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PHP - Dynamically Print Url
Is there a way to dynamically print the url of a web page once it loads? If so, how? This is for metadata purposes.
Thanks! Similar TutorialsI've searched around the internet and can't find a good method to do this. To start, I have a database with a field called 'fpath' that stores the filepath (root-relative) to uploaded PDF's. In this case, they're scanned personnel files. What I'd like to do is be able to download relevant PDF's based on a generated report... such as all PDF's of a certain category or all PDF's for a certain user. If there's a specific PEAR package or other script out there that you know works well, I can research it on my own.. but each search result is bringing up a different method to do it, which makes me nervous. Thanks! Hi, This line of code works just fine for me: $sql_quest = 'SELECT id, username FROM user ORDER BY id ASC LIMIT 0, 30'; I want to be able to set the integer values dynamically and I thought something like this would work: $sql_quest = 'SELECT id, username FROM user ORDER BY id ASC LIMIT' . $my_int_value . ',' . $my_int_value + 30; But it doesn't... Any ideas? I need to fill an array dynamically with all the data in the users table. Any help will be appreciated, thanks! I am trying to make an edit page to edit any of my post...so i designed a manage post page manage-posts.php with the given code: Code: [Select] <?php echo '<form name="frmMain" action="del1.php" method="post" OnSubmit="return onDelete();">'; $objConnect = mysql_connect("hostname","username","password") or die(mysql_error()); $objDB = mysql_select_db("dbname"); $strSQL = "SELECT * FROM text"; $objQuery = mysql_query($strSQL) or die ("Error Query [".$strSQL."]"); echo '<table width="600" border="1">'; echo '<tr>'; echo '<th width="91"> <div align="center">ID</div></th>'; echo '<th width="91"> <div align="center">Date</div></th>'; echo '<th width="91"> <div align="center">Title</div></th>'; echo '<th width="91"> <div align="center">Author</div></th>'; echo '<th width="30"> <div align="center">Edit</div></th>'; echo '<th width="30"> <div align="center">Select</div></th>'; echo '</tr>'; while($objResult = mysql_fetch_array($objQuery)) { ?> <tr> <td><?=$objResult["id"];?></td> <td><?=$objResult["date"];?></td> <td><?=$objResult["title"];?></td> <td><div align="center"><?=$objResult["author"];?></div></td> <td align="center"><a href="edit.php?NewsID=<?php echo $objResult["id"];?>" name="edit">Edit</a></td> <td align="center"><input type="checkbox" name="chkDel[]" value="<?=$objResult["id"];?>"></td> <input type="hidden" name="id" value="<?=$objResult["id"];?>" /> </tr> <? } echo '</table>'; echo '<input type="submit" name="btnDelete" value="Delete">'; echo '</form>'; and i designed another page edit.php to perform deletion of that particular post with the following code " Code: [Select] <?php $objConnect = mysql_connect("hostname","username","pass") or die(mysql_error()); $objDB = mysql_select_db("dbname"); $strSQL = "SELECT * FROM text"; $objQuery = mysql_query($strSQL) or die ("Error Query [".$strSQL."]"); $objResult = mysql_fetch_array($objQuery); ?> <input type="hidden" name="id" value="<?=$objResult["id"];?>" /> Title : <br /><input type="text" name="title" size="100" maxlength="100" value="<?=$objResult["title"];?>"/> <br /> Date : <br /><input type="text" name="date" size="20" maxlength="12" id="TextBox" value="<?=$objResult["date"];?>"/> <br /> Author : <br /><input type="text" name="author" size="20" maxlength="100" value="<?=$objResult["author"];?>"/> <br /> <br /> <input type="submit" value="Submit" name="submit" /> </p> </form></fieldset></div> But the problem is that i am not able to get that particular post every time whenever i clicked on the respective post's edit link.. i suppose there is any issue in calling the id from the mysql... kindly suggest solutions... thanks in advance... I'm looking for any guidance on how to dynamically create css files. I want users to be able to select colors for fonts/backgrounds, borders, etc. from a form which they will submit and it will create a css file and put it in a certain folder. Can someone point me in the right direction? Hi there, so recently I have been trying to dynamically set the title on a page with PHP I have tried Code: [Select] <title><?ech"$username";?>'s Profile</title> the result is "'s Profile" note that the username variable is being passed thru a file that is required. Any help is appreciated What I want to do is create a table out of records from a table that shows an image and a radio button under the image (so I would imagine it would be in 2 rows). I want it to have 3 columns across. Here's what I have to get and output the results: $fabricsql = "SELECT * FROM Fabric f, Images i WHERE f.SKU = i.SKU"; //echo $fabricsql; $fabricResult = mysql_query($fabricsql); $i=0; while($fabricAssoc = mysql_fetch_assoc($fabricResult)){ //echo $fabricAssoc['SKU']. "+ ".