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PHP - $_session Vs Mysql For Ajax Updates
Let's say I grab all the user's information from the users table.
It's stored into a variable as an array: $pun_user. Now, to get access this user data, it selects all the data each refresh and sets it to $pun_user for extraction later. My idea: Create a $_SESSION['user_id'] = $pun_user['user_id'] And then when using updating stuff via ajax requests, I can just do SELECT blah from users where where user_id = $_SESSION['user_id'] instead of: calling the main query to enter all the data into $pun_user, then do that query AGAIN and do SELECT blah from users where user_id = $pun_user['user_id'] Is the $_SESSION way going to take a performance hit on the server? Or is the MYSQL way a more detrimental approach? Which way is faster, and less intrusive on the server? Edited by Monkuar, 22 January 2015 - 10:35 PM. Similar TutorialsOk this has been driving me crazy for days now. I need to update my DB with multiple data parsed from an XML feed. I need some help in putting together the query. Currently I have: Code: [Select] $xml= 'test-feed.xml'; // URL for feed. try{ $feed = new SimpleXMLElement($xml, null, true); }catch(Exception $e){ echo $e->getMessage(); exit; } $sqlxml = ""; $arr = array(); foreach($feed->property as $property) { $propertyid = (string)$property->id; foreach($property->images->image as $image) { $i = 0; $url = (string)$image->url; $arr[] = "UPDATE property SET url = '$url' WHERE prop_id = '$propertyid', "; $i++; } } foreach($arr as $result) $sql .= $result; $sql = rtrim($sql, ","); echo $sql; if(!mysql_query($sql)){ echo '<h1 style="color: red;">Error</h1><p>', mysql_error(), '</p>'; } else { echo '<h1 style="color: red;">Property data successfully added to database!</h1>'; } This structures the query correctly for a single update but repeats it which then throws a MYSQL Syntax error. I am not sure of the correct syntax to use for multiple inserts?? What I get returned at the moment is: Code: [Select] UPDATE property SET url = 'ImageId=X1000245' WHERE prop_id = 'A1234', UPDATE property SET url = 'ImageId=X1000296' WHERE prop_id = 'A1234', UPDATE property SET url = 'ImageId=P3&ImgId=X1000237' WHERE prop_id = 'ABC1234', Need some intervention guys Thanks in advance GT Would there be any feasible way of combining the two Update statement below into one? The Members Table has id, username, password, and application_id The Application Table has the application id, the users application information and whether or not the application is approved. if($_GET['approved']=="update"){ $approved=$_GET['approved']; $approved=sanitize($approved); if($approved=="y"){ $id=(int)$_GET['id']; $username=$_GET['username']; $username=sanitize($username); $password=$_GET['password']; $password=sanitize($password); $approved_sql='UPDATE members SET username="$username" password="$password" application_id="$id"'; $approved_result=mysql_query($approved_sql); $approved_rows=mysql_affect_rows(); $update_approved_sql='UPDATE application SET approved="y" WHERE id="$id"'; $update_approved_result=mysql_query($update_approved_sql); $update_approved_rows=mysql_affect_rows(); if($approved_rows==1 && $update_approved_rows==1{ header("Location: ./index.php??admincp=investors&view=applications&id=1&approved=updated"); } } } Let's say I have 1 table and 100 rows in this table. The table is simple and only contains an Auto Increment ID field and a load_count field. Is there any way to have a field that will update any time its row is updated?
My situation is that I will have multiple devices writing to a database, and in one case the time that is being kept track of is important. And the devices writing to the database are a bit difficult to keep accurate times on, so instead of writing the time from the devices themselves, I was hoping I could just have a field update itself. I know it can be done on INSERT, but I do not want to do an INSERT every time.
Thanks!
Hey all, Trying to search for something within a database, using two different fields, one text box and one drop down (the values are actually table names). Here is what I have, this doesn't work: Code: [Select] <?php $result = mysql_query("SELECT * FROM cakeorder WHERE `{$_SESSION['name']}` = '".$_SESSION['search']. "'"); Thanks! Jason
First let me explain my code. This is later included in project_status.php] . In project_status.php] , I have included another file project_status_app.php which contains a HTML form.
