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PHP - How To Make This Tables
Hi Guys,
I building a system, where i have a customer table where user info is saved, and customer can choose the package like silver, gold, and platinum customer table: ID Username Password Name Address Active Now i want to make a table for choosing packages: package table: Package_ID Package_Name Package_Description Package_Duration Package_Amount Package_Active 1.Now my doubt is, whether Duration can be kept in days/month for example: 90 days or January, February, March 2.Package_Amount: what currency to be specify. Because am building a system for international users, what currency to be specify. (500 INR or 10USD) 3. what about upgrade of package: give me some ideas how to handle this. Please Help me, and i guess i have a design a table right. Thanks, Similar TutorialsHi again, i'm wondering how can i make Sort (for example a-z) an column in php reading mysql informations. Here's the script: <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html> <head> <title></title> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1"> <link rel="stylesheet" href="table.css" type="text/css"> </head> <body style="margin: 0 0 0 0;"> <? include("passwd.php"); @$start = $_GET["start"]; if($start =='') $start =0; include("lib.php"); $link = mysql_connect($host,$username,$password); if (!$link) { die('Could not connect: ' . mysql_error()); } $db_selected = mysql_select_db($db, $link); if (!$db_selected) { die ("Can't use $db : " . mysql_error()); } //total number of records in the table $res = mysql_query("SELECT * from `$table`"); @$rows = mysql_num_rows ($res); $result = mysql_query("SELECT * from `$table` limit $start,10"); if (!$result) { die('Invalid query: ' . mysql_error()); } echo "<p align=center class = 'menu'> Ocitana tabela: $table </p>"; $cols = mysql_num_fields($result); $records = mysql_num_rows ($result); echo "<table align='center' width='1200' >"; echo "<tr bgcolor='BBCCDD' class='menu'>"; for ($i = 0; $i < $cols;$i++) { echo "<td align='center'>".mysql_field_name($result,$i)."</td>"; } echo "</tr>"; while ($row = mysql_fetch_array($result, MYSQL_NUM)) { echo "<tr bgcolor='F6F6F6' class='normal'>"; foreach ($row as $value) { echo "<td align='center'>".$value ."</td>"; } echo "</tr>"; } $end = $start + $records; echo "<tr align = 'center' bgcolor = 'BBCCDD' class='menu'><td colspan=$cols> Prijema $start do $end od $rows </td></tr>"; echo "<tr align = 'center' class='mylink'><td colspan=$cols> "; if($start != 0) { $prev = $start - 10; echo "<a href='tabela.php?start=$prev'> Prethodna </a> "; } if($start<$rows-10) { $next = $start + 10; echo "<a href = 'tabela.php?start=$next'>Sledeca</a> "; } echo "</td></tr>"; echo "</table>"; ?> </body> </html> I'm working on a web based RPG game, and I want the ability to run different "servers" but I'm not sure what the best way to go about it would be.
First idea: Create a table which would be named, "world" when a character is created, they get to choose a world to join, and then use world_id to know what items, mobs, npc, is in that world. Here is just a quick mock-up of the table.
Second idea: Create a whole new database for the game data, creature_game contains the accounts and forum data. While creature_server_x contains the rest of the game. The structure of each database would be exactly the same.
I want the people that runs the different "servers" to be able to do whatever changes they want, even if that would mean to rewrite the story line. I could do it with both the first and second idea. But I want to hear about what people here think is best and why. Ofc, they won't be able to access or change the tables inside the databases, just the data the tables contains.
Im doing a search system and Im having some problems.
I need to search in two tables (news and pages), I already had sucess doing my search system for just one table, but for two tables its not easy to do.
I already use a select statment with two tables using UNION because I want to show number of search results, that is number of returned rows of my first sql statment.
But now I need to do a select statment that allows me to acess all fields of my news table and all fields of my pages table.
