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PHP - How To Fetch Video Stream Url Using Youtube Api In Php?
I can search for videos by keyword and can fetch videos list from youtube using its api in php. I can fetch video title, description, thumbnail etc. but how can i fetch video url not like this -> youtube.com/watch?id=xyz...
Example: ytpak[dot]com
Similar TutorialsEvening Everyone,
Been working on this problem for a couple of days and I am stumped. I have a single php file to handle download and streaming of files. It works great with music files, I can download and stream to an <audio> html 5 element just fine. When it comes to my movies, I can download fine but it fails on streaming to a <video> html 5 element. I have done some logging and it looks like after a very short time it just quits.
log when streaming music:
/path/to/music/124 - Mouth Techno -1.mp3 size: 1508731 ctype: audio/mpeg range: 0-1508730/1508731 write chunk: 8192-1508731 write chunk: 16384-1508731 .... write chunk: 1507328-1508731 write chunk: 1515520-1508731 completedlog when streaming movie - this is the complete output, it just stops: Log Started /path/to/movies/AVP_REQUIEM_UNRATED.Title1.DVDRip.mp4 size: 889628920 ctype: video/mp4 range: 0-889628919/889628920 write chunk: 8192-889628920 write chunk: 16384-889628920 write chunk: 24576-889628920 write chunk: 32768-889628920 write chunk: 40960-889628920 write chunk: 49152-889628920 write chunk: 57344-889628920 write chunk: 65536-889628920Here is how I am downloading and streaming the files. Music files work just fine with <audio>, movie files I can only download but want to stream with <video>. This is a hack from multiple sources on the net.
<?php
// sanitize the file request, keep just the name and extension
$filename = $filefix = str_replace('%20', ' ', $_GET["name"]);
$file_path = $filename;
$path_parts = pathinfo($file_path);
$file_dir = $path_parts['dirname'];
$file_name = $path_parts['basename'];
$file_ext = $path_parts['extension'];
$path_default = "/path/to/music/";
$path_types = array(
"mp3" => "/path/to/music/",
"mpg" => "/path/to/movies/",
"avi" => "/path/to/movies/",
"mp4" => "/path/to/movies/",
);
$path = isset($path_types[$file_ext]) ? $path_types[$file_ext] : $path_default;
$file_path = "$path"."$filename";
clearLog();
startLog();
writeLog("$file_path\n");
// allow a file to be streamed instead of sent as an attachment
$is_attachment = isset($_GET["play"]) ? false : true;
// make sure the file exists
if (is_file("$file_path")){
$file_size = filesize($file_path);
$file = @fopen($file_path,"rb");
writeLog("size: $file_size\n");
if ($file){
header("Expires: -1");
header("Cache-Control: public, must-revalidate, post-check=0, pre-check=0");
// set appropriate headers for attachment or streamed file
if ($is_attachment){
header("Content-Disposition: attachment; filename=\"$file_name\"");
}else{
header('Content-Disposition: inline;');
}
// set the mime type based on extension.