<?php
include 'inc_fn_header_and_menu.php';
function includeFile($file,$variable) {
$var = $variable;
include($file);
}
if (isset($_GET['id']) && $_GET['id']!="") {
$pid = $_GET['id'];
$_SESSION['pidForApproval'] = $_GET['id'];
$query = 'SELECT * FROM `profile` WHERE pid ='.'\''.$pid.'\'';
$result=mysqli_query($db,$queryToRetrievePP) or die("There are no records to display ... \n" . mysqli_error());
foreach ($result as $row) {
$status = $row['status'];
}
}
...........some PHP and HTML code.......
<div id="customerPurchaseApprovalForm">
<?php
echo '<p>APPROVAL FOR CUSTOMER PURCHASE</p>';
$discountApprovalStatus = "Granted";
if ($discountApprovalStatus == "Granted") {
includeFile("project_status_app.php",$highestannualvalue);
} else {
//.........
}
In project_status_app.php I am attempting to retrieve pidForApproval from the $_SESSION array.
<?php
// put your code here UPDATE `pp` SET `customer_purchase_remarks` = 'hahaha' WHERE `pp`.`id` = 207;
if ($_SERVER['REQUEST_METHOD'] == 'POST') {
include '../../inc/fastlogin.php';
$sql = "UPDATE pp SET customer_purchase_remarks ='{$_POST['remarkstxt']}' WHERE pp.pid='{$_SESSION['pidForApproval']}'";
$result = mysqli_query ( $fastdb, $sql ) ;
if (mysqli_affected_rows($fastdb) != 1) {
$_SESSION['err_cpa_rmks'] = "<p>Error while updating WHERE id='{$_SESSION['pidForApproval']}'</p>";
//echo "<p>Error while updating WHERE id='{$_POST['pidForApproval']}'</p>".mysqli_error($fastdb);
} else {
$_SESSION['suc_cpa_rmks'] = "<p>Records was updated successfully.</p>";
//echo "Records was updated successfully.";
}
header ("location: project_status.php?id="$_SESSION['pidForApproval']);
exit();
}
?>
When I load project_status.php, project_status_app.php is supposed to display the form. Once the user fills in the form the and the submit button has been pressed, the UPDATE statement is supposed to run and then it is supposed to navigate back to project_status.php?id=FA142. But the update is failing and the when the project_status.php is loaded back, the url looks like this http://localhost/fast/project_status.php?id= . The id is empty. It is supposed to be something like this http://localhost/fast/project_status.php?id=FA142. With the id being populated at the
header ("location: project_status.php?id=".$_SESSION['pidForApproval']);
Missing some information. Hello everyone, I am working on a form that is similar to a shopping cart system and I am thinking of creating a button that submits the checked value and saves them to a $_SESSION variable. And also a link that links to a cart.html that takes the values of a $_SESSION variable. I am have trouble figuring what tag/attribute should I use in order to achieve that.
Right now my code attached below submits the checked values to cart.html directly. However I want my submit button to save the checked box to a $_SESSION variable and STAY on the same page. And then I will implement a <a> to link to the cart.php.
I researched a little bit about this subject and I know it's somewhat related to ajax/jquery. I just wanted to know more about it from you guys. I appreciate your attention for reading the post and Thanks!