I need to acess in my news table this fields: id, title, content, link, date, nViews
I need to acess in my pages table this fields: id, title, content, link
Im trying to do this also with UNION, but in this case Im not having any row returning.
Do you see what I have wrong in my code?
<?php //first I get my $search keyword $search = $url[1]; $pdo = connecting(); //then I want to show number of returned rows for keyword searched $readALL = $pdo->prepare("SELECT title,content FROM news WHERE title LIKE ? OR content LIKE ? UNION SELECT title,content FROM pages WHERE title LIKE ? OR content like ?"); $readALL->bindValue(1,"%$search%", PDO::PARAM_STR); $readALL->bindValue(2,"%$search%", PDO::PARAM_STR); $readALL->bindValue(3,"%$search%", PDO::PARAM_STR); $readALL->bindValue(4,"%$search%", PDO::PARAM_STR); $readALL->execute(); //I show number of returned rows echo '<p>Your search keyword returned <strong>'.$readALL->rowCount().'</strong> results!</p>'; //If dont return any rows I show a error message if($readALL->rowCount() <=0){ echo 'Sorry but we didnt found any result for your keyword search.'; } else{ //If return rows I want to show, if it is a page result I want to show title and link that I have in my page table //if it is a news result I want to show title and link that I have in my news table and also date of news echo '<ul class="searchlist">'; $readALL2 = $pdo->prepare("SELECT * FROM news WHERE status = ? AND title LIKE ? OR content LIKE ? LIMIT 0,4 UNION SELECT * FROM pages where title LIKE ? OR content LIKE ? LIMIT 0,4"); $readALL2->bindValue(1, '1'); $readALL2->bindValue(2, "%$search%", PDO::PARAM_STR); $readALL2->bindValue(3, "%$search%", PDO::PARAM_STR); $readALL2->bindValue(4, "%$search%", PDO::PARAM_STR); $readALL2->execute(); while ($result = $readALL2->fetch(PDO::FETCH_ASSOC)){ echo '<li>'; echo '<img src="'.BASE.'/uploads/news/'.$result['thumb'].'"/>'; echo '<a href="'.BASE.'/news/'.$result['id_news'].'">'.$result['title'].'</a>'; //if it is a news result I also want to show date on my list //echo '<span id="date">'.$result['date'].'</span>'; echo '</li>'; } echo ' </ul>'; //but how can I do my select statement to have access to my news table fields and my page table fields?? } ?> This portion is kind of stumping me. Basically, I have a two tables in this DB: users and users_access_level (Separated for DB normalization) users: id / username / password / realname / access_level users_access_level: access_level / access_name What I'm trying to do, is echo the data onto an HTML table that displays users.username in one table data and then uses the users.access_level to find users_access_level.access_name and echo into the following table data, I would prefer not to use multiple queries if possible or nested queries. Example row for users: 1234 / tmac / password / tmac / 99 Example row for users_access_level: 99 / Admin Using the examples above, I would want the output to appear as such: Username: Access Name: Tmac Admin I am not 100% sure where to start with this, but I pick up quickly, I just need a nudge in the right direction. The code I attempted to create just shows my lack of knowledge of joining tables, but I'll post it if you want to see that I did at least make an effort to code this myself. Thanks for reading! I am trying to write some data from multiple SQL tables to a page. In the first table is a list of places. I then have more tables that are named after the different places. For example, say my first place in the list is called Place1. I have a table named Place1 with data that corresponds to place1. The data contained in the table named Place1 is a list of things to do in this place. It has 21 columns and each one is something to do in the morning, afternoon, and at night for each day of the week in the place Place1. What I am trying to do is display a sort of weekly calendar as a table on a