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PHP - Change Background And Other Images Depending On What Radio Button Is Checked
I have to radio buttons at the login page. Both of them are in group1. The value of the first is 'fancy', the value of the second is 'fast'.
Also note that the buttons are on the login page, and i want to change the bg on the main page. Similar Tutorials<?php
require_once('upper.php'); require_once('LoginStatement.php'); require_once('database.php'); echo $error_msg=''; require_once('database.php'); $LoginId=$_COOKIE['LoginIdCookie']; $query="select * from registration where LoginId='$LoginId'"; $result=mysqli_query($dbc,$query); $row=mysqli_fetch_array($result); if(isset($_POST['submit'])) { $LoginId=mysqli_real_escape_string($dbc,trim($_POST['LoginId'])); $Name=mysqli_real_escape_string($dbc,trim($_POST['Name'])); $Age=mysqli_real_escape_string($dbc,trim($_POST['Age'])); $BloodGroup=mysqli_real_escape_string($dbc,trim($_POST['BloodGroup'])); if(!isset($_POST['Sex'])) { echo 'Please enter Sex<br>'; } else{ $Sex= mysqli_real_escape_string($dbc,trim($_POST['Sex'])); } $Qualification=mysqli_real_escape_string($dbc,trim($_POST['Qualification'])); $ContactNumber=mysqli_real_escape_string($dbc,trim($_POST['ContactNumber'])); $Email=mysqli_real_escape_string($dbc,trim($_POST['Email'])); $Address=mysqli_real_escape_string($dbc,trim($_POST['Address'])); $AboutYourself=mysqli_real_escape_string($dbc,trim($_POST['AboutYourself'])); //$countCheck=count($_POST['checkbox']); //echo $countCheck; //$checkbox=$_POST['checkbox']; //$countCheck=count($checkbox); if(empty($LoginId)){echo 'Please enter Login Id';} elseif(empty($Name)){echo 'Please enter Name';} elseif(empty($Age)){echo 'Please enter Age';} elseif(!isset($_POST['Sex'])){} elseif(empty($Qualification)){echo 'Please enter Qualification';} elseif(empty($ContactNumber)){echo 'Please enter Contact Number';} elseif(empty($Email)){echo 'Please enter Email';} elseif(empty($Address)){echo 'Please enter Address';} elseif(empty($AboutYourself)){echo 'Please enter About Yourself';} else { if(mysqli_num_rows($result)==0) { $checkbox=$_POST['checkbox']; $countCheck=count($_POST['checkbox']); $reg_id=' '; for($i=0;$i<$countCheck;$i++) { $reg_id=$reg_id.$checkbox[$i].','; } $query="UPDATE registration SET (LoginId,Name,Age,BloodGroup,Sex,Qualification,ContactNumber,Email,Address,AboutYourself,Activity)values ('$LoginId',SHA('$Password1'),'$Name','$Age','$BloodGroup','$Sex','$Qualification','$ContactNumber','$Email','$Address','$AboutYourself',',$reg_id')"; $result=mysqli_query($dbc,$query) or die("Not Connect"); echo ' Dear '.$Name.'.<br>Your request has been mailed to admin.<br>Your account is waiting for approval<br>'; $from= 'Elite Brigade'; $to='ankitp@rsquareonline.com'; $subject='New User Registration'; $message="Dear admin,\n\nA new user request for registration. Please check it out.\n\nRegards\nMicro"; mail($to,$subject,$message,'From:'.$from); //header('Location: index.php'); // header('Location: Registration.php'); } else { echo 'Dear '.$Name. ', <br> An account already exist with login-id<b> '.$LoginId.'</b> <br>Please try another login-id'; }} } ?> <html> <head> <script src="jquery-latest.js"></script> <script type="text/javascript" src="jquery-validate.js"></script> <style type="text/css"> * { font-family: Verdana; } label.error { color: white; padding-left: .5em; } p { clear: both; } .submit { margin-left: 12em; } em { font-weight: bold; padding-right: 1em; vertical-align: top; } </style> <script> $(document).ready(function(){ $("#commentForm").validate(); }); </script> </head> <body> <?php echo $error_msg; ?> <form action='<?php echo $_SERVER['PHP_SELF'];?