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PHP - Google Charts
My wife is a Type 1 diabetic and I am trying to put a site together where she can record her blood/glucose readings and analyse the readings.
I am trying to use Google Charts to create a line graph so that she can see if their is a trend during the day when her blood sugar levels peak and trough. But my coding isn't providing any results.
Can anyone see what I am doing wrong?
<?php
$level=DB::getInstance()->query("SELECT * FROM tabbyhealth WHERE reading!=0");
foreach ($level->results() as $levelresults)
$glucose = $levelresults->reading;
$timestamp = date('d M Y h.i A',strtotime($levelresults->timestamp) +18000);
?>
<head>
<script type="text/javascript" src="https://www.google.com/jsapi"></script>
<script type="text/javascript">
google.load('visualization', '1.0', {'packages':['corechart']});
google.setOnLoadCallback(drawChart);
function drawChart() {
var data = new google.visualization.DataTable();
data.addColumn('string', 'Time of Reading');
data.addColumn('number', 'Blood Glucose Reading');
data.addRows([
['<?php echo $timestamp; ?>', '<?php echo $glucose; ?>']
]);
var options = {
title:'Blood Glucose Monitoring',
curveType: 'function',
legend: { position: 'bottom' }
width:600,
height:300
hAxis: {
title: 'Date/Time'
},
vAxis: {
title: 'Reading'
}
};
var chart = new google.visualization.LineChart(document.getElementById('chart_div'));
chart.draw(data, options);
}
</script>
</head>
<body>
<div id="chart_div"></div>
</body>
I have even tried replacing
data.addRows([
['<?php echo $timestamp; ?>', '<?php echo $glucose; ?>']
]);
with
data.addRows([
[0, 0, 0], [1, 10, 5], [2, 23, 15],
[3, 17, 9], [4, 18, 10], [5, 9, 5],
[6, 11, 3], [7, 27, 19], [8, 33, 25]
]);
to see if it is just a problem with reading from my database, but I am still getting nothing - by nothing I mean that no chart is appearing.
Similar TutorialsHello, I am new to pHp and javascript languages and I am trying to do some math calculations in pHp, then display the results with google charts. However, I got stuck with inserting data from pHp using json_encode. It works for the most simple array, with using 2 values. When using array of arrays, it does not work. I believe it could be a syntax errors with all those brackets but I could not figure it out. Thanks for any ideas!
<?php
// some arrays with dim 2x2
$testarr0 = array( 0.1, 2.5);
$testarr = array( 1.0, 3.5);
$testarr = array( $testarr0, $testarr ) ;
// this is how it looks in pHp
$json = json_encode($testarr);
echo($json);
echo '<br/>';
echo json_encode($json);
?>
<html>
<head>
<script type="text/javascript" src="https://www.gstatic.com/charts/loader.js">
</script>
<script type="text/javascript">
google.charts.load('current', {'packages':['line']});
google.charts.setOnLoadCallback(drawChart);
function drawChart() {
var data = new google.visualization.DataTable();
data.addColumn('number', 'x values');
data.addColumn('number', 'y1 ');
//var dataArray = <?php echo json_encode($testarr);?>;
//document.body.innerHTML = " Data Array with json: " + dataArray ;
// defining array here works well
/* data.addRows(
[
[0.1 ,2.5],
[1.0 ,3.5]
]
);
*/
// this here does not work:
data.addRow(
<?php echo json_encode($testarr);?>
);
// some options for the chart
var options = {
chart: {
title: 'Points over time',
},
width: 600,
height: 400,
axes: {
x: {
0: {side: 'top'}
}
}
};
var chart = new google.charts.Line(document.getElementById('line_top_x'));
chart.draw(data, google.charts.Line.convertOptions(options));
}
</script>
</head>
<body>
<div id="line_top_x" style="width: 900px; height: 500px"></div>
</body>
</html>
Good morning,
I am doing a small project including google charts API but I am having trouble getting my results into the json format that is required.
