PHP - Select All Code Tag...
PHPBB3 does it. I crafted it on my own forum too. Why not have it here? Code is being posted daily.
https://www.phpbb.co...655675#p5655675 See it in action? That would be usefull here instead of dragging and highlighting our mouse over the code and pressing CTRL+C. If IPB has a custom BBCODE manager, you could just use the code in their topic @Phillip. Edited by Monkuar, 25 January 2015 - 12:19 PM. Similar Tutorials
Example Code: if FirstImage=1 is absent, continue with FirstImage=0 Thanks for your idea and effort. please can you help .. I'm passing a value from another page using $_SESSION and trying to then use it in a SELECT statement in SQL think I'm missing something ... if hard code the value it works , and I have also checked at the other end that the variable is being assigned ...
code is (its the = $_SESSION['g_district'] "); that's causing the issue
I'm getting Parse error: syntax error, unexpected '' (T_ENCAPSED_AND_WHITESPACE), expecting '-' or identifier (T_STRING) or variable (T_VARIABLE) or number (T_NUM_STRING) in /Applications/XAMPP/xamppfiles/htdocs/mytimekeeper/add/add.php on line 170 in the browser <div class="row s2 m2 l2"> <div> <label for="course_id">Choose the course raced:</label> <select name="course_id"> <?php // query to create course_id dropdown $resultset = $conn->query("SELECT `course_id`,`course_name` FROM `tbl_courses` WHERE `district`= $_SESSION['g_district'] "); while($row = $resultset->fetch_assoc()) { echo "<option value='{$row[course_id]}'>{$row['course_name']}</option>"; } ?> </select>
Hi all, Currently my dob_day is not showing any value, even though there is a value in the database, it seems like it is unable to retrieve the value. No value was shown in the <select> box. Do you guys have any idea? Thanks Code: [Select] <?php $query = "SELECT name, nric, gender, picture, dob_day FROM tutor_profile WHERE tutor_id = '" . $_GET['tutor_id'] . "'"; $data = mysqli_query($dbc, $query) or die(mysqli_error($dbc)); // The user row was found so display the user data if (mysqli_num_rows($data) == 1) { $row = mysqli_fetch_array($data); if ($row != NULL) { $name = $row['name']; $nric = $row['nric']; $gender = $row['gender']; $old_picture = $row['picture']; $dob_day = $row['dob_day']; } else { echo '<p class="error">There was a problem accessing your profile.</p>'; } //HTML CODING <label for="dob" class="label">Date Of Birth</label> <select id="dob_day" name="dob_day" value="<?php if (!empty($dob_day)) echo $dob_day; ?>"> <option> <option>01</option> <option>02</option> <option>03</option> <option>04</option> <option>05</option> <option>06</option> <option>07</option> <option>08</option> <option>09</option> <option>10</option> <option>11</option> <option>12</option> <option>13</option> <option>14</option> <option>15</option> <option>16</option> <option>17</option> <option>18</option> <option>19</option> <option>20</option> <option>21</option> <option>22</option> <option>23</option> <option>24</option> <option>25</option> <option>26</option> <option>27</option> <option>28</option> <option>29</option> <option>30</option> <option>31</option> </select> ?> Hi,
I'm really at a loss here.
I have queried a table to get an option list, which returns what I expect but I need to then add it to some current code instead of the fixed option list presented.
The syntax is beyond me.
Please see attached.
Any pointers would be great.