Below is the form that I currently have:
<form name= "finalForm" method="POST" action="cart.php">
<input type="Submit" name="finalSelected"/>
<?php foreach($FinalName as $key => $item) {?>
<tr>
<td><input type="checkbox" name="fSelected[]" value="<?php echo htmlspecialchars($FinalID[$key])?>" />
<?php echo "$FinalID[$key] & $item";?>
</td>
</tr>
<?php } ;?>
Below is the code for cart.php
<?php
require ('connect_db.php');
if(isset($_POST['finalSelected']))
{
if(!empty($_POST['fSelected']))
{
$chosen = $_POST['fSelected'];
foreach ($chosen as $item)
echo "aID selected: $item </br>";
$delimit = implode(", ", $chosen);
print_r($delimit);
}
}
if(isset($delimit))
{
$cartSQL = "SELECT * from article where aID in ($delimit)";
$cartQuery = mysqli_query($dbc, $cartSQL) or die (mysqli_error($dbc));
while($row = mysqli_fetch_array($cartQuery, MYSQLI_BOTH))
{
$aTitle[] = $row[ 'name' ];
}
}
?>
<table>
<?php if(isset($delimit)) {
$c=0; foreach($aTitle as $item) {?>
<tr>
<td>
<?php echo $aTitle[$c]; $c++;?>
</td>
</tr>
<?php }}?>
</table>
This topic has been moved to Ajax Help. http://www.phpfreaks.com/forums/index.php?topic=308756.0 Hello fellow programmers I recently bought a chat site without investigating (i know stupid me). this chat is made in Php / Mysql language and ajax, My question is, is there a possibility to convert the mysql to an IRC server. I dont know how to explane it 100% but is it possible to make the webchat thats coded in ajax & mysql work for a IRC server I have knowledge of mysql / php only is this above my level. My problem is that mysql is no option for chats, I need this webchat work with IRC but I have no idea where i should start. Maby someone can kick me in the right direction Thanks for your time & help Greets BTW this is the chatsite more people bought (this aint my site) but 100% the same : http://tinyurl.com/kk4gchd Edited by Remco, 26 November 2014 - 03:32 AM. i was working on a mini project that imports csv file to the database through ajax and it's working fine
<?php
if(!empty($_FILES["marks_file"]["name"]))
{
$connect = mysqli_connect("localhost", "root", "", "dbname");
$output = '';
$allowed_ext = array("csv");
$extension = end(explode(".", $_FILES["marks_file"]["name"]));
if(in_array($extension, $allowed_ext))
{
$file_data = fopen($_FILES["marks_file"]["tmp_name"], 'r');
fgetcsv($file_data);
while($row = fgetcsv($file_data))
{
$name = mysqli_real_escape_string($connect, $row[0]);
$Physics = mysqli_real_escape_string($connect, $row[1]);
$Maths = mysqli_real_escape_string($connect, $row[2]);
$Chemistry = mysqli_real_escape_string($connect, $row[3]);
$Biology = mysqli_real_escape_string($connect, $row[4]);
$SST = mysqli_real_escape_string($connect, $row[5]);
$query = "
INSERT INTO csv
(name, Physics, Maths, Chemistry, Biology, SST)
VALUES ('$name', '$Physics', '$Maths', '$Chemistry', '$Biology' , '$SST')
";
mysqli_query($connect, $query);
}
$select = "SELECT * FROM csv ORDER BY id DESC";
$result = mysqli_query($connect, $select);
$output .= '
<table class="table table-bordered">
<tr>
<th width="25%" >name</th>
<th width="15%" >Physics</th>
<th width="15%" >Maths</th>
<th width="15%" >Chemistry</th>
<th width="15%" >Biology</th>
<th width="15%" >SST</th>
</tr>
';
while($row = mysqli_fetch_array($result))
{
$output .= '
<tr>
<td>'.$row["name"].'</td>
<td>'.$row["Physics"].'</td>
<td>'.$row["Maths"].'</td>
<td>'.$row["Chemistry"].'</td>
<td>'.$row["Biology"].'</td>
<td>'.$row["SST"].'</td>
</tr>
';
}
$output .= '</table>';
echo $output;
}
else
{
echo 'errorx';
}
}
else
{
echo "errory";
}
?>
however the imported csv files inserts null values in the tables because the format of all csv files assigned to me are in the exact same format: ,,,,,,,, ,,,,,,,, ,,,,,,,, ,,,,,,,, ,,,,,,,, ,,,,,,,, ,,,,,,,, ,,,,,,,, ,,,,,,,, ,,,Fields,Physics~75,Maths~50,Chemistry~65,Bio~85,SST~100 ,,,Name1,10,25,35,42,62 ,,,Name2,80,45,45,45,25 ,,,Name3,63,25,63,36,36 ,,,Name4,82,36,75,48,42 ,,,Name5,45,45,78,25,24 ,,,Name6,36,36,15,75,36 ,,,Name7,99,45,24,24,45 ,,,Name8,45,85,85,85,96 i changed my code a bit modified the functions to espace blank spaces and not return null values in the data tables
while (($row = fgetcsv($file_data, 1000, ",")) !== FALSE)
{
if ((string) $row[0] != '0' and empty($row[0]))
{
continue;
}
$name = mysqli_real_escape_string($connect, $row[0]);
$Physics = mysqli_real_escape_string($connect, $row[1]);
$Maths = mysqli_real_escape_string($connect, $row[2]);
$Chemistry = mysqli_real_escape_string($connect, $row[3]);
$Biology = mysqli_real_escape_string($connect, $row[4]);
$SST = mysqli_real_escape_string($connect, $row[5]);
$query = "
INSERT INTO csv
(name, Physics, Maths, Chemistry, Biology, SST)
VALUES ('$name', '$Physics', '$Maths', '$Chemistry', '$Biology' , '$SST')
";
mysqli_query($connect, $query);
}
But it doesn't work with the specified csv files i think the ajax call breaks and that's why nothing happens.However it works fine with csv files without blank spaces Edited March 19, 2019 by zetastreak Hi all,
I'm trying to code a dependable dropdownlist with php/mysql/ajax.