Google's documentation states the json format should be:
{
"cols": [
{"id":"","label":"Topping","pattern":"","type":"string"},
{"id":"","label":"Slices","pattern":"","type":"number"}
],
"rows": [
{"c":[{"v":"Mushrooms","f":null},{"v":3,"f":null}]},
{"c":[{"v":"Onions","f":null},{"v":1,"f":null}]},
{"c":[{"v":"Olives","f":null},{"v":1,"f":null}]},
{"c":[{"v":"Zucchini","f":null},{"v":1,"f":null}]},
{"c":[{"v":"Pepperoni","f":null},{"v":2,"f":null}]}
]
}
the query works perfectly fine thats not the problem but getting it into the above format is proving hard than I expected. The below is what I am trying to do to populate the json data in the correct format.
function graphdata()
{
$array['cols'][] = array('type' => 'string');
$array['cols'][] = array('type' => 'string');
$array['cols'][] = array('type' => 'string');
$result = sqlsrv_query($conn, $query);
while($row = sqlsrv_fetch_object($result)){
$array['rows'][] = array('c' => array( array('v'=>'$row->DateCreated->format('d-m-Y')'), array('v'=>$row->UnitPrice)) );
}
return $array;
}
print json_encode(graphdata());
I am using MSSQL and not the normal mysql hence the above code, i am a starter when it comes to php so I may be doing something basic totally wrong but I cannot seem to get it to work.
Thanksmy value, selectname.push(element.name); selectqty.push(element.qty); How to pass Google charts function,
$.each(data, function(index, element) {
selectname.push(element.name);
selectqty.push(element.qty);
google.charts.load('current', {
'packages': ['corechart']
});
google.charts.setOnLoadCallback(drawChart);
function drawChart() {
var data1 = google.visualization.arrayToDataTable([
['Task', 'Hours per Day'],
['Work', 11],
['Eat', 2],
['Commute', 2],
['Watch TV', 2],
['Sleep', 7]
]);
// var data1 = google.visualization.arrayToDataTable([
// [element.name, element.qty],
// //
// ]);
var options = {
title: 'Top 5 Best Selling Products'
};
var chart = new google.visualization.PieChart(document.getElementById('piechart'));
chart.draw(data1, options);
}
Hi, Ihave the below array output from a DB query. I need to convert into the bottom array for Google CHarts. Any ideas? $myarray = array( 0 => array( 'year' => 2009, 'month' => "January", 'month_sales' => 524, 'year_totalsales' => 3610 ), 1 => array ( 'year' => 2009, 'month' => 'February', 'month_sales' => 521, 'year_totalsales' => 3610 ), 2 => array ( 'year' => 2009, 'month' => 'March', 'month_sales' => 501, 'year_totalsales' => 3610 ), 3 => array ( 'year' => 2009, 'month' => 'April', 'month_sales' => 601, 'year_totalsales' => 3610 ), 4 => array ( 'year' => 2009, 'month' => 'May', 'month_sales' => 710, 'year_totalsales' => 3610 ), 5 => array ( 'year' => 2009, 'month' => 'June', 'month_sales' => 801, 'year_totalsales' => 3610 ), 6 => array ( 'year' => 2009, 'month' => 'July', 'month_sales' => 991, 'year_totalsales' => 3610 ), 7 => array ( 'year' => 2009, 'month' => 'August', 'month_sales' => 301, 'year_totalsales' => 3610 ), 8 => array ( 'year' => 2009, 'month' => 'September', 'month_sales' => 250, 'year_totalsales' => 3610 ), 9 => array ( 'year' => 2009, 'month' => 'October', 'month_sales' => 322, 'year_totalsales' => 3610 ), 10 => array ( 'year' => 2009, 'month' => 'November', 'month_sales' => 621, 'year_totalsales' => 3610 ), 11 => array ( 'year' => 2009, 'month' => 'December', 'month_sales' => 691, 'year_totalsales' => 3610 ), 12 => array ( 'year' => 2010, 'month' => "January", 'month_sales' => 789, 'year_totalsales' => 1610 ), 13 => array ( 'year' => 2010, 'month' => "February", 'month_sales' => 1409, 'year_totalsales' => 1610 ), 14 => array ( 'year' => 2010, 'month' => "March", 'month_sales' => 550, 'year_totalsales' => 1610 ) ); raw_data=[['January',524,0],['February',521,0],['March',501,0],['April',601,0],['May',710,0],['June',801,0], ['July',991,0],['August',301,0],['September',250,0],['October',322,0],['November',621,0],['December',691,0],['January',789,0],['February',1409,0],['March',550,0],]; raw_data= [ [ month1 , year1 sales figure(zero if no figure), year2 sales figure(zero if no figure).....], [ month1 , year1 sales figure(zero if no figure), year2 sales figure(zero if no figure).....]......]; Thanks all Hi
I am trying to create a google chart from data in query.php and using the google api to load it. Everything works until I want to change the MetalSourceID from a drop select box.