$fabricAssoc['Name']; echo "<a href=\"\"><img src='../../".$fabricAssoc['ThumbPath']."' alt='".$fabricAssoc['Description']."' width='".$fabricAssoc['ThumbWidth']."' /></a><br /> <input type=\"radio\" name=\"fabricSelect\" value='".$fabricAssoc['SKU']."' id=\"RadioGroup1_".$i."\" /><br /><br />"; $i++; } Any help is much appreciated. I'm not even sure this is the best way to go about this so any suggestions are appreciated. I am trying to set the HTML Page Title dynamically, but this code from my book doesn't work... <title> <?php // Dynamically set Page Title. if (isset($page_title)){ echo $page_title; } else { // Default Page Title. echo 'Knowledge is Power: And It Pays To Know'; } ?> </title> What is wrong with it? (All I see is the code in the Webpage/Window Title...) TomTees Hello - I'm (very) new to php and working on a project and wondering if anyone can point the direction? (Not necessarily give the answer, but any helpful direction). I need to take YouTube video id's, (built into an array), and post the various video clips. Also the <object> code is in an php array. (Code Below.. hard to explain). Do I need to convert the array text into a string (as shown), and how do I take that string text and paste it into multiple youtube object posts? Note that the original $embedCode is commented out, '//), so that it can be referenced. Any advice is appreciated! <?php $number = 0; $youtubeIds = array("MX0D4oZwCsA","2v-v3jh-Cco","WuYDSa4BRaw","zwo48StJSr4","exOxUAntx8I"); // $embedCode = '<object width="480" height="385"><param name="movie" value="http://www.youtube.com/v/__YOUTUBE_ID__?fs=1&hl=en_US"></param><param name="allowFullScreen" value="true"></param><param name="allowscriptaccess" value="always"></param><embed src="http://www.youtube.com/v/__YOUTUBE_ID__?fs=1&hl=en_US" type="application/x-shockwave-flash" allowscriptaccess="always" allowfullscreen="true" width="480" height="385"></embed></object>'; $string = implode($youtubeIds); $embedCode = '<object width="480" height="385"><param name="movie" value="http://www.youtube.com/v/'<?php $string?>'?fs=1&hl=en_US"></param><param name="allowFullScreen" value="true"></param><param name="allowscriptaccess" value="always"></param><embed src="http://www.youtube.com/v/'<?php $string?>'?fs=1&hl=en_US" type="application/x-shockwave-flash" allowscriptaccess="always" allowfullscreen="true" width="480" height="385"></embed></object>'; ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" lang="en" xml:lang="en" xmlns:fb="http://www.facebook.com/2008/fbml" xmlns:og="http://opengraphprotocol.org/schema/"> <head> <title>Youtube Videos</title> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <meta name="language" content="en" /> </head> <body> <h1>Youtube Videos</h1> <p><?php for($i = 0; $i < count($youtubeIds); $i++) { echo $embedCode; } ?> </p> </body> </html> This code works: // create object $zip = new ZipArchive(); // open archive if ($zip->open('./download/zipfile.zip', ZIPARCHIVE::CREATE) !== TRUE) { die ("Could not open archive"); } but, I want to create the name of the zip file dynamically. The following code does not work ... doesn't give me an error, just doesn't create the zip file: // create object $zip = new ZipArchive(); $thisTime = time(); // open archive $thisZip = './download/'.$thisTime.'_download.zip'; $thisZip_b = $thisTime.'_download.zip'; if ($zip->open($thisZip, ZIPARCHIVE::CREATE) !== TRUE) { die ("Could not open archive"); } thanks in advance oh wise ones. mrsburnside So i have an url routing class set up. I wan to call method via url so it would look something like this: http://www.mysite.com/index.php/Class/Method/Parameter. I was able to instantiate class like this: Code: [Select] $controller = new $this->UrlPath[0]; But i can't call method the same way Code: [Select] $controller->$this->UrlPath[1](); Is there a way to call method with an array? I have a slideshow that I am having to modify for my needs. The data file uses an array and i need this to be dynamic. I need to loop through all images in a directory and create the array. I have the directory being stored in a variable already. Now i just need to loop though all images in that directory to create the array like you see in the below code. You can also see the directory variable at the top. Can someone give me a hand with this please? Code: [Select] <?php echo $slideimagefolder; //http://localhost:82/images/groupphotos/1/1/ $slides = array( // --- Start slide list --- // slide elements array( "slidelink" => "http://www.frontpageslideshow.net", "title" => "Frontpage Slideshow 1.7", "category" => "About Frontpage Slideshow", "tagline" => "Image taken from the movie \"Shoot 'em up\"", "text" => "\"Frontpage SlideShow\" is the most eye-catching way to display your featured articles, stories or even products in your php based website or CMS, like Time.com, Joost.com or Yahoo! Movies do. \"Frontpage SlideShow\" creates an uber-cool slideshow with text snippets laying on top of images. These \"slides\" are being rotated one after the other with a nice fade effect. The slideshow features navigation and play/pause buttons, so the visitor has complete control over the slideshow's \"playback\"! And best of all, Frontpage Slideshow can be skinned!", "slideimage" => "ao4.jpg" ), // slide elements array( "slidelink" => "http://www.frontpageslideshow.net", "title" => "Use Frontpage Slideshow on any PHP based site!", "category" => "About Frontpage Slideshow", "tagline" => "Image taken from the movie \"The Kingdom\"", "text" => "JoomlaWorks has developed this modification of Frontpage Slideshow to work on every website that supports PHP as a minimum requirement. We call this modification the \"Static PHP\" version of Frontpage Slideshow. It's ideal for use on non-Joomla!/Mambo websites, like for example your corporate PHP based website or your Wordpress blog or Drupal website! You can obviously use this version on any CMS that is based on PHP!", "slideimage" => "the_kingdom_20070820114258369.jpg" ), // slide elements array( "slidelink" => "http://www.frontpageslideshow.net/content/view/14/37/", "title" => "FPSS is Search Engine Friendly!", "category" => "About Frontpage Slideshow", "tagline" => "Image taken from the movie \"Invaders\"", "text" => "Unlike Flash based slideshows, Frontpage Slideshow uses unobtrusive javascript and some CSS wizardry only. The content of the slides is laid out as html code, which means it can be \"read\" by search engines. The proper usage (and order) of h1, h2, p (and more) tags will make sure Google (or any other search engine) regularly \"scans\" your latest/featured items.", "slideimage" => "TVD_TR_02183_2.jpg" ), // slide elements (***TIP***: copy this data block and paste it below itself to add more slides) array( "slidelink" => "http://www.joomlaworks.gr", "title" => "About JoomlaWorks", "category" => "", "tagline" => "Image taken from the movie \"Transformers\"", "text" => "JoomlaWorks is a team of professional web designers and developers dedicated to delivering high-quality extensions and templates for Joomla! (the most popular open source Content Management System (CMS) worldwide) and Mambo (award winning CMS). JoomlaWorks has established a solid reputation in the Joomla! & Mambo communities, having developed some of the most popular and innovative free & commercial extensions & templates, since 2006.", "slideimage" => "2007_transformers_014_1.jpg" ), // --- End slide list --- ); ?> Hi PhpFreaks, I have a method that I need to be initialised dynamically and I am not sure if the code below will work I have been able to workout if the method exists but I have not found a way to it get to return the array. Has anyone go any ideas? The error I get is: Catchable fatal error: Object of class Forms could not be converted to string Code: [Select] public function setMethodForms($methodName){ echo $methodName." and does it exist ". (int)method_exists($this->formsObj, $methodName); //test to see if the method exists if ((int)method_exists($this->formsObj, $methodName) == 1){ //if it does execute //print_r ($this->formsObj->projects()); //test to see if object works $return call_user_func($this->formsObj."->".$methodName."()"); } return $return; } Okay, this is my loop to show the birthday for Years. Code: [Select] <?php for ($i=2006; $i>=1900; $i=$i-1) { echo "<option value='$i'>$i</option>"; } ?> It will show 2012 to 1900 as a dropdown menu.. in my select form. Now I want to check the user input against this loop. The form is: Code: [Select] <select name="BirthDay[]"> <?php for ($i=2012; $i>=1900; $i=$i-1) { echo "<option value='$i'>$i</option>"; } ?> </select> Now, I want to use in_array function to check if it equals any of the values I looped, if it doesn't echo out "Hacker!" Here is my in_array Code: [Select] $bday = array( NEED TO PUT THIS LOOP HERE SOMEHOW?!?! ); if (!in_array($_POST['BirthDay'], $bday)) { message("Please select a Correct Birthday, or u trying to hack"); } Thanks if u can help! Hello
I am using fpdf to generate pdf files based on certain csv files. Now the client wants certain fields of the generated pdf file to be 'interactive' .
