PHP - Using Mvc Model With Multiple Objects Possible?
Hi all,
I was just wondering is this possible what I'm trying to do?
Models can only store one object at a time...
I'm trying to access multiple objects via one model...
<?php class users extends Model { protected $username; protected $firstname; protected $secondname; protected $age; // There will be more here... public function __construct($id = NULL) { if($id != NULL) { $this->username = $sql->getUsername($id); $this->firstname = $sql->getFirstname($id); $this->secondname = $sql->getSecondname($id); $this->age = $sql->getAge($id); } } public function numOfUsers() { $num = $sql->countAllUsers($query); return $num; } public function getUsername() { return $this->username; } public function getFirstname() { return $this->firstname; } public function getSecondname() { return $this->secondname; } public function getAge() { return $this->age; } }; class UsersView extends View { $users = new users(); for($i = 0; $i < $users->numOfUsers(); $i++) { $user = new users($i); echo "Username: {$user->getUsername()}"; echo "Username: {$user->getFirstname()}"; echo "Username: {$user->getSecondname()}"; echo "Username: {$user->getAge()}"; } }; ?> Similar TutorialsI can post some code once I am back at my laptop but for now thinking about this is keeping me awake in bed and all I have handy is my phone. Anyway, I am new to OOPHP. I have a class that I created. I have two objects/instances of it, each using some of the same and some different methods within the class. When I run the page either of the instances works great alone but I get the white screen of death when I try to use both instances at the same time. Any ideas or places I should start? Hello all!
I have this array of objects:
Array ( [0] => stdClass Object ( [first_name] => test [last_name] => test [title] => test [id] => 34 [type] => 4 [manager] => 4 [email] => p@yahoo.com [date] => 2014-09-21 07:23:12 [status] => 2 [approval_date] => 2014-09-21 07:31:10 [assessment_id] => 1 [supervisor_approval] => 1 [manager_approval_date] => 2014-09-21 07:31:27 [mainmanger] => 3 ) [1] => stdClass Object ( [first_name] => test [last_name] => test [title] => test [id] => 34 [type] => 4 [manager] => 4 [email] => p@yahoo.com [date] => 2014-09-20 07:39:55 [status] => 2 [approval_date] => 2014-09-20 07:40:41 [assessment_id] => 3 [supervisor_approval] => 1 [manager_approval_date] => 2014-09-20 07:41:07 [mainmanger] => 3 ) [2] => stdClass Object ( [first_name] => jimmy john john [last_name] => john [title] => Lorad and Master [id] => 32 [type] => 4 [manager] => 3 [email] => j@j.com [date] => 2014-09-21 07:38:50 [status] => 2 [approval_date] => 2014-09-19 07:39:25 [assessment_id] => 2 [supervisor_approval] => 1 [manager_approval_date] => 2014-09-19 07:39:25 [mainmanger] => 0 ) )Where "id" = the user ID. If there are two or more entries for a user, I want to remove all but the most recent by the "approval_date",... So for the above example it would return: Array ( [0] => stdClass Object ( [first_name] => test [last_name] => test [title] => test [id] => 34 [type] => 4 [manager] => 4 [email] => piznac@yahoo.com [date] => 2014-09-21 07:23:12 [status] => 2 [approval_date] => 2014-09-21 07:31:10 [assessment_id] => 1 [supervisor_approval] => 1 [manager_approval_date] => 2014-09-21 07:31:27 [mainmanger] => 3 ) [1] => stdClass Object ( [first_name] => jimmy john john [last_name] => john [title] => Lorad and Master [id] => 32 [type] => 4 [manager] => 3 [email] => j@j.com [date] => 2014-09-21 07:38:50 [status] => 2 [approval_date] => 2014-09-19 07:39:25 [assessment_id] => 2 [supervisor_approval] => 1 [manager_approval_date] => 2014-09-19 07:39:25 [mainmanger] => 0 ) )I'm having a hard time wrapping my head around this concept, so I don't have any example code. And I don't really need or expect someone to code this for me,. just a push in the right direction would be awesome. I have the following three tables (and also delta_point and hist_point which are purposely left out and just mentioned for context). Before going down the Doctrine ORM long curvy road, aggrType was just used to restrict possible values so that I didn't need to use MySQL's ENUM, but now I am thinking there may be value to making it an entity and include some methods (and a second reason because I still can't figure out how to make Doctrine create a FK constraint yet not populate the parent entity with a AggrType object). point -id (int PK) -data -dType /* descriminator. Options are AggregatePoint, DeltaPoint, and HistoricPoint */ aggr_point -id (int PK, FK to point) -aggrType (char FK to aggrType) -data aggrType -type (char PK) /* there are about five types */ I have a service to create a new point based on the provided desired type and user data. I don't like the switch statement to determine which type of point to create, but don't know a better way. Also my entity is responsible to provide the appropriate validation rules for the given point type which might not be considered proper but it seems to work for me. Any constructive criticism is welcomed. <?php namespace NotionCommotion\PointMapper\Api\Point; use NotionCommotion\PointMapper\Domain\Entity\Point; class PointService { public function create(string $type, array $params):integer { $class=[ 'aggr'=>'AggregatePoint', 'delta'=>'DeltaPoint', 'hist'=>'HistoricPoint', ][$type]; //$class='Point\\'.