webpage that lists all of the places in one column and then lists seven days of the week as 7 more columns. Then in each data cell I would want to list the things to do in the morning, afternoon and at night for the certain day of the week and for the place. The problem is that I am creating a CMS to allow other users with no coding knowledge to update events for other places, so I have to display data that could have been altered. The only solution I know of is to do a while loop that gets all of the place names and while there are still place names, write the place names to the page and set a variable equal to the place name. Inside the while loop I would create another while loop that each time the first while loop is executed uses the variable set in the first while loop to know which table to reference and then make a call to that table pulling out the 21 columns and writing them to the page. Each time the outer while loop executes, it would (hopefully) write the place name, and then set the variable as the current place name so that the inner while loop uses the variable to write the rest of the information about that place. I don't know if that would even work and if it did, I know it cannot be the best way to do this. I am pretty stuck here and don't really have a good solution so if anyone proposes a solution that is radically different to anything I have done, I am open to everything. Thank you! Okay so my news script is set to view only 10 pieces of news. But I want it so that it starts a new page once I have more than 10 pieces of news. Code: [Select] <?php require("functions.php"); include("dbconnect.php"); session_start(); head1(); body1(); new_temp(); sotw(); navbar(); $start = 0; $display = 10; $query = "SELECT * FROM news ORDER BY id DESC LIMIT $start, $display"; $result = mysql_query( $query ); if ($result) { while( $row = @mysql_fetch_array( $result, MYSQL_ASSOC ) ) { news_box( $row['news'], $row['title'], $row['user'], $row['date'], $row['id'] ); } mysql_free_result($result); } else { news_box( 'Could not retrieve news entries!', 'Error', 'Error', 'Error'); } footer(); mysql_close($link); ?> I tried a few things but they failed....miserably. Hi there, As the question says i tried several things but i can't work it out and my knowledge about php isn't that well. $looponce = 1; foreach ($this->info as $k => $v) { if ( (($k == 'subject') && ($v['required'])) && (!$this->settings['customSubject'])) { for ($i = 0; $i <= 0; $i++) { $output[] = $this->display_errors('error_system_subject'); } } if ( (($k == 'name') && (!$v['required'])) || ((!array_key_exists("name", $this->info)) && ($looponce == 1)) ) { $output[] = $this->display_errors('error_system_name'); $looponce++; } } That is my loop that i check things in. What i'm more interested in is the name if statement. If currently checks for a name key in an array(below) and makes sure that it is set to required. If it's not set to required, print out a system error and die()'s. I'm looking for ways to remove the need for program errors and just change them to what is needed to run. What i know how to do is, get into the inner array, what i don't know is how to edit the data and put it back exactly as it was given to me. The inner array data can be put back in any order, but the outer array must be in exact order as it was given. above code $this->info = $formdata; $formdata = array( 'name' => array('name'=>"Full Name", 'required'=>false, 'type'=>'text'), # This needs to be required=>true, but i can't trust the user, which is why i have the error. 