PHP - Resizing Uploaded Images
Please, I need help with resizing uploaded images. Copied below is the code for image upload ( which I tagged "upload.php")
Code: [Select] <?php // define a constant for the maximum upload size define ('MAX_FILE_SIZE', 51200); if (array_key_exists('upload', $_POST)) { // define constant for upload folder define('UPLOAD_DIR', 'C:/upload_test/'); // convert the maximum size to KB $max = number_format(MAX_FILE_SIZE/1024, 1).'KB'; // create an array of permitted MIME types $permitted = array('image/gif', 'image/jpeg', 'image/pjpeg', 'image/png'); foreach ($_FILES['image']['name'] as $number => $file) { // replace any spaces in the filename with underscores $file = str_replace(' ', '_', $file); // begin by assuming the file is unacceptable $sizeOK = false; $typeOK = false; // check that file is within the permitted size if ($_FILES['image']['size'][$number] > 0 || $_FILES['image']['size'][$number] <= MAX_FILE_SIZE) { $sizeOK = true; } // check that file is of an permitted MIME type foreach ($permitted as $type) { if ($type == $_FILES['image']['type'][$number]) { $typeOK = true; break; } } if ($sizeOK && $typeOK) { switch($_FILES['image']['error'][$number]) { case 0: // check if a file of the same name has been uploaded // if (!file_exists(UPLOAD_DIR.$file)) { // move the file to the upload folder and rename it $success = move_uploaded_file($_FILES['image']['tmp_name'][$number], UPLOAD_DIR.$file); // } /* else { // get the date and time ini_set('date.timezone', 'Europe/London'); $now = date('Y-m-d-His'); $success = move_uploaded_file($_FILES['image']['tmp_name'][$number], UPLOAD_DIR.$now.$file); }*/ if ($success) { $result[] = "$file uploaded successfully"; } else { $result[] = "Error uploading $file. Please try again."; } break; case 3: $result[] = "Error uploading $file. Please try again."; default: $result[] = "System error uploading $file. Contact webmaster."; } } elseif ($_FILES['image']['error'][$number] == 4) { $result[] = 'No file selected'; } else { $result[] = "$file cannot be uploaded. Maximum size: $max. Acceptable file types: gif, jpg, png."; } } } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <title>Multiple file upload</title> </head> <body> <?php // if the form has been submitted, display result if (isset($result)) { echo '<ol>'; foreach ($result as $item) { echo "<strong><li>$item</li></strong>"; } echo '</ol>'; } ?> <form action="" method="post" enctype="multipart/form-data" name="multiUpload" id="multiUpload"> <p> <label for="image1">File 1:</label> <input type="hidden" name="MAX_FILE_SIZE" value="<?php echo MAX_FILE_SIZE; ?>" /> <input type="file" name="image[]" id="image1" /> </p> <p> <label for="image2">File 2:</label> <input type="file" name="image[]" id="image2" /> </p> <p> <input name="upload" type="submit" id="upload" value="Upload files" /> </p> </form> </body> </html> This works fine , except that it only uploads to C:/upload_test instead of the images folder (../img/) Can you please help with the codes for creating thumbnails while retaining the original upload. Thanks Similar TutorialsHello I have uploaded images from a server onto a website, they run through a mysql database (database holds the image file names). The problem I am having is resizing the images. Can anyone help? Thank you in advance GWG I have this script where it uploads the file name to a database plus a few more things. Main Upload form. (img_add.php) <form enctype="multipart/form-data" action="img_add.php" method="POST"> Name: <input type="text" name="name"><br> E-mail: <input type="text" name = "email"><br> Phone: <input type="text" name = "phone"><br> Photo: <input type="file" name="photo"><br> <input type="submit" value="Add"> </form> Uploader. (img_add.php) <?php //This is the directory where images will be saved $target = "mainnewsimg/"; $target = $target . basename( $_FILES['photo']['name']); //This gets all the other information from the form $name=$_POST['name']; $email=$_POST['email']; $phone=$_POST['phone']; $pic=($_FILES['photo']['name']); // Connects to your Database mysql_connect("localhost", "root", "") or die(mysql_error()) ; mysql_select_db("chat") or die(mysql_error()) ; //Writes the information to the database mysql_query("INSERT INTO `images` VALUES ('$name', '$email', '$phone', '$pic')") ; //Writes the photo to the server if(move_uploaded_file($_FILES['photo']['tmp_name'], $target)) { //Tells you if its all ok echo "The file ". basename( $_FILES['photo']['name']). " has been uploaded, and your information has been added to the directory"; } else { //Gives and error if its not echo "Sorry, there was a problem uploading your file."; } ?