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PHP - Preg_replace Not Catching '<3' As A Replaceable Text
Here are my smileys:
// Here you can add additional smilies if you like (please note that you must escape single quote and backslash)
$smilies = array(
':)' => 'smile.gif',
';)' => 'wink.gif',
':(' => 'sad.gif',
':mellow:' => 'mellow.gif',
':(' => 'sad.gif',
':angry:' => 'mad.gif',
':cry:' => 'cry.gif',
':banana:' => 'banana.gif',
':locked:' => 'dancinglock.gif',
':hug:' => 'hug.gif',
':bonk:' => 'bangin.gif',
':love:' => 'heart2.gif',
'<3' => 'heart.gif',
':blush:' => 'blush.gif',
':p' => 'tongue.png',
':lol:' => 'lol.png',
':mad:' => 'mad.png',
':rolleyes:' => 'roll.png',
':cool:' => 'cool.png');
And here is the function to convert them to images using preg_replace
function do_smilies($text)
{
global $smilies;
$text = ' '.$text.' ';
foreach ($smilies as $smiley_text => $smiley_img)
{
if (strpos($text, $smiley_text) !== false)
$text = preg_replace('%(?<=[>\s])'.preg_quote($smiley_text, '%').'(?=[^\p{L}\p{N}])%um', '<img src="/img/emoticons/'.$smiley_img.'" alt="'.$smiley_text.'">', $text);
}
return substr($text, 1, -1);
}
All of them are being replaced except for '<3', why? I tried:\<3AND <\3to see if I needed to escape the left carrot (<), but still no luck. Edited by Monkuar, 10 January 2015 - 12:19 AM. Similar TutorialsI'm trying to use preg_replace but I can't get it working. function replaceContent($sContent) { $aReplaceTags = array( "'\[MENU-CARD\](.*?)\[/MENU-CARD\]'is" => '\\1', "'\[CONTACT-FORM\]'is" => "Contactform", ); return preg_replace(array_keys($aReplaceTags), array_values($aReplaceTags), $sContent); } This works great however when I change '\\1' into a function the output of '\\1' will always be 1. function replaceContent($sContent) { $aReplaceTags = array( "'\[MENU-CARD\](.*?)\[/MENU-CARD\]'is" => $this->loadMenuCard('\\1'), "'\[CONTACT-FORM\]'is" => "Contactform", ); return preg_replace(array_keys($aReplaceTags), array_values($aReplaceTags), $sContent); } Anyone knows what I am doing wrong? Code Gurus' Salute, Please I wanna catch this image upload exception without it bringing out this: "Warning: getimagesize() [function.getimagesize]: Filename cannot be empty in C:\xampp\htdocs", Actually, I set the image size to be 32kb abd 120x120 pix. If anything varies from the above description it would not be uploaded, but it brings out "Your picture must be a GIF, JPEG, or PNG image file no greater than 32 KB and 120x120 pixels in size." alongside with that above error. Please gents how do I implement this exception without that warning signal? So basically I have a function that grabs a daily bible scripture via an rss feed. For whatever reason, it is offline today and I was greeted with a huge paragraph of errors and the bottom part of my page not rendering. Here is the function: Code: [Select] <?php function scripture(){ function fetchXML($url) { $ch = curl_init(); $useragent="Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.8.1.1) Gecko/20061204 Firefox/2.0.0.1"; curl_setopt ($ch, CURLOPT_URL, $url); curl_setopt ($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt ($ch, CURLOPT_USERAGENT, $useragent); //get data $data = curl_exec($ch); curl_close($ch); return $data; } define("USE_CURL", true); $url = "http://www.mybiblescripture.com/rss/bible.php?fmt=daily&trans=KJV"; //get xml doc with info $data = fetchXML($url); //create a SimpleXML object to parse the xml $char_xml = new SimpleXmlElement($data); $scripture_a=$char_xml->channel->item->description; $scripture_b=$char_xml->channel->item->title; echo $scripture_a . '<br><b>'. $scripture_b. '</b>'; } ?> And here is the nasty error I receive due to the url being offline: Code: [Select] Fatal error: Uncaught exception 'Exception' with message 'String could not be parsed as XML' in /path/lbcfunc.php:21 Stack trace: #0 /path/lbcfunc.php(21): SimpleXMLElement->__construct('') #1 /path/index.php(31): scripture() #2 {main} thrown in /path/lbcfunc.php on line 21 I have 0 experience in catching exceptions and unsure where to start. I would like to try and just echo: "No Bible Scripture Found" as a friendly message instead I guess. thanks. Hello, I have domain "A" coming with a wehosting and a domain "B" , it's DNS is redirected to domain "A". Now I'm solving how to catch the url (domain name) of "B", that is redirecting to me. Is it possible throught PHP ? Thak you I did not post this in Regex because I do not believe it is a problem with the preg_match. My input check on the username length works without any problems, however the check to make sure the user only uses a-z and whitespace does not work. I am not sure why and I am new to PHP. Should I setup the input check differently? The error code is never displayed if I input "!@*(#(!$)$@(" and it will not stop that from being submitted. Any help is GREATLY appreciated!! Code: [Select] if(strlen(trim($_POST['name'])) > 15 || strlen(trim($_POST['name'])) < 1) { $errors[] = $lang['No name']; } if(preg_match('/[^a-z]\s/i', $_POST['name'])) { $errors[] = $lang['Invalid char']; } I'm sure it's not much, but I'm not understanding something with custom error handlers: I've created a custom error handler, which I initially set when my page loads : set_error_handler(array ( new ErrorHandler(), 'handleError' ));
