PHP - Unable To Retrieve Selected Array Values [php]

Hi folks,

Complete No0b here when it comes to PHP and MySQL.

I am in the middle of creating a PHP website. What I want to do is have the contents of a page in a MySQL table and have PHP gather the page content and display it on the page.
Here is what I have in my home.tpl file:

Code: [Select]
<?php $query  = "SELECT home, FROM $database_name";
$result = mysql_query($query); ?>
And, in my index.php I simply call that home.tpl to display the data by using:

Code: [Select]
<?php include 'templates/default/home.tpl'; ?>
Now, all I get is a blank page on index.php. Is there something else I should be doing?
Remember, I am a complete No0b!

Thanks folks.

Hi guys,

Currently I am editing profiles online and get it updated in my database.

And when user has successfully updated his/her profile, they will be directed to a link
echo '<p>Your profile has been successfully updated. Would you like to <a href="viewprofile.php?tutor_id=' . $_GET[$row['tutor_id']] . '">view your profile</a>?</p>';

As you can see, I have set tutor_id=' . $_GET[$row['tutor_id']] . ', which I personally know is incorrect to code it in this manner. May I know how do I code in a way where I can achieve something like this...
www.abc.com/viewprofile?tutor_id=12343


The value which currently I receive is www.abc.com/viewprofile?tutor_id='blank'
Code: [Select]
<?php
if (!$error) {
      if (!empty($tutor_id) && !empty($name) && !empty($nric) && !empty($dob_day) && !empty($dob_mth) && !empty($dob_year) && !empty($gender)) {
        
// Only set the picture column if there is a new picture
if (!empty($new_picture)) {
$query = "UPDATE tutor_profile SET name = '$name', nric = '$nric', dob_day = '$dob_day', dob_mth = '$dob_mth', dob_year = '$dob_year',  
gender = '$gender', picture = '$new_picture' WHERE tutor_id = '$tutor_id' ";
}
else {
          $query = "UPDATE tutor_profile SET name = '$name', nric = '$nric', dob_day = '$dob_day', dob_mth = '$dob_mth', dob_year = '$dob_year',  
  gender = '$gender' WHERE tutor_id = '$tutor_id' ";
        }

mysqli_query($dbc, $query)
or die(mysqli_error($dbc));

        // Confirm success with the user
        echo '<p>Your profile has been successfully updated. Would you like to <a href="viewprofile.php?tutor_id=' . $_GET['tutor_id'] . '">view your profile</a>?</p>';

        mysqli_close($dbc);
        exit();
?>

I am trying to create a code where the user enters the zip code and if found in the database, a location will be retrieved. I am getting two undefined variables as errors. I am still learning the POST and GET method and I fear that is where I am getting something mixed up. I have also attached an image of my DB.

Thank you so much any input is greatly appreciated.

Notice: Undefined variable: address in C:\xampp\htdocs\index.php on line 53

Notice: Undefined variable: zip in C:\xampp\htdocs\index.php on line 54

index.php file code:

 

<?php

     include ('header.php');
     include ('function.php');

     ?>


        <div class="wrapper">
           <div>
               <?php
               echo'<form method="POST" action"'.getLocations($conn).'">
                   <input type="text" name="zip" class="search" placeholder="Zip code"><br>
                   <button type="submit" value="submit" id="submit">Submit</button>
                   </form>';
               getLocations($conn);
              ?>         
           </div>
        </div>
        
        <div>
             <!--foreach($zip as $zip) : -->
            <?php 
                  echo $address['address'];
                  echo $zip['zip']; 
            ?>
        </div>
    
    
 function.php file code:
    
    
    <?php
    
    $dBServername = "localhost";
    $dBUsername = "root";
    $dBPassword = "";
    $dBName = "addresses";
    
    // Create connection
    $conn = mysqli_connect($dBServername, $dBUsername, $dBPassword, $dBName);
    
    // Check connection
    if (!$conn) {
        die("Connection failed: " . mysqli_connect_error());
    }
    function getLocations($conn) {
        if (isset($_POST['submit'])){
            
             // Validate Zip code field
            if (!empty ($_POST['zip']) && is_numeric ($_POST['zip'])) {
                
            $zip = (int)$_POST['zip'];
        
            
        $query = "SELECT * FROM locations WHERE zip = '$zip'";
        
        //get the results
        $result = mysqli_query($conn, $query);
        
        //fetch the data
        $zip = mysqli_fetch_all($result, MYSQLI_ASSOC);
        var_dump($zip);
        
        
        mysqli_free_result($result);
        
        //close connection
        mysqli_close($conn);
    
        
       }
    } 
      
    }

 

Hi,
My output in html is :
Code: [Select]
<uL><li id="B1"></li>
<li id="B2"></li>
<li id="B3"></li>
<li id="B4"></li>
<li id="B5"></li>
<li id="B6"></li>
<li id="B7"></li>
<li id="B8"></li>
<li id="B9"></li>
<li id="B10"></li>
<li id="B11"></li>
<li id="B12" class="active"></li>
<li id="B13" class="no"></li>
<li id="B14" class="no"></li>
<li id="B15" class="no"></li>
<li id="B16" class="no"></li>
<li id="B17" class="no"></li>
<li id="B18" class="no"></li>
<li id="B19" class="no"></li>
<li id="B20" class="no"></li>
</ul>
If MySQL query result is equal to `6`, then `<li>` tag with `id` equal to "`B12`" should have class "`active`". All the `<li>` elements occuring after this active element should have class "`no`".

