PHP - Display Certain Number Of Database Entries (random)
Hello,
I am using the following code to display images managed by a MySQL database. Basically another program manages a bunch of images, but this script displays certain ones (ones with INCLUDE = 1 in the database) on my main page. My question is, is there an easy way to limit the number of images it displays, say to 5? I'm not too concerned which images actually display (ascending or descending)... or better yet, random! Most importantly, I only want five to display. Each image will be linked to the full page, which displays all the images. Any ideas? Thanks! Code: [Select] <?php $username="XXXXXXX"; $password="XXXXXXX"; $database="XXXXXXX"; mysql_connect(localhost,$username,$password); @mysql_select_db($database) or die( "Unable to select database"); $query="SELECT * FROM ft_form_12 WHERE col_24='1'"; // $query="SELECT * FROM ft_form_12"; // SELECT * FROM ft_form_12 WHERE col_24='1' $result=mysql_query($query); $num=mysql_numrows($result); mysql_close(); ?> <?php $i=0; while ($i < $num) { $f20=mysql_result($result,$i,"col_23"); //Photo file name $f21=mysql_result($result,$i,"col_24"); //INCLUDE ?> <a href="http://www.domain.com/display_whole_page.shtml"><img src="http://www.domain.com/the_file/pictures/<?php echo $f20; ?>" height="50" border="0"></a> <?php $i++; } ?> Similar Tutorialshi!, is it possible to use rand() to generate unique number that will be saved in a database as a primary key? Since i dont want to have numbers like 00001 incrementing on the table. They dont look like real account numbers... i need something like 45642 or 95452 and the like. thanks in advance. I need a way to generate a random number and insert into a database, and I need the database to not contain any duplicates of that number. I basically need to generate a RMA # (Return Merchandise Authorization Number), so the numbers absolutely CAN NOT be duplicate. I have no ideas how to go about this. Should I generate a random number, search the database and see if there's a duplicate, and if there is re-run the script? Hi, Would someone please give me some assistance on how to display random products from my database I need to display a maximum of 6 images and there link in two rows of 3 so; [image] [image] [image] [image] [image] [image] and each image would have something like; <a href="<? echo $row['product_link'] ?>"><img src="<? echo $row['product_image'] ?>"/></a> but i don't know how to display these at random and make sure only 6 appear at a time. Thanks for any help, hope you understand what im trying to explain How would I compare 2 random numbers to rows in a table. The table has 4 rows and 2 colums. My table is setup like this: ID hp mp then has just randomly placed numbers from 0 to 5. So far my script looks like this: I have $new_hp=rand(0,5); $new_mp=rand(0,5). Then i query the db by $myquery=doquery("select hp,mp from users"; $myrow=mysql_fetch_array($myquery); once this is done would a while statement like while ($myrow = mysql_fetch_array($myquery) to what each line in the table has? I would then need to compare the random numbers to those entries in the database. Something like if($myrow[hp] == $new_hp && $myrow[mp] == $new_mp) { ? But if the if statement isnt true it needs go back choose another random number and run same again and again until the statement is true and that is where im stuck at so any help would be greatly appreciated Hello, I have a real estate website, a rss feed and I use feedburner for email subscriptions etc. Since last week, feedburner is not working anymore cause it says that my feed is larger than 512 KB. Well, i would like to change the code of the feed in order to display only the last 200 items (now we have 300), but i tried many ways and didnt have any luck Another solution would be setting a minimum date for publishing the items, for example to set the feed to publish items only if their publication date was after a particular month or day. here is my code, can you help me to limit number of items, please? Thanks in advance <?php defined('_JEXEC') or die( 'Restricted access' ); jimport( 'joomla.application.component.view'); class PropertiesViewProperties extends JView { function display($tpl = null) { global $mainframe; $db =& JFactory::getDBO(); $document =& JFactory::getDocument(); $params =& $mainframe->getParams(); $document->link = JRoute::_('index.php?option=com_properties&view=properties'); $document->setMetaData('description',JURI::base()); // Get some data from the model JRequest::setVar('limit', $mainframe->getCfg('feed_limit')); $query = ' SELECT p.