Attached Files
OptionList.txt 1.61KB
7 downloads Howdy everyone, please i need help changing a php coded form from a checkbox to a select menu. Here's the form. <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post" > <table class="dtable2"> <tr><th colspan="5">Enter a domain name:</th></tr> <tr><td colspan="5"><center>www.<input name="domain" type="text" size="35" /></center></td></tr> <tr><th colspan="5">Select an extension:</th></tr> <tr> <?php $i = 0; foreach ($this->serverList as $value) { if ($value['check'] == true) $checked=" checked "; else $checked = " "; echo '<td><input type="checkbox" name="top_'.$value['top'].'"'.$checked.'/>.'.$value['top'].'</td>'; $i++; if ($i > 4) { $i = 0; echo '</tr><tr>'; } } ?> </tr> </table> <center><input type="submit" name="submitBtn" class="sbtn" value="Check" /></center> </form> <?php I'll really appreciate your help. I have a search function in php where the text characters are matched to characters in a tables field--- works perfectly.... I need to make the input box have a droplist of words from database, this is also easy for me to do. the problem here is there is no definitive value! the options list always outputs a blank in the url--- its supposed to search a matching value and then output the matching value to url... Here is the droplist code: $output['RATESTITLE']='<input class="inputbox" type="text" size="24px" name="ratestitle" value="'.$sch->filter['ratestitle'].'" onfocus="if (this.value ==\''.$output['LANGUAGE_SEARCH_RATESTITLE'].'\') {this.value = \'\'}" />'; this outputs a input text box--- i want to have a droplist of options to populate this text box... If you must know this is the third day im at it... Hello all,
Based on the suggestion of you wonderful folks here, I went away for a few days (to learn about PDO and Prepared Statements) in order to replace the MySQLi commands in my code. That's gone pretty well thus far...with me having learnt and successfully replaced most of my "bad" code with elegant, SQL-Injection-proof code (or so I hope).
The one-and-only problem I'm having (for now at least) is that I'm having trouble understanding how to execute an UPDATE query within the resultset of a SELECT query (using PDO and prepared statements, of course).
Let me explain (my scenario), and since a picture speaks a thousand words I've also inlcuded a screenshot to show you guys my setup:
In my table I have two columns (which are essentially flags i.e. Y/N), one for "items alreay purchased" and the other for "items to be purchased later". The first flag, if/when set ON (Y) will highlight row(s) in red...and the second flag will highlight row(s) in blue (when set ON).
I initially had four buttons, two each for setting the flags/columns to "Y", and another two to reverse the columns/flags to "N". That was when I had my delete functionality as a separate operation on a separate tab/list item, and that was fine.
Now that I've realized I can include both operations (update and delete) on just the one tab, I've also figured it would be better to pare down those four buttons (into just two), and set them up as a toggle feature i.e. if the value is currently "Y" then the button will set it to "N", and vice versa.
So, looking at my attached picture, if a person selects (using the checkboxes) the first four rows and clicks the first button (labeled "Toggle selected items as Purchased/Not Purchased") then the following must happen:
1. The purchased_flag for rows # 2 and 4 must be switched OFF (set to N)...so they will no longer be highlighted in red.
2. The purchased_flag for row # 3 must be switched ON (set to Y)...so that row will now be highlighted in red.
3. Nothing must be done to rows # 1 and 5 since: a) row 5 was not selected/checked to begin with, and b) row # 1 has its purchase_later_flag set ON (to Y), so it must be skipped over.
Looking at my code below, I'm guessing (and here's where I need the help) that there's something wrong in the code within the section that says "/*** loop through the results/collection of checked items ***/". I've probably made it more complex than it should be, and that's due to the fact that I have no idea what I'm doing (or rather, how I should be doing it), and this has driven me insane for the last 2 days...which prompted me to "throw in the towel" and seek the help of you very helpful and intellegent folks. BTW, I am a newbie at this, so if I could be provided the exact code, that would be most wonderful, and much highly appreciated.
Thanks to you folks, I'm feeling real good (with a great sense of achievement) after having come here and got the great advice to learn PDO and prepared statements.
Just this one nasty little hurdle is stopping me from getting to "end-of-job" on my very first WebApp. BTW, sorry about the long post...this is the best/only way I could clearly explaing my situation.