Is this possible ? Googling about editable (interactive pdf's) only confused me . any help ?
btw by interactive I mean fields that can be typed into directly by the client and then saved into the pdf .
Hey Guys, I'm querying a database that is going to return a html page. In this page I'm going to define content areas with a class. eg: <div class="category"></div> Anywhere I have this class in the html code, I want to dynamically insert a link into it. So when I retrieve the code from the database, I need the code to check for this tag (class="category") and add a standard link (<a href="..">Add new Category</a>) Not 100% sure whats the most efficient way to go about this. Hi! I am currently making a really simple photo blog. The query fetches every reference to the images which are stored on the server. I have a problem when it comes to dynamically cycling through these though. After running the query, I store each image reference in a twodimensional array like this: [["id"], ["date"], ["title"], ["filename"]] (an Array of Arrays). The image displays just fine by doing this: $pointer; //starting from the last element (image) in the array <img src="images/gallery/<?php echo $images[3][$pointer] ?>" alt="<?php echo $images[2][$pointer] ?>"> The problem is that, when I update the pointer, say for instance pointer++, the current image on the screen doesnt update. I know for a fact that the pointer updates, because I have echoed it. The basic idea is to have a previous and next link just under the image, so that the viewer can cycle the available images. Any help is greatly appreciated Friends, I have a PHP script that populates a calendar based on an array as follows: $days = array(2=>array('javascript:showWhatsOnText(2);','linked-day'), 3=>array('javascript:showWhatsOnText(3);','linked-day'), 4=>array('javascript:showWhatsOnText(4);','linked-day')); echo generate_calendar(2011, 4, $days, 1, '#'); where, for instance, the 2, 3 4 are the days of the month, By extracting a series values from a MySQL database how would I generate this array dynamically. E.g I have startday, startmonth, name and text fields in the database and would need to loop through them all to create the array. I tried playing around with something like this without any luck: $queryCat1 = "SELECT * FROM $dbCalendarEvents ORDER BY id ASC"; // WHERE visible = '1' $result1 = mysql_query($queryCat1) or die (mysql_error()); $num1 = mysql_num_rows($result1); $i=0; $daysArray = array(); while ($i < $num1) { $startday=mysql_result($result1,$i,"startday"); $startmonth=mysql_result($result1,$i,"startmonth"); $name=mysql_result($result1,$i,"name"); $name=mysql_result($result1,$i,"name"); $copy=mysql_result($result1,$i,"copy"); $daysArray[$i] = $startday=>array('/weblog/archive/2004/Jan/02','linked-day'); $i++; } Your help is appreciated. We recently migrated over to a new AMP platform that I built from source and now we can't dynamically generate images. It seems like GD is properly included into PHP (although I didn't know then I could do it using dynamic modules): My PHP configure is as follows: ================================================== './configure' '--prefix=/export/appl/pkgs/php/v5.3.9' '--with-apxs2=/export/appl/pkgs/httpd/latest/bin/apxs' '--with-mysql=/export/appl/pkgs/mysql/latest' '--with-mysqli=/export/appl/pkgs/mysql/latest/bin/mysql_config' '--with-gd=/export/appl/pkgs/libgd/latest' '--with-pear' '--with-png-dir=/export/appl/pkgs/libpng/latest' '--with-jpeg-dir=/export/appl/pkgs/jpeg/latest' '--with-curl=/export/appl/pkgs/curl/latest' '--with-freetype-dir=/export/appl/pkgs/freetype/latest' '--with-mhash=/export/appl/pkgs/mhash/latest' '--with-mcrypt=/export/appl/pkgs/libmcrypt/latest' '--enable-pcntl' '--enable-soap' '--enable-mbstring' '--with-zlib-dir=/export/appl/zlib/v1.2.5' '--with-ldap' ================================================== The GD section in phpinfo is as follows: ================================================== GD Support enabled GD Version 2.0 FreeType Support enabled FreeType Linkage with freetype FreeType Version 2.4.6 GIF Read Support enabled GIF Create Support enabled JPEG Support enabled libJPEG Version unknown PNG Support enabled libPNG Version 1.5.5 WBMP Support enabled Directive Local Value Master Value gd.jpeg_ignore_warning 0 0 ================================================== I get broken image icons in IE and Chrome, and I get an "image cannot be displayed" msg in FF. I'd appreciate someone clubbing me with a cluestick. - Joe Code: [Select] $query ="SELECT oneID FROM table WHERE table.PersonID = 'game.PlayerA'" ; $result = mysql_query($query); $row = mysql_fetch_array($result); $oneID = $row[0]; [code] If I then echo "$oneID" why does it not print anything? $result echos resource7 |
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