PHP - Added Data In Todo List Is Not Visible Without Refreshing

This topic has been moved to JavaScript Help.

http://www.phpfreaks.com/forums/index.php?topic=323252.0

I'm pulling data from an xml file and I'm getting a lot of duplicates. How can I remove the duplicates from the query?

Code: [Select]
foreach($xml->category->subcategory as $category){
echo $category[id];
}//end foreach

Hi everyone, im looking for some help if anyone can offer it.

I currently run a phpbb Playstation3 gaming forum and was looking for a way to show forum members online status info on a seperate page on my forum.

I found some php script that pulls the freinds list data from the URL mentioned in the code, for now it only works on my local host and i get errors when trying to run it from my live server.

here is the current code:
Code: [Select]
<?php


error_reporting(E_ALL);


libxml_use_internal_errors(true);
$fp = fopen("curl_log.txt",'a+');  //Logging purposes only

$dataURL     = "https://secure.eu.playstation.com/ajax/mypsn/friend/presence";
$loginURL     = "https://store.playstation.com/external/login.action?returnURL=https://secure.eu.playstation.com/sign-in/confirmation";


$cc = curl_init();

getData();

function getData()
{
   
   global $cc,$fp,$dataURL;
   
   curl_setopt ($cc, CURLOPT_URL, $dataURL);
   curl_setopt ($cc, CURLOPT_POST, 0);
   curl_setopt ($cc, CURLOPT_RETURNTRANSFER, 1);
   curl_setopt ($cc, CURLOPT_FOLLOWLOCATION, 1);
   curl_setopt ($cc, CURLOPT_USERAGENT, 'Mozilla/5.0 (Macintosh; U; Intel Mac OS X 10.5; en-US; rv:1.9.1.7) Gecko/20091221 Firefox/3.5.7');
   curl_setopt ($cc, CURLOPT_SSL_VERIFYPEER, 0);
   curl_setopt ($cc, CURLOPT_REFERER, $dataURL);
   curl_setopt ($cc, CURLOPT_VERBOSE, 1);
   curl_setopt ($cc, CURLOPT_STDERR, $fp);
   curl_setopt ($cc, CURLOPT_COOKIEFILE, 'cookie.txt');

   $output = curl_exec($cc);

   $xml = simplexml_load_string($output);

   if (!$xml)
   {
       login();
   }
   else
   {
       
              // Here you will have a simpleXML object that you can do with as you please - example output below.

               foreach($xml->psn_friend as $friend)
       {
           $img_loc = str_replace("//", "/", $friend->current_avatar);
   echo "<img src=\"https://secure.eu.playstation.com".$img_loc."\"/>&nbsp;";
echo "<font color=\"red\">$friend->onlineid</font>&nbsp;<br />";
echo "Status : ".$friend->current_presence."<BR />";
           echo "Game : ".$friend->current_game."<BR />";
           echo "Comment : ".$friend->Comment."<BR />";
   
           echo "<BR /><BR />";
       }
       
       curl_close($cc);
       fclose($fp);    
   }
}

function login()
{
   global $cc,$loginURL;
   
   curl_setopt ($cc, CURLOPT_URL, $loginURL);
   curl_setopt ($cc, CURLOPT_POST, 1);
   curl_setopt ($cc, CURLOPT_POSTFIELDS, 'loginName=<username@user.com>&password=<password>');
   curl_setopt ($cc, CURLOPT_COOKIEJAR, 'cookie.txt');
   
   curl_exec($cc);
   
   getData();
}

?>
The error i mentioned above is related to the Code: [Select]
curl_setopt ($cc, CURLOPT_FOLLOWLOCATION command, im not to concerned about that at the moment.

Im looking for someone to help me with the actually XML object, its very basic and i would, if poss, love to have it looking like the actual PSN freinds list. Here are images of this codes output and the actuall Freinds list.

Codes Ouput:


Actuall PSN FR:


Would it be possable to actually grab the exact image from the actuall playstation site, as above? or could the online/offline icons be added to the above code with a background image?

I hope i have explained the above clearly, if theirs any thing anyone is unsure of please dont hesitate to ask.

Hopefully someone can help.

Thanks, Lee

I am brand new to PHP but, after using W3 Schools,  can retrieve a record from a MySQL database using php & SQLi.    I have a page with a list of between 20 and 30 items down one side and a panel on the other. When a user clicks a list item I want to display the details of the clicked item in the panel. The details a Program (text), Convenor (text), Dates (text), Times (Text), Location (text), Notes (Text large).    The details are stored in a MySQL Database 'Documents', in a table 'Programs' and I would like to put the details into text boxes in the panel.   Could you point me to some info on doing this please? Thanks  

please help me the concept or code to retrive data from the database and display data according to the data from the dynamic list box option.