'telephone' => array('name'=>"Telephone", 'required'=>false, 'type'=>'phone'), ); Any help is greatly appreciated, also am i doing the foreach loop in the code above in an efficient manner or is there another way? hi everyone, Whats the best way to put my displayed php into my table? I already have gotten to the point where it is displayed, but it looks basic, so i want it to look like the table below it.... i just havent quite figured out how to "space" the data out so it looks better? Is it just a case of printing out what i want where in the table? or is it something more complex? http://www.removalspace.com/indextwo.php Hi everyone! I am trying to figure out how to put echoed php results from mySQL database into a table ready for styling to look how i want it too. So far i have got to the point where the results are echoed out but they are not in a good table layout. (under "latest removalspace user's) I want it more structured in my table. I have found out how to create the table but just not been able to work out how to fit the echo's in without snytax errors??? the "new" table that i want to use is near the end of the script. Code: [Select] <?php // Make a MySQL Connection mysql_connect("***", "***", "***") or die(mysql_error()); mysql_select_db("***") or die(mysql_error()); // Retrieve all the data from the "example" table $result = mysql_query("SELECT company_name, location, postcode, basicpackage_description, premiumuser_description, upload FROM Companies") or die(mysql_error()); // store the records into $row array and loop through while ( $row = mysql_fetch_array( $result, MYSQL_ASSOC ) ) { // Print out the contents of the entry echo "Name:\r".$row['company_name']; echo "\r\rLocation:\r".$row['location']; echo "\r\rPostcode:\r".$row['postcode']; echo "\r\nBasic Users:\r".$row['basicpackage_description']; echo "\r\nPremium Users:\r".$row['premiumuser_description']; echo "\r\nlogo:\r".$row['upload']; echo "<img src=\"http://www.removalspace.com/images/COMPANIES" . $row['upload'] . "\" alt=\"logo\" />"; echo "<table> <tr><th>Comppany Name</th><th>Location</th><th>Postcode</th><th>Basic Members</th><th>Upgraded Users</th><th>Company Logo</th></tr> <tr><td></td><td></td><td></td><td></td><td></td><td></td></tr>"; } ?> Hi everyone... I have a thumbnail page that is putting out tables that are skewed and I am not able to use CSS properly because of that. Is there anyways I can change the PHP output? This is my code... I think the highlighted area is responsible for my tables? But it is mismatching the <tr> and <td> tags.... I really want it to show a structured table.. like <table> <tr> <td> </td> </tr> </table> // Thumbnail Listing else if( $cid && empty( $pid ) ) { $number_of_thumbs_in_row = 4; // If current page number, use it // if not, set one! if(!isset($_GET['page'])){ $page = 1; } else { $page = $_GET['page']; } // Define the number of results per page $max_results = 400; // Figure out the limit for the query based // on the current page number. $from = (($page * $max_results) - $max_results); $result = mysql_query(" SELECT photo_id , photo_caption , photo_filename , photo_category FROM gallery_photos WHERE photo_category='".addslashes($cid)."' LIMIT $from, $max_results "); $nr = mysql_num_rows( $result ); if( empty( $nr ) ) { $result_final = "\t<tr><td>No Photos found</td></tr>\n"; } else { while( $row = mysql_fetch_array( $result ) ) { $result_array[]= "<a href='viewgallery.php?cid=$cid&pid=".$row[0]."'><img src='".$images_dir."/tb_".$row[2]."' border='0' alt='".$row[1]."' class='img'/></a>"; } $result = mysql_query( "SELECT category_name FROM gallery_category WHERE category_id='".addslashes($cid)."'" ); list($category_name) = mysql_fetch_array( $result ); mysql_free_result( $result ); $result_final = "<tr>\n\t<td> <span class='navlinks'><a href=viewgallery.php>Albums</a></span><font color=#ff0000> >> </font> <span class='navlinks'><a href=viewgallery.php?cid=$cid>$category_name</a></span><br><br/><br/><br/></td>\n</tr>\n"; foreach($result_array as $thumbnail_link) { if($counter == $number_of_thumbs_in_row) { $counter = 1; [b][size=24pt][size=18pt][b]$result_final .