Cheers guys!
case "update-delete": if(isset($_POST['highlight-purchased'])) { // ****** Setup customized query to obtain only items that are checked ****** $sql = "SELECT * FROM shoplist WHERE"; for($i=0; $i < count($_POST['checkboxes']); $i++) { $sql=$sql . " idnumber=" . $_POST['checkboxes'][$i] . " or"; } $sql= rtrim($sql, "or"); $statement = $conn->prepare($sql); $statement->execute(); // *** fetch results for all checked items (1st query) *** // $result = $statement->fetchAll(); $statement->closeCursor(); // Setup query that will change the purchased flag to "N", if it's currently set to "Y" $sqlSetToN = "UPDATE shoplist SET purchased = 'N' WHERE purchased = 'Y'"; // Setup query that will change the purchased flag to "Y", if it's currently set to "N", "", or NULL $sqlSetToY = "UPDATE shoplist SET purchased = 'Y' WHERE purchased = 'N' OR purchased = '' OR purchased IS NULL"; $statementSetToN = $conn->prepare($sqlSetToN); $statementSetToY = $conn->prepare($sqlSetToY); /*** loop through the results/collection of checked items ***/ foreach($result as $row) { if ($row["purchased"] != "Y") { // *** fetch one row at a time pertaining to the 2nd query *** // $resultSetToY = $statementSetToY->fetch(); foreach($resultSetToY as $row) { $statementSetToY->execute(); } } else { // *** fetch one row at a time pertaining to the 2nd query *** // $resultSetToN = $statementSetToN->fetch(); foreach($resultSetToN as $row) { $statementSetToN->execute(); } } } break; }CRUD Queston.png 20.68KB 0 downloads hirealimo.com.au/code1.php this works as i want it: Quote SELECT * FROM price INNER JOIN vehicle USING (vehicleID) WHERE vehicle.passengers >= 1 AND price.townID = 1 AND price.eventID = 1 but apparelty selecting * is not a good thing???? but if I do this: Quote SELECT priceID, price FROM price INNER JOIN vehicle....etc it works but i lose the info from the vehicle table. but how do i make this work: Quote SELECT priceID, price, type, description, passengers FROM price INNER JOIN vehicle....etc so that i am specifiying which colums from which tables to query?? thanks I have 2 queries that I want to join together to make one row
Dear All, I wish to have 2 drop down boxes, Country Select Box and Locality Select Box. The locality select box will be affected by the value chosen in the country select box. All is working fine except that the locality select box is not being populated. I know that the problem is in the sql statement WHERE country_id='$co' because i am having an error that $co is an undefined variable. All the rest works fine because i have replaced the $co variable directly with a number (say 98) for a particular country id and it worked fine. In what way can i define this variable $co so that it is accepted by my sql statement? Thank you for your help in advance. MySQL Tables indicated below: CREATE TABLE countries( country_id INT(3) UNSIGNED NOT NULL AUTO_INCREMENT, country_name VARCHAR(30) NOT NULL, PRIMARY KEY(country_id), UNIQUE KEY(country_name), INDEX(country_id), INDEX(country_name)) ENGINE=MyISAM; CREATE TABLE localities( locality_id INT(10) UNSIGNED NOT NULL AUTO_INCREMENT, country_id INT(3) UNSIGNED NOT NULL, locality_name VARCHAR(50), PRIMARY KEY (locality_id), INDEX (country_id), INDEX (locality_name)) ENGINE=MyISAM; Extract PHP script included below: // connect to database require_once(MYSQL); if(isset($_POST['submitted'])) { // trim the incoming data /* this line runs every element in $_POST through the trim() function, and assigns the returned result to the new $trimmed array */ $trimmed=array_map('trim',$_POST); // clean the data $co=mysqli_real_escape_string($dbc,$trimmed['country']); $lc=mysqli_real_escape_string($dbc,$trimmed['locality']); } ?> <form action="form.php" method="post"> <p>Country <select name="country"> <option>Select Country</option> <?php $q="SELECT country_id, country_name FROM countries"; $r=mysqli_query($dbc,$q) or trigger_error("Query: $q\n<br />MySQL Error: " . mysqli_error($dbc)); while($row=mysqli_fetch_array($r)) { $country_id=$row[0]; $country_name=$row[1]; echo '<option value="' . $country_id . '"'; if(isset($trimmed['country']) && ($trimmed['country']==$country_id)) echo 'selected="selected"'; echo '>' . $country_name . '</option>\n'; } ?