$ctype_default = "application/octet-stream";
$content_types = array(
"exe" => "application/octet-stream",
"zip" => "application/zip",
"mp3" => "audio/mpeg",
"mpg" => "video/mpeg",
"avi" => "video/x-msvideo",
"mp4" => "video/mp4",
);
$ctype = isset($content_types[$file_ext]) ? $content_types[$file_ext] : $ctype_default;
header("Content-Type: " . $ctype);
writeLog("ctype: $ctype\n");
$end = ($file_size - 1);
$start = 0;
header("Content-Length: $file_size");
header('Accept-Ranges: bytes');
header("Content-Range: bytes $start-$end/$file_size");
writeLog("range: $start-$end/$file_size\n");
$a=0;
while(!feof($file)) {
$chunk = (1024*8);
echo fread($file, $chunk);
//ob_flush();
flush();
$a=$a+$chunk;
writeLog("write chunk: $a-$file_size\n");
if (connection_status()!=0){
writeLog("failed\n");
fclose($file);
exit;
}
}
// file save was a success
writeLog("completed\n");
fclose($file);
exit;
}else{
// file couldn't be opened
header("HTTP/1.0 500 Internal Server Error");
exit;
}
}else{
// file does not exist
header("HTTP/1.0 404 Not Found");
exit;
}
function startLog(){
$myfile = fopen("newfile.txt", "w");
fwrite($myfile, "Log Started\n");
fclose($myfile);
}
function writeLog($pstr) {
$myfile = fopen("newfile.txt", "a");
fwrite($myfile, $pstr);
fclose($myfile);
}
function clearLog() {
//fclose("newfile.txt");
unlink("newfile.txt");
}
?>
incase it helps, code calling download.php
<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
<link rel="stylesheet" type="text/css" href="movies.css">
</head>
<body>
<a href="javascript:history.back()"><img src="pics/back.png" style=\"height:50px; width=50px;\"/></a>
<a href="index.html"><img src="pics/home.png" style="height:50px; width=50px;display: in-line;"/></a>
<div id="searchContainer" style="height: 40px; width = 700px; display: block; padding: 10px;">
<input type="text" id="SearchString" placeholder="Enter Search Address" style="vertical-align: top;padding: 10px;" class="valid">
<button name="btnSearch" id="btnSearch" type="button"></button>
</div>
<div id="Mainbox" >
<div id="ItemList">
<ol id="List">
<?php
$dir = '/path/to/movies/';
$dirlist = array_diff(scandir($dir), array('..', '.','Thumbs.db'));
asort($dirlist);
$a=0;
foreach ($dirlist as $file) {
$size = round(filesize('/path/to/movies/'.$file)/1048576);
$filefix = str_replace(' ', '%20', $file);
echo "<li><div class=\"item\" id=\"$a\">";
//title
echo "<div id=\"title\">$file</div>";
echo "<div id=\"mb\">$size MB</div>";
echo "<div id=\"dl\"><a href=\"download.php?name=$filefix\"><img src=\"pics/download.png\" style=\"height:25px; width=25px;\"/></a></div>";
if ($size < 1500){
$url = 'download.php?name='.$filefix.'&play=true';
echo "<div id=\"play\" data-value=\"$url\"><a href=\"javascript:void(0)\" onClick=\"updateSource(this);\"><img src=\"pics/play.png\" style=\"height:25px; width=25px;\"/></a></div>";
}
echo "</div></li>";
$a++;
}
?>
</ol>
</div>
</div>
<div id="videocontainer">
<video id="video" controls>
<source id="mp4movie" type="video/mp4">
<source src="movie.ogg" type="video/ogg" codecs="avc1.64001E, mp4a.40.2">
Your browser does not support the video tag.
</video>
</div>
<script type="text/javascript">
function updateSource(element) {
var dvalue = element.parentElement.getAttribute('data-value');
var video = document.getElementById('video');
var source = document.getElementById('mp4movie');
source.src=dvalue;
video.load(); //call this to just preload the audio without playing
video.play(); //call this to play the song right away
}
</script>
</body>
</html>
Thanks for any help!