= "\n</tr>\n<tr>\n";[/b][/size][/size][/b] } else $counter++; [b][size=18pt] $result_final .= "\t<td>".$thumbnail_link."</td>\n";[/size][/b] } if($counter) { And my HTML output shows the tables like this... Code: [Select] <body> <table width='100%' border='0' align='center' style='width: 80%;'> <tr> <td> <span class='navlinks'><a href=viewgallery.php>Albums</a></span><font color=#ff0000> >> </font> <span class='navlinks'><a href=viewgallery.php?cid=1>Abstract</a></span><br><br/><br/><br/></td> </tr> <td><a href='viewgallery.php?cid=1&pid=240'><img src='photos/tb_240.jpg' border='0' alt='End Of Day' class='img'/></a></td> <td><a href='viewgallery.php?cid=1&pid=239'><img src='photos/tb_239.jpg' border='0' alt='A Photographer's Dream' class='img'/></a></td> <td><a href='viewgallery.php?cid=1&pid=238'><img src='photos/tb_238.jpg' border='0' alt='Heaven's View' class='img'/></a></td> <td><a href='viewgallery.php?cid=1&pid=237'><img src='photos/tb_237.jpg' border='0' alt='Colorful World ' class='img'/></a></td> </tr> <tr> <td><a href='viewgallery.php?cid=1&pid=241'><img src='photos/tb_241.jpg' border='0' alt='' class='img'/></a></td> <td><a href='viewgallery.php?cid=1&pid=242'><img src='photos/tb_242.jpg' border='0' alt='' class='img'/></a></td> <td><a href='viewgallery.php?cid=1&pid=243'><img src='photos/tb_243.jpg' border='0' alt='' class='img'/></a></td> <td><a href='viewgallery.php?cid=1&pid=244'><img src='photos/tb_244.jpg' border='0' alt='' class='img'/></a></td> </tr> <tr> <td><a href='viewgallery.php?cid=1&pid=245'><img src='photos/tb_245.jpg' border='0' alt='' class='img'/></a></td> <td><a href='viewgallery.php?cid=1&pid=246'><img src='photos/tb_246.jpg' border='0' alt='' class='img'/></a></td> <td><a href='viewgallery.php?cid=1&pid=247'><img src='photos/tb_247.jpg' border='0' alt='' class='img'/></a></td> <td><a href='viewgallery.php?cid=1&pid=248'><img src='photos/tb_248.jpg' border='0' alt='' class='img'/></a></td> </tr> <tr> <td><a href='viewgallery.php?cid=1&pid=249'><img src='photos/tb_249.jpg' border='0' alt='' class='img'/></a></td> <td><a href='viewgallery.php?cid=1&pid=250'><img src='photos/tb_250.jpg' border='0' alt='' class='img'/></a></td> <td><a href='viewgallery.php?cid=1&pid=251'><img src='photos/tb_251.jpg' border='0' alt='' class='img'/></a></td> <td><a href='viewgallery.php?cid=1&pid=252'><img src='photos/tb_252.jpg' border='0' alt='' class='img'/></a></td> </tr> <tr> <td><a href='viewgallery.php?cid=1&pid=253'><img src='photos/tb_253.jpg' border='0' alt='' class='img'/></a></td> <td><a href='viewgallery.php?cid=1&pid=254'><img src='photos/tb_254.jpg' border='0' alt='' class='img'/></a></td> <td><a href='viewgallery.php?cid=1&pid=255'><img src='photos/tb_255.jpg' border='0' alt='' class='img'/></a></td> </table> </body> This is more than a question than anything else: I am looking for a tutorial or something that will allow me to make tables with php and mysql for example what I need is: mysql data: table = links lid = 1 lname = Page 1 linkid = page.php lid = 2 lname = Page 2 linkid = page2.php etc and i am try to get it so if there is 2 pages then the table would do Page 1 Page 2 if 3 Page 1 Page 2 Page 3 so there are 2 lname(s)s per row and 1 in each column and it would keep building the table and rows as more lname(s) are added. Does anybody know where to find a tutorial on doing something like this. Thanks in advance I want to read records from the database and print out in this table and I need help with the code. Code: [Select] <?php mysql_connect(localhost,root,""); mysql_select_db(oodb) or die( "Unable to select database"); $query=" SELECT * FROM oocust"; $result=mysql_query($query); $num=mysql_numrows($result); ?