It seems to catch all internal PHP errors, such as if I: var_dump($non_existing_var); right after the set_error_handler.... Now, I have an object that throws an exception after: set_error_handler(array ( new ErrorHandler(), 'handleError' )); $locale = new \CorbeauPerdu\i18n\Locale(...); // this should throw an exception ... I thought that with an error handler set, I could 'skip' the try/catch for it, but doing so, PHP spits out in its internal log: PHP Fatal error: Uncaught CorbeauPerdu\i18n\LocaleException: ....
My error handler doesn't catch it at all before, thus my page breaks!! If I want it to go through the error handler, I have to init my Locale with a try/catch and use trigger_error() like so:
set_error_handler(array ( new ErrorHandler(), 'handleError' ));
try {
$locale = new \CorbeauPerdu\i18n\Locale(...); // this should throw an exception
}
catch(Exception $e) {
trigger_error($e->getMessage(), E_USER_ERROR);
}
...
Is this normal ? I thought one of the goals of the error_handler was to catch anything that wasn't dealt with? Thanks for your answers! Hello ppl, I have this website link http://www.somesite.com/anotherpage/yetotherpage.html what i want to make is using preg_replace that the final result will be www.somesite.com Hi, I'm kind of new to PHP and very new to Regular Expressions and I was wondering if someone could help run through this code snippet from a callback function in a Joomla plugin called Affliates Feed. So far I have this is passed a pointer to variable item (I understand this is effectively the same as passing the variable but a lot less CPU intensive. Creates an array with keys and values Now the for loop I am stuck with, I understand the interation through the array. But what is preg_replace returning and why pass it back that way hasn't it already done its job? Can any one help? And please feel free to be as basic as possible :help: Thanks, Adam Code: [Select] function gardening(&$item) { #renaming categories, not the most efficient use for example strtolower first, and use only lowercase in the rename array $rename=array( ' Gardening?' => '', 'Climber Plants' => 'Climbing Plants', 'Seeds.*Bulbs' => 'Seeds Bulbs', 'Plant protection' => 'Horticultural goods', 'Garden structures' => 'Garden buildings',); foreach ( $rename as $k => $v ) { list($item['menu_1'],$item['menu_2'])=preg_replace("#$k#",$v,array($item['menu_1'],$item['menu_2'])); } $item['menu_1']=ucfirst(strtolower($item['menu_1'])); $item['menu_2']=ucfirst(strtolower($item['menu_2'])); $item['menu_3']=ucfirst(strtolower($item['menu_3'])); $item['menu_4']=ucfirst(strtolower($item['menu_4'])); } After days of searching I found this thread http://www.phpfreaks.com/forums/index.php?topic=236954.0 that helped me do what I was trying to do. I've gotten the code to create and rename my html document but I can't figure out how to use the preg_replace part. This is my template with the 3 variables I want to replace with values from a form. Code: [Select] <html> <head> <link rel="stylesheet" type="text/css" href="style.css" /> </head> <body> <?php include_once('content.php') ?> </body> <SCRIPT language="JavaScript" SRC="javascript.js"></SCRIPT> <script type="text/javascript"> function nametitle(){ parent.iframe1.document.getElementById("div1").innerHTML = "VARIABLE1 <br>VARIABLE2"; parent.iframe1.document.getElementById("quotes").innerHTML = "VARIABLE3"; } </script> </html> I've spent hours reading and trying to understand how to make it work but it's a little over my head. Could someone help me with this? Thanks, I'm trying to search a string for all occurences of a pattern, then append text after that pattern. The example is:
SUM("foo") as "bar"
and have it display as:
SUM("foo") over() as "bar"
The "SUM" could be any SQL aggregate and be case insensitive. So For bonus points, let's say the valid aggregates are array('SUM', 'MAX', 'MIN', 'AVG'). My plan right now is to figure it out for SUM, then loop it replacing the aggregate.