PHP CODE FOR DROP DOWN BOX:
<form>
<select name="users" onchange="showUser(this.value);drawChart();">
<option value=""> Select a Metal: </option>
<?php
$query = "SELECT TOP(31) tblMetalPrice.MetalSourceID, tblMetalSource.MetalSourceName from tblMetalPrice INNER JOIN tblMetalSource ON tblMetalPrice.MetalSourceID=tblMetalSource.MetalSourceID ORDER BY tblMetalPrice.DateCreated DESC ";
$result = sqlsrv_query( $conn, $query);
while( $row = sqlsrv_fetch_object ($result)) {
echo "<option value='".$row->MetalSourceID ."'>". $row->MetalSourceName ."</option>";
}
sqlsrv_close( $conn);
?>
</select>
</form>
This works fine and generates all the correct values. One part of this changes contents of a table which works fine. But I also echo the MetalSourceID into the javascript for the google api, JS script below:
<script type="text/javascript">
google.load('visualization', '1', {'packages':['corechart']});
google.setOnLoadCallback(drawChart);
function drawChart() {
var jsonData = $.ajax({
url: "query.php",
dataType:"json",
async: false,
data: { 'MetalSourceID' : <?php $q = intval($_GET['q']); echo $q; ?> }
}).responseText;
var data = new google.visualization.DataTable(jsonData);
var chart = new google.visualization.LineChart(document.getElementById('chart_div'));
chart.draw(data);
}
</script>
This then runs the query.php script and returns the google line chart, a copy of the query.php script is below:
i've to populate google charts with dynamic data. the data looks llike. +----+-------+---------+-------+-----------+---------+------+ | id | name | physics | maths | chemistry | biology | sst | +----+-------+---------+-------+-----------+---------+------+ | 1 | Name1 | 10 | 25 | 35 | 42 | 62 | | 2 | Name2 | 80 | 45 | 45 | 45 | 25 | | 3 | Name3 | 63 | 25 | 63 | 36 | 36 | | 4 | Name4 | 82 | 36 | 75 | 48 | 42 | | 5 | Name5 | 45 | 45 | 78 | 25 | 24 | | 6 | Name6 | 36 | 36 | 15 | 75 | 36 | | 7 | Name7 | 99 | 45 | 24 | 24 | 45 | | 8 | Name8 | 45 | 85 | 85 | 85 | 96 | +----+-------+---------+-------+-----------+---------+------+ i have to create google charts based on this such that # namewise - such that when i select a name it displays all subject marks of that particular name in a column chart #markswise - when i select a subject, it displays all the names with marks in that particular subject. conisdiering that data may be added and i've to accumulate that also, for namewise i did
// chart.php
<?php
include("connection.php");
$query = "SELECT name FROM csv GROUP BY name DESC";
$statement = $connect->prepare($query);
$statement->execute();
$result = $statement->fetchAll();
?>
<!DOCTYPE html>
<html>
<head>
<title>Google charts</title>
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css">
<script src="https://code.jquery.com/jquery-1.12.4.js"></script>
</head>
<body>
<br /><br />
<div class="container">
<div class="panel panel-default">
<div class="panel-heading">
<div class="row">
<div class="col-md-9">
<h3 class="panel-title">Student Wise Marks Data</h3>
</div>
<div class="col-md-3">
<select name="name" class="form-control" id="name">
<option value="">Select Student</option>
<?php
foreach($result as $row)
{
echo '<option value="'.$row["name"].'">'.$row["name"].'</option>';
}
?>
</select>
</div>
</div>
</div>
<div class="panel-body">
<div id="chart_area" style="width: 1000px; height: 620px;"></div>
</div>
</div>
</div>
</body>
</html>