> </select> </p> <p>Locality <select name="locality"> <option>Select Locality</option> <?php $ql="SELECT locality_id, country_id, locality_name FROM localities WHERE country_id='$co' ORDER BY locality_name"; $rl=mysqli_query($dbc,$ql) or trigger_error("Query: $q\n<br />MySQL Error: " . mysqli_error($dbc)); while($row=mysqli_fetch_array($rl)) { $locality_id=$row[0]; $country_id=$row[1]; $locality_name=$row[2]; echo '<option value="' . $locality_id . '"'; if(isset($trimmed['locality']) && ($trimmed['locality']==$locality_id)) echo 'selected="selected"'; echo '>' . $locality_name . '</option>\n'; } // close database connection mysqli_close($dbc); ?> </select> </p> <p><input type="submit" name="submit" value="Submit" /></p> <input type="hidden" name="submitted" value="TRUE" /> </form> I have the following code in html: <html> <head> <script type="text/javascript"> <!-- function delayer(){ window.location = "http://VARIABLEVALUE.mysite.com" } //--> </script> <title>Redirecting ...</title> </head> <body onLoad="setTimeout('delayer()', 1000)"> <script type="text/javascript"> var sc_project=71304545; var sc_invisible=1; var sc_security="9c433fretre"; </script> <script type="text/javascript" src="http://www.statcounter.com/counter/counter.js"></script><noscript> <div class="statcounter"><a title="vBulletin statistics" href="http://statcounter.com/vbulletin/" target="_blank"><img class="statcounter" src="http://c.statcounter.com/71304545/0/9c433fretre/1/" alt="vBulletin statistics" ></a></div></noscript> </body> </html> Is a basic html webpage with a timer redirect script and a stascounter code. I know a bit about html and javascript, but almost nothing about php. My question is: How a can convert this html code into a php file, in order to send a variable value using GET Method and display this variable value inside the javascript code where says VARIABLEVALUE. Thanks in adavance for your help. Hi, I have some code which displays my blog post in a foreach loop, and I want to add some social sharing code(FB like button, share on Twitter etc.), but the problem is the way I have my code now, creates 3 instances of the sharing buttons, but if you like one post, all three are liked and any thing you do affects all of the blog post. How can I fix this? <?php include ("includes/includes.php"); $blogPosts = GetBlogPosts(); foreach ($blogPosts as $post) { echo "<div class='post'>"; echo "<h2>" . $post->title . "</h2>"; echo "<p class='postnote'>" . $post->post . "</p"; echo "<span class='footer'>Posted By: " . $post->author . "</span>"; echo "<span class='footer'>Posted On: " . $post->datePosted . "</span>"; echo "<span class='footer'>Tags: " . $post->tags . "</span>"; echo ' <div class="addthis_toolbox addthis_default_style "> <a class="addthis_button_facebook_like" fb:like:layout="button_count"></a> <a class="addthis_button_tweet"></a> <a class="addthis_counter addthis_pill_style"></a> </div> <script type="text/javascript">var addthis_config = {"data_track_clickback":true};</script> <script type="text/javascript" src="http://s7.addthis.com/js/250/addthis_widget.js#username=webguync"></script>'; echo "</div>"; } ?> Hi, I need to insert some code into my current form code which will check to see if a username exist and if so will display an echo message. If it does not exist will post the form (assuming everything else is filled in correctly). I have tried some code in a few places but it doesn't work correctly as I get the username message exist no matter what. I think I am inserting the code into the wrong area, so need assistance as to how to incorporate the username check code. $sql="select * from Profile where username = '$username'; $result = mysql_query( $sql, $conn ) or die( "ERR: SQL 1" ); if(mysql_num_rows($result)!=0) { process form } else { echo "That username already exist!"; } the current code of the form <?PHP //session_start(); require_once "formvalidator.php"; $show_form=true; if (!isset($_POST['Submit'])) { $human_number1 = rand(1, 12); $human_number2 = rand(1, 38); $human_answer = $human_number1 + $human_number2; $_SESSION['check_answer'] = $human_answer; } if(isset($_POST['Submit'])) { if (!isset($_SESSION['check_answer'])) { echo "<p>Error: Answer session not set</p>"; } if($_POST['math'] != $_SESSION['check_answer']) { echo "<p>You did not pass the human check.