This is what I have so far... and it is not working.
$l= 'SUM("foo") as "bar"';
$l=preg_replace('/([^"]+")/','\0 over()',$l);
Thanks,
Ryan
im trying to do a complex(i think) prg replace but i keep getting the error: Code: [Select] Failed evaluating code: $lang->showing-1,1 the code i am trying to replace is: Code: [Select] <asf: lang[showing-<asf: var[num_report_alerts]>,<asf: var[num_report_alerts]>]> and the preg_replace is: Code: [Select] $content = preg_replace('|\<asf: lang\[(.*?)-(.*?)\]\>|e', '$lang->replace_vars($lang->//1, array(\\2))', $content); its supposed to take everything inside <asf: lang[]> and echo \\1 which would be "showing" and then add \\2 into an array which would be "array(1,1)". So the output would be showing 1 of 1. Anyone know where im going wrong? Hi there! I need to echo some text from a database table, this text should be linked to a url stored in the same database. I am trying to do this with preg_replace but I am terrible at it! I keep getting this error: Warning: Wrong parameter count for preg_replace() while($row = mysql_fetch_array( $result )) { $reg_exUrl = "/(http|https|ftp|ftps)\:\/\/[a-zA-Z0-9\-\.]+\.[a-zA-Z]{2,3}(\/\S*)?/"; echo preg_replace ($reg_exUrl, $row['title'); Any suggestion? Thanks i have: $msg = ereg_replace("[^A-z0-9]"," ",$msg); $msg = ereg_replace(" "," ",$msg); $msg = ereg_replace(" "," ",$msg); how will i apply preg_replace please??? thank you I am trying to pull out the image HTML tag but its not working as expected. Here is what I am doing $removeimagetag='/<a href/'; $replacwith = "illegal"; $_POST['descr']=preg_replace($removeimagetag,$replacwith,$_POST['descr']); in the 'descr' there is a <a href="http://s635.photobucket.com...... When it post it does not strip out the <a href So the image is displayed. I tried a modified version to test to see if it work that looked like this. $removeimagetag='/goofy/'; $replacwith = "illegal"; $_POST['descr']=preg_replace($removeimagetag,$replacwith,$_POST['descr']); When the word goofy appears in the text then its replaced with the word illegal, Also I would like to make it so that it replaces the entire line from the <a href....... to the </a> with a phrase that says "this feature is not allowed" rather than just the part in the front...the <a href. Any help you can be will be greatly appreciated. Hi everyone, how do i add and ampersand symbol into preg_replace preg_replace("/[^a-zA-Z0-9\s\-\'\,\.\_]/" where do i place the symbol? & I currently have some custom tags, similar to BBCode, to be used for comments on my site. I'm trying to create a [nobr] tag (note: I know the no break tag will work in many major browsers, but it's deprecated, so I'm trying to be compliant). The idea is that if I encounter the [nobr] tag, I need to remove all line breaks. Here's the best I can do, but it's not working as I had hoped. Here's what I currently use to replace line breaks with a break tag. Code: [Select] $str=str_replace("\r\n","<br>",$str); Here's my attempt at introducing this new tag. Code: [Select] function BbToHtml($str) { $before=preg_replace("/(.+)\[nobr\](.+)\[\/nobr\](.+)/Usi","\\1",$str); $during=preg_replace("/(.+)\[nobr\](.+)\[\/nobr\](.+)/Usi","\\2",$str); $after=preg_replace("/(.+)\[nobr\](.+)\[\/nobr\](.+)/Usi","\\3",$str); $during=str_replace("\r\n","",$during); if($during != "") { // If the [nobr] tag was found, go with the new string. $str = $before.$during.