE ip = '". $_SERVER['REMOTE_ADDR'] ."'");

header("location:votes.php?id=". $id ."");

}

else

{

echo 

echo "You've voted within the last hour. Please wait ". $calc ." seconds.";

}

Hey guys only thing i can find online is examples of showing how much time is left until a predetermind time.

but what I need is how many minutes are left until the next hour hits

anyone have any ideas on this? Im wanting to do it in UNIX time