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PHP - Displaying A Record From A Table As A Link In Php
I have the following code:
Code: [Select] $result = mysql_query("SELECT * FROM ESSAY_QUESTIONS WHERE SUBJECT = 'ENGLISH'") or die(mysql_error()); while($essay_data=mysql_fetch_array($result)){ $question = $essay_data['QUESTION']; $id = $essay_data['ID']; echo "<a href=\"englishessays.php?id=$id>"; echo "$question </a>"; echo "<br><br>"; } It seems to be almost working but it just displays one link and the address is all the rest of the code including </a>"; echo "<br><br>"; and other questions. I presume there's an error with how I've written the echo statements so can anyone see it? Or can anyone suggest a better way to do this? On the next page, the php will read the ID from the address and display the information form that record. Similar TutorialsI don't know if I'm wording this right. I have a textarea that is entered into a database. When this is edited, I want to store and display a list of all the changes that have been made to it. Like a conversation in a forum. The reason for this is that I want past changes to be locked from editing. Would a new database table storing only this text fields data need to be created? Maybe have column for the work request number and a second column for the text entered? But then wouldn't I need an third identifier column so the changes can be displayed in the right order? Looking for sage like wisdom Thanks Brad_Strickland I making an web app for teachers to assess their students online. The problems I am currently having are on select only one record is displayed and after update no records are displayed in the form even though it was successfully updated.. The program has two files, index.php and process.php. The problems started when got the class name into the query to search and display the class. $result = $mysqli->query("SELECT * FROM data WHERE classroom = '".$classroom."' ORDER BY '.name';") or die($mysqli->error); The query works but doesn't order by name I would like. I would be grateful if anyone could cast an eye over it and give me some tips. Thanks guys. The beers are on me if anyone can sort it, but you'll have to come to Phnom Penh, Cambodia as that is where I live. Anyway here's the code. process.php
<html>
<?php
session_start();
$mysqli = new mysqli("localhost","ray","password","reports") or die(mysqli_error($mysqli));
$id = 0;
$update = false;
$name = '';
$classroom = '';
if (isset($_GET['edit'])){
$id = $_GET['edit'];
$update = true;
$result = $mysqli->query("SELECT * FROM data WHERE id=$id") or die($mysqli->error());
if(isset($result->num_rows) && $result->num_rows > 0) {
$row = $result->fetch_array();
$name = $row['name'];
$classroom = $row['classroom'];
$pacomment = $row['pacomment'];
}
}
if (isset($_POST['update'])){
$id = $_POST['id'];
$pacomment = $_POST['pacomment'];
$mysqli->query("UPDATE data SET pacomment= '$pacomment' WHERE id=$id") or die($mysqli->error);
$_SESSION['message'] = "Record has been updated!";
$_SESSION['msg_type'] = "warning";
header('location: index.php');
}
index,php
<?php require_once 'process.php'; ?>
<!--************************************** Setup Messages **************************************** -->
<?php if (isset($_SESSION['message'])): ?>
<div class="alert alert-<?=$_SESSION['msg_type']?>">
<?php
echo $_SESSION['message'];
unset($_SESSION['message']);
?>
</div>
<?php endif ?>
<!--**************************************End Setup Messages *********************************************** -->
<?php
?>
<!DOCTYPE html>
<html>
<head>
<title>Home of English Reports</title>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width, initial-scale=1">
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.4.1/css/bootstrap.min.css">
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.5.1/jquery.min.js"></script>
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.4.1/js/bootstrap.min.js"></script>
<style>=
body {
margin: 0;
font-family: Arial, Helvetica, sans-serif;
}
.topnav {
overflow: hidden;
background-color: #008080;
}
.topnav a {
float: left;
color: #f2f2f2;
text-align: center;
padding: 14px 16px;
text-decoration: none;
font-size: 17px;
}
.topnav a:hover {
background-color: #ddd;
color: black;
}
.topnav a.active {
background-color: #4CAF50;
color: white;
}
</style>
</head>
<body style="background-color:linen;">
<!--************************************** End Setup Page Styles ************************************* -->
