PHP - Lots Of Questions, Need Help
Hey guys! im currently learning javascript, PHP and SQL. I have a pretty solid understanding of HTML and CSS. I want to make a site similar to facebook (a good facebook). this is going to be a big project and i plan on moving to a bigger server system in a year or so to keep up with demands.
Heres how the site will function:
1. Basic registration/splash page. I understand that the finished form is sent to a php file on the server side, correct? (ill change my server name files of course)
2. after the registration page, while the user is logged in with their new account, there are 3 pages after that that explain what the website is all about and how to use it. the last page allows the user to setup their profile information, ask friends to join, and asks what type of things they like. After the last page, it sends the user to their main control panel, where social media feed can be seen, friends and online chats, news, advertisements, links, pages and groups (think facebook and linkedin)
3. the user will have the ability to look at their profile (not the control panel), and of course switch back to their control panel. social media, friends, groups and ads will also be on their individual profile page as well.
4. i want the site to have two views: a standard view and an enhanced view. the enhanced view will reposition divs and all that stuff so they can see a background image (either stock or one they uploaded) this image will eventually change to an animated image of a 3d environment.
5. the site is going to be heavily social media based. This means social media feeds, image uploading, a structured comment system, a friend system, search functions and targeted advertising.
This is obviously a lot to ask, but since their is so much to learn related to PHP and SQL, can someone point me to the right tutorials on how to get these things done? I am currently learning javascript, PHP and SQL on lynda.com. Expect me to be on this forum a lot and asking a lot of questions. Thanks for any help.
Edited by PHPlearner32, 10 January 2015 - 11:19 PM. Similar TutorialsI am trying to get more than one row from a database at once, then explode each value into a seperate variable. is there a way of doing this? First, I gotta say I am new to JavaScript, but not new to languages like PHP/C++.
I am working on a large huge JS file that has a lot of things and I have a feeling that it can be made better. How is where I am at a loss. If it was PHP, I'd split that JS file into probably 20 other smaller JS files, aka "classes", and it may or may not be the right thing to do, but let me focus on one particular aspect for now, and maybe deal with others later.
Here is the piece of code that bugs the me most (truncated for clarity):
if (selection[index].selected) { result += '<TABLE class="list_grey" style="float: left; margin-left: 20px;">'; result += '<TR>'; result += '<TH colspan="2">Data</TH>'; result += '</TR>'; var flag = "All"; if (selection[index].flag == 'P') flag = "Premium"; result += '<TR>'; result += '<TD>Flag</TD>'; result += '<TD>' + flag + '</TD>'; result += '</TR>'; result += '</TABLE>'; } else { result += '<TABLE class="list_grey" style="float: left; margin-left: 20px;">'; result += '<TR>'; result += '<TH colspan="2">Frame</TH>'; result += '</TR>'; result += '<TR>'; result += '<TD>Frame</TD>'; result += '<TD>' + selection[index].frame + '</TD>'; result += '</TR>'; result += '</TABLE>'; }So what it does is this: 1. it gets "selection" var with eval() from a DIV block of HTML page, where that DIV has a looooong prepared-by-PHP JSON string with all the options prepopulated from various sources accessible to PHP. var selection = eval("(" + document.getElementById("result").innerHTML + ")");2. It then dynamically constructs and populates further HTML using logic and data found in "selection" var. 3. This particular JS implements a selection algorithm, where basically user clicking buttons can navigate "selection" var forwards and backwards, and as user does, the dynamic portion of HTML updates per behavior defined in the JS file. My Problem / Question: I have a feeling that putting HTML the way it is done here in JS file is not proper separation of concerns and not good way to code. HTML should be. .. in HTML, when possible, but being new to JS I don't know if there is a better way. Is there a more recommended way to code what I have now ? hi, I am building a web app and need all my php on one page and links posting to same page etc, at the moment, I am linking to my townpubs.php page see code below: townpubs.php Code: [Select] <!doctype html> <?php include "../config.php"; $loggedIn = (isset($_COOKIE['loggedin']) && $_COOKIE['loggedin'] == 'true')?true:false; $town = $_REQUEST['RSTOWN']; $towns = mysql_query("SELECT * FROM pubs WHERE RSTOWN = '".