>' id="commentForm" method='post'> <div class="registration_and_activity"> <table border="0" width="380"> <tr><td colspan="2"> <h3>Update Personal Details</h3></td></tr> <tr><td width="120"> <em>*</em>Enter Login id</td><td width="150"><input type='text' name='LoginId' minlength='4' value='<?php echo $row['LoginId']; ?>' /></td></tr> <tr><td width="120"> <em>*</em>Enter Name</td> <td><input type='text' name='Name' value='<?php echo $row['Name'];?>' /></td></tr> <tr><td> <em>*</em>Enter Age</td><HEAD> <SCRIPT language=Javascript> function isNumberKey(evt) { var charCode = (evt.which) ? evt.which : event.keyCode if (charCode > 31 && (charCode < 48 || charCode > 57)) return false; return true; } </SCRIPT> </HEAD> <td><INPUT onkeypress='return isNumberKey(event)' type='text' name='Age' value='<?php echo $row['Age'];?>'/></td></tr> <tr><td> <em>*</em>Enter Blood</td><td><input type='text' name='BloodGroup' value='<?php echo $row['BloodGroup'];?>' /></td></tr> [B]<tr><td> <em>*</em>Enter Sex</td><td><input type='radio' name='Sex' style='width:16px; border:0;' value='Male' checked='<?php if($row['Sex']='Male') echo 'checked';?>'/>Male <input type='radio' name='Sex' checked='<?php if($row['Sex']='Female') echo 'checked';?>' style='width:16px; border:0;' 'value='Female' />Female</td></tr>[/B] <tr><td> <em>*</em>Enter Qualification</td><td><input type='text' name='Qualification' value='<?php echo $row['Qualification'];?>' /></td></tr> <tr><td> <em>*</em>Contact Number </td><td><input onkeypress='return isNumberKey(event)'type='text' name='ContactNumber' value='<?php echo $row['ContactNumber'];?>' /></td></tr> <tr><td> <em>*</em>Enter Email</td><td><input type='text' name='Email'class="email" value='<?php echo $row['Email'];?>' /></td></tr> <tr><td> <em>*</em>Enter Address</td><td><input type='text' name='Address' value='<?php echo $row['Address'];?>' /></td></tr> <tr ><td > <em>*</em>About Yourself </td></tr> <tr><td colspan="2"><textarea rows='10' cols='40' name='AboutYourself' /><?php echo $row['AboutYourself'];?></textarea></td></tr> <tr><td> <?php echo "<tr><td colspan='2' align='center'><input type='submit' value='Update' name='submit' style='background:url(./images/button_img2.png) no-repeat 10px 0px; width:100px; padding:3px 0 10px 0; color:#FEFBC4; border:0;'/></td></tr><br>"; echo " </td></tr></table> </div> </form> </body> </html>"; require_once('lower.php'); ?> Hi friends.......... In above code I want that In database if Sex=Male then Male radio button will be checked automatically and if Sex =Female then Female radio button will be checked. But it not works ........... please help me........... thanks in advance.......... <?php $goal = rand(1, 3); ?> <td><div align="left"> Goal</div></td> <td><label> <div align="center"> <input type="radio" name="goal_chk" id="radio2" value="1" <?php if($goal == "1") { echo "checked"; }?> /> </div> </label></td> <td><label> <div align="center"> <input name="goal_chk" type="radio" id="radio13" value="2" <?php if($goal == "2") { echo "checked"; }?> /> </div> </label></td> <td><label> <div align="center"> <input type="radio" name="goal_chk" id="radio23" value="3" <?php if($goal == "3") { echo "checked"; }?> /> </div> </label></td> </tr> i have a group of radio buttons whose value is checked randomly everytime you refresh the page, now that works fine, everytime you refresh the page the checked values moves randomly but the problem i have is getting the actual of a checked radio button. i have tried this... $goal_checked = $_POST['goal_chk']; echo $goal_checked; But nothing happens. Any ideas on how to make this possible. Thanks a lot you guys. Hi people,
I'm new to PHP, and I'm having some real difficulties with trying to re-populate a radio button selection on a form.