<script type="text/javascript" src="https://www.gstatic.com/charts/loader.js"></script>
<script type="text/javascript">
google.charts.load('current', {packages: ['corechart', 'bar']});
google.charts.setOnLoadCallback();
function load_student_data(name, title)
{
var temp_title = title + ' '+name+'';
$.ajax({
url:"fetch.php",
method:"POST",
data:{name:name},
dataType:"JSON",
success:function(data)
{
drawStudentwiseChart(data, temp_title);
}
});
}
function drawStudentwiseChart(chart_data, chart_main_title)
{
var jsonData = chart_data;
var data = new google.visualization.DataTable();
data.addColumn('number', 'Physics');
data.addColumn('number', 'Maths');
data.addColumn('number', 'Chemistry');
data.addColumn('number', 'Biology');
data.addColumn('number', 'SST');
$.each(jsonData, function(i, jsonData){
var Physics = jsonData.Physics;
var Maths = jsonData.Maths;
var Chemistry = jsonData.Chemistry;
var Biology = jsonData.Biology;
var SST = jsonData.SST;
data.addRows([[Physics,Maths,Chemistry,Biology,SST]]);
});
var options = {
title:chart_main_title,
hAxis: {
title: "Subjects"
},
vAxis: {
title: 'Percentage'
}
};
var chart = new google.visualization.ColumnChart(document.getElementById('chart_area'));
chart.draw(data, options);
}
</script>
<script>
$(document).ready(function(){
$('#name').change(function(){
var name = $(this).val();
if(name != '')
{
load_student_data(name, 'Student wise marks data');
}
});
});
</script>
and in order to fetch data
// fetch.php
<?php
//fetch.php
include('connection.php');
if(isset($_POST["name"]))
{
$query = "
SELECT * FROM csv
WHERE name = '".$_POST["name"]."'
ORDER BY id ASC
";
$statement = $connect->prepare($query);
$statement->execute();
$result = $statement->fetchAll();
foreach($result as $row)
{
$output[] = array(
'Physics' => $row["Physics"],
'Maths' => $row["Maths"],
'Chemistry' => $row["Chemistry"],
'Biology' => $row["Biology"],
'SST' => $row["SST"],
);
}
echo json_encode($output);
}
?>
it diplays a blank page. however when i play with singular values i.e one subject at a time it displays fine Edited March 19, 2019 by zetastreakHello, I'm working on a project that takes a CSV (poorly formated unfortunately) and turns it in charts. What should I use? Maani XML/PHP, Pcharts, ...? There are so many possibilities, I'm lost. What do you guys recommend? thanks (if maani is any good, how do I convert something like Array ( => Array ( => Array ( => FORMULE ENTREE+PLAT [1] => 24 ) [1] => Array ( => FORMULE PLAT+DESSERT [1] => 34 ) ) [1] => Array ( => Array ( => ASSIETTE DE FRITES [1] => 2 ) [1] => Array ( => ASSIETTE MIXTE [1] => 1 ) [2] => Array ( => SALADE AUVERGNATE [1] => 8 ) [3] => Array ( => SALADE CHARENTAISE [1] => 17 ) [4] => Array ( => SALADE DU BURON [1] => 10 ) [5] => Array ( => SALADE FERMIERE [1] => 3 ) ) into a XML file? This topic has been moved to Other Libraries and Frameworks. http://www.phpfreaks.com/forums/index.php?topic=352327.0 This topic has been moved to Miscellaneous. http://www.phpfreaks.com/forums/index.php?topic=322864.0 HI guys Im developing Health site using PHP and mysql. I want to create graphs from using data in the database on weekly basis. so please tell me what is the best method of creating graphs and charts in php thank in advance Hello everybody,
I am honestly quite a newb when it comes to mod_rewrite.
We run a small social media page with different areas and I would like to change the URLs to something more clean and professional.