$town."' ORDER BY RSTOWN ASC"); ?> <html> <head> <meta charset="UTF-8" /> <title>My Pub Space v1.0 β</title> <style type="text/css" media="screen">@import "jqtouch/jqtouch.min.css";</style> <style type="text/css" media="screen">@import "themes/jqt/theme.min.css";</style> <script src="jqtouch/jquery.1.3.2.min.js" type="text/javascript" charset="utf-8"></script> <script src="jqtouch/jqtouch.min.js" type="application/x-javascript" charset="utf-8"></script> <script type="text/javascript" charset="utf-8"> var jQT = new $.jQTouch({ icon: 'jqtouch.png', addGlossToIcon: false, startupScreen: 'jqt_startup.png', statusBar: 'black', preloadImages: [ 'themes/jqt/img/back_button.png', 'themes/jqt/img/back_button_clicked.png', 'themes/jqt/img/button_clicked.png', 'themes/jqt/img/grayButton.png', 'themes/jqt/img/whiteButton.png', 'themes/jqt/img/loading.gif' ] }); </script> </head> <body> <!-- TOWNS --> <div id="towns" class="current"> <div class="toolbar"> <h1>View Pubs</h1> <a class="back" href="index.php" rel="external">Home</a> </div> <h2>Pubs in <?php echo $town ?></h2> <ul class="plastic"> <?php while($row1 = mysql_fetch_array($towns)) { echo '<li class="arrow"><a href="pubinfo.php?PUBID='.$row1['PUBID'].'" rel="external">'.$row1['rsPubName'].'</a></li>'; } ?> </ul> </div> </body> </html> I would like to have this on my index.php page: index.php Code: [Select] <!doctype html> <?php include "../config.php"; $loggedIn = (isset($_COOKIE['loggedin']) && $_COOKIE['loggedin'] == 'true')?true:false; $query1 = "SELECT DISTINCT rsTown FROM pubs ORDER BY rsTown asc"; $result = mysql_query($query1); $towns = mysql_query("SELECT DISTINCT RSTOWN, COUNT(PUBID) As PubCount FROM pubs GROUP BY RSTOWN ORDER BY RSTOWN ASC"); $counties = mysql_query("SELECT DISTINCT RSCOUNTY, COUNT(PUBID) As PubCount1 FROM pubs GROUP BY RSCOUNTY ORDER BY RSCOUNTY ASC"); if ($loggedin == 'true'){ $locals = mysql_query("SELECT * FROM pubs INNER JOIN favepub_copy ON pubs.PUBID=favepub_copy.PUBID WHERE USERID='".$_SESSION['USERID']."' ORDER BY rsPubName asc"); } ?> <html> <head> <meta charset="UTF-8" /> <title>My Pub Space v1.0 β</title> <style type="text/css" media="screen">@import "jqtouch/jqtouch.min.css";</style> <style type="text/css" media="screen">@import "themes/jqt/theme.min.css";</style> <script src="jqtouch/jquery.1.3.2.min.js" type="text/javascript" charset="utf-8"></script> <script src="jqtouch/jqtouch.min.js" type="application/x-javascript" charset="utf-8"></script> <script type="text/javascript" charset="utf-8"> var jQT = new $.jQTouch({ icon: 'jqtouch.png', addGlossToIcon: false, startupScreen: 'jqt_startup.png', statusBar: 'black', preloadImages: [ 'themes/jqt/img/back_button.png', 'themes/jqt/img/back_button_clicked.png', 'themes/jqt/img/button_clicked.png', 'themes/jqt/img/grayButton.png', 'themes/jqt/img/whiteButton.png', 'themes/jqt/img/loading.gif' ] }); </script> </head> <body> <div id="about" class="selectable"> <p><img src="jqtouch.png" /></p> <p><strong>My Pub Space</strong><br />Version 1.0 beta<br /> <a href="http://www.jbiddulph.com" target="_blank">By John Biddulph</a></p> <p><em>Mobile Web Development</em></p> <p><a href="mailto:john.mbiddulph@gmail.com" target="_blank">E-mail</a></p> <p><a href="http://twitter.com/#!/jmbiddulph" target="_blank">@jmbiddulph on Twitter</a></p> <p><br /><br /><a href="#" class="grayButton goback">Close</a></p> </div> <div id="home" class="current"> <?php if (!$loggedIn){ ?> <div class="toolbar"> <h1>My Pub Space</h1> <a href="#about" id="infoButton" class="button slideup">About</a> </div> <ul class="rounded"> <li class="forward"><a href="#signup">Register an account</a></li> <li class="forward"><a href="#login">Login</a></li> <li class="forward"><a href="#towns">View pubs by town</a></li> <li class="forward"><a href="#counties">View pubs by county</a></li> </ul> <div class="info"> <p>All Rights Reserved © 2011 mypubspace.com Created by: jbiddulph.com</p> </div> <?php } else { ?