*,c.name as name_category,t.name as name_type,cy.name as name_country,s.name as name_state,l.name as name_locality,pf.name as name_profile,pf.logo_image as logo_image_profile, ' . ' CASE WHEN CHAR_LENGTH(p.alias) THEN CONCAT_WS(":", p.id, p.alias) ELSE p.id END as Pslug,' . ' CASE WHEN CHAR_LENGTH(c.alias) THEN CONCAT_WS(":", c.id, c.alias) ELSE c.id END as Cslug,' . ' CASE WHEN CHAR_LENGTH(cy.alias) THEN CONCAT_WS(":", cy.id, cy.alias) ELSE cy.id END as CYslug,' . ' CASE WHEN CHAR_LENGTH(s.alias) THEN CONCAT_WS(":", s.id, s.alias) ELSE s.id END as Sslug,' . ' CASE WHEN CHAR_LENGTH(l.alias) THEN CONCAT_WS(":", l.id, l.alias) ELSE l.id END as Lslug, ' . ' CASE WHEN CHAR_LENGTH(t.alias) THEN CONCAT_WS(":", t.id, t.alias) ELSE t.id END as Tslug ' . ' FROM #__properties_products AS p ' . ' LEFT JOIN #__properties_country AS cy ON cy.id = p.cyid ' . ' LEFT JOIN #__properties_state AS s ON s.id = p.sid ' . ' LEFT JOIN #__properties_locality AS l ON l.id = p.lid ' . ' LEFT JOIN #__properties_profiles AS pf ON pf.mid = p.agent_id ' . ' LEFT JOIN #__properties_category AS c ON c.id = p.cid ' . ' LEFT JOIN #__properties_type AS t ON t.id = p.type ' . ' WHERE p.published = 1 ' .' ORDER BY p.id DESC' ; $db->setQuery( $query ); $prod = $db->loadObjectList(); foreach ( $prod as $row ) { // strip html from feed item title $title = $this->escape( $row->name ); $title = html_entity_decode( $title ); // url link to article $link = LinkHelper::getLink('properties','showproperty','',$row->CYslug,$row->Sslug,$row->Lslug,$row->Cslug,$row->Tslug,$row->Pslug); // strip html from feed item description text $image_name=$this->Images($row->id); //print_r($image_name); //require('a'); $image = '<img width="200" align="left" alt="'.$item->title.'" src="'.JURI::base().'images/properties/images/thumbs/'.$row->id.'/'.$image_name.'"/>'; $category = ' '.JText::_('Category').': <b>'.$row->name_category.'. </b>'; $desc = '<br>'.'<br>'.'<div align="center" style="border: 1px solid red; margin: 10px; padding: 20px;">'.$row->text.'</div>'; $description = $image.$category.$type.$ref.$desc; $description = $this->escape( $description ); $description = html_entity_decode( $description ); $listdate = $row->listdate; // load individual item creator class $item = new JFeedItem(); $item->title = $title; $item->link = $link; $item->description = $description; $item->date = $listdate; $item->category = $row->name_category; $item->type = $row->name_type; // loads item info into rss array $document->addItem( $item ); } } function Images($id) { $db =& JFactory::getDBO(); $query = ' SELECT i.name ' . ' FROM #__properties_images as i ' . ' WHERE i.published = 1 AND i.parent = '.$id . ' order by i.ordering LIMIT 1'; $db->setQuery($query); $Images = $db->loadResult(); return $Images; } } ?> As above, I have a lottery style site that picks a random number between 1-8 but my users complain for some reason that this is not enough. So i was told to look into using fopen and random.org to generate a random number. Anyone have experience of this and perhaps a code snippet for me to look at and possibly use? help will be appreciated. My php and MySQL scripting works perfectly, but when someone enters data into the php form, using an iPad with Safari browser, all number entries are inserted into the database table incorrectly. It is still a number entry but the number differs substantially from the original input. Note: All other entries, where the individual selects something from a drop-down list and date selecter works perfectly from the same