PHP - Css Float Issues In Fluid Layout

Hi,

in Mysql have a row with FLOAT 10,2

In form put the number 20.20 and after reload in form show: 20.200000762939

I know I may sound like a nab, but here I go:

Code: [Select]
$ric=10;
$price=$price+($price/$ric);

Basically I want to add a 10% to the price value

this is inside a "for", and price values is taken from a csv file.

Said value is for example:
$price=4,36

after the script takes place, the value goes to:
$price=4796

While i aimed to obtain 4,80 (a 2 precision float).

Can anyone help me? It's the first time I mess with float numbers.

EDIT: Or at least direct me to a more efficient way to apply % on doubles, while preserving the original precision

Hey all,

I can not get utf-8 working properly.

I'm having issues with special characters, such as bullets, e with an accent over it, etc.

The data is being stored in my mssql database properly, and I can see everything there fine. It's when I grab it from the database and display it on my php page. The page it set up to utf-8, if I go to Tools>Page Info, it says encoding is utf-8. I have it in my headers, I just can not figure out why it will not display on the page.

Any thoughts?

Issue # 1
How can i send the values come from $_POST['name'],$_POST['number'] to an email address xyz@radiations3.com???

Issue # 2
I am trying to display data from four different tables with the following sql query:
(The problem is that the data is getting displayed fine but i don't know why some of the (same )data gets repeated two or three times where as i checked in all four tables and all the data exists one time not twice)
If anything wrong with my query kindly help

SELECT distinct *
FROM applicant,applicant_info_nic,room,student
WHERE applicant_info_nic.status='Available' and  applicant.appNIC=applicant_info_nic.appNIC and applicant.roomID=room.roomID and applicant.appNIC=student.appNIC
ORDER BY applicant.roomID

i am trying to sort out a session now,

i normally use the folllowing code to check if someone is logged in and if they are not to forward them to the login page,
but i am getting this message:

Notice: Undefined index: username in

code:
Code: [Select]
if ($_SESSION['username']) {
}else{
 include 'login.php';
 die("");
}

can someone help please.

Hello, I'm having troubles parsing text properly.  Whenever I submit data into a mysql db, and then call that specific data, in the text, I get this symbol,  �.  Does anybody know what it is or how to remove it?  I believe it's with utf-8 and me using a function that corrupts the string but I'm not sure.  Anybody have any clues?  Thanks in advance.

Hi, my name is Michael Vallier and I am the director of Killer Film Fest.  This year I have incorporated some new features and need some php help.  If you are able to help with either or both problems, please let me know.  Thanks in advance.

1.
I am using a forum and I need help customizing it.  I have no idea what I am doing.  I have changed a few things, but don't know enough to do what I want.  I don't need anything crazy, just to fit the look of our website. The forum is not open yet but you can see it he http://www.killerfilmfest.com/forum/

2.
I found a add-on to my website which is a file manager.  People can create an account and upload files to my FTP server.  I want to use this for filmmakers to upload their films if they choose to do it this way. There is a 10mb limit and it is possible to make it unlimited. I contacted the creator of the application and he led me to a wiki page with the directions.  It looked real simple and I tried to do this but without any luck.

So if there is anyone out there who can help, that would be great.  Thanks

-Michael Vallier-

Hey I'm having issues with using strtotime(), date(), and time().

I have a couple problems.
The first is: I used strtotime to get the unix of a specific date and time (worked great, even outputted the correct time using date() to return it). However when I went to post information on it (I set it up so that you can't post after the event started), it told me it already started like an hour before it was supposed to. I used Code: [Select]
if (time() > $event['when']) { echo "too late."; } else { do it } to determine.

That had me very confused.

Then I decided instead of manually inputting the event times I would pull them from an xml file, which I had no trouble reading.

I used: Code: [Select]
strtotime("Next $day, $time PM") with $day = Sun, $time = 1:00- This outputted a unix timestamp but then date() returned it as being 7 pm on sunday instead.

Any ideas what would be causing these strange things?

Hi,
I'm trying to convert a charting app to  OOP.
So here I've simplified it down to just the bare bones issue of drawing a line to a png image and displaying it.