This shows images of horizontal rating between `0` and `10` and between 0.5
Example : 0 .5 1 1.5 2 2.5 3 3.5 4 4.5 5 5.5 6 6.5 7 7.5 8 8.5 9 9.5 10
In the example above elements from `0` to `5` will be blue, element `6` will be white and elements from `7` to `10` are black.

How could I generate this using PHP and/or MySQL?

Thanks, XXXX chirstmas XXXX

I AM WORKING ON A PROJECT , I NEED YOUR HELP.  I WANT TO USE EXISTING SRC OF IFRAME + RETRIVED VALUE FROM DATABASE INTO IFRAME

This is my data.php to retrive values from database into iframe without refresh web page.

<?php
	$conn = new mysqli('localhost', 'root', '', 'x');
if ($conn->connect_error) {
    die("Connection error: " . $conn->connect_error);
}
$result = $conn->query("SELECT number1 FROM users");
if ($result->num_rows > 0) {
    while ($row = $result->fetch_assoc()) {
        echo $row['number1'] . '<br>';
    }
}
?>

FOLLOWING IS INDEX FILE

<?php include('data.php') ?>
<html>
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
	</head>
<body>
    <div id="show"></div>
    <script type="text/javascript" src="jquery-3.1.1.min.js"></script>
    <script type="text/javascript">
        $(document).ready(function() {
            setInterval(function () {
                $('#show').load('data.php')
            }, 1000);
        });
    </script>
	    <iframe id="w3" src="DATABASE RETRIVED VALUE" height="80px" width="300px" frameborder="0" style="border: 0; width:300px; height:80px; background-color: #FFF;"></iframe>
    </body>
</html>

 

INDEX FILE CODES CAN SUCCESSFULLY RETRIVE VALUES FROM DATABASE BUT, I WANT TO STORE IT IN IFRAME SRC .

VAR= URLS = 'HTTP://WWW.GOOGLE.COM'

IFRAME SRC WILL BE VAR URLS + RETRIEVED VALUE FROM DATABASE

 

 

 

Hi,
Im battling here to get "only" certain values from a "akey" and "value" query..

I have a list of items around 200 id's strong, i only want to pull cirtain values from the list,
the table structure is like so:
id, akey, value

// i don't know the values of the specific akey's or their id's but i do know the akey value.
what i am trying to do is only pull the values that are in the "getConfigTitle's" list below (this list is only a sample the actual list is around 100 strong)
here is my code sample:



$query="SELECT akey,value FROM settings WHERE LOWER(akey) LIKE getConfigTitles();";
$settingsList=doSelectSql($query);
foreach ($settingsList as $set)
{
$r=array();
$r['CONFIGTITLE']=getConfigTitles();
$r['KEY'] = $set->akey;
$r['SETTING'] = $set->value;
$rows[]=$r;
}

function getConfigTitles()
{
$titles=array();
$titles['search']= "search" ;
$titles['viewprofile']= "viewprofile" ;
$titles['editprofile']= "editprofile" ;
$titles['dashboard']= "dashboard" ;
$titles['preview']= "preview" ;
return $titles;
}

hey i am using a MySql database and i need to create a dynamic HTML table with one of its columns as checkboxes.so i have to create multiple checkboxes.but these checkbox values are to be stored in a mysql table and then later retrieved when form reloads.and depending on previous state when form was submitted, the newly created checkboxes have to be checked in the same manner.so how do i store multiple checkbox values in my table and also how do i retrieve them?
please help.

Am a newbie in php. Since I can't insert values to the database with respect to a user Id or with any other token using WHERE clause.

I.e "INSERT INTO receipts(date) VALUES(example) where id="**....."

If I need to fetch several values of column for a particular user, how do I go about it? Thank you!!!

Hey everyone.

I am creating a website so my family can select from the list of present my daugther has asked for.  I have them logging in, and that works.  I have the table data set and the search and table display works.  But I would like to display the list (as in the code below) but with a checkbox in the first column (add a column).  From that the authenticated user can click on the item they have purchased and that selection will be moved to another table (called purchased).  I have that code.  The only thing I cannot figure out is to present the data in list form with a checkbox (like you would see on an order form).