<div class="container">
<form action="index.php" method = get>
<label for="classroom">Class name:</label><br>
<input type="text" id="classroom" name="classroom" value="107i am"><br>
<input type="submit" value="Submit">
</form>
</div>
<?php $resultcomment = $mysqli->query("SELECT EnglishComment FROM comments"); ?>
<!-- ************************************** Begin Connect DB ************************************************ -->
<div class="container" align-content-center>
<?php
$classroom = (isset($_GET['classroom']) ? $_GET['classroom'] : null);
$result = $mysqli->query("SELECT * FROM data WHERE classroom = '".$classroom."' ORDER BY '.name';") or die($mysqli->error);
?>
<!-- ************************************** End Connect DB **************************************************** -->
<div class="row justify-content-center">
<form action="process.php" method="POST">
<input type="hidden" name="id" value="<?php echo $id; ?>">
<div class="form-group">
<h1><label><?php echo $name?></label></h1>
</div>
<form action="process.php" method="POST">
<input type="hidden" name="id" value="<?php echo $id; ?>">
<div class="form-group">
<h3><label>PA Teacher's Comment</label></h3> <select name = "pacomment">
<?php
while($rows = $resultcomment-> fetch_assoc())
{
$EnglishComment = $rows['EnglishComment'];
echo "<option value='$EnglishComment'>$name.$EnglishComment</option>";
}
?></h2>
</select><br>
<p>
<div class="form-group">
<?php
if ($update == true):
?>
<button type="submit" class="btn btn-info" name="update">Update</button>
<?php else: ?>
<!-- <button type="submit" class="btn btn-primary" name="save">Save</button> -->
<?php endif; ?>
</div>
</form>
<!-- ************************************** Begin Setup Table Headers ****************************************** -->
<div class="row justify-content-center">
<table class="table" width = "20%" border = "5" cellpadding = "1";>
<thead>
<tr>
<th><center>Action</center></th>
<th><center>ID</center></th>
<th>Name and Comment</th>
</tr>
</thead>
<!-- ************************************** End Setup Classlist Table Headers ****************************************** -->
<!-- ****** Loop thru Every Record From $result Query Variable and get variables and echo each variable into the table rows ********** -->
<?php
while ($row = $result->fetch_assoc()): ?>
<tr>
<td>
<center><a href="index.php?edit=<?php echo $row['id']; ?>"
class="btn btn-info">Assess</a></center>
</td>
<!-- ************************************** Put data into Classlist table rows ****************************************** -->
<td><center><?php echo $row['studentid']; ?></center></td>
<td><?php echo $row['name']." ".$row['pacomment'] ?></td>
</tr>
<?php endwhile; ?> <!-- ****************** End While() Loop **************************** -->
</table> <!-- *************** End of Classlist Table ****************************************** -->
</div>
</div>
</div>
</body>
</html>
Edited July 25, 2020 by raymon What is the best way to display the next record on a web page, from a list of records, without executing the query over and over again each time you display the next record? For example, imagine my user has a list of messages displayed on a web page, and the user filters that list to display all messages with the title "Test", and let's say that returns 12 records. He then clicks on record 1 to read that message. Once he is done reading it, he then wants to read msg 2, and then msg 3 etc. He could hit the Back button in his browser and click on the next record from the list, but it would be more useful to just click on a link that says "Next" which displays the next message in the filtered list of messages (without having to go back to the list). A lot of web sites do this sort of thing, but what is the best way to do it? Do you have to run the original query again each time a new message is loaded, so you know which message is next, or can you somehow store the query to save the server from having to run the same query over and over again? If a user is viewing a list of pictures for example, they could be flicking through the pictures quite quickly, and I would not like to have the server running the same query over and over again every few seconds when it doesn't need to. Advice? (Thanks.) This topic has been moved to Application Design. http://www.phpfreaks.com/forums/index.php?topic=347192.0 All I am trying to do is add a record on a page without the page refreshing. For that ajax is used. Here is the code.