> <HTML><HEAD> <script type="text/javascript"> var monthNames = [ "January","February","March","April","May","June","July", "August","September","October","November","December" ]; var today = new Date(); var mmyy = monthNames[today.getMonth()] + " / " + today.getFullYear(); </script> </HEAD><BODY bgcolor="#CCCC99" background="oldorchard.jpg"><b><center> <font size=+2><b> Old Orchard Invoice </font>Date: <script type="text/javascript">document.write(mmyy);</script></center> echo "<TABLE BORDER="0" CELLPADDING="5" CELLSPACING="5" background="oldorchard.jpg"> <TD> <TABLE BORDER="0" CELLPADDING="10" CELLSPACING="10" background="oldorchard.jpg"> <TD> <TABLE BORDER="0" CELLPADDING="1" CELLSPACING="1" background="oldorchard.jpg"> <TD> <input type=text size=25 value="Old Orchard Plumbing"><br> <input type=text size=25 value="2210 E. Hogan Hollow Road"><br> <input type=text size=25 value="Margate, Fl 33063"><br></TD> <TR> <td> <input type=text size=3 value="Bill To:"><br> <input type=text size=25 value="$bname"><br> <input type=text size=25 value="$bstreet:">><br> <input type=text size=25 value="$bcity"><br> <input type=text size=25 value="$contact"><br></TD> <tr> <td> <input type=text size=5 value="Ship To:"><br> <input type=text size=25 value="$sname:"><br> <input type=text size=25 value="$street"><br> <input type=text size=25 value="$scity"></td> </TR> </TABLE> </TD> <TD> <input type=text size=25 value="Invoice No: $invnum"><br> <input type=text size=25 value="Date: $mm/dd/yyyy"><br> <input type=text size=25 value="Terms: $terms"><br> <input type=text size=25 value="Due Date: $duedate"><br> <input type=text size=25 value="Order No: $ordernum"><br> <input type=text size=25 value="Territory:"><br> <input type=text size=25 value="Salesperson:"><br> </TD> </TABLE> </TD> <TD align=center><img src="dave pic.jpg" width=250 height=350></td> </TABLE> echo "</tr>"; <hr> echo "</table>";mysql_close(); ?> </b></BODY></HTML> Hi I got three tables (employers , company , and Jobs) Employer table holds info about employer. Company hold info about the company and jobs table holds info about jobs. I was just wandering what would be a good way to link these tables in the database ? Here is the coding for each table. Employer Table Code: [Select] CREATE TABLE IF NOT EXISTS `employers` ( `id` int(11) NOT NULL, `username` varchar(50) NOT NULL, `password` varchar(50) NOT NULL, `email` varchar(50) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8; Jobs Table Code: [Select] CREATE TABLE IF NOT EXISTS `Jobs` ( `id` int(11) NOT NULL, `JobTitle` varchar(200) default NULL, `Company` varchar(200) default NULL, `Salary` varchar(30) default NULL, `Description` varchar(2000) default NULL, `CompanyURL` varchar(200) default NULL, `PhoneNumber` varchar(30) default NULL, `Requirements` varchar(2000) default NULL, `JobCategory` varchar(100) default NULL, `JobType` varchar(100) default NULL, `Apply_To` varchar(1000) NOT NULL, `Email` varchar(200) NOT NULL, `modified_at` datetime NOT NULL, `PostedOnDate` timestamp NOT NULL default CURRENT_TIMESTAMP on update CURRENT_TIMESTAMP, `Address` varchar(250) NOT NULL, `State` varchar(200) NOT NULL, `City` varchar(200) NOT NULL, `Country` varchar(100) NOT NULL, `Zipcode` varchar(100) NOT NULL, `JobID` varchar(100) NOT NULL, `WorkExperience` varchar(2000) NOT NULL, `EducationRequirement` varchar(2000) NOT NULL, `WebsitePostedFrom` varchar(200) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8; Company Table Code: [Select] CREATE TABLE IF NOT EXISTS `Company` ( `id` int(11) unsigned NOT NULL auto_increment, `CompanyName` varchar(100) NOT NULL, `Address` varchar(100) NOT NULL, `Logo` varchar(100) NOT NULL, `PhoneNumber` varchar(25) NOT NULL, `ContactPerson` varchar(25) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=2 ; this is the problem i have 2 tables table named ZAMJENE with fields id_event_1, id_event_2 table named EVENTS with fields id_event and event_date and i need echo $id_event_1 on date(EXTRACT FROM TABLE EVENTS FIELD event_date) can be replaced with $id_event_2 on date(EXTRACT FROM TABLE EVENTS FIELD event_date) structure