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PHP - Trying To Program My Way Out Of Repetitive Form Post Capture/mysql Insert!
Hi Folks,
Firstly I am new, I have read several topics here and learned a lot, I would class myself as 'slightly better than basic', but my knowledge is mostly gained from reading code.
I am making a simple POST form for work, the data gets inserted into MySQL, nice and easy, I can make it work if I write out the statement completely, BUT I need to make a new form, it will have HUNDREDS of input fields, I really don't want to write the code, and I figured programmatically is a good way to go anyway as forms change and new forms may be required, so I set about building a function to completely handle my post data, bind it to a statement and insert it into a table, I have scrapped it a half dozen times already because something fundamentally doesn't work, but I am very close! The function can write the statement, but I need to bind the POST values before I can insert, something going wrong here and I would appreciate some help, I have a feeling it's a problem with an array, but anyway I will show you what I have, give you some comments as to my reasoning, and hopefully you can help me with the last bit
public function getColumnNames($table){
$sql = "SELECT COLUMN_NAME FROM INFORMATION_SCHEMA.COLUMNS WHERE table_name = :table";
try {
$stmt = $this->dbh->prepare($sql);
$stmt->bindValue(':table', $table, PDO::PARAM_STR);
$stmt->execute();
$output = array();
while($row = $stmt->fetch(PDO::FETCH_ASSOC)){
$output[] = $row['COLUMN_NAME'];
}
$all = array($output);
$a1 = array_slice($output, 1); // I don't want column 1, it contains the ID, its auto incremented.
$a2 = array_slice($a1, 0, -3); // I don't want the last 3 columns as they have default values
$selected = array($a2); // contains all the columns except those excluded by array_slice, columns now match all of the input fields on the form
foreach ($selected as $row){
$fields = "`" . implode('`, `', $row) . "`"; // I'm making `fields` here,
$bind = ":" . implode(', :', $row); // And making :values here
}
return array (
"raw" => $all,
"fields" => $fields,
"bind" => $bind
);
}
catch(PDOException $pe) {
trigger_error('Could not connect to MySQL database. ' . $pe->getMessage() , E_USER_ERROR);
}
}
public function addRecord(){
$col = array();
$col = $this->getColumnNames("table");
$raw = array($col['raw']);
$fields = array($col['fields']);
$bind = array($col['bind']);
$columnList = implode('`, `', $fields);
$paramList = implode(', ', $bind);
$sql = "INSERT INTO `{$this->dbtable}` ($columnList) VALUES ($paramList)";
return $sql; // this returns something like:
INSERT INTO `table` (`field1`, `field2`, `field3`) VALUES (:field1, :field2, :field3)";
perfect I thought, now I just need to bind the values from $_POST... then I get stuck.
Edited by luke3, 08 January 2015 - 12:10 PM. Similar TutorialsOk .I tried to look for the problem for about 1 hour but I can't see what's wrong whit the following code: In firebug the post values appear correctly like so:id=116&usern=asdawe&com=qweqw&page=116&submit=submit and the inserc() function works correctly because i tried it whit a array of data created by my; Code: [Select] <?php if(isset($_POST['submit'])) { $comment = new comment; $comment->storeform($_POST); $comment->insertc(); } ?> <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="POST"> <input type="hidden" name="id" value="<?php echo $result['article']->id ?>"/> <ul> <li> <input type="text" name="usern" id="usern" /> </li> <li> <textarea name="com" id="com" COLS=40 ROWS=6></textarea> </li> <input type="hidden" name="page" value="<?php echo $result['article']->id ?>" /> <input type="submit" name="submit" value="submit" /> </ul> </form> Code: [Select] <?php class comment{ public $id = null; public $usern = null; public $com = null; public $page = null; public function __construct($data=array() ) { if( isset($data['id']) ) $this->id= (int)$data['id']; if( isset($data['usern']) ) $this->usern= preg_replace ( "/[^\.\,\-\_\'\"\@\?\!\:\$ a-zA-Z0-9()]/", "", $data['usern'] ); if( isset($data['com']) ) $this->com= preg_replace ( "/[^\.\,\-\_\'\"\@\?\!\:\$ a-zA-Z0-9()]/", "", $data['com'] ); if( isset($data['page']) ) $this->page= (int)$data['page']; } public function storeform ( $params ) { // Store all the parameters $this->__construct( $params ); } public function insertc() { $con = new PDO(DBN,DB_USER,DB_PASS); $sql = "INSERT INTO comments (usern,com,page) VALUES (:usern,:com,:page)"; $st =$con->prepare($sql); $st->bindValue( ":usern", $this->usern, PDO::PARAM_STR ); $st->bindValue( ":com", $this->com, PDO::PARAM_STR ); $st->bindValue( ":page", $this->page, PDO::PARAM_INT ); $st->execute(); $this->id = $con->lastInsertId(); $con = null; } } ?> Hi,
I created a form that inserts first - last name, address, and email address into a mysql databse table.
The record inserts correctly - No problems here.
The problem is I only want to insert the data if the email and address doesn't exist.
I set it up for just the email right now to try to get this to work but have failed.
When the form is submitted and the record exists it inserts the record anyway and sends the email which it's not suppose to do.
The form is suppose to after submitting -
1. validate
2. insert only if the record doesn't exist
3. send the email.