Edited by AdrianHoffman, 27 September 2014 - 11:51 PM. edited: please note all wmv files are not more than 10 or 20 seconds long. also their size is no more than 500kb. I have this following code that works for photos, but wish to alter this slightly so it will work for video files (wmv) getFtpImage.php Code: [Select] <? header('Content-Type: image/jpg'); $imgdir = '/home/mysite/ftpfolder'; readfile($imgdir . '/' . $_GET['file']); ?> index.php Code: [Select] $imgdir = '/home/mysite/ftpfolder'; // the directory, where your images are stored $allowed_types = array('png','jpg','jpeg','gif'); // list of filetypes you want to show $dimg = opendir($imgdir); while($imgfile = readdir($dimg)) { if(in_array(strtolower(substr($imgfile,-3)),$allowed_types)) { $a_img[] = $imgfile; sort($a_img); reset ($a_img); } } $totimg = count($a_img); // total image number for($x=0; $x < $totimg; $x++) { $size = getimagesize($imgdir.'/'.$a_img[$x]); // do whatever $halfwidth = ceil($size[0]/2); $halfheight = ceil($size[1]/2); ?><img src="getFtpImage.php?file=<? echo ($a_img[$x]); ?>" height="180"><? // echo 'name: '.$a_img[$x].' width: '.$size[0].' height: '.$size[1].'<br />'; } i have the images show to fill the screen and wish for the video page to do the same and with the videos you click the [play] in the center of the video image to play it like most videos play, not like the flash. hello guys i am a newbie want help with how to upload a youtube in your script and in database i know about the $_files thing but how do i give a link please help me out !! Hello, I embed some YouTube videos on my site. Sometimes a video is deleted from YouTube and I have no way of knowing. Does anyone know if there is some php script or by using their API you can check if a video has: - video has been removed - video is not embeddable any more any ideas? Thanks /df Hi, I want to get a latest video from Youtube Playlist. I look it on Google API, and the other solutions, but I think dont undestand quit good what I need to do. For example a have a playlist: https://www.youtube.com/playlist?list=PLW8l7rX2YaXkaSI8GGbmqPjOEmfzd2hz3 And I want to see always only a latest uploaded video, so I need a link (embed - watch, or "youtu.be/xy"): https://www.youtube.com/watch?v=LyzziLETNUw&list=PLW8l7rX2YaXkaSI8GGbmqPjOEmfzd2hz3 Thanks in advanced, T Hi, Thanks in advance, I want to update youtube videos. here is my code. let me tell you firstly, i am very new to php. public function updateVideo($title,$description) { $title="Hello"; $description="Updating video info"; $result=$this->clientLoginAuth($this->username,$this->pass); //$fdata = file_get_contents($fullFilePath); $tmpdata = '<?xml version="1.0"?> <entry xmlns="http://www.w3.org/2005/Atom" xmlns:media="http://search.yahoo.com/mrss/" xmlns:yt="http://gdata.youtube.com/schemas/2007"> <media:group> <media:title type="plain">'.$title.'</media:title> <media:description type="plain">'.$description.'</media:description> <media:category scheme="http://gdata.youtube.com/schemas/2007/categories.cat">People</media:category><media:keywords>Breathe Parkour Magazine</media:keywords> </media:group> <yt:accessControl action="comment" permission="allowed"/> <yt:accessControl action="commentVote" permission="allowed"/> <yt:accessControl action="videoRespond" permission="allowed"/> <yt:accessControl action="rate" permission="allowed"/> <yt:accessControl action="list" permission="allowed"/> <yt:accessControl action="embed" permission="allowed"/> <yt:accessControl action="syndicate" permission="allowed"/> </entry> '; $url = 'http://gdata.youtube.com/feeds/api/users/breathparkour/uploads/6yStkCdeLEU'; //echo $url; $data = '--f93dcbA3 Content-Type: application/atom+xml; charset=UTF-8 '.$tmpdata.' --f93dcbA3 Content-Type: video/quicktime'; //echo $data; return $this->make_update_request($url,$data); } public function make_update_request($url,$data){ //echo $url; $token = $this->accessToken; $developerKey = $this->developerKey; $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, $url); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); if($this->authType == 'GoogleLogin') $curlheader[0] = "Authorization: ".$this->authType." auth=\"$token\""; else $curlheader[0] = "Authorization: ".