</p>"; exit(); } $validator = new FormValidator(); $validator->addValidation("FirstName","req","Please fill in FirstName"); $validator->addValidation("LastName","req","Please fill in LastName"); $validator->addValidation("UserName","req","Please fill in UserName"); $validator->addValidation("Password","req","Please fill in a Password"); $validator->addValidation("Password2","req","Please re-enter your password"); $validator->addValidation("Password2","eqelmnt=Password","Your passwords do not match!"); $validator->addValidation("email","email","The input for Email should be a valid email value"); $validator->addValidation("email","req","Please fill in Email"); $validator->addValidation("Zip","req","Please fill in your Zip Code"); $validator->addValidation("Security","req","Please fill in your Security Question"); $validator->addValidation("Security2","req","Please fill in your Security Answer"); if($validator->ValidateForm()) { $con = mysql_connect("localhost","uname","pw") or die('Could not connect: ' . mysql_error()); mysql_select_db("beatthis_beatthis") or die(mysql_error()); $FirstName=mysql_real_escape_string($_POST['FirstName']); //This value has to be the same as in the HTML form file $LastName=mysql_real_escape_string($_POST['LastName']); //This value has to be the same as in the HTML form file $UserName=mysql_real_escape_string($_POST['UserName']); //This value has to be the same as in the HTML form file $Password= md5($_POST['Password']); //This value has to be the same as in the HTML form file $Password2= md5($_POST['Password2']); //This value has to be the same as in the HTML form file $email=mysql_real_escape_string($_POST['email']); //This value has to be the same as in the HTML form file $Zip=mysql_real_escape_string($_POST['Zip']); //This value has to be the same as in the HTML form file $Birthday=mysql_real_escape_string($_POST['Birthday']); //This value has to be the same as in the HTML form file $Security=mysql_real_escape_string($_POST['Security']); //This value has to be the same as in the HTML form file $Security2=mysql_real_escape_string($_POST['Security2']); //This value has to be the same as in the HTML form file $sql="INSERT INTO Profile (`FirstName`,`LastName`,`Username`,`Password`,`Password2`,`email`,`Zip`,`Birthday`,`Security`,`Security2`) VALUES ('$FirstName','$LastName','$UserName','$Password','$Password2','$email','$Zip','$Birthday','$Security','$Security2')"; //echo $sql; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } else{ mail('email@gmail.com','A profile has been submitted!',$FirstName.' has submitted their profile',$body); echo "<h3>Your profile information has been submitted successfully.</h3>"; } mysql_close($con); $show_form=false; } else { echo "<h3 class='ErrorTitle'>Validation Errors:</h3>"; $error_hash = $validator->GetErrors(); foreach($error_hash as $inpname => $inp_err) { echo "<p class='errors'>$inpname : $inp_err</p>\n"; } } } if(true == $show_form) { ?> Advance thank you. Can you help please. The error..... Warning: mysql_fetch_assoc() expects parameter 1 to be resource, string given in C:\wamp\www\test_dabase.php on line 24 code. Code: [Select] <?php //database connection. $DB = mysql_connect("localhost","root") or die(mysql_error()); if($DB){ //database name. $DB_NAME="mysql"; //select database and name. $CON=mysql_select_db($DB_NAME,$DB)or die(mysql_error()."\nPlease change database name"); // if connection. }if($CON){ //show tables. $mysql_show="SHOW TABLES"; //select show and show. $mysql_select2="mysql_query(".$mysql_show.") or die(mysql_error())"; } //if allowed to show. if($mysql_select2){ //while it and while($data=mysql_fetch_assoc($mysql_select2)){ //show it. echo $data; } } ?