Here's the code
<?php
$to = "email@email.com";
if(isset($_POST['submit']))
{
// VALIDATION
if(empty($_POST['firstName']))
{
$errorfirstName .= "First Name Required";
}
if(empty($_POST['lastName']))
{
$errorfirstName .= "Last Name Required";
}
if(empty($error)) # No error go ahead and email it.
{
$to = "$to";
$subject = 'the form';
$msg .="<html><head>
<meta http-equiv='Content-Type' content='text/html; charset=utf-8' />
<title>The Form</title>
</head>
<body>
<table>
<tr>
<td>Email sent for confirmation</td>
</tr>
</table>
</body>
</html>";
$mail($to, $subject, $headers, $msg);
if(!$result)
{
$error = "<div id='errors'>There was an unknown error </div>";
}
else
{
include('connection.php');
$firstName = mysqli_real_escape_string($con, $_POST['firstName']);
$lastName = mysqli_real_escape_string($con, $_POST['lastName']);
$address = mysqli_real_escape_string($con, $_POST['address']);
$email = mysqli_real_escape_string($con, $_POST['email']);
$email = $_POST['email'];
$sql = "SELECT * FROM table WHERE `email` = '{$email}'";
$result = mysql_query($sql);
if ( mysql_num_rows ( $result ) > 0 )
{
$error = "Email Exists.";
}
else
{
$error = "Email does not exist. Insert it!!!";
$sql="INSERT INTO table (firstName, lastName, address, email) VALUES ('$_POST[firstName]','$_POST[lastName]','$_POST[address]', '$_POST[email]')";
}
if (!mysqli_query($con,$sql))
{
die('Error: ' . mysqli_error($con));
}
mysqli_close($con)
{
}
}
}
}
?>
<!-- Form -->
<html>
<head></head>
<body>
<section>
<form method="POST" action="theform" name="for" onsubmit="return validateForm(this)">
<?php
if(!empty($error))
{
echo "$error";
}
?>
This where the inputs would go not going to include them because not having an issue with the form
</form>
</section>
</body>
</html>
Edited by barkly, 26 October 2014 - 06:54 PM. Hi. I'm making a private webpage for my self where i can post news, games, music titles and movies. I'm made it so that i can post and delete them from my page. Also i wanted to have the option to edit them. So i made a action that shows me a list og the posts in each category. And then i want the option to hit UPDATE, and then it should open the form with the info's from MySQL. I've made those two options as the following: Code: [Select] elseif ( $action == "EditNews" ) { // EDIT NEWS START if ( !$_GET['id'] ) { ?> <div id="content"> <?php $sql = mysql_query("SELECT * FROM news") or die(mysql_error()); while ( $row = mysql_fetch_assoc($sql) ) { echo "<a href=\"?page=Admin&action=UpdateNews&id=" . $row['news_id'] . "\">Update</a> | " . $row['subject'] . "<br>"; } echo "</div>"; } else { $type = $_GET['type']; $id = $_GET['id']; } // EDIT NEWS END } elseif ( $action == "UpdateNews" ) { // UPDATE NEWS START if ( !$_POST['submit'] ) { $id = $_GET['id']; $sql = mysql_query("SELECT * FROM news WHERE news_id='$id'") or die(mysql_error()); $user_id = $_SESSION['uid']; $subject = $_row['subject']; $body = nl2br($_row['body']); ?> <div id="content"> <form action="?page=Admin&action=EditNews" method="post"> <div id="">Subject</div> <div id=""><input id="input" type="text" name="subject"></div> <div id="">Message</div> <div id=""><textarea id="input" name='body' cols='15' rows='4'></textarea></div> <div id=""><input id="submit" class="input" type="submit" name="submit" value="Post News"></div> </form> </div> <?php } else { ?> <div id="content">Not Working!</div> <?php } // UPDATE NEWS END } - I know i miss something, but i've tried to get to the point, where i only have the form as blank, and need some help from there. I hope someone can help me with my problem. MOD EDIT: [code] . . . [/code] tags added. Alright so I am trying to code a very simple form that adds a user to my SQL database with certain information filled in and certain information kept hidden with default values in a form. My index.php file is as follows (not all of the code but just the form part): <?PHP $submitMessage = $_GET['value']; if ($submitMessage == success) { echo '<div class="congratulations"><font color="#84d20c"><strong>Congratulations:</strong></font> The user has been added.</div>'; }else if($submitMessage == NULL){ }else if($submitMessage == fail){ echo '<div class="error"><font color="#d3430c"><strong>Error:</strong></font> An error occurred please check the error details below:</div>'; echo 'ERROR DETAILS:'; echo mysql_error(); } ?> <h1><i>Add User</i></h1> <p>This page is where you would manually add a user to the donations databases (for example you or a member of the community with elevated status that does not need to pay).