$after; } else { // If the [nobr] tag was not found, go ahead like normal. $str=str_replace("\r\n","<br>",$str); } return $str; I can't get that working. Any ideas on how to fix that, or a completely alternate method of doing it? Thank you! Hey, I am trying to write a sort of replace function where {user:1} is converted into a set of information from a database using preg_replace. So I have created the following preg_replace: $patterns = array(); $patterns[1] = '/\{user:([0-9]+)\}/'; $replacements = array(); $replacements[1] = UserCredit('$1'); ksort($patterns); ksort($replacements); $content_show = preg_replace($patterns, $replacements, $content); echo $content_show; and then the function UserCredit which is just above that on the page: function UserCredit($user_id) { require 'connect.php'; $user_lookup = mysql_query("SELECT * FROM prop_users WHERE ID = '$user_id'"); while($row = mysql_fetch_array($user_lookup)) { $user_name = $row['full_name']; $user_file = $row['credit_file']; $user_url = $row['link_url']; $user_url_alt = $row['link_alt']; } if(mysql_num_rows($user_lookup)==0){ die("An error has occured, Sorry for any Inconvenience Caused! User ID=".$user_id); } require 'close.php'; $output = "<li class=\"clearfix\"><div class=\"credimg\"><img src=\"".$user_file."\" width=\"75px\" height=\"75px\" alt=\"".$user_name."\" /></div><p><strong><a href=\"".$user_url."\" title=\"".$user_url_alt."\">".$user_name."</a></strong><br /><em>Writing / Code</em></p></li>"; return $output; } I have tested the function and it works when I echo UserCredit('1'); And the preg_replace works at simply extracting the value for the user. The only problem is that I can't figure a way for the preg_replace to carry the value of $1 into the function it just literally carries "$1" Is there something obvious that I am missing or am I going around this the wrong way? I have no idea what the problem is with preg_replace and strings smaller than 3 characters. I'm writing to do a pattern search of abreviations(array) and replacements (array)... tried word boundries, which seems not to work at all. (it is VITAL that im able to match the whole word) here is a quick example which I cannot understand maybe someone could explain to me: 1. why repitions of certain abrevs do not get replaced. 2. why '/\bs.\b/' wont get matched (where there is a space before the b. - hense the word boundry) here is a snippet of code could someone please explain why this happens: Code: [Select] <?php $string='de d. s. pres. div. de de d. s.'; //DEFINE PATTERN $patterns = array(); $patterns[0] = '/ s. /'; $patterns[1] = '/ b. /'; $patterns[2] = '/ pres./'; $patterns[3] = '/ Ind./'; $patterns[4] = '/ Mar./'; $patterns[5] = '/ Agt./'; $patterns[6] = '/ Agy./'; $patterns[7] = '/ Indpls./'; $patterns[8] = '/ Chgo./'; $patterns[9] = '/ Corp./'; $patterns[10] = '/ U./'; $patterns[11] = '/ Fin./'; $patterns[12] = '/ ls./'; $patterns[13] = '/ Pres. /'; $patterns[14] = '/ Internat. /'; $patterns[15] = '/ m. /'; $patterns[16] = '/ N.Y.C./'; $patterns[17] = '/ div. /'; $patterns[18] = '/ de /'; $patterns[19] = '/ d. /'; //DEFINE PATTERN REPLACE $replacements = array(); $replacements[0] = ' son of '; $replacements[1] = ' born in '; $replacements[2] = ' president'; $replacements[3] = ' Indiana '; $replacements[4] = ' March '; $replacements[5] = ' Agent '; $replacements[6] = ' Agency '; $replacements[7] = ' Indianapolis '; $replacements[8] = ' Chicago'; $replacements[9] = ' Corporation '; $replacements[10] = ' U '; $replacements[11] = ' Financial '; $replacements[12] = ' Island'; $replacements[13] = ' President '; $replacements[14] = ' International '; $replacements[15] = ' married to '; $replacements[16] = ' New York City '; $replacements[17] = ' divorced'; $replacements[18] = ' de '; $replacements[19] = ' daughter of '; echo '------ Original ---------<br>'.$string.'<br>'; $data = preg_replace($patterns, $replacements, $string); echo '<br>------ Abbreviation Replace ---------<br>'.$data.'<br>'; ?> OUTPUT: ------ Original --------- de d. s. pres. div. de de d. s. ------ Abbreviation Replace --------- de daughter of son of president divorcedde daughter of d. s. any help is appriciated thanks. im not sure how to do this: my code used the deprecated ereg_replace like this: $name = ereg_replace(" ", "", $name); i replaced it with this: $name = preg_replace(" ", "", $name); //this is line 65 but know get a warning: Warning: preg_replace(): Empty regular expression on line 65 what am i doing wrong please? thank you |
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