form. Please help me here, since at least 70% of my employees use iPads, thus I need to find a cure for this problem ASAP. Thanks in advance for any help offered. JayDude I need to display a number(the number is retrieved from the db) in the form input field such that only the last 4 digits is visbile, the remaining can be masked as * or X or whatever is applicable. I know the last 4 can be obtained as follows: Code: [Select] $number=substr($number,-4,4); But when i hit the submit button the form validates the input field and checks if the number is a valid number of a specific format. Therefore when I click on the submit button then I should still be able to unmask the masked numbers or do something similar that would help me validate the whole number. Code: [Select] <input type="text" name="no" value="<?php if(!empty($number)){ echo $number;} ?>"> Hello... I have a .txt database with ~100 records. I only want to show the 15 records that are at the top (referring to reading order of the file). Here is my php code to display the records. http://www.flcbranson.org/mobile.php?content=mobile-freedownloads.php if you want to see the results of the code, below. Code: [Select] <?php $index_file = 'services/series/Index-Date.txt'; $fd = fopen($index_file, 'r'); if ($fd) { while (!feof ($fd)) { $seriestitle = trim(fgets($fd, 1024)); // Series Title if(feof ($fd)) break; $seriessubtitle = trim(fgets($fd, 1024)); // Series subtitle $seriesinfo = trim(fgets($fd, 1024)); // Series Info (Church name) $serieslocation = trim(fgets($fd, 1024)); // City, State $seriesindex = trim(fgets($fd, 1024)); // Series index file $seriesstatus = trim(fgets($fd, 1024)); //Online Only? $divider = trim(fgets($fd, 1024)); // Divider $seriestitle2 = $seriestitle; $seriestitle3 = str_replace("'", "%27", $seriestitle); // Kind of makes the alt= below work "God's Will" ends up being "God%27s Will" but without is "God" if(strstr($seriestitle,"<")) { $seriestitle2 = strip_tags($seriestitle); } $seriestitle2 = urlencode($seriestitle2); if(file_exists("images/ProductCovers/".substr($seriesindex,0,-4).".jpg")) { echo "<img src='images/ProductCovers/".substr($seriesindex,0,-4).".jpg' width='115' height='150' border='0' alt='".substr($seriestitle3,7)."'><br />"; } } fclose ($fd); } ?> I'm assuming that "for" would do the trick, but when I tried I got 10 copies of every record. Hehehe... I'm guessing that it's a quick fix. Thanks... JJ Hello, For starters I'm not sure if what I want to do is possible, but if it is I would like your input. I have a script that will show a number of fields to fill out in a second form based on the number the user puts into the first from. the problem is that only the last one saves into the database and not all of them. Code: [Select] <form auction="index.php" method="post"> System Name: <input type="text" name="systemname"> Number of E-sites: <input type="text" name="events"> Number of Sigs: <input type="text" name="sigs"><br> <input type="reset" name="reset" value="Reset"> <input type="submit" name="start" value="Start"> </form> <form auction="index.php" method="post"> <?php $events = $_POST['events']; $system = $POST['systemname']; if (isset($_POST['start'])) { $num = $_POST['sigs']; $i = 0; While ($i < $num) { echo "Sig ID: <input type=text name=sigid>"; echo "Type: <input type=text name=type>"; echo "Name: <input type=text name=name>"; echo "Notes: <input type=text name=notes>"; echo "<br>"; $i++; } } ?> <input type="submit" name="enter" value="Enter"> </form> <?php $sigid = $_POST['sigid']; $type = $_POST['type']; $name = $_POST['name']; $notes = $_POST['notes']; mysql_connect('xt', 'x', 'x'); mysql_select_db('wormhole'); if (isset($_POST['enter'])) { $query = "INSERT INTO sites VALUES ('$system','$events','$sigid','$type','$name','$notes')"; mysql_query($query); } ?