PHP - Default Value For Date Field?

Okay, I have a field called "created" in my `users` table, and I'd like to be able to view it in-game on an administrator panel. However, it's being captured in a long number format (i.e. 1335076320) which, I believe, has to deal with seconds and such.

How can I take that number and convert it to an actual date/time output?

Here's how I currently have it coded in my php form:


<tr><td width="20%">Registered On:</td><td>{{created}}</td></tr>



So, obviously it's not converting it to any format, rather just pulling that 1335076320 number out.

Thanks in advance!

Hi People. 

I am building a logbook application and have a form field where the user will enter a date.

However, I would like to simplify it for the user and give them a button which would add "todays" date into the box for them.

Please could someone tell me the code to do so.  The date format in my DB is YYYY-MM-DD.

The form would also need to take input from the user if they were adding info from a different day instead of today.

Thanks in advance.
Code: [Select]
<input type="text" name="date" id="date" size = "25"/>
    </label>
     <input type="submit" name="today" id="today" value="Add Today" />

Here is one part of php code. Here I try to show in last 1 month which dates exactly user made orders. When I run the SQL code in command prompt it works. I think problem is in while loop.

Thanks beforhand for contribution.


$query = "SELECT Date FROM orders WHERE User='$username' and DATE_SUB(CURDATE(),INTERVAL 30 DAY) <= Date;";
$result = mysql_query($query,$link_id) or die (mysql_error());

echo "<table border='1'>
        <tr>
          <td>&nbsp;Last 1 month's orders:</td>
        </tr>";
   
      while($order_date = mysql_fetch_row($result)) {
        echo "<tr>";
          echo "<td>" . $order_date[0] . "</td>";
        echo "</tr>";
      }
     
      echo "</table>

Hi all,   I have a search page where I'd like members to be able to search for races that they and their friends have entered into a database. When entering the data, users put the race date into the race_date field (Which is a DATETIME field) in the table.   I've set up the search and display pages, so users can search by a number of other criteria (first name, last name, race distance, time, etc), but am having trouble with searching by year. On my search form, is a field called race_year.   So, obviously I need some change in the code below, specifically in relation to the line $where .= " AND race_date='$race_year'"; because I want to extract the year part of the race_date column from the table and see if it matches $race_year .   Any advice would be appreciated.   Cheers, Dave  

$race_year = $_POST['race_year'];
if ($race_year != '')
{ // A year is selected
  $where .= " AND race_date='$race_year'";
}

Hi, I need to add a function for a date field on a form being submitted to MySQL DB. Something similar to this for a website field, except it shoudl make sure the format is in 01/05/2010 or 2numbers/2 numbers/4 numbers format...


if(!mb_eregi("^[a-zA-Z0-9-#_.+!*'(),/&:;=?@]*$", $website))
$this->setError('website', 'invalid website');
elseif(mb_strlen(trim($website)) > 120)
$this->setError('website', 'too long! 120 characters');


thanks in advance for any assistance.

hi i have a mysql table with upddate and updtime field as follows:
upddate       updtime
2011-02-25  11:03:05
2011-01-28  08:01:09
2011-02-20  07:00:08
2011-02-15  06:10:02
2011-02-05  10:21:04
2011-02-09  10:20:25

the data types for upddate is mysql date and for updtime its mysql time

In my php page i use Code: [Select]
<?php echo $date = date("d M Y",strtotime($row_rs1['upddate'])); ?> to retrieve date and the results displays as 25 Feb 2011. And for time right now im using Code: [Select]
<?php echo $row_rs1['updtime']; ?> which displays time as 11:03:05

I want to display time as HH:MM only, how can i do it?

Hey,

I'm using a script which allows you to click on a calendar to select the date to submit to the database.

The date is submitted like this: 2014-02-08

Is there a really simple way to prevent rows showing if the date is in the past?