It does not add the record to mysql table. Can anyone tell me what I am doing wrong?
record.php
<!DOCTYPE HTML>
<html lang="en">
<head>
<script type="text/javascript" src="js/jquery-1.11.0.min.js"></script>
<script type="text/javascript" >
$(function() {
$(".submit_button").click(function() {
var textcontent = $("#content").val();
var name = $("#name").val();
var dataString = 'content='+ textcontent + '&name='+name;
if(textcontent=='')
{
alert("Enter some text..");
$("#content").focus();
}
else
{
$("#flash").show();
$("#flash").fadeIn(400).html('<span class="load">Loading..</span>');
$.ajax({
type: "POST",
url: "action.php",
data: dataString,
cache: true,
success: function(html){
$("#show").after(html);
document.getElementById('content').value='';
$("#flash").hide();
$("#content").focus();
}
});
}
return false;
});
});
</script>
</head>
<body>
<?php
$record_id = $_GET['id']; // getting ID of current page record
?>
<form action="" method="post" enctype="multipart/form-data">
<div class="field">
<label for="title">Name *</label>
<input type="text" name="name" id="name" value="" maxlength="20" placeholder="Your name">
</div>
<div class="field">
<label for="content">content *</label>
<textarea id="content" name="content" maxlength="500" placeholder="Details..."></textarea>
</div>
<input type="submit" name="submit" value="submit" class="submit_button">
</form>
<div id="flash"></div>
<div id="show"></div>
</body>
</html>
action.php
if(isset($_POST['submit'])) {
if(empty($_POST['name']) || empty($_POST['content'])) {
$error = 'Please fill in the required fields!';
} else {
try {
$name = trim($_POST['name']);
$content = trim($_POST['content']);
$stmt = $db->prepare("INSERT INTO records(record_id, name, content)
VALUES(:recordid, :name, :content");
$stmt->execute(array(
'recordid' => $record_id,
'name' => $name,
'content' => $content
));
if(!$stmt){
$error = 'Please fill in the required fields.';
} else {
$success = 'Your post has been submitted.';
}
} catch(Exception $e) {
die($e->getMessage());
}
}
}
This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=353620.0 can i use a link to drop a record, or do u need to do a form and use a button to post to a page? Greetings! I have a website www.lanceronlinejobs.com/our_franchises.php I have a franchise images. I want to display each franchise record from database whenever a user click on franchise link. Here is my code. ourfranchises.php code: Code: [Select] <?php include('fconnection.php'); $sql = mysql_query("SELECT * FROM tbl_franchise ORDER BY id DESC") or die(mysql_error()); $row3 = mysql_fetch_array($sql); ?> <a href="franchiseDetails.php?city=<?php echo $row3['city'];?>"><img src="images/lbatkhela.jpg" width="150" height="150" alt="Batkhela" /></a>---------------------------------------------------------------------- franchiseDetails.php code: Code: [Select] <?php $id = $_GET['id']; $query = "SELECT * FROM tbl_franchise WHERE id = '$id' ORDER BY id DESC LIMIT 1"; $result = mysql_query($query); if (!$result) { echo "NO RECORD FOUND"; } else { while($row3 = mysql_fetch_array($result)): ?> Manager Name: <?php echo $row3['manager_name'];?> Please help me. Any help would be appreciated. Thanks. I have finaly got my removing recods page working, but i do have one problem... i have a delete button which goes to a new php page which contains the DELETE FROM, this deletes the record automaticaly. There are two paths which i could choose from the problem is i am stuck on both of them. 1. a link that will activate the delete code. 2. once the record has been deleted then it will automaticaly go back the the first page. can any one help me here please? I know with a submit button I can have a new record created when clicking it, but is it possible to do with a text link? Not sure how to update a record in my table here. I got my insert and delete statement working. Just can't get the update to work correctly. I'm not really sure how to do it. Here is my code for my page, and my update and delete page Code: [Select] <?php ini_set ("display_errors", "1"); error_reporting(E_ALL); require_once('database.php'); session_start(); if (isset($_POST['add_grade'])) { $query = "INSERT INTO grades (grade_id, student_id, grade_type, grade_name, grade_points) "; $query .