$class; //This doesn't seem to be possible and I needed to use the fully qualifed name without the short cut used namespace. $class='\\Greenbean\Datalogger\Domain\Entity\Point\\'.$class; $point=new $class(); $validator=$this->getValidator($point); $params=$validator->sanitize($params); $validator->validate($params); $point->setAccount($this->account); $point->populate($params, $this->em); //Will be addressed later $this->em->persist($point); $this->em->flush(); $point->setIdPublic($this->em->getRepository(Point\Point::class)->getPublicId($point->getId())); return $point->getIdPublic(); } } Now, this is the part I am struggling with the most. I only have one service to create any type of point, so I do wish to put a bunch of if/thens in it and instead move logic to the individual point type being created. The AggrPoint in question requires a sub-point and I don't think it is appropriate to inject the entity manager into a point entity and as an alternative solution find an existing point which is associated with the account which resides in the new AggrPoint. Maybe not appropriate, but it works. This type of point also has a sub-object AggrType as discussed at the very beginning of this post, so I first attempt to create a new one from scratch, but that doesn't work and I need to set $aggrType with an existing one. As an alternative, I passed the entity the entity manager, but as stated I think this is a bad idea. Any recommendations where to go from here? Thank you namespace NotionCommotion\PointMapper\Domain\Entity\Point; class AggregatePoint extends Point { public function populate(array $params, \Doctrine\ORM\EntityManager $em):\NotionCommotion\PointMapper\Domain\Entity\Entity{ $criteria = \Doctrine\Common\Collections\Criteria::create() ->where(\Doctrine\Common\Collections\Criteria::expr()->eq("id_public", $params['pointId'])); if(!$subpoint = $this->getAccount()->getPoints()->matching($criteria)->current()){ throw new \Exception("Invalid subpoint ID $params[pointId]"); } $this->setSubpoint($subpoint); //This won't work since I must use an existing AggregateType and not create a new one $aggrType=new AggregateType(); $aggrType->setType($params['aggrType']); //This just seems wrong and I shouldn't be passing the entity manager to an entity $aggrType=$em->getRepository(AggregateType::class)->findOneBy(['type'=>$params['aggrType']]); $this->setAggregateType($aggrType); unset($params['pointId'], $params['aggrType']); // parent::populate($params) not shown, but it basically calles appropriate setters based on the property name return parent::populate($params); } public function getValidatorRules():array { return $this->filesToArr(['/point/base.json', '/point/aggr.json']); } }
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Leroy. liroyleshed@gmail.com Hello I'm developing a Model-View-Controller framework for my personal learning curve. I've created an active record class and I've got stuck when using variables in a where clause. My problem is this: When, in a where statement, you want to find the Users with the first name Mike, you might write SELECT Firstname, Surname FROM Users WHERE Firstname = 'Mike' Where Mike is enclosed with quotation marks. When you're comparing entities quotation marks shouldn't be used. For example, SELECT Firstname, Surname, OrderTitle FROM Users, Orders WHERE Firstname = 'Mike' AND Users.Firstname = Orders.Firstname So when using variables in my where statements, like $Name = Mike $this->Where(Firstname',$Name); $this->Where('Users.Firstname','Orders.Firstname'); How do I differentiate, in my function Where() when to enclose the string with quotation marks, i.e when it is a (Table.Entity) rather than a constant. Thank you Hey all,
I am making a application that requires a user to login in. I have a user model, which does such things as finds, registers, logins in, updates etc a user. It also grabs all of a users data from a database, such as their username, email address etc and checks whether or not a user is logged in.