User profiles look like this:
http://www.sky-mp3.com/index.php?action=cm&siteid=59&wahl=artists&tat=details&keyid=477siteid 59 is the artists list and the keyid at the end is the ID of the artist but should be like: http://www.sky-mp3.com/mischuraor in worse case like: http://www.sky-mp3.com/user/mischuraCMS pages look like this: http://www.sky-mp3.com/index.php?siteid=106but should be like: http://www.sky-mp3.com/charts(page name instead of siteid) What I know so far: - I have to add something to the .htaccess file - I need to change something in the code (but I don`t know where) Im good he? What would be the first step on the path to clean URLs for me? I found alot of infos here and there but found nothing yet for this specific case. Kind regards from and thx in advance from Cologne This topic has been moved to Other Libraries and Frameworks. http://www.phpfreaks.com/forums/index.php?topic=344076.0 Hey guys, I have stored a google map link into a database. When I try to display it from database using the command below <?php echo $google_map; ?> I get this output, but I can't display a map. Code: [Select] <iframe width="640" height="480" frameborder="0" scrolling="no" marginheight="0" marginwidth="0" src="http://maps.google.com/maps?f=q&source=s_q&hl=hr&geocode=&q=smi%C4%8Diklasova+3,+karlovac,+croatia&sll=37.0625,-95.677068&sspn=50.910968,135.263672&ie=UTF8&hq=&hnear=Tadije+Smi%C4%8Diklasa,+Karlovac,+Republika+Hrvatska&t=h&ll=45.487155,15.55089&spn=0.028883,0.054932&z=14&iwloc=A&output=embed"></iframe><br /><small><a href="http://maps.google.com/maps?f=q&source=embed&hl=hr&geocode=&q=smi%C4%8Diklasova+3,+karlovac,+croatia&sll=37.0625,-95.677068&sspn=50.910968,135.263672&ie=UTF8&hq=&hnear=Tadije+Smi%C4%8Diklasa,+Karlovac,+Republika+Hrvatska&t=h&ll=45.487155,15.55089&spn=0.028883,0.054932&z=14&iwloc=A" style="color:#0000FF;text-align:left">Prikaz veće karte</a></small> Can you tell me why?? When try to copy that directly to HTML it works perfectly!!! I'm confused! Hi I'm using a the following google Pie Cart from here http://code.google.com/apis/ajax/playground/#pie_chart I would like to use php to COUNT printers listed in a column called machine and return result so I can echo it into google code Example of Column below would return a count of one for each except for the TurboJet which would return two. I would then like to echo the results to the google Javascript for printer 1 to 6. _______ machine ________ FB7500-1 TurboJet XL1500-1 Roland Canon TurboJet Can anyone help? Cheers Chris Code: [Select] <?php mysql_connect("localhost","chris","Cr2baxKUHWGxr6nn"); @mysql_select_db("schedule") or die( "Unable to select database"); date_default_timezone_set('Europe/London'); $query = "SELECT machine, COUNT(machine) FROM maindata GROUP BY machine"; $result = mysql_query($query) or die(mysql_error()); // Print out result while($row = mysql_fetch_array($result)){ echo "There are is ". $row['COUNT(machine)'] ." ". $row['machine'] ." items."; echo "<br />"; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="content-type" content="text/html; charset=utf-8"/> <title> Google Visualization API Sample </title> <script type="text/javascript" src="http://www.google.com/jsapi"></script> <script type="text/javascript"> google.load('visualization', '1', {packages: ['corechart']}); </script> <script type="text/javascript"> function drawVisualization() { // Create and populate the data table. var data = new google.visualization.DataTable(); data.addColumn('string', 'Task'); data.addColumn('number', 'Hours per Day'); data.addRows(5); data.setValue(0, 0, 'Printer 1'); data.setValue(0, 1, 11); data.setValue(1, 0, 'Printer 2'); data.setValue(1, 1, 2); data.setValue(2, 0, 'Printer 4'); data.setValue(2, 1, 2); data.setValue(3, 0, 'Printer 5'); data.setValue(3, 1, 2); data.setValue(4, 0, 'Printer 6'); data.setValue(4, 1, 7); // Create and draw the visualization. new google.visualization.PieChart(document.getElementById('visualization')). draw(data, {title:"Current Work in Progress"}); } google.setOnLoadCallback(drawVisualization); </script> </head> <body style="font-family: Arial;border: 0 none;"> <div id="visualization" style="width: 600px; height: 400px;"></div> </body> </html> I'm having trouble loading this kind of KML with PHP http://code.google.com/apis/maps/documentation/mapsdata/developers_guide_protocol.html#RetrievingFeatures example <atom:entry