</p> <br/> <form enctype="multipart/form-data" action="scripts/admin_save_sm_db.php" method="post"> <input name="authtype" value="steam"/><br /><br /> <h3><i>STEAM ID:</i></h3> <input name="identity" value="STEAM_0:X:XXXXXXXX"/><br /> <div class="form_help">Steam ID of the player you wish to add. Must be in the format STEAM_0:X:XXXXXXXX</div><br /> <input name="flags" value="o"/><br /><br /> <input name="name" value="Donator"/><br /><br /> <input name="immunity" value="0"/><br /><br /> <h3><i>Your Email Address</i></h3> <input name="user_email"/><br /> <div class="form_help">Your Email Address for security purposes.</div><br /> <input name="Submit" type="submit" value="Submit" class="form_submit" /> </form> My admin_save_sm_db.php file is as follows: <?php session_start(); if(!isset($_SESSION["username"])) { header('Location: login.php'); exit; } @require("../sm_admin_db.php"); $authtype = $_POST['authtype']; $identity = $_POST['identity']; $flags = $_POST['flags']; $name = $_POST['name']; $immunity = $_POST['immunity']; $user_email = $_POST['user_email']; $link = @mysql_connect(_HOST,_USER,_PASS); @mysql_select_db(_DB); $sql = @mysql_db_query(_DB,"INSERT INTO "._TBL." (`authtype`, `identity`, `flags`, `name`, `immunity`, `user_email`) VALUES (NULL, '$authtype', '$identity', '$flags', '$name', '$immunity', '$user_email')"); $okay = @mysql_affected_rows(); if($okay > 0) { header( "Location: ../index.php?value=success" ); } else { header( "Location: ../index.php?value=fail" ); } @mysql_close($link); ?> And finally my sm_admin_db.php file is as follows: <?PHP //host loaction define("_HOST", "localhost", TRUE); //database username define("_USER", "thatsact_admin", TRUE); //database username`s password define("_PASS", "*********", TRUE); //database name define("_DB", "thatsact_sadadmins", TRUE); //database table name change this to install multiple version on same database define("_TBL", "sm_admins", TRUE); //This is the email that you will recieve emails when someone signs up. define("_EMAIL", "admin@tag-clan.com", TRUE); ?> All of this together does not work and gives the echo error code, however the mysql_error() string does not return anything. Nothing is inserted into the database. Can I get some help on where I went wrong and please keep in mind I am VERY new to php and didn't write most of this script so just tell me what to edit and exactly how to do it please. Thanks in advance. hello i have a db with name which populates a form dropdown list there are various variables like this in the form. the user selects their choices and then submits the form to a new db table at the moment it does not capture the dropdown data to the insert sql help please here is the code: =============================== <?php include ('connect.php'); // Insert any new image into database if(isset($_POST['xsubmit']) && $_FILES['imagefile']['name'] != "") { $fileName = $_FILES['imagefile']['name']; $fileSize = $_FILES['imagefile']['size']; $fileType = $_FILES['imagefile']['type']; $content = addslashes (file_get_contents($_FILES['imagefile']['tmp_name'])); $jeweltype = $_POST['jeweltype']; $jewelsize = $_POST['jewelsize_in']; $jewelcolour = $_POST['jewelcolour_in']; $jewelmaterial = $_POST['jewelmaterial_in']; $jewelgender = $_POST['jewelgender_in']; if(!get_magic_quotes_gpc()) { $fileName = addslashes($fileName); } // Checking file size if ($fileSize < 150000) { mysql_query ("INSERT into jewel_images (name,size,type,content,jeweltype,jewelsize,jewelcolour,jewelmaterial,jewelgender) " . "values ('$fileName','$fileSize','$fileType','$content','$jeweltype','$jewelsize','$jewelcolour','$jewelmaterial','$jewelgender')"); } else { $err = "The Image file to too large!"; } } // Find out about latest image $gotten = mysql_query("select * from jewel_images order by row_id desc"); $row = mysql_fetch_assoc($gotten); $bytes = $row['content']; // If this is the image request, send out the image if ($_REQUEST['pic'] == 1) { header("Content-type: $row[type];"); print $bytes; } ?> <html> <head> <title>Upload an image to a database</title> </head> <body> <font color="#FF3333"><?php echo $err ?></font> <table> <form name="Upload" enctype="multipart/form-data" method="post"> <tr> <td>Upload <input type="file" name="imagefile"><br /> Jewelery Type: <select> <?php $sql="SELECT jeweltype FROM jeweltypes"; $result =mysql_query($sql); while ($data=mysql_fetch_assoc($result)){ ?> <option value ="jeweltype" ><?php echo $data['jeweltype'] ?></option> <?php } ?> </select> <br /> Jewelery Size: <select> <?php $sql="SELECT jewelsize FROM jewelsizes"; $result =mysql_query($sql); while ($data=mysql_fetch_assoc($result)){ ?> <option value ="jewelsize" ><?php echo $data['jewelsize'] ?></option> <?php } ?> </select> <br /> Jewelery Colour: <select> <?php $sql="SELECT jewelcolour FROM jewelcolours"; $result =mysql_query($sql); while ($data=mysql_fetch_assoc($result)){ ?> <option value ="jewelcolour_in" ><?php echo $data['jewelcolour'] ?></option> <?php } ?> </select> <br /> Jewelery Material: <select> <?php $sql="SELECT jewelmaterial FROM jewelmaterials"; $result =mysql_query($sql); while ($data=mysql_fetch_assoc($result)){ ?