> And the one that views it. (img_view.php) It uses a get function so do it with img_view.php?img=2 <?php mysql_connect("localhost", "root", "") or die(mysql_error()) ; mysql_select_db("chat") or die(mysql_error()) ; //Retrieves data from MySQL $newsid = $_GET['img']; $data = mysql_query("SELECT * FROM `images` WHERE id ='$newsid'") or die(mysql_error()); //Puts it into an array while($info = mysql_fetch_array( $data )) { //Outputs the image and other data Echo "<img src=mainnewsimg/".$info['photo'] ."> <br>"; } ?> And my database sql. CREATE TABLE IF NOT EXISTS `images` ( `name` varchar(30) DEFAULT NULL, `email` varchar(30) DEFAULT NULL, `phone` varchar(30) DEFAULT NULL, `photo` varchar(30) DEFAULT NULL, `id` int(11) NOT NULL AUTO_INCREMENT, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=3 ; -- -- Dumping data for table `images` -- INSERT INTO `images` (`name`, `email`, `phone`, `photo`, `id`) VALUES ('sdf', 'sdfdsdsf', 'dsffsfsdf', 'arrow_forward_last.gif', 1), ('sadd', 'sadd', 'adsadasdad', 'artbottomshadr.png', 2); The values inside I had to put in manually to test if it worked for the img_view.php Anyways, It doesnt want to upload the images at all, even tho it says it did and gives the message The file ". basename( $_FILES['photo']['name']). " has been uploaded, and your information has been added to the directory I would greatly appreciate some help, I also provided everything so you can try it on your own server too. Hi everyone!! I have looked into how the upload script works and this is what i have: Code: [Select] <?php if ((($_FILES["file"]["type"] == "image/gif") || ($_FILES["file"]["type"] == "image/jpeg") || ($_FILES["file"]["type"] == "image/pjpeg")) && ($_FILES["file"]["size"] < 20000)) { if ($_FILES["file"]["error"] > 0) { echo "Return Code: " . $_FILES["file"]["error"] . "<br />"; } else { echo "Upload: " . $_FILES["file"]["name"] . "<br />"; echo "Type: " . $_FILES["file"]["type"] . "<br />"; echo "Size: " . ($_FILES["file"]["size"] / 1024) . " Kb<br />"; echo "Temp file: " . $_FILES["file"]["tmp_name"] . "<br />"; if (file_exists("upload/" . $_FILES["file"]["name"])) { echo $_FILES["file"]["name"] . " already exists. "; } else { move_uploaded_file($_FILES["file"]["tmp_name"], "upload/" . $_FILES["file"]["name"]); echo "Stored in: " . "upload/" . $_FILES["file"]["name"]; } } } else { echo "Invalid file"; } ?> Which is un-tested at the moment, but let's just say for talking sake it worked 100% what elements of this script would i be looking at to display the files uploaded on to another page, in my case my homepage? ive found as to yet, that the uploads have to be stored on a file somewhere on my server, which i've set up. But i thought it would be just as easy to have a field in my table named upload and display it within the table next to the other results? instead i just get whatever the file name is named.jpg. Any help in looking towards the answer? many thanks in advance guys! Hi Everyone, I've been studying the topics at this site and others on ways to count uploaded images; and what I've tried hasn't worked. I have seen this question posed and answered many times and most of the answers are something akin to this: Code: [Select] $count = count($_FILES['userfile'] ['name']); echo "the number of photos is ".$count; The explanation usually states that "count($_FILES['userfile'])" will simply count the number of elements in the array and return 5. But including ['name'] will return the number of files (images) uploaded. I will allow up to five photos to be uploaded (less is OK too) and want to count them in order to iterate through the proper number of loops to filter and process the photos. I've tested both of the above and get 5 (elements) when I count the ['userfile']; but get 0 (zero) when I test "['userfile'] ['name']". Here's the html code: Code: [Select] <!-- html here to input form data --> <label></label><input type="hidden" name="MAX_FILE_SIZE" value="500000000" /><br /> <label for="userfile">Upload photo 1</label> <input type="file" name="userfile1" id="userfile1" /><br /> <label for="userfile">Upload photo 2</label> <input type="file" name="userfile2" id="userfile2" /><br /> <label for="userfile">Upload photo 3</label> <input type="file" name="userfile3" id="userfile3" /><br /> <label for="userfile">Upload photo 4</label> <input type="file" name="userfile4" id="userfile4" /><br /> <label for="userfile">Upload photo 5</label> <input type="file" name="userfile5" id="userfile5" /><br /><br /> <label></label><input type="submit" name="userfile" value="Send Ad" /> </form> I've been testing the uploads with two files (jpg) and have tried to come up with an alternative that can iterate through the file arrays and determine how many photos I have. The code I've been testing is as follows: Code: [Select] $num = 1; $count = 0; while ($num <=5) { foreach ($_FILES['userfile'.