Something like this:
if($currentdate < 2014-02-08 || $currentdate == 2014-02-08) {

}

Thanks very much,
Jack

Hi:
I'm going crazy trying to do the following:
I'm making a job registration process where the user registers on one php page to the website, must acknowlege and email receipt using an activate php page, then is directed to upload their C.V. (resume) based on the email address they enter in the active page output. I then run an upload page to store the resume in teh MySQL db based on the users email address in the same record.

If I isolate the process of the user registering to the db, it works perfectly.
If I isolate the file upload process into the db, it works perfect.
I simply cannot upload teh file to the existing record based on teh email form field matching the user_email field in the db.
With the processes together, teh user is activated, but teh file is not uploaded.

Maybe I've simply been at this too long today, but am compeled to get through it by end day.
If anyone can help sugest a better way or help me fix this, I will soo greatly appreciate it.

My code is as follows for the 2 pages.

---------activate.php-------
<?php
session_start();
include ('reg_dbc.php');
if (!isset($_GET['usr']) && !isset($_GET['code']) )
{
$msg = "ERROR: The code does not match..";
exit();
}
$rsCode = mysql_query("SELECT activation_code from subscribers where user_email='$_GET[usr]'") or die(mysql_error());
list($acode) = mysql_fetch_array($rsCode);
if ($_GET['code'] == $acode)
{
mysql_query("update subscribers set user_activated=1 where user_email='$_GET[usr]'") or die(mysql_error());
echo "<h3><center>Thank You! This is step 2 of 3. </h3>Your email is confirmed. Please upload your C.V. now to complete step 3.</center>";
} else
{ echo "ERROR: Incorrect activation code... not valid"; }

?>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">

<head>
<meta content="text/html; charset=utf-8" http-equiv="Content-Type" />
<title>Job application activation</title>
</head>
<body>
<center>
<br/><br/><br/>
<p align="center">
        <form name="form1" method="post" action="upload.php" style="padding:5px;">
        <p>Re-enter you Email : <input name="email" type="text" id="email"/></p></form>
          <form enctype="multipart/form-data" action="upload.php" method="POST">
          <input type="hidden" name="MAX_FILE_SIZE" value="4000000">
          Upload your C.V.: <input name="userfile" type="file" id="userfile">
          <input name="upload" type="submit" id="upload" value="Upload your C.V."/></form>
</p>
</center>
</body>

</html>
--------upload.php----------
<?php
session_start();
if (!isset($_GET['usr']) && !isset($_GET['code']) )
{
$msg = "ERROR: The code does not match..";
exit();
}
if(isset($_POST['upload']) && $_FILES['userfile']['size'] > 0)
{
$fileName = $_FILES['userfile']['name'];
$tmpName  = $_FILES['userfile']['tmp_name'];
$fileSize = $_FILES['userfile']['size'];
$fileType = $_FILES['userfile']['type'];
$email = $_POST['email']['user_email'];

$fp      = fopen($tmpName, 'r');
$content = fread($fp, filesize($tmpName));
$content = addslashes($content);
fclose($fp);

if(!get_magic_quotes_gpc())
{
    $fileName = addslashes($fileName);
}

include 'reg_dbc.php';

$query = "UPDATE subscribers WHERE $email = user_email (name, size, type, content ) ". "VALUES ('$fileName', '$fileSize', '$fileType', '$content')";

mysql_query($query) or die('Error, query failed');
mysql_close($dbname);
}
?>
<center>
<br/>
<br/>
<br/>
<br/>
Thank you for uploading your <?php echo "$fileName"; ?> file, completing your registration, and providing us your C.V. for this position.
<br/>
<br/>
<br/>
We will contact you if your canditature qualifies.
</center>

Code: [Select]
$new_array2=array_diff($my_array,$itemIds);

$updatedb = mysql_query("UPDATE content_type_ads SET field_expire_value = '666' WHERE $new_array2 = field_item_id_value");
"$new_array2" has only 12 digit numbers for each item in the array, and I want to match them to the "field_item_id_value" field in the table, updating the "field_expire_value" field for the record where they match.  I know I am close because the UPDATE code works before I add the WHERE statement (it of course adds '666' to EVERY field, but for a noobie it's a start!).