> <option value ="jewelmaterial_in" ><?php echo $data['jewelmaterial'] ?></option> <?php } ?> </select> <br /> Jewelery Gender: <select> <?php $sql="SELECT jewelgender FROM jewelgenders"; $result =mysql_query($sql); while ($data=mysql_fetch_assoc($result)){ ?> <option value ="jewelgender_in" ><?php echo $data['jewelgender'] ?></option> <?php } ?> </select> <br /> <input type="submit" name="xsubmit" value="Upload"> </td> </tr> <tr> <td>Latest Image</td> </tr> <tr> <td><img src="?pic=1"></td> </tr> </form> </table> </body> </html> Need a little help with this code. I'm running Apache 2.21 / PHP 5.3.5 on Windows. This is a V6 application. I am running Windows 7. I am new, and trying to learn. What am I doing wrong in line 8 with the 'if' statement? The idea is to create a table in mySQL using a form interface. Thank you in advance. Parse error: syntax error, unexpected '{' in C:\website\do_createtable.php on line 8 <? $db_name="booster"; $connection=mysql("localhost", "user", "password") or die (mysql_error()); $db=mysql_select_db($db_name, $connection) or die (mysql_error()); $sql="CREATE TABLE $_POST[table_name] ("; for ($i=0; $i < count($_POST[field_name]); $i++) { $sql .= $_POST[field_name][$i]." ".$_POST[field_type][$i]; if ($_POST[field_length][$i] != "" { $sql .= " (".$_POST[field_length][$i]."),"; } else { $sql .= ","; } } $sql=substr($sql,0,-1); $sql .= ")"; In brief, I'm attempting to capture the form data from a dynamic form to a mysql database. From he
To He
The post data looks like this from the form - Array(
... ) PHP CODE:
... As a non-php or mysql developer, I'm learning on the fly. This is a section of the php file that I was using to post the form data to mySQL. This worked great up to the point I added the dynamic form widget.
<?php
// This function will run within each post array including multi-dimensional arrays
function ExtendedAddslash(&$params)
{
foreach ($params as &$var) {
// check if $var is an array. If yes, it will start another ExtendedAddslash() function to loop to each key inside.
is_array($var) ? ExtendedAddslash($var) : $var=addslashes($var);
unset($var);
}
}
// Initialize ExtendedAddslash() function for every $_POST variable
ExtendedAddslash($_POST);
$submission_id = $_POST['submission_id'];
$formID =$_POST['formID'];
$ip =$_POST['ip'];
$fname =$_POST['fname'];
$lname =$_POST['lname'];
$spousename =$_POST['spousename'];
$address =$_POST['address'][0]." ".$_POST['address'][1]." ".$_POST['address'][2]." ".$_POST['address'][3]." ".$_POST['address'][4]." ".$_POST['address'][5];
...
$db_host = 'localhost';
$db_username = 'xxxxx';
$db_password = 'xxxxx';
$db_name = 'xxxxx';
mysql_connect( $db_host, $db_username, $db_password) or die(mysql_error());
mysql_select_db($db_name);
// search submission ID
$query = "SELECT * FROM `tableName` WHERE `submission_id` = '$submission_id'";
$sqlsearch = mysql_query($query);
$resultcount = mysql_numrows($sqlsearch);
if ($resultcount > 0) {
mysql_query("UPDATE `tableName` SET
`fname` = '$fname',
`lname` = '$lname',
`spousename` = '$spousename',
`address` = '$address',
WHERE `submission_id` = '$submission_id'")
or die(mysql_error());
} else {
mysql_query("INSERT INTO `tableName` (submission_id, formID, IP, fname, lname, spousename, address)
VALUES ('$submission_id', '$formID', '$ip', '$fname', '$lname', '$spousename', '$address') ")
or die(mysql_error());
}
?>
It has been suggested that I explore using the PHP Explode() function. It's possible that may work, but can't get my head around how to apply the function to the PETLIST Array. Looking for suggestions or direction to find a solution for this challenge. Looking forward to any replies. I want to pull some records plus unique key from one mysql table and then use them as questions in a form/questionnaire. The post form will have six radio buttons to the right of the fields pulled with the key posted but hidden and will wirte to another table. I guess this is a templating question- as I've successfully retrieved the table 1 records via a query - I just can't seem to use them in the form. Below is the code I'm using to view table "PCM1" <?php // query.php require_once 'login.php'; $db_server = mysql_connect($db_hostname, $db_username, $db_password); if (!$db_server) die("Unable to connect to MySQL: " . mysql_error()); mysql_select_db($db_database) or die("Unable to select database: " . mysql_error()); $query = "SELECT * FROM pcm1"; $result = mysql_query($query); if (!