Code: [Select]

<?php
 class chart {
  var $im;
  var $backgroundColor;
  var $textColor;
  function chart() {
    $this->im= @ImageCreate (100, 200) or die ("Cannot Initialize new GD image stream");
    $this->backgroundColor = ImageColorAllocate ($this->im, 224, 234, 234);
    $this->textColor = ImageColorAllocate($this->im, 233, 14, 91);
  }
 
  function display() {
    imageline ($this->im,0,0,100,200,$this->backgroundColor);
    imageline ($this->im,100,0,0,200,$this->textColor);

    ImagePng ($this->im);
  }
}
?>


Here is the code which instantiates the class.

Code: [Select]
<?php
  include "simple_draw.php";

$mychart = new chart();
$mychart->chart();
$mychart->display();

?>



Basically depending on how I rework it, one of two things happens: a)it generates a bunch of little boxes which say fffd, or b) I get a message saying the resource is invalid or nonexistent (this error isn't coming up right now so I can't be precise.)

If this is run outside the OOP environment it works fine. No sure. I'm really trying to work with classes but this kind of problem is frustrating and admittedly makes it tempting to just go back to regular functions.

Any ideas??

Thanks,
Jeff

I have this code that i tried running it on my phpmyadmin it works fine ,but  when i use it on my php code to query its not working.What could be the issue?

 SELECT * FROM `roombook` ORDER BY (CASE stat
   WHEN 'Checked in' 	 THEN 1
   WHEN 'Booked' 	 THEN 2
   WHEN 'Deposit Confirmation' 	 THEN 3
   WHEN 'Email/phone' THEN 4
   WHEN 'Checked Out' 	THEN 5
   ELSE 'Cancelled' END) ASC, stat ASC

 

As far as it goes for me I have the switch() working, but not to what im trying to do. This is for a "media" page where I have 3 different categories "Music", "Videos" and "Photos". I'm trying to get it so when you goto the "Media" page it will show just the 3 categories, that section works but it is also showing the sub categories for all them categories. So for what im trying to do is when viewing the "media" page, it will display the 3 categories, then when selecting the category it will display the "sub categories". and then when you select the "sub category" it will display the contents of that "sub category"

should i be trying to do this a different way? or do i have something wrong here? lol

here is my switch() code
Code: [Select]
<?php
 $cat = (isset($_GET["m_cat"])) ? (intval($_GET["m_cat"])) : 0;
 switch($_GET["b"]=="true")
{
default :
if("/ffy/media.php"==$_SERVER['PHP_SELF'])
{
echo "Select a Category";
}

case "false":
if($_GET["m_cat"]==$cat)
{

echo "<font size='3'>";
$dcat = mysql_query("SELECT * FROM media_sub_cat WHERE m_cat=$cat")
or die("mySQL Query Failed: " .mysql_error());

while($catrow = mysql_fetch_array($dcat)) {
list($id, $m_sub_cat, $m_cat) = $catrow;

echo ": <font class='myFont'><a href='media.php?b=true&cat=".$m_cat."&subcat=".$m_sub_cat."'>".$m_sub_cat."</a></font> ";
}
echo ":</font>";
echo "Work Damb You";
}
break;

case "true":
if($_GET["cat"]==$cat && $_GET["subcat"]==$m_sub_cat)
{

echo "Weird...";

}
break;
}
?>

i have two pages
form and submit page
index.php
Code: [Select]
<?php 
error_reporting(E_ALL);
$bauturi = array('bauturi_alcoolice'=>'Bauturi alcoolice','sucuri'=>'Sucuri','bauturi_racoritoare'=>'Bauturi racoritoare'); 
echo '<form action="post.php" method="post">';

echo'<select name="bauturi">'; 

foreach($bauturi as $let=>$word){ 
    echo'<option value="'.$let.'">'.$word.'</option>'; 
} 
echo'</select>';
echo '<INPUT type="submit" value="show me money">

</form>';
?> post.php
Code: [Select]
<?php 
error_reporting(E_ALL);

$drop = $_REQUEST['bauturi']; 
echo $drop;
?>if i select Bauturi alcoolice on post.php page i get bauturi_alcoolice
but i want to get Bauturi alcoolice as result

i tried to use foreach like this
Code: [Select]
<?php 
error_reporting(E_ALL);