$num] as $upload){ if ($upload ['error'] != 4){ } $count ++; } $num++; } echo "the number of photos is ".$count; I'm using "['error'] !=4" because some times people won't have 5 photos to upload. The result I get is 25 or 5 (files) x 5 (elements) for a total of 25. Does anyone know the proper way of doing this? Thanks for you input! Cheers, Rick Hi everyone, I am after a scrpit/function that will get information of an uploaded image, resize it, then display the manipulated image. in my "upload" script, there will be a size limit and a file extension/type limit to: 600 x 200px / jpg, gif, jpeg... this is to keep the script i'm after more simple. As using vector images i'm told is such a complicated problem for me at this time. So... to get the size info/dimensions its like this: Code: [Select] <?php list($width, $height, $type, $attr) = getimagesize("image_name.jpg"); echo "Image width " .$width; echo "<BR>"; echo "Image height " .$height; echo "<BR>"; echo "Image type " .$type; echo "<BR>"; echo "Attribute " .$attr; ?> and..... resize something like this: Code: [Select] function get_image_sizes($sourceImageFilePath, $maxResizeWidth, $maxResizeHeight) { // Get width and height of original image $size = getimagesize($sourceImageFilePath); if($size === FALSE) return FALSE; // Error $origWidth = $size[0]; $origHeight = $size[1]; // Change dimensions to fit maximum width and height $resizedWidth = $origWidth; $resizedHeight = $origHeight; if($resizedWidth > $maxResizeWidth) { $aspectRatio = $maxResizeWidth / $resizedWidth; $resizedWidth = round($aspectRatio * $resizedWidth); $resizedHeight = round($aspectRatio * $resizedHeight); } if($resizedHeight > $maxResizeHeight) { $aspectRatio = $maxResizeHeight / $resizedHeight; $resizedWidth = round($aspectRatio * $resizedWidth); $resizedHeight = round($aspectRatio * $resizedHeight); } // Return an array with the original and resized dimensions return array($origWidth, $origHeight, $resizedWidth, $resizedHeight); } // Get dimensions $sizes = get_image_sizes($sourceImageFilePath, $maxResizeWidth, $maxResizeHeight); $origWidth = $sizes[0]; $origHeight = $sizes[1]; $resizedWidth = $sizes[2]; $resizedHeight = $sizes[3]; // Create the resized image $imageOutput = imagecreatetruecolor($resizedWidth, $resizedHeight); if($imageOutput === FALSE) return FALSE; // Error condition // Load the source image $imageSource = imagecreatefromjpeg($sourceImageFilePath); if($imageSource === FALSE) return FALSE; // Error condition $result = imagecopyresampled($imageOutput, $imageSource, 0, 0, 0, 0, $resizedWidth, $resizedHeight, $origWidth, $origHeight); if($result === FALSE) return false; // Error condition // Write out the JPEG file with the highest quality value $result = imagejpeg($imageOutput, $outputPath, 100); if($result === FALSE) return false; // Error condition And.... display is this: Code: [Select] <?php $database="***"; mysql_connect ("***", "***", "***"); @mysql_select_db($database) or die( "Unable to select database"); $result = mysql_query( "SELECT company_name, location, postcode, basicpackage_description, premiumuser_description, upload FROM Companies" ) or die("SELECT Error: ".mysql_error()); $num_rows = mysql_num_rows($result); print "\n\n\nThere are $num_rows records.<P>"; echo "<table><tr><th>Comppany Name</th><th>Location</th><th>Postcode</th><th>Basic Members</th><th>Upgraded Users</th><th>Company Logo</th></tr><tr><td></td><td></td><td></td><td></td><td></td><td></td></tr>";// store the records into $row array and loop through while ( $row = mysql_fetch_array( $result, MYSQL_ASSOC ) ) { // Print out the contents of the entry echo "<tr><td>{$row['company_name']}</td>"; echo "<td>{$row['location']}</td>"; echo "<td>{$row['postcode']}</td>"; echo "<td>{$row['basicpackage_description']}</td>"; echo "<td>{$row['premiumuser_description']}</td>"; echo "<td><img src=\"http://www.removalspace.com/images/COMPANIES{$row['upload']}\" alt=\"logo\" /></td></tr>";} echo "</table>"; ?