$result) die ("Database access failed: " . mysql_error()); $rows = mysql_num_rows($result); for ($j = 0 ; $j < $rows ; ++$j) { echo 'RID: ' . mysql_result($result,$j,'mcde') ; echo 'Statement: ' . mysql_result($result,$j,'oppclub') . '<br />'; ; } Not sure exactly what my problem is here, but i have looked at this at least a hundred times and I just can't figure out what is going on. Everything works great except for the sending the email part. It displays the error "There was a problem sending the mail". The form field checking works fine, the insert into mysql works fine - - but it won't send the email. I have tried using double quotes and single quotes for the email information ($to, $subject, etc...) I have even eliminated the form data from the email information and it still doesn't send. I am hopelessly stuck at this point Any ideas?? Code below: <html> <body bgcolor = 'blue'> <div align = 'center'> <h1>test FORM</h1> </div> <p> <?php If ($_POST['submit']) //if the Submit button pressed { //collect form data $fname = $_POST['FName']; $lname = $_POST['LName']; $email = $_POST['Email']; $tel = $_POST['Tel']; $mess = $_POST['Mess']; $errorstring = ""; if (!$fname) $errorstring = $errorstring."First Name<br>"; if (!$lname) $errorstring = $errorstring."Last Name<br>"; if (!$email) $errorstring = $errorstring."Email<br>"; if ($errorstring !="") echo "<div align = 'center'><b>Please fill out the following fields:</b><br><font color = 'red'><b>$errorstring</b></font></div>"; else { $fname = mysql_real_escape_string($fname); $lname = mysql_real_escape_string($lname); $email = mysql_real_escape_string($email); $tel = mysql_real_escape_string($tel); $mess = mysql_real_escape_string($mess); $con = mysql_connect("localhost","user","password"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("mec", $con); $sql="INSERT INTO formtest (FName, LName, Title, Tel, Email, Mess) VALUES ('$fname','$lname','$title','$tel','$email','$mess')"; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } $to = 'myemailaddress'; $subject = 'test form'; $message = 'Hello'; $headers = 'From Me'; $sent = mail($to, $subject, $message, $headers); if($sent) {print "Email successfully sent";} else {print "There was an error sending the mail";} mysql_close($con); } } ?> <p> <form action= 'testmecform.php' method= 'POST'> <table width = '640' border = '0' align = 'center'> <tr> <td align = 'right'><b>First Name</b></td> <td><input type = 'text' name = 'FName' value = '<?php echo $fname; ?>' size = '25'></td> <td><div align = 'right'><b>Telephone</b></div></td> <td><input type = 'text' name = 'Tel' value = '<?php echo $tel; ?>' size = '25'></td> </tr> <tr> <td align = 'right'><b>Last Name</b></td> <td><input type = 'text' name = 'LName' value = '<?php echo $lname; ?>' size = '25'></td> <td> </td> <td> </td> </tr> <tr> <td align = 'right'><b>Email</b></td> <td><input type = 'text' name = 'Email' value = '<?php echo $email; ?>' size = '25'></td> <td> </td> <td> </td> </tr> <tr> <th colspan = '4'><b>Please enter any additional information he </b></th> </tr> <tr> <th colspan = '4'><textarea name = 'Mess' cols = '50' rows = '10'><?php echo $mess; ?></textarea></th> </tr> <tr> <th colspan = '4'><b>Please make sure all information is correct before submitting</b></th> </tr> <tr> <th colspan = '4'><input type = 'submit' name = 'submit' value = 'Submit Form'></th> </tr> </table> </form> </body> </html> I have a list names in a database table in MySQL that I need to repeat the same search for on my system to get the associated information. Is there a Loop command or some type of trick to making a php script search table1.row1 then table1.row2 then table1.row3 etc. Basically using the row in the table as a variable for the other commands in the code. I really need some direction. Thanks. HI,
I am a beginner at programing and I have to do this project where it is asking me to valid ISBN 10 and 13 using MySQL database to store the information. I checked my php code to validate ISBN 10 and 13 and it works, but when I try to store the data to MySQL it is not working. What I mean is that when I click ShowISBN link it doesn't show this information:
ISBN Number
ISBN Type
Date Entered using timestamp
Valid or Invalid
This is the codes I have for input page of ISBN page:
<?php
//this is the isset function which allows us to submit back
//to the same form. If there isn't anything in the ISBN, it will
//show the bottom part of the form
if(isset($_POST["ISBN"])|| empty($_POST['isbn_type'])
|| empty($_POST['Valid_Invalid']))
{
$ISBN = $_POST["ISBN"];;
$IsbnType = $_POST["isbn_type"];;
$VaorIn = $_POST["Valid_Invalid"];;
$ISBN_Arr = str_split($ISBN);
$not10 =0;
$notNum=0;
$notX=0;
//entering error checking for the code
//check for 10 first, if clear do additional checking
if(strlen($ISBN) == 10)
{//start further error checking
//check to make sure first 9 are numeric
for($i=0;$i<=8;$i++)
{
if(!is_numeric($ISBN_Arr[$i]))
$notNum = 1;
}//end for loop check
//check to see if there is a X or a x
if($ISBN_Arr[9]=='x' || $ISBN_Arr[9]=='X')
{
$ISBN_Arr[9] = 10;
}
//if not an x, is it at least numeric?