> <div class="toolbar"> <h1>Hi <?php echo $_SESSION['s_username'];?></h1> <a href="dologoff.php" rel="external" class="button">Logout</a> </div> <ul class="rounded"> <li class="forward"><a href="#locals">View Locals</a></li> <li class="forward"><a href="#towns">View Towns</a></li> <li class="forward"><a href="#counties">View Counties</a></li> </ul> <div class="info"> <p>All Rights Reserved © 2011 mypubspace.com Created by: jbiddulph.com</p> </div> <?php } ?> </div> <!-- LOCALS --> <div id="locals"> <div class="toolbar"> <h1>My Locals</h1> <a class="back" href="#home">Back</a> </div> <ul class="plastic"> <?php while($row1 = mysql_fetch_array($locals)) { echo '<li class="arrow"><a href="pubinfo.php?PUBID='.$row1['PUBID'].'" rel="external">'.$row1['rsPubName'].', '.$row1['rsTown'].'</a></li>'; } ?> </ul> </div> <!-- TOWNS --> <div id="towns"> <div class="toolbar"> <h1>View Towns</h1> <a class="back" href="#home">Back</a> </div> <ul class="edgetoedge"> <?php $ltr = ''; while($row1 = mysql_fetch_array($towns)) { $letter1 = substr($row1['RSTOWN'],0,1); if ($letter1 != $ltr) { print'<li class="sep">'. $letter1 .'</li>'; } $ltr = $letter1; echo '<li class="forward"><a href="townpubs.php?RSTOWN='.$row1['RSTOWN'].'" rel="external">'.$row1['RSTOWN'].'<small class="listcounter">'.$row1['PubCount'].'</small></a></li>'; } ?> </ul> </div> <!-- COUNTIES --> <div id="counties"> <div class="toolbar"> <h1>View Counties</h1> <a class="back" href="#home">Back</a> </div> <ul class="edgetoedge"> <?php $ltr = ''; while($row1 = mysql_fetch_array($counties)) { $letter1 = substr($row1['RSCOUNTY'],0,1); if ($letter1 != $ltr) { print'<li class="sep">'. $letter1 .'</li>'; } $ltr = $letter1; echo '<li class="forward"><a href="countypubs.php?RSCOUNTY='.$row1['RSCOUNTY'].'" rel="external">'.$row1['RSCOUNTY'].'<small class="listcounter">'.$row1['PubCount1'].'</small></a></li>'; } ?> </ul> </div> <form id="login" action="dologin.php" method="POST" class="form"> <div class="toolbar"> <h1>Login</h1> <a class="back" href="#">Back</a> </div> <ul class="rounded"> <li><input type="text" name="rsUser" value="" placeholder="Username" /></li> <li><input type="Password" name="rsPass" value="" placeholder="Password" /></li> </ul> <a style="margin:0 10px;color:rgba(0,0,0,.9)" href="#" class="submit whiteButton">Submit</a> </form> <form id="signup" action="dosignup.php" method="POST" class="form"> <div class="toolbar"> <h1>Sign up</h1> <a class="back" href="#">Back</a> </div> <ul class="rounded"> <li><select name="RSTOWN" class="postcodedrop"> <option value="">Choose your Town...</option> <?PHP while($row = mysql_fetch_array($result)) { echo '<option value="'.$row['rsTown'].'">'; echo $row['rsTown']; echo '</option>'; }?> </select></li> <li><input name="RSUSER" type="text" class="textbox" id="RSUSER" value="" placeholder="Username" /></li> <li><input type="Password" name="RSPASS" value="" placeholder="Password" /></li> <li>Male <input name="RSGENDER" type="radio" value="Male" /> Female <input name="rsGender" type="radio" value="Female" /></li> <li><input name="RSEMAIL" type="text" class="textbox" id="rsEmail" placeholder="Email" /></li> <li><input name="RSMOBILE" type="text" class="textbox" id="rsMobile" placeholder="Mobile No." /></li> <li><input name="RSAGE" type="text" class="textbox" id="datepicker" placeholder="DOB: dd/mm/yyyy" /></li> </ul> <a style="margin:0 10px;color:rgba(0,0,0,.9)" href="#" class="submit whiteButton">Submit</a> </form> </body> </html> I need to set empty variables at the top and link page to itself?! Hey guys, I'm having a strange problem with cURL that I'm drawing an absolute blank to. It works completely fine locally, but when I upload the files to my webhost and test it over there, it doesn't work at all - it loads for about 2 minutes, and then displays: Server error. The website encountered an error while retrieving http://www.craigwatcher.me/playground/units.php. It may be down for maintenance or configured incorrectly. I've checked the error logs but nothing new is being added into there. Basically I'm just iterating through a list of URLs and cURLing each of them. Let me show you the code that I'm working with: ini_set('max_execution_time',0); require_once('../system/utilities.php'); // This will give us our getLocations() function, which has been tested to work 100% both locally and online $categories = array('jjj', 'ggg', 'bbb', 'sss', 'hhh'); $locations = getLocations(); if (!