Goal is to select one thing in the first dropdown and depending on that option (and without reloading the page) enabling the second and add the options to the second, dependant on the first.
This is the index :
<?php
require_once($_SERVER['DOCUMENT_ROOT'].'/dbconnect.php');
?>
<script type="text/javascript" src="http://ajax.googleapis.com/
ajax/libs/jquery/1.4.2/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function()
{
$(".country").change(function()
{
var id=$(this).val();
var dataString = 'id='+id;
$.ajax
({
type: "POST",
url: "edit_form.php",
data: dataString,
cache: false,
success: function(html)
{
$(".city").html(html);
}
});
});
});
</script>
<?php
$id_test=$_POST['selector'];
$N = count($id_test);
for($i=0; $i < $N; $i++)
{
$result = mysqli_query($conn, "SELECT * FROM cloud where id='$id_test[$i]'");
while($row = mysqli_fetch_array($result))
{
$id_bird = $row['id'];
?>
<div style="margin:80px">
<label>Country :</label> <select name="country" class="country">
<option selected="selected">--Select Country--</option>
<?php
$sql=mysqli_query($conn, "SELECT category.id AS cat_id, category.name, category.type, cloud.id
FROM cloud,category,link_category_cloud
WHERE link_category_cloud.cloud_id = cloud.id
AND link_category_cloud.category_id = category.id
AND cloud.id='$id_test[$i]'");
while($row=mysqli_fetch_array($sql))
{
$id_test=$row['cat_id'];
$data=$row['name'];
echo '<option value="'.$id_test.'">'.$data.'</option>';
} ?>
</select>
<br/>
<br/>
<label>City :</label> <select name="city" class="city">
<option selected="selected">--Select City--</option>
</select>
</div>
<?php
}
}
?>
And this is the edit_form.php part :
<?php
require_once($_SERVER['DOCUMENT_ROOT'].'/dbconnect.php');
$cat_id = $_GET['cat_id'];
$cloud_id = $_GET['id'];
if($_POST['id_test'])
{
$id_test=$_POST['id_test'];
$data=$_POST['data'];
$sql=mysqli_query($conn, "SELECT * FROM link_category_cloud WHERE category_id={$cat_id}");
$data=$row['cloud_id'];
$id_test=$_POST['id_test'];
echo '<option value="'.$id_test.'">'.$id_test.' '.$data.'</option>';
//}
}
?>
Now, it does not work. I'm not only tring to pass through ID to 'edit_form.php', but also $data and $id_test[i]. Any idea how I can do this?
Thank you very much, all help is so appreciated!!