> How do I get it so all the data saves, lets say that $num = 5, I want all 5 to save not just the last one. I am quite new so I am sure this is an easy fix for some of the experts around here. I am using the canned script below to add urls to the database as text. The problem is if you update one of the form text boxes it loads all the urls into the database again resulting in a lot of duplicates. My question is, How do I get the form to only post the new changes and not re-post the existing urls? <?php session_start(); if(isset($_SESSION['userSession']) && !empty($_SESSION['userSession'])) { include_once("dbc.php"); if($_POST) { $c = 0; $errMssg = ""; for($i=0;$i<count($_POST['url']);$i++) { if($_POST['url'][$i]=="") { $c++; } } if($c==5) { $errMssg = "Submission error . Please fill at least 1 url."; } else { for($j=0;$j<count($_POST['url']);$j++) { if(!empty($_POST['url'][$j])) { $sql = mysql_query("INSERT INTO images (id ,url ,user_id)VALUES (NULL , '".$_POST['url'][$j]."',".$_SESSION['userId'].")"); } } } } $sqlresult = mysql_query("SELECT * FROM images WHERE user_id =".$_SESSION['userId']); $count = 0; while($data = mysql_fetch_array($sqlresult)) { $image[$count] = $data['url']; $count++; } ?> Code: [Select] $query = mysql_query("SELECT a.*, b.* FROM friendlist a INNER JOIN friendlist b ON (a.friendemail=b.friendemail) INNER JOIN users c ON (b.friendemail = c.EmailAddress) WHERE a.email = 'asdf@gmail.com' AND c.Username LIKE '%carol%' GROUP BY a.id ORDER BY count(*) DESC"); Code: [Select] while ($showfriends = mysql_fetch_array($query)) { echo $showfriends['Username']; } and I would get nothing. It produces the correct number of <div> so i know it's getting through, but it's having trouble displaying the entries? Is there any other way of getting PHP form data into C# any other way besides calling www.downloadHandler.text I am having issues bringing all the entries into C# and breaking them all up. I can do one row fine but multiple rows isn't working. I keep getting an out range error. This is my PHP echo echo $row['userName']. '|' .$row['level']. '|' .$row['points']. '|' .$row['killRate']. '/'; And this is my C# code string nothing = "Not Placed"; string Data_string = www.downloadHandler.text; string[] DataArray; DataArray = Data_string.Split('/'); int numberOfEntries = DataArray.Length; Debug.Log(numberOfEntries); if (DataArray[0] == null || numberOfEntries == 1) { DataArray[0] = nothing; Debug.Log("Data Array [0] isn't there"); High_Points_1.text = DataArray[0]; } else { High_Points_1.text = DataArray[0]; //Debug.Log(DataArray.Length); } if (DataArray[1] == null || numberOfEntries == 2) { DataArray[1] = nothing; Debug.Log("Data Array [1] isn't there"); High_Points_2.text = DataArray[1]; } else { High_Points_2.text = DataArray[1]; //Debug.Log(DataArray.Length); } if (DataArray[2] == null || numberOfEntries == 3) { DataArray[2] = nothing; Debug.Log("Data Array [2] isn't there"); High_Points_3.text = DataArray[2]; } else { High_Points_3.text = DataArray[2]; } if (DataArray[3] == null || numberOfEntries == 4) { DataArray[3] = nothing; Debug.Log("Data Array [3] isn't there"); High_Points_4.text = DataArray[3]; } else { High_Points_4.text = DataArray[3]; } if (DataArray[4] == null || numberOfEntries == 5) { DataArray[4] = nothing; Debug.Log("Data Array [4] isn't there"); High_Points_5.text = DataArray[4]; } else { High_Points_5.text = DataArray[4]; } I have two entries in the database. But when I debugged the number int he array I get 3 strings. I want to show the top five entries in the database. I have an issue with some code I have. All the code works correctly apart from when submit is clicked not only does it update a the current club but it creates a blank entry in the database! I cant see whats wrong. Here is the code......... //gets $validation = $_GET['new_club']; //Querys $qGetClub = "SELECT * FROM clubs WHERE validationID = '$validation'"; $rGetClub = mysql_query($qGetClub); $Club = mysql_fetch_array($rGetClub); //Query for category by name $qGetCat = "SELECT * FROM club_category WHERE catID = ".$Club['cat'].""; $rGetCat = mysql_query($qGetCat); $CatName = mysql_fetch_array($rGetCat); //query for related sub categorys. $qGetSub = "SELECT * FROM sub_categorys WHERE catID =".$Club['cat'].""; $rSubCat = mysql_query($qGetSub); // query for groups created $Groupq = mysql_query("SELECT * FROM groups WHERE memberID = '".