PHP - How To Get An Null Echo Reslut
cant figure out how to get this script to post a message if no results are found. please help to new at this.
Similar TutorialsI am trying to update the database with isset to set the value of the variable to either null or the value entered by the user. Currently, if no value has been entered null is being set as a string causing the date field to populate with zeros. How do I code it so that it populates or sets the value as null and not as string null?
Here's my code: (yes I know sql injections it's still in development )
<?php OK, have no idea what's going on... I've done this a million times... why wont this output!?? I must have a major brain meltdown and dont know it yet!!! Code: [Select] <?php // this echoes just fine: echo $_POST['testfield']; // but this wont echo: echo if (isset($_POST['testfield'])) { $_POST['testfield'] = $test; } echo $test; /// or even this DOESNT echo either!: $_POST['testfield'] = $test; echo $test; ?> Hi All, I'm trying to echo the response from an SLA query, the query works and returns the data when I test it on an SQL application.. but when I run it on my webpage it won't echo the result. Please help? <?php $mysqli = mysqli_connect("removed", "removed", "removed", "removed"); $sql = "SELECT posts.message FROM posts INNER JOIN threads ON posts.pid=threads.firstpost WHERE threads.firstpost='1'"; $result = mysqli_query($mysqli, $sql); echo {$result['message']}; ?> I have a log system that allows 10 logs on each side(Left and right). I am trying to make it so that the left side has the 10 most recent logs, then the right as the next 10. Any ideas? So I need to echo a row from my database with php, but where i need to echo is already inside an echo. This is my part of my code: $con = mysql_connect("$host","$username","$password"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("main", $con); $result = mysql_query("SELECT * FROM Vendor"); while($row = mysql_fetch_array($result)) { //I need to echo right here .................. but I get a blank page when I try this. Please Help. echo '<option value=$row['vendor_id']>'; echo $row['vendor_id']; echo '</option>'; } mysql_close($con); Result: A Blank page. Thanks in advance! Hi
I try to echo out random lines of a html file and want after submit password to whole content of the same html file. I have two Problems.
1st Problem When I echo out the random lines of the html file I don't get just the text but the code of the html file as well. I don't want that. I just want the text. How to do that?
for($x = 1;$x<=40;$x++) { $lines = file("$filename.html"); echo $lines[rand(0, count($lines)-1)]."<br>"; }I tried instead of "file("$filename.html");" "readfile("$filename.html");" But then I get the random lines plus the whole content. Is there anything else I can use instead of file so that I get the random lines of text without the html code?P.S file_get_contents doesn't work either have tried that one. 2nd Problem: As you could see in my first problem I have a file called $filename.html. After I submit the value of a password I want the whole content. But it is like the program did forget what $filename.html is. How can I make the program remember what $filename.html is? Or with other words how to get the whole content of the html file? My code: if($_POST['submitPasswordIT']){ if ($_POST['passIT']== $password ){ $my_file = file_get_contents("$filename.html"); echo $my_file; } else{ echo "You entered wrong password"; } }If the password isn't correct I get: You entered wrong password. If the password is correct I get nothing. I probably need to create a path to the file "$filename.html", but I don't know exactly how to do that. Hello All, I tried searching here and google, but couldn't figure it out on my own... still Bellow is my code, I need some help figuring out how to tell PHP that "If picture is NULL, don't try to display it." Basically I have a dynamic news system set up. Some stories have pictures, some do not. I need PHP to not display the code for showing the picture if the picture