The problem I face is this. I want to control what content a user can see depending on if they are logged in or not. In addition to this, I want to output the users data, such as their username, in other parts of the website – such as the header and footer. There is no real easy way of doing this, and requires the user model to be instantiated on every page. My question is should this class be a model or just a core library class?
Hi, I have a cakePHP program that works and displays data from a database table. The part I dont understand and I couldnt find anything on the cakephp blog as yet was the model was left blank? q1) The model is left blank but still works so what is the default behaviour here for the model? It doesnt seem to be needed to do anything i?. q2)I am selecting all the data from 1 table but how do I add a sql statement to select part of the table or a join of 2 tables? the find 'all' seems to just do that only in finding all data from a table. <?php class Post extends AppModel { /*var $name='User';*/ } ?> <?php class PostsController extends AppController { public $helpers=array('Html','Form'); public function index() { $this->set('posts',$this->Post->find('all')); } public function home() { $this->set('posts',$this->Post->find('all')); } } ?> view /// .. <?php foreach ($posts as $item): echo '<tr><td>'. $item['Post']['id']. '</td>'; echo '<td>'. $item['Post']['title'].'</td>'; echo '<td>'. $item['Post']['body'].'</td>'; echo '<td>'. $item['Post']['created'] .'</td>'; echo '</tr>'; endforeach; unset($item); ?> Can a person instantiate a model? If so how do you do it. I already know how to instantiate a class thank you This topic has been moved to Application Frameworks. http://www.phpfreaks.com/forums/index.php?topic=355229.0 Hi Everyone. I am in need of assistance, I need a form that i will use on a model agency site i am making, the form i have only has the option to upload one image and records name, age etc... What i need is a form that will upload multiple images, 2 will do but if i had a option to add more that would be great, and a pdf resume, does anyone have a similar form i can have a look at that does this, any help be awesome, i am already over the deadline. This topic has been moved to Application Frameworks. http://www.phpfreaks.com/forums/index.php?topic=318251.0 Dear Members, I am a PHP developer and desisgning a WAP page for mobiles.I need some php code to find out the model of a mobile phone from where request is coming so that based on that information I can upload the proper CSS for my page.If you can give me some hints as well that would also help me to proceed further.Currently I am able to fetch user-agent of mobile but not able to find out the specific model of mobile. Hi I am new to PHP and I need to create an array and add both books to the array and than loop through the array this is where I am having trouble if the price of a book is less than $20.00 output the book’s name and price if the book’s title comes after the letter R in the alphabet output the book’s title. I am getting these error:
Notice: Trying to get property 'price' of non-object in C:\xampp\htdocs\PHP objects\books.php on line 45 My code is:
<?php
// Methods
$first_book = new Book();
foreach ($book as $bookItem) { Any help will be very much appreciated Thank you In a relational database, you "link" tables together. For example, Customer (parent) ---> Product (child) How do you do that with Objects? I have a "User" class and an "AddressBook" class. A User can have zero or more Addresses (in their AddressBook). If I create a User object and an AddressBook object, I need a way to link them up similar to how they are linked up in the database. Make sense?! TomTees Hi all,
I am working with the following 2 page script: https://github.com/k...hi/php-riot-api. All works well and the data is pulled via the API as intended. However, depending on the data I'm trying to display on screen, the object contains multiple values.