$User['memberID']."'"); //end of querys if(isset($_POST['insert_clubbtn1'])){ //Process data for validation $subcat = trim($_POST['subcat']); $NewSubCat = trim($_POST['NewSubCat']); //Prepare data for db insertion $subcat = mysql_real_escape_string($subcat); //find the new category //insert $result = mysql_query("UPDATE clubs SET `sub_category` = '$subcat' WHERE validationID ='$validation'") or die(mysql_error()); if ($result!=="") { $otherg = trim($_POST['other_groups']); $newg = trim($_POST['new_group']); $newg = mysql_real_escape_string($newg); //if an item other than none from the list is selected then update the club with an ID relating to the group it belongs to if ($otherg !=='None') { $groupsq = mysql_query("UPDATE `clubs` SET groupID ='$otherg' WHERE validationID ='$validation'") or die (mysql_error()); } // If none is selected then $newg must have a value so create a new group in the groups table and then on the next page I will add the group in the club table else { $groupsq = mysql_query("INSERT INTO `groups` (`memberID`, `group`, `clubID`) VALUES ('".$User['memberID']."', '$newg', '".$Club['clubID']."')")or die (mysql_error()); } } if ($NewSubCat !="") { mail("mail","New Sub Category Request","Dear Ring Master, \n\nThe club in the name of $name with a validation code of $validationID would like a new sub category called $new_cat\n\n \nTeam Arena\n\n\n\n"); } $url = "/members/create/create_clubp3.php?new_club=$validation"; header("Location: $url"); } For some reason my for loop only seems to be storing some data in my fields, most of the time the data is not true but simply duplicating one of the entries. So instead of having a string of 1,2,3,4 for instance it would store all of them as 4. The entires are selected using fields in a multiple select box, in theory of someone choses 10 unique entries from the "Systems" category all 10 should be made into rows in the MySQL table. Any idea why this is happening? The form, if ($type == "games") { echo "<tr><td>".$name."</td><td><select name='".$name."_".$i."'[] multiple='multiple'><option value='' selected>--------</option>"; $sqla = mysql_query("SELECT * FROM ".$pre."games ORDER BY `name` ASC") or die(mysql_error()); while($row2a = mysql_fetch_array($sqla)) { $system = mysql_fetch_array(mysql_query("SELECT * FROM ".$pre."systems WHERE id = '".$row2a[system]."'")); echo "<option value='".$row2a[id]."'>".$row2a[name]." - ".$system[name]."</option>"; } echo "</select></td></tr>"; } if ($type == "system") { echo "<tr><td>".$name."</td><td><select name='".$name."_".$i."'[] multiple='multiple'><option value='' selected>--------</option>"; $sqlb = mysql_query("SELECT * FROM ".$pre."systems ORDER BY `name` ASC") or die(mysql_error()); while($row2b = mysql_fetch_array($sqlb)) { echo "<option value='".$row2b[id]."'>".$row2b[name]."</option>"; } echo "</select></td></tr>"; } The PHP code, while($row = mysql_fetch_array($query)) { $name = "$row[name]"; for ($i = 0; $i < count($_POST["systems_$i"]); $i++) { mysql_query("INSERT INTO ".$pre."fielddata VALUES (null, 'systems', '".$_POST["systems_$i"]."', '".$fetch[0]."', 'content')"); } for ($i = 0; $i < count($_POST["games_$i"]); $i++) { mysql_query("INSERT INTO ".$pre."fielddata VALUES (null, 'games', '".$_POST["games_$i"]."', '".$fetch[0]."', 'content')"); } Hi, I want to be able to generate visitor statistics for a blog I'm creating. I'm going to be collecting numerous pieces of data when a post is viewed, including a time stamp of the visit. I need to be able to select timestamps that were within the current day, the previous day, the day before that ect.. So that I can generate the statistics. Show it for the current week (current day and 6 previous days). So it would be the entries where the timestamp was made on the days: 11/1, 10/1, 9/1, 8/1, 7/1, 6/1, 5/1. For example. Not quite sure how I could do this. Thanks. hi im trying to display the form entities in the textarea field so they can be sent to the user in an email, but its not working properly it prints out the variable $idName instead of its value?? any help would be greatly appricated ive been stuck on this bit of ages <?php function display_output_page() { $idName = trim($_REQUEST['username']); $firstName = trim($_REQUEST['firstname']); $Surname = trim($_REQUEST['surname']); $Address = trim($_REQUEST['address']); $Email = trim($_REQUEST['email']); $Phone = trim($_REQUEST['phone']); $Fitness = isset($_REQUEST['fitness']) ? $_REQUEST['fitness'] : ''; $goGym = isset($_REQUEST['gogym']) ? $_REQUEST['gogym'] : ''; $whyGym = isset($_REQUEST['whyGym']) ? $_REQUEST['whyGym']: array(); ?