$this->authType." token=\"$token\""; $curlheader[1] = "X-GData-Key: key=\"$developerKey\""; $curlheader[2] = "Host: gdata.youtube.com"; $curlheader[3] = "Content-Type: application/atom+xml"; $curlheader[4] = "Content-Length: ".strlen($data); $curlheader[5] = "GData-Version: 2"; curl_setopt($ch, CURLOPT_HTTPHEADER, $curlheader); //curl_setopt($ch, CURLOPT_POST, 1); curl_setopt($ch, CURLOPT_POSTFIELDS, $data); curl_setopt($ch, CURLOPT_PUT, true); $output = curl_exec($ch); curl_close($ch); print_r($output); $validresult = $this->checkErrors($output); print_r($validresult); //echo $output; if($validresult['is_error'] == 'No') { unset($validresult); return "Success"; } else { $result = array(); $result['is_error'] = $validresult['is_error']; $result['error'] = $validresult['error']; unset($validresult); return $result; } } i am getting this error. GDataParseExceptionPremature end of file Please help me. i have spent almost 6 hours on this issue. Pleazzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz zzzzzzzzzzzzzzzzzzz Anyone have access to a youtube video/audio downloader script? I'm sure there are one of these laying around somewhere... Looking for 1. I have a video system on my website that allows users to post videos and it embeds youtube videos into the site, I would like to create an interface where you can comment on the actual video itself and it go to youtube's commenting stream. Is that possible? difficult? Hi guys, In an application I'm working on, I'm looking to embed a youtube video with [YOUTUBE][/YOUTUBE]. Code: [Select] echo preg_replace('#(?:<\>]+href=\")?(?:http://)?((?:[a-zA-Z]{1,4}\.)?youtube.com/(?:watch)?\?v=(.{11}?))[^"]*(?:\"[^\<\>]*>)?([^\<\>]*)(?:)?#', '<object width="425" height="350"><param name="movie" value="http://www.youtube.com/v/'.$matches[2].'"></param><param name="wmode" value="transparent"></param><embed src="http://www.youtube.com/v/'.$matches[2].'" type="application/x-shockwave-flash" wmode="transparent" width="425" height="350"></embed></object>', $ENTIREPAGE?); The problem is that the video appears with a slider control at the bottom. How do I get rid of the Youtube slider control at the bottom? Thanks. I'm not sure if this is possible
Previously I had a problem of outputting rows of a specific query
This was the solution that was given to me
$txt .= $date . " " . $stratoparse . "\n\n";Where a while loop's results were concatenated to a single string What I would like to do is output the results in individual containers with controls such as dragging for repositioning / an x for deletion That's not what I'm here for in this post I want to embed youtube videos, so they are not just stored as links, rather a clickable video so if you have something like string.string2.string3.string4.string5.<iframe src="youtube"...>.string7.string8 how would that video be isolated and parsed / understood as a front end youtube video ? To provide a brief background in case you are wondering why in my right mind, I would want to do this... First it is the primary solution that comes to mind going off what already works Secondly, the purpose or point of the concatenated string comes from the "application" design which is a store and recall interface. Vague, I know. The website has multiple users and they all have access to a single database. They save random strings, whether they are paragraphs or links, possibly videos that are uploaded, etc... these are saved by a keyphrase, later recalled by searching that keyphrase. Currently the output is nothing more than a concatenated string, that was fine initially but some of my friends have been testing the website and they made suggestions which are good such as repositioning and deleting entries. Now I want to automatically parse youtube links into embedded videos... I'll probably use that explode "function" to disect the link and place the url within the src=" " Anyway, I have to look into this but if anyone has any thoughts I'd appreciate it. Edited by moose-en-a-gant, 11 January 2015 - 02:05 AM. Hello everyone I am working on a blog system. and I am having problems with the youtube video embed I have found some script online that kinda works If I post more then one youtube link the player shows up.. but it says movie not loaded. if I post just one video it just shows the url to the video on youtube. here is my youtube_function.php <?PHP //convert youtube links into embede function show_youtube($text) { $VID_WID = 320; $VID_HEI = 240; for ($k=0; $k<9; $k++) { $text .