else if (!is_numeric($ISBN_Arr[9]) )
{
$notX=1;
}
}//end additional error checking
else {
$not10=1;
}//end not 10 check
//start of error messages if prereqs are not met
if($notNum ==1 || $notX ==1 || $not10)
{
Print "<h2>Input error</h2><br/>";
Print "Here is the error(s) discovered:<br/>";
if($notNum ==1)
print"Your ISBN contains non-numeric data.<br/>";
if($notX ==1)
print"The last digit is not a number or a X.<br/>";
if($not10 ==1)
print"ISBN 10 number should contain 10 characters.<br/>";
include"ISBN_not_val_include.html";
}
//end error checking
else{
$chk_sum_num=10;
$chk_sum =0;
for($i=0;$i<=9;$i++)
{
$chk_sum +=$ISBN_Arr[$i] *$chk_sum_num;
//print"$ISBN_Arr[$i] | $chk_sum_num<br/>";
$chk_sum_num--;
}//end for loop
$is_valid_ISBN= $chk_sum%11;
//print"chk_sum: $chk_sum </br> is_valid_ISBN: $is_valid_ISBN</br>";
if($is_valid_ISBN==0)
{
print"<h3>VALID</h3><br/>";
print"$ISBN is a VALID 10 digit ISBN number.<br/>";
include"ISBN_val_include.html";
}
else{
print"<h3>INVALID</h3><br/>";
print"$ISBN is an INVALID 10 number ISBN.<br/>";
include"ISBN_not_val_include.html";
}//end is_valid if
}//end
}//end is set if
else{
include"ISBN_val_include.html";
}//end isset else
?>
</form>
<p><a href="_ShowISBN10and13DBProject.php">Show ISBN
</a></p>
</body>
</html>
This is the second part of the code that incorporates php and MySQL:
<?php
if (empty($_POST['ISBN'])|| empty($_POST['isbn_type'])
|| empty($_POST['Valid_Invalid']))
echo "<p>You must enter a Valid ISBN 10 to Continue!
Please Click your browser's Back Button to return
to the input page of ISBN 10 with Database.</p>\n";
else {
$DBConnect = @mysql_connect("xxx.xxx.xx.xxx", "xxxxxxxx", "xxxxxxxx");
if($DBConnect === false)
echo"<p>Unable to conenct to the database server.</p>"
. "<p>Error code " . mysql_errno()
. ": " . mysql_error() . "</p>";
else{
$DBName = "xxxxxxxx";
if (!@mysql_select_db($DBName, $DBConnect)) {
$SQLstring = "CREATE DATABASE $DBName";
$QueryResult = @mysql_query($SQLstring,
$DBConnect);
if ($QueryResult === FALSE)
echo "<p>Unable to execute the query.</p>"
. "<p>Error code " . mysql_errno($DBConnect)
. ": " . mysql_error($DBConnect) . "</p>";
else
echo "<p>You are the first visitor!</p>";
}
mysql_select_db($DBName, $DBConnect);
$TableName = "isbn";
$SQLstring = "SHOW TABLES LIKE '$TableName'";
$QueryResult = @mysql_query($SQLstring, $DBConnect);
if ($QueryResult === FALSE)
echo "<p>Unable to create the table.</p>"
. "<p>Error code " . mysql_errno($DBConnect)
. ": " . mysql_error($DBConnect) . "</p>";
$ISBNum = stripslashes($_POST['ISBN']);
$ISBNType = stripslashes($_POST['isbn_type']);
$VaORIn = stripslashes($_POST['Valid_Invalid']);
$SQLstring = "INSERT INTO $TableName
VALUES(NULL, '$ISBNum', '$ISBNType',
'$VaORIn')";
$QueryResult = @mysql_query($SQLstring, $DBConnect);
if($QueryResult === false)
echo"<p>Unable to execute the query.</p>"
. "<p>Error code " . mysql_errno($DBConnect)
. ": " . mysql_error($DBConnect) . "</p>";
else
echo"<h1>Thank you for trying our ISBN 10 program!</h1>";
mysql_close($DBConnect);
}
}
?><!--End PHP Script-->
This is the page where it is not working!
<?php
$DBConnect = @mysql_connect("xxx.xxx.xx.xxx", "xxxxxxx", "xxxxx");
if($DBConnect === false)
echo"<p>Unable to conenct to the database server.</p>"
. "<p>Error code " . mysql_errno()
. ": " . mysql_error() . "</p>";
else{
$DBName = "xxxxxx";
if (!@mysql_select_db($DBName, $DBConnect))
echo"<p>There are no entries in the guest book!</p>";
else {
$TableName = "isbn";
$SQLstring = "SELECT * FROM $TableName";
$QueryResult = @mysql_query($SQLstring, $DBConnect);
if (mysql_num_rows($QueryResult) == 0)
echo"<p>There are no entries in the ISBN 10 Database!</p>";
else{
echo"<p>The following ISBN have
been recorded:</p>";
echo"<table width='100%' border='1'>";
echo"<tr><th>ISBN Number</th><th>ISBN Type</th><th>
Date Entred</th><th>
Valid OR Invalid</th></tr>";
while (($Row = mysql_fetch_assoc($QueryResult)) !==FALSE) {
echo "<tr><td>{$Row['ISBN']}</td>";
echo "<tr><td>{$Row['isbn_type']}</td>";
echo "<tr><td>{$Row['TIMESTAMP']}</td>";
echo "<td>{$Row['Valid_Invalid']}</td></tr>";
}
}
mysql_free_result($QueryResult);
}
mysql_close($DBConnect);
}
When I click show ISBN nothing happens and I am not shore why!
This is how I have my table setup in MySQL Manually by clicking table and create table:
Columns:
count int(11) Al PK
ISBN varchar(45)
isbn_type varchar(45)
TIMESTMP datetime PK
Valid_Invalid varchar(45)
Can someone please tell me why when I click Show ISBN in the input page the first code pasted I get nothing! How do I fix the issue because my validation works, but it's not storing it or showing up when click Show ISBN!
Any help will be appreciate it!