xmlns='http://www.opengis.net/kml/2.2' xmlns:atom='http://www.w3.org/2005/Atom' xmlns:batch='http://schemas.google.com/gdata/batch' xmlns:gd='http://schemas.google.com/g/2005'> <atom:id> http://maps.google.com/maps/feeds/features/userID/mapID/full/featureID</atom:id> <atom:published>2008-08-14T17:46:06.462Z</atom:published> <atom:updated>2008-08-14T18:12:31.589Z</atom:updated> <atom:category scheme='http://schemas.google.com/g/2005#kind' ..... it seems like the column in atom:entry, etc is causing this. $response = simplexml_load_string($response); print_r($response); the above just gives an empty SimpleXMLElement Object() Any ideas For every search, I get ZERO RESULTS, and I don't understand what I'm doing wrong. Code: [Select] <?php require('places_class.php'); $types = $_POST['type']; $location = $_POST['place']; $radius = $_POST['radius']; $gplaces = New GooglePlaces; $gplaces->SetLocation("$location"); $gplaces->SetRadius($radius); $gplaces->SetTypes("$types"); $results = $gplaces->Search(); print_r($results); ?> That's when the form is submitted, I checked the variables, and they are echoing out correctly. Then I thought I'd hard-code the values in, same results Code: [Select] <?php require('places_class.php'); $gplaces = New GooglePlaces; $gplaces->SetLocation("40.5267,81.4778"); $gplaces->SetRadius(50); $gplaces->SetTypes("food"); $results = $gplaces->Search(); print_r($results); ?> Here is the class Code: [Select] <?php class GooglePlaces { private $APIKey = ""; public $OutputType = "json"; //either json, xml or array public $Errors = array(); private $APIUrl = "https://maps.googleapis.com/maps/api/place"; private $APICallType = ""; private $IncludeDetails = false; //all calls private $Language = 'en'; //optional - https://spreadsheets.google.com/pub?key=p9pdwsai2hDMsLkXsoM05KQ&gid=1 //Search private $Location; //REQUIRED - This must be provided as a google.maps.LatLng object. private $Radius; //REQUIRED private $Types; //optional - separate tyep with pipe symbol http://code.google.com/apis/maps/documentation/places/supported_types.html private $Name; //optional //Search, Details, private $Sensor = 'false'; //REQUIRED - is $Location coming from a sensor? like GPS? //Details & Delete private $Reference; //Add private $Accuracy; public function Search() { $this->APICallType = "search"; return $this->APICall(); } public function Details() { $this->APICallType = "details"; return $this->APICall(); } public function Checkin() { $this->APICallType = "checkin-in"; return $this->APICall(); } public function Add() { $this->APICallType = "add"; return $this->APICall(); } public function Delete() { $this->APICallType = "delete"; return $this->APICall(); } public function SetLocation($Location) { $this->Location = $Location; } public function SetRadius($Radius) { $this->Radius = $Radius; } public function SetTypes($Types) { $this->Types = $Types; } public function SetLanguage($Language) { $this->Language = $Language; } public function SetName($Name) { $this->Name = $Name; } public function SetSensor($Sensor) { $this->Sensor = $Sensor; } public function SetReference($Reference) { $this->Reference = $Reference; } public function SetAccuracy($Accuracy) { $this->Accuracy = $Accuracy; } public function SetIncludeDetails($IncludeDetails) { $this->IncludeDetails = $IncludeDetails; } private function CheckForErrors() { if(empty($this->APICallType)) { $this->Errors[] = "API Call Type is required but is missing."; } if(empty($this->APIKey)) { $this->Errors[] = "API Key is is required but is missing."; } if(($this->OutputType!="json") && ($this->OutputType!="xml") && ($this->OutputType!="json")) { $this->Errors[] = "OutputType is required but is missing."; } } private function APICall() { $this->CheckForErrors(); if($this->APICallType=="add" || $this->APICallType=="delete") { $URLToPostTo = $this->APIUrl."/".$this->APICallType."/".$this->OutputType."?key=".$this->APIKey."&sensor=".$this->Sensor; if($this->APICallType=="add") { $LocationArray = explode(",", $this->Location); $lat = trim($LocationArray[0]); $lng = trim($LocationArray[1]); $paramstopost[location][lat] = $lat; $paramstopost[location][lng] = $lng; $paramstopost[accuracy] = $this->Accuracy; $paramstopost[name] = $this->Name; $paramstopost[types] = explode("|", $this->Types); $paramstopost[language] = $this->Language; } if($this->APICallType=="delete") { $paramstopost[reference] = $this->Reference; } $result = json_decode($this->CurlCall($URLToPostTo,json_encode($paramstopost))); $result->errors = $this->Errors; return $result; } if($this->APICallType=="search") { $URLparams = "location=".