> How will all these fit together in one script? any help i'd love it! many thanks in advance Hi all, Could someone help me add a thumbnail script to the below that works on scaling it down to 200px x 133px. I guess it is not that hard. <?php $destination='aircraft/'.$reg."1.jpg"; $temp_file = $_FILES['image']['tmp_name']; move_uploaded_file($temp_file,$destination); ?> Thanks Upload images - Thumbnail sizes? Hi all I haven't used php for a while now and I'm really stuck on some code I wrote and now I can't work how to change it. I have this function to upload images and create thumbnails. The thumbnails can be either landscape or portrait and I want them to have the same height. At the moment the portrait thumbnails height is equal to the landscape thumbnail width. The dimensions of the thumbnails are the same but the portrait images are portrait. How can I size the thumbnails so they all have the same height. Thanks in advance for any help or advice on this. Code: [Select] function upload_images(){ $photo_types = array('image/pjpeg'=>'.jpeg','image/jpeg'=>'.jpg','image/gif'=>'.gif','image/.bmp'=>'bmp','image/x-png'=>'.png'); //$number_of_uploads = 5; $image_Dir = "images_1/"; $image_thumb_Dir = $image_Dir . "thumbs/"; $photo_id_arr = array(); $photo_ext_arr = array(); $photo_id_ext_arr = array(); // if(isset($_FILES['images'])){ $image_uploaded = $_FILES['images']; for($i=0; $i<=count($_FILES['images']['name']);$i++){ if(!empty($image_uploaded['name'][$i])){ if(array_key_exists($image_uploaded['type'][$i], $photo_types)){ $file_temp = mysql_prep($image_uploaded['name'][$i]); // $query = "INSERT INTO photos (filename) VALUES ('{$file_temp}')"; $result = mysql_query($query); confirm_query($result); if($result){ $photo_id = mysql_insert_id(); array_push($photo_id_arr, $photo_id); } // $filetype = $image_uploaded['type'][$i]; $ext = $photo_types[$filetype]; array_push($photo_ext_arr, $ext); $dbfile_name = $photo_id . $ext; // $query = "UPDATE photos SET filename = '{$dbfile_name}' WHERE photo_id = '{$photo_id}'"; $result = mysql_query($query); confirm_query($result); // // $stored_image = $image_Dir . $dbfile_name; $stored_thumb = $image_thumb_Dir . $dbfile_name; move_uploaded_file($image_uploaded['tmp_name'][$i], $stored_image ); // $src_image = imagecreatefromjpeg($stored_image); // $src_width = imagesx($src_image); $src_height = imagesy($src_image); $new_width = 900; $new_height = 900; // if($src_width > $src_height){ $img_w = $new_width; $img_h = $src_height*($new_height/$src_width); } if($src_width < $src_height){ $img_w = $src_width*($new_width/$src_height); $img_h = $new_height; } if($src_width == $src_height){ $img_w = $new_width; $img_h = $new_height; } // $mainImg = imagecreatetruecolor($img_w, $img_h); imagecopyresampled($mainImg, $src_image,0,0,0,0,$img_w, $img_h, $src_width, $src_height); imagejpeg($mainImg, $stored_image, 100); imagedestroy($src_image); imagedestroy($mainImg); //*************************** // // // //*************************** $src_image = imagecreatefromjpeg($stored_image); // $src_width = imagesx($src_image); $src_height = imagesy($src_image); $new_width = 85; $new_height = 85; // if($src_width > $src_height){ $thumb_w = $new_width; $thumb_h = $src_height*($new_height/$src_width); } if($src_width < $src_height){ $thumb_w = $src_width*($new_width/$src_height); $thumb_h = $new_height; } if($src_width == $src_height){ $thumb_w = $new_width; $thumb_h = $new_height; } // $thumb = imagecreatetruecolor($thumb_w, $thumb_h); imagecopyresampled($thumb, $src_image,0,0,0,0,$thumb_w, $thumb_h, $src_width, $src_height); imagejpeg($thumb, $stored_thumb, 100); imagedestroy($src_image); imagedestroy($thumb); }else{ //echo "File format not supported."; } } } array_push($photo_id_ext_arr, $photo_id_arr); array_push($photo_id_ext_arr, $photo_ext_arr); return $photo_id_ext_arr; } } Right now users log in and upload an image to the website. I want every image that is uploaded to be watermarked with a particular logo. Is this possible? Any hints or tips will be appreciated. Thank you. Is it better to store uploaded images as 'content' in the database? (like he http://www.techsupportforum.com/forums/f49/tutorial-upload-files-to-database-176804.html).. Or just as a regular file which is referenced in the database..? Hi, this is what I want to get working: each time I add an entry, it is displayed in a nice html table, and each entry listed in this html table has an UPDATE link that allows the user to update the Price and Description field of the corresponding table in my database. I have also included an upload element which whenever a user chooses an image, it will replace the default fileUploadIcon.jpg with this. Please see the index.php and bellUpdateForm.php below respectively Code: [Select] //index.php <table border="border"> <?php require 'bellConnect.inc.php'; $curImage; $imgIndx=-1;//iniitally $result=mysql_query("SELECT ID, Name, Manufacturer, Price, Description, SimSupport FROM bellProducts"); $indx=0;//***HOW DO I MAKE THIS SHARED SO THAT EACH ENTRY ADDED HAS AN INCREMENTED index appended to end of its name attribute //phpinfo(); //print "Val of \$counter so far: ".