I wonder whether someone can help me please. I've found http://www.plus2net.com/php_tutorial/ajax-listbox.php tutorial to create a drop down menu using mySQL table data, which, in turn returns a list of results on the page. Following this tutorial I've put together the tables in my database and the required scripts as shown in the tutorial with the one exception, the "z_db.php" file, which I've assumed to be: Code: [Select] <?php mysql_connect("host", "user", "password")or die(mysql_error()); mysql_select_db("database"); ?> The problem I have, is that when I try and run this, I receive the following error: Quote Parse error: syntax error, unexpected T_STRING, expecting ',' or ';' in /homepages/2/d333603417/htdocs/development/catsearch.php on line 91 which is this line in the search form: echo "</head><body onload="ajaxFunction()";>";. I must admit I've guessed as to the structure of the 'z_db.php' file should look like because this is not shown so perhaps this is the problem. I just wondered wether someone could perhaps take a look at this please and let me know where I've gone wrong. Many thanks and kind regards
//my controller
<?php
namespace App\Http\Controllers;
use Illuminate\Http\Request;
use DB;
class homeController extends Controller
{
public function index() {
$employee = DB::table('employee')->orderBy('id','desc')->get();
$department = DB::table('department')->orderBy('id','desc')->get();
return view('index', ['employee' => $employee , 'department' => $department]);
}
}
//my routes
Route::get('index','homeController@index');
//my view using blade temmplating engine
@foreach($employee as $emp)
<div class="employee">
<b>{{ $emp->name }} </b>
<a href="employee/{{ $emp->id }}">
<p class="intro">{{ substr($emp->intro ,0, 50) }}...</p>
</a>
</div>
@endforeach
@foreach($department as $dep)
<div class="department">
<b>{{ $dep->name }} </b>
<a href="department/{{ $dep->id }}">
<p class="desc">{{ substr($dep->description ,0, 100) }}...</p>
</a>
</div>
@endforeach
I want to fetch using ajax, how can i do it, teach/help me This topic has been moved to Beta Test Your Stuff!. http://www.phpfreaks.com/forums/index.php?topic=342258.0 Hello everyone, I begin in everything web related but I have been programming for years. I tried to code something simple : small Mysql DB (works fine) and to begin a search bar to browse data. I adapted a code that I understood provided here : https://www.cloudways.com/blog/live-search-php-mysql-ajax/. Base principle is simple : as you type in your query, it will pass the text to script.js that will forward this request to ajax.php file. In the ajax.php, a javascript function named “fill()” will pass the fetched results. This function will also display the result(s) into “display” div in the “search.php” file. The problem is that when I type anything it displays, below the search bar, at the moment I type a character: Quote
'; //Fetching result from database. while ($Result = MySQLi_fetch_array($ExecQuery)) { ?> ")'>
instead of the actual answer from my database (no error in the browser console). I tested the SQL query + the user I provide and everything seems fine. Any clue what could be the root cause ? I strongly suspect a mistake in the code as I already corrected one (script.js instead of scripts.js) but I really cannot figure out where. Thanks in advance,
problematic code (ajax.php):
<?php
//Including Database configuration file.
include "db.php";
//Getting value of "search" variable from "script.js".
if (isset($_POST['search'])) {
//Search box value assigning to $Name variable.
$Name = $_POST['search'];
//Search query.
$Query = "SELECT Name FROM search WHERE Name LIKE '%$Name%' LIMIT 5";
//Query execution
$ExecQuery = MySQLi_query($con, $Query);
//Creating unordered list to display result.
echo '
<ul>
';
//Fetching result from database.
while ($Result = MySQLi_fetch_array($ExecQuery)) {
?>
<!-- Creating unordered list items.
Calling javascript function named as "fill" found in "script.js" file.
By passing fetched result as parameter. -->
<li onclick='fill("<?php echo $Result['Name']; ?>")'>
<a>
<!-- Assigning searched result in "Search box" in "search.php" file. -->
<?php echo $Result['Name']; ?>
</li></a>
<!-- Below php code is just for closing parenthesis. Don't be confused. -->
<?php
}}
?>
</ul>
This topic has been moved to Ajax Help. http://www.phpfreaks.com/forums/index.php?topic=347691.0 I am having a problem making this work. It adds and deletes but it does it by passing the date directly to the PHP files and refreshing the screen. I want it to do it through the jquery Ajax script. This should work according to what I have read but no mater what I try the jquery script does not work.