= ""; $find = 'youtube.com/watch?v='; $pos = strpos($text, $find); if ($pos == false) { break; } $len = strlen($text); for ($i=$pos; $i>=0; $i--) { if (substr($text, $i, 6) == 'http://') { $pos1 = $i; break; } } for ($i=$pos; $i<$len; $i++) { if (in_array($text[$i], array('&', ' ', "\r", "\n", ',', "\t"))) { $pos2 = $i; break; } } $link1 = substr($text, $pos1, $pos2 - $pos1); $link2 = str_replace('/watch?v=', '/v/', $link1); $embed = '<object width="' . $VID_WID . '" height="' . $VID_HEI . '">'. '<param name="movie" value="' . $link2 . '"></param>'. '<param name="allowFullScreen" value="true"></param>'. '<param name="allowscriptaccess" value="always"></param>'. '<embed src="' . $link2 . '" type="application/x-shockwave-flash" '. 'allowscriptaccess="always" allowfullscreen="true" '. 'width="' . $VID_WID . '" height="' . $VID_HEI . '"></embed></object>'; $text = str_replace($link1, $embed, $text); } return $text; } ?> and I have index.php <?php session_start(); include ("includes/includes.php"); include ("includes/youtube_function.php"); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> <head> <link rel="stylesheet" href="includes/style.css" type="text/css" media="screen" title="no title" charset="utf-8"> <title>Simple Blogging System</title> </head> <body> <div id="wrap"> <div id="header"><h1>Simple Blogging System<br /><font size="6">*Keep it simple*</font></h1></div> <div id="nav"> <center> Link Link Link </center> </div> <div id="main"> <div id="blogPosts"> <?php $blogPosts = GetBlogPosts(); foreach ($blogPosts as $post) { echo "<div class='post'>"; echo "<h2>" . $post->title . "</h2>"; echo show_youtube($post->post, $text); echo "<span class='footer'>Posted By: " . $post->author . " Posted On: " . $post->datePosted . " Tags: " . $post->tags . "</span>"; echo "</div>"; ?> <br /> <?php } ?> </div> </div> <div id="sidebar"> <h2>Archive</h2> <p> old </p> <p> old </p> <p> old </p> </div> <div id="footer"> <p>Simple Blogging System</p> </div> </div> </body> </html> so as you can see I have show_youtube($post->post, $text); I have tried this just out of curiosity to see if I could fix this myself. but It seems like the video does not want to run at all... I am confused with this and some help would be greatly appreciated. Thank you in advance I am looking for a code where I can get a video URL from Youtube, Vimeo, Facebook and convert it to an embedded video to be shown on my site. I found a script that does that. It works fine. The only errors I get are in the inspect element window in the browser. Errors such as this. Failed to load resource: net::ERR_BLOCKED_BY_CLIENT googleads.g.doubleclick.net/pagead/id:1 Failed to load resource: net::ERR_BLOCKED_BY_CLIENT static.doubleclick.net/instream/ad_status.js:1
This is the function to generate the embedded videos. Do the above errors matter if the videos show up and play fine?
function generateVideoEmbedUrl($url){
//This is a general function for generating an embed link of an FB/Vimeo/Youtube Video.
$finalUrl = '';
if(strpos($url, 'facebook.com/') !== false) {
//it is FB video
$finalUrl.='https://www.facebook.com/plugins/video.php?href='.rawurlencode($url).'&show_text=1&width=200';
}else if(strpos($url, 'vimeo.com/') !== false) {
//it is Vimeo video
$videoId = explode("vimeo.com/",$url)[1];
if(strpos($videoId, '&') !== false){
$videoId = explode("&",$videoId)[0];
}
$finalUrl.='https://player.vimeo.com/video/'.$videoId;
}else if(strpos($url, 'youtube.com/') !== false) {
//it is Youtube video
$videoId = explode("v=",$url)[1];
if(strpos($videoId, '&') !== false){
$videoId = explode("&",$videoId)[0];
}
$finalUrl.='https://www.youtube.com/embed/'.$videoId;
}else if(strpos($url, 'youtu.be/') !== false){
//it is Youtube video
$videoId = explode("youtu.be/",$url)[1];
if(strpos($videoId, '&') !== false){
$videoId = explode("&",$videoId)[0];
}
$finalUrl.='https://www.youtube.com/embed/'.$videoId;
}else{
//Enter valid video URL
}
return $finalUrl;
}
How could I from the varying URLs parse only the YouTube video ID? http://www.youtube.com/watch?v=SwrawcORlp0&feature=player_embedded http://www.youtube.com/watch?v=SwrawcORlp0&feature=popular How can I from the URLs above only extract the id into a variable $url SwrawcORlp0 Thanks, df I am creating a stream for my website similar to facebook's news feed where users can post to, add photos too ect. When a user uploads a photo it gets added to the photos table and a new row to the stream Code: [Select] mysql_query("INSERT INTO photos VALUES ('','$id','$username','$photo','$time')"); mysql_query("INSERT INTO stream VALUES ('','$id','$username','$time','No comment','$photo','')"); Which displays the image on the stream fine but what i