> hey gurus, i am a newbie php coder.. i am learning by example. what i am trying to do is write a piece of code which will alter 3 tables (user, bonus_credit, bonus_credit_usage) ---------------------------------------------------------------- the table structure that will be used is as follows: user.bonus_credit user.ID bonus_credit.bonusCode bonus_credit.qty bonus_credit.value bonus_credit_usage.bonusCode bonus_credit_usage.usedBy ---------------------------------------------------------------- so lets say, in bonus_credit i have the following bonusCode = 'facebook' (this is the code they have to type to redeem the bonus qty = '10' ( number of times the bonusCode can be redeemed, but same person can't redeem it more than once) value = '5' (this is the amount of bonus_credit for each qty) Now, I need to write a code that check to see if the code has been redeemed in the bonus_credit_usage table and if the user.ID exists in this table as bonus_code_usage.usedBy, then give an error that its already been used and if it hasn't been used, then subtract 1 from qty, add ID to usedBy and then add the value to the bonus_credit ----------------------- i have started the steps just to create a simple textbox and entering a numeric value to bonus_credit, and that works.. but now i have to use JOIN and IF and ELSE.. which is a little too advanced for me.. so i'd appreciate a guide as i write the code. if(isset($_REQUEST['btnBonus'])) { $bonus_credit = addslashes($_REQUEST['bonusCode']); $query = "update user set bonus_credit=bonus_credit+'".$bonus_credit."' where id='".$_SESSION['SESS_USERID']."'"; echo "<script>window.location='myreferrals.php?msgs=2';</script>"; mysql_query($query) or die(mysql_error()); } Can you help me integrate this code :
<form method="post" action="submit.php"> <input type="checkbox" class="required" /> Click to check <br /> <input disabled="disabled" type='submit' id="submitBtn" value="Submit"> </form>In to this Contact Form code, please? <form action="../page.php?page=1" method="post" name="contact_us" onSubmit="return capCheck(this);"> <table cellpadding="5" width="100%"> <tr> <td width="10" class="required_field">*</td> <td width="80">Your Name</td> <td><input type="text" name="name" maxlength="40" style="width:400px;/></td> </tr> <tr> <td class="required_field">*</td> <td>Email Address</td> <td><input type="text" name="email" maxlength="40" style="width:400px;/></td> </tr> <tr> <td></td> <td>Comments:</td> <td><textarea name="comments" style="width: 400px; height: 250px;"></textarea></td> </tr> </table> </form I use this type of a code to send automatic emails from my website: Code: [Select] $headers = ; $headers .= ; $to = ; Click here to go to Google. ", $headers); I am having hard time figuring out how to do hyperlink on words (like here). If I do something like this: Code: [Select] <a href='http://www.google.com'>here</a> it spits out that exact thing out. Thanks you for your input Hi, Look at this code below: Code: [Select] <?php function outputModule($moduleID, $moduleName, $sessionData) { if(!count($sessionData)) { return false; } $markTotal = 0; $markGrade = 0; $weightSession = 0; $grade = ""; $sessionsHTML = ""; foreach($sessionData as $session) { $sessionsHTML .= "<p><strong>Session:</strong> {$session['SessionId']} <strong>Session Mark:</strong> {$session['Mark']}</strong> <strong>Session Weight Contribution</strong> {$session['SessionWeight']}%</p>\n"; $markTotal += round($session['Mark'] / 100 * $session['SessionWeight']); $weightSession += ($session['SessionWeight']); $markGrade = round($markTotal / $weightSession * 100); if ($markGrade >= 70) { $grade = "A"; } else if ($markGrade >= 60 && $markGrade <= 69) { $grade = "B"; } else if ($markGrade >= 50 && $markGrade <= 59) { $grade = "C"; } else if ($markGrade >= 40 && $markGrade <= 49) { $grade = "D"; } else if ($markGrade >= 30 && $markGrade <= 39) { $grade = "E"; } else if ($markGrade >= 0 && $markGrade <= 29) { $grade = "F"; } $moduleHTML = "<p><br><strong>Module:</strong> {$moduleID} - {$moduleName} <strong>Module Mark:</strong> {$markTotal} <strong>Mark Percentage:</strong> {$markGrade} <strong>Grade:</strong> {$grade} </p>\n"; return $moduleHTML . $sessionsHTML; } $output = ""; $studentId = false; $courseId = false; $moduleId = false; while ($row = mysql_fetch_array($result)) { if($studentId != $row['StudentUsername']) { //Student has changed $studentId = $row['StudentUsername']; $output .= "<p><strong>Student:</strong> {$row['StudentForename']} {$row['StudentSurname']} ({$row['StudentUsername']})\n"; } if($courseId != $row['CourseId']) { //Course has changed $courseId = $row['CourseId']; $output .