(Another quite newbie...)
I have already an online booking form. The Form works fine now and I would like to add on one more issue, but the code ignores what I want to check. I have 4 fields: arrival, departure, no. of persons and comments to check.

Scenario 1:

All field mentioned above are emtpty: Workes fine and message appears: "You have not provided any booking details".

Scenario 2:

If arrival (date_start) and departure (date_end) is entered, there should be at least an entry either in the field "comment", or in the field "pax". If not, there should be a message: "You have not provided sufficient booking details".

INSTEAD: The booking request is sent, which should not be the case.

The code is currently:

      # all fields empty : arrival, departure, pax and comments - error

if(empty($data_start) && empty($data_end) && empty($pax)&& empty($comment)){
    exit("You have not specified any booking details to submit to us.
    <br>Please use your browser to go back to the form.
    <br>If you experience problems with this Form, please e-mail us");
    exit;
}
      #If arrival  and departure date is entered, there should be at least an entry

either in the field "comment", or in the field "pax".
      
if(!isset($data_start) && !isset($data_end) && empty($pax) && empty($comment)){
    exit("You have not provided sufficient booking details.
    <br>Please use your browser to go back to the form.
    <br>If you experience problems with this Form, please e-mail us");
    exit;
}

The form can be tested at http://www.phuket-beachvillas.com/contact-own/contact-it.php

Can someone please check and tell me what's wrong with the code ? Thanks to anyone for any hint.

Hi,
I'm developing an app using flash AS2 as the front end via PHP and a mySQL database at the backend on my server.

what i'm looking to do is update/insert into a table called 'cards' and at the same time update/insert into another table called 'jingle'. There is a field called 'cardID' in jingle that should be the same as the ID number created in 'cards' thus creating a link between entries in the different tables that can be called up as i choose.

hope i've been clear i just wouldn't know where to start any help would be appreciated.

MySQL client version: 5.0.91
PHPmyAdmin Version information: 3.2.4


thanks in advance

Hello. I'm new to pHp and I would like to know how to get my $date_posted to read as March 12, 2012, instead of 2012-12-03.
Here is the code:
Code: [Select]
<?php

$sql = " SELECT id, title, date_posted, summary FROM blog_posts ORDER BY date_posted ASC LIMIT 10 ";

$result = mysql_query($sql);

while($row = mysql_fetch_assoc($result)) {
$id = $row['id'];
$title = $row['title'];
$date_posted = $row['date_posted'];
$summary = $row['summary'];

echo "<h3>$title</h3>\n";
echo "<p>$date_posted</p>\n";
echo "<p>$summary</p>\n";
echo "<p><a href=\"post.php?id=$id\" title=\"Read More\">Read More...</a></p>\n";
}

?>
I have tried the date() function but it always updates with the current time & date so I'm a little confused on how I get this to work.

I have tried a large number of "solutions" to  this but everytime I use them I see 0000-00-00 in my date field instead of  the date even though I echoed and can see that the date looks correct.

Here's where I'm at:
I have a drop down for the month (1-12) and date fields (1-31) as well as a text input field for the year.  Using the POST array, I  have combined them into the xxxx-xx-xx format that I am using in my field as a date field in mysql. 

<code>
$date_value =$_POST['year'].'-'.$_POST['month'].'-'.$_POST['day'];
echo $date_value;
</code>

This outputs 2012-5-7 in my test echo but 0000-00-00 in the database.

I have tried unsuccessfully to use in a numberof suggested versions of:
strtotime()
mktime

Any help would be extremely appreciated.
I am aware that I need to validate this data and insure  that it is a valid date. That I'm okay with. I would like some help on getting it into the database.

Alright, I have a Datetime field in my database which I'm trying to store information in. Here is my code to get my Datetime, however it's returning to me the wrong date. It's returning:
1969-12-31 19:00:00

$mysqldate = date( 'Y-m-d H:i:s', $phpdate );
$phpdate = strtotime( $mysqldate );
echo $mysqldate;


Is there something wrong with it?