Basically, I'm working on a WordPress plugin which uses custom fields to create a Bet custom post type.
I need to have my form submit the user input, then re-populate it so that if the user wants to edit and update the Bet data, they don't have to fill in the whole form details again, they can just edit what they need to, and update (re-submit) the form.
I've managed to get all of the form elements re-populating, apart from a radio button. I've been trawling round the internet for most of yesterday evening and this morning, trying different things, but nothing I've found works for me.
I'd really appreciate some help if anyone knows how to do this.
Here's my code so far (non working)
<?php I need a button in php to change my background color every 5 presses with a random one, every five presses the color have to change once and need to stay for the next 5 presses. here is my code <head>
<title>click 5 times</title> I am trying to allow the user to update a variable he chooses by radio buttons, which they will then input text into a box, and submit, to change some attributes. I really need some help here. It works just fine until I add the second layer of variables on top of it, and I can't find the answer to this question anywhere. <?PHP require('connect.php'); ?> <form action ='' method='post'> <select name="id"> <?php $extract = mysql_query("SELECT * FROM cars"); while($row=mysql_fetch_assoc($extract)){ $id = $row['id']; $make= $row['make']; $model= $row['model']; $year= $row['year']; $color= $row['color']; echo "<option value=$id>$color $year $make $model</option> ";}?> </select> Which attribute would you like to change?<br /> <input type="radio" name="getchanged" value="make"/>Make<br /> <input type="radio" name="getchanged" value="model"/>Model<br /> <input type="radio" name="getchanged" value="year" />Year<br /> <input type="radio" name="getchanged" value="color" />Color<br /><br /> <br /><input type='text' value='' name='tochange'> <input type='submit' value='Change' name='submit'> </form> //This is where I need help... <?PHP if(isset($_POST['submit'])&&($_POST['tochange'])){ mysql_query(" UPDATE cars SET '$_POST[getchanged]'='$_POST[tochange]' where id = '$_POST[id]' ");}?> Hi. Im pretty sure this is easy but ive been trying for hours and looked all over the web but cant seem to do it. I have information submitted to my database which I then retrieve on another page. I retrieve the landlord name and group the same values together plus retrieve an overall rating which I average and sort by. This works and is done using: Code: [Select] $sql="SELECT landlord_name, AVG(overall) FROM $tbl_name GROUP BY landlord_name ORDER BY AVG(overall) DESC"; $result=mysql_query($sql); // Start looping rows in mysql database. while($rows=mysql_fetch_array($result)){ Where Im finding it difficult though is I have 5 radio buttons with values from 1-5 and want one of them to be checked if the value matches the averaged overall rating. What I've tried is: Code: [Select] if (AVG(overall)==1){ $check1="checked";} if (AVG(overall)==2){ $check2="checked";} if (AVG(overall)==3){ $check3="checked";} if (AVG(overall)==4){ $check4="checked";} if (AVG(overall)==5){ $check5="checked";} then in the form: Code: [Select] <table width="600" border="1" cellspacing="0" cellpadding="3"> <tr> <td><? echo $rows['landlord_name']; ?></td> <td><div class="avg"><form> <input type="radio" value="1" disabled="disabled" checked= "<? $check1 ?>" /> <input type="radio" value="2" disabled="disabled" checked= "<? $check2 ?>" /> <input type="radio" value="3" disabled="disabled" checked= "<? $check3 ?>" /> <input type="radio" value="4" disabled="disabled" checked= "<? $check4 ?>" /> <input type="radio" value="5" disabled="disabled" checked= "<? $check5 ?>"/> </form></div> </td> </tr> </table> To make it a bit more difficult, the AVG(overall) value will not always be an integer from 1-5 and will need to be rounded to the closest one. Think i can use ROUND for this but dont know how to put it in. Thanks for your help in advance. As you can probably tell im new to php and still learning the basics. I am echoing out 2 radio input fields in a foreach statement. I would like to have the first option checked in all the radio input fields that gets echoed out.