value = NULL. Any help would be appreciated! <?php include ("../../includes/connections/newsconnection.php"); $id=$_GET['id']; //declare the SQL statement that will query the database $query = " SELECT * FROM news WHERE id='$id' "; //execute the SQL query and return records $result = mssql_query($query); //display the results //id, school, date, link, title, story, picture while($row = mssql_fetch_array($result)) { echo "<span class='bodyb'>"; echo $row["title"]; echo "</span>"; echo "<br /><i>"; echo date('l, F j, Y', strtotime($row['date'])); echo "</i>"; echo "<br /><br />"; //heres where I need to stop if picture is null echo "<img src='../../images/news/"; echo $row["picture"]; echo "' align='left' class='imgspacer-left'>"; echo fixQuotes($row["story"]); } //close the connection mssql_close($dbhandle); ?> I'm trying to force a NULL value into the database with a hidden value and I can't seem to get it to work. Any suggestions? <input type="hidden" name="inactive" value=""/> I also tried here too: $sql="UPDATE product SET inactive='NULL' WHERE id = '$item_id'"; Hi... i have table EMP_NO LOGIN - DATETIME, NULL LOGOUT - DATETIME, NULL I have this query: Code: [Select] <?php include 'config.php'; $currentEmpID = $_SESSION['empID']; if(!isset($_POST['submit_'])){ $DATE1 = $_POST['firstinput']; $DATE2 = $_POST['secondinput']; $sql = "SELECT EMP_NO, LOGIN, LOGOUT FROM employee_attendance WHERE DATE(LOGIN) BETWEEN '$DATE1' AND '$DATE2'"; $attendance = $conn3->GetAll($sql); $smarty->assign('attendance', $attendance); } $smarty->display('header_att.tpl'); $smarty->display('empAttendance.tpl'); $smarty->display('footer.tpl'); ?> My problem is I have data EMP_NO 00000223 LOGIN NULL LGOUT NULL this data was not displayed because it has a null value.. i want it to displayed also and highlight it because it has a value null.. Thank you Can someone help me to get this code working... Code: [Select] public function getBowlContents(){ if is_null($this->contents) { return "The bowl is empty!"; } else { return "The bowl contains " . $this->contents . " soup!"; } TomTees My code; $sql = "SELECT SUM(IF(`submitdate` IS NULL , 1 , 0 )) as 'Survey Started But Not Completed' FROM `survey_$surveyid`"; $statement = $dbh->prepare($sql); $statement->execute(); $result = $statement->fetch(PDO::FETCH_OBJ); //pass that data to an objectIs returning; stdClass Object ( [Survey Started But Not Completed] => ) I need to set this to a vaule that I can actually print out on the screen... Like a "0" for example. At the moment it is just a NULL. How do I do this?? These don't work; $result = 0; $result = array(['Survey Started But Not Completed'] => "0"); 2 PART QUESTION (so I don't have to ask two questions 😀 )
1.)
2.) On my particular coding, I can use either the NULL/isset style, or, the ""/== style, with no errors or ill effects.... but something tells me the expert PHP coders prefer one over the other... Thank you!! Edited July 10 by ChenXiuI have a php page where user/db info is being passed: <?php include "include/dbc.php"; include "include/header.inc"; $exerciseid = $_POST["exerciseid"]; $duration = $_POST["duration"]; $distance = $_POST["distance"]; $metric = $_POST["metric"]; echo'<h1>Added Activities</h1>'; // name of array echo '<h1>Exercise</h1>'; if (is_array($exerciseid)) { foreach ($exerciseid as $key => $value) { echo $key .' : '. $value .'<br />'; } } // name of array echo '<h1>Duration</h1>'; if (is_array($duration)) { foreach ($duration as $key => $value) { echo $key .' : '. $value .'<br />'; } } // name of array echo '<h1>Distance</h1>'; if (is_array($distance)) { foreach ($distance as $key => $value) { echo $key .' : '. $value .'<br />'; } } // name of array echo '<h1>Metric</h1>'; if (is_array($metric)) { foreach ($metric as $key => $value) { echo $key .' : '. $value .'<br />'; } } ?