Can anyone tell me why this is not INSERTing? My array data is coming out just fine.. I've tried everything I can think of and cannot get anything to insert.. Ahhhh! <?php $query = "SELECT RegionID, City FROM geo_cities WHERE RegionID='135'"; $results = mysqli_query($cxn, $query); $row_cnt = mysqli_num_rows($results); echo $row_cnt . " Total Records in Query.<br /><br />"; if (mysqli_num_rows($results)) { while ($row = mysqli_fetch_array($results)) { $insert_city_query = "INSERT INTO all_illinois SET state_id=$row[RegionID], city_name=$row[City] WHERE id = null" or mysqli_error(); $insert = mysqli_query($cxn, $insert_city_query); if (!$insert) { echo "INSERT is NOT working!"; exit(); } echo $row['City'] . "<br />"; echo "<pre>"; echo print_r($row); echo "</pre>"; } //while ($rows = mysqli_fetch_array($results)) } //if (mysqli_num_rows($results)) else { echo "No results to get!"; } ?> Here is my all_illinois INSERT table structu CREATE TABLE IF NOT EXISTS `all_illinois` ( `state_id` varchar(255) NOT NULL, `city_name` varchar(255) NOT NULL ) ENGINE=MyISAM DEFAULT CHARSET=latin1; Here is my source table geo_cities structu CREATE TABLE IF NOT EXISTS `1` ( `CityId` varchar(255) NOT NULL, `CountryID` varchar(255) NOT NULL, `RegionID` varchar(255) NOT NULL, `City` varchar(255) NOT NULL, `Latitude` varchar(255) NOT NULL, `Longitude` varchar(255) NOT NULL, `TimeZone` varchar(255) NOT NULL, `DmaId` varchar(255) NOT NULL, `Code` varchar(255) NOT NULL ) ENGINE=MyISAM DEFAULT CHARSET=latin1; when i remove the action from the form it submits the post correctly if not it goes to the action url withoutposting Code: [Select] <form action="https://www.sandbox.paypal.com/cgi-bin/webscr" target="_top" method="post"> <input type="hidden" name="cmd" value="_s-xclick"> <input type="hidden" name="hosted_button_id" value="wwww"> <?php <input type="hidden" name="item_name" id="item_name" value="<?php echo $md5c;?>"> <input type="image" src="https://www.sandbox.paypal.com/en_US/i/btn/btn_paynowCC_LG.gif" border="0" name="submit" alt="Submit Form"> <img alt="" border="0" src="https://www.sandbox.paypal.com/en_US/i/scr/pixel.gif" width="1" height="1"> </form> <?php if(isset($_POST['submit_x']) || isset($_POST['submit_x'])) { //$Subscription_id = mysql_real_escape_string($md5c); $PropertyID = mysql_real_escape_string($rowData['ID']); $User_ID = mysql_real_escape_string($rowData['User_ID']); $item_name=mysql_real_escape_string($_POST['item_name']); //$query = 'INSERT INTO SP_subscriptions(id,) values("'.$item_name.'")'; $query = 'INSERT INTO SP_subscriptions(id,PropertyID,User_ID) values("'.$item_name.'","'.$PropertyID.'","'.$User_ID.'")'; $success = mysql_query($query); echo $query; } else echo 'POST nada'; var_dump($_POST); var_dump($query); ?> Hi - I have an HTML form which is dynamically produced using CodeIgniter / PHP and presents products a customer has ordered. When the customer has finished changing his quantities they must now submit the form. My problem is that my form will contain many of the same named fields for example, 'Product ID', or 'Product Name' or 'quantity'. So now when it gets processed a typical post array like product id could look like this: Code: [Select] Array ( [0] => 28 [1] => 24 [2] => 101 [3] => 23 [4] => 17 ) Of course I get an error: Quote Severity: Notice Message: Array to string conversion Filename: mysql/mysql_driver.php I really need some advice on how I should pre-process the various POST arrays so I can get them into my DB. A very grateful student of PHP ! Thanks This topic has been moved to Miscellaneous. http://www.phpfreaks.com/forums/index.php?topic=310661.0 Hey Guys. I am working with a form that shows the grand total on the checkout page. The value of the grand total is inside a hidden field. When click on submit, the _POST array doesn't get back the last value of the grand total. I need to hit the button twice to get the last value. The weird thing is when I echo the value of the grand total it display the latest value, but not with the POST array
For example. If the grand total is $10.00 and I click on submit. It will show the POST['grand_total'] as empty. If I click on submit again it will show the grand total of $10.00.
Below is my code that I am working with. Any help would be really appreciated.
if(isset($_POST['submit'])) {
/* Doesn't show if i put it after if($_POST['submit'] */
if(isset($_POST['grand_total'])) {
echo $_POST['grand_total'];
}
}
//A bunch of other html/php code. Another class calculates the subtotal assigns it the variable $subtotal
$cart_totals = new cartTotals($subtotal, $discounted_amount,$post_values->tip); // Cart class is shown below
/* Doesn't show if i put it before if($_POST['submit'] */
if(isset($_POST['grand_total'])) {
echo $_POST['grand_total'];
}
echo "<input name='grand_total' type='hidden' value='$cart_totals->grand_total' />"; // Shows the grand total after second from submission
echo "$cart_totals->grand_total"; // Shows grand total after the first submission
Cart Totals Class
class cartTotals {
public $subtotal;
public $sales_tax;
public $tip;
public $grand_total;
public $discount_amount;
public $href_page;
public $invalidCouponMessage;
const TEST_ENVIORMENT = FALSE;
/**
* [ Function gets constructed in the order summary where the [$discount_amount= ""] arg does need to be passed.