$counter; //NB: print table headings if(mysql_num_rows($result))//if there is at least one entry in bellProducts, make a table { //$counter+=1; print "<table border='border'>"; print "<tr> <th>ID</th> <th>Image</th> <th>Name</th> <th>Manufacturer</th> <th>Price</th> <th>Description</th> <th>SimSupport</th> <th colspan=2 align='center'>Modify</th> </tr>"; //NB: now output each row of records while($row=mysql_fetch_assoc($result)) { //extract($row); //if($indx<sizeof($bellProductsArray)) //{ "<tr align='center'> <td>$row[ID]</td> <td>"; if($_POST['upload']) print "<img src=".$_FILES['image']['name'].">"; else print "<img src='fileUploadIcon.jpg' name='image' /> </td> <td> $row[Name] </td> <td> $row[Manufacturer] </td> <td> $$row[Price]</td> <td align='left'>$row[Description]</td> <td>$row[SimSupport]</td> <td><a href='bellUpdateForm.php?ID=$row[ID]'>UPDATE</a></td> <td><a href='bellDeleteForm.php?ID=$row[ID]' name='delete'>DELETE</a></td> </tr>"; //}//END INNER IF $indx++; }//END WHILE }//END BIG IF ?> </table> </body> </html> Code: [Select] //bellUpdateForm.php <?php require 'bellConnect.inc.php'; if($_GET && !$_POST)//this is to make sure that the current entry is selected BUT the updated info NOT submitted yet { if(isset($_GET['ID'])) { $ID=$_GET['ID']; $result=mysql_query("SELECT * FROM bellProducts WHERE ID=$ID"); $row=mysql_fetch_assoc($result); //store the one entry that will be updated print "You are currently updating item: <strong>$row[Manufacturer] $row[Name] </strong> <br /><br />"; "<form action='bellUpdate.php' method='post'> <label> Price:<input type='text' value='$row[Price]' name='price' id='price'></input> </label> <label> Description: <textarea cols='60' rows='3' name='description' id='description'> $row[Description] </textarea> </label> <div> <input type='submit' value='Update entry' name='update' id='update' /> <input type='hidden' value=$row[ID] name='id' /> </div> <input type='reset' value='Reset entry' />"; print "</form>"; }//END INNER IF }//END BIG IF ?> <form method='post' action='index.php' enctype='multipart/form-data' name='uploadImage' id='uploadImage'> <p> <label>Upload image</label> <input type='file' name='image' id='image' /> </p> <p> <input type='submit' value='Upload this' name='upload' id='upload' /> </p> </form> <?php if(array_key_exists('upload', $_POST)) { // define constant for upload folder define('UPLOAD_DIR', 'C:\wamp\www'); // move the file to the upload folder and rename it move_uploaded_file($_FILES['image']['tmp_name'], ! UPLOAD_DIR.$_FILES['image']['name']); } ?> </body> </html> Hi, I have a pretty simple application that allows my users to upload images and i'm able to succesfull upload images to a new dir to be outputted. But as to save on download time and server space is there a simple piece of code I can add to the below code that will resize every image on uploded to 460(w) x 300 (h) from my users Code: [Select] <?php if ((($_FILES["article_image"]["type"] == "image/gif") || ($_FILES["article_image"]["type"] == "image/jpeg") || ($_FILES["article_image"]["type"] == "image/pjpeg")) && ($_FILES["article_image"]["size"] < 5000000)) { move_uploaded_file($_FILES["article_image"]["tmp_name"], "images/" . $_FILES["article_image"]["name"]); } ?> Thanks in advance for any help and suggestions I am absolutley stumped with this: im trying to have PHP get the size of an image that has been uploaded to mySQL, and return it to a certain size, lets say 200X200px. The problems im having to finding an existing script to help me understand - and then fit it into a table? All the help from google searches seem to suggest using software, but i would like to learn how to do this properly. First off the upload script: Code: [Select] <?php error_reporting(E_ALL); ini_set("display_errors", 1); echo '<pre>' . print_r($_FILES, true) . '</pre>'; //This is the directory where images will be saved $target = "/home/users/web/b109/ipg.removalspacecom/images/COMPANIES"; $target = $target . basename( $_FILES['upload']['name']); //This gets