must remains because i have half site build already and i have 3rd table where i just need use JOIN hope you understand problem Hello, I am very new to both php and sql. Hello all , I have a small issue in regards to allowing for my results to be placed horizontally across the page instead of vertically. I find the code i have posted works well when it comes to finding and displaying my information as requested (vertically) , but i am having trouble with finding a way to display the results horizontally. I know i need a way to identify each result?in order to echo it out in between <td> </td> , but i am still unsure , a point in the right direction would be good as i am struggling to find a way thankyou. $title = $runrows['title']; $desc = $runrows['description']; $url = $runrows['url']; $img = $runrows['image']; $id = $runrows['id']; echo " <table width='100px'> <h4><a href='http://$url'><b>$title</b></a><br /> $desc<br> <font color='00CC00'>$url</font></h4> <tr><img src='data:image/png;base64,$img' /> $id "; I hope this is not confusing. Lets say I want to join 2 tables. When I put it through a while loop, how do I write the code so that all id's in table2 are on the SAME line for each referring id in table 1, before dropping to the next line and going to the next record in table 1? I THINK that actually makes sense if you read it carefully :-) Hello, I'm trying to get a join with 2 tables but cannot get it to work. It's a contentsystem with an ID for the author. Another table tells the name of the author. Now I want to join these things. This is what i've coded so far: <? $query = "SELECT rmnl_content.content_aid, COUNT(rmnl_content.content_id), rmnl_crew.crew_id, rmnl_crew.crew_name FROM rmnl_content, rmnl_crew" "where rmnl_content.content_aid = rmnl_crew.crew_id"; $result = mysql_query($query) or die(mysql_error()); // Print out result while($row = mysql_fetch_array($result)){ echo " <b>". $row['COUNT(rmnl_content.content_id)'] ."</b> posted messages by ". $row ['crew_rmnl.crew_name'] ."</td> ."; echo "<br />"; } ?> I need to get the friends password and insert it into the table so the friend can delete it later can some one help me do a table join <?php //include the connect script include "../../../../connect.php"; //Post variables from flash $username = $_POST['username']; $password = $_POST['password']; $status = $_POST['status']; $friend = $_POST['friend']; $username = stripslashes($username); $password = stripslashes($password); $status = stripslashes($status); $friend = stripslashes($friend); $username = mysql_real_escape_string($username); $password = mysql_real_escape_string($password); $status = mysql_real_escape_string($status); $friend = mysql_real_escape_string($friend); $sql = mysql_query("SELECT * FROM user_declined_list WHERE username = '$username' and password = '$password' and friend = '$friend' and status ='$status'"); $rows = mysql_num_rows($sql); $your_username=$rows['username']; if($rows > 0) { echo "&msgTextFriendShipRejected= RESEND NEW FRIEND REQUEST SUCCESSFULLY!"; // ok they are now our friend but we are not thier friend so lets insert the friendship in reverse and set the status to 1 on both ends // Problem i see is this if the user wishs to remove the friend later he will neen his password set to delete from this table. // so i need to do a join table again where friend password gets inserted here.. $insertnewfriend = mysql_query("INSERT INTO user_friends_list (username,password,friend,status) VALUES ('$friend','$password','$username','0')") or die(mysql_error()); //ok lets update the request and set the friend to be a friend becuase we said yes be my friend. $deleteuserfriend = mysql_query("DELETE FROM user_declined_list WHERE username = '$username' and password = '$password' and friend = '$friend' and status ='0'"); return; } ?> |
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