$this->Location."&radius=".$this->Radius."&types=".$this->Types."&language=".$this->Language."&name=".$this->Name."&sensor=".$this->Sensor; } if($this->APICallType=="details") { $URLparams = "reference=".$this->Reference."&language=".$this->Language."&sensor=".$this->Sensor; } if($this->APICallType=="check-in") { $URLparams = "reference=".$this->Reference."&language=".$this->Language."&sensor=".$this->Sensor; } $URLToCall = $this->APIUrl."/".$this->APICallType."/".$this->OutputType."?key=".$this->APIKey."&".$URLparams; $result = json_decode(file_get_contents($URLToCall),true); $result[errors] = $this->Errors; if($result[status]=="OK" && $this->APICallType=="details") { foreach($result[result][address_components] as $key=>$component) { if($component[types][0]=="street_number") { $address_street_number = $component[short_name]; } if($component[types][0]=="route") { $address_street_name = $component[short_name]; } if($component[types][0]=="locality") { $address_city = $component[short_name]; } if($component[types][0]=="administrative_area_level_1") { $address_state = $component[short_name]; } if($component[types][0]=="postal_code") { $address_postal_code = $component[short_name]; } } $result[result][address_fixed][street_number] = $address_street_number; $result[result][address_fixed][address_street_name] = $address_street_name; $result[result][address_fixed][address_city] = $address_city; $result[result][address_fixed][address_state] = $address_state; $result[result][address_fixed][address_postal_code] = $address_postal_code; } return $result; } private function CurlCall($url,$topost) { $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, $url); curl_setopt($ch, CURLOPT_HEADER, FALSE); curl_setopt($ch, CURLOPT_RETURNTRANSFER, TRUE); curl_setopt($ch, CURLOPT_POSTFIELDS, $topost); $body = curl_exec($ch); curl_close($ch); return $body; } } ?> And yes, I do have the correct API Key, I just took it out Can anybody see what the issue is? Hi Guys!! I am in need of creating a categories' listing similar to that of Google Directory, http://www.google.com/dirhp All the categories along with their respective sub categories, subcategories of the subcategories, and the subsub categories of the subsub categories ( as deep down as the category system goes ) should be displayed which is exactly similar to that of the Google Directory. Could anyone suggest me how to do it as am pretty much new to PHP. The categories list is stored in a database and should be displayed using PHP and MySQL. This is exactly what i require. I have gone through some articles related to this, (both in this forum and elsewhere) but in all those tutorials, the depth of the categories is known (say, up to 4 or 5 levels). But, what i require is dynamic creation of these categories whose depth is unknown and also provide a way that any user can add a category from the front-end and also the admin can add a category from the back-end. Am in urgent need of this. Can anyone guide me in this regard, pls? And an example of the same would be of great help. Thanks in advance!! Hi I have been working on this code for almost two weeks and can't get over the last hurdle. If someone can put a fresh set of eys on it I would appreciate it. I have 3 files - a geocoder php script which I can't get to work, but it is exactly like the example given on Google except that I have my addresses broken down by street, city, state and zip. - marker.php which is echoing the data correctly, and my map - location.html which pulls up a map but no markers. my geocoder script is below: Code: [Select] <?php define("MAPS_HOST", "maps.google.com"); define("KEY", "mykey"); // Opens a connection to a MySQL server $connection = mysql_connect("server", "user","pwd"); if (!$connection) { die("Not connected : " . mysql_error()); } // Set the active MySQL database $db_selected = mysql_select_db("Db", $connection); if (!$db_selected) { die("Can\'t use db : " . mysql_error()); } // Select all the rows in the markers table $query = "SELECT * FROM table WHERE 1"; $result = mysql_query($query); if (!