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PHP - Easy Question: Image Doesnt Move
Hello Everybody
I usually work with C#, but I'm doing a website right now and have a question:
I want a picture in my header and when I change the window size the image may not move.
My code so far:
#a1 {
position: relative;
top:-175px; left:0px; width:50px; height:50px;
background-image:url(http://domain.png);
background-repeat:no-repeat;}
</style>
Hope someone can answer this question easySimilar TutorialsAfter image is drop into container , I want to move copy of the original image to be move when original image dragend within container. I tried but it display copy image each time when original image dragend. can anyone help me?
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>Prototype</title>
<script type="text/javascript" src="http://code.jquery.com/jquery.min.js"></script>
<script src="http://d3lp1msu2r81bx.cloudfront.net/kjs/js/lib/kinetic-v4.7.2.min.js"></script>
<script src="http://code.jquery.com/ui/1.9.2/jquery-ui.min.js"></script>
<style>
body{padding:20px;}
#container{
border:solid 1px #ccc;
margin-top: 10px;
width:350px;
height:350px;
}
#toolbar{
width:350px;
height:35px;
border:solid 1px blue;
}
</style>
<script>
$(function(){
var $house=$("#house");
$house.hide();
var $stageContainer=$("#container");
var stageOffset=$stageContainer.offset();
var offsetX=stageOffset.left;
var offsetY=stageOffset.top;
var stage = new Kinetic.Stage({
container: 'container',
width: 350,
height: 350
});
var layer = new Kinetic.Layer();
stage.add(layer);
var image1=new Image();
image1.onload=function(){
$house.show();
}
image1.src="http://vignette1.wikia.nocookie.net/angrybirds/images/b/b6/Small.png/revision/latest?cb=20120501022157";
$house.draggable({
helper:'clone',
});
$house.data("url","house.png"); // key-value pair
$house.data("width","32"); // key-value pair
$house.data("height","33"); // key-value pair
$house.data("image",image1); // key-value pair
$stageContainer.droppable({
drop:dragDrop,
});
function dragDrop(e,ui){
var x=parseInt(ui.offset.left-offsetX);
var y=parseInt(ui.offset.top-offsetY);
var element=ui.draggable;
var data=element.data("url");
var theImage=element.data("image");
var image = new Kinetic.Image({
name:data,
x:x,
y:y,
image:theImage,
draggable: true,
dragBoundFunc: function(pos) {
return {
x: pos.x,
y: this.getAbsolutePosition().y
}
}
});
image.on("dragend", function(e) {
var points = image.getPosition();
var image1 = new Kinetic.Image({
name: data,
id: "imageantry",
x: points.x+65,
y: points.y,
image: theImage,
draggable: false
});
layer.add(image1);
layer.draw();
});
image.on('dblclick', function() {
image.remove();
layer.draw();
});
layer.add(image);
layer.draw();
}
}); // end $(function(){});
</script>
</head>
<body>
<div id="toolbar">
<img id="house" width=32 height=32 src="http://vignette1.wikia.nocookie.net/angrybirds/images/b/b6/Small.png/revision/latest?cb=20120501022157"><br>
</div>
<div id="container"></div>
</body>
</html>
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i have an easy short code to upload multiple photos to "images" directory.
after upload each file, i give it unique name.
the problem i have is:
i want see the name of uploaded files and print this using echo as in line 21.
the line 21 gives me names but not the same names of uploaded files!
thank you very much for your help.
Rafal
<?php
foreach ($_FILES['file']['name'] as $i => $name)
{
$types = array("gif", "jpeg", "jpg", "png");
$temp = explode(".", $name);
$extension = end($temp);
if ($_FILES["file"]["size"][$i] < 10240000 && in_array($extension, $types))
{
if ($_FILES["file"]["error"][$i] > 0)
{
echo "Return Code: " . $_FILES["file"]["error"][$i] . "<br>";
}
else
{
if (file_exists("images/" . $name))
{
}
else
{
move_uploaded_file($_FILES["file"]["tmp_name"][$i], "images/" . uniqid() . "." . $extension);
echo "uploaded " . $_FILES["file"] , uniqid() . "." . $extension ;
echo "<br>";
}
}
}
else
{
$error = "Invalid file";
}
}
?>
<html>
<head>
<title></title>
</head>
<body>
<form enctype="multipart/form-data" action="photo.php" method="POST">
<input type="file" name="file[]" id="file" ><br>
<input type="file" name="file[]" id="file" ><br>
<input type="file" name="file[]" id="file" ><br>
<input type="file" name="file[]" id="file" ><br>
<input type="submit" value="upload">
</form>
</body>
</html>
I am not sure whether this is an appropriate question for this forum but am hoping it might be. I have an image and intend to create a number of image maps of it so that readers can click on various parts of the image and then get a document coming up inviting them to write their thoughts about that part of the image. I am wondering whether it is possible, once they have written down their thoughts, for what they have written then to be superimposed on the image where the image map is? Thanks. How can I make the image path not have the starting slash for the $path? Currently this... Code: [Select] function getUserAvatar($username) { if (file_exists("{$GLOBALS['path']}/img/${username}.png")) { return "/assets/img/${username}.png"; } else { return "/assets/img/defaultuser.jpg"; } } When path is executed I need it to make /assets/ be assets/ I need to remove the first character from the $path variable. if ($type === 'image/png'){ imagepng($this->img, $path); } Ok I have seen many posts on this script and many people asking question on this site. The script can be found..... http://www.white-hat-web-design.co.uk/blog/resizing-images-with-php/ However I still can not make it work with what I have got. So here is the problem. First of all I upload the image and save the name to the database. I then pass its ID to the next page to retrieve the image and its path from the database. This is where the script comes in. I then run the image through the script and send you to the success page. Now the image is not being resized! The code is not erroring (even with error reporting on). It would seem the code it just get ignored completely. The image is still there and displays how it was uploaded but the size just hasnt changed. Im asuming Im using it in the correct way. Here is the code after the image has been uploaded. $Fetchq = mysql_query("SELECT * FROM images WHERE imageID ='".$_GET['image']."' ") or die('error stuff here'); $fetched = mysql_fetch_array($Fetchq); $path = "/members/images/members/merseyside/{$fetched['imagename']}"; include('SimpleImage.php'); $image = new SimpleImage(); $image->load('$path'); $image->resize(60,60); $image->save('$path'); $url = "/activity-photos.php?uploaded=true"; header("Location: $url"); Any help would be greatly appreciated as I've had enough of banging my head against this code wall OK, I think this is easy, but I just can't seam to get it figured out. I have this piece of code echo '<img src="maps/' . $map . '.jpg" />'; And what I want to do is if that $map is not in the directory I want it to display a standard image that I know is in the directory. So basically I want the alt tag to be a image instead of text. |
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