> And here is the output from that code: Added Activities Exercise 0 : Canoeing, on camping trip 1 : Canoeing, rowing, over 6 mph, vigorous effort 2 : Canoeing, rowing, crewing, competition 3 : Canoeing, rowing, light effort 4 : Canoeing, rowing, moderate effort 5 : Diving, springboard or platform 6 : Kayaking 7 : Sailing, boat/board, windsurfing, general 8 : Sailing, in competition 9 : Skiing, water 10 : Ski-mobiling, water 11 : Skin diving, scuba diving, general 12 : Snorkeling 13 : Surfing, body or board 14 : Swimming laps, freestyle, fast, vigorous effort 15 : Swimming laps, freestyle, light/moderate effort 16 : Swimming, backstroke, general 17 : Swimming, breaststroke, general 18 : Swimming, butterfly, general 19 : Swimming, leisurely, general 20 : Swimming, sidestroke, general 21 : Swimming, sychronized 22 : Swimming, treading water, fast/vigorous 23 : Swimming, treading water, moderate effort 24 : Water polo 25 : Water volleyball 26 : Whitewater rafting, kayaking, or canoeing Duration Canoeing, on camping trip : 20 Canoeing, rowing, over 6 mph, vigorous effort : Canoeing, rowing, crewing, competition : Canoeing, rowing, light effort : Canoeing, rowing, moderate effort : Diving, springboard or platform : Kayaking : Sailing, boat/board, windsurfing, general : Sailing, in competition : Skiing, water : Ski-mobiling, water : Skin diving, scuba diving, general : Snorkeling : Surfing, body or board : Swimming laps, freestyle, fast, vigorous effort : Swimming laps, freestyle, light/moderate effort : Swimming, backstroke, general : Swimming, breaststroke, general : Swimming, butterfly, general : Swimming, leisurely, general : Swimming, sidestroke, general : Swimming, sychronized : Swimming, treading water, fast/vigorous : Swimming, treading water, moderate effort : Water polo : Water volleyball : Whitewater rafting, kayaking, or canoeing : Distance Canoeing, on camping trip : 20 Canoeing, rowing, over 6 mph, vigorous effort : Canoeing, rowing, crewing, competition : Canoeing, rowing, light effort : Canoeing, rowing, moderate effort : Diving, springboard or platform : Kayaking : Sailing, boat/board, windsurfing, general : Sailing, in competition : Skiing, water : Ski-mobiling, water : Skin diving, scuba diving, general : Snorkeling : Surfing, body or board : Swimming laps, freestyle, fast, vigorous effort : Swimming laps, freestyle, light/moderate effort : Swimming, backstroke, general : Swimming, breaststroke, general : Swimming, butterfly, general : Swimming, leisurely, general : Swimming, sidestroke, general : Swimming, sychronized : Swimming, treading water, fast/vigorous : Swimming, treading water, moderate effort : Water polo : Water volleyball : Whitewater rafting, kayaking, or canoeing : Metric 0 : mile 1 : mile 2 : mile 3 : mile 4 : mile 5 : mile 6 : mile 7 : mile 8 : mile 9 : mile 10 : mile 11 : mile 12 : mile 13 : mile 14 : mile 15 : mile 16 : mile 17 : mile 18 : mile 19 : mile 20 : mile 21 : mile 22 : mile 23 : mile 24 : mile 25 : mile 26 : mile As you can see, null values are being passed as well. I am hoping that someone can show me the correct way to use php unset to get rid of these null values. Thank you. hi all, i have a script in where the user enters there post code and it will provide a price for delivery, how would i echo "please contact us for price" if the db record for the price is (null) or empty?? <?php mysql_connect ("localhost", "root","password") or die (mysql_error()); mysql_select_db ("postcode"); $term = $_POST['term']; $sql = mysql_query("SELECT * FROM uk_postcodes, zones WHERE postcode LIKE '%$term%' AND zone_id = zone_large "); while ($row = mysql_fetch_array($sql)){ echo '<br/> Postcode: '.$row['postcode']; echo '<br/> Town: '.$row['town']; echo '<br/> County: '.$row['county']; echo '<br/> Small: £'.$row['price_s']; echo '<br/> Medium: £'.$row['price_m']; echo '<br/> Large: £'.$row['price_l']; echo '<br/><br/>'; } ?