$result) { die("Invalid query: " . mysql_error()); } // Initialize delay in geocode speed $delay = 0; $base_url = "http://" . MAPS_HOST . "/maps/geo?output=xml" . "&key=" . KEY; // Iterate through the rows, geocoding each address while ($row = @mysql_fetch_assoc($result)) { $geocode_pending = true; while ($geocode_pending) { $street = $row["street"]; $city = $row["city"]; $state = $row["state"]; $zip_code = $row["zip_code"]; $id = $row["id"]; $request_url = $base_url . "&q=" . urlencode($street + $city + $state + $zip_code); $xml = simplexml_load_file($request_url) or die("url not loading"); $status = $xml->Response->Status->code; if (strcmp($status, "200") == 0) { // Successful geocode $geocode_pending = false; $coordinates = $xml->Response->Placemark->Point->coordinates; $coordinatesSplit = split(",", $coordinates); // Format: Longitude, Latitude, Altitude $lat = $coordinatesSplit[1]; $lng = $coordinatesSplit[0]; $query = sprintf("UPDATE table " . " SET lat = '%s', lng = '%s' " . " WHERE id = '%s' LIMIT 1;", mysql_real_escape_string($lat), mysql_real_escape_string($lng), mysql_real_escape_string($id)); $update_result = mysql_query($query); if (!$update_result) { die("Invalid query: " . mysql_error()); } } else if (strcmp($status, "620") == 0) { // sent geocodes too fast $delay += 100000; } else { // failure to geocode $geocode_pending = false; echo "Address " . $street . " failed to geocoded. "; echo "Received status " . $status . " \n"; } usleep($delay); } } ?> my html file looks like the following: Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="content-type" content="text/html; charset=utf-8"/> <title>location</title> <script src="http://maps.google.com/maps?file=api&v=2&key=mykey" type="text/javascript"></script> <script type="text/javascript"> var iconFlag = new GIcon(); iconFlag.image = 'images/redflag.png'; iconFlag.iconSize = new GSize(12, 20); iconFlag.iconAnchor = new GPoint(6, 20); iconFlag.infoWindowAnchor = new GPoint(5, 1); var iconBlue = new GIcon(); iconBlue.image = 'images/glossy-ball.png'; iconBlue.iconSize = new GSize(12, 20); iconBlue.iconAnchor = new GPoint(6, 20); iconBlue.infoWindowAnchor = new GPoint(5, 1); var iconRed = new GIcon(); iconRed.image = 'images/redbutton.png'; iconRed.iconSize = new GSize(12, 20); iconRed.iconAnchor = new GPoint(6, 20); iconRed.infoWindowAnchor = new GPoint(5, 1); var customIcons = []; customIcons["Db1"] = iconFlag; customIcons["Db2"] = iconBlue; customIcons["Db3"] = iconRed; function load() { if (GBrowserIsCompatible()) { var map = new GMap2(document.getElementById("map")); map.addControl(new GSmallMapControl()); map.addControl(new GMapTypeControl()); map.setCenter(new GLatLng(39.0000, 72.0000), 11); // Change this depending on the name of your PHP file GDownloadUrl("marker.php", function(data) { var xml = GXml.parse(data); var markers = xml.documentElement.getElementsByTagName("markers"); for (var i = 0; i < markers.length; i++) { var informant = markers[i].getAttribute("id"); var firstname = markers[i].getAttribute("firstname"); var lastname = markers[i].getAttribute("lastname"); var phone = markers[i].getAttribute("phone"); var zip_code = markers[i].getAttribute("zip_code"); var type = markers[i].getAttribute("type"); var point = new GLatLng(parseFloat(markers[i].getAttribute("lat")), parseFloat(markers[i].getAttribute("lng"))); var marker = createMarker(point, id, firstname, lastname, street, city, state, zip_code, type); map.addOverlay(marker); } }); } } function createMarker(point, id, firstname, lastname, street, city, state, zip_code, type) { var marker = new GMarker(point, customIcons[type]); var html = "<b>" + id + "</b> <br/>" + firstname + "<br/>" + lastname + "<br/>" + phone + "<br/>" + street + "<br/>" + city + "<br/>" + state + "<br/>" + zip_code +"<br/>" + type; GEvent.addListener(marker, 'click', function() { marker.openInfoWindowHtml(html); }); return marker; } //]]> </script> </head> <body background="images/bg2.jpg"> <body onload="load()" onunload="GUnload()"> <center><div id="map" style="width: 800px; height: 600px"></div></center> </body> </html> Thanks for any help Hi guys Mods please move if this is the wrong place to ask. I have a google maps api added to my web site but i want to be able to position "pins" on the map to show all the the registered clubs in an area... eg the user searches dublin and all teh clubs pop up... My question is.. is there anyway to do this without needing the user to supply the long/lat.. ie can it be gotten automatically?? I really just want it to work off the addrees/area they supplied when they registered. thanks tt |
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