Hi,

I am hoping someone can help me out with a slight issue I have with php and mySQL.

I have an ajax-powered form with a select (dropdown) field populated through a php function. Based on the user-selected values in this field, data is displayed on the webpage; i.e. selected value 1 returns values x and y on the page. I am now trying to call additional data (value z) from a different table in the same database, and as before, use the selected values from the dropdown to display the data.

For some reason, value z is not changing according to the user-selected value.

This is my code:

[The function to populate the select field]

Code: [Select]
function kfl_get_funds_names()
{
$result = array();
$result['CDF'] = 'Crosby Dragon Fund';
$result['CPF'] = 'Crosby Phoenix Fund';
$result['AMZPIF'] = 'AMZ Plus Income Fund';
$result['KASBIIF'] = 'KASB Islamic Income Opportunity';
$result['KASBCPGF'] = 'KASB Capital Protected Gold Fund';
$result['KASBLF'] = 'KASB Income Opportunity Fund';
$result['KASBCF'] = 'KASB Cash Fund';
$result['KASBBF'] = 'KASB Asset Allocation Fund';
$result['KASBSMF'] = 'KASB Stock Market Fund';

return $result;
}
[the code calling and using the function to interact with the database]

Code: [Select]
$funds_to_display = kfl_get_funds_names();
$current_symbol = key( $funds_to_display );
$current_nav_rates = kfl_get_latest_rates( $current_symbol );
[the code calling additional data, value z, from the database, and using the info in the select field to filter it]
Code: [Select]
$cutoff = kfl_cutoff( $current_symbol );
The display of each of these items is as follows:

Code: [Select]
<?php echo $current_nav_rates['nav_date']; ?>
<?php echo $funds_to_display[$current_symbol]; ?>
<?php echo $cutoff['cutoff']; ?>
I can't get the $cutoff code to display the correct values. It picks up the first symbol to display and doesn't change with user selection. The code for the selection box, by the way:

Code: [Select]
<select id="dailynav-funds" autocomplete="off" name="dnf">
<?php
foreach ($funds_to_display as $fund_symbol => $fund_name)
{
echo '<option';
if( $fund_symbol == $current_symbol ) {
echo ' selected="selected"';
}
echo ' value="' . $fund_symbol . '">';
echo $fund_name;
echo '</option>';
}
?>
</select>
I've tried to get data using $_GET['dnf'] into the cutoff code, but that throws up parse errors. What am I doing wrong, and how can I resolve this issue?

Thanks in advance!

Hi pals,
I got a complex Array from the Query. it's Structure is like

Quote

Array
(
    => Array
        (
            [server_name] => anes.admod.net
            [id] => 1
            [server_id] => 1
            [description] => nice Anes Server
            [status] => 0
            [max_down_count] => 9
            [check_interval] => 15
            [fail_recheck] => 6
            [log_retain] => 1
            [warning] => 12
            [critical] => 15
            [timeout] => 8
            [audible] => Y
            [email] => Y
            [im] => Y
            [sms] => Y
            [rss] => N
            [rssid] =>
            [vcare] => Y
            [created] => 2010-12-06 10:26:26
            [last_update] => 2010-12-13 16:41:48
            [name] => POP3
            [port] => 110
            [okay] => OK
            [warn] => WARNING
            [crit] => CRITICAL
            [down] => Connection refused
            [advanced] => N
            [typestatus] => 1
        )

    [1] => Array
        (
            [server_name] => neseema.admod.net
            [id] => 2
            [server_id] => 2
            [description] => another server
            [status] => 1
            [max_down_count] => 11
            [check_interval] => 15
            [fail_recheck] => 12
            [log_retain] => 2
            [warning] => 12
            [critical] => 16
            [timeout] => 6
            [audible] => Y
            [email] => Y
            [im] => Y
            [sms] => N
            [rss] => N
            [rssid] =>
            [vcare] => N
            [created] => 2010-12-07 10:27:42
            [last_update] => 2010-12-13 16:41:48
            [name] => Cpanel
            [port] => 2082
            [okay] => OK
            [warn] => WARNING
            [crit] => CRITICAL
            [down] => Connection refused
            [advanced] => N
            [typestatus] => 1
        )