all the other information from the form $company_name=$_POST['company_name']; $basicpackage_description=$_POST['basicpackage_description']; $location=$_POST['location']; $postcode=$_POST['postcode']; $upload=($_FILES['upload']['name']); // Connects to your Database mysql_connect("server", "user", "password") or die(mysql_error()) ; mysql_select_db("removalspacelogin") or die(mysql_error()) ; //Writes the information to the database mysql_query("INSERT INTO `Companies` (company_name, basicpackage_description, location, postcode, upload) VALUES ('$company_name', '$basicpackage_description', '$location', '$postcode', '$upload')") ; echo mysql_error(); //Writes the photo to the server if(move_uploaded_file($_FILES['upload']['tmp_name'], $target)) { //Tells you if its all ok echo "The file ". basename( $_FILES['upload']['name']). " has been uploaded, and your information has been added to the directory"; } else { //Gives and error if its not echo "Sorry, there was a problem uploading your file."; } ?> this works great, it uploads the users pictures. This displays them out: Code: [Select] <?php $database="removalspacelogin"; mysql_connect ("server", "user", "password"); @mysql_select_db($database) or die( "Unable to select database"); $result = mysql_query( "SELECT company_name, location, postcode, basicpackage_description, premiumuser_description, upload FROM Companies" ) or die("SELECT Error: ".mysql_error()); $num_rows = mysql_num_rows($result); print "\n\n\nThere are $num_rows records.<P>"; echo "<table><tr><th>Comppany Name</th><th>Location</th><th>Postcode</th><th>Basic Members</th><th>Upgraded Users</th><th>Company Logo</th></tr><tr><td></td><td></td><td></td><td></td><td></td><td></td></tr>";// store the records into $row array and loop through while ( $row = mysql_fetch_array( $result, MYSQL_ASSOC ) ) { // Print out the contents of the entry echo "<tr><td>{$row['company_name']}</td>"; echo "<td>{$row['location']}</td>"; echo "<td>{$row['postcode']}</td>"; echo "<td>{$row['basicpackage_description']}</td>"; echo "<td>{$row['premiumuser_description']}</td>"; echo "<td><img src=\"http://www.removalspace.com/images/COMPANIES{$row['upload']}\" alt=\"logo\" /></td></tr>";} echo "</table>"; ?> Right now all the information in my table is fine except the image coloumn, the images are all the same size as they went in, i'd like them to all be one size so there in a uniformed fashion. But need all the rest of the mySQL table displayed, so how does it fit into my script to display the table? Many thanks!??? I am using Amazon's S3 service to allow users to upload images. Since you have to pay for this service, my plan was to resize all uploaded images (maybe to a max of 200 pixels wide or something) immediately before sending them to Amazon. I googled this and only thing I found said that "resizing on the fly is slow and expensive because disk space is cheaper than CPU." Is this accurate? Anyone have any thoughts on this? I feel like I have to restrict the size of images some way because I don't wan't people uploading huge 2000x2000 images. In case it matters, below is some code I have used below for resizing (albeit on my own server), so I imagine I'll use something similar for this new project which ultimately sends the image to Amazon. Code: [Select] // This is the temporary file created by PHP $uploadedfile = $_FILES['userfile']['tmp_name']; // Create an Image from it so we can do the resize $src = imagecreatefromjpeg($uploadedfile); // Capture the original size of the uploaded image list($width,$height) = getimagesize($uploadedfile); $newheight=70; $newwidth= 70; $tmp=imagecreatetruecolor($newwidth,$newheight); // this line actually does the image resizing, copying from the original // image into the $tmp image imagecopyresampled($tmp,$src,0,0,0,0,$newwidth,$newheight,$width,$height); // now write the resized image to disk. I have assumed that you want the // resized, uploaded image file to reside in the ./images subdirectory. $imagefolder = 'images/userimages/user' . $_SESSION['userid'] . '.jpg'; $filename = $imagefolder; $_SESSION['filename'] = $filename; if (imagejpeg($tmp,$imagefolder,100)) { $imagemessage = "File is valid, and was successfully uploaded into FOLDER.\n"; $success="yes"; } else { $imagemessage = "Possible file upload attack!