<html> <head> <script src="//ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script> <script src="//ajax.googleapis.com/ajax/libs/jqueryui/1.11.0/jquery-ui.min.js"></script> </head> <body> <script type="text/javascript"> $(document).ready(function(){ $('MySignform').submit(function(e) { e.preventDefault(); $.ajax({ type: 'POST', url: $('MySignform').prop('action'), data: $('MySignform').serialize(), success: function() { alert("It worked!"); } }); }); }); </script> <script type="text/javascript"> $(document).ready(function(){ $('DelForm').submit(function(e) { e.preventDefault(); $.ajax({ type: 'POST', url: $('DelForm').prop('action'), data: $('DelForm').serialize(), success: function() { alert("It worked!"); } }); }); }); </script> <br /> <br /> <br /> <center> <form name="MySignform" action="addsigningfee.php" method="post"> <label>Signing fee</label> <input name="signingfee" type="text" id="signingfee"/> <input name="pid" type="hidden" value="7"/> <p></p> <button id="form-submit" type="submit">Save</button> </form> <br /> <div id="result"></div> <br /> <form name="DelForm" action="delsigningfee.php" method="post"> <select name="signingfee"> <?php require_once("connect.php"); foreach ($db->query("SELECT signingfee,id FROM options WHERE signingfee <> '' AND pid = '7'") as $row) { echo "<option value=" . $row['id'] . ">" . $row['signingfee'] . "</option>"; } ?> </select> <p></p> <button type="submit" >Delete</button> </form> </center> </body> </html> Adding and Deleteing mysql date using jquery Ajax I am having a problem making this work. It adds and deletes but it does it by passing the date directly to the PHP files and refreshing the screen. I want it to do it through the jquery Ajax script. This should work according to what I have read but no mater what I try the jquery script does not work. Some help getting me In the right direction would be great. Code: I had this working, but when I try and get fancy and use AJAX the data doesn't display. I think this is a PHP problem though. My code for the select form including AJAX code Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en-GB"> <head> <title>AJAX Example</title> <link rel="stylesheet" type="text/css" href="Form.css" media="screen" /> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js"></script> <script type="text/javascript"> $(document).ready(function(){ $("tr:odd").addClass("odd"); }); </script> <script type="text/javascript"> function showPlayers(str) { var xmlhttp; if (str=="") { document.getElementById("DataDisplay").innerHTML=""; return; } if (window.XMLHttpRequest) {// code for IE7+, Firefox, Chrome, Opera, Safari xmlhttp=new XMLHttpRequest(); else {// code for IE6, IE5 } xmlhttp=new ActiveXObject("Microsoft.XMLHTTP"); } xmlhttp.onreadystatechange=function() { if (xmlhttp.readyState==4 && xmlhttp.status==200) { document.getElementById("DataDisplay").innerHTML=xmlhttp.responseText; } } xmlhttp.open("GET","Query.php?category_id="+str,true); xmlhttp.send(); } </script> </head> <body> <h1">AJAX Example</h1> <?php #connect to MySQL $conn = @mysql_connect( "localhost","username","pw") or die( "You did not successfully connect to the DB!" ); #select the specified database $rs = @mysql_SELECT_DB ("MyDB", $conn ) or die ( "Error connecting to the database test!"); ?> <form name="sports" id="sports"> <legend>Select a Sport</legend> <select name="category_id" onChange="showPlayers(this.value)"> <option value="">Select a Sport:</option> <?php $sql = "SELECT category_id, sport FROM sports ". "ORDER BY sport"; $rs = mysql_query($sql); while($row = mysql_fetch_array($rs)) { echo "<option value=\"".$row['category_id']."\">".$row['sport']."</option>\n "; } ?> </select> </form> <br /> <div id="DataDisplay"></div> </body> </html> Query.php <?php #get the id $id=$_GET["category_id"]; #connect to MySQL $conn = @mysql_connect( "localhost","username","pw") or die( "Error connecting to MySQL" ); #select the specified database $rs = @mysql_SELECT_DB ("MyDB", $conn ) or die ( "Could not select that particular Database"); #$id="category_id"; #create the query $sql ="SELECT * FROM sports INNER JOIN players ON sports.category_id = players.category_id WHERE players.category_id = '".$id."'"; echo $sql; #execute the query $rs = mysql_query($sql,$conn); #start the table code echo "<table><tr><th>Category ID</th><th>Sport</th><th>First Name</th><th>Last Name</th></tr>"; #write the data while( $row = mysql_fetch_array( $rs) ) { echo ("<tr><td>"); echo ($row["category_id"] ); echo ("</td>"); echo ("<td>"); echo ($row["sport"]); echo ("</td>"); echo ("<td>"); echo ($row["first_name"]); echo ("</td>"); echo ("<td>"); echo ($row["last_name"]); echo ("</td></tr>"); } echo "</tr></table>"; mysql_close($conn); ?> I think the problem is either with this part in the AJAX Code: [Select] xmlhttp.open("GET","Query.php?category_id="+str,true); or most likely in my Query.php code when I wasn't using AJAX and using POST it worked fine, but adding the AJAX stuff and GET it doesn't work. When I echo out the SQL the result is Code: [Select] SELECT * FROM sports INNER JOIN players ON sports.category_id = players.category_id WHERE players.category_id = '' so the category_id is not being selected properly and that is the primary key/foreign key in the MySQL table which connects the JOIN. All I am trying to do is add a record on a page without the page refreshing. For that ajax is used. Here is the code.