Here is the display code (there is no error checking at this point):


<head><LINK REL="SHORTCUT ICON" HREF="cmwschl.ico"></head>

<body bgcolor="#C0C0C0">

<font face="Arial" color="#000080">Books from the Selected Series</font> </h1>
<hr font color="Navy" font size="3">
<center>

<table border="1" cellpadding="5" cellspacing="0" bordercolor="#000000">
<tr>
<td width="170" bgcolor="#FFCC66"><center><b><font color="navy" size="2" face="Trebuchet MS"><b><center>Book Number</center></font></b></center></td>
<td width="140" bgcolor="#FFCC66"><center><b><font color="navy" size="2" face="Trebuchet MS"><b><center>Book Group</center></font></b></center></td>
<td width="100" bgcolor="#FFCC66"><center><b><font color="navy" size="2" face="Trebuchet MS"><b><center>Book Title</center></font></b></center></td>
</tr>

<?php
$con = mysql_connect("localhost","twilson","R00tb33r!") or die('Connection: ' . mysql_error());;
mysql_select_db("CMWWeb", $con) or die('Database: ' . mysql_error());
?>
<?
$group = $_POST['bookgrp'];

//if ($Prod <> 0) {
$sql = "SELECT * FROM `OpenBooks` WHERE `bookgrp`= '$group'";
$results = mysql_query($sql);
if ($results) { //this will check if the query failed or not
 if (mysql_num_rows($results) > 0) {  //this will check if results were returned
    while($copy = mysql_fetch_array($results)) {
       $variable1=$copy['booknum'];
$variable2=$copy['bookgrp'];
$variable3=$copy['booktitle'];
//table layout for results

print ("<tr>");
print ("<td><center>$variable1</center></td>");
print ("<td><center>$variable2</center></td>");
print ("<td><left>$variable3</left></td>");
print ("</tr>");    }
  } else {
    echo "No results returned";
  }
} else {
  echo "Query error: ".mysql_error();
}
mysql_close($con);
?>
</table>    
</center>

I have created a query to show the subject name as a drop down box now I would like to you use value to compare what module available in the database.

For now I can disaplyed all the module that is avilable for all the subject. But i would like to use the drop down box to gather which subject they have chosend then use this information to gather the module

$query=("SELECT Tes_Name FROM User u, Subject s, Test t WHERE u.Use_ID = '{$_SESSION['ID']}'
    
    AND s.Sub_ID=t.Sub_ID

");
<Html>

<?php

session_start();

$Value1 = mysql_real_escape_string(trim($_POST['myselect'])); 

$_SESSION['myselect'] = $Value1;

//echo $Value1;

include '../Database/connection.php';



?>

<body>
<form action="Previousq_Module2.php" method="post">
<?PHP


include '../Database/Module_Exsit.php';


$result=mysql_query($query) or die ("Unable to Make the Query:" . mysql_error() );
echo "<select name=select>";

while($row=mysql_fetch_array($result)){

echo "<OPTION VALUE=".$row['Tes_ID'].">".$row['Tes_Name']."</OPTION>";
}

echo "</select>";

?>

<input type="submit" value="submit"/>
</form>
</body>
</html>

I have several drop down boxes. When submit is clicked it execute query on another page. Problem is when submit is clicked selected values are return to defaults. Is it possible for the values to be remembered after submitting them? Part of the drop down code:
Code: [Select]
  <?php
            $result = mysql_query("SELECT *
 FROM product
GROUP BY Rim");
            ?>
           
  <select id="Rim" name="Rim"  selected="selected" style="width:158px;position:static;z-index:-1;">
  <option value="rim" selected="selected"><?php echo "Rim"; ?></option>

 <?php
 
 while ($row = mysql_fetch_array($result)) {
  echo "<option>" . $row['Rim']  . "</option>";
  echo "<br />";
  } ?>
 
       </select>  

Hi, I have a form for news articles.  It has a title and a body which is fine.  I also have a search box that allows the user to search for a memeber and click their name when it appears.  This moves a div with a data-id into another div.  The purpose of this is to tag them in the article.

I am able to post all of the simple stuff but how would i post these value.  I am assuming that i would need to create an array of said values but i am struggling to get them showing in post at all.