am looking to do is if the user uploads more images one after another instead of adding a new post to the stream for every picture i want to show all of the new pictures in one post like what Facebook does. I can't figure out how i would do this. Hi ! I'm trying to understand how php://input works. I've read the manual ( http://php.net/manual/en/wrappers.php.php ) and I have an example of a file upload receiving the file with php://input instead of $_FILES. But I can't understand it, does somebody a good tutorial about php://input ? What is the data inside it? is always the same that $HTTP_RAW_POST_DATA ? How can we send a file to PHP and receive it with php://input ? I'm trying to see what's inside php://input with this code: Code: [Select] $in = fopen("php://input", "rb"); echo Debug::vars($in); if ($in) { while ($buff = fread($in, 4096)) { echo $buff . EOL; // fwrite($out, $buff); } } but I get always blank output (Debug is a Kohana class and it returns: Quote resource(stream) php://input Thanks !! The following will create a PHP stream. $response = $this->guzzleHttp->get($url); $stream = \GuzzleHttp\Psr7\StreamWrapper::getResource($response->getBody()); How can I return a stream using just PHP's native cURL library? Hi! I am having trouble reading a stream of data being sent to my PC via PHP5. It seems that my code stops when it gets to the read section and just sits there indefinately. I am somewhat new to PHP so a solution and explanation would be great! Code: [Select] <?php $host = "129.000.00.01"; // host IP address $port = 40000; // port to listen to // sets script execution limit set_time_limit(30); // 0 means unlimited execution time (constant running) // create UDP socket $socket = socket_create(AF_INET, SOCK_DGRAM, SOL_UDP) or die("Could not create UDP socket!\n"); // reset socket for binding if(!socket_set_option($socket, SOL_SOCKET, SO_REUSEADDR, 1)) { echo "Failed to reset socket!\n"; } else echo "Reset socket successfully!\n"; // bind socket socket_bind($socket, $host, $port); // connect if (!socket_connect($socket, $host, $port)) { echo "Failed to connect to port!\n"; } else echo "Connected to port successfully!\n"; while (1) { echo socket_read($socket, 1024, PHP_NORMAL_READ)."\n"; } // close sockets socket_close($socket); echo "\nDone"; I have my IP camera with the streaming URL :
http://x.x.x.x:81/li...user=admin&pwd=
Now i want to record the streaming using PHP . Now please anyone help how to do this ?
Any help would be appreciated .
Edited by ZohaibKhalid1, 17 October 2014 - 08:41 AM. The other day I noticed someone had post something like this, well this was actually the solution to the problem. But it got me thinking about a project of mine that I am working on and the need to pump out a downloadable file. We are storing most of the files in a database using base64 encoding the 2 key types of files we are storing are images and PDF's mostly pdf's anyway where I am wanting to go with this is, is there anyway to take the base64 encoded file and get it to download through this, or am I tackling the idea in the wrong way? <?php $filename = 'somename.txt'; //this would obviously be changed according to the file type we would output $data =<<<DATA I know my data would go here for the given file once decoded. DATA; header('Content-Description: File Transfer'); header('Content-Type: application/octet-stream'); header('Content-Disposition: attachment; filename=' . $filename); header('Content-Transfer-Encoding: binary'); header('Expires: 0'); header('Cache-Control: must-revalidate, post-check=0, pre-check=0'); header('Pragma: public'); header('Content-Length: ' . strlen($data)); echo $data; ?> I am trying to display an image stream from my pond cam... The stream generated by my ip video server is a jpeg stream without boundaries. Causeur of this the normal mime replace isn't working. I need php to read a picture from the stream, and display the picture in the browser while reading the next picture in the background. I've got to the point that I am able to connect to the stream, read the first image, and display it in the browser as can be seen in the link below (cam is only on from 09:00 until 16:00) http://cam.xsiteit.nl/readstream_test.php From this point I need to read the second image and replace the image in the browser with the new one. This process has to continu until the browser is closed. Any help would be great! Regards, Peter |
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