> <html> <head><title>Form Results</title></head> <body> <h1>Form Results</h1> <form action='mailto:$Email?subject=user comments' method='post'enctype='text/plain'> <textarea name='Topic' rows=15 cols=90> idName: ". $idName\n; Firstname: ". $_POST["firstname"]\n; Surname: ". $_POST["surname"]\n; Address: ". $_POST["address"]\n; Email: ". $_POST["email"]\n; Phone no.: ". $_POST["phone"]\n; Your fitness level: ". $_POST["fitness"]\n; How often do you go to the gym: ". $_POST["goGym"]\n; Why do you go to the Gym: ". $_POST["whyGym"]; </textarea></br> <input type='submit' value='Send Thru Email'> </form> </body> </html> <?php } ?> I coded the following but some parts are not working (the "curveball" mentioned at the end). How would YOU do this? I have a page (A) displaying a form with a textarea field using a WYSIWYG interface. The user will enter a list of unordered items and upon submit the string will look something like this: This is my list of food items: <ul> <li> Lettuce </li> <li> Tomatoes </li> <li> Eggs </li> <ul> Upon submit, I need to give each list item an unique id and store this id along with the text next to it in a separate table: List_item_id List_item_text List_item_state food_1 Lettuce food_2 Tomatoes food_3 Eggs The user will then land in another page with a form displaying the list. The text is now in the page itself and not in a textarea. Instead of the bullets a dropdown list appears, and the user can select "buy" or "sell" for each list item. This page (B) looks something like this: <form> This is my list of food items: <br><select name="food_1"> <option value="buy">Buy</option> <option value="sell">Sell</option> </select> Lettuce <br><select name="food_2"> <option value="buy">Buy</option> <option value="sell">Sell</option> </select> Tomatoes <br><select name="food_2"> <option value="buy">Buy</option> <option value="sell">Sell</option> </select> Eggs <input type=submit value="submit"> </form> When the user hits "submit" the table with the list items will be updated with the values selected in the dropdown list: List_item_id List_item_text List_item_state food_1 Lettuce Buy food_2 Tomatoes Buy food_3 Eggs Sell The next time the user goes to Page B the list will remember the states. Here's the curveball: At any point the user may click on "EDIT LIST" on Page B so they may add more items (at the begining, middle or end of the string). On edit mode the list items should appear as bullets again inside the WYSIWYG interface. Keep in mind that some of the text in the string may not be a list item (ie, "this is my list of food...") Hello. Many thanks for your help. I am writing a PHP/MySQL dating-site and have hit a programming impass. I have a database full of members and a search form consisting of checkboxes. So to search, a member ticks say...gender: female; age: 21,22,23,24,25,26; height: 5'4",5'5",5'6",5'7"; county: cornwall,devon,somerset How can a run a check on the database selecting all entries that fall into the selected criteria. For example a 23 year old female of 5'5" living in Cornwall and a 26 year old female of 5'4" living in Somerset? The key index of my database is 'id' and the fields a age,height,county The names of the form checkboxes a Gender: male, female; Age: 21,22,23,24 etc; Height: 5_4,5_5,5_6 etc; county: cornwall,devon etc Im trying to create a website where users login, and then when they add a new entry to the database there name is put as the author. This is how my tables are set up. One table