> I have a for loop that I am looping through. When I use var_dump() I get 10 results (which is what I should be getting). However, when I loop through it using a for() loop I am getting an extra 11th value that is blank. What would be causing this? My code is below: Code: [Select] $legacy = new Legacy(); // Loop through each film in the shopping cart for ($i = 0; $i < $myShoppingCartInfo['row_count']; $i++) { // Determine if the film is of a legacy series if ($legacy->isLegacyCheckout($myShoppingCartInfo['data']['PRODUCTSKUID'][$i])) { // Declare array to hold all legacy film entity_id values $legacyEntityIds = array(); $legacyEntityIds = $legacy->getLegacyEntityIds($myShoppingCartInfo['data']['PRODUCTSKUID'][$i]); var_dump($legacyEntityIds); // Loop through all legacy video entity_id's for ($i = 0; $i < $legacyEntityIds['data']['ENTITY_ID']; $i++) { // Grant streaming access to each entity id echo $legacyEntityIds['data']['ENTITY_ID'][$i] . '<br />'; // Insert the product into the order items table /*$query = "INSERT INTO tblOrderItems (OrderItemID, ProductSKUID, RentalDate, OrderID) VALUES (##newID##, '".$myShoppingCartInfo['data']['PRODUCTSKUID'][$i]."', ".($myShoppingCartInfo['data']['RENTALDATE'][$i] === NULL ? 'NULL' : "'".$myShoppingCartInfo['data']['RENTALDATE'][$i]."'").", ".$newOrderID.")"; $cartItemInserted = counter_id_insert($query,'OrderItemID'); $curr_user->addNewEntityLicense($legacyEntityIds['data']['ENTITY_ID'][$i]);*/ } } When I view the source code of the output page in a browser, this is what I see: array(5) { ["row_count"]=> int(10) ["col_count"]=> int(1) ["col_names"]=> array(1) { => string(9) "entity_id" } ["col_types"]=> array(1) { => string(3) "int" } ["data"]=> array(1) { ["ENTITY_ID"]=> array(10) { => string(7) "1681799" [1]=> string(7) "1681872" [2]=> string(7) "1681871" [3]=> string(7) "1681870" [4]=> string(7) "1681869" [5]=> string(7) "1681868" [6]=> string(7) "1681867" [7]=> string(7) "1681866" [8]=> string(7) "1681865" [9]=> string(7) "1681864" } } } 1681799<br />1681872<br />1681871<br />1681870<br />1681869<br />1681868<br />1681867<br />1681866<br />1681865<br />1681864<br /><br /> I'm trying to display the null values only, where am I going wrong?
SELECT IFNULL(trans, 0) AS 'Transactions', customer.cID AS 'Customer ID', customer.surname AS 'Surname' FROM customer LEFT JOIN account ON (account.cID = customer.cID) WHERE IFNULL(trans, 0); How can I change Yes to No for the NULL field in the mysql db structure. E.g. (Table name: address and Column name : state) <?php $link = mysql_connect("localhost","db","pw"); mysql_select_db("db"); mysql_query("alter table address modify state null NO); $result = mysql_query($query); $sent = "Edit Successful."; echo ($sent); ?> I have an array which can be empty; in this case, I get error. I want to skip when the array is empty. When calling the array from file, I use the following code if (file_exists($array_file)) { "the doing code" } else { echo "File does not exist"; } How I should use this If Else condition when array comes from a string like $test_array = explode(', ', $examplestring, -1); Hello
I am having an issue with encoding an array to JSON, my array seems to be formed correctly but when I try and echo the json_encode version I get "null". I echo the JSON error code and it is "0" indicating no issue..
I have read that non UTF-8 characters can be an issue, but this is simple data, no strange characters... but I added the utf8_encode anyway....
Here is my code:
$dataArray = array( 'title' => 'Test Item', 'icon_url' => 'http://url/api/testimage.jpg', 'item_id' => '12345', 'expiration' => 600 ); utf8_encode($dataArray); $responsArray = array( 'success' => '1', 'data' => $dataArray ); utf8_encode($responsArray); header('Content-type: application/json'); echo print_r($responsArray); echo json_encode ($responseArray); echo json_last_error(); I have a column in my MySQL database "paid". I have values of p for PayPal, c for check, and f for free. Those who haven't paid the record is marked (NULL). Right now my code is: if ($line['paid'] == 'y') { echo '.</center></td>';} else { echo '</center></td>';} That works pretty well for when I was just using those who paid vs. those who didn't. However, I'm wanting my site to show who has paid vs. those who haven't, while my data table will easily show how they paid. I either need an array or I need to reverse the IF...ELSE to say IF it's NULL do nothing, ELSE mark paid. |