$locations) exit; $ch = curl_init(); curl_setopt($ch, CURLOPT_RETURNTRANSFER, TRUE); curl_setopt($ch, CURLOPT_FOLLOWLOCATION, TRUE); curl_setopt($ch, CURLOPT_TIMEOUT, 10); foreach ($locations as $country => $cities) { $countryCode = getCountryCode($country); foreach ($cities as $city) { foreach ($categories as $category) { $url=$city.'.en.craigslist.'.$countryCode.'/'.$category.'/index.rss'; echo $url.'<br/>'; curl_setopt($ch, CURLOPT_URL, $url); $rss = curl_exec($ch); if (!$rss) echo ' FAILED to load: '.$url.'<br/>'; } } } curl_close($ch); I've already tested everything else (eg. the getLocations() and getCountryCode(), and they prove to work 100% fine both locally and online. What could it POSSIBLY be!? I'm pulling my hair out over here, my mind is boggling and I'm completely lost at what could possibly be going wrong. Hi there, I'm creating a shopping cart and to work out postage cost I need to add all the items weights together. The weight of each item is in the database. I currently have this code: Code: [Select] $basket = $_SESSION['basket']; if ($basket) { $items = explode(',',$basket); $contents = array(); foreach ($items as $item) { $contents[$item] = (isset($contents[$item])) ? $contents[$item] + 1 : 1; } foreach ($contents as $id=>$qty) { $sql = "SELECT * FROM store WHERE id LIKE '$id' AND live LIKE '0'"; $result = mysql_query($sql); while ($rows = mysql_fetch_array($result)) { extract($row); so to work out each item's weight I can do $rows['weight'] * $qty. but how could i add all the item's weight together? i hope that makes some sense. thanks, jack Hi i followed a guid to create a login area to my site however i believe its a little outdated and therefore not working, i have done a little bit but being quite new i cannot find all the problems at the moment i have: Parse error: syntax error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING or T_VARIABLE or T_NUM_STRING in /home/a9855336/public_html/checklogin.php on line 12 here is my script line 12 is marked <?php $host="*************"; // Host name $username="a9855**6_root"; // Mysql username $password="************"; // Mysql password $db_name="****3***36_mail; // Database name // Connect to server and select databse. mysql_connect($host, $username, $password) mysql_select_db($db_name); // username and password sent from form $myusername=$_POST['myusername']; // line 12 $mypassword=$_POST['mypassword']; // To protect MySQL injection (more detail about MySQL injection) $myusername = stripslashes($myusername); $mypassword = stripslashes($mypassword); $myusername = mysql_real_escape_string($myusername); $mypassword = mysql_real_escape_string($mypassword); // encrypt password $encrypted_mypassword=md5($mypassword); $sql="SELECT * FROM $tbl_name WHERE username='$myusername' and password='$encrypted_mypassword'"; $result=mysql_query($sql); // Mysql_num_row is counting table row $count=mysql_num_rows($result); // If result matched $myusername and $mypassword, table row must be 1 row if($count==1){ // Register $myusername, $mypassword and redirect to file "login_success.php" session_register("myusername"); session_register("mypassword"); header("location:login_success.php"); } else { echo "Wrong Username or Password"; } ?> if you help please tell me the error so i can learn to debug scripts myself in the future thanks blink359 My site seems to be going well, but on the back end, the users database is going crazy with duplicate entrys. but its not doing it from an INSERT. it seems to be doing it with this code: Code: [Select] $bitquery = $bitcoin->move("bittleship$username", "bittleships", $cost, $minconfirmations); if ($bitquery == true){ $query = mysql_query("INSERT INTO `transactions` ( `id` , `username` , `type` , `amount`, `address`) VALUES ('', '$username', 'buyclicks', '$cost', '')") or die(mysql_error()); $query = mysql_query("UPDATE users SET `clicks` = `clicks`+$quantity, `balance`=`balance`-$cost WHERE `username` = '$username' ") or die(mysql_error()); include('update.php'); We have a database that shows for example: 2500-5000 5000-10000 10000-15000 15000-20000 I need to show in a screen what people are have 3000 followers, and as such as grouped into that 2500-5000. The best way I can see how to do this, is to run through the database table for these values. Then for each value, put the first and second set of numbers into two respective variables, say $low, $high. Then find those people who are on a particular platform with followers between those two values. So how do I turn $row->followsrange (which might be for example: "2500-5000"), into:
$low = 2500 Many thanks. ps I have a feeling the hyphen might play a bit part, as it cannot be done by the amount of characters.......... Hi, in Mysql have a row with FLOAT 10,2 In form put the number 20.20 and after reload in form show: 20.200000762939 I am having a problem I have encounted like no other. I am running a MySQL query from PHP and for some bizarre reason, its just not working... Ok, that sounds really general. lol To start off, here is my database: http://i56.tinypic.com/2hh0up1.png I am writing my own user interface with HTML/PHP/MySQL for every day catalog management: http://i54.tinypic.com/axxsb7.png To catalog a product is done from here (this page works): http://i51.tinypic.com/2e0qs7s.png ETC ... <FORM action="result.html" enctype="multipart/form-data" method="post"> ... ETC ETC ... Name: <INPUT name="name" type="text"> <BR> Brand: <INPUT name="brand" type="text"> <BR> Country of origin: <INPUT name="country" type="text"> <BR> Material: <INPUT name="material" type="text"> <BR> Primary colour: <INPUT name="primarycolour" type="text"> ... ETC result.html: ETC ... $query = "INSERT INTO products(name, brand, country, material, primarycolour) VALUES('".$_POST['name']."', '".$_POST['brand']."', '".$_POST['country']."', '".$_POST['material']."', '".$_POST['primarycolour']."')"; ... ETC To alter a product, you enter in a product ID: http://i56.tinypic.com/2lcsqch.png Code: [Select] <FORM action="dataentry.html" method="post"> <DIV class="drop">Alter product ID: <INPUT name="id" type="text">    <INPUT type="submit" value="Submit"></DIV> The data entry page pulls all the values from the MySQL database and populates them into the INPUT fields, so the user does not have to write them all again: http://i56.tinypic.com/2zh0hgn.png ... ETC echo '<FORM action="result.html" enctype="multipart/form-data" method="post">'; ETC ... ... ETC echo 'Name:'; $query = "select name from products where id=".$_POST['id'].""; $result = mysql_query($query); $row = mysql_fetch_array($result); echo ' <INPUT name="name" type="text" value="'.$row['name'].'">'; echo $query; ETC ... I will now change the value of "Name" from 'a' to 'c' and submit the changes: http://i55.tinypic.com/dzi9hc.png http://i54.tinypic.com/ab5lyg.png Now, you would think the result has been inserted into my database yeah? It failed... but when I enter the same command directly into MySQL. Success! http://i51.tinypic.com/29z5y5x.png Why the F is this happening?! Hi there im not quite sure how to do something and was wondering if anyone can help me, I am going to create a large database with lots of fields and these are going to be displayed on a page i want to limit it to 20 per page and be able to sort them aswell by ID (default) and then a-z or z-a, i dont know how to do this and i also need to know how to create the next previous and last and first links im guessing theres a count++ involved ? im not quite sure but anyway if someone can help it will be great. Thanks, Blink359 Howdy, I am new to SEO. Could you please help me? 1. I like to post programming tutorials to both my website & various programming forums. Is that going to screw up my website's ranking in Google? 2. My editor of my history website who sometimes posts essays there also posts them in some history forums. Is that bad for SEO? 3. I made a Facebook page for my history website. It says there "Promote your page" basically you pay $5 for around 100 likes. Has anyone tried that? Does it work? Because $5 seems like little money for additional 100 likes which will increase the traffic considerably. Thank you so much for the help! Hi. I'll like to ask few questions about PHP, as I think they are related to it.