But for some reason it marks the radio input field "checked" all the way in the bottom. (The last one)
How can I make it so that every input field that gets echoed out will be marked checked?
Below is my code. Thank you for your help
foreach ($menu_cat_options as $menu_cat_option){
<input type="radio" checked="checked" name="display_type" value="radio" >Radio
<br>
<input type="radio" name="display_type" value="checkbox">Check Box
}
I am new to PHP and learning as I go I am stuck with a piece of code that I am trying to change. I have a php application that has tickboxes in and some are checked as standard. I want to change the tick box setting to be unchecked as standard. Here is the code. <label><input type="checkbox" name="notify" value="1" <?php echo (!isset($_SESSION['as_notify']) || !empty($_SESSION['as_notify'])) ? 'checked="checked"' : ''; ?> /> <?php echo $hesklang['seno']; ?></label><br /> I have tried everything I know but since I do not know that much I have been unable to change the standard. I am sure it is something small that I am overlooking. Anyone out there know what I am doing wrong? how can i set the color of a table background depending on what a variable is in my database? I currently have a table which echos data from my database, but i want the background too be a color depending on the value of a variable called 'status' (there are 3 variations) the variations are; order placed, processing and complete so for example: Code: [Select] if (status == placed) { background would be red } Code: [Select] if (status == processing) { background would be orange } Code: [Select] if (status == complete) { background would be green } appreciate any help. thank you. Hi All, I am trying to develop an application that show's where PC's are located in an office. Basically, what I want to be able to do, is to overlay avatar-like images over a main floorplan layout, and place them in a position, depending on thier x/y co-ordinates, which would be retreived from a database. Is this possible using PHP at all? Thanks in advance Matt i have an html form which is a "post" on it i have an array of checkboxes and a sumbit button, once button is clicked i go to another page where i handle those boxes checked the problem now is if NO checkboxes are checked and i hit the submit...i get errors on the other page my code: foreach($product_names as $product_row) { ?> <tr> <td > </td><td width='200px'><?php echo $product_row->getName(); ?></td> <td width='200px'><input type="checkbox" name="graphic[]" value="<?php echo $product_row->getId();?>" /></td> <td width='200px'><input type="checkbox" name="text[]" value="<?php echo $product_row->getId();?>" /></td> </tr> <?php } ?> </table> <table> <tr> <td> <input type='submit' name='submit' value='Submit'> <?php if ( (isset($graphic)) || (isset($text) )) { echo "checkboxes checked"; //show submit button } else { //hide submit botton and echo "no boxes check"; } ?> the above is NOT working please help???? I have a site that I have an about page with pictures of people on it. I would like to create something that would do the following: * When you click on one of the images, i need text for that image to load in a text area. I would like to do this rather than have to make a different HTML page for each person, but I am not sure how to go about doing it. I do not have a database for this site, so I will need to pull the text from a text file or something like that. Any ideas on how to get started would be helpful. Thanks in advance! As I title says; I need to have an image showed the number of times, the value of a table/field.. How can I do this? I am trying to have the text alongside the radio button trigger the radio button (cannot use < a href ) e.g. () Trigger with this text The closest I have found is <label for="r1"><input type="radio" name="group1" id="r1" value="1" /> button one</label> But it does not seem to work? Any help greatly appreciated I have a function to display some images and allow a user to select a choice via a radio button.The value is then passed to another function. I have 2 problems My selection is not being passed back and I cant assign the value to a query sring in a link to another page. On the form do i need to add checked? Any help appreciated. Code: [Select] function cover() { echo'<h2>Please upload your book cover or choose one from the selection</h2> <p>All book ideas require a cover. Your choice can be changed at a later date.