    [2] => Array
        (
            [server_name] => anes.admod.net
            [id] => 3
            [server_id] => 1
            [description] => nice Anes Server another Service
            [status] => 1
            [max_down_count] => 14
            [check_interval] => 15
            [fail_recheck] => 3
            [log_retain] => 3
            [warning] => 12
            [critical] => 16
            [timeout] => 18
            [audible] => Y
            [email] =>
            [im] =>
            [sms] =>
            [rss] => N
            [rssid] =>
            [vcare] => N
            [created] => 2010-12-07 12:58:01
            [last_update] => 2010-12-13 16:41:48
            [name] => SMTP
            [port] => 25
            [okay] => OK
            [warn] => WARNING
            [crit] => CRITICAL
            [down] => Connection refused
            [advanced] => N
            [typestatus] => 1
        )

)


In this Result I have 2 Rows in result to show, I mean I need to merge the data of First (0th) and Third(2nd) element because it display the
data of same item. So How it can done, I am working in that whole day but not get a solution fully.... I saw a near solution like :


<?php
 
$input = array(
 
                0 => array ( 'id' => 160, 'payment_period' => 'Monthly', 'plan_payment_type_id' => 171, 'payment_type_id' => 4), 
                1 => Array ( 'id' => 160, 'payment_period' => 'Monthly', 'plan_payment_type_id' => 172, 'payment_type_id' => 5), 
                2 => Array ( 'id' => 161, 'payment_period' => 'Weekly', 'plan_payment_type_id' => 173, 'payment_type_id' => 9), 
                );  

echo "<pre>"; 
print_r($input);
echo "</pre>";  
echo "****************************************************************************";
$output = array();
$id_array = array();
$i = 0;
foreach($input as $key=>$val) {
        if(array_key_exists($val['id'],$id_array)) {
                $pos = $id_array[$val['id']];
                $output[$pos]['payment_types'][] = array('plan_payment_type_id'=> $val['plan_payment_type_id'],'payment_type_id' => $val['payment_type_id']);
        } else {
                $output[$i] = array('id' => $val['id'],'payment_period' => $val['payment_period'],'payment_types' => array(array('plan_payment_type_id'=> $val['plan_payment_type_id'],'payment_type_id' => $val['payment_type_id'])));
                $id_array[$val['id']] = $i; 
                $i++;
        }   
}
echo "<pre>"; 
print_r($output);
echo "</pre>";  
?>




But I cannot handle it nicely, please give any sample or helping code idea for same , waiting your immediate Reply

Thankfully
Anes P.A 

I have a form created with code already written. I am in need of a push in the right direction or a potential tutorial on this issue i have. I am running a fanatsy golf website where the user will pick one golfer each week and the cannot select them again. Is there a way I can remove that data from the list for the next week when the user makes his selection or can I have that data another color and unselectable. If you want code, please let me know and i can provide it. Thanks in advance for your help.


p.s. the list data is stored in a MySQL database.

I am getting an error on line 3 for the original code, so I need help there, but what I do have a question on is this:

http://kaboomlabs.com/PDI/test2.php

Code: [Select]

 <?php
$dbc = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD, DB_NAME)
$result = $mysqli_query("SELECT * FROM comp");

      echo "<SELECT name='comp'>\n";
      while($row = $result->fetch_assoc()) {
         echo "<option value='{$row['name']}</option>\n";   
      }
      echo "</select>\n";

      $result_close();

      ?>

What  I am attempting to do is two fold.

1. Using PHP create a pull down menu that grabs data from the database.

2.  Have something in where after line three there is a dotted break, and then the rest of the list is shown.

There are over 150 entities that go into this database, so the top 3 are going to be the most used, the rest are going to be in alphabetical order.

Now the database has a auto-increment numbering system, the company name, address, phone number, and email if possible. I only want it to show the company name.

Is this possible at all? 

I have a mysql table with the structure of
Code: [Select]
ID  Menu_Name   Parent_ID
1   Finance     NULL
2   Business    NULL
3   Investment  1
4   Trading     2
How can I create a html <ul><li> list based on the parent?

Hi? im just a beginner in php i just want to ask how to insert a data into a table from a dropdown list. I have concatenate the itemid and description to form the dropdown list. But when i viewed my item_table the itemid and description columns are null. can you help me with this..
this is my php code for the dropdown list...
         <?php
         $query = "SELECT CONCAT(itemid,' ', '-',' ', description) AS Item FROM item_table";
         
         $result = mysql_query($query) or die(mysql_error());
         
         $dropdown = "<SELECT CONCAT(itemid,' ' '-',' ', description) AS Item FROM item_table>";

         while($row = mysql_fetch_assoc($result)) {

         $dropdown .= "\r\n<option value='{$row['Item']}'>{$row['Item']}</option>";

         }
         $dropdown .= "\r\n</select>";

         echo $dropdown;
         ?>

this my code for inserting data into the item_table...