I've came across some webpages, what I've spotted is that a webpage displays content but each "page" has different argument and there is no filename.
For example:
"http://www.website.com/?home" is home-like webpage, by changing "/?home" to "/?anotherpage" land me on some other webpage on their website and so on. My question is how is it done? Is it done from PHP?
Another question I wanted to ask is.. I went on InvisionPower.Board forum (such as this PHP Freaks ). How to force "folders" to be displayed as "files"?
For example:
"http://forums.phpfre...ks-on-facebook/" which links to a thread.
Thanks in advance
Hello everyone, I have been doing web developing for a little while and just recently decided to make the leap to developing standalone applications. I started learning C++ and JAVA for this purpose, but quickly learned that PHP can also be used to this end, and since I am quite familiar with PHP, I thought it would make sense to start with PHP GTK. But before I jump right in, I have a few questions that I would greatly appreciate some answers for: Does PHP have any significant advantages/disadvantages over lower level languages such as C++ ? I would imagine that PHP being originally designed for web programming would be less suited for stand alones. I'm a little confused as to whether the GTK is a graphical user interphase software, the likes of QT and Netbeans, or is it a markup language like HTML, where the widgets are generated with text commands? Please I need a little clarification on that. Also are there any other tools that need to be downloaded to get started besides the GTK? Finally, am I supposed to learn OOP PHP to get going or is traditional procedural PHP sufficient? Answers to any or all of the above questions and any other advice would be highly appreciated. Thanks. I've been coding PHP for some time and would consider myself to be at an intermediate level. I can write code to do what I need but it's probably not the best way to do it. I rarely see any code that I am not able to read, understand, or follow. I've created modifications for everything from vBulletin, WordPress, Kayako Support Suit, Magento, and more. However, I've never really built a strong understanding around OOP. For example, let say you have the following classes: _main - db - admin - - modules - - - dashboard How would you share the db connection with the dashboard class? I've been trying to read up on Dependency Injections and Singletons but I haven't found an article that has explained it on a level that I can understand. I get a feeling that most people who use OOP in PHP have a background in Java or C++ and are much more familiar with everything. Could someone please explain this to me in simple terms or link me to an extremely well explained article that I'd be able to understand without a background in computer science? Thanks A few questions about mod_rewrites... 1.) If I want to determine if the URL ends with either "list" or "gallery", and then take appropriate action, does the code below look correct?
RewriteRule shop/(.+)/([list|gallery])$ shop/catalog.php?category=$1&view=2 [L]
2.) Is it bad to use mod_rewrites to determine how your website branches? For example...
RewriteRule shop/music/(.*)$ go somewhere [L] RewriteRule shop/movies/(.*)$ go somewhere else [L] RewriteRule shop/books/(.*)$ go yet somewhere else [L]
I basically have a picture uploading system for users. I have two questions: 1) What CHMOD should I use for the folders that are there for uploading files to? Currently it is 755, but I want it to be accessible and safe. 2) When I use the standard mkdir() function to create folders in my main parent folder, the folders don't get created. Is this because my parent folder is CHMOD 755? Thanks This topic has been moved to mod_rewrite. http://www.phpfreaks.com/forums/index.php?topic=348665.0 This topic has been moved to Third Party PHP Scripts. http://www.phpfreaks.com/forums/index.php?topic=348384.0 |