\n"; $success="no"; } imagedestroy($src); imagedestroy($tmp); // NOTE: PHP will clean up the temp file it created when the request // has completed. } Hi I am trying to resize images as they are uploaded. The problem I have is that the image is uploading and adding to the database, but is not resizing. The code I am using is below Code: [Select] <?php include("config.inc.php"); include('../includes/connect_inc.php'); // initialization $result_final = ""; $counter = 0; // List of our known photo types $known_photo_types = array( 'image/pjpeg' => 'jpg', 'image/jpeg' => 'jpg', 'image/gif' => 'gif', 'image/bmp' => 'bmp', 'image/x-png' => 'png' ); // GD Function List $gd_function_suffix = array( 'image/pjpeg' => 'JPEG', 'image/jpeg' => 'JPEG', 'image/gif' => 'GIF', 'image/bmp' => 'WBMP', 'image/x-png' => 'PNG' ); // Fetch the photo array sent by add-photos.php $photos_uploaded = $_FILES['photo_filename']; // Fetch the photo caption array $photo_caption = $_POST['photo_caption']; while( $counter <= count($photos_uploaded) ) { if($photos_uploaded['size'][$counter] > 0) { if(!array_key_exists($photos_uploaded['type'][$counter], $known_photo_types)) { $result_final .= "File ".($counter+1)." is not a photo<br />"; } else { mysql_query( "INSERT INTO gallery_photos(`photo_filename`, `photo_caption`, `photo_category`) VALUES('0', '".addslashes($photo_caption[$counter])."', '".addslashes($_POST['category'])."')" ); $new_id = mysql_insert_id(); $filetype = $photos_uploaded['type'][$counter]; $extention = $known_photo_types[$filetype]; $filename = $new_id.".".$extention; mysql_query( "UPDATE gallery_photos SET photo_filename='".addslashes($filename)."' WHERE photo_id='".addslashes($new_id)."'" ); //resize photos to maximum height or width //define parameters - maximum height & width for new images $image_max_width=599; $image_max_height=599; $max_dimension=800; // Grab the width and height of the image. list($width,$height) = getimagesize($_FILES['photo_filename']); // If the max width input is greater than max height we base the new image off of that, otherwise we // use the max height input. // We get the other dimension by multiplying the quotient of the new width or height divided by // the old width or height. if($image_max_width > $image_max_height){ if($image_max_width > $max_dimension){ $newwidth = $max_dimension; } else { $newwidth = $image_max_width; } $newheight = ($newwidth / $width) * $height; } else { if($image_max_height > $max_dimension){ $newheight = $max_dimension; } else { $newheight = $image_max_height; } $newwidth = ($newheight / $height) * $width; } // Create temporary image file. $tmp = imagecreatetruecolor($newwidth,$newheight); // Copy the image to one with the new width and height. imagecopyresampled($tmp,$image,0,0,0,0,$newwidth,$newheight,$width,$height); //end of resizing // Store the orignal file copy($photos_uploaded['tmp_name'][$counter], $images_dir."/".$filename); // Let's get the Thumbnail size $size = GetImageSize( $images_dir."/".$filename ); if($size[0] > $size[1]) { $thumbnail_width = 100; $thumbnail_height = (int)(100 * $size[1] / $size[0]); } else { $thumbnail_width = (int)(100 * $size[0] / $size[1]); $thumbnail_height = 100; } // Build Thumbnail with GD 1.x.x, you can use the other described methods too $function_suffix = $gd_function_suffix[$filetype]; $function_to_read = "ImageCreateFrom".$function_suffix; $function_to_write = "Image".$function_suffix; // Read the source file $source_handle = $function_to_read ( $images_dir."/".$filename ); if($source_handle) { // Let's create an blank image for the thumbnail $destination_handle = ImageCreate ( $thumbnail_width, $thumbnail_height ); // Now we resize it ImageCopyResized( $destination_handle, $source_handle, 0, 0, 0, 0, $thumbnail_width, $thumbnail_height, $size[0], $size[1] ); } // Let's save the thumbnail $function_to_write( $destination_handle, $images_dir."/tb_".$filename ); ImageDestroy($destination_handle ); // $result_final .= "<img src='".$images_dir. "/tb_".$filename."' /> File ".($counter+1)." Added<br />"; } } $counter++; } header('Location: add-photos.php'); // Print Result echo <<<__HTML_END <html> <head> <title>Photos uploaded</title> </head> <body> $result_final </body> </html> __HTML_END; ?