= "<br><strong>Course:</strong> {$row['CourseId']} - {$row['CourseName']} <strong>Course Mark</strong> <strong>Grade</strong> <br><strong>Year:</strong> {$row['Year']} </p>\n"; } if($moduleId != $row['ModuleId']) { //Module has changed if(isset($sessionsAry)) //Don't run function for first record { //Get output for last module and sessions $output .= outputModule($moduleId, $moduleName, $sessionsAry); } //Reset sessions data array and Set values for new module $sessionsAry = array(); $moduleId = $row['ModuleId']; $moduleName = $row['ModuleName']; } //Add session data to array for current module $sessionsAry[] = array('SessionId'=>$row['SessionId'], 'Mark'=>$row['Mark'], 'SessionWeight'=>$row['SessionWeight']); } //Get output for last module $output .= outputModule($moduleId, $moduleName, $sessionsAry); //Display the output echo $output; } } } ?> This code allallows me to make calculations and display a student's course and linked with it the course the modules in the course and linked with modules are all the sessions. It is able to display what marks each student have got for each module and session. Now look at code below, it is able to display modules and in those modules the sessions that link to those modules: Code: [Select] <?php if($moduleId != $row['ModuleId']) { //Module has changed if(isset($sessionsAry)) //Don't run function for first record { //Get output for last module and sessions $output .= outputModule($moduleId, $moduleName, $sessionsAry); } //Reset sessions data array and Set values for new module $sessionsAry = array(); $moduleId = $row['ModuleId']; $moduleName = $row['ModuleName']; } //Add session data to array for current module $sessionsAry[] = array('SessionId'=>$row['SessionId'], 'Mark'=>$row['Mark'], 'SessionWeight'=>$row['SessionWeight']); } What I want to know is how can I do something similar for course so that it picks out the right modules depending on the course it displays. There maybe some code that needs to be added in the function. Can I combine also HTML code in PHP function? For example, can a PHP function include HTML form and the PHP code to handle this form? If yes, this will make my main code much more smaller and readable. If not, is there a way to define an "external macro" like, which allow me to replace pre-defined lines of code with short alias? Hello Everyone I am new to php and indeed Web Development. After testing and Playing a bit, I can get the following code to work as two files, the form calling the *.php file to insert into the database, however, I am trying to create one html/php file that displays the form and then executes the php code to insert into the database once user clickes the button. Please can you assist me with the code? I have something horribly wrong and I cannot find it. Code: [Select] <?php> <html> <head> <title>Personal Details</title> </head> <body> <form method="post" action="contactdetails.html"><font face="Arial"> Call Sign:<br> <input name="callsign" size="5" type="text"><br> Surame:<br> <input name="surname" size="30" type="text"><br> First Name:<br> <input name="firstnames" size="30" type="text"><br> Known as:<br> <input name="knownas" size="30" type="text"><br> RSA ID No.:<br> <input name="rsaid" size="13" type="text"><br> Birth Date:<br> <input name="birthdate" size="12" type="text"><br> <input name="Insert" value="Next" type="submit"></form> </font><br> </body> </html> //php to insert data into table $callsign = $_POST['callsign']; $surname = $_POST['surname']; $firstnames = $_POST['firstnames']; $knownas = $_POST['knownas']; $rsaid = $_POST['rsaid']; $birthdate = $_POST['birthdate']; mysql_connect ("localhost", "jredpixm_testuse", "PHPDevelopment") or die ('I cannot connect to the database because: ' .mysql_error()); mysql_select_db ("jredpixm_test"); $query="INSERT INTO personal_details (callsign, surname, firstnames, knownas, rsaid, birthdate)Values ('$callsign', '$surname', '$firstnames', '$knownas', '$rsaid', '$birthdate')"; mysql_query($query) or die ('Error updating Database'); echo "<p>Thanks, your information has been added to the database.</p>"; ?> Regards Allen |