For example:
$r = $test->getSummoner($summoner_id,'name'); print_r($r);outputs their ID and name: {"585897":"TheirName"} Just as the following: $r = $test->getSummonerByName($summoner_name); print_r($r);outputs username, ID, Name, profile icon ID, level, and timestamp: {"theirname":{"id":585897,"name":"TheirName","profileIconId":642,"summonerLevel":30,"revisionDate":1405652924000}} Depending on which function I am calling (on example.php), I would like to be able to split the values so I can echo them throughout a page: Name: <value> ID: <value> Level: <value> etc... Any guidance would be appreciated. I took an object, and saved it into a database serialized. Code: [Select] $object_here = serialize($theobject); Then later on, I go and I get that data from a database, and try to unserialize it.. Code: [Select] $objecthere = unserialize($row->theobject) And it throws the following error...any advice? Quote Warning: unserialize() [function.unserialize]: Node no longer exists in /path/to/file on line 20 I found it helpful to configure all my objects in one or several bootstrap scripts. Before doing so, I would often find myself forgetting that I already had written some class which is located deep in some script and recreating it for some other need (granted, composer definitely helped in this regard, but using it wasn't always applicable). <?php $c=new Pimple\Container(getMySettings()); $c['pdo'] = function ($c) { $db = $c['settings']['mysql']; return new \PDO(bla); }; $c['foo'] = function ($c) { return new Foo( $c->get('pdo') ); }; $c['bar'] = function ($c) { return new Bar( $c->get('foo') ); }; It is all good until I find myself needing to create some new instance of some class instead of just passing some common instance to whoever needs it. class Foo { private $pdo; public function __construct(\PDO $pdo) { $this->pdo=$pdo; } public function getSomething():SomeClass { return new SomeClass($this->getAllDataFromDB($GET['id'])); } } class SomeClass { private $arr; public function __construct(array $records) { foreach($records as $record) { $arr[]=new SomeOtherClass($record); } } } I've read that one shouldn't create new objects in a given class's constructor, and while I could instead do so in some class's method and pass the object to the given class's constructor, to me it seems to really be the same thing. The three issues I have with this scenario a Needing to remember that these classes exist as they are hidden deep in some classes. Makes it more difficult to replace one of the classes with some other class in the future. Some duplication of code.Are there other compelling reasons not to do so? Is it worth the effort to do differently? If so, how would you recommend doing so? My thoughts would either to use Pimple's factory() method are create my only factory which also relies on anonymous functions. Maybe something else? $c['someClass'] = $c->factory(function (array $record, Container $c) { return new SomeClass($record); }); Thanks I know it is often frivolous, but sometimes I can't help trying to optimize things, and use the following two methods to create either an object injected with a string or one of a set of objects. For both cases, the class has no setters so there is no chance that the object will later be changed. I first stated doing this in continuously running server applications which I believe makes sense, however, it has leaked over to standard HTTP requests. Please commit good or bad on this approach. Thanks
public static function create(string $unit):self { static $stack=[]; if(!isset($stack[$unit])) { $stack[$unit] = new self($unit); } return $stack[$unit]; } public static function create(string $class):FunctionInterface { static $stack=[]; if(!isset($stack[$class])) { $stack[$class] = new $class; } return $stack[$class]; }
Hello, Can anyone help me with this. To put it simply. Class foo { protected $bar = new Moo(); How can i use this object (And it's methods) inside the methods of that class. So function whatNot (){ $this->bar->Doesn't work. } } I hope you can get my general meaning. What is the better way, in terms of best practice and also speed of storing PHP objects in a database? Is it: Serialize Code: [Select] $SQL = "INSERT INTO my_table (my_object) VALUES ('" . seralize($php_object). "')"; OR JSON Code: [Select] $SQL = "INSERT INTO my_table (my_object) VALUES ('" . json_encode($php_object). "')"; Any idea which is faster serialize() / unserialize() or json_ecode() / json_decode()? |