<?php
if(isset($_POST ['submit']))
{
   $itemid = $_POST['itemid'];
   $description = $_POST['description'];
   $datein  = $_POST['datein'];
   $qtyin  = $_POST['qtyin'];
   $unitprice  = $_POST['unitprice'];
   $unit  = $_POST['unit'];
   $category  = $_POST['category'];
   $empid = $_POST['empid'];   
   $message ='';   
   if(($itemid && $description == "")||($itemid && $description == null))
   {
         header("location:IncomingEntry.php?msg=Incorrect");
         exit();
   }
   else
   {
      $link = mysql_connect('localhost', 'root', '') or die(mysql_error());
      $db_selected = mysql_select_db('inventory', $link);
      $message='';      
      $query = "INSERT INTO incoming_table (itemid , description,  datein,  qtyin, unitprice, unit, category, empid) VALUES ('".$itemid."',  '".$description."', '".$datein."',  '".$qtyin."', '".$unitprice."', '".$unit."', '".$category."', '".$empid."')";
      
      if (!mysql_query($query,$link))
      {
        die('Error: ' . mysql_error());
      }
      header("location: IncomingEntry.php?msg=1 record added");   
   }
}
?>

 

could anyone please help me with the code which is i have already displayed data as a multi select list but now i need to select one or more from them and insert into another database table. would be appreciate your help. thanx

Hi guys, basically here pull out the data from database then creating taxt field automatically and submit into anther table. everything works fine but data not inserting in to the table. could you guys check my code please?


 <?php

$con = mysql_connect("localhost","root","");

mysql_select_db("uni", $con)or trigger_error('MySQL error: ' . mysql_error());
?>
<?php
$result  = mysql_query("SELECT * FROM course") or trigger_error('MySQL error: ' . mysql_error());


echo '<select name ="cid[]">';

while($row = mysql_fetch_array($result))
{

    echo '<option value="' . $row['CourseID'] . '">'. $row['CourseID'] .'</option>';
}

echo '</select>';
//------------------
?>
   
 <?php
if(!empty($_POST["submit"]))
{
 $value = empty($_POST['question']) ? 0 : $_POST['question'];
?>
 <form name="form1" method="post" action="result.php">
 <?php


 for($i=0;$i<$value;$i++)
 {
  echo 'Question NO: <input type="text" name="qno[]" size="2" maxlength="2" class="style10">&nbsp;&nbsp;&nbsp;&nbsp;
        Enter Marks: <input type="text" name="marks[]" size="3" maxlength="3" class="style10"><br>';
  }


?>
  <label> <br />
  <br />
  <input type="submit" name="Submit" value="Submit" class="style10">
  </label>
 </form>
<?php
 }
else{
?>

<form method="POST" action="#">


 
<label>
<span class="style10">Enter the Number of Question</span>
<input name="question" type="text" class="style10" size="2" maxlength="2"> 
</label>
<input name="submit" type="submit" class="style10" value="Submit">

 
</form>
<?php }?>


result.php
<?php
 

$con = mysql_connect("localhost","root","") or die('Could not connect: ' . mysql_error());
mysql_select_db("uni",$con) or die('Could not connect: ' . mysql_error());

foreach ($_POST['cid'] as $c) {$cid [] = $c;}
foreach($_POST['qno'] as $q){$qno[] = $q;}
foreach($_POST['marks'] as $m){$marks[] = $m;}
$ct = 0;
for($i=0;$i<count($qno);$i++)
{

 $sql="INSERT INTO examquesion (CourseID,QuesionNo,MarksAllocated) VALUES('$cid[$i]','$qno[$i]','$marks[$i]')";
 mysql_query($sql,$con) or die('Error: ' . mysql_error());
 $ct++;
 }
echo "$ct record(s) added";
mysql_close($con)
?>

I am trying to convert and old website from mysql database to sqlite. One of the chores it must do is collect information from the database and put it in a list/menu select box on a page so the user can choose which item to pursue.   In the following (incomplete) snippit, I am doing something incorrectly because the sql query does get the proper information (I can put it in a table on the page just fine). But I'm having trouble getting the information into the select options on a list/menu. It appears to be putting them all, one after the other in the first option spot. The last one seems to be the only one of 6 or 7 that shows up.   It's been 10 or 12 years since I've messed with php, so I think I'm way behind... any help would be appreciated.   --------------------------- <form action="sqlPropDisplay.php" method="post" id="Residential">