= "VALUES (:grade_id, :student_id, :grade_type, :grade_name, :grade_points) "; $statement = $db->prepare($query); $statement->bindValue (':student_id', $_SESSION['student_id']); $statement->bindValue (':grade_id', $_SESSION['grade_id']); $statement->bindValue (':grade_type', $_POST['grade_type']); $statement->bindValue (':grade_name', $_POST['grade_name']); $statement->bindValue (':grade_points', $_POST['grade_point']); $statement->execute(); $statement->closeCursor(); $grade_type = $_POST['grade_type']; if ($grade_type == 'Lab') { $final *= .60; } echo $final; $grade_type = $_POST['grade_type']; if ($grade_type == 'Mid-Term') { $final *= .20; } echo $final; $grade_type = $_POST['grade_type']; if ($grade_type == 'Final') { $final *= .20; } echo $final; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>View Course Grades</title> <link rel="stylesheet" type="text/css" href="main.css" /> </head> <body> <?php $student_name = $_SESSION['student_name']; $student_id = $_SESSION['student_id']; $query = "SELECT * FROM grades WHERE student_id = :student_id "; $statement = $db->prepare($query); $statement->bindValue (':student_id', $student_id); $statement->execute(); $grades = $statement->fetchAll(); $statement->closeCursor(); echo "<h1>Show Grades for $student_name </h1>"; foreach ($grades as $grade) { echo $grade['grade_type'] . " " . $grade['grade_name']. " " . $grade['grade_points'] . "<br />"; } ?> <div id="content"> <!-- display a table of products --> <table> <tr> <th>Grade Type</th> <th>Grade Name</th> <th>Grade Points</th> <th>Remove</th> </tr> <?php foreach ($grades as $grade) : ?> <tr> <td><?php echo $grade['grade_type']; ?></td> <td><?php echo $grade['grade_name']; ?></td> <td><?php echo $grade['grade_points']; ?></td> <td><form action="delete_grade.php" method="post"> <input type="submit" name="remove" value="Delete" /> </form></td> </tr> <?php endforeach; ?> </table> </div> </div> <div id="footer"> </div> <form name="grades" method="post" action="grades.php"> <p>Grade Type<SELECT NAME="grade_type"> <OPTION VALUE="Mid-Term">Mid-Term <OPTION VALUE="Final">Final <OPTION VALUE="Lab">Lab </SELECT> <br> Grade Name:<input type="text" name="grade_name" value=""><br /> Grade Points:<input type="text" name="grade_point" value=""> <input type="submit" name="add_grade" value="Add Grade"> </form> </table> </body> </html> My delete and update page Code: [Select] <html> <head> <title>Delete Grade</title> </head> <body> <form method="post" action="delete_grade.php"> <?php ini_set ("display_errors", "1"); error_reporting(E_ALL); $dbc = mysqli_connect('localhost', 'se266_user', 'pwd', 'se266') or die(mysql_error()); //delete grades if (isset($_POST['remove'])) { foreach($_POST['delete'] as $delete_id) { $query = "DELETE FROM grades WHERE grade_id = $delete_id"; mysqli_query($dbc, $query) or die ('can\'t delete user'); } echo 'user has been deleted.<br />'; } if (isset($_POST['update'])) { foreach($_POST['update'] as $update_id) { $query = "UPDATE grades SET grade_id = $grade_id"; mysqli_query($dbc, $query) or die ('can\'t update user'); } } //Display grade info with checkbox to delete $query = "SELECT * FROM grades"; $result = mysqli_query($dbc, $query); while($row = mysqli_fetch_array($result)) { echo '<input type="checkbox" value="' .$row['grade_id'] . '" name="delete[]" />'; echo ' ' .$row['grade_type'] .' '. $row['grade_name']; echo '<br />'; } mysqli_close($dbc); ?> <input type="submit" name="remove" value="Remove" /> <input type="submit" name="update" value="Update" /> </form> </body> </html> I have some code that will update a record and is generic, meaning any POST variables can be used - whatever you have on the form. See below: Code: [Select] $set = array(); foreach($_POST as $field => $value){ $field = mysql_real_escape_string($field); $value = mysql_real_escape_string($value); $set[] = "`{$field}` = '{$value}'"; } $query .