$drop = $_REQUEST['bauturi']; 
$bauturi = array('bauturi_alcoolice'=>'Bauturi alcoolice','sucuri'=>'Sucuri','bauturi_racoritoare'=>'Bauturi racoritoare'); 
foreach($bauturi as $drop=>$word){ 
echo $word;
echo "<br/>";
unset($word);
}
?>
but i get all the values in the form
i only want to show the selected value from the form in post.php page

thanks in advance

This topic has been moved to CSS Help.

http://www.phpfreaks.com/forums/index.php?topic=327118.0

Hi Guys,
             Beginner needs help with accommodation search feature...i have two drop downs(area and type), each one has an 'any' option. I cant evalute the 'any' options directly against the database so have written this:

Code: [Select]
<?php
                
                //query database
if ($_SESSION['type']== 'any' && $_SESSION['area']== 'any'){
    $query = mysql_query("SELECT * FROM hotels Order by RAND() ");
   
}
elseif ($_SESSION['area'] == 'any' && $_SESSION['type'] != 'any'){
    $query = mysql_query("SELECT * FROM hotels WHERE type = $_SESSION[type] Order by RAND()");
}
elseif ($_SESSION['type'] == 'any' && $_SESSION['area'] != 'any'){
    $query = mysql_query("SELECT * FROM hotels WHERE location =$_SESSION[area] Order by RAND()");
}

else{
    $query = mysql_query("SELECT * FROM hotels WHERE location ='$_SESSION[area]' AND type ='$_SESSION[type]' Order by RAND()");
}
    

//show results
while ($search_result = mysql_fetch_assoc($query)) 
{
  echo '<b>'.$search_result[name] . '</b><br>';
  echo '<p><img src="'.$search_result['photo1'].'" /></p>';
  echo '<p><img src="'.$search_result['award'].'" /></p>';
  echo $search_result[description] . '<br><br>';
}?>
The first if and last else return the correct info from database but the middle two elseif's throw this error: Warning: mysql_fetch_assoc() expects parameter 1 to be resource, boolean given....
I have commented out the queries and replaced them with simple echoes and they all seem to evaluate correctly!. So im lost why $query isnt assigned in the middle two elseif's ??

Any ideas what im doing wrong and is there a better way.
Cheers!!

Now I am getting:

Use of undefined constant  - assumed 'cust_no' in C:\wamp\www\flow\query\111.php on line 25

Use of undefined constant office - assumed 'office' in C:\wamp\www\flow\query\111.php on line 26

Use of undefined constant fname - assumed 'fname' in C:\wamp\www\flow\query\111.php on line 30

Use of undefined constant lname - assumed 'lname' in C:\wamp\www\flow\query\111.php on line 31

In the browser when I go to this file....what am I missing? Please see my simple code....basically, I'm just trying to pull data from a MySQL database to view in a browser & I think I am either missinh a " or ' or need to add one somewhere......thanks

Code: [Select]


<html
<head>
<?php
require('connection.php');

if (isset($_GET['op']) && $_GET['op'] == "d") 
if($_GET['op'] == "d" && !empty($_GET['id']) )
{

   $result = mysql_query($query) or die(mysql_error());  
}

$query="SELECT fid, cust_no, fname, lname, office FROM psrinfo";
$result = mysql_query($query) or die(mysql_error());  
 
while($row = mysql_fetch_array( $result )) {
?>
 
<?php } 

echo '<form action="111.php" method="post">

<table width="75%" border="1">
<tr>
<td><b>Customer No:</b> <br><input type="text" name="cust_no" size="25" maxlength="30" value="'. $row[cust_no] .'" /><br> </td>
<td><b>Office:</b> <br><input type="text" name="office" size="25" maxlength="30" value="'. $row[office] .'" /><br> </td> 
</tr>

<tr>
<td><b>Customer First Name:</b> <br><input type="text" name="fname" size="25" maxlength="30" value="'. $row[fname] .'" /><br> </td>
<td><b>Customer Last Name:</b> <br><input type="text" name="lname" size="25" maxlength="30" value="'. $row[lname] .'" /><br> </td>
</tr>

</table>
</form>';
mysql_close(); // Close the database connection.
?>           
 </tbody>
 </table>