* But does get passed in when called on the checkout.php page. Therefore we set the default value to an empty string.]
* @param [float] $subtotal [subtotal get passed in from the parent class coreCartFunction]
* @param string $discount_amount [The class checkCouponCode calculates this discount amount based on the
* subtotal and the discount amount. It gets instantiated on the clients side and passed is this construction function.
* This is all done on the checkout page.]
*/
/*The way the construct function works is by invoking all the methods the passed arguments
When the methods get invoked the do all the work and set the properties its values. The properties then get echoed out
on the client side. */
function __construct($subtotal="", $discount_amount= "", $tip=""){
$this->subTotal($subtotal, $discount_amount);//SubTotal method takes the discount amount and subtracts it from the subtotal.
$this->salesTax($subtotal, $discount_amount);
$this->tip = $tip;
$this->grandTotal();
}
private function subTotal($subtotal,$discount_amount) {
$rounded_subtotal = round($subtotal-$discount_amount,2);
$money_format_subtotal = money_format('%i',$rounded_subtotal);
$this->subtotal = $money_format_subtotal;
}
private function salesTax($subtotal, $discount_amount =""){
$sales_tax = (STORE_SALES_TAX)?(float)STORE_SALES_TAX:8.875;
$sales_tax =(($this->subtotal)*$sales_tax)/100;
$sales_tax = round($sales_tax,2);
$this->sales_tax = $sales_tax;
}
public function Tip() {
//global $post_values;
//$last_tip_selected = $post_values->tip > 0 ? $post_values->tip : "" ;
$tip_output = "<select id='tip' name='tip'>";
for($tip=0.00; $tip<=11.75; $tip+=0.25){
if( $tip == "2") {$selected = " selected";} else {$selected ="";}
$formatted_tip = money_format('%i',$tip);
$tip_output .= "<option {$selected} id='selected_tip' value='$formatted_tip'>"."$".$formatted_tip ."</option>".PHP_EOL;
}
$tip_output .= "</select>";
return $tip_output;
}
private function grandTotal(){
$grand_total = round($this->sales_tax+$this->subtotal+$this->tip,2);
$grand_total_formatted = money_format('%i',$grand_total);
$this->grand_total = $grand_total_formatted;
}
hi ..
hit little snag Ive got html <form name="formx" method="POST" action="connect.php" class='ajaxform'> and about 4 varibles in that form .. now how to properly
query table users so i can find out which prefix correspond with that user
Insert into table "upis" in this case that prefix with 3 variables..
everything in single,.. in this case connect.php file
I know how to do QUERY and INSERT INTO but i don't know how to connect with 2 different tbl or db and do the query and input of data.. every time I put 2 of them together .. never works out..
this is example.. i dont know is this right way to do it .. When i click my submit button i am posting the following.
Array
(
[submitStaffOrder] =>
[staffMember] => Array
(
[0] => 2
[1] => ANYCHEF1
)
[date] => Array
(
[0] => 2020-02-18
[1] => 2020-02-18
)
[startTime] => Array
(
[0] => 11:01
[1] => 10:10
)
[finishTime] => Array
(
[0] => 11:01
[1] => 10:01
)
[delExisting] => Array
(
[0] =>
[1] => toDel
)
)
I would like to update/insert if delExisting is blank and delete if it has toDel in there. I have the following but i am pretty sure the if is not working.
$date = $_POST['date'];
$stime = $_POST['startTime'];
$ftime = $_POST['finishTime'];
$del = $_POST['delExisting'];
$staff = $_POST['staffMember'];
$stmt = $conn -> prepare("
INSERT IGNORE INTO ssm_staff_order (job_id, staff_id, staff_start_time, staff_finish_time, staff_start_date, staff_finish_date)
VALUES (?,?,?,?,?,?)
ON DUPLICATE KEY
UPDATE
staff_start_time = VALUES(staff_start_time),
staff_finish_time = VALUES(staff_finish_time);
");
$delstmt = $conn -> prepare("
DELETE FROM ssm_staff_order
WHERE staff_id = ?
AND job_id = ?
AND staff_start_date = ?
");
foreach ($staff as $key => $staffId) {
if ($del == '') {
$start = $date[$key].' '.$stime[$key];
$finish = $date[$key].' '.$ftime[$key];
$stmt -> bind_param('isssss', $jid, $staffId, $start, $finish, $date[$key], $date[$key]);
$stmt -> execute();
}
if ($del == 'toDel') {
$delstmt -> bind_param('sis', $staffId, $jid, $date[$key]);
$delstmt -> execute();
}
}
}
Can i do what i am trying to do or am i way off here?
I struggle with arrays Edited February 24, 2020 by AdamhumbugI want to remove the HTTP:// or HTTPS:// from the insert into the DB. The Viewer may put just www, or copy the entire URL with the HTTP:// or HTTPS://
I tried using the preg-replace but couldn't seem to get it to work.
Any other recommendation?
Thanks in advance,
Mike
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