Here is the code i have so far

<?php

function searchForPeople($searchVal, $exclude = '0'){

	$sv1 = $searchVal;
	$sv2 = $searchVal;

	include 'includes/dbconn.php';
	$out ="";

	$stmt = $conn -> prepare("
	                         SELECT fname, lname, id
	                         FROM person 
	                         WHERE id NOT IN (".implode(',', array_map('intval', $exclude)).") 
	                         AND (fname LIKE CONCAT('%',?,'%') OR lname LIKE CONCAT('%',?,'%'))
	                         ");
	$stmt -> bind_param('ss', $sv1, $sv2);
	$stmt -> execute();
	$stmt -> bind_result($fn, $ln, $pid);

	while($stmt -> fetch()){
		$out .= "<div class='btn btn-primary m-1 tagInArticle' name='taggedPerson[]' data-id='$pid'>$fn $ln</div>";
	}

	return $out;
}

?>

		......
							<div id="searchResultsHere">
								<!-- ajax content here -->
							</div>
							<hr>
							<div id="taggedInArticleContainer">
								<!-- ajax content here -->
							</div>
		.......


						<div class="col-lg-2">
							<button type="submit" name="PublishNewNews" class="btn btn-primary w-100 mb-3">Publish</button>
							<button class="btn btn-primary w-100">Save</button>
							<hr>
							<div class="btn btn-warning w-100 mb-3">Private</div>
							<input type="hidden" name="howVisible" value="Private">
							<hr>
							<p class="text-justify">Private news articles will only be avilable to logged in users</p>
						</div>

		.......



<script>

	$('#searchResultsHere').on('click', '.tagInArticle', function tagInArticle(){
		var tagButton = $(this);
		tagButton.appendTo('#taggedInArticleContainer')
	});

	$('#searchForPeopleBox').keyup(function(){
		var searchVal = $(this).val()
		var tagged = '0'
		var tagged = $('#taggedInArticleContainer').find('.tagInArticle').map(function(){
		 return $(this).data('id');
  		}).get();
		$.ajax({
			type: 'post',
			data: {"ajax" : 'one', "val" : searchVal, "exclude" : tagged},
			success: function(resp){
				$('#searchResultsHere').html(resp)
			}
		})
	});

	


</script>

I hope this is enough to go on.

I am sure it is simple but i just cant get it.

Thanks all in advance.

Hi all.   how can i make the values show like a list. I tried html line break "<br>" and php \n but all to no avail. It just show all the values in one straigth line.   example of what i want is for the values to appear like this:   1234567890 0987654345 4567890675   instead of :   1234567890 0987654345 4567890675   Thanks

 
<form data-abide method="post" action="">
<div>
<select name="">
  <option value="name">
  <?php
$stmt = $pdo->query("SELECT acct_num FROM table order by id desc");
while ( $row = $stmt->fetch(PDO::FETCH_ASSOC) ) {
echo $row['acct_num'];
}
 
  ?>
</option>
</select>
</div>
<div>
    <label>New Password <small>required</small></label>
    <input type="password" name="password" id="password" required>
    <small class="error">New password is required and must be a string.</small>
</div>
<div>
    <label>Confirm New Password <small>required</small></label>
    <input type="password" name="password2" id="password2" required>
    <small class="error">Password must match.</small>
</div>
 

<input name="submit" type="submit" class="button small" value="Change Password">
</form>

Edited by Mr-Chidi, 13 November 2014 - 01:34 AM.

Hello,

I have a datepicker that when a date is selected, the post to a php file will get the sum values for that selected day, month, and year.

I have the "by day" working with this...


<?php  
$choice = (isset($_POST['choice'])) ? date("Y-m-d",strtotime($_POST['choice'])) : date("Y-m-d"); 
$con = mysql_connect("localhost","root","xxxxxxxxxx");  
if (!$con)  {  
die('Could not connect: ' . mysql_error());  
}  
mysql_select_db("inverters", $con);  
$sql = "SELECT sum(power/1000) AS choice FROM feed WHERE date = '".$choice."' group by date"; 
$res = mysql_query($sql) or die('sql='.$sql."\n".mysql_error()); 
$row = mysql_fetch_assoc($res); 
echo $row['choice'].'<br />';  
?>

But by month and year are not clicking...

Help Please

Alan

I have an audio mix submitting form on my website. The first part of the form takes the details from the user and inserts a new row in the first table 'mix', auto incrementing to generate a mix_id primary key.

The second part then uses a series of check boxes  to select which genres the mix contains and a foreach for the resulting array to insert, into the 2nd table 'genres_for_mix', a new row for each genre id (foreign key for the genres table) that is selected and the mix_id that it concerns.

Now I'm starting to think this is a bad way to do this because:

1. I don't know how to echo this out when a user edit's the mix to make all the relevant checkboxes selected.
2. When a user deselects a choice, it would be quite long winded to delete the nessesary row.


So instead I'm thinking that it would be much wiser to user the serialise functions to put the array into the database


However, I still don't know how to make the right checkboxes selected when I echo out the edit form. Do I use something like inarray()? If so how?

Also, it's really important that I can query the database for mixes that are associated with a specific genre. Without unserialising the array and therefore echo'ing out all the results, I don't know how to query this. Would I just use a 'WHERE genre_field LIKE 'genre_id'?

Can anyone help me with this please?