= implode(", ",$set) . " WHERE $id_name = '".$id."' LIMIT 1"; mysql_query($query) or die(mysql_error()); My question is, how would I modify this to insert a NEW record (not update an existing one). I'm not sure how to order this within a foreach statement because the add query has a different form: insert into tabel (all the fieldnames here) VALUES (all the values here) Hi, I just want to know how to check if a row/record already exists for a given table, but this code gives me message in browser: Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in myTest.php This is the the snippet I am running: Code: [Select] <?php $connxn=mysql_connect("localhost","root"); $db=mysql_select_db("siliconvalley"); $toyNodePath="#document/siliconValleyHELLO"; $queryA=mysql_query("SElECT FROM pathexpress (path_express) WHERE path_express='$toyNodePath'");//make sure AT MOST ONE ROW EXISTS!! if(mysql_num_rows($queryA)==1) print "ALREADY IN table pathexpress!"; else { mysql_query("INSERT INTO pathexpress (path_express) VALUES ('$toyNodePath')"); print "ADDED $toyNodePath to table pathexpress!"; } ?> Please, any help is greatly appreciated! This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=348130.0 Greetings mates, I have not been here for years. I have been thrust into an app written by someone else. The requirement is to amend, not edit, an existing record. In other words, rather than edit an existing record, management would like an empty new text box to enter amended data and save to another table so that when queried, would display existing record and the newly amended record. Below is an ID of an existing record:
$sql = "SELECT * FROM DBO.existingTable where year_created = 2019 Order by Id";
echo '<table id="results-table">
<thead>
<tr>
<th>ID</th>
<th>Edit</th>
<th>View PDF</th>
<th>Task Lead</th>
<th>Task Title</th>
<th>Division</th>
</tr>
</thead>';
while ( $row = sqlsrv_fetch_array( $stmt, SQLSRV_FETCH_BOTH ) ) {
$div = ($row['division'] == "1" ? "Divname" : ($row['division'] == "2" ? "Highway" : "NULL"));
$taskType = ($row['task_type'] == 0 ? "Annual" : ($row['task_type'] == 1 ? "Carryover" : ($row['task_type'] == 2 ? "New" : "NULL")));
if($row['year_created'] == 2019){
echo '<tr id="taskId">
<td>'.$row['Id'].'</td>
<td><a href="project_edit.html?id='.$row['Id'].'" target="_blank">Edit</a></td>
<td><input type="button" onclick="getReport('.$row['Id'].')" value="View PDF"></td>
<td>'.$row['task_lead'].'</td>
<td>'.$row['task_title'].'</td>
<td>'.$div.'</td>
</tr>
}
}
echo '</table>'
The above code isa snippet of code in edit.php. What I would like to do is grab the ID which is '.$row['Id'].' from this edit page and use it when inserting the amended code which is in insert,php file:
//The ID from edit.php code should go here
$task_lead = (empty($_POST['task_lead'])) ? "''" : "'" . str_ireplace( "'", "", $_POST[ 'task_lead' ] ) . "'";
$task_title = (empty($_POST['task_title'])) ? "''" : "'" . str_ireplace( "'", "''", $_POST[ 'task_title' ] ). "'";
$division = (empty($_POST['division'])) ? "''" : "'" . str_ireplace( "'", "", $_POST[ 'division' ] ) . "'";
//Then my insert statement should be something like this:
$sql = "INSERT INTO DBO.Amended_Records ({id from table with existing record}, amended_taskActivities, amended_taskProducts,amendscope_dev_fhwa, amendconsultant_procurement, amendcontract_negotiations, amendconsultant_notice, amendtotal_duration, year_created)
VALUES ({$rowId - that I need to get from edit.php}, $amendproposed_activities, $amendanticipated_products,$amendscope_dev_fhwa,$amendconsultant_procurement,$amendcontract_negotiations,$amendconsultant_notice,$amendtotal_duration, 2021)";
When I insert this record into the DB, the id from edit.php is getting inserted as null. Can you please advise how I can resolve this? I posted a topic earlier and there was confusion as to what I could not work out.