is named job and has the columns id, jobtext, jobdate, and authorid. Another table is called author. This table contains the columns id, username, password, and name. Authorid from the job table matches with id from the author table. When a user logins in this code is used to register the name...session_start(); $_SESSION['myusername'] = $_POST['myusername']; $_SESSION['mypassword'] = $_POST['mypassword']; header("location: index.php"); } else { echo "Wrong Username or Password"; } This is the form users use to add a new entry... if (isset($_GET['add'])) { $pagetitle = 'New Job'; $action = 'addform'; $text = ''; $authorid = ''; $id = ''; $button = 'Add job'; include $_SERVER['DOCUMENT_ROOT'] . '/jobs/includes/db.inc.php'; // Build the list of authors $sql = "SELECT id, name FROM author"; $result = mysqli_query($link, $sql); if (!$result) { $error = 'Error fetching list of authors.'; include 'error.html.php'; exit(); } while ($row = mysqli_fetch_array($result)) { $authors[] = array('id' => $row['id'], 'name' => $row['name']); } // Build the list of categories $sql = "SELECT id, name FROM category"; $result = mysqli_query($link, $sql); if (!$result) { $error = 'Error fetching list of categories.'; include 'error.html.php'; exit(); } while ($row = mysqli_fetch_array($result)) { $categories[] = array( 'id' => $row['id'], 'name' => $row['name'], 'selected' => FALSE); } include 'form.html.php'; exit(); } if (isset($_GET['addform'])) { include $_SERVER['DOCUMENT_ROOT'] . '/includes/db.inc.php'; $text = mysqli_real_escape_string($link, $_POST['text']); $author = mysqli_real_escape_string($link, $_POST['author']); if ($author == '') { $error = 'You must choose an author for this job. Click ‘back’ and try again.'; include 'error.html.php'; exit(); } $sql = "INSERT INTO job SET jobtext='$text', jobdate=CURDATE(), authorid='$author'"; if (!mysqli_query($link, $sql)) { $error = 'Error adding submitted job.'; include 'error.html.php'; exit(); } $jobid = mysqli_insert_id($link); if (isset($_POST['categories'])) { foreach ($_POST['categories'] as $category) { $categoryid = mysqli_real_escape_string($link, $category); $sql = "INSERT INTO jobcategory SET jobid='$jobid', categoryid='$categoryid'"; if (!mysqli_query($link, $sql)) { $error = 'Error inserting job into selected category.'; include 'error.html.php'; exit(); } } } header('Location: .'); exit(); } Form.html.php = <?php include_once $_SERVER['DOCUMENT_ROOT'] . '/includes/helpers.inc.php'; ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> <head> <title><?php htmlout($pagetitle); ?></title> <meta http-equiv="content-type" content="text/html; charset=utf-8"/> <style type="text/css"> textarea { display: block; width: 100%; } </style> </head> <body> <?php session_start(); ?> <h1><?php htmlout($pagetitle); ?></h1> <form action="?<?php htmlout($action); ?>" method="post"> <div> <label for="text">Type your job he </label> <textarea id="text" name="text" rows="3" cols="40"><?php htmlout($text); ?></textarea> </div> <div> <label for="author">Author:</label> <select name="author" id="author"> <option value="">Select one</option> <?php foreach ($authors as $author):?> <option value="<?php htmlout($author['id']); ?>"<?php if ($author['id'] == $authorid) echo ' selected="selected"'; ?>><?php htmlout($author['name']); ?></option> <?php endforeach; ?> </select> </div> <fieldset> <legend>Categories:</legend> <?php foreach ($categories as $category): ?> <div><label for="category<?php htmlout($category['id']); ?>"><input type="checkbox" name="categories[]" id="category<?php htmlout($category['id']); ?>" value="<?php htmlout($category['id']); ?>"<?php if ($category['selected']) { echo ' checked="checked"'; } ?>/><?php htmlout($category['name']); ?></label></div> <?php endforeach; ?> </fieldset> <div> <input type="hidden" name="id" value="<?php htmlout($id); ?>"/> <input type="submit" value="<?php htmlout($button); ?>"/> </div> </form> </body> </html> Right now, under authors, it displays all the authors in the database. I want it to just show/submit the authorid of the logged in user. |