It does not add the record to mysql table. Can anyone tell me what I am doing wrong?
record.php
<!DOCTYPE HTML>
<html lang="en">
<head>
<script type="text/javascript" src="js/jquery-1.11.0.min.js"></script>
<script type="text/javascript" >
$(function() {
$(".submit_button").click(function() {
var textcontent = $("#content").val();
var name = $("#name").val();
var dataString = 'content='+ textcontent + '&name='+name;
if(textcontent=='')
{
alert("Enter some text..");
$("#content").focus();
}
else
{
$("#flash").show();
$("#flash").fadeIn(400).html('<span class="load">Loading..</span>');
$.ajax({
type: "POST",
url: "action.php",
data: dataString,
cache: true,
success: function(html){
$("#show").after(html);
document.getElementById('content').value='';
$("#flash").hide();
$("#content").focus();
}
});
}
return false;
});
});
</script>
</head>
<body>
<?php
$record_id = $_GET['id']; // getting ID of current page record
?>
<form action="" method="post" enctype="multipart/form-data">
<div class="field">
<label for="title">Name *</label>
<input type="text" name="name" id="name" value="" maxlength="20" placeholder="Your name">
</div>
<div class="field">
<label for="content">content *</label>
<textarea id="content" name="content" maxlength="500" placeholder="Details..."></textarea>
</div>
<input type="submit" name="submit" value="submit" class="submit_button">
</form>
<div id="flash"></div>
<div id="show"></div>
</body>
</html>
action.php
if(isset($_POST['submit'])) {
if(empty($_POST['name']) || empty($_POST['content'])) {
$error = 'Please fill in the required fields!';
} else {
try {
$name = trim($_POST['name']);
$content = trim($_POST['content']);
$stmt = $db->prepare("INSERT INTO records(record_id, name, content)
VALUES(:recordid, :name, :content");
$stmt->execute(array(
'recordid' => $record_id,
'name' => $name,
'content' => $content
));
if(!$stmt){
$error = 'Please fill in the required fields.';
} else {
$success = 'Your post has been submitted.';
}
} catch(Exception $e) {
die($e->getMessage());
}
}
}
I have created a registration page to access my website. After the user registrate himself should appear an alert saying that the registration was OK and a redirect to main.php page... however for some reason if I create an insert statement the alert and the redirect don't appear... If I remove the insert the alert and the redirect works... why? This is part of the code of my 3 files: registration.php (ajax call) $('#submit').click(function() {var username2 = $('#uname2').val(); var password2 = $('#psw2').val(); $.ajax({ url: 'ajax/response.php', type: 'GET', data: {username2 : username2, password2: password2}, success: function(data) { if(data === 'correct') { alert("Username and Password have been created!"); //don' work with the insert location.replace("main.php"); //don' work with the insert } else { alert("Username or password are not correct... please register yourself!"); } } }); }); response.php (answer to ajax call) if(isset($_GET['username2']) && isset($_GET['password2'])) {$username2 = $_GET['username2']; $password2 = $_GET['password2']; if (checkUser($pdo, $username2) === true) { echo 'duplicate'; } else { insertUserPwd($pdo, $username2, $password2); //including this line the redirect and the alert doesn't work... the insert is OK echo 'correct'; } } data_access.php (the function works but doesn't permit alert and redirect to appear) function insertUserPwd(PDO $pdo, $usr, $pwd){ $data = [ 'id' => '', 'user' => $usr, 'password' => $pwd ]; $sql = "INSERT INTO users (id, user, password) VALUES (:id, :user, :password)"; $stmt= $pdo->prepare($sql); $stmt->execute($data); } Can someone help me to fix the code? |
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