</p>'; //process selection of cover if (isset($_POST['submit'])) { $coverID=$_POST['cover']; echo $coverID; ?>   <ul><li class="demo-menu-link"><a href="?page=submenu7&coverID=$coverID">Finnished Cover</a></li></ul><?php exit(); } else{ echo "not Submitted"; } global $wpdb; $query = "select * from wp_cover"; $result = mysql_query($query) or trigger_error("Query: $query\n<br />MySQL Error: " . mysql_error()); echo mysql_error(); if (!$result){ return false; } echo'<div class="wrap"><p>choose from one of the covers below</p></div>'; ?><form action="<?php $_SERVER['PHP_SELF'] ?>" method="POST" id="cover" enctype="multipart/form-data"> <table><tr><?php /* display picture and radio button */ while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) { $coverID=$row['coverID']; echo"<img src=\"/wordpress_3/wp-content/plugins/Authors2/jackets/{$row['pix']}\" />"; echo"<td>"; echo $coverID; echo "<Input type = 'Radio' Name ='cover' value= '$coverID'/>"; ?> </tr></table> <input type=submit value=submit> </form><?php } } What am I doing wrong with this selected radio button? <form action="Process/privacy.php" method="post" enctype="multipart/form-data" id="privacy"> <div id="privacy_vis">Your profile is visible to:</div> <div id="privacy_select"> <label> <input name="RadioGroup1" type="radio" id="RadioGroup1_0" value="1" <?if($visible=="1")echo 'checked="checked"';?> /> Everyone</label> <label> <input name="RadioGroup1" type="radio" id="RadioGroup1_1" value="0"/> Members Only</label> </div> <br /> <div id="privacy_vis">Your Password to view your private pictures is:</div> <div> <input name="pictures_pw" type="text" id="pictures_pw" value="<? echo "$xxx_pw" ?>" size="50" maxlength="20" /> </div> <br /> <div> <input name="submit" type="submit" class="button" id="submit" value="Save Changes" /> </div> </form> </div> Hello, I had 3 radio buttons with the same name, well, I had created 3 text box that are next to those 3 radio buttons. When I click save to the form, I need to know which radio button had been pressed, so that I can detect & retrieve its value. Any help? Thanks This topic has been moved to HTML Help. http://www.phpfreaks.com/forums/index.php?topic=317717.0 I have a group of 4 radio buttons. my mysql database knows which one the user selected previously when they stored some information. I now wish to display the same buttons but have radio button checked that the user chose before. I know this can be done but having one of those mind melt moments where I cannot think of the solution so I have 4 buttons that look like this Code: [Select] <input type="radio" name="clarity" id="clarity" value="Opaque"> Opaque<br> <input type="radio" name="clarity" id="clarity" value="Deep"> Deep<br> <input type="radio" name="clarity" id="clarity" value="Mid"> Mid<br> <input type="radio" name="clarity" id="clarity" value="Pale"> Pale<br></td> I just need to attached a checked field to the correct item Hi, I have 2 radio button's within a table and need to pass this array. All other rows within my table can be sent as array's and captured using $_POST['field_name'][$ROW 1 value etc]. However for radio buttons this doesn't work. As an example, a standard textbox I can send an array using the following: echo "<td width='33%'><input type='Textbox' width='100%' id='test' name='test[]' value='" .$row['test']. "'></td>"; I can then capture it using: $test = $_POST['test'][$iLine]; This works, no problem, however for radio buttons, I can't use a static array name, as presumably it dumps all rows into the array, if I do this, only the last row has a checked button, hence I need to use the following (where $checked includes the logic to decide whether the button should be checked or not, this works correctly): echo "<input type='radio' name='".$row['venue_id']."[]' value='1'".$checked."/>P1" echo "<input type='radio' name='".$row['venue_id']."[]' value='0'".$checked2." />P2"; I tried using the following: var_dump($_POST[$row]['game_id'][$iLine]); But this just returns a null value. Any ideas? |
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