> Any help would be appreciated. I am looking to resize images from a database and found this guide. It looks relatively simple. Is this the easiest method of resizing images. http://articles.sitepoint.com/article/image-resizing-php Hi I'm trying to setup Pagination at the bottom of the page after showing 10 images in the following script but have no clue where to start and how to implement it into the script. I am trying to upload files to a user profile system. here is the profile page Code: [Select] <?php include('core/init.inc.php'); if (isset($_POST['email'], $_POST['location'], $_POST['about'])) { $errors = array(); if(filter_var($_POST['email'], FILTER_VALIDATE_EMAIL) === false) { $errors[] = "The email address you entered is not valid"; } if(preg_match('#^[a-z0-9 ]+$#i',$_POST['location'])===0) { $errors[] = 'Your location must only contain A-Z 0-9 and spaces.'; } if (empty($_FILES['avatar']['tmp_name']) === false) { $file_ext = end(explode('.', $_FILES['avatar']['name'])); if(in_array(strtolower($file_ext), array('jpg', 'jpeg', 'gif', 'png')) === false) { $errors[] = 'Your avatar must be an image.'; } } if(empty($errors)) { print_r($_FILES); set_profile_info($_POST['email'],$_POST['location'],$_POST['about'], (empty($_FILES['avatar']['tmp_name'])) ? false : $_FILES['avatar']['tmp_name']); } $userinfo = array( 'email' => htmlentities($_POST['email']), 'location' => htmlentities($_POST['location']), 'about' => htmlentities($_POST['about']) ); } else { $userinfo = fetch_user_info($_SESSION['uid']); } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Edit your Profile</title> </head> <body> <div> <?php if(isset($errors) == false) { echo 'Click update to edit your profile.'; } else if(empty($errors)) { echo 'Your profile has been updated.'; } else { echo '<ul><li>', implode('</li><li>', $errors), '</li></ul>'; } ?> </div> <form action="" method="post" enctype="multipart/form-data"> <div> <label for="email">Email: </label> <input type="text" name="email" id="email" value="<?php echo $userinfo['email']; ?>" /> </div> <div> <label for="location">Location: </label> <input type="text" name="location" id="location" value="<?php echo $userinfo['location']; ?>" /> </div> <div> <label for="about">About Me: </label> <textarea name="about" id="about" rows="14" cols="50"><?php echo strip_tags($userinfo['about']); ?></textarea> </div> <div> <label for="avatar">Avatar: </label> <input type="file" name="avatar" id="avatar"/> </div> <div> <input type="submit" value="Update" /> </div> </form> </body> </html> here is the function taken from an external file Code: [Select] function set_profile_info($email, $location,$about,$avatar) { $email = mysql_escape_string(htmlentities($email)); $about = mysql_escape_string(nl2br(htmlentities($about))); $location = mysql_escape_string($location); if (file_exists($avatar)) { $src_size = getimagesize($avatar); if ($src_size['mime'] === 'image/jpeg') { $src_img = imagecreatefromjpeg($avatar); } else if ($src_size['mime'] === 'image/png') { $src_img = imagecreatefrompng($avatar); } else if ($src_size['mime'] === 'image/gif') { $src_img = imagecreatefromgif($avatar); } else { $src_img = false; } if ($src_img !== false) { $thumb_width= 200; if($src_size[0] <= $thumb_width) { $thumb = $src_img; } else { $new_size[0] = $thumb_width; $new_size[1] = ($src_size[1] / $src_size[0]) * $thumb_width; $thumb = imagecreatetruecolor($new_size[0], $new_size[1]); imagecopyresampled($thumb, $src_img, 0, 0, 0, 0, $new_size[0], $new_size[1], $src_size[0], $src_size[1]); } imagejpeg($thumb, "{$GLOBALS['path']}/user_avatars/{$_SESSION['uid']}.jpg"); } } $sql = "UPDATE `users` SET `user_email` = '{$email}', `user_about` = '{$about}', `user_location` = '{$location}' WHERE `user_id` = {$_SESSION['uid']}"; mysql_query($sql); } Below I have returned the array of files to check if its been uploaded correctly. Array ( [avatar] => Array ( [name] => Sonic.jpg [type] => image/jpeg [tmp_name] => /var/tmp/php.waq8n [error] => 0 [size] => 48477 ) ) But I get this error message. Warning: imagecreatefromjpeg() [function.imagecreatefromjpeg]: '/var/tmp/php.waq8n' is not a valid JPEG file in /web/stud/u0963643/userprofilesection/finaluserprofile/core/inc/user.inc.php on line 71 If someone could point out where in this code I have made an error I would be very grateful Thanks Jamie Hello, I have a form for uploading CV files into a CV database. Once the files are uploaded to their directory (e.g. www.jobsboard.com/cvdatabase/) please could someone tell me how to restrict access to users? e.g. once a user logs into their userpanel they should be able to click on a hyperlink to download a CV e.g. (www.jobsboard.com/cvdatabase/CV1.doc) but a user who isn't logged in shouldn't be able to access www.jobsboard.com/cvdatabase/CV1.doc Please could you tell me whether this is possible? Many thanks, Stu At the moment I have been uploading files to my server using <input type='files'> and binary encrytion. I would like to have more controll over the files tmp_name. is there a way to assing it befor hand? |