I am able to display the checkbox, either checked or unchecked depending of the value or 1 or 0 in the obcDisplay field.
<input type="checkbox" name="obcDisplay" value="<?=$r['obcDisplay'] ?>" <?=($r['obcDisplay']) ? 'checked="checked"' : ''; ?>/>I am trying to update the DB table by the checkbox. If the checkbox is checked (obcDisplay = 1) and I uncheck the box and submit, I want the table updated so that obcDisplay now equals 0. When the form is displayed, the checkbox is now uncheck (obcDisplay = 0). Now I check the box and submit and the update changes the field from 0 to 1. I can display the checkbox as checked or unchecked by the DB field obcDisplay being either 0 or 1. It is changing the value where I am having the problem. Hello,
Here is my current code:
index.php
<html>
<body>
<form id="hey" name="hey" method="post" onsubmit="return false">
Name:<input type="text" name="name">
<input type="submit" name="submit" value="click">
</form>
<table class="table table-bordered" id="update">
<thead>
<th>Name</th>
</thead>
<tbody>
<script type="text/javascript">
$("#hey").submit(function() {
$.ajax({
type: 'GET',
url: 'response.php',
data: { username: $('#name').val()},
success: function (data) {
$("#update").prepend(data);
},
error: function (xhr, ajaxOptions, thrownError) {
alert(thrownError);
}
});
});
</script>
</tbody>
</table>
response.php
<?php $username = $_GET['username']; echo "<tr>"; echo "<td>$username</td>"; echo "</tr>"; ?>This code works fine, it prints out the rows as what the user enters. Now what I want to do is, log all these entries to a mySQL database and also, display these rows over the site. i.e., any user who is online, should be seeing this without having to refresh the page too.. Real time updates in a way. How can I achieve that? Thanks! Hey all! In the code in question I echo out individual records of data from MySQL successfully. For each record there is a number which is used as a var in the javascript that does the count-down-timer part. However when I view the resulting page the timer works dynamically only with the first record. With the rest, the timer is static. Code: [Select] <? $result0 = mysql_query("SELECT * FROM table WHERE field='$value'"); while ($riw0 = mysql_fetch_assoc($result0)) { $seconds1 = $riw0['seconds'] ; //// echo out data and set variable for the number of seconds to count down ?> <script language="JavaScript"> var countDownInterval=<?=$seconds1?>; var c_reloadwidth=200 </script> <ilayer id="c_reload" width=&{c_reloadwidth}; ><layer id="c_reload2" width=&{c_reloadwidth}; left=0 top=0></layer></ilayer> <script> var countDownTime=countDownInterval+1; function countDown(){ countDownTime--; if (countDownTime <=0){ countDownTime=countDownInterval; clearTimeout(counter) window.location.href="military3.php" //Redirection URL return } var mins = Math.floor(countDownTime/60) var secs = countDownTime-(mins*60) if (document.all) //if IE 4+ document.all.countDownText.innerText = mins+" minutes "+secs+ " "; else if (document.getElementById) //else if NS6+ document.getElementById("countDownText").innerHTML=mins+" minutes "+secs+ " " else if (document.layers){ document.c_reload.document.c_reload2.document.write('Soldiers will be ready in... <span id="countDownText">'+countDownTime+' </span> seconds') document.c_reload.document.c_reload2.document.close() } counter=setTimeout("countDown()", 1000); } function startit(){ if (document.all||document.getElementById) document.write('Soldiers will be ready in <span id="countDownText">'+countDownTime+' </span> seconds') countDown() } if (document.all||document.getElementById) startit() else window.onload=startit </script> <? } ?> I tried replacing the javascript vars with PHP echoes for unique variables, but then no timer shows up, even static. So could anyone advice me on how I could use this code to apply for all MySQL records? Thanks in advance, Thauwa P.S. If I am unclear with my quandary, do let me know. Thank you. Hi, n0obie here. I'm trying to identify where my customers are coming from via emails I've sent/received. However, many email providers (namely Gmail) have circumvented this by disallowing IP address geolocation/image caching. |
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